What is the difference between a physical change and a chemical change. Give an example of each.
Answer:
A physical change is a change in form.
A Chemical change is a change in materials.
Explanation:
Example of a physical change would be an ice cube meting.
Example of a chemical change would be mixing food coloring into a cup of water.
Guide Questions:
1. How do you compare the distance travelled by the object
when you pushed it with a weak/gentle, strong and
strongest?
Refle
2. Which amount of force applied made the materials travelled
the farthest from the starting point. Nearest the starting
point?
3. What factors do you think affected the movement of the
materials?
Answer:
Kindly check explanation
Explanation:
The force applied is directly proportional to the distance moved by an object, the larger the applied force, the greater the distance moved.
a = f/m
a = acceleration ; f = applied force ; m = mass
From the relation, we can see that acceleration is directly proportional to force applied.
The ball will travel farthest with the greatest applied force while, nearest distance will be attained with the smallest applied force.
The distance covered is affected by both the mass of the object and the applied force
if 7.90 mol of C5H12 reacts with excess O2, how many moles of CO2 will be produced by the following combustion reaction?
Answer:
If 7.9 moles of C₅H₁₂ reacts with excess O₂, 39.5 moles of CO₂ will be produced.
Explanation:
The balanced reaction is:
C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₅H₁₂: 1 moles O₂: 8 molesCO₂: 5 moles H₂O: 6 molesThen you can apply the following rule of three: if by stoichiometry 1 mole of C₅H₁₂ produces 5 moles of CO₂, then 7.9 moles of C₅H₁₂ will produce how many moles of CO₂?
[tex]amount of moles of CO_{2} =\frac{7.9 moles of C_{5}H_{12}*5 moles of CO_{2} }{1 mole of C_{5}H_{12} }[/tex]
amount of moles of CO₂= 39.5 moles
If 7.9 moles of C₅H₁₂ reacts with excess O₂, 39.5 moles of CO₂ will be produced.
Aluminum reacts with excess copper(II) sulfate according to the unbalanced reaction
Al(s) + CuSO4(aq) −→
Al2(SO4)3(aq) + Cu(s)
If 2.98 g of Al react and the percent yield of
Cu is 46.4%, what mass of Cu is produced?
Answer in units of g.
Answer: The mass of Cu produced is 4.88 g
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Given mass of aluminum = 2.98 g
Molar mass of aluminum = 27 g/mol
Plugging values in equation 1:
[tex]\text{Moles of aluminum}=\frac{2.98g}{27g/mol}=0.1104 mol[/tex]
The given chemical equation follows:
[tex]2Al(s)+3CuSO_4(aq)\rightarrow Al_2(SO_4)_3(aq)+3Cu(s)[/tex]
By the stoichiometry of the reaction:
If 2 moles of aluminum produces 3 moles of Cu
So, 0.1104 moles aluminium will produce = [tex]\frac{3}{2}\times 0.1104=0.1656mol[/tex] of Cu
Molar mass of Cu = 63.5 g/mol
Plugging values in equation 1:
[tex]\text{Mass of Cu}=(0.1656mol\times 63.5g/mol)=10.516g[/tex]
The percent yield of a reaction is calculated by using an equation:
[tex]\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100[/tex] ......(2)
Given values:
% yield of product = 46.4 %
Theoretical value of the product = 10.516 g
Plugging values in equation 2, we get:
[tex]46.4=\frac{\text{Actual value of Cu}}{10.516g}\times 100\\\\\text{Actual value of Cu}=\frac{46.4\times 10.516}{100}\\\\\text{Actual value of Cu}=4.88g[/tex]
Hence, the mass of Cu produced is 4.88 g
What would happen to the pressure of a closed sample of gas whose temperature increased while its volume decreased? Explain your reasoning in terms of the kinetic molecular theory of gases.
Answer:
As the temperature increases, the average kinetic energy increases as does the velocity of the gas particles hitting the walls of the container. The force exerted by the particles per unit of area on the container is the pressure, so as the temperature increases the pressure must also increase.
