Write a program which:

Allows the user to input any of the following string: A1, A2, B1, B2, C1, C2

If the input is from the A category, the program must output "Footwear: ". And if the input is A1 it should output "Shoes" and if A2 it should output "Trainers"

B should output "Tops: "

B1 "Jackets"

B2 "TShirts"

C "Pants: "

C1 "Trousers"

C2 "Shorts"

If the user has not entered the correct data, the program must output "Incorrect input"

Answers

Answer 1

Answer:

Ill do this in C# and Java

Explanation:

C#:

public static void Main(string[] args)

       {

           string input = Console.ReadLine();

               switch (input)

               {

                   case "A1":

                       Console.WriteLine("Footwear:");

                       Console.WriteLine("Shoes");

                       break;

                   case "B1":

                       Console.WriteLine("Tops:");

                       Console.WriteLine("Jackets");

                       break;

                   case "C1":

                       Console.WriteLine("Pants:");

                       Console.WriteLine("Trousers");

                       break;

                   case "A2":

                       Console.WriteLine("Footwear:");

                       Console.WriteLine("Trainers");

                       break;

                   case "B2":

                       Console.WriteLine("Tops:");

                       Console.WriteLine("TShirts");

                       break;

                   case "C2":

                       Console.WriteLine("Pants:");

                       Console.WriteLine("Shorts");

                       break;

                   default:

                       Console.WriteLine("Incorrect Input");

                       break;

               }

       }

Java:

public static void main(String[] args)

   {

       Scanner myObj = new Scanner(System.in);  // Create a Scanner object

       String input = myObj.nextLine();

       {

           switch (input)

               {

                   case "A1":

                       System.out.println("Footwear:");

                       System.out.println("Shoes");

                       break;

                   case "B1":

                       System.out.println("Tops:");

                       System.out.println("Jackets");

                       break;

                   case "C1":

                       System.out.println("Pants:");

                       System.out.println("Trousers");

                       break;

                   case "A2":

                       System.out.println("Footwear:");

                       System.out.println("Trainers");

                       break;

                   case "B2":

                       System.out.println("Tops:");

                       System.out.println("TShirts");

                       break;

                   case "C2":

                       System.out.println("Pants:");

                       System.out.println("Shorts");

                       break;

                   default:

                       System.out.println("Incorrect Input");

                       break;

               }

       }


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Explanation:

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Answer:

Slide Shorter View

Explanation:

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Answer:

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Linked Implementation

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(line break) tag does not require a closing tag.


true or false

Answers

True in HTML 5 line break tag doesn’t require closing tag

Convert the following C program to C++.

More instructions follow the code.

#include
#include

#define SIZE 5

int main(int argc, char *argv[]) {
int numerator = 25;
int denominator = 10;
int i = 0;

/*
You can assume the files opened correctly and the
correct number of of command-line arguments were
entered.
*/
FILE * inPut = fopen(argv[1], "r");
FILE * outPut = fopen(argv[2], "w");

float result = (float)numerator/denominator;
fprintf(outPut,"Result is %.2f\n", result);

float arr[SIZE];

for( ; i < SIZE; i++) {
fscanf(inPut, "%f", &arr[i]);
fprintf(outPut, "%7.4f\n", arr[i]);
}

return 0;
}

Notice this is uses command-line arguments. I have provided an input file called num.txt that will be used when running the program. The output file is called out.txt.

Make sure you are using C++ style file I/O (FILE pointers/fopen) as well as regular I/O including the C++ style output formatting (fscanf, fprintf, formatting). Also use the C++ method of casting. The lines above that are bold are the lines that you need to convert to C++. Don't forget to add the necessary C++ statements that precede the main() function.

Answers

Answer:

The program equivalent in C++ is:

#include <cstdio>

#include <cstdlib>

#define SIZE 5

using namespace std;

int main(int argc, char *argv[]) {

int numerator = 25;

int denominator = 10;

FILE * inPut = fopen(argv[1], "r");

FILE * outPut = fopen(argv[2], "w");

float result = (float)numerator/denominator;

fprintf(outPut,"Result is %.2f\n", result);

float arr[SIZE];

for(int i = 0; i < SIZE; i++) {

fscanf(inPut, "%f", &arr[i]);

fprintf(outPut, "%7.4f\n", arr[i]);

}

return 0;

}

Explanation:

See attachment for explanation.

