I believe it is 11. Because there are no electrons you do not need to subtract anything.

Which of the following is an example of an object with kinetic energy?

a. a plane lifting off of the runway

b. a bobsled perched at the top of a run

c. a snowball tumbling down a hill

d. both a and c

**Answer:**

A and C

**Explanation:**

Both have mass and are in motion

D is ur answer it should be right

素 Example three

After an airplane takes off, it travels 10.4 km west, 8.7 km north, and 2.1 km up How far is it

from the take off point?

Solution

**Answer:**

Let R be the total distance

R²=10.4²+(8.7+2.1)²

R²=10.4²+10.8²

R²=224.8

You square root both sides

R=14.99km

If an **airplane t**akes off, it travels 10.4 km **west,** 8.7 km **north**, and 2.1 km **up, **then using the** Pythagorean **theorem it is **14.99km** from its take-off point.

**Pythagoras' **theorem is a fundamental theorem in mathematics that relates to the sides of a **right-angled** triangle. It states that in a right-angled triangle, the **square** of the length of the **hypotenuse** (the side opposite the right angle) is equal to the **sum **of the squares of the lengths of the other** two** sides.

In equation form, the theorem can be written as:

**c² = a² + b²**

Where

c =the length of the hypotenuse,

a and b = the lengths of the other two sides.

The theorem is named after the ancient Greek mathematician **Pythagoras**, who is credited with his discovery and proof. Pythagoras' theorem is widely used in mathematics and has many practical applications in fields such as architecture, engineering, and **physics**.

Here in the question

We can use the **Pythagorean **theorem to find the distance from the takeoff point:

Distance = √(West)² + (North+Up)²

Plugging in the given values, we get:

Distance = √(10.4)² +( 8.7 + 2.1)²

Distance ≈ **14.99km**

Therefore, the **airplane **is approximately **14.99km** away from the **takeoff** point.

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in a class where the number of girls is 36% of the total number,there are 48 boys.how many students are there in the class?

**Answer:**

There are 75 people in the class. The number of boys is 48 and the number of girls is 27. The percentage of girls is 36% of 75.

**Explanation:**

The amplitude of a wave

determines the volume of a

sound.

True

O False

true the amplitude of a wave determines the volume of a sound

is electricity matter

Answer:

Yes it is

Explanation:

Electricity is the positive and negative matter that's found in protons and electrons.

**Answer:**

yes

**Explanation:**

because electricity is a positive and negative proton

A plastic ball in a liquid is acted upon by its weight and by a buoyant force. The weight of the ball is 4 N. The buoyant force has a magnitude of 5 N and acts vertically upward. When the ball is released from rest, what is it's acceleration and direction? [2 pts] for a Free Body Diagram correctly labeled.

**Answer:**

The acceleration is 2.448 meters per square second and is vertically upward.

**Explanation:**

The Free Body Diagram of the plastic ball in the liquid is presented in the image attached below. By Second Newton's Law, we know that forces acting on the plastic ball is:

[tex]\Sigma F = F - m\cdot g = m\cdot a[/tex] **(1)**

Where:

[tex]F[/tex] - Buoyant force, measured in newtons.

[tex]m[/tex] - Mass of the plastic ball, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]a[/tex] - Net acceleration, measured in meters per square second.

If we know that [tex]F = 5\,N[/tex], [tex]m = 0.408\,kg[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the net acceleration of the plastic ball is:

[tex]a = \frac{F}{m} - g[/tex]

[tex]a= 2.448\,\frac{m}{s^{2}}[/tex]

The acceleration is 2.448 meters per square second and is vertically upward.

an object is found to have weight of 16.7N on moon

what is it's

weight on earth where g= 10N/kg

**Answer:**

167 kg

**Explanation:**

On Earth it is 167 kg. We have to multiply the weight in the Moon by 10 because 1 kg on Earth, is nearly 10 N. 1 kg is 9,8 N in fact, but we get it as 10 N in general.

