Write the equation of the circle with center C(-5,8) and radius = 7

Write The Equation Of The Circle With Center C(-5,8) And Radius = 7

Answers

Answer 1

Answer:

( h + 5 )^2 + ( y - 8 ) ^2 = 49

Step-by-step explanation:

Equation of a circle:

( x - h )^2 + ( y - k )^2 = r^2

Where ( h , k ) = center and r = radius

We are given that the circle has a center at ( -5 , 8 ) meaning that h = -5 and k = 8

We are also given that the circle has a radius of 7 meaning that r = 7

Now that we have identified each variable we plug the values into the equation

( h - (-5)^2 + ( y - 8 )^2 = 7^2

Our final step is to simplify

we get that the equation of the circle is

( h + 5 )^2 + ( y - 8 ) ^2 = 49

By the way ^ means exponent


Related Questions

I need help with this!

Answers

Answer:

1.  y=5   x=1

2.  y=4   x=4/5

3.  y=2   x=2/5

Step-by-step explanation:

Plug the y-values in for y:

1. 5=5x

2. 4=5x

3. 2=5x

Then solve for x:

1. x=1

2. x=4/5

3. x= 2/5

Hope this helps!

I need help I’ll mark u as brainlest

Answers

Answer:

105 in³

Step-by-step explanation:

Volume of triangular prism = base area * height

here

base area =  (10*7)/2 = 35

height = 3

Volume = 35* 3 = 105

Ivy is competing in a 400 m race.
She runs at a constant speed of 5.4 m/s for the first 150 m, then 4.5 m/s for 40 seconds.
The remainder of the race takes her 34 seconds to complete.
What is Ivy's average speed for the entire race to 1 dp?

Answers

Answer:

4.5m/s

Step-by-step explanation:

4.5x40=180

180+150=330

400-330=70

70/34=2.05882352941

(2.05882352941x70)+(5.4x150)+(4.5x180)=1791.11764706

1791.11764706/400=4.47779411765

4.47779411765=4.5

4.5m/s

Answer:

Average speed = 3.9 m /s

Step-by-step explanation:

Total distance = 400m

First 150m = 5.4m/s

[tex]speed = \frac{distance}{time} \\\\time = \frac{distance}{speed} = \frac{150}{5.4} = 27.78 \ s[/tex]

Second part :

S = 4.5m/s for 40s

[tex]Distance = speed \times time = 4.5 \times 40 = 180 \ m[/tex]

Third part :

Remaining distance = 400 - 150 -180 = 70m

Time taken to cover it = 34s

[tex]speed = \frac{distance}{time} = \frac{70}{34} = 2.05 \[/tex]

Speed = 2.05m/s

Find average speed

        [tex]Average\ speed = \frac{total \ distance }{total \ time \ taken } \\\\Average \ speed = \frac{400}{101.78} = 3.93 \ mps[/tex]

Round to 1 dp => average speed = 3.9m /s

Expand, and simplify the following expressions a. (2x+y)(x+y) + (2x-y)(x+y)​

Answers

Step-by-step explanation:

2x²+2xy+yx+y²+2x²+2xy-yx+y²

2x²+2x²+2xy+2xy+yx-yx+y²+y²

2x²+2x²+2xy+2xy

4x²+4xy

Your Answer is in the above image.

Hope this solution may help you

HELP HELPPP!!!у- 3
|
у+
у- 3
3
What is the common denominator of y+
3
in the complex fraction
5 2
9* Зу
?
Зу(у – 3)
у(у – 3)
Зу
О 3

Answers

Answer:

The common denominator of [tex]y + \frac{y-3}{3}[/tex] is 3

Step-by-step explanation:

Given

The complex fraction

Required

The common denominator

To solve this, we need not consider the whole complex fraction.

We only consider

[tex]y + \frac{y-3}{3}[/tex]

Take LCM

[tex]y + \frac{y-3}{3} = \frac{3y - (y-3)}{3}[/tex]

Single out the denominator, i.e. 3

Hence, the common denominator of [tex]y + \frac{y-3}{3}[/tex] is 3

PLS HELP

the simplest form of this product has a numerator of

x + 2
x - 2
( x - 2 ) ( x - 2 )
( x + 2 ) ( x - 2 )

and a denominator of

x - 5
( x - 5 ) ( x - 1 )
x - 1
( x + 5 ) ( x + 1 )

the expression has an excluded value of x

- 5
2
-1
5

Answers

(x+2)(x-2) / (x-1)(x-5) this is the simplified form of the expression.