I hope this will help you if not soo sorry :)
The "nitrogen rule" of mass spectrometry requires a compound containing an odd number of nitrogens to have an odd-mass molecular ion and a compound containing an even number of nitrogens to have an even-mass molecular ion. What is the molecular formula of the CHN-containing compound pyrazine, M+ = 80? (The order of atoms should be carbon, then hydrogen, then others in alphabetical order.)
Answer:
C₄H₄N₂
Explanation:
Given that:
M+ = 80.
It implies that the number of nitrogen present in the molecule must also be even according to the Nitrogen rule.
So from the Formula CHN, the nitrogen will have to be 2 because if we make use of 4, it will exceed the given M+ which is 80.
∴
C₄ = 4 × 12 = 48
H₄ = 4 × 1 = 4
N₂ = 2 × 14 = 28
80
As such, the molecular formula of the compound is C₄H₄N₂
A 2.9 kg model rocket accelerates at 15.3 m/s2 with a force of 44 N. Before launch, the model rocket was not moving. After the solid rocket engine ignited, hot gases were pushed out from the rocket engine nozzle and propelled the rocket toward the sky.
Which of Newton’s laws apply in this example?
Answer:
Newton's first and third law of Motion
Explanation:
The laws applying in the example Newton's first and third laws of Motion.
The first law states that any object at rest (ie. not moving) will stay at rest until it is forced to move by an external force. In this case, said force were the propulsion gases ignited.As the hot gases were pushed out from the engine nozzle, there was another force equal in magnitud but opposite in direction (as the gases went down, that force went upwards), said force is directly responsible for the rocket taking off. That is an example of the third law.Answer:
It Newtons first, second, and third laws
Explanation:
g Phosphorus -32 is a commonly used radioactive nuclide in biochemical research, particularly in studies of nucleic acids. The half-life of phosphorus-32 is 14.3 days. What mass of phosphorus-32 is left from an original sample of 175 mg of Na332PO4 after 35.0 days
Answer:
6.88 mg
Explanation:
Step 1: Calculate the mass of ³²P in 175 mg of Na₃³²PO₄
The mass ratio of Na₃³²PO₄ to ³²P is 148.91:31.97.
175 mg g Na₃³²PO₄ × 31.97 g ³²P/148.91 g Na₃³²PO₄ = 37.6 mg ³²P
Step 2: Calculate the rate constant for the decay of ³²P
The half-life (t1/2) is 14.3 days. We can calculate k using the following expression.
k = ln2/ t1/2 = ln2 / 14.3 d = 0.0485 d⁻¹
Step 3: Calculate the amount of P, given the initial amount (P₀) is 37.6 mg and the time elapsed (t) is 35.0 days
For first-order kinetics, we will use the following expression.
ln P = ln P₀ - k × t
ln P = ln 37.6 mg - 0.0485 d⁻¹ × 35.0 d
P = 6.88 mg
there are tiny plants growing on rock fence after the several year . you observe something happened on the rock which of the following describes your observations ? the plants the rock
it is moss
Explanation:
Which best expresses the uncertainty of the measurement 32.23 cm?
A.) ±0.05 cm
B.) 0.1 cm
C.) 1%
D.) ±0.01 cm?
Answer:
D.) ±0.01 cm?
Explanation:
Since 32.23 cm has two decimal places, the uncertainty is taken as one-half the last decimal pace.
The last decimal place is 0.03. Half of this is 0.03 cm/2 = 0.015 cm.
Since we cannot go below two decimal places, we ignore the 5 in 0.015 cm.
So, we have our uncertainty as 0.01 cm.
So, the best expression of the uncertainty in the measurement 32.23 cm is ± 0.01 cm.
So, the answer is D. which is ± 0.01 cm.
greater than 6
Less than or equal to 3
Odd
Not 0
3or9
I think it's 9 ................'
At 1630 hours you started an IV with 500 cc of D5W running at 60 gtt/min using microdrip
tubing (60 gtt/ce). You now receive an BAXTER IV Pump.
A)How many cc/hr should you set the pump for to keep the IV going at the same rate?
Answer:._ml/h
1. B) What time will the infusion be completed?
ions
Answer:
Answer:
0050 hours
Explanation:
The size of the drops is regulated by types of tubing in microdrip tubing 1cc(1ml ) forms 60 gtt.
Gtt in 500 cc D5W is 500×60 gtt.= 30000 gtt.
