The pieces of information that is provided by the box plots are the median and first quartile.
The piece of information that is not provided by the box plots is the mean.
The interquartile range is 22.50.
An outlier would distort the values of the median and the quartiles.
What is a box plot?
A box plot is used to study the distribution and level of a set of scores. The end of the first line represents the minimum number and the end of the second line represents the maximum number.
On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median. The third line on the box represents the upper (third) quartile. The difference between the quartiles is the interquartile range.
Interquartile range = 60 - 37.50 = 22.50
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Pls answer quick I rly need this.
Linking each equation with its equivalent equation below:
5 + 9x - 7 - 4x - 3x + 6 ≡ 2x + 4x + 8 + 4x - 3x - 4 ≡ 2x + 46x - 9 5x + 4 - x + 5x + 5 ≡ 5x3x + 5 - 2x - 5x + 9 + 8x ≡ 4x + 114x + x - 11 - 5x + 25 + 4x ≡ 4x + 11x - 3 + 2x + 3 + 2x ≡ 5xMeaning of Equivalent equationEquivalent equation can be defined as an equation that has the same value with another equation.
Equivalent equation are not directly the same but can be transformed to look like each other.
In conclusion, The equivalent equations have been matched in the list above.
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at the movie theatre, child admission is $6.10 and adult admission is $9.70. On Monday , 146 tickets were sold for a total sales of $1074.20.HOw many adult tickets were sold that day ?
Answer:
51
Step-by-step explanation:
Let c be the number of child tickets sold.
Let a be the number of adult tickets sold.
From the information given from the question, we can deduce:
6.10c + 9.70a = 1074.20 - Equation 1
c + a = 146 - Equation 2
From here, we can use the substitution method in solving simultaneous equations to find a and c. We will use Equation 2 as the base.
c = 146 - a - Equation 2A
We will then substitute equation 2A into Equation 1 to find a.
6.10(146-a) + 9.70a = 1074.20
890.6 - 6.10a + 9.70a = 1074.20
890.6 + 3.6a = 1074.20
3.6a = 1074.20 - 890.6
3.6a = 183.6
a = [tex]\frac{183.6}{3.6}[/tex]
a = 51
Therefore we know that 51 adult tickets were sold that day.
After that you can substitute a into equation 2 to find c.
Es LOGICA PROPOSICIONAL, me pueden ayudar porfavor?
[tex]\begin{array}{c|c|c|c} p & q & \neg q & p \land \neg q \\ T & T & F & F \\ T & F & T & T \\ F & T & F & F \\ F & F & T & F \end{array}[/tex]
[tex]\begin{array}{c|c|c|c} t & s & \neg t & \neg t \implies s \\ T & T & F & T \\ T & F & F & T \\ F & T & T & T \\ F & F & T & F \end{array}[/tex]
[tex]\begin{array}{c|c|c}p\land \neg q & \neg t \implies s & (p \land \neg q) \implies (\neg t \implies s) \\T & T & T \\ T & F & F \\ F & T & T \\ F & F & T \end{array}[/tex]
The given logical statement is false when [tex]p\land\neg q[/tex] and [tex]\neg t\implies s[/tex] are true and false, respectively.
[tex]p\land\neq g[/tex] is true when [tex]p[/tex] is true and [tex]q[/tex] is false[tex]\neg t \implies s[/tex] is false when both [tex]t[/tex] and [tex]s[/tex] are falseTrue or false? The graph represents a function.
5
O A. True
O B. False
A pie with a temperature of 140∘F is taken out of the oven and placed on a windowsill to cool. Its temperature as a function of t minutes is given by
T(t)=68e−0.0174t+72
How long, to the closest minute, will it take for the pie to cool to 80∘F?