Each line were numbered with equivalent line number in the C program

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5-6. Add to your design in the previous question. Add another client next to the first client. Both connect to the same switch. This second client will also communicate with the server and will also need 800 M b p s in transmission speed. Again, your design will specify the locations of switches and the transmission link between the switches.

Answers

Answer:

ok so u have take the 5 and put 6

Explanation:

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5-6. Additional client connects to the same switch, UTP connection, maintains existing fiber optic link, 800 Mbps communication with the server.

What is the explanation for this?

5-5. For connecting a single client PC to a single server, both located 900 meters apart and requiring communication at 800 Mbps, the following Ethernet network design can be implemented:

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- Use fiber optic cables for the 900-meter transmission link between the switches.

- Install switches at the client PC and server locations.

- Ensure that the switches support at least 1 Gbps Ethernet speeds to accommodate the required transmission speed.

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- Connect both clients to the same switch.

- Use UTP cables to connect the second client to the switch.

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Answer:

A: force the text to wrap

Explanation:

Just took the test and got it right!!! Hope this helps :D

Answer:

A) Force the text to wrap

Explanation:

Did it on ed2020

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public class TvShow {

   int x;

   public TvShow(String showName, int numMinutes){

   }

   public int getNumActors(String actors){

       //method code goes here but since it's just a signature we don't put anything here.

       return 0;

   }

   TvShow show22 = new TvShow("Leave it to Beaver", x);

   public double cost(int i){

       return 0;

   }

   public static void main(String[] args) {

   }

   

}

class Tester {

   public static void main(String[] args) {

       TvShow tv = new TvShow("", 0);

       tv.show22.cost(0);

   }

   

}

I hope this helps in some way!

sum_even Write a program that reads an integer 0 < n < 2^32, returns the sum of all digits in n that are divisible by 2. For example, if n = 341238 the output would be 14, because it is the sum of 4 + 2 + 8. Hint: a signed int may not be enough.

Answers

Answer:

Written in Python

n = int(input("Num: "))

sum_even = 0

if n > 0 and n < 2**32:

     strn = str(n)

     for i in range(0,len(strn)):

           if int(strn[i])%2 == 0:

                 sum_even = sum_even+ int(strn[i])

print(sum_even)

Explanation:

This line prompt user for input

n = int(input("Num: "))

This line initializes sum_even to 0

sum_even = 0

This line checks for valid input

if n > 0 and n < 2**32:

This line converts input to string

     strn = str(n)

This line iterates through each digit of the input

     for i in range(0,len(strn)):

This if condition checks for even number

           if int(strn[i])%2 == 0:

This adds the even numbers

                 sum_even = sum_even+ int(strn[i])

This prints the sum of all even number in the user input

print(sum_even)

what is scientific and​

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Answer:

And what??????????????

And what? You didn’t finish

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A.
online decision support system
B.
online transaction processing
C.
online office support processing
D.
online batch processing
E.
online executive processing

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I believe the answer is A. because he has to listen to what the people tell him and he information he has to think about and make a choice on what to reply with.

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Answer:

B

Explanation:

Answer:

b  def drawT():

Explanation:

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Technology makes it simpler to connect with employees by utilizing e-mail and memos, and it helps keep employee information and corporate paperwork a lot more organized using computers and software.

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By streamlining time-consuming procedures, technology also increases office productivity. For instance, using document management software eliminates the need for manual data entry, filing, as well as in file retrieval.

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I’m confused on the question can you rephrase that

Backing up and synchronization are the same thing.

A.)True
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Answer: A.)true

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Answer choices
Choose file>import>import library
Choose file>open>insert image
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Choose file> New> file

Answers

Answer:

Choose file>import>import library

Explanation:

because it is the process to add images to your library

Why the shape of a cell is hexagonal

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Answer:

Hexagonal cell shape is perfect over square or triangular cell shapes in cellular architecture because it cover an entire area without overlapping i.e. they can cover the entire geographical region without any gaps.

I hope this helps

Pls mark as brainliest

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Answers

Hi, your question is incomplete. Here are the options:

A. persuade the audience.

B, encourage critical thinking.

C. increase discussion.

D. relay detailed information

Answer:

D. relay detailed information

Explanation:

Indeed, slide software (like MS Powerpoint) would be an effective presentation tool, especially when the speech goal is to relay detailed information.

