**Answer: **Dynamic balance

**Explanation: **Dynamic balance movements are movements in which constant agonist-antagonist muscle contractions occur in order to maintain a certain position or posture. ISSA pg 121

a sports car has a mass of 1300kg.Starting from the rest the car generates a force of 4400 N.The frictional force opposing this motion is 280 N.What is the car’s acceleration

since the car moves, the force needed to move is greater than the frictional forces opposing it

a = 3.17m/s²

The **acceleration of the car **with a **mass** of **1300 kg** which starts from rest generating a force of **4400 N **and having a **frictional force** of **280 N **is **3.17 m/s²**

Force (F) = 4400 N

Frictional force (Fբ) = 280 N

Net force (Fₙ) =?Fₙ = F – Fբ

Fₙ = 4400 – 280

Fₙ = 4120 NThus, the **net force** acting **on** the **car** is **4120 N**

Mass (m) = 1300 Kg

Net force (F) = 4120 N

Acceleration (a) =?Force = Mass × Acceleration

4120 = 1300 × a

Divide both side by 1300

[tex]a = \frac{4120}{1300}\\\\[/tex]

a = 3.17 m/s²Therefore, the **acceleration** of the **car** is **3.17 m/s². **

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If 155 g of sugar can be dissolve in 100g of water at 20 degree than how much sugar will be dissolved in 300 g of water at same temperature if someone do I will make you brainly

**Answer:**

465 grams of sugar.

**Explanation:**

I'm not sure this is true: is the relationship linear?

If it is then 300 grams of water should be able told 3*155 grams of sugar

3 * 155 = 465 grams of sugar in 300 grams of water.

What is sin for the given right triangle?

8.6 meters

5 meters

6.99 meters

A. l0.71

B. 0.81

C. 0.58

D. 1.72

**Answer:**

C

**Explanation:**

sin of a right triangle is opposite divided by hypotenuse

in this case, that is 5/8.6 = 0.581395349

you can easily remember the trig functions with this acronym:

SOH-CAH-TOA

S: Sine

O: Opposite

H: Hypotenuse

C: Cosine

A: Adjacent

H: Hypotenuse

T: Tangent

O: Opposite

A: Adjacent

**Explanation:**

sin = Mp /0P

sin = 5/8,6

sin = 0,58

Select the correct answer.

A pair of pliers is an example of a simple machine with two levers. Which part of the pliers is the fulcrum?

A. A

B. B

C. C

D. D

E. E

**Answer:**

There isnt enough in your question to answer the question bro, like we need a picture or something bro.

**Explanation:**

You don't have a image attached

During a normal reaction to a stressful event, muscles are moved to their maximum capacity, and sensitivity is

**Answer:**

The paper focuses on the biology of stress and resilience and their biomarkers in humans from the system science perspective. A stressor pushes the physiological system away from its baseline state toward a lower utility state. The physiological system may return toward the original state in one attractor basin but may be shifted to a state in another, lower utility attractor basin. While some physiological changes induced by stressors may benefit health, there is often a chronic wear and tear cost due to implementing changes to enable the return of the system to its baseline state and maintain itself in the high utility baseline attractor basin following repeated perturbations. This cost, also called allostatic load, is the utility reduction associated with both a change in state and with alterations in the attractor basin that affect system responses following future perturbations. This added cost can increase the time course of the return to baseline or the likelihood of moving into a different attractor basin following a perturbation. Opposite to this is the system's resilience which influences its ability to return to the high utility attractor basin following a perturbation by increasing the likelihood and/or speed of returning to the baseline state following a stressor. This review paper is a qualitative systematic review; it covers areas most relevant for moving the stress and resilience field forward from a more quantitative and neuroscientific perspective.

**Explanation:**

During a normal **reaction** to a **stressful** event, **muscles** are moved to their maximum capacity, and **sensitivity** is **increased**.

This is defined as the **ability** of an organism to **respond** to **stimuli** such as touch, sensation etc.

During **exercise**, **sensitivity** to substances such as **insulin** when **glucose** transport wears off helps to **balance** **energy** supply.

Read more about **Sensitivity** here https://brainly.com/question/8043930

What evidence do we have that the moon is receding from Earth?