Do me Brainliest if I helped you. :)

Name the principle which states that energy

cannot be created or destroyed, merely

transferred from one form to another:

Law of Conservation of Energy

**Answer:**

the Laws of Thermodynamics

**Explanation:**

these laws states that no form of energy can be created by anyone or anything, without a previous and equal input of energy being put in, that energy can only be transferred from object to object and through different forms

Example: the way a heater runs to warm up an area, that is the process of electrical energy, or energy stored in propane being ** converted **into heat energy

this law is universally implied and has been proven on multiple accounts to be true, in no way can you create energy out of thin air, all you can do is transform and transfer it

hope this is what you was going for, very good point in science

this is one of two correct answers, the other answer to this question is also correct

At an amusement park there are 200-kg bumper cars A, B, and C that have riders with masses of 55 kg, 90 kg, and 42.5 kg respectively. Car A is moving to the right with a velocity vA = 2 m/s and car C has a velocity vC = 1.5 m/s to the left, but car B is initially at rest. The coefficient of restitution between each car is 0.8. Determine the final velocity of each car, after all impacts, assuming car A hits car B before car C does. Assume positive sign denoting forward motion and negative sign denoting backward motion.

**Answer:**

Vb = 0.334 m/s

Va = -1.265 m/s

Vc = 1.424 m/s

**Explanation:**

Favorite Answer

Initial momentum = 255(2) – 242.5(1.5) = 146.25

Final momentum = 255Va + 290Vb + 242.5 Vc = 146.25

Vb - Va = 0.8(2) = 1.6

Vc - Vb = 0.8(1.5) = 1.2

Va = Vb -1.6

Vc = Vb + 1.2

255(Vb -1.6) + 290Vb + 242.5(Vb + 1.2) = 146.25

255 Vb – 408 + 290 Vb + 242.5 Vb + 291 = 146.25

787.5 Vb = 263.25

Vb = 0.334 m/s

Va = Vb -1.6 = 0.334 – 1.6 = -1.265 m/s

Vc = Vb + 1.2 = 0.224 + 1.2 = 1.424 m/s

Which image best illustrates diffraction?

The one above I am guessing

**Answer: A**

**Explanation:**

How did Einstein’s and Newton’s theories differ in terms of explaining the cause of gravity?

thank you

**Answer:**

Newton's theory identified mass as the factor that causes gravity. On the other hand, Einstein's theory identified the curvature of space-time as the factor that causes gravity.

**Answer:**

Hey mate...

**Explanation:**

This is ur answer....

In the 17th century Newton concluded that objects fall because they are pulled by Earth's gravity. Einstein's interpretation was that these objects do not fall. According to Einstein, these objects and Earth just freely move in a curved spacetime and this curvature is induced by mass and energy of these objects.

Hope it helps you,

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You wish to make a simple amusement park ride in which a steel-wheeled roller-coaster car travels down one long slope, where rolling friction is negligible, and later slows to a stop through kinetic friction between the roller coaster's locked wheels sliding along a horizontal plastic (polystyrene) track. Assume the roller-coaster car (filled with passengers) has a mass of 743.0 kg and starts 83.4 m above the ground. (a) Calculate how fast the car is going when it reaches the bottom of the hill. m/s (b) How much does the thermal energy of the system change during the stopping motion of the car

**Answer:**

(a) The car is going approximately 40.43 m/s at the bottom of the hill

(b) The thermal energy will increase by 607,268.76 J

**Explanation:**

In the question, we have;

The height of the roller coaster above ground = 83.4 m

The mass of the roller coaster, m = 743.0 kg

(a) By the conservation of energy principle, we have;

The potential energy at the top of the hill, P.E., is equal to the kinetic energy at the bottom of the hill, K.E.

∴ P.E. = K.E.

P.E. = m·g·h

Where;

m = The mass of the roller coaster = 743.0 kg

g = The acceleration due to gravity = 9.8 m/s²

h = The height of the roller coaster = 83.4 m

Therefore, we have;

P.E. = 743.0 kg × 9.8 m/s² × 83.4 m = 607,268.76 J

P.E. = 607,268.76 J

K.E. = 1/2·m·v²

∴ K.E. = 1/2 × 743.0 kg × v²

P.E. = K.E.

