Which of the following is most likely to cause you to start a filtration over again?
A.
failure to use a stirring rod

B.
overflowing the top edge of the filter paper

C.
placing the tip of the funnel in the center of the beaker

D.
using too large a piece of filter paper

Calculating the molarity of acetic acid in vinegar:

Molarity (M) = (number of moles of solute) / (volume of solution in liters)

The molar mass is the same as mass number if it is only one element with no subscripts.

the mass of acetic acid in the vinegar will be determined first:

Mass = volume (L) × density (g/mL)

Mass = 1 L × 1.05 g/mL

Mass = 1.05 g/L

Then, the moles of acetic acid can be calculated using the molar mass of acetic acid:

Moles = mass (g) / molar mass

Moles = 1.05 g / 60.05 g/mol

Moles = 0.01748 mol

Acetic acid molarity = 0.01748 mol / 1 L

                                = 0.01748 M

Calculating the percentage of acetic acid in vinegar:

% acetic acid = (mass of acetic acid/volume of vinegar) × 100%

                     = (1.05 g / 100 mL) × 100%

                     = 1.05%

Therefore, the result of the calculation will be close to 1.05%, not 5%.

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7.5 gallons of a 5% acid solution must be mixed with 5 gallons of a 10% solution to obtain a 7% solution.

The formula for calculating this is:

Total volume of solution = (volume of 10% solution x 10%) + (volume of 5% solution x 5%) / desired concentration

So: 7 gallons = (5 gallons x 10%) + (x gallons x 5%) / 7

Simplifying the above equation,

0.05x + 0.5 = 0.07x + 0.35

Subtracting 0.05x and 0.35 from both sides,

we get

0.5 - 0.35 = 0.07x - 0.05x0.15 = 0.02x

Dividing both sides by 0.02,we get

7.5 = x

Therefore, we need to mix 7.5 gallons of a 5% acid solution with 5 gallons of a 10% solution to obtain a 7% solution.

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During a normal water diuresis, the urine flow rate and specific gravity are inversely proportional. Urine specific gravity is a measure of the concentration of solutes in the urine and is normally between 1.003 and 1.035, with a lower value indicating a more dilute urine. As the urine becomes more dilute, the flow rate increases, and vice versa.

During a normal water diuresis, the relationship between urine flow rate and specific gravity is inversely proportional. Normal water diuresis is the formation of urine due to the normal filtration, reabsorption, and excretion functions of the kidneys, without any physical or hormonal changes, dehydration, or pathological conditions. During normal water diuresis, a person consumes a normal amount of fluids and has a normal urinary output. The specific gravity of urine is also normal, i.e. between 1.003 and 1.035.

Specific gravity is the measure of the density of a substance compared to the density of water. The specific gravity of urine is an indicator of the amount of dissolved substances in it, such as salts, minerals, glucose, and proteins. An increase in specific gravity indicates increased dissolved substances in urine and dehydration, while a decrease in specific gravity indicates decreased dissolved substances and increased hydration.

The urine flow rate and specific gravity have an inverse relationship during normal water diuresis. This means that when the urine flow rate increases, the specific gravity decreases, and vice versa. The reason behind this relationship is that when the urine flow rate is high, the kidneys have less time to reabsorb the dissolved substances from the filtrate, and hence, more water and less dissolved substances are excreted in the urine. This leads to a decrease in the specific gravity of urine.

Conversely, when the urine flow rate is low, the kidneys have more time to reabsorb the dissolved substances from the filtrate, and hence, less water and more dissolved substances are excreted in the urine. This leads to an increase in the specific gravity of urine.

