Express 60g as a percentage of 3kg?

Answers

Answer 1

Answer:

SOLUTION IS ON PICHOPE IT HELPS YOUMARK AS BRAINLIST ANSWER
Express 60g As A Percentage Of 3kg?

Related Questions

What percent is represented by the shaded area?

Answers

Answer:91%

Step-by-step explanation:

verify that :- 5/8x(7/9-11/6)=(5/8x7/9)-(5/8x11/6)

please answer​

Answers

The distributive law states that a(b - c) = ab - ac
In this example a = 5/8, b = 7/9 and c = 11/6

Over which interval does f have an average rate of change zero?
A. -3≤x≤5
B. -5≤x≤3
C. 2≤x≤4
D. -3≤x≤-1

Answers

Answer:

Step-by-step explanation:

The average rate of change is the slope. Slope has a formula that is the change in y over the change in x, which is a fraction. The only time a fraction can have a vlue of 0 is where the numerator of the fraction is equal to 0 (since we are not allowed to have a denominator of 0). If the change in y is in the top of the slope fraction, then we have to find the interval where the y values are the same. I'll show you one where the y values are not the same so you can compare it to the slope where the y values are the same. We will find the slope of choice A.

When x = -3, y = 0 so the coordinate is (-3, 0).

When x = 5, y = 5 so the coordinate is (5,4). Now let's find the slope (aka average rate of change) between those 2 coordinates:

[tex]m=\frac{4-0}{5-(-3)}=\frac{4}{8}=\frac{1}{2}[/tex]  and the top of the fraction is a 1, not a 0, so the average rate of change between these 2 points is 1/2, not 0. Now let's do D.

When x = -3, y = 0 so the coordinate is (-3, 0).

When x = -1, y = 0 so the coordinate is (-1, 0). The slope between these 2 points is

[tex]m=\frac{0-0}{-1-(-3)}=\frac{0}{2}=0[/tex] This fraction is equal to 0 because the numerator is 0. Choice D is the one you want.

Why is making a record of withdrawals and deposits in your checkbook register a good practice?

Answers

Answer:

it helps you balance your checkbook

Step-by-step explanation:

Balancing your checkbook means that you do a check in your account that shows how much money is available.

I hope it helps❤️

Question 9 Multiple Choice Worth 1 points)
(01.06 MC)
Solve the following equation for x: 2x + 5y = 8.

Answers

Answer:

x = 4 - 5/2 y

Step-by-step explanation:

2x + 5y = 8.

Subtract 5x from each side

2x + 5y -5y = 8-5y

2x = 8 -5y

Divide each side by 2

2x/2 = (8-5y)/2

x = 4 - 5/2 y

Answer:

x=[tex]\frac{-5y}{2}[/tex]+4

Step-by-step explanation:

Hi there!

We're given the equation 2x+5y=8 and we want to solve it for x

as we don't know the value of y, x won't actually be a number (it'll be an expression instead). However, we will solve this as if it was a regular equation by isolating x onto one side

here's the given equation

2x+5y=8

start by subtracting 5y from both sides

2x=-5y+8

divide both sides by 2

x=[tex]\frac{-5y}{2}[/tex]+4

Hope this helps!

In a 45-45-90 right triangle, what is the ratio of the length of one leg to the length of the other leg? O A. sqrt2:1 O B. 1:1 Oc. C. 2:1 O D. 1:sqrt2​

Answers

B, they are the same length

Answer:

B. 1 : 1

Step-by-step explanation:

the triangle has the same size of legs (the same angles 45°)

The sides of a number cube are labeled 1 through 6.
Suppose you toss the cube 600 times. About how many times
would you expect the cube to land on 1?

Answers

Answer:

100 times for 1

Step-by-step explanation:

If the cube is a fair one, you would expect it to land on each number about 1/6 of the time. Since 1 is one of the faces, you would expect to land on it 1/6 of the time.

(1/6)*600=100

So any number should land 100 times

Use the following number line to determine if the expressions are true or false.

