if we change the order of integration for the given integral, we obtain the sum of two integrals:
∫b_a∫g2(x)_g1(x) f(x,y)dydx + ∫d_c∫g4(x)_g3(x) f(x,y)dydx
where a = 0, b = 2
g1(x) = 0, g2(x) = √(4 - x²)
c = 0, d = 2
g3(y) = 0, g4(y) = √(4 - y)
To change the order of integration for the given integral, we first need to sketch the region of integration. The limits of x and y are given as follows:
0 ≤ y ≤ √(4 - y)
0 ≤ x ≤ 2
When we sketch the region of integration, we see that it is the upper half of a circle centered at (0, 2) with radius 2.
To change the order of integration, we need to find the limits of x and y in terms of the new variables. Let's say we integrate with respect to y first. Then, for each value of x, y varies from the lower boundary of the region to the upper boundary. The lower and upper boundaries of y are given by:
y = 0 and y = √(4 - x²)
Thus, the limits of x and y in the new order of integration are:
a = 0, b = 2
g1(x) = 0, g2(x) = √(4 - x²)
Now, we integrate with respect to y from g1(x) to g2(x), and x varies from a to b. This gives us the first integral:
∫b_a∫g2(x)_g1(x) f(x,y)dydx
Next, let's say we integrate with respect to x. Then, for each value of y, x varies from the left boundary to the right boundary. The left and right boundaries of x are given by:
x = 0 and x = √(4 - y)
Thus, the limits of x and y in the new order of integration are:
c = 0, d = 2
g3(y) = 0, g4(y) = √(4 - y)
Now, we integrate with respect to x from g3(y) to g4(y), and y varies from c to d. This gives us the second integral:
∫d_c∫g4(x)_g3(x) f(x,y)dydx
Therefore, if we change the order of integration for the given integral, we obtain the sum of two integrals:
∫b_a∫g2(x)_g1(x) f(x,y)dydx + ∫d_c∫g4(x)_g3(x) f(x,y)dydx
where a = 0, b = 2, g1(x) = 0, g2(x) = √(4 - x²), c = 0, d = 2, g3(y) = 0, and g4(y) = √(4 - y).
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what is the slope of -3x
Answer:
The slope is -3, in a y=mx+b equation the x coefficient is the slope
= {y: y is a multiple of 3, 5 < y < 10}
Answer:
Step-by-step explanation:
6 and 9
The design of a building that has a square pyramid roof as a roof is shown. The cost of material for the outside of the building and for the roof
ranges from $25 per square foot to $50 per square foot. The budget for this material is $500,000. The rectangular front of the building has a
length twice as long as its height. The slant height of the roof is the same as the height of the rectangular front of the building.
What is the maximum possible length of the rectangular front of the building to the nearest foot?
feet
The maximum possible length of the rectangular front of the building is
A. 164
B. 41
C. 82
D. 29
The maximum possible length of the rectangular front of the building is 23 feet
How to determine the maximum possible length?The complete question is attached
Let the length of the rectangular front be x and the height be y.
So, we have:
x = 2y
The building has 4 congruent sides.
So, the area of the 4 sides is
A = 4 * (x * y)
This gives
A = 4 * (x * 2x)
Evaluate
A = 8x²
For the triangular roof, we have:
Slant height, l = y
Base, b = x
So, the area of the 4 triangular faces is
A = 0.5 * 4 * xy
This gives
A = 2xy
Recall that:
x = 2y
Make y the subject
y = 1/2x
So, we have:
A = 2x * 1/2x
A = x²
The cost of designing the buildings is
C = 25 * 8x² + 50 * x²
C = 200x² + 50x²
C = 250x²
This gives
250x² = 500000
Divide both sides by 250
x² = 2000
Square both sides
x = 45
Recall that:
y = 1/2x
This gives
y = 1/2 * 45
y = 23
Hence, the maximum possible length of the rectangular front of the building is 23 feet
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Line A is perpendicular to Line B.
If the slope of Line A is
-1/7
what is the slope of Line B?
[?]
Answer:
7
Step-by-step explanation:
Perpendicular lines have slopes that are negative reciprocals of each other. For example, if line A has a slope of 2, then line B, perpendicular to line A, will have a slope of -0.5.
