Which of the following compounds contain sterogenic centres (stereocentres)?

The  pOH refers to the negative logarithm of the hydroxide concentration.

The term pOH refers to the negative logarithm of the hydroxide concentration. Now we know that there is a relation that states that;

[H+]  [OH-]  = 1 * 10^-14

We shall now apply this relation in each case as follows;

[OH-]  =  1 * 10^-14/1 x 10-12

[OH-]  = 1 * 10^-2

pOH = 2

2. pOH = -log( 1 x 10-6 M) = 6

3.  [OH-]  =  1 * 10^-14/ 1 x 10-1

[OH-]  =  1 * 10^-13

pOH = 13

4.  [OH-]  =  1 * 10^-14/  1 x 10-4

[OH-]  =   1 * 10^-10

pOH = 10

5.  pOH = -log(  1 x 10-7) = 7

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Answer:

Metals

Explanation:

Positive ions are formed when atoms give up some valence electrons in order to have a full octet. The atoms most likely to do this have a small number of valence electrons. Most to these atoms are generally in the s-block (left side) of the periodic table. These elements are metals.

*nonmetals are located in the p-block (right side) and noble gases are located in the 18th column (far right column)

Answer:

See below

Explanation:

H2 S     shows that each mole of H2S has two moles of H in it

  so 10 moles of H2S would have 20 moles of H

Each mole is Avagadro's Number of atoms

   20 moles  *   6.022 x10^23  atoms/mole = 120.44 x 10^23 toms of H

H2S has one mole of S   for each mole of H2S

     there are then 10 moles of S

       10 * 6.022 x 10^23 = 60.22 x 10^23 atoms of S

The factor that has changed inside the container would be the pressure.

Sodas in cans are preserved using a gas, carbon dioxide to be precise.

The gas is used to preserve the drink and sealed under pressure.

When a can of soda is opened, the first thing that escapes is the carbon dioxide gas. By doing so, the pressure in the can reduces.

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1. The mass of silane gas, SiH₄ formed from the reaction is 3.57 g

2. The mass of H₂O produced from the reaction is 173.75 g

Balanced equation

Mg₂Si (s) + 4H₂O (l) ---> 2Mg(OH)₂ (aq) + SiH₄ (g)

Molar mass of Mg₂Si = (24×2) + 28 = 76 g/mol

Mass of Mg₂Si from the balanced equation = 1 × 76 = 76 g

Molar mass of SiH₄ = 28 + (4×1) = 32 g/mol

Mass of SiH₄ from the balanced equation = 1 × 32 = 32 g

SUMMARY

From the balanced equation above,

76 g of Mg₂Si reacted to produce 32 g of SiH₄

From the above information, we can obtain the mass of SiH₄ produced by the reaction of 8.48 g of Mg₂Si as illustrated below:

From the balanced equation above,

76 g of Mg₂Si reacted to produce 32 g of SiH₄

Therefore,

8.48 g of Mg₂Si will react to produce = (8.48 × 32) / 76 = 3.57 g of SiH₄

Thus, 3.57 g of SiH₄ were obtained from the reaction.

Balanced equation

4NH₃ (g) + 7O₂ (g) ---> 4NO₂ (g) + 6H₂O (g)

Molar mass of NH₃ = 14 + (1×3) = 17 g/mol

Mass of NH₄ from the balanced equation = 4 × 17 = 68 g

Molar mass of H₂O = (2×1) + 16 = 18 g/mol

Mass of H₂O from the balanced equation = 6 × 18 = 108 g

SUMMARY

From the balanced equation above,

68 g of NH₃ reacted to produce 108 g of H₂O

From the above information, we can obtain the mass of H₂O produced by the reaction of 109.4 g of NH₃ as illustrated below:

From the balanced equation above,

68 g of NH₃reacted to produce 108 g of H₂O

Therefore,

109.4 g of NH₃ will react to produce = (109.4 × 108) / 68 = 173.75 g of H₂O

Thus, 173.75 g of H₂O were obtained from the reaction.

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The missing labels are:

It is a way to represent a chemical reaction.

Let's consider the following chemical equation.

CuCO₃(s) + H₂SO₄(aq) →  CuSO₄(aq) + H₂O(l) + CO₂(g)

The missing labels are:

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The correct number of significant figures are,

Final volume of burette is 38.86ml

Volume of NaOH is 38.36ml

Initial volume of burette V(I)= 0.50ml

Molarity of NaOH is M1 = 0.4171M

Volume of Vinegar V2 = 10.00ml

Molarity of acetic acid M2= 1.6M

Final volume of burette V(f)= ?

volume of NaOH V1 = V(f) - V(I) = ?

