Answer:
Nine more than two-fifths of a number is nine.
Step-by-step explanation:
we know that the total will be 9, and that 2/5x is equivalent to 2/5 of a number (so it should be 2/5n) and we are adding 9 more.
Y+1.27=7.23 solve for y
Answer:
y=5.96
Step-by-step explanation:
You can do a reverse equation and do 7.23 - 1.27 = 5.96
Can anyone solve this?
Answer:
54 cubic inches
Step-by-step explanation:
Just as the area of a triangle is half the area of a rectangle with the same dimensions, the volume of a triangular prism is half the volume of a rectangular prism with the same dimensions:
V = 1/2(LWH)
V = (1/2)(9 in)(4 in)(3 in) = 54 in³
The volume of Phil's block of cheese is 54 in³.
Constants are numbers without letters attached.
What is the constant in the equation x/2 - 3?
answers:
2
-3
Answer:
constant = - 3
Step-by-step explanation:
[tex]\frac{x}{2}[/tex] - 3 = [tex]\frac{1}{2}[/tex] x - 3
the number without letters attached is the constant - 3
Answer:
-3
Step-by-step explanation:
The answer is -3 because 2 has a letter attached to it which is x/2 -3 is without a letter.
hope dis helps):
Put the equation below into vertex form.
y=(x+9)(x+25)
PLS HELP I am giving 25 points here is the question
A shopkeeper sold 12 bags of potatoes for $2.99 each. He bought the potatoes for $1.90 for each bag what was his total profit
Find theFind tha amount of profit per bag by subtracting:
2.99 - 1.90 = 1.09
He made $1.09 profit per bag.
Now multiply the profit per bag by the number of bags:
1.09 x 12 = 13.08
Total profit = $13.08 amount of profit per bag by subtracting:
2.99 - 1.90 = 1.09
He made $1.09 profit per bag.
Now multiply the profit per bag by the number of bags:
1.09 x 12 = 13.08
Total profit = $13.08
Is (-7, -3) a solution to this system of equations?
x = -7
y = -x - 10
Yes or no
===========================================================
Explanation:
The point (-7,-3) means x = -7 and x = -3
Right off the bat, the first equation x = -7 is proven true based on the first coordinate.
Let's now plug the coordinates into the second equation.
y = -x-10
-3 = -(-7)-10
-3 = 7-10
-3 = -3
Which is a true statement.
Both equations are true when (x,y) = (-7,-3)
This is why it is a solution to the system. It turns out it's the only solution to this system. This system is consistent and independent.
You can use a graphing tool like Desmos to plot the two equations, and you should see them crossing at the point (-7,-3)
Answer:
The answer is yes
*View the attached graph to check your answer graphically.*
Step-by-step explanation:
x = -7
y = -x - 10
For this problem, I will be using substitution, since the second equation is already in the slope-intercept form.
First, I will substitute the first equation, for x, into the first equation:
x = -7
y = -x - 10
y = -(-7) - 10 <== multiplying two negatives, makes a positive
y = 7 - 10
y = - 3 <== the value of y
Now, we find the value of x by substituting - 3 for y:
y = -x - 10
- 3 = -x - 10
+10 +10
7 = -x <== you can't have a negative variable
/-1 /-1
-7 = x <== the value of x
(x, y) ==> (-7, -3)
Therefore, yes (-7,-3) is a solution to this system of equations.
*View the attached graph to check your answer graphically.*
Hope this helps!
please help, what would the answer be?
round to the nearest hundredth
(please help picture inculded)
Answer:
AB ≈ 6.53
Step-by-step explanation:
using the cosine ratio in the right triangle
cos40° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{5}{AB}[/tex] ( multiply both sides by AB )
AB × cos40° = 5 ( divide both sides by cos40° )
AB = [tex]\frac{5}{cos40}[/tex] ≈ 6.53 ( to the nearest hundredth )
If 3x - 5y = 11 and 2x + 3y = 5, then what is the ratio of x to y?
Answer:
-58/7
Step-by-step explanation:
Alright so this is a system of equations. First we'll solve the system, and then find the ratio afterwards.
[tex]3x-5y = 11\\2x+3y =5\\[/tex]
Isolate for y on both.
[tex]2x + 3y = 5\\3y = 5-2x\\y = \frac{5-2x}{3}[/tex]
and
[tex]3x - 5y = 11\\-5y = 11-3x\\y = \frac{11-3x}{-5}[/tex]
Set both equations equal to each other:
[tex]\frac{11-3x}{-5} = \frac{5-2x}{3}\\ \\\frac{3(11-3x)}{-5} = 5-2x\\ \\3(11-3x) = -5(5-2x)\\\\33 - 9x = -25 + 10x\\33 = -25 + 19x\\58 = 19x\\\frac{58}{19} = x[/tex]
We've got x, now let's solve for y:
[tex]y = \frac{11-3x}{-5} = \frac{11-3(\frac{58}{19}) }{-5}[/tex]
Now we got both x and y, and what they equal.
