Answer:
The answer answer is 150 km
Answer:
Explanation:
Distance =Speed×time
Speed=50km/hr
Time=3hours
Hence the Distance will be(50km/hr×3hours)
The answer is 150km
The objective of baseball is to OUTSCORE your opponent.
True or false
Help ?
Answer:
True
Explanation:
The team with the most points at the end of the game is the winner.
Erin said that when you are standing in front of a fire you are warm because you release the coolness of your body to the heat of the fire.
Chris said that when you are standing in front of a freezer with the door open you feel cool because the air from the freezer is being transferred to your body.
Who has made the accurate statement regarding heat transfer?
Both Erin and Chris are correct.
Erin is correct.
Chris is correct.
Neither Erin nor Chris are correct.
third down, chris is correct
help me with the question b.
Answer:
a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.
b) Liquid P - [tex]Q = 3840\,J[/tex], Liquid Q - [tex]Q = 5500\,J[/tex], Liquid R - [tex]Q = 7800\,J[/tex], Liquid S - [tex]Q = 2856\,J[/tex]
Explanation:
a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.
b) Let suppose that heat transfer rates between liquids and surroundings are stable. The quantity of the heat released is determined by the following expression:
[tex]Q = m\cdot c\cdot (T_{r} - T_{f})[/tex] (1)
Where:
[tex]m[/tex] - Mass of the liquid, in kilograms.
[tex]c[/tex] - Specific heat capacity, in joules per kilogram-degree Celsius.
[tex]T_{r}[/tex] - Initial temperature of the sample, in degrees Celsius.
[tex]T_{f}[/tex] - Freezing point, in degrees Celsius.
Liquid P ([tex]m = 1\,kg[/tex], [tex]c = 160\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]T_{r} = 30\,^{\circ}C[/tex], [tex]T_{f} = 6\,^{\circ}C[/tex])
[tex]Q = (1\,kg)\cdot \left(160\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 6\,^{\circ}C)[/tex]
[tex]Q = 3840\,J[/tex]
Liquid Q ([tex]m = 1\,kg[/tex], [tex]c = 220\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]T_{r} = 30\,^{\circ}C[/tex], [tex]T_{f} = 5\,^{\circ}C[/tex])
[tex]Q = (1\,kg)\cdot \left(220\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 5\,^{\circ}C)[/tex]
[tex]Q = 5500\,J[/tex]
Liquid R ([tex]m = 1\,kg[/tex], [tex]c = 300\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]T_{r} = 30\,^{\circ}C[/tex], [tex]T_{f} = 4\,^{\circ}C[/tex])
[tex]Q = (1\,kg)\cdot \left(300\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 4\,^{\circ}C)[/tex]
[tex]Q = 7800\,J[/tex]
Liquid S ([tex]m = 1\,kg[/tex], [tex]c = 102\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]T_{r} = 30\,^{\circ}C[/tex], [tex]T_{f} = 2\,^{\circ}C[/tex])
[tex]Q = (1\,kg)\cdot \left(102\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 2\,^{\circ}C)[/tex]
[tex]Q = 2856\,J[/tex]
Which formula is used to find an object's acceleration?
Ο α= Δί - Δν
Ο α= Δv+ Δ
Ο α=Δyl Δί
α= Δ / Δν
Answer:
4 option is correct ........
A pole-vaulter first converts kinetic energy into
a. thermal energy.
b. chemical energy. mechanical energy.
c. mechanical energy
d. elastic potential energy.
Answer:
d. elastic potential energy
15. You are watching a baseball game on television that 15
being broadcast from 4500 km away. The batter hits
the ball with a loud "crack" of the bat. A microphone
is located 22 m from the batter, and you are 2.0 m from
the television set. On a day when sound travels 343 m/s
in air, what is the minimum time it takes for you to hear
the crack of the bat after the batter hits the ball?