What is fraction?

A fraction is a mathematical term that represents a part of a whole or a ratio between two quantities. It is a way of expressing a number as a quotient of two integers, where the top number is called the numerator, and the bottom number is called the denominator.

x²-3x-10/x²-6x+5 • x-2/x-5

We can factor the numerator and denominator of the first fraction as follows: (x-5)(x+2) / (x-5)(x-1)

Notice that there's a common factor of x-5 in both the numerator and denominator. We can cancel them out, leaving: (x+2) / (x-1)

Now let's simplify the second fraction:

x-2 / x-5

We can't simplify this fraction any further, so we leave it as is.

Putting it all together, we get:

(x+2) / (x-1) * (x-2) / (x-5)

Multiplying the two fractions, we get:

(x+2)(x-2) / (x-1)(x-5)

This is the simplified form of the expression.

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look at attachment below

Answers

I think it’s 8/55=4/x
So it’s 8x=4(55)
8x=220
x=220/8
x=27.5

write the other side of this equation so its true for all values of x: 1/2(6x-10)-x=

Answers

9514 1404 393

Answer:

  2x -5

Step-by-step explanation:

Any equivalent expression can be used. It is perhaps easiest just to simplify the given expression.

  1/2(6x -10) -x = 3x -5 -x = 2x -5

Putting 2x-5 on the right will give an equation true for all x.

  1/2(6x -10) = 2x -5

Cómo chica quiere armar sus propios lindos para una galería de arte los cuadros deben ser de forma cuadrada así que todos los lados deben de medir los mismos y una amiga le donó dos trozos de madera de 128 cm y 224 cm respectivamente qué tan grande es podrían ser los lados sin que sobre madera?

Answers

You need to multiply 2 x 5 and then you get 10 idiot

ppose we are testing a new shampoo to see if it makes hair grow faster. We knowthat the average rate of hair growth is 0.5 inches per month. The hypothesis are as follows:H0:m0:5vs.H1:m>0:5. Suppose that the null hypothesis is not rejected and that thereal truth is that the shampoo actually does make hair grow faster. What type of error, if any,occurred?

Answers

Answer:

Type II error occurred

Step-by-step explanation:

It is given that a new shampoo is being tested to determine whether the hair grows faster by using this shampoo.

It is known that hair grow at 0.5 inches per month at average.

The hypothesis are,

Null hypothesis, [tex]$H_0: \mu=0.5$[/tex]

Alternate hypothesis, [tex]$H_1: \mu>0.5$[/tex]

But it is known that :

Type [tex]$I$[/tex] error occurs when rejecting the null hypothesis when the null hypothesis is true actually.

Type [tex]$II$[/tex] error occurs [tex]\text{when we fail reject the null hypothesis}[/tex] when the null hypothesis is actually false.

Now here since the null hypothesis is not been rejected, type  [tex]$II$[/tex] error had occurred.

Which function is increasing and has a domain of (1,∞ )

Answers

The graph of a square root function has a domain of (0, ∞) and range of [1, ∞).

Answer:

f(x)=log(x-1)+2

Step-by-step explanation:

I did the test on plato and got it right.

Which of the following equations is NOT an example of inverse variation?
I. f(x)=kx
II. f(x)=2kx
f
(
x
)
=
2
k
x
III. f(x)=−kxz

Answers

Based on the equation,the equation which is not an inverse variation is f(x) = kx

Inverse variation

f(x) = kx

= k × x

f(x) = 2k/x

= k(2/x)

f(x) = -kx/z

= k(-x/z)

Inverse variation is given by:

y = k(1/x)

where,

k = constant of proportionality

Therefore, f(x) = kx is not an inverse variation.

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I need help resolving this please

Answers

27x^6 = 387420489

You want something similar but cubed.