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1) Kb for NH2OH (hydroxylamine) is 1.08 x 10^-8 mol/L and 2) Kb for C17H19O3N is 7.8 x 10^-10 mol/L

In the laboratory, a general chemistry student measured the pH of a 0.587 M aqueous solution of hydroxylamine, NH2OH to be 9.848. Kb for the base hydroxylamine, NH2OH is given by; Kb=Kw/Ka=1.00×10−14/Ka, Let x be the concentration of OH- ion produced by hydrolysis of the NH2OH base. The Kb expression for NH2OH is: NH2OH(aq) + H2O(l) ⇆ NH3OH+(aq) + OH−(aq)Initial concentration 0.587 0 0. Equilibrium concentration (0.587 - x) x xKb = [NH3OH+] [OH−] / [NH2OH]Kb = x × x / (0.587 - x)Kw/Ka = (x^2) / (0.587 - x) 9.848 = - log[x] => [x] = 1.39×10^-10(1.00×10−14)/Kb = x^2 / (0.587 - x) (with Kb in mol/L). Therefore; Kb for NH2OH is 1.08 x 10^-8 mol/L

In the laboratory, a general chemistry student measured the pH of a 0.587 M aqueous solution of morphine, C17H19O3N to be 10.804. Kb for the base morphine, C17H19O3N is given by;Kb=Kw/Ka=1.00×10−14/KaLet x be the concentration of OH- ion produced by hydrolysis of the C17H19O3N base. Kw/Ka = (x^2) / (0.587 - x)10.804 = - log[x] => [x] = 7.09×10^-11(1.00×10−14)/Kb = x^2 / (0.587 - x) (with Kb in mol/L)Therefore; Kb for C17H19O3N is 7.8 x 10^-10 mol/L

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a.) The stressor that causes high concentrations of abscisic acid to travel from the roots to the shoot is drought.

An essential element of a plant's reaction to abiotic stress, particularly drought, is played by the hormone abscisic acid (ABA). Drought causes plants to create large amounts of ABA, which is then transferred from the roots to the shoot. Many physiological reactions result from this, including the closing of stomata, which lowers water loss through transpiration, and the activation of genes that encourage the manufacture of proteins that shield cells from dehydration-related cell damage. In addition, ABA causes inhibition of root development, which enables roots to sever deeper layers of soil in quest of water. In general, ABA production and transport play a key role in how plants manage drought stress and keep their water balance.

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Answer:

Explanation:

Solubility is the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.

T=Q/MC

  =10/100

   =0.1

Answer:

proofs attached to answer

Explanation:

proofs attached to answer

0.0637 moles of NaOH were used in the reaction.

Moles (mol) are a unit of measurement used to quantify the amount of a substance. One mole represents the amount of a substance that contains as many entities (atoms, molecules, ions, etc.) as there are atoms in exactly 12 grams of carbon-12.

Moles provide a way to relate the mass of a substance to the number of its constituent particles. The concept of moles is essential for performing calculations involving stoichiometry, determining the ratio of reactants and products in chemical reactions, and understanding the relationship between mass, volume, and the number of particles in a substance.

moles = volume (in liters) x molarity

6.37 ml ÷ 1000 = 0.00637 L

moles = 0.00637 L x 10.0 M

= 0.0637 moles

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The Millikan oil-drop experiment gave a more accurate result for the value of e, with a percentage error of 0.002%. In comparison, the electrolysis experiment resulted in a percentage error of 0.06%.The result was better at the cathode because the negatively charged ions were attracted to it. Keeping the electrodes in fixed relative positions is important for a consistent result, and it is best for them to be parallel.

1. Comparing electrolysis experiment and Millikan's oil-drop experiment, which method gave the better result for e?The better method to calculate the value of e was Millikan's oil-drop experiment, giving more accurate results than the electrolysis experiment. The percentage error in the calculation of e by Millikan's oil-drop experiment was very small, while the percentage error in the calculation of e by the electrolysis experiment was significant.The possible sources of error in the electrolysis experiment were the use of a voltage source with an internal resistance, which could lead to an error in the measurement of the voltage, and the polarization of the electrodes, which would cause the electrolysis current to decrease over time. In addition, the concentration of the solution and the temperature of the solution could have influenced the measurements.  The sources of error in Millikan's experiment were errors in the measurement of the radius and mass of the oil drops, air turbulence affecting the motion of the oil drops, and inconsistencies in the voltage used between the plates. 2. Which electrode gave better results in the electrolysis experiment?The cathode provided a better result than the anode. Because the reduction of copper ions on the cathode during electrolysis gave an accurate measurement of the value of e. 3. Why should the electrodes be kept in fixed relative positions during the electrolysis?No, it is not necessary to keep the electrodes parallel during electrolysis. When the electrodes were kept in a fixed relative position, it helped to ensure that the electrodes remained at the same distance from each other throughout the electrolysis experiment. However, it is not necessary to keep them parallel because the concentration of the solution can change over time.The second electrolysis was more accurate than the first one. It is because we obtained the desired result, i.e., 3.3 x 10^{-19} C. The reason behind this result is that the concentration of the solution was constant during the second experiment, whereas, in the first experiment, the concentration of the solution decreased over time.