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Requires a lot of experience
Easy for a computer to understand
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Answers

Runs quicker because High-level programming showcases features like generic data structures and operations, run faster, and intermediate code files which are most likely to result in higher memory consumption, and larger binary program size hope that helps :)

Plz answer me will mark as brainliest ​

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Answer:

7. true

8.B

Hopefully those are correct!

Explanation:

Select a cybersecurity career that interests you. Describe the job duties and identify the skills required to excel in that career. Then, make a career plan.

Answers

Answer:

it's business

Explanation:

business you started with small and work for it grow up.

If you want Nud3s add me on sc Kermit4lyfe1

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Answer:

que pinga this is a hw website not snap

Explanation:

bro are you okay umm

The intentional defacement or destruction of a website is called: Group of answer choices spoofing. cybervandalism. cyberwarfare. phishing. pharming.

Answers

Answer:

cybervandalism

Explanation:

The intentional defacement or destruction of a website is called cybervandalism. This ultimately implies that, cybervandalism is carried out or done by someone through the use of computer technology such as an internet to destroy data (informations).

Additionally, the defacement or destruction of a website simply means changing the appearance and data relating a website. Some of the tools use for cybervandalism is a file transfer protocol (FTP), structured query language (SQL) injection etc.

In may 2005, President Donald Trump's Wikipedia web page was vandalized by an attacker.

It should be noted that intentional defacement or destruction of a website is called cybervandalism.

Cybervandalism can be regarded as the damage or destruction which is been carried out in digital form.

It may involves the cyber vandals which involves the defacing of a website.

Therefore, cybervandalism serves as intentional defacement or destruction of a website.

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Data Structure in C++
Using namespace std;
In this assignment you will implement a variation of Mergesort known as a bitonic mergesort, recursively.
In a normal mergesort, the input to the merge step is a single array, which is divided into two sections, both sorted ascending. We assume that the first half (0 up to but not including size/2) is the first section and the second half (size/2 up to but not including size) is the second section.
In a bitonic mergesort, we use the same arrangement, except that the second sequence is sorted in descending order: the first half goes up, and then the second half goes down. This means that when we are doing a merge, sometimes we want to merge the results into ascending order, while other times we want to merge into descending order (depending on which "half" of the final array the result will end up in). So we add another parameter, to describe the direction the output should be sorted into:
void merge(int* input, int size, int* output, bool output_asc);
If output_asc == true then after the merge output should contain size elements, sorted in ascending order. If output_asc == false, output should contain the elements sorted in descending order.
The other thing we glossed over in class was the allocation of the temporary space needed by the algorithm. It’s quite wasteful to allocate it in each recursive call: it would be better to allocate all the necessary space up front, and then just pass a pointer to it. In order to do this, we’ll write the recursive mergesort function in a helper function which will preallocate the space needed for the results:
int* mergesort(int* input, int size) {
int* output = new int[size];
mergesort(input, size, output, true);
return output;
}
void mergesort(int *input, int size, int* output, bool output_asc) {
// Your implementation here
}
The parameter output_asc serves the same purpose here as for merge: it tells the function that we want the output to be sorted ascending.
Interface
You must implement the functions
void merge(int* input, int size, int* output, bool output_asc);
int* mergesort(int* input, int size);
void mergesort(int *input, int size, int* output, bool output_asc);
Download a template .cpp file containing these definitions. This file is also available on the server in /usr/local/class/src.
merge must run in O(n) time with n= size. mergesort (both versions) must run in O(nlogn) time, and must use O(n) space. If you allocate any space other than the output array, you should free it before your function returns.
The test runner will test each function separately, and then in combination. It checks the result of sorting to make sure that it’s actually sorted, and then nothing is missing or added from the original (unsorted) sequence.