[tex]\sqrt[3]{387420489}[/tex] = 729

YOUR ANSWER: 729x^3 = 387420489

Step-by-step explanation:

What are the 2 \ 3 parts of a right angle in a whole wheel?​

Answers

Answer:

[tex]\frac{2}{3} \ part \ of \ right \ angle \ is \ \frac{1}{6} \ part \ of \ a \ whole \ wheel.[/tex]

Step-by-step explanation:

[tex]\frac{2}{3} \ of \ a \ right \ angle \ = \frac{2}{3} \times 90^{\circ} = 60^{ \circ}\\\\A \ whole \ wheel \ is \ = 360^ {\circ}\\\\[/tex]

Now to find what part of 360 is 60 :

[tex]Let \ it \ be \ x\\\\x \times 360 = 60 \\\\x = \frac{60}{360} = \frac{1}{6}[/tex]

Therefore ,

          [tex]\frac{2}{3} \ part \ of \ right \ angle \ is \ \frac{1}{6} \ part \ of \ a \ whole \ wheel.[/tex]

What is 15 5/7 - 6 4/5

Answers

Answer:

8.9

Step-by-step explanation:

15.71428571-6.8=8.914285714

We round of to one significant figure because its addition n the lowest is 6.8

Answer:

[tex]8\frac{32}{35}[/tex]

Step-by-step explanation:

1.) If I am selling a dozen at $3, how much would each egg cost?
2.) If each egg costs that amount of money, how much would an 18 pack be?


I'm trying to figure this out because this is a real-life problem, and I'm trying to sell eggs to my teacher.

Answers

Answer:

1.$3÷12=0.25

each egg would cost 25 cents

2.12×18=216

216×25=5,400

Có 7 cây hãy trồng thành 6 hàng, mỗi hàng 3 cây?

Answers

Answer:

Step-by-step explanation:

Bạn vẽ 1 tức giác ABCD lồi sau đó nối AB và CD cắt nhau tại E, AD và BC cắt nhau tại F, AC và BC cắt nhau tại G. Trồng 7 cây vào các điểm ABCDEFG  l. Ta có sáu hàng là ABE, DCE, BCF, ADF, ACG, BDG

please help steps thx

Answers

Answer:

240 cubic metres

Step-by-step explanation:

I'm not really sure for Q17 but I do know Q18.

Q18. Volume of cuboid = Length×Breadth×Height

=12×4×5

=240 cubic metres

hope it helps!!!

Classify each differential equation as separable, exact, linear, homogeneous, or Bernoulli. Some equations may be more than one kind. Do not solve.
a) dy/dx = (x − y)/x
b) (x + 1)dy/dx = −y + 20
c) dy/dx = 1/(x(x − y2))
d) dy/dx =(y^2 + y)/(x^2 + x)
e) dy/dx = 5y + y^2
f) y dx = (y − xy^2) dy
g) x dy/dx = ye^(xy) − x
h) 2xyy' + y^2 = 2x^2
i) y dx + x dy = 0
k) (x^2 + 2y/x) dx = (3 − ln x^2) dy
l) (y/x^2) dy/dx + e^(2x^3) + y^2 = 0

Answers

a) dy/dx = (x − y)/x=> This is a separable differential equation.b) (x + 1)dy/dx = −y + 20=> This is a linear first-order differential equation.c) [tex]dy/dx = 1/(x(x - y^2))[/tex]=> This is a separable differential equation.d) [tex]dy/dx = (y^2 + y)/(x^2 + x)[/tex]=> This is a separable differential equation.e)[tex]dy/dx = 5y + y^2[/tex]=> This is a Bernoulli differential equation.f) [tex]y dx = (y - xy^2) dy[/tex]=> This is a separable differential equation.g) [tex]x dy/dx = ye^{(xy)} - x[/tex] => This is a linear first-order differential equation.h) [tex]2xyy' + y^2 = 2x^2[/tex]=> This is a linear first-order differential equation.i) y dx + x dy = 0 => This is a separable differential equation.k) [tex](x^2 + 2y/x) dx = (3 - \text ln x^2) dy[/tex] => This is a linear first-order differential equation.l) [tex](y/x^2) dy/dx + e^{(2x^3)} + y^2 = 0[/tex] => This is a linear first-order differential equation.