What is the measure of b 35 right angle
Answer:
acute angle and angle between zero and 90 degrees right angle and 90 degree angle obtuse angle and angle between 90 and 180
Answer:
what kind of people are the best division
11. (04.01 MC)
Choose the system of equations that matches the following graph: (1 point)
The linear functions that match the following graph are given by:
2x + y = 0.-5x + y = -7.What is a linear function?A linear function is modeled by:
y = mx + b
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.The system of equations in this problem is composed by two lines.
The decaying line goes though (-2,4) and (2,-4), hence the slope is given by:
m = (-4 - 4)/(2 - (-2)) = -2
Hence:
y = -2x + b
When x = -2, y = 4, hence we find b as follows:
4 = -2(-2) + b
b = 0.
Hence:
y = -2x -> 2x + y = 0.
The increasing line goes though (1,-2) and (2,3), hence the slope is given by:
m = (3 - (-2))/(2 - 1) = 5
Hence:
y = 5x + b
When x = 1, y = -2, hence we find b as follows:
-2 = 5 + b
b = -7.
Hence:
y = 5x - 7.
-5x + y = -7.
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A coin is flipped, and a number cube is rolled. what is the probability of getting tails on the coin and an even number on the number cube?
The probability of getting tails on the coin and an even number on the number cube is 1/4
What are probabilities?Probabilities are used to determine the chances, likelihood, possibilities of an event or collection of events
How to determine the probability?The sample space of a coin is:
S = {H, T}
The sample space of a die is:
S = {1, 2, 3, 4, 5, 6}
The above means that:
A coin has 2 faces, one of which is the tail.
So, we have:
P(Tail) = 1/2
A number cube has 6 numbers, 3 or which are even.
So, we have
P(Even) = 3/6
The required probability is
P = P(Tail) * P(Even)
This gives
P = 1/2 * 3/6
Evaluate
P = 1/4
Evaluate the quotient
P = 0.25
Hence, the probability of getting tails on the coin and an even number on the number cube is 1/4 or 0.25
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what is the length of side s of the square shown below
Hello,
an other method
Pythagorean theorem :
x² + x² = 6²
2x² = 36
x² = 36/2
x² = 18
x = √18 (and not -√18 because x ≥ 0)
x = √(9 × 2)
x = √(3² × 2)
x = 3√2
Answer A
Find the domain and range of the exponential function h(x) = 125 x .
Explain your findings.
As x decreases, does h increase or decrease? Explain.
As x increases, does h increase or decrease? Explain.
The domain of the exponential function given is the set of all real numbers while the range of the exponential function is the set of all real numbers greater than zero.
What is the domain and range of the exponential function?As with other exponential functions, it follows that the domain of the exponential function given is the set of all real numbers while the range of the exponential function is the set of all real numbers greater than zero.
Additionally, by observation, the function has a positive variable correlation, hence;
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A sample of 337 students at a university is surveyed. The students are classified according to gender ("female" or "male"). They are also classified according to major ("biology", "business", "engineering", "mathematics", or "computer science"). The results are given in the contingency table below.
Using it's concept, the relative frequency of business majors in the sample is of 0.16 = 16%.
What is a relative frequency?
A relative frequency is given by the number of desired outcomes divided by the number of total outcomes.
In this problem, there are 337 students, of which 30 + 24 = 54 students are business majors, hence the relative frequency is:
r = 54/337 = 0.16 = 16%.
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335cm rounding off to the
nearest
Answer:
nearest what?
Step-by-step explanation:
nearest tens's=340
nearest hundred's=300
Find the surface area of the composite figure. Round your answer to the nearest tenth if necessary.
The surface area of the composite figure is 444m²
Given a composite figure which is shown in the question.
The area of a shape (in square units) is the number of unit squares required to cover the entire area without gaps or overlaps. If a hologram has planes, those faces are called faces. Area is the sum of the areas of the faces.
Firstly, we will find the area of front and end triangles by using the formula
Area=(1/2)×b×h and we will multiply this area by 2 because we are finding the area of two same triangles.
Here, h=6 and b=16 and substitute these values in the formula, we get
A₁=2×(1/2)×16×6
A₁=2×8×6
A₁=96m²
Now, we will find the area of the left and right side rectangles which joined both the triangles.
We will find the area by using the formula Area=l×b and we will multiply this area by 2 because we are finding the area of two same rectangles.
here, l=10 and b=5 and substitute these values in the formula, we get
A₂=2×10×5
A₂=100m²
Further, we will find the area of the front and end side rectangles that joined both by the base of the triangles.