For the last few billion years the Moon's gravity has been raising tides in Earth's oceanswhich the fast spinning Earth attempts to drag ahead of the sluggishly orbiting Moon. The result is that the Moon is being pushed away from Earth by 1.6 inches (4 centimeters) per year and our planet's rotation is slowing.

What is the chemical formula for magnesium sulfide?

**Answer:**

MgS

**Explanation:**

14. Which of the following is not an example of work being done?

A. pushing a basketball away from your body

B. holding a coffee mug

C. carrying boxes across a warehouse floor

**Answer:**

**B. holding a coffee mug **

**Explanation:**

**Something must move a distance for work to be done. **

A cyclist exerts a 15.0 N force while riding 251 m in 30.0 s. What power does the cyclist develop?

**Answer:**

P=126W

**Explanation:**

Sorry if im wrong!

**Answer:**

125.5 watts

**Explanation:**

P=work/time

work=F*d

P=(F*d)/t

P=(15*251)/30

P=125.5 watts

Time Dilation. A group of scientists discover a new, rare isotope and are able to store a small amount of it. They determine that the isotope is unstable and half of their sample will decay in 13.0 monthsmonths . The scientists need a new laboratory to properly conduct measurements on the isotope. If laboratory is built before half the sample decays there will still be enough of the isotope available for experiments. However, it will take 21.0 monthsmonths to build the new lab. Fortunately, the scientists can quickly start construction and they have access to a spaceship that can travel at speeds approaching the speed of light c = 3.00

This question is incomplete, the complete question is;

Time Dilation. A group of scientists discover a new, rare isotope and are able to store a small amount of it. They determine that the isotope is unstable and half of their sample will decay in 13.0 months . The scientists need a new laboratory to properly conduct measurements on the isotope. If laboratory is built before half the sample decays there will still be enough of the isotope available for experiments. However, it will take 21.0 months to build the new lab. Fortunately, the scientists can quickly start construction and they have access to a spaceship that can travel at speeds approaching the speed of light c = 3.00 x 10⁸ m/s.

If they place their sample of the isotope on the spaceship, at what speed must it travel in order for the new laboratory to be completed on Earth by the time half of the isotope on the spaceship decays? Assume that it took one month for the scientists to actually start construction and launch the spaceship so half the sample will remain in 12.0 months but it will still take 21.0 months to build the new lab.

**Answer:**

the required speed is **2.4618 x 10⁸ m/s**

**Explanation: **

Given the data in the question;

Time taken to complete a lab = 21 months

it took them one one to actually start so

Time remaining so that sample only decays by 1/2 = (13 - 1) = 12 months

we need to find at what speed the spaceship should travel so that time on earth ( = 12 months) become time on spaceship ( = 21 months)

we make use of time dilation equation;

t' = t/√( 1 - v²/c² )

where t is time in rest frame = 12 and t' is time in moving frame = 21

so we substitute

21 = 12/√( 1 - v²/c² )

21√( 1 - v²/c² ) = 12

√( 1 - v²/c² ) = 12/21

we square both side

( 1 - v²/c² ) = ( 12/21 )²

( 1 - v²/c² ) = 0.3265

v²/c² = 1 - 0.3265

v²/c² = 0.6735

v² = 0.6735 × c²

v = √0.6735 × √c²

v = 0.8206 × c

given that speed of light c = 3 x 10⁸ m/s

v = 0.8206 × 3 x 10⁸ m/s

v = **2.4618 x 10⁸ m/s**

Therefore, the required speed is **2.4618 x 10⁸ m/s**

Yanni just turned one. He loves to play with his cars and trucks. He can also name the animals he sees in books.

In which stage of development is Yanni?

childhood

infancy

adolescence

adulthood

infancy

i think hope this helps

i think hope this helps

You are riding in the passenger seat of a car as it goes around a tight turn. You slide across the seat to the passenger side door. Which statement below properly describes what is happening? a. You are exerting a centripetal force on the door. b. The door and seat are exerting a centripetal force on you that balances the centrifugal force of the turn. c. The car seat exerts a centripetal force on you, but not enough to keep you in place, so the door exerts the rest. d. The centrifugal force is greater than the force of friction between you and the seat, so you slide outward.