Answer:
t_total = 6.99 s
Explanation:
It asks us how long it takes to hear the sound, for this we must look for the time (t₁) it takes for the sound to reach the microphone, the time it takes for the video signal (t₂) to reach the television and the time (₃) it takes for the TV sound to reach us, so the total delay time is
t_total = t₁ + t₂ + t₂
we look for t1, it indicates that the distance x = 22m
v = x / t
t = x / v
t₁ = 22/343
t₁ = 6.41 10-2 s
time t₂
t₂ = 4500 103/3 108
t₂ = 1.5 10-5 s
time t₃
t₃ = 2/343
t₃ = 5.83 10⁻³
Total time is
t_total = t₁ + t₂ + t₃
t_total = 6.41 10⁻² + 1.5 10⁻⁵ + 0.583 10⁻²
t_total = 6.99 s
A young student drops a stone off the side of a cliff that is 41 meters high. How long does it take the stone to hit the ground below?
A)
2.89 s
B)
8.36 s
C)
3.20 s
D)
2.04 s
You have recently been called to troubleshoot network connectivity problems at a user's workstation. You have found that the network cable runs across high-traffic areas on the floor, causing the cable to wear through and break. You have replaced the cable with a plenum-rated and shielded twisted pair cable. You would like to minimize the problem and prevent it from happening again.Which of the following will BEST protect the cable from further damage?A. Encase the cable in a protective shield and secure the cable to prevent it from slipping.B. Periodically check the cable for kinks and wear. Replace the cable when necessary.C. Run the cable through the ceiling area instead of across the floor.D. Run the cable under the carpet.
Answer:
C
Explanation:
Prevents further damage to the network cable.
List two applications of an echo?
Answer:
I think the echo sounds do not depend on the direction of the sound and sound the same as the original sound
Explanation:
An echo is defined as a sound that is produced when a sound wave is reflected back from any hard surface and repeated.
Two major application of echo include:
- Bats, fisherman, and dolphins use echoes to detect or identify any object /obstruction.
- Echo is widely used in medical science applications for imaging of human organs such as echocardiography and ultrasound.
I hope this help you!:)
A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42° . What is the force of static friction acting on the box if box has a gravitational force of 112.1 N ?
70 N
80 N
75 N
85 N
Answer:
the correct answer is 75 N
Explanation:
This is a translational balancing exercise, let's set a reference system with the x-axis in the direction of the plane and the y-axis perpendicular to the plane.
In this reference system the force to decompose is the weight
sin 42 = Wₓ / W
cos 42 = W_y / W
Wₓ = W sin 42
W_y = W cos 42
Wₓ = 112.1 sin 42 = 75.0 N
W_y = 112.1 cos 42 = 83.3 N
The expression for equilibrium on the x-axis is
Wₓ - fr = 0
fr = Wₓ
fr = 75.0 N
the correct answer is 75 N
What is the force of gravity between Earth (6.0 × 1024 kilograms) and Venus (4.88 × 1024 kilograms)? The distance between the two planets is about 3.8 × 1010 meters. (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)
Answer:
ans: 13.53 × 10^17 Newton
Please help me find the answers!