We will find the area by using the formula Area=l×b and we will multiply this area by 2 because we are finding the area of two same rectangles.
here, l=16 and b=4 and substitute these values in the formula, we get
A₃=2×16×4
A₃=128m²
Furthermore, we will find the area of the left and right side rectangles which joined by the front and end rectangles.
We will find the area by using the formula Area=l×b and we will multiply this area by 2 because we are finding the area of two same rectangles.
here, l=4 and b=5 and substitute these values in the formula, we get
A₄=2×4×5
A₄=40m²
Now, we will find the area of the base of the composite figure which is rectangle.
We will find the area by using the formula Area=l×b.
here, l=16 and b=5 and substitute these values in the formula, we get
A₅=16×5
A₅=80m²
So, the surface area of the given composite figure will be
Surface area=A₁+A₂+A₃+A₄+A₅
Surface area=96m²+100m²+128m²+40m²+80m²
Surface area=444m²
Hence, the surface area of the given composite figure is 444m².
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Solve for the product of four and two thirds multiplied by seven eighths.
A. three and nineteen twenty fourths
B. four and two twenty fourths
C. four and sixteen twenty fourths
D. five and two twenty fourths
The outcome of the product is 4 + 2/24, so the correct option is B.
How to solve the product?
Here we want to solve:
(4 + 2/3)*(7/8)
Using the distributive property of the product we get:
4*(7/8) + (2/3)*(7/8)
28/8 + 14/24
Now we can multiply the first fraction by (3/3) (it does not change the fraction).
(3/3)*28/8 + 14/24
84/24 + 14/24 = 98/24
Now we can rewrite it as:
98/24 = (96/24) + (2/24) =4 + 2/24
Then the correct option is B.
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n this activity, you will apply your understanding of permutations and combinations to calculate probabilities. Use the information in this scenario to answer the questions that follow. Coach Bennet’s high school basketball team has 14 players, consisting of six juniors and eight seniors. Coach Bennet must select three players from the team to participate in a summer basketball clinic.
In order to determine the number of different groups of three players that are possible for Coach Bennet to select from, we would use a mathematical model referred to as combination.
Mathematically, combination is given by this mathematical equation:
[tex]_nC_r = \frac{n!}{r!(n-r)!}[/tex]
Where:
n is the number of items.r is the number of times of choosing items.Substituting the given parameters into the formula, we have;
Number of groups = (⁶C₃ × ⁸C₀) + (⁶C₂ × ⁸C₁) + (⁶C₁ × ⁸C₂) + (⁶C₀ × ⁸C₃)
Number of groups = 20 + 120 + 168 + 56
Number of groups = 364 different groups.
Therefore, there are 364 different groups of three players possible for Coach Bennet to select.
In conclusion, we can infer and logically deduce that this is a combination because the order in which the players are selected isn't important.
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Complete Question:
In this activity, you will apply your understanding of permutations and combinations to calculate probabilities. Use the information in this scenario to answer the questions that follow. Coach Bennet’s high school basketball team has 14 players, consisting of six juniors and eight seniors. Coach Bennet must select three players from the team to participate in a summer basketball clinic.
How many different groups of three players are possible for Coach Bennet to select?
Use the drawing tool(s) to form the correct answer on the provided graph.
Graph the solution to this system of inequalities in the coordinate plane.
3y>2x + 122x + y ≤ -5
The solution to the system of inequalities is (-3.375, 1.75)
How to graph the inequalities?The system of inequalities is given as:
3y > 2x+12
2x+y ≤ -5
Next, we plot the graph of the system using a graphing tool
From the graph, both inequalities intersect at
(-3.375, 1.75)
Hence, the solution to the system of inequalities is (-3.375, 1.75)
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Jesse ran 250 kilometers last week. How many meters did Jesse run?
Answer:
250,000 Meters
Step-by-step explanation:
1 Km = 1000 meters
250x1000= 250,000 meters
Sound the loudness of a sound l in decibels is defined by l= 10 log.r, where r is the relative intensity of the sound. a chofr director wants to determine how many members could sing while maintaining a safe level of sound, about 80 decibels. if one person has a relative intensity of 10 when singing, then how many people could sing with the same relative intensity to achieve a loudness of 80 decibels?