**Answer:**

**Explanation:**

answer C looks good

there isn't really a "centrifugal " force. :/ when we are pushed "back" in a car seat.. it's not because there is a force pushing us backwards... but a force pushing us forwards.. just like when turning too, a force pushes us into the corner, not a force pushing out of the corner. :)

Two small, identical conducting spheres repel each other with a force of 0.020 N when they are 0.35 m apart. After a conducting wire is connected between the spheres and then removed, they repel each other with a force of 0.055 N. What is the original charge on each sphere

**Answer:**

why does anyone need to know

**Explanation:**

1 plus one = 69

A woman stands still holding a 350 Newton bag (about 80 pounds) 2 meters off the ground. How much work does the woman do?

Answer:

700 Joules

Explanation:

What we know:

Force = 350 Newton

Distance = 2 meters

Work = ?

The formula for work is:

Work = force x distance

Plugging values into equation:

Work = 350 Newtons x 2 meters

Work = 700 Joules

I had the same question on the homework assignment with the answers provided:

a) It depends on how long she holds the bag

b) 350 Joules

c) none

d) 350 Newtons

The final answer would be c) none. The work done is 700 Joules. Hope this helps!

amount of force times the distance it moves object

work=force×distance this is the formula

****PLEASE HELP**** WILL MARK BRAINLIEST

Assuming that voltage remains constant, what happens to the current in a

wire if the length of the wire increases?

O A. The current decreases.

OB. The current alternates between high and low values.

O C. The current increases.

O D. The current is not affected by a change in wire length.

**Answer:**

The Current decreases

**Explanation:**

HOPE THIS HELPS!

A spring has a spring constant of 65.5 N/m and it is

stretched with a force of 15.3 N. How far will it stretch?

0.234m !!!!!! hope this helps :)))

a wave of frequency 10hz forms a stationary wave pattern in a medium where the velocity is 30cm/s. the distance between adjacent nodes is?

Answer:

The ans is 1 not 2

Explanation:

The distance between two adjacent node in a stationary wave is half wavelength π/2 and not full wavelength as in π,so when solving we got 2cm as the wavelength since they ask the dist. Also adjacent nodes you will divide it by 2 and the ans will give u 1cm.

Hope this helps.

In 1976, a 53 kg helicopter was built in Denmark. Suppose this helicopter flew east with a speed of 60.0 m/s and the total momentum of the helicopter and pilot was 7,200 kg∙m/s to the east. What was the mass of the pilot?

**Answer:**

**67 kg.**

**Explanation:**

From the question,

Total momentum = (mass of the pilot+ mass of the helicopter)×velocity.

I = (m+M)v............................... Equation 1

Where I = Total momentum of the pilot and the helicopter, m = mass of the pilot, M = mass of the helicopter, v = velocity.

make m the subject of the equation

m = (I/v)-M.............................. Equation 2

Given: I = 7200 kg.m/s, v = 60 m/s, M = 53 kg.

Substitute these values into equation 2

m = (7200/60)-53

m = 120-53

m = 67 kg.

Hence the mass of the pilot is 67 kg

Astronomers observe the motion of four planets that orbit a star similar to the Sun. Each planet follows an elliptical orbit around its star. The astronomers measure each planet's orbital period, as shown in the table.

Planet; Orbital Period (Earth days)

Planet W; 10

Planet X; 640

Planet Y; 80

Planet Z; 270

To determine the distance each planet is from the star, astronomers applied one of Kepler's three laws.

Kepler's first law: The path of each planet around a star is an ellipse, with the star at one focus. Kepler's second law: A planet sweeps out equal areas in equal amounts of time as it revolves around the star.

Kepler's third law: The square of the time for one revolution of a planet is proportional to the cube of the radius of its orbit.

Based on the table, identify the planet that is the farthest distance from the star, and indicate which of Kepler's three laws can be used to justify your answer. Enter your answer in the box provided.

