Which statement best describes the circular flow model?

Answer:

Weight

Explanation:

The force of gravity on a an object gives the object its weight.

Answer: I am so sorry i hadn't learned this Yet~!

Explanation:

Answer:

mass

Explanation:

The mass of an object is the same on the earth as it is on the moon.

Mass always remains constant, it never changes with respect to place.

Answer:

what is heat and transfer

is one of these the question

(a) The time of flight be for a tennis ball launched by the ball machine is 0.19 s.

(b) The range of the tennis ball be is 1.01 m.

(c)  The final velocity of the ball with which it reaches the ground is 7.16 m/s.

The time of flight of the tennis ball is calculated as follows;

h = vt + ¹/₂gt²

1.2 = 5.3t + 0.5(9.8)t²

1.2 = 5.3t + 4.9t²

4.9t² + 5.3t - 1.2 = 0

a = 4.9, b = 5.3, c = 1.2

solve using quadratic formula

t = 0.19 s

Thus, the time of flight be for a tennis ball launched by the ball machine is 0.19 s.

The range of the tennis ball is calculated as follows;

R = vt

R = 5.3 x 0.19

R = 1.01 m

The final velocity of the ball with which it reaches the ground is calculated as follows;

vf = vo + gt

vf = 5.3 + 9.8(0.19)

vf = 7.16 m/s

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Answer:

friction

Explanation:

Answer:

convection is the answer

The process that describes the warm ocean that transfers heat to the air above it is known as Convection. Thus, the correct option for this question is B.

Some characteristics of heat are as follows:

The process of convection transfers heat with the help of the migration of a fluid (liquid or gas) between areas of different temperatures. It is an approach that signifies the transfer of heat between two bodies by involving currents of moving gas or fluid.

Therefore, convection is the process that describes the warm ocean that transfers heat to the air above it. Thus, the correct option for this question is B.

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The final speed of the block, after being lifted 2.00 m is 3.39 m/s

Speed can be defined as the rate of change in the distance of a body.

To calculate the speed of the block after being lifted 2.00 m,  first, we need to calculate the acceleration of the block using the formula below

Formula:

Where:

Restructuring the formula above,

From the question,

Given:

Substitute these values into equation 2

Finally, to calculate the speed of the block, we use the formula below.

Where:

From the question,

Given:

Substitute these values into equation 3

Hence, The final speed of the block, after being lifted 2.00 m is 3.39 m/s.

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[tex]\text{Weight ,} W = mg = 150 \times 9.8 =1470N[/tex]

Explanation:

f=ma

where force is weight. we know that a is the acceleration of gravity which is -9.8 m/s^2

so f is

-1471.5 N

As a conservation biologist for the Chesapeake Bay, you and your

colleagues have been conducting a research study that tracks the decrease

in the bald eagle population over the past few years.

What evidence can you find for the decrease in the bald eagle population?

For residences, series circuits are impracticable. Parallel circuits are practical because each appliance is controlled by its own switch, which prevents the other appliances from being turned off. A) The appliances are all turned on. The conductor wire is carrying a considerable quantity of current (arrow).

For A block of mass m = 8.40 kg, moving on a horizontal frictionless surface with a speed of 4.20 m/s  is mathematically given as

F = 193.2N

Generally, the equation for the  magnitude of the average force mathematically given as

F = m(v1+v2)/t

F = 8.40(4.2+O.4)/t

F = 193.2N

In conclusion magnitude of the average force is

F = 193.2N

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Answer:

I don't understand your question ❓,the object.....of what experiment

Explanation:

simple machine can multiplayer of speed and force

Answer:

-------1

Explanation:

beacuse that is what i know

Answer:

Burning coal and boiling water are both chemical changes. Burning coal is a chemical change, and boiling water is a physical change. Burning coal is a physical change, and boiling water is a chemical change.