The time taken to the closest minutes for the pie to cool to 80∘F is 123 minutes
TemperatureT(t) = 68e^−0.0174t + 72
80 = 68e^−0.0174t + 72
80 - 72 = 68e^−0.0174t
8 = 68e^−0.0174t
e^−0.0174t = 8/68
e^−0.0174t = 0.11764705882352
take natural log of both sidesln e (−0.0174t) = ln (0.11764705882352)
1 × −0.0174t = -2.1400661634962708
-0.0174t = -2.1400661634962708
divide both sides by -0.0174t = -2.1400661634962708 / -0.0174
t = 122.9923
Approximately,
t = 123 minutes
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write the equation of the line that is parallel to the line represented by 5 x + 2 y = 6 and passes through the point (1, 5.5).
Answer:
[tex]y=-2.5x+8[/tex]
Step-by-step explanation:
Parallel lines have the same slope but different y-intercepts. So, first, transform the given equation into the slope-intercept form, [tex]y=mx+b[/tex].
[tex]5x+2y=6[/tex]
[tex]2y=-5x+6[/tex]
[tex]y=-\frac{5}{2} x+3[/tex]
Then, determine the equation of a line that has a slope of [tex]-\frac{5}{2}[/tex] and passes through (1, 5.5). Substitute all the known values and solve for b.
[tex]y=mx+b[/tex]
[tex]5.5 = -\frac{5}{2} *1+b[/tex]
[tex]5.5=-2.5+b[/tex]
[tex]b=8[/tex]
Therefore, the answer is [tex]y=-2.5x+8[/tex].
5
364,860
0/1 point
Camila has finally found a house she adores! The cost of the home is $210,000, which she intends to purchase on a 30-year fixed mortgage. Blinded by her adoration for the
property, she has agreed to a 5.5% interest rate. Round all answers to the nearest cent.
How much will Camila pay in interest over the lifetime of the mortgage?
The total interest on the mortgage loan is $219,249.60
What is a mortgage loan?
It is a loan taken in order to purchase a property that requires periodic repayments such as monthly repayment since most mortgages are repaid monthly.
Our first task is to determine the monthly repayment using the present value formula of an ordinary annuity because the monthly payment becomes due at the end of each month.
PV=monthly repayment*(1-(1+r)^-N/r
PV=loan amount=$210,000
monthly repayment=unknown(assume it is X)
r=monthly interest rate=5.5%/12=0.00458333333333333
N=number of monthly payments in 30 years=30*12=360
$210,000=X*(1-(1+0.00458333333333333)^-360/0.00458333333333333
$210,000=X*(1-(1.00458333333333333)^-360/0.00458333333333333
$210,000=X*(1-0.19277525234572900)/0.00458333333333333
$210,000=X*0.80722474765427100/0.00458333333333333
$210,000=X*176.12176312456800000
X=$210,000/176.12176312456800000
X=monthly payment=$1,192.36
total repayments(360 months)=$1,192.36*360
total repayments(360 months)=$429,249.60
Total interest=total repayments(360 months)-loan amount
Total interest=$429,249.60-$210,000
Total interest=$219,249.60
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The solving to this question
This is a simple harmonic motion exercise. The proof that the resultant force on the particle, at time t, is -225 Newtons is indicated below.
What is the proof that the resultant force on the particle, at time t, is -225x newtons?Note that we have been given the following:
Mass = 9kg,
Y = 45 N
ζ = 0.4 m
Then, Y/ζ = 45N/0.4m
= 112.5 N/m
Hence, the spring constant =
K = 112. 5N/m
From this point we can resolve the Amplitude (A):
Amplitude is given as:
A = CB - PB
= 0.6 - 0.5
A = 0.1m
I) So because one spring is elongated by x and the other is compressed by x, Hence, the spring force is:
F[tex]_{net}[/tex] = - Kₓ - Kₓ
= - 2Kₓ
= -2 x 112.5 x* X
F[tex]_{net}[/tex] = -225x Newton ..........Lets call this expression 1
From equation 1 above, we know that
Ma = -225x
a = (-225/m) x
⇒ a ∝ - x,
Hence, the motion is is simple harmonic in nature.