**Answer:**

planet that is farthest away is planet X

kepler's third law

**Explanation:**

For this exercise we can use Kepler's third law which is an application of Newton's second law to the case of the orbits of the planets

T² = ([tex]\frac{4\pi ^2}{ G M_s}[/tex] a³ = K_s a³

Let's apply this equation to our case

a = [tex]\sqrt[3]{ \frac{T^2}{K_s} }[/tex]

for this particular exercise it is not necessary to reduce the period to seconds

Plant W

10² = K_s [tex]a_{w}^3[/tex]

a_w = [tex]\sqrt[3]{ \frac{100}{ K_s} }[/tex]

a_w = [tex]\frac{1}{ \sqrt[3]{K_s} }[/tex] 4.64

Planet X

a_x = [tex]\sqrt[3]{ \frac{640^3}{K_s} }[/tex]

a_x = \frac{1}{ \sqrt[3]{K_s} } 74.3

Planet Y

a_y = [tex]\sqrt[3]{ \frac{80^2}{K_s} }[/tex]

a_y = \frac{1}{ \sqrt[3]{K_s} } 18.6

Planet z

a_z = [tex]\sqrt[3]{ \frac{270^2}{K_s} }[/tex]

a_z = \frac{1}{ \sqrt[3]{K_s} } 41.8

From the previous results we see that planet that is farthest away is planet X

where we have used kepler's third law

Lichen grows on the surface of hornblende granite and causes it to breakdown at a faster rate. This is an example of. _______ Weathering

Answer:

Chemical.

Explanation:

Weathering can be defined as the physical and chemical breakdown of rock into smaller pieces called sediment. Weathering can be classified into two categories namely;

I. Physical weathering : it is the process of breaking rocks into pieces without affecting its chemical composition e.g temperature, abrasion and frost action.

II. Chemical weathering : it is the process of breaking rocks into pieces by chemical action which leads to changes in its chemical composition e.g carbonation, hydration, plant acid and oxidation.

In this scenario, Lichen grows on the surface of hornblende granite and causes it to breakdown at a faster rate. Thus, this is an example of chemical weathering

Is the speed of light constant throughout the universe.?

**Answer:**

It is a basic postulate of the theory of relativity that the speed of light is constant. This can be broken down into two parts: The speed of light is independent of the motion of the observer. The speed of light does not vary with time or place.

**Explanation:**

Find the momentum of a 15 kg object traveling at 7 m/s

What is the momentum?

What equation did you use to solve?

**Answer:**

105 kg*m/s

**Explanation:**

p=mv

momentum=mass*velocity

momentum=15kg*7m/s

momentum=105kg*m/s

In what order were the following energy sources

discovered by humans

There’s no order to go off of...

pls help its already late lol

**Answer:**

Temperature

**Explanation:**

**Answer:**

Gravity

**Explanation:**

Gravity has nothing to do with weather. Temperature means hot or cold, water is rain and thunder, and wind is if it's in the winter or something like that

If you increase the frequency of a sound wave four times, what will happen to its speed?

А

The speed will increase four times.

B.

The speed will decrease four times,

C. The speed will remain the same.

D.

The speed will increase twice.

E.

The speed will decrease twice.

The answer is C wave frequency does not affect wave speed

A 40-pF capacitor is charged to a potential difference of 500 V. Its terminals are then connected to those of an uncharged 10-pF capacitor. Calculate: (a) the original charge on the 40-pF capacitor; (b) the charge on each capacitor after the connection is made; and (c) the potential difference across the plates of each capacitor after the connection.

(a)** **The **original charge** on the **40-pF capacitor** is [tex]2 .0 \ \times \ 10^{-8} \ C[/tex].

(b) The **charge **on **each capacitor** after the connection is made is [tex]4 .0 \ \times \ 10^{-9} \ C[/tex].

(c) The **potential difference **across the plates of each capacitor after the connection is** 100 V** and **400 V.**

The **original charge** on the **40-pF capacitor** is calculated as follows;

[tex]Q = CV\\\\Q = 40 \times 10^{-12} \times 500\\\\Q = 2 .0 \ \times \ 10^{-8} \ C[/tex]

Charge on each capacitor[tex]C = \frac{C_1C_2}{C_1 + C_2} \\\\C = \frac{10 \times 10^{-12} \times 40 \times 10^{-12}}{10\times 10^{-12} \ + \ 40 \times 10^{-12}} \\\\C = 8 \times 10^{-12} \ F[/tex]

[tex]Q = Q_1 = Q_2\\\\Q = 8 \times 10^{-12} \ \times \ 500\\\\Q = 4 \times 10^{-9} \ C[/tex]