Answers

Answer:

[tex]{ \tt{a < b→true}} \\ { \bf{reason :because \: - 1 \: is \: less \: than \: 4.5 }}\\ \\ { \tt{ |a| > b →false}} \\ { \bf{reason :1 \: is \: not \: greater \: than \: 4.5 }}\\ \\ { \tt{a < |b| →true}}[/tex]

Answer:

true

false

true

Step-by-step explanation:

Grade 10 Math. Solve for y. Will mark right answer brainliest :)​

Answers

Answer:

y=5, y=[tex]\frac{38}{11}[/tex]

Step-by-step explanation:

Hi there!

We are given the equation

[tex]\frac{y+2}{y-3}[/tex]+[tex]\frac{y-1}{y-4}[/tex]=[tex]\frac{15}{2}[/tex] and we need to solve for y

first, we need to find the domain, which is which is the set of values that y CANNOT be, as the denominator of the fractions cannot be 0

which means that y-3≠0, or y≠3, and y-4≠0, or y≠4

[tex]\frac{y+2}{y-3}[/tex] and [tex]\frac{y-1}{y-4}[/tex] are algebraic fractions, meaning that they are fractions (notice the fraction bar), but BOTH the numerator and denominator have algebraic expressions

Nonetheless, they are still fractions, and we need to add them.

To add fractions, we need to find a common denominator

One of the easiest ways to find a common denominator is to multiply the denominators of the fractions together

Let's do that here;

on [tex]\frac{y+2}{y-3}[/tex], multiply the numerator and denominator by y-4

[tex]\frac{(y+2)(y-4)}{(y-3)(y-4)}[/tex]; simplify by multiplying the binomials together using FOIL to get:

[tex]\frac{y^{2}-2y-8}{y^{2}-7y+12}[/tex]

Now on [tex]\frac{y-1}{y-4}[/tex], multiply the numerator and denominator by y-3

[tex]\frac{(y-1)(y-3)}{(y-4)(y-3)}[/tex]; simplify by multiplying the binomials together using FOIL to get:

[tex]\frac{y^{2}-4y+3}{y^{2}-7y+12}[/tex]

now add [tex]\frac{y^{2}-2y-8}{y^{2}-7y+12}[/tex] and [tex]\frac{y^{2}-4y+3}{y^{2}-7y+12}[/tex] together

Remember: since they have the same denominator, we add the numerators together

[tex]\frac{y^{2}-2y-8+y^{2}-4y+3}{y^{2}-7y+12}[/tex]

simplify by combining like terms

the result is:

[tex]\frac{2y^{2}-6y-5}{y^{2}-7y+12}[/tex]

remember, that's set equal to [tex]\frac{15}{2}[/tex]

here is our equation now:

[tex]\frac{2y^{2}-6y-5}{y^{2}-7y+12}[/tex]=[tex]\frac{15}{2}[/tex]

it is a proportion, so you may cross multiply

2(2y²-6y-5)=15(y²-7y+12)

do the distributive property

4y²-12y-10=15y²-105y+180

subtract 4y² from both sides

-12y-10=11y²-105y+180

add 12 y to both sides

-10=11y²-93y+180

add 10 to both sides

11y²-93y+190=0

now we have a quadratic equation

Let's solve this using the quadratic formula

Recall that the quadratic formula is y=(-b±√(b²-4ac))/2a, where a, b, and c are the coefficients of the numbers in a quadratic equation

in this case,

a=11

b=-93

c=190

substitute into the formula

y=(93±√(8649-4(11*190))/2*11

simplify the part under the radical

y=(93±√289)/22

take the square root of 289

y=(93±17)/22

split into 2 separate equations:

y=[tex]\frac{93+17}{22}[/tex]

y=[tex]\frac{110}{22}[/tex]

y=5

and:

y=[tex]\frac{93-17}{22}[/tex]

y=[tex]\frac{76}{22}[/tex]

y=[tex]\frac{38}{11}[/tex]

Both numbers work in this case (remember: the domain is y≠3, y≠4)

So the answer is:

y=5, y=[tex]\frac{38}{11}[/tex]