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Answer:

Explanation:

To calculate the standard enthalpy of formation for TICL(I), we need to use the given thermochemical equations and Hess's law. The equation for the formation of TICL(I) is:

C(s) + TiO₂ (s) + 2Cl(g) → TICL(I) + CO(g)

Using the given equations for the formation of CO(g) and TiO2(s), we can manipulate them to get the necessary reactants for the formation of TICL(I):

Ti(s) + O₂(g) → TiO₂(s) (reverse the equation)

C(s) + 1/2O₂(g) → CO(g) (multiply by 2)

Adding these two equations, we get:

Ti(s) + 2C(s) + O₂(g) → TiO₂(s) + 2CO(g)

This equation is the reverse of the equation given for the formation of TICL(I), so we need to flip its sign to get the correct value for the enthalpy change:

TICL(I) → C(s) + TiO₂ (s) + 2Cl(g) + CO(g)

ΔH° = -(-394 kJ/mol + 286 kJ/mol + 0 + (-221 kJ/mol))

ΔH° = -(-329 kJ/mol)

ΔH° = +329 kJ/mol

Therefore, the correct value for the standard enthalpy of formation for TICL(I) is +329 kJ/mol, which is option D.

Option (A) is correct. If more solvent is added to a solution the solution molarity decreases as it increases the volume of the solution but the moles of the solute remains same.

The molarity of a solution is defined as the number of moles of solute dissolved in one liter of solution. In order to calculate the molarity of a solution, we divide the moles of solute by the volume of the solution expressed in liters.

  Molarity = moles of solute / volume of the solution

When more solvent is added to an aqueous solution, the molarity of that solution decreases. The molarity decreases because the number of moles of the solute does not change but the total volume of the solution increases. On adding more solvent to a solution it allows more solutes to dissolve in the solution and makes the solution unsaturated. It is called dilution process. In the dilution process the amount of solute remains constant but the total amount of solution increases by decreasing the final concentration.

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The pressure in the can that holds 2.00 moles of gas at 22.3°C is 48.49atm.

The pressure in a container can be calculated by using the following ideal gas law expression;

PV = nRT

Where;

According to this question, a 1.0L canister holds 2.00 moles of gas at 22.3°C. The pressure can be calculated as follows:

P × 1 = 2 × 0.0821 × 295.3

P = 48.49atm

Therefore, the pressure in the canister is 48.49 atm.

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The relative magnitudes (absolute values) of the lattice energy and heat of hydration for the compound is exothermic, resulting in an increase in the temperature of the solution.

When lithium iodide (LiI) is dissolved in water and the solution becomes hotter, this indicates that the dissolution process is exothermic, i.e., it releases heat to the surroundings.

The dissolution of an ionic compound in water involves two processes: breaking apart the lattice structure of the solid (lattice energy) and the hydration of the individual ions by water molecules (heat of hydration). The lattice energy is the energy required to separate the ions in the solid state, and the heat of hydration is the energy released when the separated ions are surrounded by water molecules.

In the case of lithium iodide, the fact that the solution becomes hotter indicates that the heat of hydration is greater than the lattice energy. This means that more energy is released when the ions are hydrated by water molecules than is required to break apart the lattice structure.