[tex]y = \frac{-7}{19}\\[/tex]
[tex]x = \frac{58}{19}[/tex]
The ratio of x to y, is essentially [tex]\frac{x}{y}[/tex]. So we will calculate that.
[tex]\frac{\frac{58}{19} }{\frac{-7}{19} } = \frac{58}{19} * \frac{19}{-7} = \frac{-58}{7}[/tex]
Please help me my teacher hasn't been helping me I really need your help
Answer:
550.5323531336038
Step-by-step explanation:
I have a hint: if you ever need help with triangle trigonometry questions go to carbside depot trigonometry calculator it is a literal life savor
How do you multiplying or dividing a fractions to obtain equivalent
What is the number with the mark
[tex]\huge\mathsf\blue{♧ANSWER♧}[/tex]
[tex]\huge \mathfrak \blue{\frac{ - 7}{8} }[/tex]
Which graph matches? I'll give brainliest. and 100pts
Function:
[tex]\sf 2\left(3\right)^{x}+2[/tex]
Find y-intercept:
[tex]y=2\left(3\right)^{0}+2[/tex]
[tex]y=\sf 4[/tex]
option B is correct as it cuts y-intercept at 4
Answer:
This is a positive exponential graph with a y-intercept of 4 (when x is 0, y is 4)
Hope this helps!
Sammy’s dad drove their car 150 miles in three hours. At this rate, how far would he drive in nine hours?
Answer:
distance in 3 hours = 150 miles
distance in 1 hour = 150/3 = 50 miles
distance in 9 hours = 50 × 9 = 450 miles
Answer:
Sammy's dad traveled 450 miles in 9 hours.
Step-by-step explanation:
mph = [tex]\frac{Miles}{Hours}[/tex]
Miles = 150
Hours = 3
Plug into the formula of distance/time
[tex]\frac{150}{3} = 50mph[/tex]
Sammy's dad is driving at 50mph
In three hours you can use this formula: [tex]50mph=\frac{miles}{9}[/tex]
Multiply both sides by 9: [tex]50mph * 9 =\frac{miles}{9} *9[/tex]
Solve:
[tex]50mph * 9 =miles[/tex]
[tex]450 =miles[/tex]
Sammy's dad traveled 450 miles in 9 hours.
Hope this helped! :)
Solve for x: √(32^0 + 2/3)=(0.6)^2-3x
Step-by-step explanation:
Given: √{32⁰ + (2/3)} = (0.6)²⁻³ˣ
Asked: Find the value of x = ?
Solution: Given that √{32⁰ + (2/3)} = (0.6)²⁻³ˣ
⇛√{1 + (2/3)} = (0.6)²⁻³ˣ
⇛√{(1/1) + (2/3) = (0.6)²⁻³ˣ
⇛√{(1*3 + 2*1)/3} = (0.6)²⁻³ˣ
⇛√{(3 + 2)/3} = (0.6)²⁻³ˣ
⇛√(5/3) = (0.6)²⁻³ˣ
Squaring on both sides then
⇛{√(5/3)}² = {(0.6)²⁻³ˣ}²
⇛√(5²/3²) = {0.6}(²⁻³ˣ)²
⇛√{(5*5)/(3*3)} = {0.6}(²⁻³ˣ)²
⇛5/3 = {0.6}(²⁻³ˣ)²
[[tex]\mathsf{\because}[/tex] (aᵐ)ⁿ = aᵐⁿ]
⇛5/3 = (0.6)²*²⁻³ˣ*²
⇛5/3 = (0.6)⁴⁻⁶ˣ
⇛5/3 = (6/10)⁴⁻⁶ˣ
⇛5/3 = {(6÷2)/(10÷2)})⁴⁻⁶ˣ
⇛5/3 = (3/5)⁴⁻⁶ˣ
⇛(3/5))⁻¹ = (3/5)⁴⁻⁶ˣ
[[tex]\mathsf{\because}[/tex] a⁻ⁿ = 1/aⁿ]
Base are the same, so the exponents must be equal.
[tex]\mathsf{\therefore}[/tex] -1 = 4 - 6x
Shift the number 4 from RHS to LHS, changing it's sign.
⇛-1 - 4 = -6x
⇛-5 = -6x
⇛x = {(-5)/(-6)}
[tex]\mathsf{\therefore}[/tex] x = 5/6
Answer: Hence, the value of x for the given problem is 5/6.
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-2x^2+bx -5 Determine the b-value that would ensure the function has two real root.