Hope this helps! :)

b) 6 x (5 + 4) 1) 32 - (14 - 6) X 3 35 - {15 - (19 + 5)=3} 1) 5 {13 + 12 + 3 (2 x 2)​

Answers

Answer:

your answer is 1275

Step-by-step explanation:

ccifufbfjrorwfeejeidiffgfkxxocyegdo

The correct answer is 1275
Incorrect answer being 1274
Followed by 1276

Or/ :)

5.
The cube root for three hundred and forty three is
Punca kuasa tiga bagi tiga ratus empat puluh tiga adalah
A. 343
B. 73
C. 3433
D. 7​

Answers

D. 7

Hope this helps! :)

______________

Answer:

The cube root of 343 is 7.

the bag of skittles has 3 parts red skittles , 5 parts yellow skittles and 7 parts orange skittle. Represent this ratio three ways;visually, using ratio notation and using fraction notation

Answers

Step-by-step explanation:

Given that,

The bag of skittles has 3 parts red skittles, 5 parts yellow skittles and 7 parts orange skittle.

Ratio notation is= 3:5:7

Frction notation,

Red skittle[tex]=\dfrac{3}{3+5+7}=\dfrac{1}{5}[/tex]

Yellow skittle [tex]=\dfrac{5}{3+5+7}=\dfrac{1}{3}[/tex]

Orange skittle [tex]=\frac{7}{3+5+7}=\dfrac{7}{15}[/tex]

Hence, this is the required solution.

Determine whether the triangles are congruent. Explain your reasoning .
SAS (Side, Angle, Side) or ASA (Angle, Side, Angle)

Answers

Answer:

Step-by-step explanation:

First use the fact that the sum of interior angles of a triangle is 180° to find the measure of the missing angle

in ΔDEF we have 180 -68 -81 = 31°

in ΔABC we have 180 -68 -33 = 79°

the measure of the angles in ΔABC and ΔDEF are different 33°, 68°, 79° ≠81°, 68°, 31°so the two triangles are not congruent.


Round to 3 SF
0.0692494

Answers

rounding 0.0692494 to 3SF is 0.069

The first three significant digits are 692
Rounding 0.0692494 = 0.0692 (3 sf)

A rectangular vegetable farm measures 45 m by 15 m. It has also a path of 1m wide. What is the area of the path?​

Answers

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]

A rectangular vegetable farm measures 45 m by 15 m. It has also a path of 1m wide. What is the area of the path?

[tex]\underline{\sf{\red{Formula\:for\: area\: of \:rectangular\: form:}}}[/tex]

[tex]\quad\quad\quad\quad\boxed{\sf{\red{➢} \: \sf{a=l×b}} }[/tex]

[tex]\underline{\sf{\red{Given:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{Length\:of\:rectangular\:form = 45m} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{Breadth\:of\:rectangular\:form = 15m} }[/tex]

[tex]\underline{\sf{\red{Solution:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=l×b} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=45m×15m} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=\boxed{\sf{{675m}^{2}}}} }[/tex]

[tex]\underline{\sf{\red{For\:rectangular\: form\:with\:path:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{Length\:of\:rectangular\:form = 45m+2=47m} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{Breadth\:of\:rectangular\:form = 15m+2=17m} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=l×b} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=47m×17m} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=\boxed{\sf{{799m}^{2}}}} }[/tex]

[tex]\huge\underline{\sf{\red{Area\:of\:path:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a={799m}^{2}-{675m}^{2}} }[/tex]

[tex]\quad\quad\quad\quad\boxed{\sf{\red{➢} \: \sf{a={124m}^{2}} }}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad\quad\underline{\boxed{\sf{\red{a={124m}^{2}} }}}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex]\sf{\red{︎✰}ShineBrighter\red{︎✰}}[/tex]

[tex]\sf{✍︎ C.Rose\red{❀}}[/tex]

ฅ^•ﻌ•^ฅ

The spinner depicted is a fair spinner. The spinner is least likely to land on which number?




A 1

B 2

C 3

D It is impossible to tell.

Answers

D is the correct answer.