Time required to infuse whole fluid with the rate of 60gtt /min = 30000gtt÷60gtt/min = 500minute.
= 8hours 20 minute.
Fluid infusion started at 1630 hours after and it ends after 8 hours 30 minutes .
Therefore, infusion will be completed at 1630 hours +0830 hours.= 0050 hours.
A mixture of coarse sand and sugar is 45.0 percent sand by mass. 120.0 grams (g) of the mixture is placed in a fine-mesh cloth bag and dunked repeatedly in Lake Michigan. After drying, the mass of the contents of the bag equals: ________.
A. 66.0 g
B. 120.0 g
C. 65.0 g
D. 72.00 g
E. 54.0 g
Answer:
Option E
Explanation:
From the question we are told that:
Amount of sand in percentage [tex]s_p=45%[/tex]
Sample size[tex]n=120g[/tex]
Note:After being dumped in the river repeatedly the sugar melts away leaving behind the insoluble sand
Generally the equation for Amount of sand content is mathematically given by
[tex]X=n*s_p[/tex]
[tex]X=120*\frac{45}{100}[/tex]
[tex]X=54g[/tex]
Therefore
After drying, the mass of the contents of the bag equals
[tex]X=54g[/tex]
Option E
Dugongs are animals that live in the ocean and eat underwater grasses. The sun is shining on the shallow ocean water where the grasses and dugongs live.
What is happening to the carbon in the water around the grasses and the dugongs? Is carbon moving into the water, moving out of the water, or both?
Answer:
please mark as brainliest
Explanation:
The sun is shining on the shallow ocean water where the grasses and dugongs live. What is happening to the carbon in the water around the grasses and the dugongs? Is carbon moving into the water, moving out of the water, or both? Carbon is not moving into the water; it is only moving out of the water.
Como es la
fórmula química del agua
Answer:
h2o
Explanation:
How are elements with similar properties grouped in the periodic table?
A. In the same half
B. In the same column
C. In the same row
D. In the same box
AAnswer:A
Explanation:
Use the Conductivity interactive to identify each aqueous solution as a strong electrolyte, weak electrolyte, or nonelectrolyte. You are currently in a sorting module. Turn off browse mode or quick nav, Tab to items, Space or Enter to pick up, Tab to move, Space or Enter to drop.
Strong electrolyte Weak electrolyte Nonelectrolyte
NH3 NaCl HCI NaOH C12H22O
Explanation:
strong electrolyte- Nacl HCL NAOH
weak electrolyte- c12H22O, NH3
NaCl,HCl and NaOH are strong electrolytes while ammonia is a weak electrolyte and sucrose is a non-electrolyte.
What are electrolytes?It is a solution which consists of ions which are electrically conducting as a result of movement of ions.Class of electrolytes include most soluble salts,acids and bases which are dissolved in a polar solvent.On dissolution, they separate into the constituent ions.
There are 3 classes according to the nature of substance which results upon dissolution:
1) Strong electrolytes- Substances which on dissolution in a medium dissociate completely are strong electrolytes. eg: NaCl,HCl
2) Weak electrolytes- Substances which on dissolution in a medium dissociate partially are weak electrolytes. eg: NH₃
3)Non-electrolytes- Substances which do not dissociate on dissolution are non-electrolytes. eg: sucrose
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Sound waves travel the same speed through all mediums (solids, liqiuds, and gases).
A
True
B
False
A metal X from two oxide A and B .3.oogm of A and B contain 0.72 and 1.16g of oxygen respectively.calculate the maases of metal in gm which combine with one gram of oxygen in each case
Answer:
Explanation:
Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.
Metal X can form 2 oxides (A and B).
A + B = 3g
The mass of oxygen in A is 0.72g and the mass of oxygen in B is 1.16g.
The mass of metal X in the two oxides will be the same because it's the same metal.
Thus, we represent the mass of the metal in the two oxides as 2X.
2X + 0.72 + 1.16 = 3
2X + 1.88 = 3
2X = 3 - 1.88
2X = 1.12
X = 0.56
Thus, 0.56 g of the metal combines with 0.72g of oxygen in A and 1.16 g of oxygen in B.
