Water in a swimming pool is treated with two chemicals mixed in the ratio of 5: 4. The total volume of the chemicals is 48 litres. How much of each chemical is used?

On solving the provided question, we can say that - the charge for 42 units = is $139.20; so, charge per unit is 139.20/42 = $3.3142857143

The unit technique is an approach to problem-solving that involves first determining the value of a single unit, then multiplying that value to determine the required value. The unit method, to put it simply, is used to extract a single unit value from a supplied multiple. For instance, 40 pens would cost 400 rupees, or the price of one pen. The process for doing this may be standardized. a single country. anything that has an identity element. (mathematics, algebra) (Linear algebra, mathematical analysis, mathematics of matrices or operators) Its adjoint and reciprocal are equivalent.

here,

the charge for 42 units = is $139.20.

so, charge per unit is 139.20/42 = $3.3142857143

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During the winter, the grill was marked at $85. In June, the price was changed to $110. 50. So, 23.08% is the change in percentage.

When the denominator is 100, percentages are really just fractions. We place the percent sign (%) next to the number to indicate that the number is a percentage.

Comparing two amounts while re basing the second amount to 100 is the simplest way to use percentages. The word percentage comes from the Latin term per centum, which means "by the hundred." In the 16th century, the Latin term made its way into English. It was later abbreviated to %.

Given that,

the grill was marked at $85

the price was changed to $110. 50.

Now, percentage change:

= [{(110. 50 - 85)/110.50} × 100]

= (0.2308 × 100)

= 23.08%

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The Equation for the value y is a. y = 21 + 0.25x (where x represents the number of weeks)

b. The value of the stock after 20 weeks would be 21 + (0.25 * 20) = $26.

This equation represents the linear relationship between the value of the stock (y) and the number of weeks (x). The value of the stock is initially $21, and it increases by $0.25 every week. This is represented by the coefficient of x (0.25) in the equation. By plugging in x=20 into the equation, we can find that after 20 weeks, the value of the stock would be $26. This is assuming that the rate of increase remains constant over time.

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Therefore , the solution of the given problem of equation comes out to be 1.45 mph (speed of the current).

A mathematical depiction of two equal things, one on either side of a "equals" sign, is called an expression. Equations can be used to solve common problems. To solve challenges in real life, we frequently turn for pre algebra assistance. Lessons in pre-algebra cover the foundational ideas of mathematics.

Here,

The 15 miles that Bob the Boy Scout must paddle upwards against the current takes him 10 hours.

He discovers that paddling 22.5 miles against the current only took him 5 hours when he turns back.

——

Upstream data: rate = d/t = 15/10 = 1.5 mph, distance = 15 miles, time = 10 hours.

————————

Downstream DATA: rate = d/t = 22/5 = 4.4 mph; duration = 5 hours; distance = 22 miles.

———————-

Equations:

upstream: Downstream, b-c = 1.5 mph; b+c = 4.4 mph

2b = 5.9 mph;

2b = 2.95; add and solve for "b" (speed of the boat in still water)

—-

For "c," use the formula

=> b + c = 4.4

=>2.95 + c = 4.4

=> c = 1.45 mph (speed of the current)

Therefore , the solution of the given problem of equation comes out to be 1.45 mph (speed of the current).

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The number of times the diameter of Uranus is larger than the diameter of Mars is 7.5 times

From the question, we have the following parameters that can be used in our computation:

The diameters of Uranus and Mars

These diameters are given as

Diameter of Uranus: 5.11×10^4 kilometers

Diameter of Mars: 6.79×10^3 kilometers

Express the diameters properly

So, we have the following representation

Diameter of Uranus: 5.11 × 10⁴ kilometers

Diameter of Mars: 6.79 × 10³ kilometers

This means that

Number of times larger = Diameter of Uranus/Diameter of Mars

Substitute the known values in the above equation, so, we have the following representation

Number of times larger = 5.11 × 10⁴ kilometers/6.79 × 10³ kilometers

Evaluate the quotient

So, we have the following representation

Number of times larger = 7.5

Hence, the number of times is 7.5

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Answer:

A directed segment is a segment that has distance (length) and direction. Hope this helps.

Proportion is the ratio of the two equal fractions. It compares the part of a whole to another part of another whole. Option c is the correct option which is, The test provides convincing evidence the proportion is greater than 90% but the actual proportion is equal to the 90%.