Answer:
No solutionStep-by-step explanation:
Given is the quadratic function
y = -2x² + bx - 5In order to have two real roots the discriminant should be posivive
D = - b² - 4acD = - b² - 4(-2)(-5) = - b² - 40We need D > 0
-b² - 40 > 0b² + 40 < 0b² < - 40There is no solution as b² is never negative
What is the slop of the line?
5(y+2)=4(x-3)
A. 3/2
B. 2/3
C. 4/5
D. 5/4
Answer:
c. 4/5
Step-by-step explanation:
HELP ME PLEASE
PRETTY PLEASEEEEEEEEEEE
Answer:
93
Step-by-step explanation:
19x-2 = 18x+3
x=5
15(5) -2=93
18(5)+3=93
Write the following series in sigma notation.
7 + 16 + 25 +34 +43 +52 + 61
The series 7 + 16 + 25 +34 +43 +52 + 61 is an illusration of arithmetic series
The sigma notation of the series is: [tex]\sum\limits^7_{n=1} {9n - 2}[/tex]
How to write the series in sigma notation?The series is given as:
7 + 16 + 25 +34 +43 +52 + 61
The above series is an arithmetic series, with the following parameters
First term, a = 7Common difference, d = 9Number of terms, n = 7Start by calculating the nth term using:
a(n) = a + (n - 1) * d
This gives
a(n) = 7 + (n - 1) * 9
Evaluate the product
a(n) = 7 - 9 + 9n
Evaluate the difference
a(n) = 9n - 2
So, the sigma notation is:
[tex]\sum\limits^7_{n=1} {9n - 2}[/tex]
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PLSS help important
(will gibe brainliest)!
I dont understand this
To form the vector notation for the translation:
--> must find how much the new graph moved horizontally from the old
graph
--> the graph moved 8 units horizontally
--> must find how much the new graph moved vertically from the old
graph
--> the graph moved 4 units vertically
In vector notation, that would be (8,4)
Hope that helps!
In ΔWXY, y = 8.6 cm, x = 8.5 cm and ∠X=100°. Find all possible values of ∠Y, to the nearest 10th of a degree.
The possible value of ∠Y to the nearest tenth of a degrees in triangle WXY is 85.1 degrees.
How to find angle of a triangle using sine rule
Let's find angle Y using sine rule,
Hence,
x / sin X = y / sin Y
where
x = 8.5 cmy = 8.6 cm∠X = 100°8.5 / sin 100° = 8.6 / sin Y
cross multiply
8.5 sin Y = 8.6 sin 100°
sin Y = 8.6 sin 100° / 8.5
sin Y = 8.4693466759 / 8.5
Y = sin ⁻¹ 0.99639372657
Y = 85.1325941735
∠Y = 85.1°
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Which of the following notes is G?
how to multiply and divide decimals with whole numbers
Lita must find the area of the sector enclosed by central angle QCR in circle C.
Points Q and R lie on circle C. The measure of angle Q C R is 74 degrees and the radius of circle C is 1 foot.
What steps should Lita take to correctly solve this problem?
A: Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360∘, so the portion of the area she wants to find is 74∘360∘. Therefore, she must multiply 74∘360∘ times the area, which is πr2.Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360 degrees textsf comma so the portion of the area she wants to find is 74∘360∘. Therefore, she must multiply 74∘360∘ times the area, which is πr2.
B: Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360∘, so the portion of the area she wants to find is 74∘360∘, so she must multiply 74∘360∘ times the area, which is 2πr.Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360 degrees textsf comma so the portion of the area she wants to find is 74∘360∘, so she must multiply 74∘360∘ times the area, which is 2πr.
C: Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360∘, so she should subtract 74∘ from 360∘. The portion of the area she wants to find is 286∘360∘, so she must multiply 286∘360∘ times the area, which is 2πr.Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360 degrees textsf comma so she should subtract 74 degrees from The portion of the area she wants to find is 286∘360∘, so she must multiply 286∘360∘ times the area, which is 2πr.
D: Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360∘, so she should subtract 74∘ from 360∘. The portion of the area she wants to find is 286∘360∘, so she must multiply 286∘360∘ times the area, which is πr2.
To find the area of the sector, Lita must multiply 74°/360° times the area of the circle, which is πr² (Option A).
What is the Area of the Sector of a Circle?Area of sector = ∅/360 × πr², where ∅ = central angle, and r = radius of the circle.
Given the following:
∅ = m∠QCR = 74°r = 1 ft.The area of the circle she wants to find is: 74°/360°.
Since the area of the whole circle is, πr², therefore, to find the area of the sector, Lita must multiply 74°/360° times the area of the circle, which is πr² (Option A).
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Given the function h of x equals negative 2 times the square root of x, which statement is true about h(x)?
The function is decreasing on the interval (0, ∞).
The function is decreasing on the interval (–∞, 0).
The function is increasing on the interval (0, ∞).
The function is increasing on the interval (–∞, 0).