Thus, mass of metal (X) in 1g of oxygen in A is
0.56g ⇒ 0.72g
X ⇒ 1
X = 1 × 0.56/0.72
X = 0.78 g
Hence, 0.78g of the metal will combine with 1g of oxygen for A
Also, mass of metal (X) in 1g of oxygen in B is
0.56g ⇒ 1.16g
X ⇒ 1g
X = 1×0.56/1.16
X = 0.48 g
Thus, 0.48g of the metal will combine with 1g of oxygen for B
During a reaction in an aqueous solution, the concentration of bactants
decreases and the amount of products increases. How do these changes in
concentration affect the reaction rate?
A. The reaction rate decreases.
B. The reaction rate varies unpredictably.
C. The reaction rate increases.
D. The reaction rate stays the same.
Answer:
my define it will be turst me is c
Cu20(s) + C(s) - 2Cu(s) + CO(g)
To perform this synthesis, the team added 114.2 grams of Cu20 to 11.1 grams of C to form 87.1 grams of Cu.
In this copper synthesis reaction, what is the limiting reagent and the excess reagent?
Answer:
That means Cu2O is limiting reagent and C is excess reagent
Explanation:
Based on the reaction, 1 mole of Cu2O reacts per mole of C. The ratio of reaction is 1:1.
To solve this question we need to convert the mass of each reactant to moles. The reactant with the lower amount of moles is limiting reactant and the excess reactant is the reactant with the higher number of moles.
Moles Cu2O -Molar mass: 143.09 g/mol-
114.2g Cu2O * (1mol / 143.09g) = 0.798 moles Cu2O
Moles C -Molar mass: 12.01g/mol-
11.1g C * (1mol / 12.01g) = 0.924 moles C
That means Cu2O is limiting reagent and C is excess reagent
The carbon-carbon bonds in benzene are:
O a) Easily broken in chemical reactions
b) A hybrid between double bonds and single bonds
c)
Identical to the carbon-carbon bonds in cyclohexene
d) Identical to the carbon-carbon bonds in cyclohexane
please hurry
Answer:
a
Explanation:
Easily broken in chemical reactions
Regions of compressed air caused by the sound of an explosion correspond to the ___?_____ of the sound waves
Explanation:
Compressions and Rarefactions
A vibrating tuning fork is capable of creating such a longitudinal wave. As the tines of the fork vibrate back and forth, they push on neighboring air particles. The forward motion of a tine pushes air molecules horizontally to the right and the backward retraction of the tine creates a low-pressure area allowing the air particles to move back to the left.

Because of the longitudinal motion of the air particles, there are regions in the air where the air particles are compressed together and other regions where the air particles are spread apart
Regions of compressed air caused by the sound of an explosion correspond to the compressions and rarefactions of the sound waves.
What is a sound wave?A sound wave is any distortion in the movement of energy transported by a suitable environment (e.g., air).
Sound waves can be transmitted by different environments such as air (atmosphere) and aquatic media.In humans, sound waves are captured by the ear and then processed by the nervous system.In conclusion, regions of compressed air caused by the sound of an explosion correspond to the compressions and rarefactions of the sound waves.
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A student named a particular compound 2-ethyl-3-methyl-2-butene. Assuming that the student's choice actually corresponded to the correct distribution of the double bond and the substituents, what is the correct IUPAC name for this compound
Answer:
2-ethyl-3-methylbut-2-ene
Explanation:
The whole idea of IUPAC nomenclature is to devise a universally accepted system of writing the name of a compound from its structure.
According to IUPAC nomenclature, the root of the compound is the longest carbon chain. The substituents are named in alphabetical order and in such a way as to give each one the lowest number. The position of the functional group is indicated accordingly.
For the compound in question, its correct IUPAC name is 2-ethyl-3-methylbut-2-ene.
In an experiment, you added a base, NaOH, one mL at a time to 50 mL acetate buffer and recorded the pH. For the first 6 mL NaOH the pH increased from 4.5 to 4.9. At the 7th mL the pH was 6.6 and by the 8th mL the pH was 10.7. Knowing what you do about titrating acetate buffer with acid, is this experimental result what you expected or is it not expected
Answer:
yes the experimental result is the expected result .