Molarity = moles of solute / volume of solution

Molarity of acetic acid = moles of CH3C00H / Volume of vinegar

1.6 = moles of CH3C00H / 10.00

moles of CH3C00H = 1.6 * 10.00

Moles of CH3COOH is 16.00mols

In a volumetric titration the amount of Standard solution (titrant) used in the titration is stoichiometrically equivalent to amount of unknown solution (analyte) used for the titration at the endpoint.

Hence,

Moles of NaOH = Moles of CH3COOH

Moles of NaOH is 16.00mols

Molarity of NaOH = moles of NaOH / Volume of NaOH

0.4171 = 16.00 / V(f)-V(I)

0.4171 = 16.00 / V(f)- 0.50

V(f)  = ( 16 / 0.4171 ) + 0.50

V(f) = 38.86 ml

Final volume of NaOH V(f) is 38.86ml

Volume of NaOH V1 = 38.86 - 0.50

Volume of NaOH is 38.36ml

DISCLAIMER: Question is incomplete

Initial volume of burette = 0.50ml

Molarity of NaOH  = 0.4171M

Volume of Vinegar = 10.00ml

Molarity of acetic acid = 1.6M

Final volume of burette = ?

volume of NaOH  = ?

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The state of matter of Polaris, the north star is gas.

Stars are made up of a mixture of hot gases.

The mixture consists of helium and hydrogen. Hydrogen burns into helium to give starts a shining appearance when observed from a far distance.

Thus, the state of matter of all stars, including the north star, is gas.

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The number of moles of the gas sample present at the end is 0.78 moles.

PV = nRT

V = nRT/P

At a constant volume, V;

n₁RT₁/P₁ = n₂RT₂/P₂

n₁T₁/P₁ = n₂T₂/P₂

n₂ = (n₁T₁P₂)/(P₁T₂)

where;

n₂ = (3 x 294.7 x 0.998)/(3.75 x 301.1)

n₂ = 0.78 moles

Thus, the number of moles of the gas sample present at the end is 0.78 moles.

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The endangered species in my region with their estimate population are:

This cheetah is said to be an endangered species because of their loss of their habitat and  also due to fragmentation, trade and little human-activities.

West African Lion is said to be an endangered species because the lion's historic range in West Africa was said to be lowered by a lot of amount or scale as a result of land use changes and human activities such as falling of trees, buildings, etc.

Hence the endangered species in my region with their estimate population are:

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The sample with the largest number of oxygen atoms will be calcium perchlorate.

Since we are not looking at the number of moles, the mass of the compounds has no bearing on the number of atoms of oxygen.

Therefore, the compound with the largest number of oxygen atoms is calcium perchlorate.

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Answer: D. 3Ag+ + PO43- = Ag3PO4

Explanation:

Overall Chemical Equation:

Ensure that the elements on both sides of the equation are balanced.

3C2H3AgO2 + Na3O4P = Ag3PO4 + 3C2H3NaO2

Solubility Equation:

Determine the state or phase of each substance (gas=g, liquid=l, solid/non-soluble=s, aqueous/soluble=aq) in its undissociated form.

3C2H3AgO2(aq) + Na3O4P(aq) = Ag3PO4(s) + 3C2H3NaO2(aq)

Complete Ionic Equation:

The complete ionic equation includes spectator ions. Write it by breaking all the soluble ionic compounds into their respective ions.

3Ag+(aq) + 3CH3COO-(aq) + 3Na+(aq) + PO43-(aq) = Ag3PO4(s) + 3Na+(aq) + 3CH3COO-(aq)

Net Ionic Equation:

The balanced net ionic equation includes only species that are involved in the reaction. It can be found by removing ions that occur on both the reactant and product side of the complete ionic equation.

3Ag+(aq) + PO43-(aq) = Ag3PO4(s)

Answer:

A ship comprises of both visible as well as invisible parts. . The most forward part of a ship is called a Bow, the left-hand side of . at a topmost accessible height of the ship and just above the bridge . The mast is a rangy spar arrangement which is elevated more or less vertically to the Centre line of a ship .

The pH of the buffer solutions as determined using the Henderson–Hasselbalch equation are:

The pH of a buffer is determined using the Henderson–Hasselbalch equation shown below:

A. Volume of acetic acid = 5 mL; Volume of sodium acetate = 5 mL; pka of acetic acid = 4.75

The solutions of acetic acid and sodium acetate are equimolar;

pH = 4.75 + log(1)

pH = 4.75

B. Volume of acetic acid = 5 ml; Volume of sodium acetate = 1 mL; pka of acetic acid = 4.75

The solutions of acetic acid and sodium acetate are equimolar;

pH = 4.75 + log(1/5)

pH = 4.05

C. Volume of acetic acid = 10 ml; Volume of sodium acetate = 1 mL; pka of acetic acid = 4.75

The solutions of acetic acid and sodium acetate are equimolar;

pH = 4.75 + log(1/10)

pH = 3.75

D. Volume of acetic acid = 1 ml; Volume of sodium acetate = 10 mL; pka of acetic acid = 4.75

The solutions of acetic acid and sodium acetate are equimolar;

pH = 4.75 + log(10/1)

pH = 5.75

E. Volume of acetic acid = 1 ml; Volume of sodium acetate = 5 mL; pka of acetic acid = 4.75

The solutions of acetic acid and sodium acetate are equimolar;

pH = 4.75 + log(5/1)

pH = 5.45

In conclusion, the pH of the buffer solutions are determined using the Henderson–Hasselbalch equation.