Around 298 people can sing together with the same relative intensity to achieve a loudness of 80 decibels.
Given Information
Loudness of sound is given as, l = 10 log₁₀r
Here, r is the relative intensity.
Relative intensity of a single person when singing = 10
Loudness to be achieved, L = 10 decibels
Calculating the Number of People
Let the number of people with relative intensity 10 singing together be n decibels, then to produce a loudness of 80 decibels, we have,
80 = 10 log₁₀(r × n)
80 = 10 log₁₀(10 × n) [∵ r = 10]
log₁₀(10 × n) = 8
10n ≈ 2980
n = 298
Therefore, 298 people, each with a relative intensity of 10 decibels can sing together to achieve a loudness of 80 decibels.
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Find the scale factor of TUVW to ABCD
Answer:
the scale factor is :
[tex]\frac{9}{15}[/tex]
Step-by-step explanation:
The trapezoids TUVW and ABCD are similar
and AB is the corresponding side of the side TU
Then the function that transform TUVW to ABCD is of scale factor :
[tex]= \frac{AB}{TU}[/tex]
[tex]= \frac{9}{15}[/tex]
The exam scores (out of 100 points) for all students taking an introductory Statistics course are used to construct the following boxplot. Box plot Based on this boxplot, which of the following statements is true
The interquartile range is 55.
What is interquartile range?The interquartile range is the difference between the upper quartile and the lower quartile. In example 1, the IQR = Q3 – Q1 = 87 - 52 = 35. The IQR is a very useful measurement. It is useful because it is less influenced by extreme values as it limits the range to the middle 50% of the values.
Interquartile range = higher quartile - lower quartile
Given data, 50,25,80,10
To arrange the given data in ascending order 10,25,50,80.
Now, we will find the median for the given data.
The median is obtained by first arranging the data in ascending order and applying the following rule.
If the number of observations is even, then the median is [tex]\frac{n}{2}th[/tex] term.
In given data the number of observations is '4'(even)
If the number of observations is even, then the median is [tex]\frac{4}{2} th[/tex] means 2nd term. So median for the given data is 25. It means the value of lower quartile is 25 .
Interquartile range = higher quartile - lower quartile
= 80-25
= 55
Thus, interquartile range for the given data is 55.
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The above question is not complete.
If the first equation is multiplied by 3 and then the equations are added, the result is _____.
3x + y = 3
x - 3y = -2
Answer:
10x-6y-11
Step-by-step explanation:
3(3x+y) = 3(3) +×-3y=-2
9x + 3y = 9 + x -3y =-2
9x+x = -3y-3y =-2-9
10x = -6y =-11
10x-6y-11
On a coordinate plane, a curved line labeled f of x with a minimum value of (1.9, negative 5.7) and a maximum value of (0, 2), crosses the x-axis at (negative 0.7, 0), (0.76, 0), and (2.5, 0), and crosses the y-axis at (0, 2).
Which statement is true about the graphed function?
F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5).
F(x) > 0 over the intervals (-∞, -0.7) and (0.76, 2.5).
F(x) < 0 over the intervals (-0.7, 0.76) and (2.5, ∞).
F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞).
The graphed function, F(x), has a value greater than 0 over the intervals (-0.7, 0.76) and (0.76, ∞) . F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞) is the correct statement [Fourth choice].
About a Graphed Function
The function graph of an object F stands for the set of all points in the plane that are (x, f(x)). The graph of f is also known as the graph of y = f. (x). The graph of an equation is thus a specific example of the graph of a function. A graphed function is a function that has been drawn out on a graph.
It is evident from the attached graph that the supplied function exceeds 0 for the following range:
-0.7 < F(x) < 0.76
And, 0.76 < F(x) < ∞
As a result, the intervals for which the given graphed function, F(x) is greater than 0 are as follows,
(-0.7, 0.76) and (0.76, ∞)
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A gambling game pays 10 to 1 and there is 1 chance in 12 for me to win. suppose i play this game 150 times, betting $20 each time. assume that the plays are independent of each other.
The amount the gambler can win in this fractional game that pays a 10 to 1 with a 1/12 chance of winning is $2,500.
What is a fractional game?A fractional betting or game allows the gambler to calculate the winning from their betting when it is compared with their stake.
The number on the left-side represents the winning, while the number on the right side of the fractional odds represents the stake (investment).