Explanation:
When Titrating acetate buffer with acid the PH will decrease gradually from a more neutral PH to a more acidic level and this is because buffer solutions are prepared with weak acids and its conjugate base.
The results gotten from the continuous addition of base NaOH to the acetate buffer is the expected result because the base is been absorbed by the buffer solution and it is converted to a conjugate base of the buffer solution which will gradually increase the PH level of the solution as more conjugate base is formed due to the addition of more NaOH.
Water (H2O) is a polar solvent, and carbon tetrachloride (CCl4) is a nonpolar solvent. In which solvent is each of the following substances, found or used in the body, more likely to be soluble?
a. NaNO3, ionic
b. I2, nonpolar
c. sucrose (table sugar), polar
d. gasoline, nonpolar
e. vegetable oil, nonpolar
f. benzene, nonpolar
g. LiCl, ionic
h. Na2SO4, ionic
Answer:
a. NaNO3, ionic - water
b. I2, nonpolar - CCl4
c. sucrose (table sugar), polar - water
d. gasoline, nonpolar - CCl4
e. vegetable oil, nonpolar - CCl4
f. benzene, nonpolar -CCl4
g. LiCl, ionic - water
h. Na2SO4, ionic - water
Explanation:
Water is a polar substance. This means that it has the ability to dissolve other polar substances. Furthermore, water, even being made by covalent bonds, manages to dissolve ionic substances, because it is a molecule with a partial positive charge on one side, due to hydrogen, and a partial negative charge on the other side, due to the two molecules of oxygen. In this case, any polar or ionic substance has the ability to be dissolved in water, while any non-polar substance needs a non-polar liquid to be able to be dissolved, such as CCI4.
draw the structure of two acyclic compounds with 3 or more carbons which exhibits one singlet in the 1H-NMR spectrum
Answer:
attached below
Explanation:
Structure of two acyclic compounds with 3 or more carbons that exhibits one singlet in 1H-NMR spectrum
a) Acetone CH₃COCH₃
Attached below is the structure
b) But-2-yne (CH₃C)₂
Attached below is the structure
During a chemical reaction, an iron atom became the ion Fe2+. What happened to the iron atom?
Explanation:
Iron atom is been oxidised as it losses 2 electron to form 2 + ion.
An OH group attached to a hydrocarbon is called a _________ group whereas ______________ is a polyatomic ion with a charge of _______.
An OH group attached to a hydrocarbon is called an alkyl group whereas hydroxide is a polyatomic ion with a charge of -1.
What is OH group?OH group is also called hydroxyl group. Alcohol is a type of organic compound that is characterized by one or more hydroxyl (―OH) groups attached to a carbon atom of an hydrocarbon chain so we can conclude that an OH group attached to a hydrocarbon is called an alkyl group whereas hydroxide is a polyatomic ion with a charge of -1.
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Someone help me fill this out TY
Please fill it out in each blank :)
Answer and Explanation:
We have to identify the anion (negatively charged ion) and the positive ion to form each compound. The sum of the positive and negative charges will be equal to 0 for a neutral compound.
Chloride: the anion is Cl⁻ (1 negative charge).
Magnesium (Mg²⁺) + Chloride (Cl⁻) : MgCl₂
Sodium (Na⁺) + Chloride (Cl-): NaCl
Zinc (Zn²⁺) + Chloride (Cl-): ZnCl₂
Lithium (Li⁺) + Chloride (Cl-) : LiCl
Lead(II) (Pb²⁺) + Chloride (Cl⁻): PbCl₂
Calcium (Ca²⁺) + Chloride (Cl⁻): CaCl₂
Iron(II) (Fe²⁺) + Chloride (Cl⁻): FeCl₂
Iron(III) (Fe³⁺) + Chloride (Cl⁻): FeCl₃
Potassium (K⁺) + Chloride (Cl): KCl
Nitrate: the anion is NO₃⁻ (1 negative charge).