Answer:
1. T₁ is approximately 100.33 N
T₂ is approximately -51.674 N
2. 230°F is 383.15 K
3. Part A
The total torque on the bolt is -4.2 N·m
Part B
Negative anticlockwise
Explanation:
1. The given horizontal force = 86 N
The direction of the given 86 N force = To the left (negative) and along the x-axis
(The magnitude and direction of the 86 N force = -86·i)
The state of the system of forces = In equilibrium
The angle of elevation of the direction of the force T₁ = 31° above the x-axis
The direction of the force T₂ = Downwards, along the y-axis (Perpendicular to the x-axis)
Given that the system is in equilibrium, we have;
At equilibrium, the sum of the horizontal forces = 0
Therefore;
T₁ × cos(31°) - 86 = 0
T₁ = 86/(cos(31°)) ≈ 100.33
T₁ ≈ 100.33 N
Similarly, at equilibrium, the sum of the vertical forces = 0
∴ T₁×sin(31°) + T₂ = 0
Which gives;
100.33 × sin(31°) + T₂ = 0
T₂ = -100.33 × sin(31°) ≈ -51.674
T₂ ≈-51.674 N
2. 230° F to Kelvin
To convert degrees Fahrenheit (°F) to K, we use;
[tex]Degrees \ in \ Kelvin, K = (x^{\circ} F + 459.67) \times \dfrac{5}{9}[/tex]
Pluggining in the given temperature value gives;
[tex]Degrees \ in \ Kelvin, K = (230^{\circ} F + 459.67) \times \dfrac{5}{9} = 383.15[/tex]
230°F = 383.15 K
3. Part A
Torque = Force × perpendicular distance from the line of action of the force
Therefore, the clockwise torque = 9 N × 0.4 m = 3.6 N·m (clocwise)
The anticlockeisre torque = 13 N × 0.6 m = 7.8 N·m (anticlockwise)
The total torque o the bolt = 3.6 N·m - 7.8 N·m = -4.2 N·m (clockwise) = 4.2 N·m anticlockwise
Part B
The torque is negative anticlockwise.
the same crops are grown in different seasons true or false
Answer: False
Explanation:
Growing different crops in different seasons in the same field will deplete the soil of nutrients. False. Growing different crops In the same field actually help to improve the fertility of the field.
Ball X has a mass of 8kg and is moving toward ball Y (which is sitting still) at 2m/s. After they collide, ball X is
sitting still. How fast is ball Y moving after the collision if it has a mass of 4kg?
Answer:
v = 4 m/s
Explanation:
Given :
Ball X :
Mass, m1 = 8kg ;
Initial Velocity, u1 = 2 m/s
Final velocity, v1 = 0
Ball Y:
Mass, m2 = 4kg ;
Initial Velocity, u2 = 0 m/s
Final velocity, v2 = v
(m1u1 + m2u2) = (m2v2 + m1v1)
(8*2 + 4*0) = (4*v + 4*0)
16 + 0 = 4v + 0
16 = 4v
v = 16 / 4
v = 4 m/s
Answer:
Explanation:
This is the Law of Momentum Conservation which for us looks like this:
[tex][m_xv_x+m_yv_y]_b=[m_xv_x+m_yv_y]_a[/tex] and that should look familiar to you if this is what you are doing in physics. Filling in our particular info:
[(8.0 × 2.0)+ (4.0 × 0.0)] = [(8.0 × 0.0) + (4.0v)] and
16 + 0 = 0 + 4.0v and
16 = 4.0v so
v = 4.0 in the direction of ball X
Which nutrients are needed in soil in larger doses?
Mineral Nutrients
Macronutrients
Non-mineral Nutrients
Micronutrients
Answer:
The primary nutrients are nitrogen, phosphorus and potassium.
The intermediate nutrients are sulfur, magnesium, and calcium.
The remaining essential elements are the micronutrients and are required in very small quantities.
Answer:
The primary nutrients are nitrogen, phosphorus and potassium.
The intermediate nutrients are sulfur, magnesium, and calcium.
The remaining essential elements are the micronutrients and are required in very small quantities.
Explanation:
A series circuit is shown in the diagram below. What is the potential drop
across Rg? (Ry - 200, R2-40 Q, R3-60 , V = 60 V) (Ohrris law: V-IR)
Answer:
Option C. 20 V
Explanation:
We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:
Resistor 1 (R₁) = 20 Ω
Resistor 2 (R₂) = 40 Ω
Resistor 3 (R₃) = 60 Ω
Equivalent Resistance (R) =?
R = R₁ + R₂ + R₃ (series arrangement)
R = 20 + 40 + 60
R = 120 Ω
Next, we shall determine the current in the circuit. This can be obtained as follow:
Voltage (V) = 60 V
Equivalent Resistance (R) = 120 Ω
Current (I) =?
