Answer:
Option C
Explanation:
Diverging lens are negative lens as they have negative focal length. Their
magnification is smaller than one.
They produce virtual image in which the refracted rays extended back in order to meet
Hence, option C is correct
I WILL GIVE BRAINLY
1. Describe the electromagnet’s field. What pattern/connection do you see? Explain.
Explanation:
sana po nakatulong
pa brainliest po thanks❤
Jenny is doing her homework when Jenny writes, the pencil exerts a force of 5N on the paper. The area of the pencil in contact with the paper is 0.5mm2 calculate the pressure of the pencil in the paper give the unit
Answer:
here is your answer
mark me as brainlist
Planets A and B have the same size, mass, and direction of travel, but planet
A is traveling through space at half the speed of planet B. Which statement
correctly explains the weight you would experience on each planet?
A. You would weigh the same on both planets because their masses
and the distance to their centers of gravity are the same.
B. You would weigh more on planet B because it is traveling twice as
fast as planet A.
C. You would weigh the same on both planets because your mass
would adjust depending on the planet's speed.
D. You would weigh less on planet B because it is traveling twice as
fast as planet A.
Answer:
A. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.
Explanation:
Given that Planets A and B have the same size, mass.
Let the masses of the planets A and B are and respectively.
As masses are equal, so .
Similarly, let the radii of the planets A and B are and respectively.
As radii are equal, so .
Let my mass is m.
As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.
So, my weight on planet A,
my weight of planet B,
By using equations (i) and (ii),
.
So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.
Hence, option (A) is correct.
Which statement is the best interpretation of the ray diagrem shown below
Answer:
B...................
Answer:
Option A is correct: "A concave mirror forming a larger, virtual image"
Explanation:
There are two types of mirror:
Concave (converging) mirrors: a concave mirror is a mirror that reflects the light inward
Convex (diverging) mirrors: a convex mirror is a mirror that reflects the light outward
The image formed by a mirror can also be of two types:
Real image: it is formed on the same side of the object, with respect to the mirror
Virtual image: it is formed on the opposite side of the object, with respect to the mirror
In the figure of this problem, we see that:
< The mirror reflects the light from the object inward --> so it is a concave mirror
< The image is formed on the other side of the mirror --> it is a virtual image
So the correct option is
A) A concave mirror forming a larger, virtual image
Dont have a question rn
Answer:
you have gay
Explanation:
699999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999ooooooooooooooooooooooooooo
Answer:
Answer: C. -12 newtons
Explanation: Since, the block is in static equilibrium,
the net force on the block is zero i.e. balance forces are acting on the block.
In the horizontal direction,
force applied+force due to friction = 0
20 N + (-20N) = 0
In the vertical direction as well, net force is zero:
Force due to gravity + force exerted by the ground = 0
12 N + force exerted by the ground = 0
⇒force exerted by the ground = 0 -12 N = -12 N
Thus, the correct option is C. -12 N where negative sign means that the direction of the force due to ground is opposite to the force of gravity.
To pop a balloon you stab it with a pencil. If the area of the pencil tip is .01 cm² and the pressure applied by the pencil to the balloon is 100 N/ cm², how hard (what force) must you push on the pencil to make the balloon pop?
Answer:
Push with force of 1N
Explanation:
I have explained in the paper.
Goodluck
You must push with 1 newton on the pencil to make the balloon pop.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.
A spring balance can be used to calculate the Force. Newton is the SI unit of force.
Applied pressure is = 100 N/cm².
Cross sectional area = 0.01 cm².
The required force = pressure × area
= 100 N/cm² × 0.01 cm²
= 1 Newton.
Hence, you must push with 1 newton on the pencil to make the balloon pop.
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ASAPP PLS HELP MEE
The density of aluminum is 2.7 g/cm^3. Which of the following statement is true?
A) 1 g of aluminium has a volume of 1 cm^3
B) 2.7 g of aluminium has a volume of 1 cm^3
C) 1 g of aluminium has a volume of 2.7 cm^3
D) 2 g of aluminium has a volume of 7 cm^3
Answer:
B) 2.7 g of aluminium has a volume of 1 cm^3
Explanation:
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
[tex]Density = \frac{mass}{volume}[/tex]
If the density of aluminum is 2.7 g/cm³, it simply means that 2.7 g of aluminium has a volume of 1 cm³
Check:
Given the following data;
Mass = 2.7 grams
Volume = 1 cm³
Substituting into the formula, we have;
[tex]Density = \frac{2.7}{1}[/tex]
Density = 2.7 g/cm³
name the device of measurement and write its used or its function?