Using translation concepts, it is found that the correct statement about h(x) is:
The function is decreasing on the interval (0, ∞).
What is a translation?A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.
In this problem, the parent function is:
[tex]f(x) = \sqrt{x}[/tex]
Which is increasing on (0, ∞).
After the translation, the function is:
[tex]h(x) = -2\sqrt{x}[/tex]
It was multiplied by a negative number, which means that it was reflected over the x-axis, and it will be decreasing on the interval (0, ∞).
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you buy a sandwich for $6.965, a salad for $3.25, and a drink for $1.79. if sales tax is 7%, how much change do you receive from $20 bill, rounded to the nearest cent?
6.965 + 3.25 + 1.79 = 12.005, now, let's apply a 7% taxation on that
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of 12.005}}{\left( \cfrac{7}{100} \right)12.005}\implies 0.84035~\hfill \underset{total~bill}{\stackrel{12.005~~ + ~~0.8435}{12.84535}} \\\\\\ 20~~ - ~~12.84535\implies 7.15465~~\approx ~~ \$7.15[/tex]
Hazel and 4 of her friends bought tickets for a baseball game. They received a $30 group discount. If the total cost was under $125, how much could each ticket have been?
Each ticket could have cost up to $31.
What is the discount?
A discount is a reduction in the price of an item or service. It is often offered as an incentive to encourage customers to purchase or use a particular product or service. The discount amount may be a percentage of the total price, a fixed dollar amount, or a combination of both.
Let the cost of each ticket be $x. Then the total cost for 5 tickets would be 5x. After applying the $30 group discount, the total cost would be 5x - $30.
We know that the total cost was under $125, so we can set up the inequality:
5x - $30 < $125
Simplifying this inequality, we get:
5x < $155
Dividing both sides by 5, we get:
x < $31
Hence, each ticket could have cost up to $31.
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#SPJ1
On Saturday, the temperature was
75.5°F. The temperature rose by
6°F on Sunday, then dropped by
3.5°F on Monday. Write an expression
to represent how the temperature
changed. What was the temperature
on Monday?
Answer:
78°F
Step-by-step explanation:
75.5°F on Saturday...
75.5 + 6 = 81.5 on Sunday
81.5 - 3.5 = 78°F on Monday
The expression that represents the temperature change is
N = L + 6°F + 3.5°F
The temperature on Monday is 85°F.
What is an expression?An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
Temperature:
Saturday = L= 75.5°F ______(1)
Sunday = M = Rose by 6°F
M = L + 6 _____(2)
Monday = N = Dropped by 3.5°F
N = L + 6 - 3.5 _____(3)
The expression that represents the temperature change:
From (1), (2), and (3) we get
N = L + 6°F + 3.5°F
The temperature on Monday:
N = 75.5 + 6 + 3.5
N = 85°F
Thus,
The expression that represents the temperature change is
N = L + 6°F + 3.5°F
The temperature on Monday is 85°F.
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Consider the function defined by f(x) lnx/x^4 for x > 0 and its graph y = f(x).
The graph of f has a horizontal tangent at point P. Find the coordinates of P.
Answer:
[tex]\sqrt[4]{e};\frac1{4e}[/tex]
Step-by-step explanation:
The first derivative of [tex]f(x)[/tex] will give, for each x, the slope of the tangent at that specific x. Let's calculate the derivative, applying the quotient rule.
[tex]D(\frac AB) = \frac{A'B-AB'}{B^2}\\f'(x)= \frac1{x^8}[(\frac1x)x^4-(lnx)(4x^3)]=\frac1{x^8}[x^3(1-4lnx)]=\frac{1-4lnx}{x^5}[/tex]
Now, to find the point with an horizontal tangent (called "stationary points"), we set the first derivative equal to 0. Considering that we're working with [tex]x > 0[/tex] we deal only with the numerator.
[tex]1-4lnx = 0 \rightarrow lnx= \frac14\\x=e^\frac14 =\sqrt[4]{e}[/tex]
At this point we Replace the value we found in the equation to find it's y coordinate
[tex]f(\sqrt[4]e) = \frac{ln\sqrt[4]e}{\sqrt[4]e^4}= \frac{\frac14}{e} = \frac1{4e}[/tex]
Find the distance between the two points
☟ ︎Photo down below ☟
[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}[/tex]
Let's use distance formula ~
[tex]\qquad \sf \dashrightarrow \: d = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: d = \sqrt{(2 - ( - 4)) {}^{2} + (0 - 1) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: d = \sqrt{(2 + 4) {}^{2} + ( - 1) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: d = \sqrt{ {}^{} 36+ 1{}^{} } [/tex]
[tex]\qquad \sf \dashrightarrow \: d = \sqrt{ {}^{} 37{}^{} } [/tex]
Therefore, the required distance is [tex]\sf \sqrt{37}[/tex] units