When the gambler wins, they receive 10x their stake. The expected amount to be won is computed as the total stakes, multiplied by the winning probability and the fractional odds.
Data and Calculations:Fractional odds of winning = 10/1
Chance of winning = 1/12
Number of independent games played = 150 times
Bet each time = $20
Total bets = $3,000 ($20 x 150)
Amount won = $2,500 ($3,000 x 1/12 x 10/1)
Thus, the amount the gambler can win in this fractional game that pays a 10 to 1 with a 1/12 chance of winning is $2,500.
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Question Completion:How much do you expect to win?
help
11-16
please i dont understand
Answer:
see attached
Step-by-step explanation:
There are many vocabulary words and theorems associated with angles where a transversal crosses parallel lines. These are needed for the "explain your reasoning" part of the question.
Where 2 lines crossWhere one line crosses another, the angles formed are either "adjacent" (share a side and vertex), or "vertical" (share only a vertex, formed from opposite rays). In Figure 11, x° and 67° are "adjacent" angles. In Figure 12, y° and 109° are "vertical" angles.
The adjacent angles are also called a "linear pair", and their total is 180°. They are supplementary.
The vertical angles are congruent.
Where a transversal crosses parallel linesTwo sets of four angles are formed when a transversal crosses parallel lines. The relations between angles of one of those sets and angles of the other of those sets are described using several different terms:
"Alternate" angles are on opposite sides of the transversal. "Consecutive" or "same-side" angles are on the same side of the transversal. "Exterior" angles are outside the parallel lines. "Interior" angles are between the parallel lines. "Corresponding" angles are in the same relation to the point of intersection.
Alternate exterior angles (congruent): Fig. 11, x° and y°.
Alternate interior angles (congruent): Fig. 13, y° and the one marked with the right angle symbol.
Consecutive interior angles (supplementary): Fig. 12, x° and 109°; Fig. 14, x° and y°.
Consecutive exterior angles (supplementary): none shown in these figures.
Corresponding angles (congruent): Fig 14, x° and 65°; Fig. 16, x° and 130°.
The upshot of all of these relations is this:
all acute angles are congruentall obtuse angles are congruentobtuse angles are supplementary to acute anglesIf any angle is a right angle, all of them are.ApplicationThe attached table shows the values of x° and y° in the various figures. For the purpose here, we simply identified the angles as acute or obtuse, and matched values accordingly. The explanation can get as elaborate as you like. For example, ...
11. x° and y° are alternate exterior angles, so congruent. x° and 67° are a linear pair, so x° = 180° -67° = 113°.
12. x° and 109° are consecutive interior angles, so supplementary. x° = 180° -109° = 71°. y° and 109° are vertical angles, so congruent.
The ratio of the number of picture books encyclopedias, and fairy tale books Annette had is 3:4:5 She gave half of her encyclopedias to her brother and he gave her 5 books of fairytales Now she has 14 more books of fairy tales than encyclopedias How many picture books does she have?
Using a system of equations, it is found that she has 9 picture books.
What is a system of equations?A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
Variable x: Number of picture books.Variable y: Number of encyclopedias.Variable z: Number of fairy tale books.The ratio of the number of picture books encyclopedias, and fairy tale books Annette had is 3:4:5, hence:
[tex]\frac{x}{y} = \frac{3}[4}, \frac{x}{z} = \frac{3}{5}, \frac{y}{z} = \frac{4}[5}[/tex]
She gave half of her encyclopedias to her brother and he gave her 5 books of fairytales. Now she has 14 more books of fairy tales than encyclopedias, hence:
z + 5 - 0.5y = 14.
z - 0.5y = 9
From the ratios, we have that:
[tex]y = \frac{4}{3}x, z = \frac{5}{3}x[/tex]
Hence we solve for x to find the number of picture books:
[tex]z - \frac{y}{2} = 9[/tex]
[tex]\frac{5}{3}x - \frac{2}{3}x = 9[/tex]
x = 9.
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Allen is 5 feet 9 inches tall, terrel is 6 feet 2 inches tall. what is the average height
The average height is [tex]5feet[/tex] and [tex]11.5[/tex] inches if Allen is [tex]5 feet 9 inches[/tex] tall and Terrel is [tex]6 feet 2 inches[/tex] tall.
How to find the average height ?