∴ P.E. = K.E. = 607,268.76 J

1/2 × 743.0 kg × v² = 607,268.76 J

v² = 607,268.76 J/(1/2 × 743.0 kg) = 1,634.64 m²/s²

v = √(1,634.64 m²/s²) ≈ 40.43 m/s

(b) Given that the material wheel moves along polystyrene track, the sound released will be minimal and almost all the kinetic energy will be converted to heat energy when the train stops, therefore, the thermal energy will increase by K.E. = 607,268.76 J

The** thermal energy change** of the system is **624,492 J.**

We know that in the **roller coaster**, there is an energy transformation from **gravitational potential energy** to** kinetic energy**. As such we can write;

mgh = 1/2mv^2

Where we cancel out the **mass **from both sides, we are left with;

gh=0.5v^2

v= √gh/0.5

v = √10 × 83.4 m/0.5

v = **41 ms-1**

Now the **kinetic energy **is converted also into **heat energy **hence;

Thermal energy change of the system = 1/2 mv^2 = 0.5 × 743.0 kg × ( 41 ms-1)^2 = **624,492 J**

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The potential energy of a 40-kg cannonball is 14000 J. How high was the cannon ball to have this much potential energy?

**Answer:**

35.71 m

**Explanation:**

Potential energy is calculated using this formula:

We are given 3 out of the 4 variables in this problem. We want to solve for h, the height of the cannon ball.

List out the known variables:

PE = 14,000 J m = 40 kg g = 9.8 m/s² h = ? mSubstitute these values into the potential energy formula.

14,000 = (40)(9.8)h 14,000 = -392h h = 35.7142857143The cannonball was **35.71 m** high to have a potential energy of 14,000 J.

NEED HELP ASAP TEST IS DUE TMR

What is the angular displacement of a wheel with a 3mm radius and an angular speed of 6 rad/s over a time period of 2.5 seconds?

**Answer:**

The answer should be uranus

**Explanation:**

the motion of a body with respect to another body is?

**Answer:**

Motion that changes the orientation of a body is called rotation. ... In both cases all points in the body have the same velocity (directed speed) and the same acceleration (time rate of change of velocity).

**Answer:**

its called relative speed

A 0.242 g sample of potassium is heated in oxygen. The result is 0.292 g of a crystalline compound. What is the formula of this compound?

A.

KO3

B.

KO2

C.

KO

D.

K2O

**Answer:**

Hello there Dude answer is B :D hope it helped mark me brainliest.

The **formula **of the **compound formed **has been [tex]\rm \bold {K_2O}[/tex]. Thus, **option D **is **correct**.

The **sample **of **potassium **has **mass **of **0.242 g**. Since, the **substance **has been **heated **in the presence of **oxygen**, the **gain **in the **weight **has been **corresponds **with the **mass **of **oxygen**.

The given **sample **has:

**Mass **of **potassium**, [tex]m_K=0.242\;\text g[/tex]

**Mass **of **heated sample**, [tex]m_S=0.292\;\text g[/tex]

The **mass **of **oxygen **([tex]m_O[/tex]) in the **sample **has been given as:

[tex]m_O=m_S-m_K[/tex]

**Substituting **the **values**:

[tex]m_O=0.292\;-\;0.242\;\text g\\m_O=0.05\;\text g[/tex]

The **mass **of **oxygen **in the **sample **has been **0.05 g.**

The **moles **(** M**) of

[tex]M=\dfrac{m}{mwt}[/tex]

Where, ** m **has been the

** mwt **has been the

The **moles **of **potassium **([tex]M_K[/tex]) has been given as:

[tex]M_K=\dfrac{0.242}{39.098}\\M_K=0.006\;\text mol[/tex]

The **moles **of **oxygen **([tex]M_O[/tex]) has been given as:

[tex]M_O=\dfrac{0.05}{16}\\M_O=0.003\;\text mol[/tex]

The **molecular compound **has been formed with **Potassium **and **oxygen **in the **ratio **of their **moles **as:

[tex]\rm \dfrac{K}{O}=\dfrac{0.006}{0.003}\\ \dfrac{K}{O}= \dfrac{2}1}[/tex]

Thus, the **molecular formula **of the **compound **has been [tex]\rm \bold {K_2O}[/tex]. Thus, **option D **is **correct**.

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What did Thomas Edison create that made him most famous today? I know it is something about light, but I do not believe he was first. May someone tell me his most famous accomplishment in easy words to understand? Thanks

**Explanation:**

Thomas Edison invented the incandescent light bulb which is kind of like the light bulbs we use today. but they have been improved throughout the years.

hope this is simple and understandable

**Answer:**

One of the most famous and prolific inventors of all time, Thomas Alva Edison exerted a tremendous influence on modern life, contributing inventions such as the incandescent light bulb, the phonograph, and the motion picture camera, as well as improving the telegraph and telephone.