Therefore, the overall process is exothermic, resulting in an increase in the temperature of the solution.

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The complete question goes thus

When lithium iodide (LiI) is dissolved in water, the solution becomes hotter.

Is the dissolution of lithium iodide endothermic or exothermic?

What can you conclude about the relative magnitudes of the lattice energy of lithium iodide and its heat of hydration?

The correct designation for the stereocenter carbon atom in the molecule is s configuration.

The correct designation for the stereocenter carbon atom in the molecule is s configuration. A central carbon has a dashed bond pointing up to a methyl group, a wedged bond pointing to the right to an aldehyde, a dashed bond pointing down to a hydroxy group and a wedged bond pointing to the left to a hydrogen. The stereochemistry of it is s configuration and it is pointing in upward direction. The stereo center of carbon atom rotates in two ways and its dash pointing in upward direction and wedge pointing in downward direction.

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In the catalytic triad, the purpose of the aspartic acid residue is to activate the serine residue by removing a hydrogen ion (H+) from the serine residue, causing it to become a highly reactive alkoxide ion.

The catalytic triad is a trio of amino acid residues that play a significant role in catalyzing reactions in a diverse range of enzymes. The residues found in the triad are typically present in the active site of an enzyme, where they work together to catalyze a reaction.Aside from the aspartic acid residue, the catalytic triad also contains two other amino acid residues: serine and histidine. These three residues work together to carry out the enzyme's function. In the case of the aspartic acid residue, its primary role is to activate the serine residue by removing a hydrogen ion (H+) from the serine residue, causing it to become a highly reactive alkoxide ion. This highly reactive ion then goes on to react with the enzyme's substrate, resulting in the desired reaction.Catalytic triads are found in a variety of enzymes, including chymotrypsin, trypsin, and elastase. Each of these enzymes has a slightly different catalytic triad that is uniquely suited to catalyzing the specific reaction the enzyme carries out.

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The correct response is D. Elements W and Z are metals, Elements X and Y are nonmetals, but Element Y is in Group 18 (noble gas).

A substance is considered to be an element if it cannot be chemically reduced to a simpler form. Every atom in an element has the same amount of protons in its atomic nucleus, and as such, the element is made up of identical atoms.

In general, elements in the same group of the periodic table exhibit comparable chemical and physical properties due to their similar electron configurations.

Option D proposes that Elements W and Z are metals, which frequently lose electrons to create positive ions and have poor electronegativity. In contrast, Elements X and Y are nonmetals, which tend to have strong electronegativity and tend to gain electrons to create negative ions. This grouping makes sense as metals and nonmetals have extremely different properties, and elements that are close each other in the periodic table tend to have different properties.

Noble gases are known for their unreactivity and non-reactive character due to their stable electron configurations, so this classification makes sense as well.

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It is incorrect to say that adding more reactants to an equilibrium chemical system will result in only one of the reactants being consumed.

A reaction mixture's equilibrium composition is unaffected. This is due to the fact that in a reversible reaction, a catalyst enhances the speed of both forward and backward reactions to the same level.

Every reaction aims to achieve a state of chemical equilibrium, or the point when both the forward and backward processes are moving at the same rate.

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The correct option is (B) LiOH. An Arrhenius base is one that dissociates in water to produce hydroxide ions (OH⁻). LiOH is an example of an Arrhenius base.

According to the Arrhenius acid-base theory, acids are compounds that dissolve in water to form H⁺ (hydrogen ion) while bases are compounds that dissolve in water to form OH⁻ (hydroxide ion).

Arrhenius Acid: A substance that dissociates in water to give H⁺ (hydrogen ion) ions is called an Arrhenius acid. They release hydrogen ions when dissolved in water. For example, HCl, HNO₃, H₂SO₄, HClO₄, etc.

Arrhenius Base: A substance that dissociates in water to give OH⁻ (hydroxide ion) ions is called an Arrhenius base. They release hydroxide ions when dissolved in water. Examples include NaOH, KOH, Mg(OH)₂, Ca(OH)₂, etc.