Potential differenceThe **potential difference** across the plates of each capacitor after the connection is calculated as follows;

[tex]V = \frac{Q}{C} \\\\V_1 = \frac{Q}{C_1} \\\\V_1 = \frac{4 \times 10^{-9}}{40 \times 10^{-12}} \\\\V_1 = 100 \ V\\\\V_2 = \frac{Q}{C_2} \\\\V_2 = \frac{4 \times 10^{-9}}{10 \times 10^{-12} } \\\\V_2 = 400 \ V[/tex]

Learn more about **charge of a capacitor** here: https://brainly.com/question/13578522

A basketball player jumps straight up for a ball. To do this, he lowers his body 0.250 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.960 m above the floor. (a) Calculate his velocity (in m/s) when he leaves the floor. 4.33 Correct: Your answer is correct. m/s (b) Calculate his acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.250 m.

**Answer:**

a. 3.73 m/s b. 27.8 m/s²

**Explanation:**

**(a) Calculate his velocity (in m/s) when he leaves the floor.**

Using the conservation of energy principles,

Potential energy gained by basketball player = kinetic energy loss of basket ball player

So, ΔU + ΔK = 0

ΔU = -ΔK

mg(h' - h) = -1/2m(v'² - v²)

g(h' - h) = -1/2(v'² - v²) where g = acceleration due to gravity = 9.8 m/s², h' = 0.960 m, h = 0.250 m, v' =0 m/s (since the basketball player momentarily stops at h' = 0.960 m) and v = velocity with which the basketball player leaves the floor

Substituting the values of the variables into the equation, we have

9.8 m/s²(0.960 m - 0.250 m) = -1/2((0 m/s)² - v²)

9.8 m/s²(0.710 m) = -1/2(-v²)

6.958 m²/s² = v²/2

v² = 2 × 6.958 m²/s²

v² = 13.916 m²/s²

v = √(13.916 m²/s²)

v = 3.73 m/s

**(b) Calculate his acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.250 m.**

Using v² = u² + 2as where u = initial speed of basketball player before lengthening = 0 m/s, v = final speed of basketball player after lengthening = 3.73 m/s, a = acceleration during lengthening and s = distance moved during lengthening = 0.250 m

So, making, a subject of the formula, we have

a = (v² - u²)/2s

Substituting the values of the variables into the equation, we have

a = ((3.73 m/s)² - (0 m/s)²)/(2 × 0.250 m)

a = (13.913 m²/s² - 0 m²/s²)/(0.50 m)

a = 13.913 m²/s²/(0.50 m)

a = 27.83 m/s²

a ≅ 27.8 m/s²

what is the potential energy the greatest in a roller coaster

**Answer:**

Gravitational potential energy is the greatest

**Explanation**

It is the highest point of a roller coaster.

In which scenario is the greatest amount of work done on a wagon?

A force of 55 N moves it 8 m.

A force of 60 N moves it 6 m.

A force of 50 N moves it 5 m.

A force of 40 N moves it 10 m.

**Answer:**

The first scenario!

**Explanation:**

W=F*d

**a) 55*8= 440J**

b) 60*6= 360J

c) 50*5= 250J

d) 40*10= 400J

The **scenario **with the **greatest amount **of **work done **on a **wagon **is "A force of 55 N moves it 8 m" and the **Work done **is ** 440N.m.**

**Work done **is simply defined as the **energy** **transfer **that takes place when an **object **is either **pushed **or **pulled **over a certain **distance **by an **external force**. It is expressed as;

**W = F × d**

Where F is force applied and d is distance travelled.

From the question;

A force of 55 N moves it 8 m

**W = 55N×8m = 440N.m**

A force of 60 N moves it 6 m.

W = 60N×6m = 360N.m

A force of 50 N moves it 5 m.

W = 50N×5m = 250N

A force of 40 N moves it 10 m.

W = 40N×10m = 400N.m

Therefore, the **scenario **with the **greatest amount **of **work done **on a **wagon **is "A force of 55 N moves it 8 m" and the **Work done **is ** 440N.m.**

Learn more about **work done**: brainly.com/question/26115962

**#SPJ2**

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