Answer:

d

Step-by-step explanation:

it is impossible to tell since no numbers were given nor signs were offered to help us know whether we are dealing with additon , subtraction , multiplication or division

HELPPP ASAPPP PLAESE HELPP

Answers

2 3 1 hope this helps

Answer:

first question answer is step 2 and second step is answer step 3, last one is step is answer step 1

add 8/9 + 7/9 Simplify the answer and write as a mixed number.

Answers

Answer:

[tex]1\frac{6}{9}[/tex]

Step-by-step explanation:

[tex]\frac{8}{9}+\frac{7}{9}[/tex]

[tex]\frac{8+7}{9}=\frac{15}{9}=1\frac{6}{9}[/tex]

Name the marked angle in 2 different ways.

Answers

Answer:

∠XWV ∠UWV

Hope this helps! :)

PLEASE HELP WILL MARK BRAINLIEST - An airplane travels 150 miles horizontally during a decrease of 35,000 feet vertically.
1. What is the angle of descent?
2. How long is the plane's path?

Answers

Answer:

[tex]\text{1. }2.53^{\circ},\\\text{2. }792,772.98\:\mathrm{ft}[/tex]

Step-by-step explanation:

Start by converting miles to feet:

[tex]150\text{ miles}=150\cdot 5280\text{ feet}=792000\text{ feet}[/tex]

Form a right triangle with the plane's displacement marking the hypotenuse of this triangle. We can now use basic trig for a right triangle to solve for the angle of descent.

Let the angle of descent be [tex]\theta[/tex]. In a right triangle, the tangent of an angle is equal to its opposite side divide by its adjacent side.

Therefore, we have:

[tex]\tan \theta=\frac{35000}{792000},\\\\\theta =\arctan(\frac{35000}{792000})=2.53036411\approx \boxed{2.53^{\circ}}[/tex]

In all right triangles, [tex]a^2+b^2=c^2[/tex], where [tex]c[/tex] is the hypotenuse of the triangle and [tex]a[/tex] and [tex]b[/tex] are the two legs of the triangle (Pythagorean Theorem).

Therefore, the length of the plane's path is:

[tex]35,000^2+792,000^2=c^2,\\c^2=628489000000,\\c=\sqrt{628489000000}=792772.981376\approx \boxed{792,772.98\:\mathrm{ft}}[/tex]

Need help on this question asap pleasee

Answers

Answer:

B

Step-by-step explanation:

9 divided by 4, then multiply by 12

Answer:

y = 2.25(12)

Step-by-step explanation:

$9 for 4 pizzas

$9/4 = $2.25

$9 for 4 pizzas is the same ratio as $2.25 per 1 pizza

To deliver x number of pizzas, the charge, y, is

y = 2.25x

For 12 pizzas, the delivery charge is

y = 2.25(12)

Which multiplication equation is false?

A) (-a)*(-1)=(-a)

B) (-a)*0=0

C) (-a)*1=(-a)

D) (-a)*b=b*(-a)

Answers

Answer:

A is wrong

Step-by-step explanation:

Answer:

A(-a)*(-1)=(-a)

Step-by-step explanation:

Anything multiplied by 0 is 0. Therefore, option B is correct.

Option A is wrong because when multiplying two negatives you should get a positive not a negative.

Anything multiplied by 0 is 0. Therefore, option B is correct

Option C is correct because a negative times a positive gives a positive.

Option D is correct because you can't solve for different times being multiplied you can only combine like terms therefore your answer will equal the same result here.

Which of the following is NOT an example of a contract?

lease

credit card

borrowing lunch money

rental

Answers

Answer: “borrowing lunch money”

Explanation: The other options involve paperwork, whereas borrowing lunch money is more casual. Paperwork is not needed for borrowing lunch money.

Six oranges in a bag of 30 oranges are bad. Express the number of bad oranges as a fraction in its lowest terms​

Answers

Answer:

1

5

is the answer

Step-by-step explanation:

hope it helps you!

What is the area of the yellow region?