Let's now analyze the given options.

A) CH₃CO₂H is an organic acid called acetic acid. It is a weak acid and not an Arrhenius base.

B) LiOH dissociates in water to form Li⁺ and OH⁻ ions. Hence, it is an Arrhenius base.

C) CH₃OH is an alcohol called methanol. It is a weak acid and not an Arrhenius base.

D) NaBr is an ionic compound consisting of Na⁺ and Br⁻ ions. It is neither an acid nor a base.

E) More than one of these compounds is an Arrhenius base. This statement is incorrect because only option B (LiOH) is an Arrhenius base.

Hence, option B is the correct answer.

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If the reaction quotient (Q) is smaller than the equilibrium constant (K) for a reaction, then the reaction will proceed towards the right, i.e., in the direction of the products. The correct option is (b).

This is because the forward reaction is favored over the reverse reaction as there is less number of products present, and the system tends to minimize the stress caused by an increase in the number of reactants. Here, stress refers to the difference between Q and K.

In other words, if Q < K, then the system has less number of products than it should at equilibrium. Hence, the reaction proceeds in the forward direction to increase the number of products until Q = K. After this point, the reaction reaches equilibrium, and the rates of the forward and reverse reactions become equal.

In contrast, if Q > K, then the system has more products than it should be at equilibrium. Hence, the reaction proceeds in the reverse direction to decrease the number of products until Q = K. After this point, the reaction reaches equilibrium, and the rates of the forward and reverse reactions become equal.

Therefore, option (b) is the correct answer. The reaction will proceed to the right (product side) if Q is smaller than K.

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13.75 mL of titrant were released from the burette as a whole.

To determine the total volume of titrant dispensed from the burette, you need to subtract the initial reading from the final reading for each trial and add up the results.

For the first trial:

Final reading = 12.75 mL

Initial reading = 3.50 mL

Volume of titrant dispensed = Final reading - Initial reading = 12.75 mL - 3.50 mL = 9.25 mL

For the second trial:

Final reading = 15.60 mL

Initial reading = 12.75 mL

Volume of titrant dispensed = Final reading - Initial reading = 15.60 mL - 12.75 mL = 2.85 mL

For the third trial:

Final reading = 17.25 mL

Initial reading = 15.60 mL

Volume of titrant dispensed = Final reading - Initial reading = 17.25 mL - 15.60 mL = 1.65 mL

The total volume of titrant dispensed from the burette is the sum of the volumes from each trial:

Total volume = 9.25 mL + 2.85 mL + 1.65 mL = 13.75 mL

Therefore, the total volume of titrant dispensed from the burette is 13.75 mL.

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Atoms with five valence electrons typically form three covalent bonds.

This is because atoms tend to form enough bonds to complete their outermost shell, which typically requires eight valence electrons (the octet rule). In the case of an atom with five valence electrons, it needs to gain three electrons to complete its outer shell. However, it is often easier for the atom to share three electrons with other atoms through covalent bonding, resulting in three covalent bonds being formed. This is commonly seen with elements such as nitrogen (N) and phosphorus (P), which have five valence electrons in their outermost shells.

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For this investigation, you used commercial juices, which are known to contain appreciable amounts of malic acid. The malic acid in the juice sample will undergo neutralization.

This means the volume of base used in the neutralization reaction is less than what it should have been, making it appear like there are more moles of malic acid present.

Therefore, the calculated concentration of the malic acid in the juice samples will be greater than the actual concentration in the commercial juices.

This means the volume of NaOH used in the neutralization reaction is less than what it should have been, making it appear like there are more malic acids present.

What is neutralization?  Neutralization is the chemical reaction between an acid and a base to produce a salt and water.

This chemical reaction takes place between hydrogen ions (H+) and hydroxide ions (OH-).

The main aim of neutralization is to balance the acid and base's pH level.

When the pH value is around 7, it means that the acid and base are neutralized.