What is proportion?

proportion is the ratio of the two equal fraction. It compare the part of a whole to other part of of the another whole.

Given

Options for the following question are,

A) The test does not provide convincing evidence that the proportion is greater then 90 percent but the actual proportion is greater then 90 percent.

B) The test does not provide convincing evidence  the proportion is greater than 90% but the actual proportion is equal to the 90%.

C)The test provides convincing evidence the the proportion is greater than 90% but the actual proportion is equal to the 90%.

D)The test provides convincing evidence that the proportion is greater then 90 percent but the actual proportion is greater then 90 percent.

E) All type 1 error is not possible for this hypothesis test.

The Null Hypothesis for the given question is,

The proportion of all washers produced with the specified diameter is equal to 90 percent. The Null Hypothesis for the given case is true and actual proportion is equal to 90 percent.

Hence, option c is the correct option which is, The test provides convincing evidence tha the proportion is greater than 90% but the actual proportion is equal to the 90%.

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Answer:

Here are a few of the factor pairs. The rest you can find in the pdf below.

A = 1, y = -2/3, The value of a for which the system of equations has a unique solution is a = -3.

1. Set the first equation equal to 0:

2x + ay = 2

2. Subtract 2x from both sides of the equation to get:

ay = -2

3. Divide both sides of the equation by a to get:

y = -2/a

4. Substitute this value of y into the second equation to get:

6x + 3(-2/a) = 3

5. Multiply both sides of the equation by a and simplify to get:

6ax - 6 = 3a

6. Add 6 to both sides of the equation to get:

6ax = 3a + 6

7. Divide both sides of the equation by 6 to get:

x = (3a + 6)/6

8. The value of a for which the system of equations has a unique solution is a = -3.

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Answer: Based on the survey results, we can calculate the number of ice cream cones to sell for each flavor by multiplying the percentage of the flavor by the total number of ice cream cones to be sold.

Mint: 10% of 300 ice cream cones = 0.1 * 300 = 30 ice cream cones

Strawberry: 25% of 300 ice cream cones = 0.25 * 300 = 75 ice cream cones

Chocolate chip: 15% of 300 ice cream cones = 0.15 * 300 = 45 ice cream cones

Vanilla: 50% of 300 ice cream cones = 0.5 * 300 = 150 ice cream cones

So, based on the survey results, you should sell 30 ice cream cones of Mint flavor, 75 ice cream cones of Strawberry flavor, 45 ice cream cones of Chocolate chip flavor, and 150 ice cream cones of Vanilla flavor.

It's worth mentioning that the sum of the percentages provided, 10+25+15+50 = 100%. Which means that it is a proper survey and the total number of ice cream cones you expect to sell is equal to the survey results.

Step-by-step explanation:

Based on the survey results flavors sold at the sporting event are, 30 mint ice creams, 75 Strawberry icecreams, 45 Chocolate chip icecreams, and 150 Vanilla icecreams.

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

The number of different types of ice creams can be obtained as follows,

10% - Mint.

= (10/100)×300.

= 30.

25% - Strawberry.

= (25/100)×300.

= 75.

15% - Chocolate chip.

= (15/100)×300.

= 45.

50% - Vanilla.

= (50/100)×300.

= 150.

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The percentage of adults from this country who viewed a college education as essential for success x years after the first year can be represented by the function P(x) = 31 + 2.6x.

What is the percentage function?

To determine the percentage, we have to divide the value by the total value and then multiply the resultant by 100. Percentage formula = (Value/Total value) × 100. Example: 2/5 × 100 = 0.4 × 100 = 40 per cent.

The percentage of adults from this country who viewed a college education as essential for success x years after the first year can be represented by the function:

P(x) = 31 + 2.6x

Where P(x) is the percentage of adults who viewed college education as essential for success x years after the first year, and x is the number of years after the first year.

The function shows that the percentage increase by 2.6 every year for x years after the first year, and the initial percentage is 31%.

This function is representing a linear trend since the coefficient of x is constant.

Hence, The percentage of adults from this country who viewed a college education as essential for success x years after the first year can be represented by the function P(x) = 31 + 2.6x.

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As per the following graph, if y = 0,then it makes the horizontal line on graph.

The term graph in math is defined as the visual representation of data or equation.

Here we have given that the value of y = 0.

Here we know that the slope of a horizontal line is zero while the slope of a vertical line is undefined.