Here, we have to classify each differential equation based on their characteristics:

a) dy/dx = (x − y)/x

This is a separable differential equation because the variables can be separated on different sides of the equation.

It's of the form dy/dx = g(x) - f(y)/h(y), where g(x) = x/x and h(y) = 1.

b) (x + 1)dy/dx = −y + 20

This is a linear first-order differential equation because it can be rearranged to the form y' + P(x)y = Q(x), where P(x) = -1/(x + 1) and Q(x) = 20/(x + 1).

c) [tex]dy/dx = 1/(x(x - y^2))[/tex]

This is a separable differential equation because the variables x and y can be separated on different sides of the equation.

d) [tex]dy/dx = (y^2 + y)/(x^2 + x)[/tex]

This is a separable differential equation because the variables x and y can be separated on different sides of the equation.

e)[tex]dy/dx = 5y + y^2[/tex]

This is a Bernoulli differential equation because it is of the form [tex]dy/dx = p(x)y + q(x)y^n[/tex], where p(x) = 0 and q(x) = 5x, n = 2.

f) [tex]y dx = (y - xy^2) dy[/tex]

This is a separable differential equation because the variables x and y can be separated on different sides of the equation.

g) [tex]x dy/dx = ye^{(xy)} - x[/tex]

This is a linear first-order differential equation because it can be rearranged to the form y' + P(x)y = Q(x), where P(x) = -1/x and [tex]Q(x) = e^{(xy)} - x^{(-1)[/tex].

h) [tex]2xyy' + y^2 = 2x^2[/tex]

This is a linear first-order differential equation because it can be rearranged to the form y' + P(x)y = Q(x), where P(x) = -2/x and Q(x) = 2x.

i) y dx + x dy = 0

This is a separable differential equation because the variables x and y can be separated on different sides of the equation.

k) [tex](x^2 + 2y/x) dx = (3 - \text ln x^2) dy[/tex]

This is a linear first-order differential equation because it can be rearranged to the form y' + P(x)y = Q(x), although it's not immediately obvious what P(x) and Q(x) are.

l) [tex](y/x^2) dy/dx + e^{(2x^3)} + y^2 = 0[/tex]

This is a linear first-order differential equation because it can be rearranged to the form y' + P(x)y = Q(x), where [tex]P(x) = -1/x^2[/tex] and [tex]Q(x) = -e^{(2x^3)} - y^2[/tex].

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what is 1+1+3+4+6+2+6+3+5=+8+2+5

Answers

Answer:

16

Step-by-step explanation:

baámmáy tính  

An educational psychologist wondered whether there was a relationship between the amount of academic pressure a high school student felt and their plans for college. They surveyed a random sample of 300 high school students throughout the country about their college plans and whether they felt academic pressure. Here are the responses and partial results of a chi-square test (expected counts appear below observed counts):
Chi-square test:
Planned years of college vs. feeling academic pressure now
O years Up to 4 years Up to 4 years More than 4 years Total
Yes 31 48 161 240
31.2 48 160.8
No 8 12 40 60
7.8 12 40.2
Total 39 60 201 300
They want to use these results to carry out a xạ test of independence. Assume that all conditions for inference were met. What are the values of the test statistic and P-value for their test?
What are the values of the test statistic and P-value for their test?
A. x² = 0.002;
0.001 < P-value < 0.0025
B. x² = 0.002;
P-value > 0.25
C. x² = 0.007;
0.005 < P-value < 0.01
D. x² = 0.007;
P-value > 0.25

Answers

Answer:

D. x² = 0.007;

P-value > 0.25

Step-by-step explanation:

The observed and expected values are given below :

Yes____31 48 161 ____240

______31.2 48 160.8

No ____ 8 12 40_____ 60

______7.8 12 40.2

Total __ 39 60 201 ___300

The Chisquare statistic, χ²:

Σ(Observed - Expected)²/ Expected

Chi-Squared Values:

0.00128205 __ 0 __ 0.000248756

0.00512821 __ 0 __ 0.000995025

(0.00128205 + 0 + 0.000248756 + 0.00512821 + 0 + 0.000995025 )

= 0.007654041

The degree of freedom = (row - 1) * (column - 1)