Answer:
There is a lot of instruments used for measurement, may I ask which one are you referring to?
Which best compares radiation and conduction?
C Both transfer thermal energy from warm objects to cooler objects.
O Both can transfer energy through empty space.
O Both transfer thermal energy by electromagnetic waves.
O Both involve the transfer of energy through direct contact.
Answer:
The statements that best compares radiation and conduction are the following: both transfer thermal energy from warm objects to cooler objects and both can transfer energy through matter. The difference is that conduction is through direct heat transfer; whereas, radiation transfers heat through waves.
1) Un cuerpo se mueve desacelerando a razón de 8m/s2, calcula: a) La velocidad que tenía 5 segundos antes de detenerse. b) La distancia recorrida los últimos 5 segundos de su trayectoria.
Answer:
Initial velocity (u) = 40 m/s
Distance travel in last 5 seconds = 100 m
Explanation:
Given:
Acceleration (a) = 8 m/s²
Final velocity (v) = 0 m/s
Find;
1] Initial velocity before 5 sec
2] Distance travel in last 5 seconds
Computation:
1] Initial velocity before 5 sec
v = u + at
0 = u + (-8)(5)
u - 40 = 0
Initial velocity (u) = 40 m/s
2] Distance travel in last 5 seconds
s = ut + (1/2)(a)(t²)
s = (40)(5) + (1/2)(-8)(5²)
s = 200 - 100
Distance travel in last 5 seconds = 100 m
What is the pH when just enough ammonia solution is added to react with all the nitric acid?
Answer:
<7
Explanation:
This is a reaction between a steong acid and a weak base which produces a acidic salt at equvalence point. Hence pH is less than 7
What is Meaning of Registration
Answer:
Theres 2 meanings first is:
the action or process of registering or of being registered.
The other one is:
a combination of stops used when playing the organ.
The meaning of registration is the action of process of registering to some applications or websites which includes some terms and conditions also.
What is registration?Registration is the process or action of registering into a website or application or to any institute through online or offline mode. By registering we are giving some personal and professional details as per the requirements of the source which need us to be registered.
For example, if we are applying for a central examination, we have to register our name and details in the official website of the examination board.
The registration process bring us some terms and conditions which we can apply or accept to continue the registration process. After successful registration we can have an acknowledgement for the action.
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help please just give the answers asap no explanation needed
Answer:
where is the question? I can only see the diagram
d) is an atom of Sodium and an atom of Chlorine.
e) is a molecule of water.
pls someone should help me answer question 3. Thank you
Answer:
(a) 12 m/s
(b) At t = 0, x'(t) = 0
At t = 5.0 s, x'(t) = 15 m/s
At t = 10.0 s, x'(t) = 12 m/s
(c) i. The initial velocity = 2.0 cm/s
The initial position = 50 cm
The initial acceleration = 0.125 cm/s²
ii. 16 seconds
2. (a) Approximately 0.85 m/s
(b) 2.094 J
(c) i. Approximately 49.74 m/s
ii. Approximately 86.38°
3. (i) 4·i + 5·j
(ii) -2·i - j - 2·k
(iii) 5·i + 4·j - 3·z
(iv) 8
(v) (a) The magnitude is 2.8 cm, the direction is East
(b) The magnitude is ((14·√3)/5) cm, the direction is North
(c) The magnitude is ((14·√3)/5), the direction is South
Explanation:
x(t) is given as follows;
x(t) = b·t² - c·t³
Where;
b = 2.4 m/s(²) (we note that the unit of b for the term to be distance in m/s²)
c = 0.120 m/s³
(a) At t = 0, we have;
x(0) = b × 0² - c × 0³ = 0
