The only variable we found that affects the speed of a wave on a string was the tension of the string. How does this relate to how a musician tunes a stringed instrument?

Answers

Answer 1

Answer:

We know that in a string with two fixed points (like the one you will find in a guitar, where the string is "fixed" at the bridge and at the nut) the only thing that defines the speed (the frequency) at which the string vibrates is the tension (the length is also important, but for the 6 strings in the guitar all of them have the same length, but, as you know, when you press in a given fret the note changes, this happens because you are changing the length of the string, finally, the mass of the string is also important, but all the strings have almost the same mass, so we can ignore this).

Then for the open notes (the notes that you play when you don't fret any note) the only thing that defines the note that will sound is the tension of the string.

And a musician can tune the stringed instrument by changing the tension of each string using a tuner, which is the mechanism in the headstock of the instrument). As more tense is the string, higher will be the open note.


Related Questions

Identifying the factors contributing to and acting as determinant factors of health disparities during the program theory and development process is a means of culturally tailoring the program.
a) true
b) false

Answers

Answer:

a) True

Explanation:

A program-specific message provided to an individual or group with the intention of raising awareness of a health condition, motivating behavior change, removing perceived barriers to participating in a health habit, or something else relating to the program's aims and objectives. The most effective intervention messages are usually theory-based and culturally adapted.

A person rolls a 7 kg bowling ball down a lane in a bowling alley. The lane is
18 m long. The ball is traveling at 7 m/s when it leaves the person's hand.
What is the ball's kinetic energy at this point?

Answers

Answer:

171.5J

Explanation:

K=1/2 *m *U²

K=1/2 *7 *7²

K=171.5 J

An object produces a sound wave with a wavelength 75.0cm. if the speed of sound is 350.0m/s, the frequency of the sound is

Answers

Answer:

wavelength=75.0

speed of sound(v)=350 .0m/s

frequency(f)=?

we know,

v=f*wavelengh

350.0 =f*750

f. =350/75

=4.667

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The red light from a helium-neon laser has a wavelength of 644.6 nm in air. Find the speed, wavelength, and frequency of helium-neon laser light in air, water, and glass. (The glass has an index of refraction equal to 1.50.)speed (m/s)wavelength (nm)frequency (Hz)airwaterglass

Answers

Answer:

air  f = 4.6527 10¹⁴ Hz

water f = 3.4914 10¹⁴ Hz

glass f = 3.1027 10¹⁴ Hz

Explanation:

The refractive index of a material is given by

         n = c / v

where c is the speed of light in a vacuum c = 3 108 m / s and v is the speed of light in the material medium.

the speed of the wave is

         v = λ f

we substitute

         c / n = λ f

          f = [tex]\frac{c}{n \ \lambda}[/tex]

 

The refractive indices are

air 1,00029

water 1.3330

glass 1.5

let's calculate the frequencies

vaccum

         f = 3 10⁸ / 1 644.6 10⁻⁹

         f = 4.6540 10¹⁴ Hz

air

         f = 3 10⁸ / 1,00029 644.6 10⁻⁹

         f = 4.6527 10¹⁴ Hz

Water

         f = 3 10⁸ / 1.333 644.6 10⁻⁹

         f = 3.4914 10¹⁴ Hz

glass

        f = 3 10 ^ 8 / 1.5 644.6 10⁻⁹

        f = 3.1027 10¹⁴ Hz

A man standing on a frictionless ice throws a 1.00kg mass at 20m/s at an angle elevation of 40.0 degrees. What was the magnitude of the mans momentum immediately after the the throl

Answers

Answer:

Explanation:

1.00kg×20m/s×cos40=15.3

Which of these hazmat products are allowed in your FC?
Please choose all that apply.
A GPS unit (lithium batteries)
A subwoofer (magnetized materials)
A can of hairspray (flammable/aerosols)
Fireworks (explosives)

Answers

Answer: Hazmat products are allowed in your FC are:

A GPS unit (lithium batteries) A subwoofer (magnetized materials)

Explanation:

Hazmat products consist of flammable, corrosive and harmful substances which are actually very hazardous to human health and environment.  

Hazardous material allowed in FC are as follows.

Magnetized material products like as speakers.Non-spillable battery products like toy cars.Lithium-ion battery containing products like laptops, mobile phones etc.Non-flammable aerosol.

So, hazmat allowed products are GPS unit (lithium batteries) and subwoofer (magnetized materials).