The time period, T = 2 π√m/K[tex]_{eq}[/tex]
Where, K[tex]_{eq}[/tex] = 2K
= 2π√(9/225)
= 2π * 3/15
= 2(22/7) * (3/15)
= 1.25714285714; thus
T ≈ 1.26 secs...............lets call this expression 2
What is the speed of the particle when it is 0.05 meters from C?Note that Angular Frequency is = 2π/T
= 2π/1.26
= 4.9866550057
ω = 4.99 rad/s
Since the velocity at any point x from the mean position is given by
V = ω √ (A² - x²); hence
V = 4.99 √[(0.1)² - (0.05)²
V = 4.99 x 0.0866
V = 0.432134
V ≈ 0.432..........Lets call this expression 3
What is the expression of x in terms of t?Along the x-axis, A simple harmonic motion can be depicted as:
x = A sin (ωt + Ф) ..........lets call this expression 4
where, Ф = Phase constant
At t = 0; x = A
A = A sinФ
⇒ SinФ = 1
⇒ Ф = π/2
Expression 4 becomes:
x = A sin (ωt + π/2)
Inserting the values of ω and A, we have
x = 0.1 sin (4.99t + π/2).........Lets call this expression 5a
or x = 0.1 cos (4.99t).......Lets call this expression 5b
Hence,
Sin(π/2 + Ф) = CosФ
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3 to 2 if there are 120 children who like pizza, how many total
Answer:
320
Step-by-step explanation:
Is the 3 to 2 part to part? Out of every 5 people, 3 prefer pizza and 2 do not. We can us this to set up a proportion.
3/5 = 120/x The 3 represent the part that like pizza over the whole of 5. The second ratio is showing the actual number of people that liked pizza over the total number of people.
What would be multiply 3 by to get 120? 40. So, we will multiply 5 times 40 to get the total number of people. 5 x 40 = 200
Solve for x, 3x+21=8x*54
Answer:
Exact form: 7/143
Decimal form: /0.048951
Answer:
[tex]x=\frac{7}{143}[/tex]
Step-by-step explanation:
Simplify the right side of the equation. [tex]3x+21=432x[/tex]. Subtract 21 from both sides of the equation. [tex]3x=432x-21[/tex]. Subtract 432x from both sides of the equation, [tex]-429x=-21[/tex]. The negative signs cancel out to get [tex]429x=21[/tex]. Divide both sides but 429 to get [tex]x=\frac{21}{429}[/tex]. Reduce to get [tex]x=\frac{7}{143}[/tex].
How would you describe the difference between the graphs of f(x) = 2x² and
g(x) = -2x²?
O A. g(x) is a reflection of f(x) over the line y = x.
B. g(x) is a reflection of f(x) over the line y = -1.
C. g(x) is a reflection of f(x) over the y-axis.
D. g(x) is a reflection of f(x) over the x-axis.
Answer:
D. g(x) is a reflection of f(x) over the x-axis.
Step-by-step explanation:
So when you have the equation: [tex]-2x^2[/tex] it's just negating the value of f(x), which is [tex]2x^2[/tex] and since f(x) represents the y-value, you're negating the y-value and the x-value is unchanged. So each point on f(x) was originally: (x, f(x)) and now it's (x, -f(x)). Since the y-value is changing, it's going to be reflecting across the x-axis. So g(x) is a reflection of f(x) over the x-axis.
How many triangles are created in the following situation:
m/A=35°, a = 12,b=16
1 triangle
2 triangles
3 triangles
no triangle
Answer:
Step-by-step explanation:
3 things of triangle are given.
2 sides + 1 angle
so, possible triangles = 1 ans
The point A (-5, -2) is reflected over the line y=-1, and then is reflected over the line x= 3.
The coordinates of A exist (11, 0).
How to estimate the coordinates of A?Let, the point A (-5, -2) exists reflected over the line y = -1, and then stand reflected over the line x = 3.