At t = 10.0 s, we have;
x(10.0) = 2.4 m/s² × (10.0 s)² - 0.120 m/s³ × (10.0 s)³ = 120 m
The average velocity = (Total distance)/(Total time)
∴ The average velocity of the car for the time interval t = 0 to t = 10.0 s, [tex]v_{ave}[/tex], is given as follows;
[tex]v_{ave}[/tex] = (120 m - 0 m)/(10.0 s - 0 s) = 12 m/s
The average velocity of the car for the time interval t = 0 to t = 10.0 s, [tex]v_{ave}[/tex] = 12 m/s
(b) The instantaneous velocity, [tex]v_{inst}[/tex], is given as follows;
[tex]v_{inst} = \lim \limits_{t \to 0} \left( v_{ave}\right) = \lim \limits_{t \to 0} \left( \dfrac{\Delta x}{\Delta t} \right) = \dfrac{dx}{dt} = x'(t)[/tex]
[tex]x'(t) = \dfrac{d\left (b \cdot t^2 - c \cdot t^3\right)}{dt}[/tex]
x'(t) = 2·b·t - 3·c·t²
At t = 0, x'(t) = 2 × b × 0 - 3 × c × 0² = 0
At t = 5.0 s, x'(t) = 2 × 2.4 m/s² × 5.0 s - 3 × 0.120 m/s³ × (5.0 s)² = 15 m/s
At t = 10.0 s, x'(t) = 2 × 2.4 m/s² × 10.0 s - 3 × 0.120 m/s³ × (10.0 s)² = 12 m/s
(c) x(t) = 50 cm + (2.0 cm/s)·t - (0.0625 cm/s²)·t²
i. The initial velocity is the instantaneous velocity, x'(t), at time, t = 0
x'(t) = 2.0 cm/s - 2 × 0.0625 cm/s² × t
At t = 0, x'(0) = 2.0 cm/s - 2 × 0.0625 cm/s² × 0 = 2.0 cm/s
The initial velocity, x'(0) = 2.0 cm/s
The initial position = The position at time t = 0 = x(0)
x(0) = 50 cm + (2.0 cm/s) × 0 - (0.0625 cm/s²) × 0² = 50 cm
The initial position, x(0) = 50 cm
The initial acceleration, x''(0) = 2 × 0.0625 cm/s² = 0.125 cm/s²
ii. x'(t) = 2.0 cm/s - 2 × 0.0625 cm/s² × t
When the velocity of the turtle, x'(t) = 0 we have;
0 = 2.0 cm/s - 2 × 0.0625 cm/s² × t
∴ t = (2.0 cm/s)/(2 × 0.0625 cm/s²) = 16 seconds
The velocity of the turtle is zero after 16 seconds
2. The mass of the large fish, m₁ = 15.0-kg
The speed of the large fish, v₁ = 1.1 m/s
The mass of the smaller fish, m₂ = 4.50 kg
The speed of the small (stationary) fish, v₂ = 0
The initial momentum = 15.0 kg × 1.1 m/s + 4.50 kg × 0 = 16.5 kg·m/s
The initial momentum = 16.5 kg·m/s
The final momentum = (15.0 kg + 4.50 kg) × v₃ = 19.50 kg × v₃
The final momentum = 19.50 kg × v₃
Where;
The total initial momentum = The total final momentum
We get;
16.5 kg·m/s = 19.50 kg × v₃
∴ v₃ = (16.5 kg·m/s)/(19.50 kg)
v₃ = (16.5/19.50) m/s = (11/13) m/s ≈ 0.85 m/s
∴ The speed of the large fish just after it eats the small, v₃ ≈ 0.85 m/s
(b) The initial kinetic energy, K.E.₁ = (1/2) × 15 kg × (1.1 m/s)² = 9.075 J
The final kinetic energy, K.E.₂ = (1/2) × 19.5 kg × (11/13 m/s)² = 363/52 J
The mechanical energy dissipated, ΔE = K.E.₁ - K.E.₂
ΔE = (9.075 - 363/42) J = 1089/520 J ≈ 2.094 J
The mechanical energy dissipated, ΔE = 2.094 J
(c) i. We have the total momentum = 110 × 8.8· j + 85 × 7.2· i = 9.680·i + 612·i
The velocity after collision, v = (9.680·i + 612·i)/(110 + 85) = 49.64·j + 3.14·i
The magnitude of the velocity, v = √(49.64² + 3.14²) ≈ 49.74 m/s
ii. The direction, θ = arctan(49.64/3.14) ≈ 86.38°
3. (i) [tex]\underset{A}{\rightarrow} + \underset{B}{\rightarrow}[/tex] = (i + 2·j - k) + 3·i + 3·j + k = 4·i + 5·j
(ii) [tex]\underset{A}{\rightarrow} - \underset{B}{\rightarrow}[/tex] = (i + 2·j - k) - (3·i + 3·j + k) = -2·i - j - 2·k
(iii) [tex]\underset{A}{\rightarrow} \times \underset{B}{\rightarrow}[/tex] = (2 + 3)·i - (1 + 3)·j + (3 - 6)·z = 5·i + 4·j - 3·z
(iv) [tex]\underset{A}{\rightarrow} \cdot \underset{B}{\rightarrow}[/tex] = 1×3 + 2 × 3 + (-1)×1 = 8
(v) (a) [tex]\underset{A}{\rightarrow} + \underset{B}{\rightarrow}[/tex] = 2.8·cos(60°)·i + 2.8·sin(60°)·j + (2.8·cos(60°)·i - 2.8·sin(60°)·j
[tex]\underset{A}{\rightarrow} + \underset{B}{\rightarrow}[/tex] = 5.6·cos 60°·i = 2.8·i
The magnitude = 2.8, the direction is east