Degree of freedom = (2-1)*(3-1) = 1*2= 2

The Pvalue = 0.9962

Pvalue > 0.25

After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only four women among the last 19 new employees. She also learns that the pool of applicants is very large, with an approximately equal number of qualified men as qualified women.
Help her address the charge of gender discrimination by finding the probability of getting four or fewer women when 19 people are hired, assuming that there is no discrimination based on gender.
(Report answer accurate to 8 decimal places).
P(at most four) =

Answers

Answer:

P(at most four) = 0.00960541

Step-by-step explanation:

For each employee hired, there are only two possible outcomes. Either it is a women, or it is not. The probability of an employee being a women is independent of any other employee, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

19 new employees.

This means that [tex]n = 19[/tex]

Approximately equal number of qualified men as qualified women.

This means that [tex]p = 0.5[/tex]

Probability of getting four or fewer women when 19 people are hired

This is:

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{19,0}.(0.5)^{0}.(0.5)^{19} = 0.00000191[/tex]

[tex]P(X = 1) = C_{19,1}.(0.5)^{1}.(0.5)^{18} = 0.00003624[/tex]

[tex]P(X = 2) = C_{19,2}.(0.5)^{2}.(0.5)^{17} = 0.00032616[/tex]

[tex]P(X = 3) = C_{19,3}.(0.5)^{3}.(0.5)^{16} = 0.00184822[/tex]

[tex]P(X = 4) = C_{19,4}.(0.5)^{4}.(0.5)^{15} = 0.00739288[/tex]

Then

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.00000191 + 0.00003624 + 0.00032616 + 0.00184822 + 0.00739288 = 0.00960541[/tex]

So

P(at most four) = 0.00960541

There is a bag filled with 3 blue and 4 red marbles.
A marble is taken at random from the bag, the colour is noted and then it is replaced.
Another marble is taken at random.
What is the probability of getting exactly 1 blue?

Answers

Answer:

its a three in seven chance, since there are seven total outcomes and there is only one favorable outcome. Hope that helps.

Step-by-step explanation:

I. Read each question carefully, then write the letter of the correct answer.
1. What is the relationship of the volume between a prism and a pyramid of the same dimensions?
A. the volume of the pyramid is 2/3 of the volume of the prism
B. the volume of the pyramid is 3/3 of the volume of the prism
C. the volume of the pyramid is 1/3 of the volume of the prism
D. the volume of the pyramid is 3/2 of the volume of the prism
2. The volume of a cone is the volume of a cylinder if both are of the same dimensions.
A. double B. thrice
C. twice
D. 4 times
3. How many cones can fill the whole sphere with the same dimension?
A. 1
B. 2
C.3
D.4
4. If the volume of a cylinder is 120 m3, what will be the volume of a cone with the same dimension?
A.180m3
B. 60 m3
C. 40 m3
D. 30 m3
5. What is the length of the edge of a cube if it has a volume of 27 cubic inches?
A. 9 in
B. 6 in
C. 3 in
D. 2 in

Answers

Answer:

The answer for number 1 is C

bine like terms.
7 – 64 – 5x3 – 1 + x3 – 7 – 2y
PLS HURRY

Answers

Answer:

-4x³ - 8y - 1

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

7 - 6y - 5x³ - 1 + x³ - 7 - 2y

Step 2: Simplify

[Addition] Combine like terms (x³):                                                                  -4x³ + 7 - 6y - 1 - 7 - 2y[Subtraction] Combine like terms (y):                                                              -4x³ - 8y + 7 - 1 - 7[Subtraction] Combine like terms:                                                                   -4x³ - 8y - 1

Write the phrase as an algebraic expression and simplify if possible. Let x represent the unknown number

Three times a number, decreased by five

(Simplify your answer.)

Answers

EZ,
3x-5
(3x) = 3 times a number.
Decrease means subtract.

To express the phrase "Three times a number, decreased by five" as an algebraic expression, we can use the variable x to represent the unknown number: 3x - 5

Now, let's simplify this expression: Given that the unknown number is represented by x, we can substitute it into the expression above. Substituting x into the expression, we have: [tex]3(x) - 5 3x - 5[/tex] Therefore, the algebraic expression representing "Three times a number, decreased by five" is [tex]3x - 5.[/tex] At this point, there is no further simplification possible since the expression is already in its simplest form.