Answers

Answer:

195 sq cm

Step-by-step explanation:

15 x 15 = 225

----------------------

3(8) + 2(3) = 30

----------------------

225 - 30 = 195 sq cm

The area of the yellow region is the area of square minus 4 times the area of one half semicircle at the corner of the square. These four half semicircle will form a complete circle. This means that the area of 4 half semicircles is equal to the area of the circle.

Help please will be marked as brainliest if correct.

Answers

Answer:

5

Step-by-step explanation:

Greater than 0

Less than 100

Is not 4, but is greater than four

Is less than 5.5

Must be a whole number

5 is the only whole number between 4 and 5.5

I'LL MARK FIRST CORRECT ANSWER BRAINLIEST !!!

Faith makes greeting cards with colored paper. She plans to make 15 of the cards out of red paper. She has 25 sheets of colored paper in all. If she uses all the colored paper she has, how many sheets are a color other than red?

a. 5

b. 20

d. 25

c. 125


ps: any incorrect, irrelevant, plagiarized, or absurd, will be reported! sorry for the inconvenience !

Answers

It would be answer choice A or 5

if 2x + 3y = 12 and xy = 6, find the value of 8x^3 + 27y^3​

Answers

Answer:

The value of [tex]8\cdot x^{3} + 27\cdot y^{3}[/tex] is 432.

Step-by-step explanation:

Let be the following system of equations:

[tex]2\cdot x + 3\cdot y = 12[/tex] (1)

[tex]x\cdot y = 6[/tex] (2)

Then, we solve both for [tex]x[/tex] and [tex]y[/tex]:

From (1):

[tex]2\cdot x + 3\cdot y = 12[/tex]

[tex]2\cdot x = 12- 3\cdot y[/tex]

[tex]x = 6 - \frac{3}{2}\cdot y[/tex]

(1) in (2):

[tex]\left(6-\frac{3}{2}\cdot y \right)\cdot y = 6[/tex]

[tex]6\cdot y-\frac{3}{2}\cdot y^{2} = 6[/tex]

[tex]\frac{3}{2}\cdot y^{2}-6\cdot y + 6 = 0[/tex]

The roots of the polynomial are determined by the Quadratic Formula:

[tex]y_{1} = y_{2} = 2[/tex]

By (1):

[tex]x = 6 - \frac{3}{2}\cdot (2)[/tex]

[tex]x = 3[/tex]

If we know that [tex]x = 3[/tex] and [tex]y = 2[/tex], then the final value is:

[tex]z = 8\cdot x^{3}+27\cdot y^{3}[/tex]

[tex]z = 8\cdot 3^{3}+27\cdot 2^{3}[/tex]

[tex]z = 432[/tex]

The value of [tex]8\cdot x^{3} + 27\cdot y^{3}[/tex] is 432.

What is the range of the function on the graph?
у
5
all real numbers
3
2
all real numbers greater than or equal to 0
O all real numbers greater than or equal to 1
all real numbers greater than or equal to 2
1
1
-5 -4 -3 -2 -11 + 1 2 3 4 5 X
-2-
-3
4+

Answers

Answer:

D. all real numbers greater than or equal to 2

Step-by-step explanation:

Range values consists of all possible set of y-value plotted on the vertical axis. So, we are looking at the y-values on the y-axis (vertical axis).

The line starts at 2 on the y-axis. The shaded "o" means that 2 is included or the range of the function is 2 or above.

Thus, this means that:

the range of the function of the graph are "all real numbers greater than or equal to 2."

The Range of the function are all real numbers greater than or equal to 2

Range of a function

The Range of a function is the output values or values of the dependent variable of a function.

Since the y - axis represents the dependent variable, the Range of the function is the values of y given from the graph. The values of y given from the graph range from and include 2 to ∞. The value 2 is included since it is shaded.

So, the Range of the function are all real numbers greater than or equal to 2

Learn more about range of a function here:

https://brainly.com/question/6615538

What are the five key points that you need to find for any given set of numbers in order to draw a Box plot for the data. Write the answer. Help​

Answers

The five-number summary is the minimum, first quartile, median, third quartile, and maximum. In a box plot, we draw a box from the first quartile to the third quartile.

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