Explanation:

Answer:

-259322.03N

Explanation:

[tex]F=m*(\frac{v}{t})\\ F=4500kg*(\frac{0-102m/s}{1.77s} )\\F=-259322.033898\\\\[/tex]

[tex]\text{Given that, mass m = 70 kg and velocity v = 3 m/s}\\\\\text{Momentum,}~ p = mv = 70 \times 3 = 210~ kg ~ms^{-1}[/tex]

Answer:

Environmental means relating to or caused by the surroundings in which someone lives or something exists. It protects against environmental hazards such as wind and sun. The form the human family takes is a response to environmental pressures.

Explanation:

I HOPE IT HELPS!!

THANX!!!

STAY SAFE!!!!

Answer: b or d

Explanation: b or d

Answer:

a

Explanation:

F= ma

interestingly

when you increase the mass the acceleration decreases while when the mass decreases the acceleration increases

(man, PHYSICS IS JUST THE BESY)

A: a

object with the smallest mass has largest acceleration

The magnitude of the tangential acceleration of the hanging mass is 2mg/MR

The tangential acceleration of the hanging mass around the pulley is determined from the principle of conservation of angular momentum as shown below;

τ = Iα

Where;

[tex]\alpha = \frac{\tau}{I} \\\\\alpha = \frac{mgR}{3/2MR^2} \\\\\alpha = \frac{2mgR}{3MR^2} \\\\\alpha = \frac{2mg}{3MR}[/tex]

Where;

The tangential acceleration is calculated as follows;

[tex]a = \alpha R\\\\a = \frac{2mg}{3MR} \times R\\\\a = \frac{2mg}{3M}[/tex]

Thus, the magnitude of the tangential acceleration of the hanging mass is 2mg/MR

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Answer:

Gravitational force is the force that attracts objects towards each other. Two factors that affect the gravitational force between objects are the mass of the two objects and the distance between

Explanation:

Gravity is what pulls us towards the Earth if we were to jump into the air, so it is the force that pulls things towards other things. The bigger the objects are the more gravity they have, so a planet has more gravity than say, an apple. Distance between objects also makes their gravity change, so the Earth's pull on the moon is different than the Earth's pull on the sun.

Hopefully this helps- let me know if you have any questions!

Describe gravitational force in your own words. Which two factors affect the gravitational force between two objects?

[tex]F = \frac{G m{ \tiny1}m{ \tiny2} }{ {r}^{2} } [/tex]

where

Hi there!

We can begin by using Lenz's Law:
[tex]\epsilon = -N\frac{d\Phi _B}{dt}[/tex]

N = Number of Loops

Ф = Magnetic Flux (Wb)
t = time (s)

Also, we can rewrite this as:
[tex]\epsilon = -NA\frac{dB}{dt}[/tex]

A = Area (m²)

Since the area is constant, we can take it out of the derivative.

This is a single wire loop, so N = 1.

Now, we can develop an expression for the induced emf.

We can begin by solving for the area:

[tex]A = \pi r^2 \\\\d = r/2 r = 0.05cm \\\\A = \pi (0.05^2) = 0.007854 m^2[/tex]

We can also express dB/dt as:
[tex]\frac{dB}{dt} = \frac{\Delta B}{t} = \frac{0-0.5}{t} = \frac{-0.5}{t}[/tex]

Now, we can create an equation.

[tex]\epsilon = -(1)(0.007854)\frac{-0.5}{t} = \frac{0.003927}{t}[/tex]

To solve the system, we must now develop an expression for current given an emf and resistance.

Begin by calculating the resistance of the copper wire:
[tex]R = \frac{\rho L}{A}[/tex]

ρ = Resistivity of copper (1.72 * 10⁻⁸ Ωm)
L = Length of wire (0.01 m)

A = cross section area (m²)

Solve:
[tex]R = \frac{(1.72*10^{-8})(0.01)}{\pi (0.001^2)} = 5.475 * 10^{-5} \Omega m[/tex]

Now, we can use the following relation (Ohm's Law):

[tex]\epsilon = iR\\\\\epsilon = \frac{Q}{t}R[/tex]

*Since current is equivalent to Q/t.