Magnesium (Mg²⁺) + Nitrate (NO₃⁻) : Mg(NO₃)₂
Sodium (Na⁺) + Nitrate (NO₃⁻): NaNO₃
Zinc (Zn²⁺) + Nitrate (NO₃⁻): Zn(NO₃)₂
Lithium (Li⁺) + Nitrate (NO₃⁻) : LiNO₃
Lead(II) (Pb²⁺) + Nitrate (NO₃⁻): Pb(NO₃)₂
Calcium (Ca²⁺) + Nitrate (NO₃⁻): Ca(NO₃)₂
Iron(II) (Fe²⁺) + Nitrate (NO₃⁻): Fe(NO₃)₂
Iron(III) (Fe³⁺) + Nitrate (NO₃⁻): Fe(NO₃)₃
Potassium (K⁺) + Nitrate (NO₃⁻): KNO₃
Sulphate: SO₄²⁻ (2 negative charges)
Magnesium (Mg²⁺) + Sulphate (SO₄²⁻) : MgSO₄
Sodium (Na⁺) + Sulphate (SO₄²⁻): Na₂SO₄
Zinc (Zn²⁺) + Sulphate (SO₄²⁻): ZnSO₄
Lithium (Li⁺) + Sulphate (SO₄²⁻) : Li₂SO₄
Lead(II) (Pb²⁺) + Sulphate (SO₄²⁻): PbSO₄
Calcium (Ca²⁺) + Sulphate (SO₄²⁻): CaSO₄
Iron(II) (Fe²⁺) + Sulphate (SO₄²⁻): FeSO₄
Iron(III) (Fe³⁺) + Sulphate (SO₄²⁻): Fe₂(SO₄)₃
Potassium (K⁺) + Sulphate (SO₄²⁻): K₂SO₄
Carbonate: CO₃²⁻ (2 negative charges)
Magnesium (Mg²⁺) + Carbonate (CO₃²⁻) : MgCO₃
Sodium (Na⁺) + Carbonate (CO₃²⁻): Na₂CO₃
Zinc (Zn²⁺) + Carbonate (CO₃²⁻): ZnCO₃
Lithium (Li⁺) + Carbonate (CO₃²⁻): Li₂CO₃
Lead(II) (Pb²⁺) + Carbonate (CO₃²⁻): PbCO₃
Calcium (Ca²⁺) + Carbonate (CO₃²⁻): CaCO₃
Iron(II) (Fe²⁺) + Carbonate (CO₃²⁻): FeCO₃
Iron(III) (Fe³⁺) + Carbonate (CO₃²⁻): Fe₂(CO₃)₃
Potassium (K⁺) + Carbonate (CO₃²⁻): K₂CO₃
Hydroxide: OH⁻ (1 negative charge)
Magnesium (Mg²⁺) + Hydroxide (OH⁻): Mg(OH)₂
Sodium (Na⁺) + Hydroxide (OH⁻): NaOH
Zinc (Zn²⁺) + Hydroxide (OH⁻): Zn(OH)₂
Lithium (Li⁺) + Hydroxide (OH⁻): LiOH
Lead(II) (Pb²⁺) + Hydroxide (OH⁻): Pb(OH)₂
Calcium (Ca²⁺) + Hydroxide (OH⁻): Ca(OH)₂
Iron(II) (Fe²⁺) + Hydroxide (OH⁻): Fe(OH)₂
Iron(III) (Fe³⁺) + Hydroxide (OH⁻): Fe(OH)₃
Potassium (K⁺) + Hydroxide (OH⁻): KOH
Phosphate: PO₄³⁻ (3 negative charges)
Magnesium (Mg²⁺) + Phosphate (PO₄³⁻): Mg₃(PO₄)₂
Sodium (Na⁺) + Phosphate (PO₄³⁻): Na₃PO₄
Zinc (Zn²⁺) + Phosphate (PO₄³⁻): Zn₃(PO₄)₂
Lithium (Li⁺) + Phosphate (PO₄³⁻): Li₃PO₄
Lead(II) (Pb²⁺) + Phosphate (PO₄³⁻): Pb₃(PO₄)₂
Calcium (Ca²⁺) + Phosphate (PO₄³⁻): Ca₃(PO₄)₂
Iron(II) (Fe²⁺) + Phosphate (PO₄³⁻): Fe₃(PO₄)₂
Iron(III) (Fe³⁺) + Phosphate (PO₄³⁻): FePO₄
Potassium (K⁺) + Phosphate (PO₄³⁻): K₃PO₄