Thus, we can conclude that hazmat products are allowed in your FC are:

A GPS unit (lithium batteries) A subwoofer (magnetized materials)

You take your pulse and observe 80 heartbeats in a minute. What is the period of your heartbeat? What is the frequency of your heartbeat?

Answers

Answer:

120 beats per minute.

Explanation:

If I take your pulse and observe 80 heartbeats in a minute. Then the period of your heartbeat is 0.8 s and frequency is 1.3Hz.

What is Heartbeat ?

A pulse is the term used in medicine to describe the tactile arterial palpation of the cardiac cycle (heartbeat) by skilled fingertips. Any location where an artery can be compressed close to the surface of the body, such as the carotid artery in the neck, the radial artery in the wrist, the femoral artery in the groyne, the popliteal artery behind the knee, the posterior tibial artery near the ankle joint, and on the foot, can be used to palpate the pulse (dorsalis pedis artery). Heart rate may be determined by monitoring pulse, or the number of arterial pulses per minute. Auscultation, which is the process of counting the heartbeats while listening to the heart using a stethoscope, is another way to determine the heart rate. Typically, three fingers are used to gauge the radial pulse.

Given,

heart beat = 80 beats/min = 1.3 beats/s

Frequency is nothing but how much beats is heart having in one second and that is 1.3 beats/s. Hence frequency of heart is 1.3Hz.

The Period is reciprocal of frequency,

T = 1/f = 0.8 s

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The position of an object of
mass 5 kg as a function of
time is giving by r = (20m/s4)t4
i + (12 m/s3)t3 j. Find the
force acting on the object as a
function of time. Express the
force in unit vectors. Hint:
Remember that Newton's
second Law relates the force
to the acceleration

Answers

Answer:

[tex]F=5(240t^2i+72tj)\ N[/tex]

Explanation:

Given that,

The mass of the object, m = 5 kg

The position vector is, [tex]r=20t^4i+12t^3j[/tex]

Velocity, [tex]v=\dfrac{dr}{dt}=80t^3i+36t^2j[/tex]

Acceleration, [tex]a=\dfrac{dv}{dt}=240t^2i+72tj[/tex]

Newton's second law of motion is given as follows:

F = ma

Put all the values,

[tex]F=5(240t^2i+72tj)\ N[/tex]

Hence, this is the required solution.

What happens to the water when you throw rock into a pond

Answers

Answer:

The water usually rushes back too enthusiastically, causing a splash – and the bigger the rock, the bigger the splash. The splash then creates even more ripples that tend to move away from where the rock went into the water.

Mark Brsinliest please

Answer :

When a stone is thrown into a pond transverse waves are produced.

Suppose 3 mol of neon (an ideal monatomic gas) at STP are compressed slowly and isothermally to 0.19 the original volume. The gas is then allowed to expand quickly and adiabatically back to its original volume.

Required:
a. Find the highest temperature attained by the gas.
b. Find the lowest temperature attained by the gas.
c. Find the highest pressure attained by the gas.
d. Find the lowest pressure attained by the gas.

Answers

Answer:

a. 273 K b. 90.1 K c. 5.26 atm d. 0.33 atm

Explanation:

For isothermal expansion PV = constant

So, P₁V₁ = P₂V₂ where P₁ = initial pressure of gas = 1 atm (standard pressure), V₁ = initial volume of gas, P₂ = final pressure of gas and V₂ = final volume of gas,

So, P₁V₁ = P₂V₂

P₂ = P₁V₁/V₂

Since V₂/V₁ = 0.19,

P₂ = P₁V₁/V₂

P₂ = 1 atm (1/0.19)  

P₂ = 5.26 atm

For an adiabatic expansion, PVⁿ = constant where n = ratio of molar heat capacities = 5/3 for monoatomic gas

So, P₂V₂ⁿ = P₃V₃ⁿ where P₂ = initial pressure of gas = 5.26 atm, V₂ = initial volume of gas, P₃ = final pressure of gas and V₃ = final volume of gas,

So, P₂V₂ⁿ = P₃V₃ⁿ

P₃ = P₂V₂ⁿ/V₃ⁿ

P₃ = P₂(V₂/V₃)ⁿ

Since V₃ = V₁ ,V₂/V₃ = V₂/V₁ = 0.19

1/0.19,

P₃ = P₂(V₂/V₃)ⁿ

P₃ = 5.26 atm (0.19)⁽⁵/³⁾

P₃ = 5.26 atm × 0.0628

P₃ = 0.33 atm

Using the ideal gas equation

P₃V₃/T₃ = P₄V₄/T₄ where P₃ = pressure after adiabatic expansion = 0.33 atm , V₃ = volume after adiabatic expansion, T₃ = temperature after adiabatic expansion  P₄ = initial pressure of gas = P₁ = 1 atm , V₄ = initial volume of gas = V₁ and T₄ = initial temperature of gas = T₁ = 273 K (standard temperature)

P₃V₃/T₃ = P₄V₄/T₄

T₃ = P₃V₃T₄/P₄V₄    

T₃ = (P₃/P₄)(V₃/V₄)T₂

Since V₃ = V₄ = V₁ and P₄ = P₁

V₃/V₄ = 1 and P₃/P₄ = P₃/P₁

T₃ = (P₃/P₁)(V₃/V₄)T₂

T₃ = (0.33 atm/1 atm)(1)273 K  

T₃ = 90.1 K

So,

a. The highest temperature attained by the gas is T₁ = 273 K

b. The lowest temperature attained by the gas = T₃ = 90.1 K

c. The highest pressure attained by the gas is P₂ = 5.26 atm

d. The lowest pressure attained by the gas is P₃ = 0.33 atm

For the following questions, assume the wavelengths of visible light range from 380 nm to 760 nm in a vacuum. (a) What is the smallest separation (in nm) between two slits that will produce a ninth-order maximum for any visible light

Answers

Answer:

Explanation:

This is an interference exercise, which the case of constructive interference is described by the expression

          d sin θ  = m λ

in this case they indicate that we are in the ninth order (m = 9).

To be able to observe the pattern, the dispersion angle must be less than 90º

         

we substitute

           sin 90 = 1

           d = m  lang

           

let's calculate

           d = 9 λ

           d = 9 380 10⁻⁰

            d = 3.42 10⁻⁶  

           d2 = 9 760 10⁻⁹

           d2 = 6.84 10₋⁶

Rahul sits in a chair reading a book. Which force is equal to the force Rahul exerts on Earth?

Answers

In fact, the force Rahul exerts on Earth corresponds to the force of gravity. But Rahul's weight is, in fact, the force of gravity exerted by the Earth on Rahul, and these two forces correspond to the action-reaction pair of Newton's third law, which states that the two forces are equal.

Answer:

Rahul's weight

Explanation:

In fact, the force Rahul exerts on Earth corresponds to the force of gravity. But Rahul's weight is, in fact, the force of gravity exerted by the Earth on Rahul, and these two forces correspond to the action-reaction pair of Newton's third law, which states that the two forces are equal.

Using formulas, Rahul's weight is equal to

W=mg

where m is Rahul mass and g is the gravitational acceleration (g=9.81 m/s^2).

When an AC source is connected across a 17.0 Ω resistor, the output voltage is given by Δv = (190 V)sin(50πt). Determine the following quantities. (a) maximum voltage V (b) rms voltage V (c) rms current A (d) peak current A (e) Find the current when t = 0.0045 s.

Answers

Explanation:

the answer is in the above image

(a) The maximum voltage V is  190 Volts.

(b) The rms voltage V is 95√2 Volts.

(c) The rms current in Amperes is  7.9 A.

(d) The peak current Amperes is  11.18 A.

(e)The current when t = 0.0045 s is 7.26 A.

What is current?

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

Given is an AC source is connected across a 17.0 Ω resistor, the output voltage is given by Δv = (190 V)sin(50πt).

(a) From the given voltage equation, maximum voltage V is 190 Volts.

(b) rms voltage =Vmax/√2

Put the values, we get

Vrms = 190/√2 = 95√2 Volts

(c) rms current = Vrms/Resistance

Put the values, we get

Irms =  95√2 /17

Irms = 7.9 Amperes.

(d) peak current  =√2 Irms

Substitute the values, we get

Peak current = 7.9 √2 = 11.18 A

(e) The current when t = 0.0045 s is written as

I =  (190 V)sin(50πt)/R

Substitute the values, we have

I =  (190 )sin(50π x0.0045)/17

I = 7.26 A.

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Assignment: 06.05 Infections and Health

Answers

Is there a certain question u have?

Now imagine that you are a Haitian taptap driver and want a more comfortable ride. You decide to replace the springs with new springs that can handle the typical heavy load on your vehicle. What spring constant do you want your new spring system to have?
The new springs should have a spring constant that is (slighty larger, substantially larger, slightly smaller, substantially smaller) substantially larger slightly larger slightly smaller substantially smaller than the spring constant of the old springs.

Answers

Answer:

We use a spring of large spring constant.

Explanation:

The spring constant is defined as the force applied on the spring per unit extension or compression in length.

F = k x

where, F is the force, x is the extension, k is the spring constant.

Its unit is N/m.

To get the comfortable ride, we use the spring of large spring constant, so that the spring gets stiffer and we get comfort.

State two (2) examples of osmosis occurring in everyday life

Answers

when you keep raisin in water and the raisin gets puffed.
Movement of salt-water in animal cell across our cell membrane.

Short-term memory is active, while long-term memory is:
A dynamic
B
reflective.
c) passive
D
recessive.

Answers

Answer:

the answer is b. reflective

Consider a point on a bicycle wheel as the wheel turns about a fixed axis, neither speeding up nor slowing down. Compare the linear and angular accelerations of the point.

a. Both are zero.
b. Only the angular acceleration is zero.
c. Only the linear acceleration is zero.
d. Neither is zero

Explain your choice

Answers

Answer:

c. Only the linear acceleration is zero.

Explanation:

The linear acceleration is defined as the rate of change of linear velocity. Since the bicycle is moving in the same direction, with the same speed, without speeding up or slowing down. Therefore, there will be no change in linear velocity and as a result, linear acceleration will be zero.

The angular acceleration is the rate of change of angular velocity. Since the angular velocity is changing its direction constantly. Therefore, it has a certain component of acceleration at all times called centripetal acceleration.

Therefore, the correct option is:

c. Only the linear acceleration is zero.

A(n) 60.9 kg astronaut becomes separated
from the shuttle, while on a space walk. She
finds herself 36.5 m away from the shuttle
and moving with zero speed relative to the
shuttle. She has a(n) 0.928 kg camera in her
hand and decides to get back to the shuttle
by throwing the camera at a speed of 12 m/s
in the direction away from the shuttle.
How long will it take for her to reach the
shuttle? Answer in minutes.
Answer in units of min.

Answers

Answer:

m v = M V  conservation of momentum after  throwing camera

V = m * v / M =   .928 * 12 / 60.9 = .183 m/s

t = S / V = 36.5 / .183 = 199 sec = 3.32 min

concave mirror daily application​

Answers

Answer:

concave mirror use in headlights and torches

Explanation:

Concave mirrors are used in headlights and torches. The shaving mirrors are also concave in nature since these mirrors can produce enlarged clear images. Doctors use concave mirrors as head mirrors to have a clearer view of eyes, noses, and ears. The dental mirrors used by dentists are also concave.

Use a projectile motion kinematic equation for the vertical motion to find the time t that the ball is in the air, from when it leaves the track until it strikes the floor.

Answers

Answer:

The time of flight is [tex]T = \frac{2 u sin A}{g}[/tex].

Explanation:

Let the initial velocity is u and the angle of projection is A.

Use first equation of motion for vertical motion

Let the time to reach the maximum height is t.

[tex]v = u - gt\\\\0 = u sin A - gt \\\\t = \frac{ u sin A}{g}[/tex]

Total time of flight is

T =2  t

[tex]T = \frac{2 u sin A}{g}[/tex]

a system absorbs 500J of heat and at the same time 400J of work is done on the system what is change in internal energy​

Answers

This is the solution of the problem. The problem is calculated from a closed system energy balance equation


The engine in the car from question 1 uses a force of 1200 N to cause the car to accelerate at 3.5 m/s2. What is the car's mass?​

Answers

Answer:

Mass of car's engine = 342.85 kg (Approx.)

Explanation:

Given values:

Force applied by car = 1,200 N

Acceleration of car' engine = 3.5 m/s²

Find:

Mass of car's engine

Computation:

⇒ Mass = Force / Acceleration

⇒ Mass of car's engine = Force applied by car / Acceleration of car

⇒ Mass of car's engine = 1,200 / 3.5

⇒ Mass of car's engine = 342.85 kg (Approx.)

Determine the minimum horizontal force P required to hold the crate from sliding down the plane. The crate has a mass of 50 kg and the coefficient of static friction between the crate and the plane is . ms

Answers

Answer: hello some data related to your question is missing attached below is the missing data and diagram related to the solution

answer:

P = 141.21 N

Explanation:

Given data:

Mass of crate = 50 kg

coefficient  of static friction ( μ ) = 0.25

Calculate minimum horizontal force ( P ) that holds the crate from sliding

∑fx = 0

     = P + Fcos θ - N*sinθ = 0

     = P + 0.25N cos 30° - Nsin30°  = 0

∴ P = 0.2835 N = 0

P - 0.2853 N = 0 ------- ( 1 )

∑fy = 0

     - 50g + Ncosθ + Fsinθ

     - 50*9.81 + Ncos30° + 0.25Nsin30°

∴ N = 494.942 N ----- ( 2 )

input 2 into 1

P - 0.2853 ( 494.942 ) = 0

P = 141.21 N

A kettle operates from a 120 V outlet. It has a heating element with a resistance of 8.0 Ω . Calculate the current going through the element.

Answers

Answer:

I = 15A

Explanation:

V = I*R

120V = I*8.0ohms

I = 120V/8.0ohms

I = 15A

Answer:

I=15A

Explanation:

you know what to do.

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What is a reasonable measurement for the distance to Neptune?
30 light years
30 kilometers
30 parsecs
30 Astronomical Units

Answers

Answer:

30 kilometers is a reasonable measurement

A car has a mass of 900 kg is accelerated from rest at a rate of 1.2 m/s calculate the time taken to reach 30/s​

Answers

Answer:

12+2=24+30+2=66

Explanation:

What is the potential energy of a 7kg object 4m off the ground ?

please show your work

Answers

Answer:

Gravitational potential energy is mass of the object times the gravitational constant times the height of the object:

U = mgh (I will use 10 for the gravitational constant but you can use 9.8 or 9.81 or something even more accurate)

U = 280

The gravitational potential of the object is 280 joules

It is said that a gas fills all the space available to it. Why then doesn't the atmosphere go off into space?

Answers

Earth has its own atmosphere. That is one reason all the water that has been on Earth has been recycled through the water cycle. It never leaves Earth’s atmosphere.

The first charged object is exerting a force on the second charged object. Is the second charged object necessarily exerting a forcer on the first?

Answers

Answer:

Explanation:

Of course because it's Newton's Law that if body A exerts force on body B, then body B will exert equal but opposite force on body A.

HAPPY LEARNING:)

The first charged object is exerting a force on the second charged object. The second charged object necessarily exerting a force on the first is correct.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Newton's third law states that for every action (force) in nature there is an equal and opposite reaction, from that we can understand when force is exerted on first charged object is exerting a force on the second charged object. The second charged object necessarily exerting a force on the first.

The first charged object is exerting a force on the second charged object. The second charged object necessarily exerting a force on the first is correct.

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Using the AS-AD and IS-LM models, show the effects of an increase in consumer confidence on the position of the AD, AS, IS, and LM curves in the short run and in the medium run. Precisely label all axes and curves to receive full credit. Label the short-run equilibrium and medium-run equilibrium with SR and MR, respectively. What information in the passage suggests that the Olmec culture had spread? All swimming equipment is on sale with a 30% discount. A snorkeling set regularly sellsfor $50. Find the discount. idioms of unforgettable 5 line tell me pls name and explain any two advantages for Samuel maharero in supporting the German soldiers A Depuis quand to frequente cette cole? g) Combien de professeur ya-t-il dans ton cole? Name three reasons why people are fleeing Central America? What is the area of the circle in terms of pi? How many solutions are there to the equation below?8(x-3) = 7x- 20 Why is the newtons law of cooling and explain how to derive it/ In the triangles, GK PN and HG 2MP.Which statement correctly compares the angles?HMAngle G is congruent to angle P.O Angle G is smaller than angle P.O Angle G is larger than angle P.O Angle G is congruent to angle N.32 cm40 cmGKPN Why did the Radical Republicans in Congress oppose President AbrahamLincoln's plan for Reconstruction? * El permetro de un rectngulo es 58 y su base excede en 10 a su ancho, Cunto mide la base? AYUDAAAA In front of Aqra bin Habis, Rasoolullah showed his love for Hazrat Hasan in a way that:a) fed himb)made him sit on his backc) kissed himd) played with him read the following sentence from hellen keller's the story of my life I became impatient at her repeated attempts and, seizing the new doll, I dashed it upon the floor how would the sentence read if it was in the third person pov The economy of the north in 1800's was based on What is the correct form ot the verb in bracket written in the preterite tense.El profesor ________________ en la clase. (Entrar) En rpublique du Bnin, on parle l/le............ comme langue officiellea. allemandb. anglaisc. francaisd. espagnol help please I'll mark brainliest What is the most likely setting for a Gothic novel?O A. A conference room in a sterile office buildingO B. A memorial site where a great battle took placeO c. A forest at night, far from civilization and comfortO D. A masked ball in a large house in the citySUBM