The distance between the y value exists -1 - (-2)= 1
We move 1 unit beyond the line y = -1
After reflection over the line y = -1 the coordinates of A becomes (-5, 1-1) is (-5, 0)
It exists reflected over the line x = 3
The distance between -5 and 3 exists 3 - (-5) = 8
We move 8 units out from the line x = 3
The Point (-5, 0) becomes (3 + 8, 0) exists (11, 0).
Therefore, the coordinates of A exist (11, 0).
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The complete question:
The point A (-5, -2) is reflected over the line y = -1, and then is reflected over the line x = 3. What are the coordinates of A.
What is the simplified form of the quantity of x plus 6, all over the quantity of x plus 4 + the quantity of x minus 3, all over 3 ? (2 points) the quantity of x squared plus 3x minus 18, all over 3 times the quantity of x plus 4 the quantity of x squared plus 4x plus 6, all over the quantity of x plus 7 the quantity of x squared plus 3x minus 18, all over the quantity x plus 7 the quantity of x squared plus 4x plus 6, all over 3 times the quantity of x plus 4
The simplified expression of the given equation is [tex]\frac{x^{2} + 4x + 6}{3x + 12}[/tex]
There are three basic steps for addition or subtraction of two fractions
Step 1: Make sure the bottom numbers (the denominators) are the sameStep 2: Add the top numbers (the numerators), put that answer over the denominatorStep 3: Simplify the fraction (if possible)The given expression :- [tex]\frac{x+6}{x+4} +\frac{x-3}{3}[/tex]
Taking LCM or making the denominators same we get,
= {3(x+6) + (x-3)(x+4)}/3(x+4)
= {3x + 18 + x² +x -12}/3(x+4)
={x² + 4x + 6}/3x + 12
= [tex]\frac{x^{2} + 4x + 6}{3x + 12}[/tex]
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Answer:
i believe its B
Step-by-step explanation:
After defeating the fire breathing dragon, the knight decides
to celebrate his victory with a celebratory goblet made out of Dragon Alloy #17, which is 36% gold, 9% silver, and 55% magic steel. The dwarves have Dragon Alloy #11, which is 36% gold, 28% magic steel, and the rest silver. They also have Dragon Alloy #15, which is 36% gold and 64% magic steel. How many grams of each
alloy should the dwarves combine to get 1 kg of Dragon Alloy #17?
250 grams of dragon alloy #11 and 750 grams of dragon alloy #35 is needed to make 1000 grams (1 kg) of Dragon alloy #17.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Let x represent the amount of alloy #11 and y represent the amount of alloy #15, hence:
(0.36x) + (y * 0.36) = 1(0.36) (1)
Also:
0.28x + 0.64y = 1(0.55) (2)
From both equations:
x = 0.25, y = 0.75
250 grams of dragon alloy #11 and 750 grams of dragon alloy #35 is needed to make 1000 grams (1 kg) of Dragon alloy #17.
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Hello there I need help with this question pls help me I'll mark it as a brain list and give extra 50 points if you answer with an explanation and it MUST be correct
Answer:
iTS 6 2/3 OPTION 2.
Step-by-step explanation:
Because Area = L*B
SO L = A/b
L= 65/3 * 4/13(reciprocal and multiply)
L=20/3 = 6 2/3
Answer:
So answer is 6 2/3
because Look carefully
Area =length× width
length=Area÷ width
so
[tex]21 \frac{2}{3} \div 3 \frac{1}{4} = 6 \frac{2}{3} [/tex]
35 Please help with this question.
The critical values are 0.622, 0.707, 0.789 and 0.834
How to determine the critical values?The sample size is given as:
n = 8
Calculate the degrees of freedom using
df = n - 2
So, we have:
df = 8 - 2
df = 6
Using the table of values of critical values, we have:
Critical values = 0.622, 0.707, 0.789 and 0.834
By comparing the critical values and the linear correlation coefficient, we can conclude that there is no significant linear correlation.