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Answer:

The Clausius-Clapeyron equation is given by:

ln(P2/P1) = -(ΔHvap/R) * (1/T2 - 1/T1)

where P1 and T1 are the vapor pressure and temperature of the substance at one point, P2 and T2 are the vapor pressure and temperature at another point, ΔHvap is the enthalpy of vaporization, and R is the gas constant.

We can use this equation to find the vapor pressure of methanol at 73.5°C, given the vapor pressure of water at 100.0°C.

First, we convert the temperatures to Kelvin:

T1 = 100.0°C = 373.2 K

T2 = 73.5°C = 346.7 K

Next, we substitute the values into the equation, along with the enthalpy of vaporization for methanol and the gas constant:

ln(P2/101.3 kPa) = -(35.2 kJ/mol / 8.314 J/(mol*K)) * (1/346.7 K - 1/373.2 K)

Simplifying, we get:

ln(P2/101.3 kPa) = -5.631

Taking the exponential of both sides, we get:

P2/101.3 kPa = e^(-5.631)

P2 = 101.3 kPa * e^(-5.631)

P2 = 2.784 kPa

Therefore, the vapor pressure of methanol at 73.5°C is approximately 2.784 kPa, to the first decimal point.

The empirical formula for a compound which contains 0.0134 g of iron, 0.00769 g of sulfur and 0.0115 g of oxygen is FeS2O3.

First determine the ratio of each element. Divide the mass of each element by its atomic weight and then divide the results by the smallest value obtained.

The atomic weights are: Fe=55.845, S=32.065 and O=16.00. Dividing the mass of each element by its atomic weight gives the following ratios: Fe=0.0240, S=0.0024 and O=0.0072.

Dividing the ratios by the smallest value (0.0024) gives us 10, 1 and 3 respectively. This means that the empirical formula is Fe10S1O3.

We must divide all values by the highest common factor, which in this case is 2. This gives us Fe5S1/2O3/2 or FeS2O3.

Therefore, the empirical formula for a compound which contains 0.0134 g of iron, 0.00769 g of sulfur and 0.0115 g of oxygen is FeS2O3.

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The amount of Calcium chloride required to prepare 15 ml of 0.25 M CaCl₂ solution using deionized water and CaCl₂ salt is 0.415 grams. Thus can be calculated by using molarity.

The calculation to prepare 15 ml of a 0.25 M CaCl₂ solution using deionized water and CaCl₂ salt is given below:

To make a 0.25M CaCl₂ solution, the molar mass of CaCl₂ must be calculated first.

Molar mass of CaCl₂ = 1 × 40.08 + 2 × 35.45= 110.98 g/mol

The calculation of number of moles is given as:

Number of moles = Molarity × Volume (L)

Number of moles of CaCl₂ = 0.25 × (15/1000) = 0.00375 moles

Number of grams of CaCl₂ = Number of moles × Molecular weight

Number of grams of CaCl₂ = 0.00375 × 110.98= 0.415g

So, to prepare a 0.25M CaCl₂ solution with a volume of 15 ml, 0.415g of CaCl₂ needs to be added to 15 ml of deionized water.

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The concentration of the chemist's Iron(III) bromide solution is 2.147 mol/L.

Iron(III) bromide, also known as ferric bromide, is a coordination compound with the formula FeBr₃. It is a powerful Lewis acid and has an octahedral molecular geometry.

It is a potent catalyst for organic reactions and is used as a starting material for the synthesis of other compounds. The chemical formula for iron(III) bromide is FeBr₃.

The molar mass of FeBr₃ is: 55.85 + 79.90 × 3 = 274.55 g/mol

The number of moles of FeBr₃:

mass of FeBr₃ = 0.59 kg = 590 g number of moles of FeBr₃ = mass / molar mass

= 590 / 274.55

= 2.147 mol

Thus, the concentration of the chemist's iron(III) bromide solution is 2.147 mol/L.