**Explanation:**

*Your **well-wisher*

PLEASE CLICK ON THIS IMAGE I NEED HELP

**Answer:**

Second option

**Explanation:**

"Uniform" pretty much means the same thing happens.

Which of these statements is true about the effect of a force exerted upon an object?

A. A large force always produces a large change in the object’s momentum.

B. A small force always produces a large change in the object’s momentum.

C. A small force applied over a long time interval can produce a large change in the object’s momentum.

D. A large force produces a large change in the object’s momentum only if the force is applied over a very short time interval.

Answer:

D. A large force produces a large change in the object’s momentum only if the force is applied over a very short time interval.

Explanation:

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

[tex] Momentum = mass * velocity [/tex]

Also, the impulse of an object is given by the formula;

[tex] Impulse = force * time [/tex]

In accordance with the impulse-momentum theorem, the statement which is true about the effect of a force exerted upon an object is that a large force produces a large change in the object’s momentum only if the force is applied over a very short time interval.

when a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with a mass 12 kg, the acceleration of the object is 6 m/s. If the same force acts on another object whose mass is 9kg, what is the objects acceleration

**Answer:**

8 m/s²

**Explanation:**

From the question,

Since the same force act on both object,

F = ma = m'a'.............................. Equation 1

Where F = force action on the obeject, m = mass of the first object, a = acceleration of the first object, m' = mass of the second object, a' = acceleration of the second object.

make a' the subject of the equation

a' = ma/m'................... Equation 2

Given: m = 12 kg, a = 6 m/s², m' = 9 kg.

Substitute these values into equation 2

a' = 12(6)/9

a' = 8 m/s².

Hence the acceleration of the second object is 8 m/s²

A student at a polymer lab conducted a stress-relaxation experiment on a polymer, whose material response can be modeled by the Maxwell model. In the experiment, a 10-cm-long bar was stretched instantly until the stress reached 200 MPa. After 2 min, the measured stress in the bar was 160 MPa. a) Calculate the relaxation time constant of the polymer. b) If the initial stress was reached by stretching the bar by 16 mm, what is the viscosity of the dashpot in the Maxwell model

**Answer: add 10 cm plus 200 mpa divided by 2 min then caculate that into 160 bars.**

**Explanation:**

a) The **relaxation **time constant of the **polymer **is approximately 8.9 min.

b) The **viscosity **of the dashpot in the **Maxwell model **is approximately 4.55 GPa s.

The stress-relaxation response of the **Maxwell model **can be modeled by the following equation:

σ(t) = σ₀ exp(-t/τ)

where σ₀ is the initial stress, τ is the relaxation time constant, and t is the time.

a) The **relaxation time **constant of the polymer:

σ(2 min) = 160 MPa

σ₀ = 200 MPa

160 MPa = 200 MPa exp(-2 min/τ)

Taking the natural **logarithm **of both sides, we get:

ln(160/200) = -2 min/τ

Solving for τ, we get:

τ = -2 min / ln(160/200) ≈ 8.9 min

Therefore, the **relaxation time **constant of the **polymer **is approximately 8.9 min.

b) The displacement of the spring in the Maxwell model can be modeled by the following equation:

x(t) = (σ₀ / G) (1 - exp(-t/τ))

where G is the **shear modulus **of the polymer. We can use this equation and the given displacement of 16 mm to find the **viscosity **of the dashpot:

x(t) = 16 mm = 0.016 m

σ₀ = 200 MPa

τ = 6.09 min = 365.4 s

Assume that the **shear modulus **of the polymer is constant and use the given stress to find it:

G = σ₀ / γ

where γ is the **strain **induced by the stretching.

Since the bar was stretched by 16 mm and its original length was 10 cm (i.e., 100 mm), the strain is:

γ = 16 mm / 100 mm = 0.16

Therefore,

G = 200 MPa / 0.16 = 1250 MPa

Now we can solve for the **viscosity **of the dashpot:

η = σ₀τ / x(t)

= (200 MPa) (365.4 s) / (0.016 m)

≈ 4.55 GPa s

Therefore, the **viscosity **of the dashpot in the **Maxwell model **is approximately 4.55 GPa s.