Answers

The code .cpp is available bellow

#include<iostream>

using namespace std;

//declaring variables

void merge(int* ip, int sz, int* opt, bool opt_asc); //merging

int* mergesort(int* ip, int sz);

void mergesort(int *ip, int sz, int* opt, bool opt_asc);

void merge(int* ip, int sz, int* opt, bool opt_asc)

{

  int s1 = 0;

  int mid_sz = sz / 2;

  int s2 = mid_sz;

  int e2 = sz;

  int s3 = 0;

  int end3 = sz;

  int i, j;

   

  if (opt_asc==true)

  {

      i = s1;

      j = e2 - 1;

      while (i < mid_sz && j >= s2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (i != mid_sz)

      {

          while (i < mid_sz)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (j >= s2)

      {

          while (j >= s2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

      }

  }

  else

  {

      i = mid_sz - 1;

      j = s2;

      while (i >= s1 && j <e2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

      if (i >= s1)

      {

          while (i >= s1)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

      }

      if (j != e2)

      {

          while (j < e2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

  }

   

  for (i = 0; i < sz; i++)

      *(ip + i) = *(opt + i);

}

int* mergesort(int* ip, int sz)

{

  int* opt = new int[sz];

   

  mergesort(ip, sz, opt, true);

  return opt;

}

void mergesort(int *ip, int sz, int* opt, bool opt_asc)

{

  if (sz > 1)

  {

      int q = sz / 2;

      mergesort(ip, sz / 2, opt, true);

      mergesort(ip + sz / 2, sz - sz / 2, opt + sz / 2, false);

      merge(ip, sz, opt, opt_asc);

  }

}

int main()

{

  int arr1[12] = { 5, 6, 9, 8,25,36, 3, 2, 5, 16, 87, 12 };

  int arr2[14] = { 2, 3, 4, 5, 1, 20,15,30, 2, 3, 4, 6, 9,12 };

  int arr3[10] = { 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 };

  int *opt;

  cout << "Arays after sorting:\n";

  cout << "Array 1 : ";

  opt = mergesort(arr1, 12);

  for (int i = 0; i < 12; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 2 : ";

  opt = mergesort(arr2, 14);

  for (int i = 0; i < 14; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 3 : ";

  opt = mergesort(arr3, 10);

  for (int i = 0; i < 10; i++)

      cout << opt[i] << " ";

  cout << endl;

  return 0;

}

Secondary sources
information gathered from primary sources.

Answers

Answer:

The answer is interpret Proof is down below

Explanation:

Here is the proooooooffffffff i made a 90 but this one was right

Secondary sources interpret information gathered from primary sources.

What are Secondary sources of information?

A secondary source is known to be made up of discussion that is often based on a primary information source.

Hence, the feature of secondary sources are known to give some kind of interpretation to all the information that has been gathered from other primary sources.

Learn more about Secondary sources from

https://brainly.com/question/896456

#SPJ2

The Environmental Master Equation includes all of the following terms except:
O Resource use per person
O Population
•Percent of resource emitted into the atmosphere
•Environmental impact per unit of resource use

Answers

Answer:  [C]:  " percent of resource emitted into the atmosphere ."

________________________

Explanation:

In the "Environmental Master Equation"—

Note that the:

    "Environmental impact" ;

            =  (population) * (resource use per unit population) *

              (environmental impact per unit of resource use) .

________________________

The question asks:  

   "The Environmental Master Equation includes all of the following terms —EXCEPT ...[with 4 (four) answer choices following.]."

________________________

Consider the given answer choices:

 [A]:  "resource user per person"—which is the same as"

          "(resource use per UNIT [emphasis added] population" ;

              — which does appear in the equation;

                   → so we can rule out "Choice:  [A]."

________________________

 [B]: "population" —this is included within the equation; so we can rule out "Choice:  [B]."

________________________

 [C]: "percentage of resource emitted into the atmosphere" ;  

    Note:  This clearly does NOT appear within the equation; so this is a likely answer choice.

________________________

Note: There is one more answer choice—so let us examine:

________________________

 [D]: "environmental impact per unit of resource use" —this is included within the equation, so we can rule out "Choice:  [D]."

________________________

   Furthermore, the particular answer choices given—A, B, and D ; constitute all elements within the "Environmental Master Equation."

________________________

As such: The correct answer is:  

             [C]:  "percent of resource emitted into the atmosphere."

________________________

Hope this is helpful to you!

  Best wishes in your academic pursuits!

________________________

Answer:

•Percent of resource emitted into the atmosphere

Explanation:

Hope this will help

guy if you now nitro type pls login and search prouy pro and you will se the legenddetroyer click my team and plssssss come to my team

Answers

Answer:

ok

Explanation:

Answer:

I will join ala you don't disband it. XD

Explanation:

I am You-Drive-Me-Crazy

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