(b) [tex]\underset{A}{\rightarrow} - \underset{B}{\rightarrow}[/tex] = 2.8·cos(60°)·i + 2.8·sin(60°)·j - (2.8·cos(60°)·i - 2.8·sin(60°)·j
[tex]\underset{A}{\rightarrow} - \underset{B}{\rightarrow}[/tex] = 5.6·sin(60°)·j= ((14·√3)/5)·j
The magnitude = ((14·√3)/5), the direction is North
(c) [tex]\underset{B}{\rightarrow} - \underset{A}{\rightarrow}[/tex] = (2.8·cos(60°)·i - 2.8·sin(60°)·j - (2.8·cos(60°)·i + 2.8·sin(60°)·j)
[tex]\underset{B}{\rightarrow} - \underset{A}{\rightarrow}[/tex] = -5.6·sin(60°)·j= (-(14·√3)/5)·j
The magnitude = ((14·√3)/5), the direction is South
PLS HELP IM GOING TO GIVE U BRAINLIST
The nucleus contains positively charged protons and uncharged neutrons . Protons and neutrons are collectively referred to as
A. nucleons
B. atoms
C. ions
d. molecules
From the graph below, which segment has the fastest speed--A, B, C, D, or E?
Answer:
D bcz the slope rose the fastest
Explanation:
I DON'T WANNA BE QUESTIONED, THIS IS BECAUSE y POSITION ROSE FASTER THAN x POSITION
The frequency of a note played on a piano is 262 Hz. Given that the velocity of sound at 20°C is 343 m/s, what is the wavelength of the note?
Answer:
Explanation:
The equation for frequency is
[tex]f=\frac{v}{\lambda}[/tex] where
f = frequency, v is velocity, and lambda is wavelength. Filling in:
[tex]262=\frac{343}{\lambda}[/tex] and
[tex]\lambda=\frac{343}{262}[/tex] so
[tex]\lambda=1.31m[/tex]
The wavelength of the note played on the piano is 1.31m.
Given the data in the question;
Frequency of the note played on a piano; [tex]f = 262Hz = 262s^{-1}[/tex]Velocity; [tex]v = 343m/s[/tex]Wavelength of the note; [tex]\lambda = \ ?[/tex]
WavelengthWavelength is simply referred to as the spatial period of a periodic wave i.e when the shapes of waves are repeated, the distance over which they are repeated is called wavelength. It is expressed as;
[tex]\lambda = \frac{v}{f}[/tex]
Where v is velocity and f is frequency
We substitute our given values into the expression above;
[tex]\lambda = \frac{v}{f} \\\\\lambda = \frac{343m/s}{262s^{-1}} \\\\\lambda = 1.309m\\\\\lambda = 1.31m[/tex]
Therefore, the wavelength of the note played on the piano is 1.31m.
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Match the following. Column A 1. Torque 2. Centre of gravity 3. Plumb line Column B A. Line of centre of gravity B. Maximum constant velocity C. Not in motion D. Point of action of weight E. Turning effect of force F. Study of forces 4. Terminal velocity 5. Statics
Answer:
1. Torque → F. Study of forces
2. C.O.G → D. Point of action of weight.
3. Plumb line → A. Line of C.O.G
Your friend has informed you that his/her uncle has decided not to look after him anymore.Write to your friends uncle giving him at least two reasons why he should change his mind
Answer:
Cause you are their family and they need you. Do you wanna be someone who abandoned them or be the one they look to and dont dislike into adulthood. Also you signed onto this job no one said it was going to be easy but you making your life easier but harder for someone who is just a kid who still needs you.
A partially inflated balloon is faded over the open end of a glass beaker that contains water the beaker is placed in an ice bath which cause the water and causes the balloon to the flea what are the correct designs for the heat and work changes to the beaker and balloon system
Answer:
a
Explanation:
A girl travels 50m in 12s and then another 30m in 5s .Calculate her average speed?
Answer:
4.71m/s
Explanation:
Average speed = Total distance travelled ÷ Total time taken.
80/17=4.71
4.71m/s
Answer:
Average speed = Total distance travelled ÷ Total time taken.In this question,
Total distance travelled = 50m + 30m= 80m.