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g Design an experiment you can use to determine the mass of the metal cylinder. When you explain your experiment, be sure to mention: What is the underlying model (equation) that you can use to determine the mass from your measurements

**Answer:**

m = [tex]\frac{k}{g}[/tex] x,

**graph of x vs m**

**Explanation:**

For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation

F_e -W = 0

k x = m g

m = [tex]\frac{k}{g}[/tex] x

We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a **graph of x vs m **is made to serve as a spring calibration.

In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass

A woman pushes a 35.0 kg object at a constant speed for 10.8 m along a level floor, doing 280 J of work by applying a constant horizontal force of magnitude F on the object. (a) Determine the value of F (in N). (Enter the magnitude.) N (b) If the worker now applies a force greater than F, describe the subsequent motion of the object. The object's speed would increase with time. The object's speed would remain constant over time. The object would slow and come to rest. (c) Describe what would happen to the object if the applied force is less than F. The object's speed would increase with time. The object's speed would remain constant over time. The object would slow and come to rest.

**Answer:**

**a) F= 25.9 N**

**b) The object's speed would increase with time.**

**c) The object would slow and come to rest.**

**Explanation:**

**a)**

[tex]W = F_{app} * d (1)[/tex]

We can solve for Fapp, replacing W and d by their values:[tex]F_{app} =\frac{W}{d} = \frac{280J}{10.8m} = 25.9 N (2)[/tex]

**b)**

**c)**

a sentence that describes how energy is related to work

**Answer:**

Energy should be transferred to an object in order to move it. ... This amount of energy transferred by the force to move an object is called work or work done. Thus, the relation between Work and Energy is direct. That is, the difference in the Kinetic energy of an object is work done by an object

An amusement park ride called the Rotor debuted in 1955 in Germany. Passengers stand in the cylindrical drum of the Rotor as it rotates around its axis. Once the Rotor reaches its operating speed, the floor drops but the riders remain pinned against the wall of the cylinder. Suppose the cylinder makes 26.0 rev/min and has a radius of 3.70 m. 1) What is the coefficient of static friction between the wall of the cylinder and the backs of the riders

**Answer:**

**μs = 0.36**

**Explanation:**

[tex]F_{frmax} = \mu_{s}* F_{n} = m * g (1)[/tex]

where μs= coefficient of static friction (our unknown)As we have already said Fn = Fc.The value of the centripetal force, is related with the angular velocity ω and the radius of the drum r, as follows:[tex]F_{n} = m* \omega^{2} * r (2)[/tex]

Replacing (2) in (1), simplifying and rearranging terms, we can solve for μs, as follows:[tex]\mu_{s} = \frac{g}{\omega^{2} r} (3)[/tex]

Prior to replace ω for its value, is convenient to convert it from rev/min to rad/sec, as follows:[tex]\omega = 26.0 \frac{rev}{min} * \frac{1min}{60 sec} *\frac{2*\pi rad }{1 rev} = 2.72 rad/sec (4)[/tex]

Replacing g, ω and r in (3):[tex]\mu_{s} = \frac{g}{\omega^{2} r} = \frac{9.8m/s2}{(2.72rad/sec)^{2} *3.7 m} = 0.36 (5)[/tex]Each vertical line on the graph is 1 millisecond (0.001 s) of time. What is the period and

frequency of the sound waves?

**Explanation:**

Given that,

Each vertical line on the graph is 1 millisecond (0.001 s) of time.

We need to find the period and the frequency of the sound wave. The period of a wave is equal to the each vertical line on graph i.e. 0.001 s.

Let f be the frequency of the sound wave. So,

f = 1/T

i.e.

[tex]f=\dfrac{1}{0.001 }\\\\f=1000\ Hz[/tex]

So, the period and the frequency of the sound waves is 1 milliseond and 1000 Hz respectively.

Cuestions

A radio station is transmitting at a frequency of 15.42 MHz.Calculate the frequency of

the transmission

**Answer:**

The wavelength of the transmitting waves is 55.35 m

**Explanation:**

Radio waves are electromagnetic waves, thus travel at the speed of light (3.0 x [tex]10^{8}[/tex] m/s)

The frequency of transmission = 15.42 MHz

= 15.42 x [tex]10^{6}[/tex] Hz

But,

v = fλ

where: v is the velocity of the wave, f is the frequency and λ is the wavelength

The wavelength of the transmitting waves can be determined by,

λ = [tex]\frac{v}{f}[/tex]

= [tex]\frac{3.0 *10^{8} }{5.42 *10^{6} }[/tex]

= 55.3506

λ = 55.35 m

The wavelength of the transmitting waves is 55.35 m.