Allen height is [tex]5feet ,9inches[/tex]
Terrel height is [tex]6feet,2inches[/tex]
And we know that [tex]1feet=12inches[/tex]
So Allen height is
[tex]=5*12+9\\=60+9\\=69 inches[/tex]
And Terrel height is
[tex]=6*12+2\\=72+2\\=74inches[/tex]
Average of the Allen and Terrel height is
[tex]\frac{69+74}{2\\} \\=143/2\\=71.5inches[/tex]
And average height in feet is [tex]5feet,11.5inches[/tex]
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a 10 foot ramp must make an angle of 30° with the ground if it is to reach a certain window. what angle must a 15 foot ramp make with the ground to reach the same window
The 15 foot ramp must make an angle 19.45° with the ground to reach the same window.
What angle must be made with the ground by the 15 foot ramp?Since the height of the window above ground remains constant in both cases, it follows that by means of trigonometric identity sine; we have;
10sin30° = 15sinx
sinx = 5/15 = 0.333
x = sin-¹(0.333)
x = 19.45°.
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Complete the remainder of the
table for the given function rule:
y = -2x +9
-4 -2 0 2 4
[?] [] [] []
y 17
The complete table of values for the function rule y = -2x +9 is
x -4 -2 0 2 4
y 17 13 9 5 1
What are linear equations?Linear equations are equations that have constant average rates of change, slope or gradient
How to complete the remainder of the table for the given function rule?From the question, the function rule is given as:
y = -2x +9
The table of values is given as:
x -4 -2 0 2 4
y 17
Next, we substitute the other values of x in the equation y = -2x +9
y = -2(-2) +9 = 13
y = -2(0) +9 = 9
y = -2(2) +9 = 5
y = -2(4) +9 = 1
So, the complete table of values is
-4 -2 0 2 4
y 17 13 9 5 1
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Drag the tiles to the correct boxes to complete the pairs Match each inequality to the number line that represents its solution
Answer:
x ≤ 7 => [tex]- \frac{13x}{18}[/tex] + [tex]\frac{5}{9} \geq - \frac{9}{2}[/tex]
x ≤ 8 => -[tex]\frac{x}{10}[/tex] + [tex]\frac{1}{5}[/tex] ≥ -[tex]\frac{33}{55}[/tex]
x ≤ -5 => - [tex]\frac{50x}{3}[/tex] - [tex]\frac{11}{6}[/tex] [tex]\geq[/tex] [tex]\frac{163}{2}[/tex]
x ≤ -6 => [tex]\frac{3x}{2}[/tex] + 105 ≤ 96
Step-by-step explanation:
-[tex]\frac{x}{10}[/tex] + [tex]\frac{1}{5}[/tex] ≥ -[tex]\frac{33}{55}[/tex]
[tex]\frac{1}{5}[/tex] + [tex]\frac{33}{55}[/tex] ≥ [tex]\frac{x}{10}[/tex] / *10
2 + 6 ≥ x
8 ≥ x
- [tex]\frac{50x}{3}[/tex] - [tex]\frac{11}{6}[/tex] [tex]\geq[/tex] [tex]\frac{163}{2}[/tex] / *6
- 100x - 11 ≥ 489
-500 ≥ 100x
-5 ≥ x
[tex]\frac{3x}{2}[/tex] + 105 ≤ 96
[tex]\frac{3x}{2}[/tex] ≤ 96 - 105 / * [tex]\frac{2}{3}[/tex]
x ≤ -6
[tex]- \frac{13x}{18}[/tex] + [tex]\frac{5}{9} \geq - \frac{9}{2}[/tex] /*18
-13x + 10 ≥ - 81
-13x ≥ -91 /:-13
x ≥ 7
What is the common difference in this
recursive definition?
common is 1 because 3-2 is 1
In an algebra class, there are 10 less than twice as many boys as girls. If the total number of students is 38, how many boys and girls are there in class?
Answer: 16 girls and 22 boys
Step-by-step explanation:
This can be solved with simple algebra.
Let's say that the number of girls is x.
Since there are 10 less than twice as many boys as girls, the number of boys would be 2x-10. (2x for twice as many, and -10 for ten less.)
The total number of students is 38. Adding the girls, the equation is now 3x-10=38.
3x=48
x=16.
2x-10=the number of boys, as said earlier. SO, 32-10=22=the number of boys.
To check our work, add 16+22. This equals 38.