Plug in the value of R and set the two equations equal to each other.

[tex]\frac{Q}{t}(5.475 * 10^{-5}) = \frac{0.003927}{t}[/tex]

Cancel out 't'.

[tex]Q (5.475 * 10^{-5}) = 0.003927 \\\\Q = \frac{0.003927}{5.475*10^{-5}} = \boxed{71.73 C}[/tex]

Answer:

(A) 0.8 kgm/s

Explanation:

because of the even ground it would only slow down

(i) The total capacitance for the circuit is 5 μF.

(ii) The total charge stored in the circuit is 1 x 10⁻⁴ C.

(iii) The charge stored in 3μF capacitor is  6 x 10⁻⁶ C.

The total capacitance of the circuit is determined by reolving the series capacitors separate and parallel capacitors separate as well.

[tex]\frac{1}{C_{12}} = \frac{1}{C_1 } + \frac{1}{C_2} \\\\\frac{1}{C_{12}} = \frac{1}{4 } + \frac{1}{4} \\\\\frac{1}{C_{12}} = \frac{1}{2} \\\\C_{12} = 2 \ \mu F[/tex]

[tex]C_{123} = C_{12} + C_3\\\\C_{123} = 2\ \mu F + 2\ \mu F \\\\C_{123} = 4 \ \mu F[/tex]

[tex]\frac{1}{C_{t} } = \frac{1}{C_{123}} + \frac{1}{C_5} + \frac{1}{C_6} \\\\\frac{1}{C_{t} } = \frac{1}{4} + \frac{1}{6} + \frac{1}{6} \\\\\frac{1}{C_{t} } = \frac{12}{24} \\\\\frac{1}{C_{t} } = \frac{1}{2} \\\\C_t = 2 \ \mu F[/tex]

[tex]\frac{1}{C_{78}} = \frac{1}{6} + \frac{1}{6} \\\\\frac{1}{C_{78}} = \frac{2}{6} \\\\\frac{1}{C_{78}} =\frac{1}{3} \\\\C_{78} = 3 \ \mu F[/tex]

Ct + C(78) = 2 μF + 3 μF = 5 μF

The total charge stored in the capacitor is calculated as follows;

Q = CV

Q = (5 x 10⁻⁶) x (20)

Q = 1 x 10⁻⁴ C

Q =  (3 x 10⁻⁶) x (20)

Q = 6 x 10⁻⁶ C

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(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.

(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.

The magnitude of the electric field at a point on the cylindrical Gaussian surface is calculated as follows;

E = λ/2πε₀r

where;

[tex]E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 5.5} \\\\E = 2.35 \times 10^4 \ N/C[/tex]

[tex]E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 2.5} \\\\E = 5.18 \times 10^4 \ N/C[/tex]

Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.

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Answer:

Explanation:

You can use the cross product. Let the vector that perpendicular to a and c is [tex]\vec{d}[/tex], so:

[tex]\vec{d}=\vec{a}\times\vec{c}=\left|\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\5&4&-6\\4&3&2\end{array}\right] \right|=(8+18)\hat{i}-\hat{j}(10+24)+\hat{k}(15-16)=26\hat{i}-34\hat{j}-\hat{k}[/tex]

To check that c is perpendicular with a and b, do the dot product between c and a and also c and b and if the result is zero, you're true.

[tex]\vec{d}.\vec{a}=(26*5)-(34*4)+(6)=0[/tex]  (c perpendicular to a)

[tex]\vec{d}.\vec{c}=(4*26)-(34*3)-(2*1)=0[/tex] (d perpendicular to c)

There is no temperature change which drives heat flow, thus no heat will be released by the water.

The heat released by the water when it freezes is calculated as follows;

Q = mcΔФ

where;

Initial temperature of water, Фi = 0 °C

when water freezes, the final temperature, Фf = 0 °C

Q = 22 x 4200 x (0 - 0)

Q = 0

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

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