For example, let's assume the unknown number x is 7. We can plug in this value to evaluate the expression: [tex]3(7) - 5 = 21 - 5 = 16[/tex] Similarly, if x is -2, the calculation would be: [tex]3(-2) - 5 = -6 - 5 = -11[/tex] In conclusion, the algebraic expression 3x - 5 represents the phrase "Three times a number, decreased by five."

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A man, 1.5m tall, is on top of a building. He observes a car on the road at an angle of 75°. If the building is 30m, how far is the car from the building?​

Answers

Answer:

The answer to this question is 8.44 m.

Step-by-step explanation:

This problem is best illustrated in the photo below.

First, we must know that the angle stated in the problem is the angle of depression. Angle of depression is the angle between the horizontal and the line of sight of the observer. On the other hand, if the observer is looking upward, then the angle between the horizontal and his line of sight is called the angle of elevation.

Since we have the given angle of depression, we must use its complementary angle to solve for the distance of the car from the building.

Let x = complementary angle of 75°

y = distance of the car from the building

To solve for x,

To solve for y, we need to use a trigonometric function that will relate the adjacent of 15° and the opposite of 15°. Let us look at the mnemonics

SOH: Sine =  

CAH: Cosine =  

TOA: Tangent =  

Therefore we must use the tangent function to solve for y.

 

A crew clears brush from 1/3 acre of land in 2 days. How long will it take the same crew to clear the entire plot of 2 1/ 2 acres?

Answers

Answer:

15 days

Step-by-step explanation:

Given that :

Time taken to clear 1/3 acre = 2 days

This means that, they will be able to clear ;

1/3 ÷ 2 = 1/3 * 2 /1 = 1/6 acre in one day

1/6 acres per day :

Hence, the number of days it will take to clear 2 1/2 acres will be :

2 1/2 acres ÷ 1/6

5 / 2 ÷ 1/ 6

5/2 * 6 /1 = (5*6) / (2*1) = 30/2 = 15

Hence, it will take 15 days to clear 2 1/2 acres

a bag contains 16 red coins , 8 blue coins , and 8 green coins. A player wins by pulling a red coin from the bag. Is this game fair? Justify your answer

Answers

Answer:

Step-by-step explanation:

there are a total of 16+8+8=32 coins in bag

16 out of 32 are red

player wins by pulling a red coin

assume it is a single pull, the winning probability = 16/32 = 1/2

so it is 50/50 chance n hence a fair game

Step-by-step explanation:

yes it is a fair game because any one don't know what the coin will get, it is based on luck

Construct a frequency polygon that represents the following data regarding the selling prices of houses sold in 2006 for a particular neighborhood find the midpoint

Class Frequency
78787 – 98786 9
98787 – 118786 8
18787 – 138786 9
138787 – 158786 4
158787 – 178786 8

Answers

Answer:

See attachment for polygon

Step-by-step explanation:

Given

[tex]\begin{array}{cc}{Class} & {Frequency} & 78787 - 98786 & 9 &98787 - 118786 & 8 & 118787 - 138786 & 9 & 138787 - 158786 & 4 & 158787 - 178786 & 8 \ \end{array}[/tex]

Required

The frequency polygon

First, we calculate the midpoint of each class.

This is the average of the class limits

So, we have:

[tex]x_1 = \frac{78787 + 98786}{2} = \frac{177573}{2} = 88786.5[/tex]

[tex]x_2 = \frac{98787 + 118786}{2} = \frac{217573}{2} = 108786.5[/tex]

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-

[tex]x_5 = \frac{158787 + 178786}{2} = \frac{337573}{2} = 168786.5[/tex]

(138787 + 158786)/2

So, the table becomes:

[tex]\begin{array}{ccc}{Class} & {Frequency} & {x} &78787 - 98786 & 9 & 88786.5 & 98787 - 118786 & 8 & 108786.5 & 118787 - 138786 & 9 & 128786.5 & 138787 - 158786 & 4 & 148787.5 & 158787 - 178786 & 8 & 168786.5\ \end{array}[/tex]

See attachment for frequency polygon

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