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Find the z a/2 critical value needed to construct a confidence interval with level .The critical value for the confidence level 90% is.......
( round to two decimal places )
Using the z-distribution, the critical value for a confidence level of 90% is of Z = 1.65.
What is the critical value for a 90% confidence interval using the z-distribution?In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.65.
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Compute the requested operating costs as indicated, based on the preceding table and the following information.
Car: six-cylinder compact
Year driven: second
Miles driven: 14,000
The insurance cost for second year is $
.
The insurance cost for the second year from the information given will be $476.
How to calculate the insurance cost?The insurance cost for the second year will be:
= $14000 × 0.034
= $476
Therefore, the insurance cost for the second year will be $476
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The insurance cost for the second year from the information given will be $476.
How to calculate the insurance cost?
The insurance cost for the second year will be:
= $14000 × 0.034
= $476
Therefore, the insurance cost for the second year will be $476
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The variable y varies directly as x. When x = 20, y = 12. What is the value of ywhen x = 15?
The value of y at x =15 is 9.
What is Direct Variation?Two variables are said to be in Direct Variation when increasing one variable the other also increases.
The direct variation is represented by
y ∝ x
y = kx
where k is the proportionality constant
the value of y =12 , x = 20
12 = k * 20
12/20 = k
k = 0.6
The equation becomes
y = 0.6 x
The value of y at x = 15 is
y = 0.6 * 15
y =9
Therefore, the value of y at x =15 is 9.
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90. Find 33.3% of 81.
write equation that has base of 3 stretched vertically by factor of 2/3 reflected in y axis, asymptote of y=2 and passes through point (0,3,5)
The exponential equation is [tex]y = \frac23(3)^{-x+0.74} + 2[/tex]
How to determine the equation?An exponential function is represented as:
[tex]y = b^x[/tex]
The base is 3.
So, we have:
[tex]y = 3^x[/tex]
It is stretched vertically by 2/3.
So, we have:
[tex]y = \frac23(3)^x[/tex]
When reflected over the y-axis, we have:
[tex]y = \frac23(3)^{-x}[/tex]
An asymptote of y = 2, makes the function becomes
[tex]y = \frac23(3)^{-x} + 2[/tex]
Lastly, it passes through the point (0, 3.5).
So, we have:
[tex]y = \frac23(3)^{-x+h} + 2[/tex]
This gives
[tex]3.5 = \frac23(3)^{-0+h} + 2[/tex]
[tex]3.5 = \frac23(3)^{h} + 2[/tex]
Subtract 2 from both sides
[tex]1.5 = \frac23(3)^{h}[/tex]
Multiply by 3/2
[tex]2.25 = (3)^{h}[/tex]
Take the logarithm of both sides
log(2.25) = h * log(3)
Solve for h
h = 0.74
Substitute h = 0.74 in [tex]y = \frac23(3)^{-x+h} + 2[/tex]
[tex]y = \frac23(3)^{-x+0.74} + 2[/tex]
Hence, the exponential equation is [tex]y = \frac23(3)^{-x+0.74} + 2[/tex]
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Give the name (monomial,
binomial, trinomial etc.) and
degree of the polynomial.
√29x6
Name? [? ]
Degree? [
solve the equation. y/8 = 5
y=?
Answer:
y = 40
Step-by-step explanation:
y/8 = 5
———————————————————
Multiply both sides by 8:
8y/8 = 5 * 8
———————————————————
Simplify:
y = 40
Hope that helps! :)
Answer:
Y = 40
Step-by-step explanation:
Step 1:
y/8 = 5
Bring 8 to the right side changing its arithmetic sign to multiply.
Step 2:
y = 5 x 8
Now multiply 5 by 8 to get the answer.
Step 3:
y = 40
Therefore, y is equal to 40.