V = IR
60 = I × 120
Divide both side by 120
I = 60 / 120
I = 0.5 A
Finally, we shall determine the potential drop across R₂. This can be obtained as follow:
Current (I) = 0.5 A
Resistor 2 (R₂) = 40 Ω
Voltage (V) =?
V = IR₂
V = 0.5 × 40
V = 20 V
Therefore, the potential drop across R₂ is 20 V
A free-fall parachutist eventually reaches a top speed where air resistance prevents further acceleration. What name is given to this ‘top speed'?
The name given to it is "terminal velocity".
In reality, it isn't a velocity, and it doesn't happen in free-fall.
Go figure.
Give atleast (5) etypes of cleaning tools , equipment,supplies, and materials that you can find either in your home or school. Identify each use
Answer and Explanation:
Cleaning tools, equipment, supplies, and materials that can be easily found in a school in one each are: scrub brush, sponges, buckets and brooms.
These equipments are essential to promote a clean, organized and safe environment and for this reason, they can be easily found both at school and in a home, since the cleanliness of these two places is essential for the well-being, proactivity and health of the people who attend them.
Atividade 1) A presença do campo magnético terrestre proporciona alguns efeitos interessantes. Dentre eles estão as auroras polares. Faça uma pesquisa e explique como esse fenômeno ocorre. Atividade 2 Utilizando a simulação mostrada na figura abaixo, aproxime o ímã da bússola em várias posições ao longo do plano. a) O que representam as pequenas agulhas ao redor do ímã? b) O que acontece com a agulha da bússola quando o ímã é movimentado ao seu redor? c) Marque a seleção "Mostrar medidor de campo". Movimente o medidor de campo O que você observa em relação ao campo magnético⃗ , quando o medidor de campo se aproxima do imã? c) Marque a caixa de seleção "planeta Terra". Como são mostradas as polaridades do ímã? Por que aparece dessa forma?
VI. A student attaches four drawing pins to a copper rod using candle wax as shown in the diagram
The rod is then heated continuously at one end and the pins fall off in the order 4, 3, 2, 1
Explanation:
[tex]C.) \: Conduction \: \\ \\ = > it \: is \: a \: process \: of \: transferring \: \\ \\ of \: heat \: from \: one \: object \: to \: another \\ \\ when \: they \: are \: in \: contact \: [/tex]
By the conduction process the heat reaches the pin.Option C is correct.
What is heat transfer?The term "heat transfer" refers to the movement of heat. The flow of heat across a system's boundary is due to a temperature differential between the system and its surroundings.
Conduction is the type of heat transfer occurs mainly in solid or by contact.In the given condition the rod is then heated continuously at one end and the pins fall off in the order 4, 3, 2, 1.
By the conduction process the heat reaches the pin.
Hence option C is correct.
To learn more about the heat transfer refer to the link;
https://brainly.com/question/13433948
#SPJ2
Alcohol of mass 21g and density 0.7gcm-3 is mixed with 10g of water. Determine the density
of the mixture. (density of water = 1.0g cm-3)
Answer:
0.775 g/cm³
Explanation:
The given parameters are;
The mass of the alcohol = 21 g
The density of the of the alcohol = 0.7 g/cm³
The mass of water with whichit is mixed = 10 g
The density of water = 1.0 g/cm³
Therefore, the mass of the mixture, m = 21 g + 10 g = 31 g
Volume = Mass/Density
The volume of the alcohol = 21 g/(0.7 g/cm³) = 30 cm³
The volume of the water = 10 g/(1.0 g/cm³) = 10 cm³
Therefore, the volume of the mixture, V = 30 cm³ + 10 cm³ = 40 cm³
The density of the mixture, ρ = (Mass, m)/(Volume, V) = m/V
∴ ρ = (31 g)/(40 cm³) = 0.775 g/cm³
The density of the mixture, ρ = 0.775 g/cm³.