During a blood transfusion, gravity is used to provide the pressure to overcome the blood pressure and force the flow through a small needle into a vein. Consider a case where the needle is 3.0 cm long and has an internal diameter of 0.75 mm. If the required rate of flow is 0.03 cm3/s and the blood pressure in the vein is 11.00 kPa higher than atmospheric pressure (Pa), how high should the bottle be placed above the needle

Density of blood = 1.06x10³

Viscosity = 4 mpas

**Answer**:

It should be 1.10 higher

**Explanation**:

L = 0.93

D = 0.75

R = 0.75/2 = 0.375

Q = 0.03x10^-3

Blood pressure = 11x10³

Pn = 4x10^-3

n = 4 x 10^-3

Density of blood = 1.06x10³

Pn - Pv = 8*Q*n*L/pi*r⁴

Pn - pv = 463.57pa

Pn - pv = 463.57pa

Make pn subject

Pn = Pv + 463.57pa ----1

Vn = Q/An

= 0.0679m/s

To get height above needle

Pn + 1/2pv²n = Pa + pgh ----2

We equate 1 and 2 together

We get

Pgh = 11466

To get h we divide through by pg

h = 11466/pg

h = 11466/(1.06x10³)x9.81

h = 1.1026

Approximately

Height = 1.1 meters

So it should be **1.10 meters** higher

*the **full **calculations** are** **in **the **attachment**.*

*thank **you**!*

A piece of gold aluminum alloy weighs 49N. When suspended from a balance and submerged in water it weighs 39.2. What is the weight of gold in the alloy of relative density of gold if 19.3 and aluminum is 2.5

Answer:20.8

Explanation:

You pull with a force of 295 N on a rope that is attached to a block of mass 22 kg, and the block slides across the floor at a constant speed of 1.6 m/s. The rope makes an angle of 35 degrees with the horizontal. What is the net force on the block

**Answer:**

**Fnet = 0**

**Explanation:**

[tex]F_{appx} = F_{app} * cos \theta = 295 N * cos 35 = 242 N (1)[/tex]

In the vertical direction, the block is not accelerated either, so the sum of the normal force and the vertical component of the applied force, must be equal in magnitude to the force of gravity on the block:[tex]F_{appy} = F_{app} * cos \theta = 295 N * sin 35 = 169 N (2)[/tex]

⇒ 169 N + Fn = Fg = 216 N (3)

This means that there must be a normal force equal to the difference between Fappy and Fg, as follows:Fn = 216 N - 169 N = 47 N (4)
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A substance that does not dissolve in a solvent is said to be:A. insolubleB. immiscibleC. miscibleD. soluble
5x + 4 = 3x + 10 how would you solve for the value of x? How would you prove your solution is correct? How would you prove another value is incorrect? Explain in as much detail as possible.
An elementary school is offering 3 language classes: one in Spanish, one inFrench, and one in German. The classes are open to any of the 100 students inthe school. There are 28 students in the Spanish class, 26 in the French class,and 16 in the German class. There are 12 students that are in both Spanish andFrench, 4 that are in both Spanish and German, and 6 that are in both Frenchand German. In addition, there are 2 students taking all 3 classes.(a) If a student is chosen randomly, what is the probability that he or she isnot in any of the language classes
Imagine that you mixed flour, sugar, salt, baking powder, eggs, and milk in a bowl while making cake batter. Would the order in which you mixed the ingredients affect the total mass of the mixture? ANSWER THIS EMEDEITLY PLEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEAAAASEthank you () (ps. this is the closest subject to science (that deals with volume, mass, and matter you know that kind of stuff )that I could find
7x10+2x1+6x1/10+3x1/1000
What do you think was the most important factor that caused the French Revolution?A) The wide gap between the rich and the poorB) The fact that the issues and concerns of the people were not taken into account by the rulersC) The fact that there had been a revolution across the Atlantic Ocean
There are three numbers for the combination to the store's safe. The first number is 17. The two numbers can be multiplied together to give a product of 28. What are all of the possibilities for the other two numbers? IT IS MULTIPLICATION BTW
how many 0 are in 123456789123456789000012010100101010101010101010010