Here the following Slopes represent a line's ratio of vertical change to horizontal change.

Whereas horizontal and vertical lines remain constant and never increase or decrease, they're merely straight lines.

Here we have also know that the Horizontal lines have no steepness at all.

Therefore if y=0 is the linear equation to denote the x - axis, then all the points on the x- axis, have their y co-ordinate as 0.

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Rounded to the nearest tenth, the measure of side ST is 8.0.

In order to find the measure of side ST, you will need to use the concept of similarity. If two triangles are similar, then their corresponding sides are in proportion. If we let x be the measure of side ST, then we can set up a proportion using the given information:

[tex]OP/PQ = ST/RQ[/tex]

We also know that

[tex]OP/PQ = 2/3[/tex]

and

[tex]RQ = 12[/tex]

So we can substitute these values into the proportion and solve for x:

[tex](2/3) = ST/12[/tex]

[tex]ST = (2/3) * 12[/tex]

[tex]ST = 8[/tex]

Rounded to the nearest tenth, the measure of side ST is 8.0.

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Therefore because of this, the answer to the speed problem is that a family can travel 31.875 miles in 3/4 of an hour.

Speed is a tempo that is determined by the distance an entity travels in a predetermined period of time. Numerous methods exist for measuring speed, including miles per hour, laps per minute, and meters per second. The measurements of speed, distance, and time are related. The relationship can be expressed in three different ways:

D = RT, R = DT, & T = DR.

Here,

We are given that

Distance drives by a family=4[tex]\frac{1}{4}[/tex] miles

Time = 1/10

We have to find the rate of speed in miles per hour.

The speed formula will be used to get the velocity in miles per hour.

Distance traveled in a given amount of time equals speed.

=> Speed = 17/4 * 10

=> Speed = 42.5

So, using the calculation, we arrive at 42.5 miles per hour.

The miles traveled in 3/4 miles are therefore:

Distance is calculated as speed times time,

therefore 42.5 * 3/4 would equal 31.875 miles in distance.

Because of this, the answer to the speed problem is that a family can travel 31.875 miles in 3/4 of an hour.

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The area for 2 pounds of fertilizer is 400 square feet

How to determine the amount of fertilizer for 2 pounds?

From the question, we have the following parameters that can be used in our computation:

seven pounds of fertilizer can cover 1400 square feet

This means that

7 pounds of fertilizer = 1400 square feet

Divide both sides of the equation by 7

So, we have the following representation

1 pounds of fertilizer = 200 square feet

Multiply both sides of the equation by 2

So, we have the following representation

2 pounds of fertilizer = 400 square feet

Hence, the area is 400 square feet

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Answer:

Kumain ka Ng pansit para ka Maka sagot

Step-by-step explanation:

follow pleas helpme

The measure of angle B is, 67°.

A triangle is a three sided polygon, which has three vertices and three angles which has the sum 180 degrees.

Given that;

Interior angles are,

⇒ ∠ C = 83°

⇒ ∠ B = 6x + 7

An exterior angle is,

⇒ ∠ A = 15x

Now, We know that;

The sum of two interior angles in a triangle is equal to the exterior angle in a triangle.

⇒ 83° + 6x + 7 = 15x

⇒ 90 = 15x - 6x

⇒ 90 = 9x

⇒ x = 10

Thus, The measure of B is,

⇒ m ∠B = 6x + 7

             = 6×10 + 7

             = 60 + 7

             = 67

⇒ m ∠B =  67

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Answer:

She will earn $900.00 in 12 hours.

Step-by-step explanation:

Her unit rate is 75 dollars per hour.

375/5 = $75

75 x 12 = 900

Answer:  $900

Step-by-step explanation: 375/5x12.

The area of the semi-circle with the radius of 4.1 mm, round to the nearest tenth is 52.8 mm²

The area of the semi-circle will be calculated by the formula -

Area = 1/2πr², where r is the radius of the circle.

Keep the values in formula to find the value.of area of semi circle

Area = 1/2×3.14×4.1²

Performing multiplication on Right Hand Side of the equation to find the area of the semi-circle

Area = 52.78 mm²

Round off the nearest tenth

Area = 52.8 mm²

Thus, the area of semi-circle with mentioned radius is 52.8 mm².

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Answer:

12?