Three circuits diagrams are shown. Which statement about the circuit diagram is accurate?
Answer:
Circuits A and B are both series circuit.
Explanation:
In series combination, two resistors are connected with their ends to ends. The equivalent resistance in this case is given by :
[tex]R_s=R_1+R_2+...[/tex]
In circuit A both voltage (V) and R₁ are connected in series.
Similarly in circuit B, voltage (V), R₁ and R₂ are in series./
Hence, the correct option is (a).
Explain hydraulic machine as force multiplier.
Answer:
The pressure on piston 1 is always equal to the pressure on piston 2. ... It is equal to the force on piston 1, multiplied by A2/A1. Hydraulic systems are called force multipliers for exactly this reason. A small force can be increased by using hydraulics
Explanation:
Radhe Radhe❤
what is the difference between static electricity produced by friction, conduction of electricity, and induction of an electrical charge?
Answer:
ummm a whole bunch
Explanation:
The density of oil is 0.8 g/cm^3. What is the mass of 36 cm^3 of oil? + (1 Point) O 0.29 N O 28.09 28.8 g O 36.89
Answer:
density = mass/volume
density=0.8
volume=36
mass=?
0.8=mass/36
mass = 36x0.8=28.8g
A current of 2.0A flows through a light bulb. What is the amount of charge flowing through the light bulb in 40 seconds?
Answer:
Quantity of charge = 80 Coulombs
Explanation:
Given the following data;
Current = 2 A
Time = 40 seconds
To find the amount of charge flowing through the light bulb;
Mathematically, the quantity of charge passing through a conductor is given by the formula;
Quantity of charge = current * time
Substituting into the formula, we have;
Quantity of charge = 2 * 40
Quantity of charge = 80 Coulombs
Explain the effect of the multiplier in the conversion of a moving coil galvanometer to a voltmeter.
Answer:
Explanation:
A galvanometer which is used for the measurement of a very small current can be converted to a voltmeter when it is connected to a high resistance or a multiplier is a series. The purpose of this is to reduce the amount of current that goes through the galvanometer so as prevent full scale deflection.
Hitungkan pecutan bagi blok di bawah: / Cal
(a)
m= 2 kg
F= 8.0 N
Answer:
Acceleration = 4 m/s²
Explanation:
Given the following data;
Force = 8 N
Mass = 2 kg
To find the acceleration of the block;
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
[tex] Acceleration = \frac {Net \; force}{mass} [/tex]
Substituting into the formula, we have;
[tex] Acceleration = \frac {8}{2} [/tex]
Acceleration = 4 m/s²
¿Cómo se presentan las cargas en la materia, en su estado natural y que no presentan campos eléctricos?
Answer: Se presentan en equilibrio a nivel atómico y/o molecular
Explanation: Sólo los iones presentan campo eléctrico pero no son estables en la naturaleza ya que tienden a encontrar al ion de carga opuesta con el cual equilibrar la carga. El estado de equilibrio de un cuerpo o materia se da al tener idéntica cantidad de electrones (-) que de protones (+)-
The force of friction acting on a sliding crate is 223 N.
How much force must be applied to main- tain a constant velocity?
Answer:
Friction Opposes Motion of an Object.
Now
To get the Net force that Moves an Object and causes acceleration....You subtract the Frictional force
Net force = Pushing Force - Frictional Force
Recall
Net Force; F=Ma
Ma = P - Fr
Now the question asked for How Much force Must be applied to Maintain a Constant velocity.
In a Constant Velocity Motion... Acceleration do not change... Its Zero
So Putting this into the formula above
M(0) = P - Fr
0=P - Fr
Fr = P.
This means
That The force needed to keep this object Moving at Constant Velocity Must be equal to its Frictional Force
Since Frictional Force; Fr =223N
The Applied Force(Pushing Force) Must be equal to 223N too.