If h(x)=1/2x-5 and f(x)=3h(x)+4 then which of the following is the value of f(4)
Answer: -5
Step-by-step explanation:
[tex]h(4)=\frac{1}{2}(4)-5=-3\\\\f(4)=3h(4)+4=3(-3)+4=-5[/tex]
Find the value of x in each case. Show your work with proper statements and notation. P belongs to line MQ
Answer:
x = 14
Step-by-step explanation:
PMN forms a triangle and the sum of interior angles in a triangle is equal to 180 therefore we can use the following equation to find the value of x
32 + 64 + 6x = 180 add like terms
96 + 6x = 180 subtract 96 from both sides
6x = 84 divide both sides by 6
x = 14
someone please help me on this question
i need detailed step by step explaination with reasoning
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
Correct option - C[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]
Area left for flowers = Area of flower garden - Area of bird bath.
Area of flower garden [ rectangle ] :
[tex]\qquad❖ \: \sf \:length \times width[/tex]
[tex]\qquad❖ \: \sf \:3 \times 2[/tex]
[tex]\qquad❖ \: \sf \: 6\: \: {m}^{2} [/tex]
Area of bird bath [ Circle ] :
[tex]\qquad❖ \: \sf \: \pi{r}^{2} [/tex]
[tex]\qquad❖ \: \sf \:3.14 \times ( \frac{1}{2} ) {}^{2} [/tex]
[tex]\qquad❖ \: \sf \:3.14 \times \frac{1}{4} [/tex]
[tex]\qquad❖ \: \sf \:0.785 \: \: m {}^{2} [/tex]
Area left for flowers :
[tex]\qquad❖ \: \sf \:6 - 0.785[/tex]
[tex]\qquad❖ \: \sf \:5.215 \: \: m {}^{2} [/tex]
[tex]\qquad❖ \: \sf \: \approx5.22 \: \: m {}^{2} [/tex]
[tex] \qquad \large \sf {Conclusion} : [/tex]
Correct option - CSuppose that X-N (2,6) is a normal distribution with mean 2 and standard deviation 6. What value of x has a z-score of three?
The value of x has a z-score of three is 20
How to determine the value of x?The given parameters are:
Mean = 2
Standard deviation = 6
z = 3
The z-score is calculated as:
[tex]z = \frac{x - \mu}{\sigma}[/tex]
So, we have:
[tex]3 = \frac{x -2}{6}[/tex]
Multiply through by 6
18 = x - 2
Add 2 to both sides
x = 20
Hence, the value of x has a z-score of three is 20
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The circumference of a circle is 15π in. What is the area, in square inches? Express your answer in terms of \piπ.
Answer:
the area would be 176.7
Step-by-step explanation:
You know the area of a circle is A = pi×r^2, so you need the radius.
You know C = 2pi×r, so r = C/(2pi)
r = 15pi / 2pi = 7.5
A = pi(7.5)^2 = 56.25pi ~ 176.715 square inches.
The area of the circle is about 176.7 square inches.
The radius of the circle is 7.5 inches. Therefore, the area of the circle will be 56.25π square inches.
What is the circumference and area of a circle?Let r be the radius of the circle. Then the area of the circle will be given as,
A = πr² square units
The circumference of the circle will be given as,
C = 2πr units
The circumference of a circle is 15π inches. Then the radius of the circle is calculated as,
15π = 2πr
r = 7.5 inches
The area of the circle is calculated as,
A = π x 7.5²
A = 56.25π square inches
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Given triangle ABC, which equation could be used to find the measure of angle C?
Please HELPP ONLY A FEW MINUTES TO TURN IN
Okay, it's very simple, to solve this triangle you need to understand what the other angles are. We know that angle A is 90º, as it is represented as a square.
We now need to solve for angle B. angle B can be solved for by
Sin (x) = Opposite / Hypotenuse = 3 / 3√5 = 2.24ish
sin(x) = 2.24
x = [tex]sin^{-1}[/tex](2.24)
Use sin.
Answer:
Step-by-step explanation:
what's the answer