Total time taken = 12s + 5s= 17s
So, Average speed would be 80 ÷ 17
= [tex]\frac{80}{17}[/tex]
= 4.71 m/s. or 4.71 meter per second.
Answer pls…………………………
how can one add vectors and subtract vectors
Answer
Explanation:
Simple arithmetic cannot be used if two or more vectors are not along the same direction. Vectors can be added when two vectors are in the same direction but for the subtraction of vectors, if the vectors are not in the same direction you then subtract.
Match the reactants with the products. zinc sulfate + copper aluminum chloride + copper copper oxide copper + water copper sulfate + oxygen
Answer:
The Reactants Products
Copper sulfate + zinc → Zinc sulfate + copper
aluminum + copper chloride → Aluminum chloride + Copper
Copper + Oxygen → Copper oxide
Explanation:
The Reactants Products
Copper sulfate + zinc Zinc sulfate + copper
aluminum + copper chloride Aluminum chloride + Copper
Copper + Oxygen Copper oxide
First reaction can be described as a single replacement reaction
Second reaction is also a single replacement reaction just like the first reaction
The third is a synthesis reaction ( i.e. reaction in which elements combine to form single compound )
B
oc
OD
A metal has a specific heat capacity of 360J/(kg°C).
An object made of this metal has a mass of 2.0kg.
What is the thermal capacity (heat capacity) of the object?
Answer:
Thermal capacity of the object = 720 j/°C
Explanation:
Given:
Specific heat capacity of metal = 360J/(kg°C)
Mass of given object = 2 kg
Find:
Thermal capacity of the object
Computation:
Thermal capacity = Specific heat x Mass
Thermal capacity of the object = Specific heat capacity of metal x Mass of given object
Thermal capacity of the object = 360 x 2
Thermal capacity of the object = 720 j/°C
An object with a mass of 7.60 kg is moving to the right and experiences an applied force of 50 N to the right. The friction force on this object is 30 N to the left. What is the acceleration of the object?
Answer:
Explanation:
We will use the equation F - f = ma, which is a fancy way of stating Newton's 2nd Law.
F = +50.0,
f = -30.0,
m = 7.60 kg. Therefore:
50.0 - 30.0 = 7.60a and
20.0 = 7.60a and
a = 20.0/7.60 so
a = 2.63 m/s/s to the right
A swimmer is capable of swimming at 1.4m/s in still water. a. How far downstream will he land if he swims directly across a 180m wide river? b. How long will it take him to reach the other side.
Answer:
t = 180 / 1.4 = 129 sec (time to swim horizontally across river)
S = 129 sec * V where V is speed of current and S is the distance he will be carried downstream
The problem does not specify V the speed of the river
Answer:
Explanation:
From the given information:
a) the distance(D) showing how dar downstream he will land can be computed as follows:
Assuming the current of the river = 0.2 m/s
[tex]D = \dfrac{180 \ m \times 0.2 \ m/s}{1.4 \ m/s}[/tex]
D = 36 m ÷ 1.4
D = 25.71 m
The required time (t) to reach the other side is:
time (t) = 180 m/ 1.4 m/s
time (t) = 128.57 seconds
This ray diagram shows the image formed when a candle is placed in front of
a curved mirror. Which of the following describes the image?
A. Virtual; smaller than object
B. Real; larger than object
C. Virtual; larger than object
D. Real; smaller than object
Answer:
Explanation:
Virtual images are always right side up while real images are always upside down. Therefore, the is a virtual image that is smaller than the original.
five scientist who travelled to space
Answer:
The Most Famous Astronomers of All Time. Karl Tate, SPACE.com. ...
Claudius Ptolemy. Bartolomeu Velho, Public Domain. ...
Nicolaus Copernicus. Public Domain. ...
Johannes Kepler. NASA Goddard Space Flight Center Sun-Earth Day. ...
Galileo Galilei. NASA
What is centripetal force? A. A force acting parallel to the path of an object in circular B. A force opposing motion along a circular path C. A force acting away from the center of a circular motion D. A force acting toward the center of a circular motion
Answer:
c.
Explanation:
Answer:
Centripetal force is the force acting towards the center of circular motion or path.
[tex]{ \tt{formular : \: F = \frac{m {v}^{2} }{r} }} \\ { \tt{F : \: is \: centripetal \: force}} \\ { \tt{m : \: is \: mass}} \\ { \tt{v : \: is \: velocity}} \\ { \tt{r : \: is \: radius}}[/tex]
Explanation:
Its opposite is centrifugal force which acts away from the center of circular path.