Step-by-step explanation:

Lowkey don't understand the last part of your q but if it's 4 times then if the original was 12 48 is four times bigger

The derivative function for equations 1 and 2 will be

y' = -1/ [2√(1-x²)] and y' = 3/[2(1 + x²)] respectively

Here we need to find the derivative of

[tex]y = tan^{-1}\sqrt{\frac{1-x}{1+x} }[/tex]

Let x = cos2z

Hence we get

[tex]y = tan^{-1}\sqrt{\frac{1-cos2z}{1+cos2z} }[/tex]

[tex]or, y = tan^{-1}\sqrt{\frac{2sin^{2}z}{2cos^{2}z} }[/tex]

[tex]or, y = tan^{-1}(tanz)[/tex]

or, y = z

Hence dy/dx = dz/dx

We know that

x = cos2z

or, 2z = cos⁻¹x

or, 2 dz/dx = -1/√(1-x²)

Hence dy/dx = -1/ [2√(1-x²)]

The second equation is

[tex]y = 3tan^{-1}[x-\sqrt{1+x^{2}} ][/tex]

Let x = cotz

Hence we get

[tex]y = 3tan^{-1}[cotz-\sqrt{1+cot^{2}z} ][/tex]

[tex]y = 3tan^{-1}[cotz-\sqrt{cosec^{2}z} ][/tex]

or, y = 3tan⁻¹ [cotz - cosecz]

or, y = 3tan⁻¹ [cosz/sinx - 1/sinz]

or, y = 3tan⁻¹ [(cosz - 1)/sinz]

or, y = 3tan⁻¹ [-2sin²(z/2)/{2sin(z/2) cos(z/2)}]

or, y = 3tan⁻¹ [-sin(z/2)/cos(z/2)]

or, y = 3tan⁻¹ [-tan{z/2)]

or, y = 3tan⁻¹ [tan{-z/2)]

or, y = -3z/2

or, dy/dz = -3/2 dz/dx

We have

x = cotz

or, z = cot⁻¹z

or, dz/dx = -1/(1 + x²)

Hence we get

dy/dx = 3/[2(1 + x²)]

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3a) Rounded to the closest benchmark, Samuel walked about 3 Miles on the parade route.

3b)  Rounded to the closest benchmark, Samuel walked about 2 Miles home

3c) Samuel walked about 5 Miles in all

We know that when rounding a fraction to the closest benchmark:

1) if the numerator is much smaller than the denominator, round a fraction to 0

2) if the numerator  is about half the denominator, round a fraction to 1/2

3) if the numerator is nearly equal to the denominator, round a fraction to 1

Samuel walked 3 1/8 miles along the parade route.

Rounding to the closest benchmark a fraction 3 1/8 woule be

3 1/8

= 3            

This means, he walked about 3 Miles on the parade route.

Samuel walked 2 5/6 miles home.

Rounding to the closest benchmark a mixed fraction 2 5/6 woule be

2 5/6

= 2            

This means, he walked about 2 Miles homes.

The total distance would be,

d = 3 + 2

d = 5 miles

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Answer:

165 students or the sophomore class of 220 are not athletic.

Step-by-step explanation:

60/240 = .25 This means that 25% of the class is athletic.  That would mean and .75 or 75% are not athletic.

220 x .75 = 165

The arithmetic expression may be used to get the formula T = (11 + w)/4, which is the distance Kane runs in a training session after w weeks.

Every training session, Kane begins out by running 3 miles, and he has a plan to improve that distance by 1/4 mile each week.

The number of weeks is w.

The arithmetic progression may be used to calculate an expression that displays the distance Kane runs during a training session after w weeks.

T = A + (n-1)d is the formula for the nth term in an arithmetic operation, where an is the first term, which is 3, d is the difference between two consecutive terms, which is, is the last term, and n is the total number of terms.

We get, T = (11+w)/4

This is the expression to show the distance Kane runs in a training session after w weeks.

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Complete question - Kane is training for a marathon. He starts by running 3 miles during every training session each week plans to increase the distance of his runs by 1/4 mile. Let w be the number of weeks. Write and expression to show the distance Kane runs in a training session after w weeks

Answer:

C - 16√5

Step-by-step explanation:

Simply subtract 19 and 3 while keeping √5 the same.

19√5 - 3√5 = 16√5

Answer:

Y=7x+67

Step-by-step explanation:

The answer would be −6q−11

Answer:

-6q-11

Step-by-step explanation: