Suppose the particles in the preceding problem have masses The velocities of the particles are (a) Calculate the angular momentum of each particle about the origin. (b) What is the total angular momentum of the four-particle system about the origin?

Answers

Answer 1

Part A: The angular momentum of each particle about the origin

The angular momentum of the first particle is -0.4 kg.m²/s.The angular momentum of the second particle is 0.The angular momentum of the third particle is 1.3 kg.m²/s.The fourth particle's angular momentum is 0.

Part B: The total angular momentum of the four-particle system is 0.95 kg.m²/s.

The expression used to calculate angular momentum L is:

                             L = r x mv

Here, r is the position vector of the object m is the mass and v is the velocity vector.

According to the superposition principle, the resultant angular momentum due to many particles is the vector sum of the individual angular momentum.

L = L₁ + L₂ + L₃ + ...

Here, L₁ is the angular momentum of a particle, L₂ is the angular momentum of the particle, and so on.

In the question

Mass of a particle = 5.0 kg

vector r = (2.0i - 3.0j) m

vector v = (3.0i) m/s

Part A (seen in the picture for instruction)

For particle 1

The position vector is 2.0j m

Substitute 0.10 kg from m₁, 2.0j from r, and 2.0i m/s for v₁ in the expression of angular momentum

L = r x mv

L₁ = (2.0jm) x [(0.10 kg)( 2.0i m/s)]

L₁ = -4.0 kg.m²/s

The angular momentum for the first particle is -4.0 kg.m²/s.

For particle 2

Position vector is (2.0i - 2.0j) m

Substitute 0.20 kg from m₂, (2.0i - 2.0j) m from r, and (3.0i - 3.0j)m/s for v₂ in the expression of angular momentum

L₂ = (2.0i - 2.0j) m x [ (0.20 kg) (3.0i - 3.0j) m/s]

L₂ = 0

The angular momentum for the second particle is 0

For particle 3

The position vector is (-3.0i + 1.0j) m.

Substitute 0.30 kg from m₃,  (-3.0i + 1.0j) m from r, and  -5.0j m/s for v₃ in the expression of angular momentum

L₃ = (-3.0i + 1.0j) m x [((-3.0i + 1.0j) m) ( -5.0j m/s)]

L₃ = 1.35 kg.m²/s

The angular momentum for three particles is 1.35 kg.m²/s.

For particle 4

The position vector is 4.01i m.

Substitute 0.40 kg from m₄, 4.0i m from r, and -4.0i m/s for v₄ in the expression of angular momentum

L₄ = (4.0i m) x [(0.40 kg) (-4.0i m/s)

L₄ = 0

The angular momentum for four particles is 0.

Part B

Formula used: L = L₁ + L₂ + L₃ + L₄

The total angular momentum of the four-particle system is calculated as follows:

By superposition principle

L = L₁ + L₂ + L₃ + L₄

L = -4.0 kg.m²/s + 0 + 1.35 kg.m²/s + 0

L = 0.95 kg.m²/s

Hence, the total angular momentum of the four-particle system is 0.95 kg.m²/s.

Your question is incomplete but most probably your full question was:

Suppose the particles in the preceding problem have masses m₁ =0.10 kg, m₂=0.20 kg, m₃ = 0.30 kg, m₄ = 0.40 kg. The velocities of the particel are  v₁= 2.0i m/s,v₂= (3.0i - 3.0j) m/s,  v₃= - 1.5j m/s,  v₄= -4i m/s.

(a) Calculate the angular momentum of each particle about the origin.

(b) What is the total angular momentum of the four-particle system about the origin?

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Suppose The Particles In The Preceding Problem Have Masses The Velocities Of The Particles Are (a) Calculate

Related Questions

find the value of e, the margin of error, for c = 0.99, n = 16 and s = 2.6.

Answers

The margin of error is 3.96.

The value of e, or the margin of error, can be calculated using the formula:

e = z*(s/√n)

where:

z = the critical value from a standard normal distribution table (for c = 0.99, z = 2.576)

s = the sample standard deviation (in this case, s = 2.6)

n = the sample size (in this case, n = 16)

So, to find the margin of error for this scenario, we plug the given values into the formula:

e = 2.576*(2.6/√16) = 2.576*(2.6/4) = 2.576*0.65 = 3.96

Therefore, the margin of error is 3.96.

It's worth noting that this value represents the range within which we expect the true population value to fall with a certain level of confidence

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If A and B are non-zero vectors, is it possible for A×B and A·B both to be zero?

Answers

It is important to note that the dot product and cross product of any two non-zero vectors cannot both be zero therefore  A×B and A·B cannot both be zero.

What are non-zero vectors?

In vector space, a non-zero vector. V is a vector that differs from the zero vector in V. If u is a non-zero vector in V and an is a scalar, i.e. an element of the field over which V is defined, then au=0 is only possible if a=0.

The product of any two non-zero vectors is non-zero in this vector context. It is referred to as Hamilton's Quaternions. Over the real numbers, quaternions form a four-dimensional vector space, and their multiplication is a combination of dot product and cross product.

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How can we determine the change in internal energy of a system?

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The greater the mass of an object, the more particles there are in the sample and the more thermal energy it possesses at the same temperature. Assume you have some boiling hot water at 100 degrees Celsius to demonstrate this concept.

The energy contained inside a thermodynamic system is quantified as the quantity of energy required to get the system from its standard internal state to its current internal state of interest, accounting for energy gains and losses owing to changes in its internal state, including magnetization.  

It eliminates the kinetic energy of motion and the potential energy of the system's overall location in relation to its surroundings and external force fields.

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Impulse is ________. View Available Hint(s)for Part A the time interval that a force lasts. the area under the force curve in a force-versus-time graph. a force that is applied very suddenly. a force that is applied at a random time.

Answers

The area below the force curve on a force versus time graph is known as the impulse.

The concept of "impulse" refers to how much of an impact a force has over time. The cricket batsman striking the ball is one of the most well-known and frequently used illustrations. The bat significantly changes the ball's trajectory despite making contact with it for a relatively brief period and launching a bicycle. Everyone occasionally makes rash decisions, particularly when we're young. In general, as we get older, we learn to control our urges. It might or might not be a sign of a problem. A mental health concern may be indicated by persistently impulsive behavior.

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An airplane starts from rest and accelerates at a constant 3.00 m/s2 for 30.0 s before leaving the ground. a. How far did it move

Answers

The airplane that starts from rest and accelerates at 1 constant 3 m/s2 for 30 s before leaving the ground moved by the distance of 1350m.

Acceleration is given as 3.00 m/s2

Time is 30 sec.

The formula we can use in this case is:

s = ut + 0.5 at^2

v = at + u

where,

s is distance travelled

u is initial velocity = 0 since at rest

t is time travelled

a is acceleration

v is the final velocity when it took off

a. s = 0 + 0.5 * 3 * 30^2

s = 1350 m

The distance moved by the airplane is 1350 m.

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calculate the frequency of the red light emitted by a neon sign with a wavelength of 659.9 nm.

Answers

The frequency of the red light emitted by a neon sign with a wavelength of 659.9 nm is 4.5×10^14 Hz.

What is the frequency?

The frequency is the number of times a recurring occurrence takes place during a predetermined period. For example, if an event occurs twice in one second, then the frequency is 2 Hz (Hertz).

A recurring event's frequency is the number of times it happens in a predetermined period. For example, a frequency of a wave is the number of wave peaks passing a fixed point in one second.

The frequency is the number of times something occurs in a given period. For example, the frequency of a radio station is the number of times it broadcasts a signal per second.

Given:

Wavelength = 659.9nm

Speed of light = 3×10^8 m/s

Frequency = speed of light / wavelength

Frequency = (3.0 x 10^8 m/s) / (659.9 nm)

Frequency = 4.5 x 10^14 Hz

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Suppose you have a set of spheres of various sizes. The formula below shows a possible relationship between the surface area (S) and volume for the spheres (V).

Answers

The formula that shows the relationship between the surface area (S) and volume (V) for spheres is S = 4πr² and V = (4/3)πr³ where r is the radius of the sphere.

This formula shows that the surface area of a sphere is directly proportional to the radius squared, and the volume is directly proportional to the radius cubed. This means that as the radius of a sphere increases, the surface area and volume will increase at a much faster rate. For example, a sphere with a radius of 2 will have four times the surface area and eight times the volume of a sphere with a radius of 1.

The question is incomplete, hence the answer is general.

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The hammer throw is a track-and-field event in which a 7.1-kg ball (the ''hammer''), starting from rest, is whirled around in a circle several times and released. It then moves upward on the familiar curving path of projectile motion. In one throw, the hammer is given a speed of 26.0 m/s. For comparison, a .22 caliber bullet has a mass of 2.6 g and, starting from rest, exits the barrel of a gun with a speed of 403 m/s. Determine the work done to launch the motion of both the hammer and the bullet.

Answers

The work done to launch the motion of both the hammer and the bullet are 3.1×10³ Joule and 2.2×10² Joules respectively.

As we know,

Work = Kinetic Energy

         = (0.5)(mv^2)

For Work in Joules, the mass is in units of Kg, and the velocity is in units of m/s.

KE(hammer) = 1/2mv^2 = 1/2 x 7.3 x (29)^2 = 3.1 x 10^3 J

and KE(bullet) = 1/2mv^2 = 1/2 x 2.6 x 10^-3 x (410)^2 = 2.2 x 10^2 J

To solve this problem, we must assume that energy is conserved. (This isn't stated in the problem, and is not true in general in these real-world examples, however we must assume conservation of energy in order to solve the problem with the information given).

When an object moves while a force is being exerted on it, then work is being done on the object by the force. If an object moves through a displacement d while a constant force F is acting on it, the force does an amount of work equal to W = F · d = F d cos φ where φ is the angle between d and F.

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Ms. Estes shows her class a video from when she worked at the space center launching rockets. She asks her students which of the following items in the video were examples of Newton's first law of motion? (1 point)

-- The rocket accelerating rapidly off the launch pad
-- The astronaut being pushed back into his seat as the rocket accelerates
-- The astronaut experiencing zero gravity in orbit
-- The booster rocket falling back into the ocean after the launch

Answers

The astronaut being pushed back into his seat as the rocket accelerates - this was the  example of Newton's first law of motion.

What is Newton's first law of motion?

According to Newton's First Law, a body in uniform motion or at rest will remain in that state up to and unless a net external force acts on it.

When the astronaut  worked at the space center launching rockets, no force is worked on him. When the rocket accelerates, according to  Newton's first law of motion, the astronaut remains in same motion, that's why, he pushed back into his seat .

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At t = 0, a wheel rotating about a fixed axis at a constant angular acceleration of -0.40 rad/s2 has an angular velocity of 1.5 rad/s and an angular position of 2.3 rad. what is the angular position of the wheel at t = 2.0 s?

Answers

At t = 0, the wheel has an angular position of 2.3 rad and an angular velocity of 1.5 rad/s.

Since the wheel is rotating about a fixed axis at a constant angular acceleration of -0.40 rad/s2, we can use the equation for angular position to calculate the wheel's angular position at t = 2.0 s.

Angular position = initial angular position + (initial angular velocity × time) + (1/2 ×angular acceleration ×time²)

Angular position at t = 2.0 s = 2.3 rad + (1.5 rad/s × 2.0 s) + (1/2 ×-0.40 rad/s2 × (2.0 s)²)

Angular position at t = 2.0 s = 2.3 rad + 3.0 rad + -1.6 rad

Angular position at t = 2.0 s = 3.7 rad

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8. Jax bounced a dodgeball off a wall. The dodgeball has a momentum of 32. 6 kg · m/s after the

collision. What is the total momentum of the system before the collision?

Answers

32. 6 kg m/s will be the total momentum of the system before the collision.

What does "collision" mean?

In physics, a collision is any circumstance in which two or more bodies rapidly apply forces to one another.

Despite the fact that the most common usage of the word "collision" relates to instances in which two or more objects smash violently, the scientific usage of the word makes no such assumptions.

If most or all of the total kinetic energy from the collision is lost (dissipated as heat, sound, etc., or absorbed by the objects themselves), the collision is said to be inelastic; such collisions result in the objects coming to a complete stop. A collision involving a car serves as an example of this type of collision since cars fold inward rather than colliding with one another.

Briefing:

pf = Final momentum of the system = 32.6 kg m/s

According to the principle of conservation of angular momentum we have

pi = pf => pi = 32.6 kg m/s

The wall is not moving so the initial and final momentum of the system are equal.

Therefore, the total momentum of the system before the collision is 32.6 kg m/s

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What happens to the magnitude of the torque if the angle increases toward 90?

Answers

The magnitude of the torque will increase as the angle between the force and the line of action of the torque approaches 90 degrees.

Torque is a measure of the rotational force acting on an object and is defined as the product of the force and the distance from the axis of rotation to the point where the force is applied. The torque is also proportional to the sine of the angle between the force and the line of action of the torque.

When the angle between the force and the line of action of the torque is 0 degrees, the torque is zero, as the force is acting in the same direction as the line of action of the torque. As the angle increases, the torque increases and reaches its maximum value when the angle is 90 degrees, at this point the sine of the angle is 1, so the torque is at its maximum value.

In practical terms, if you imagine a door knob, when you push or pull the door knob closer to 90 degree angle with the door, it will be harder to open or close the door, than when you push or pull the door knob at a small angle.

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What is Accenture doing for sustainability?

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By calculating carbon emissions reduction and sustainability index improvement, the Accenture MyNav Green Cloud Advisor incorporates sustainability when moving client data centers to the cloud.

The availability of computer system resources without the user having to manage them directly is referred to as cloud computing. The network of remote servers located on the internet in this instance aids in the management and storage of the data.

Mynav Green Cloud Advisor is essential since it aids businesses in creating cloud solutions that may be utilized to lower carbon emissions.

As cloud solutions are essential to businesses, Accenture MyNav Green Cloud Advisor integrates sustainability.

reduces the expense of transportationcreates a design that is appropriate and aids the customer in becoming more sustainable.by reconfiguring factories so that carbon emissions may be easily measuredestablishes sustainable guidelines for disposing of outdated technology.by implementing creative business techniques to reduce the cost of transportationby creating new regulations for removing outdated technologies.

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If an object was traveling horizontally off a cliff at 6 m/s for 3 seconds, how long did it take to
hit the ground?

Answers

The time taken by the object to hit the ground is 1.8 seconds.

What do you mean by gravitational force?

The attraction that draws two objects together is known as gravitational force, sometimes referred to as gravity. Every mass-containing object pulls on nearby things gravitationally in a sizable way.

The time it takes for an object to hit the ground after being dropped off a cliff can be calculated using the formula:

t = √(2*d/g)

where t is the time, d is the distance fallen, and g is the acceleration due to gravity.

In this case, we don't know the distance fell, but we can use the horizontal velocity and time of travel to find it:

d = v * t

where v is the velocity (6 m/s), and t is time (3 seconds)

d = 6 * 3 = 18 m

Now we can use the distance fallen to calculate the time it takes to hit the ground:

t = √(2*d/g)

g is approximately 9.8 m/s^2

t = √(2*18/9.8) = √ (3.6) = 1.8 seconds

So, it takes 1.8 seconds for the object to hit the ground after traveling horizontally off a cliff at 6 m/s for 3 seconds.

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Please explain what the above equation shows and justify your answer. Does this equation prove that gamma radiation cannot be produced by this type of nuclear decay? Please explain your answer.

Answers

This is not a gamma radiation because there is a change in the atomic number of the daughter nucleus. It is rather a beta decay.

What is a nuclear decay?

We have to note that when we talk about a decay we are talking about the manner that we can be able to break up the atom of a radioactive substance so that we can be able to produce a new substance.

We can see now that what we have here is the loss of a beta ray or an electron from the specie that is shown. This is evidenced by the change in the atomic number of the daughters nucleus.

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What does an increases in concentration do to a material?

Answers

Answer:

it will increase the frequency of collisions between the two reactants

Explanation:

mark brainliest?

Matt i a 85kg lifeguard, he lide down a water lide that i inclined at 35 degree to the horizontal into a wimming pool. If the coefficient of kinetic friction of the lide i 0. 9. What i Matt’ rate of acceleration a he goe down the lide

Answers

The rate of acceleration at which Matt goes down the slide is equal to 5.32 m/s².

The normal force or [tex]F_{N}[/tex] acts perpendicular to the object.

The angle of inclination = 35°

cosθ = [tex]F_{N}[/tex]/mg

 [tex]F_{N}[/tex] = mgcosθ = 85 × 10 × cos 35

= 850 × 0.819 = 696.15 N

To find the force of friction,

μ = 0.050

[tex]F_{f}[/tex] = μ × [tex]F_{N}[/tex]

= 0.050 × 696.15 = 34.80 N

To find the downward component of weight that pulls him down the slide.

sinθ = [tex]F_{d}[/tex]/mg

[tex]F_{d}[/tex] = mgsinθ

= 85 × 10 × sin35

= 850 × 0.5736 = 487.56 N

To find the acceleration,

[tex]F_{net} = F_{d} - F_{f}[/tex]

 = 487.56 - 34.80 = 452.76 N

To solve for acceleration,

F = force = 452.76 N

m = mass = 85 kg

Force = mass × acceleration

a = F/m = 452.76/85 = 5.32 m/s²

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What is the formula to calculate torque?

Answers

Torque =   force x distance from point of rotation

Torque is a measure of the turning effect of an applied force about a specific point or axis. It is calculated by multiplying the force applied to an object by the distance from the point of rotation to the point where the force is applied. The greater the force or the longer the distance from the point of rotation, the greater the torque. The unit of torque is typically Newton-meters (N·m) in the International System of Units (SI) or pound-feet (lb·ft) in the imperial system. Torque is essential in various fields such as physics, mechanics, engineering and robotics.

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1. Calculate the size of the gravitational pull of a sphere of mass 10 kg on a mass 2.0 kg. When their
centres are 200 mm apart. What is the force of the 2.0 kg mass on the 10 kg mass?

Please answer with an explanation if you can!!!

Answers

Explanation:

Let a be the sphere of mass 10 kg and b be the sphere of mass 20 kg. According to Newton's universal law of gravitation, the gravitational force of a on b is expressed as:

F

a

b

=

G

m

M

d

2

, where:

G

=

6.67

×

10

11

N

m

2

/

k

g

2

is the gravitational constant

m = 2 kg is the mass of a

M = 10 kg is the mass of b

d = 0.2 m is the separation between the two spheres

So:

Fab=GmMd26.67

×

10

11

×

2

×

10

0.2

2

CAN SOMEONE PLEASE ANSWER THESE 4 QUESTIONS I WILL NEED IT IN A FEW HOURS , YOU WILL GET BRAINLIEST!!

1.) Compare reflection and refraction. How are they similar and how are they different?

2.) In your own words, describe how ray diagrams can be used to describe if light rays are being reflected or refracted.

3.) What is the formula for the Law of Reflection? Define the variables and explain what it tells us about the motion of light.

4.) What is the formula for Snell's? Define the variables and explain what it tells us about the motion of light.

Answers

Answer:

1.)Reflection is the act of light reflecting back when it hits a medium on a plane. Refraction is the process by which light shifts its path as it travels through a material, causing the light to bend. Thus, this is the key difference between reflection and refraction. This phenomenon usually occurs in mirrors.

2.)ray diagrams are a visual representation of the propagation of light. They can help us to understand and visualise multiple situations, such as light being reflected off of a mirror or changing its direction while moving through a lens.

3.)Reflection: The process of sending back the light rays which fall on polished surface is called reflection of light.

Laws of reflection:

(i) The angle of reflection is always equal to the angle of incidence.

(ii) The incident rays, reflected rays and the normal, all lie in the same plane.

4.)Snell’s law formula is expressed as: μ= sin i/sin r

, where i is the angle of refraction, r is the angle of refraction and μ is known as the refractive index of the second medium with respect to the first medium.

How is torque calculated using the moment arm?

Answers

Torque is calculated using the moment arm is Torque =Lever Arm x Fy (or Force sin( )) Torque = Force (Fm) x Moment Arm.

How is torque moment calculated?

Calculating Torque: The formula for torque is =|r| |F|sin = | r | | F | sin, where |r| is the size of the lever arm, |F| is the size of the force vector, and is the angle created between the two vectors.

Is torque equivalent to the moment arm?

In mechanics, they have slightly different meanings but the same meaning in physics. The moment is a static force, whereas the torque is a moving force, even though they both have the same unit, N-m. Torque is utilized when there is rotation, whereas moment is used when there isn't.

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If you rub an air filled balloon on your hair it is possible to stick on the wall and have it statically remain there. Explain how this is possible and be sure to answer the following questions in your explanation: (A) is the balloon a conductor or an insulator? (B) is the wall a conductor or an insulator?

Answers

The balloon will be drawn to the wall once it has been rubbed sufficiently to build up a sufficient negative charge. Even though the wall should generally be neutrally charged, its charges can change, causing a positively charged region to pull the negatively charged balloon toward it.

The balloon gains electrons when it is rubbed against your hair or a piece of wool cloth, making it negatively charged. Once charged, the two balloons will move away from one another because like charges repel and like charges attract (the paper will be attracted to the charged balloons.)The pull of an electrostatic force is what keeps the ball clinging to the wall.The balloon becomes charged when we rub it with a synthetic cloth, and when it is brought close to a wall, the electrostatic force causes it to be drawn to the neutral wall.

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How is Pythagorean Theorem used in baseball?

Answers

Bill James came up with the Pythagorean Theorem of Baseball, which connects the amount of runs a club has scored and given up to its actual winning %.

Its uses are:

The Pythagorean Theorem is the idea that a baseball team's record may be roughly estimated by taking the square of team runs scored and dividing it by the square of team runs scored plus the square of team runs allowed. Bill James, a baseball analyst, made this idea famous.

The Pythagorean Winning % approach uses the relationship between a team's victories and losses and the number of points scored and allowed to calculate the predicted winning percentage. To follow Pythagorean winning percentages for the seasons, consult the team statistics.

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a telescope searching for newly formed stars would make the most discoveries if it were pointed

Answers

Yes, the center of the Milky Way is the most densely populated area of stars, and is therefore the most likely region to find newly formed stars.

What is the populated?

Populated refers to an area that has a large number of people residing in it. It is usually used to describe cities, towns, or other densely populated areas. Populated areas usually contain a variety of services and infrastructure to support their populations, such as schools, hospitals, transport links, and other amenities. Populated areas usually have higher rates of crime, pollution, and other problems associated with increased human activity.Populated refers to an area that has a high density of people living in it. It is usually used to describe cities and towns, but can also describe smaller areas, like neighborhoods.

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How long would it take for a falling object to reach a final velocity of 147 m/s?

Answers

Answer:

15 seconds :)

Explanation:

A plane flying at the speed of 150. M/s is accelerated uniformly at a rate of 5. 00 m/s^2


a. What is the plane's speed at the end of 10. 0 seconds?

b. What distance has it traveled?

Answers

The plane's speed at the end of 10.0 seconds is 200 m/s and the distance it has travelled is 1750 meters.

The initial speed of the plane, u = 150 m/s

Acceleration of the plane, a = 5 m/s²

Time, t = 10 sec

We can find the plane's speed at the end of 10. 0 seconds by the formula

a = (v - u)/ t

⇒5 = (v - 150)/ 10

⇒50 = v - 150

⇒v = 150 + 50

⇒v = 200 m/s

Now, to find the distance it has travelled we will use the kinematic equation

v² = u² + 2as

⇒200² = 150 ² + 2 × 5 × s

⇒40000 = 22500 + 10s

⇒17500 = 10 s

⇒s = 1750 m

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In an electrical circuit, two resistors of 2Ω & 4Ω have been connected in series to a 6V battery. The heat dissipated by the 4Ω resistor in 5s will be

Answers

R= 2+4=6Ω

in series connection, same current and different voltage

total voltage= total current × total resistance

6=I×6

I=6/6= 1A

voltage across 4Ω resistor= 1×4=4v

Therefore, heat dissipated by the 4Ω resistor in 5s= (v²/R)×t= (4²/4)× 5 = 16/4 × 5 = 20J

What did Galileo discover when he dropped two cannon balls into f different weights from the leaning tower of pisa

Answers

Answer: The time it took for them to fall ere the same.

Explanation:

The only difference was because of resistance, weight doesn't affect the speed of gravity, the speed of gravity stays the same (9.801 meters per second)

An electron is projected with an initial speed v0 = 1. 10106m/s into the uniform field between the parallel plates in the figure. Assume that the field between the plates is uniform and directed vertically downward, and that the field outside the plates is zero. The electron enters the field at a point midway between the plates.


(a)If the electron just misses the upper plate as it emerges from the field, find the magnitude of the electric field.


(B) suppose that in the figure, the electron is replaced by a proton with the same initial speed. Would the proton hit one of the plates?


(c) what would be the direction of proton's displacement? upward or downward?


(d) compare the paths traveled by the electron and the proton and explain the differences

Answers

The electron feels a force upward as it passes between the charged plates and narrowly avoids striking the top plate. It just misses the to plate by a small amount as it moves higher.

The explanation for the above answer:

The proton will accelerate less and miss the plates since it is more massive. We once more utilise the kinematic equation to determine the vertical displacement when it occurs for the plates.

y=1/2at²=1/2eE/mp(1.25×10-8s)

² \s=2.73×10-6m

As stated in (b), the proton won't collide with one of the plates because, despite the fact that the electric force felt by the proton and the electrons is identical, the electric force produces a smaller acceleration than g, making it plausible to disregard gravity.

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A 200-kg crate is pushed horizontally with a force of 720 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate.

Answers

1.54 is the acceleration of the crate. The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.

Acceleration is proportional to the net force.

That acceleration is proportional to the net force and inversely proportional to the mass of the object. It can be expressed with the formula: Where, Fn = Net force, m  = mass. The m=200 kg crate is pushed horizontally with a force Fa=700 N. The friction force opposes the motion and a horizontal net force appears causing the acceleration.

Forces in the vertical direction?

The forces in the vertical direction are in balance since the crate does not accelerate in that direction, thus the weight and the normal force are equal: N = W = mg, The friction force can be calculated by using the coefficient of friction μ: μ*n. Calculating the normal force: N = 200 * 9.8 = 1,960 N. The friction force is f=0.2*1960, f=392. The horizontal net force is 308. Finally, the acceleration is computed: m/s^2

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