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For our indicator, the wavelength of maximum absorbance for the ph < 4.00 solution is equals to the 450 nm and the color correspond to this wavelength is yellow. the wavelength of maximum absorbance for the ph < 10.00 solution is equals to the 590 nm and the color correspond to this wavelength is purple. The colors of these solutions relate to the colors at their absorbance maxima is observed due colors complementary nature of observing colour with color of the wavelength that is being absorbed.

The color of bromcresol violet changes from yellow in its acidic form to purple in its basic form. After we make all of the experiment we should obtain a graph similar to the one which present above figure 2. Now, to select the wavelength of maximum absorbance for the pH < 4.00 solution pick the line of the graph traced at pH 4. This line has a maximum around 450 nm (look closely at the graph). The color in this case is yellow. To determine the wavelength of maximum absorbance for the pH > 10.00 solution pick now the line traced for the solution at pH 10. The maximum curvature should be around 590 nm. The color for this wavelength is purple. For the last question, is about the observation of the colors of these solutions relate to the colors at their absorbance maxima. The observing colours are complementary to the color that is measured the absorption wavelength. We can say that 590 nm is the wavelength of the red color. Since the red hue is the absorbed color, the reflected color is what we see, the complementary color. The same goes for yellow. Therefore, yellow is a complementary color of the wavelength that is being absorbed.

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Complete question:

For your indicator, what is the wavelength of maximum absorbance for the ph < 4. 00 solution? what is the wavelength of maximum absorbance for the ph > 10. 00 solution? what colors correspond to these wavelengths? how do the observed colors of these solutions relate to the colors at their absorbance maxima?See the above figure.

NH4NO₃is endothermic and the dissolving of NaOH is exothermic. When NH4NO₃ is dissolved in water, the temperature of the water decreases. When NaOH is dissolved in a separate water sample, the temperature of the water increases.

Endothermic reactions are chemical reactions that produce products by absorbing heat energy from their surroundings. These reactions reduce the temperature of their surroundings, resulting in a cooling effect.

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6.82 g of coal must be burned to heat 500.0g of water from20.0°Celsius to 95.0°Celsius when heat combustion for a sample of coal is 23.0 kJ/g.

To calculate the amount of coal (in grams) that must be burned to heat 500.0g of water from 20.0°Celsius to 95.0°Celsius, we first need to calculate the amount of heat energy needed to heat the water. This is done using the equation:

Q = m * c * ΔT

where Q is the amount of heat energy needed (in Joules), m is the mass of water being heated (in grams), c is the specific heat capacity of water (4.184 J/(Celsius)(g)), and ΔT is the change in temperature (95.0°Celsius - 20.0°Celsius).

Using the given values, we have:

Q = 500.0g * 4.184 J/(Celsius)(g) * (95.0°Celsius - 20.0°Celsius)

Q =  156,900J

Now, since the heat combustion for the sample of coal is 23.0 kJ/g, we need to calculate how many grams of coal we need to burn to provide 953,280 J of energy. To do this, we divide the heat energy needed ( 156,900J) by the heat combustion of coal (23.0 kJ/g), which gives us:

156,900 J / 23.0 kJ/g = 6.82 g

Therefore, to heat 500.0g of water from 20.0°Celsius to 95.0°Celsius, we need to burn 6.82 g of coal.

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The compound that is a non-electrolyte when dissolved in water is CCl4.

When CCl4 dissolves in water, it does not break down into ions, and it does not conduct electricity.What is an electrolyte?An electrolyte is a compound that dissolves in water, and its solution conducts electricity due to the presence of ions. A compound must dissociate in water to produce ions to be considered an electrolyte. The ions can move freely through the solution, allowing for the conduction of electricity.There are three types of electrolytes: strong electrolytes, weak electrolytes, and nonelectrolytes. Strong electrolytes dissociate fully into ions in water and conduct electricity very efficiently. Weak electrolytes only partially dissociate, and they conduct electricity less efficiently than strong electrolytes.Nonelectrolytes are substances that do not dissolve in water or dissolve but do not dissociate into ions. Because they do not have ions, they do not conduct electricity. CCl4 is a nonelectrolyte, as it does not produce any ions when it dissolves in water.

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