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Answer:

Dihydrogen

Explanation:

Dihydrogen is FORMALLY oxidized.... i.e. its oxidation number increases... And we adds the half equations together such that the electrons are eliminated

They are life cycle differences that protect the offspring and help them to survive. The correct option is C.

Some organisms have life cycle features that ensure that their population is perpetuated in subsequent generations.

Such features include ensuring that propagules are only released when they are mature and making sure that eggs are hatched and offspring become viable before they are allowed to move to the environment.

These actions will make sure that the propagules of offspring have what it takes to survive in their new environment.

In other words, these life cycle features are embedded in the genome of organisms as a way to survive the environment.

Thus, the features of the Himalayan balsam plant and that of the Surinam toad are more or less targeted toward the same thing - the survival of their offspring.

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Answer: Option (C) is correct, They are life cycle differences that protect the offspring and help them to survive.

Explanation: Hope it helps!

Good luck!!!

Considering the definition of percent yield, the percent yield is 76%.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

[tex]percent yield=\frac{actual yield}{theorical yield}x100[/tex]

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

In this case, you know:

Replacing in the definition of percent yield:

[tex]percent yield=\frac{0.532 moles}{0.700 moles}x100[/tex]

Solving:

percent yield= 76%

Finally, the percent yield is 76%.

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The excerpt from an essay about higher education that most clearly shows an example of logos is:

The Logos Definition is one that is often argued by a lot of people as people tends to appeal to others emotions and some other times, people do appeal to one's' ethics or morals.

The term logos is a term that connote the use of logic. It also includes the use of deductive reasoning to get to a conclusion.

The excerpt from an essay about higher education that most clearly shows an example of logos is:

Option d is correct because it shows the cause and its effect.

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Answer:

Watson law is not part of the combined gas law

There are 5 basic gas laws of ideal gases:

This law features Charles', Boyle's and Gay-Lussac's laws.

Therefore, Dalton's and Avogadro's laws are exluded.

Answer:

63.9%

Explanation:

moral mass of x (# x ions) -divided by- Moral mass of compound.

% of cl = (35.5g) (2 cl ions) -divided by- 111.1g × 100

%= 63.9%

The total energy released per gram of methane burnt is  119,941.3 J/g.

Q = mcΔθ

where;

Q = (500)(4.184)(68 - 25)

Q = 89,956 J

0.3T =  89,956 J

T =  89,956 J/0.3

T = 299,853.3 J

Total energy per gram of methane, E = T.E/m

E = (299,853.3 J) / (2.5 g)

E = 119,941.3 J/g

Thus, the total energy released per gram of methane burnt is  119,941.3 J/g.

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Answer:

A. Semi Permeable.

Explanation:

Cell membranes are semi permeable.

A substance is an element if it consists of a single type of atom. A substance is a compound if it is made up of more than one element.

In chemistry, an element is defined as all pure substances consisting of the same atom. For example, magnesium and potassium metal are all elements because they consist of magnesium and potassium atoms only.

On the other hand, compounds are defined as substances consisting of 2 or more atoms of different elements. For example, sodium chloride consists of atoms of sodium and chlorine. Hence, it is considered to be a compound.

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From the calculations, the pH of the final solution is 9.04.

We can use the Henderson Hasselbach equation to obtain the final pH of the solution in terms of the pKb and the base concentration.

Number of moles of salt = 250/1000 L * 0.5 M = 0.125 moles

Number of moles of base = 150/1000 L * 0.5 M = 0.075 moles

Total volume of solution = 250ml + 150ml = 400ml or 0.4 L

Molarity of base = 0.075 moles/ 0.4 L = 0.1875 M

Molarity of salt = 0.125 moles/ 0.4 L = 0.3125 M

pOH = pKb + log[salt/base]

pKb = -log(1.8 x 10^-5) = 4.74

pOH = 4.74 + log[0.3125/0.1875 ]

pOH = 4.96

pH = 14- 4.96

pH = 9.04

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Answer:

H2O

Explanation:

water is made up of 1 hydrogen snd 2 oxygen

The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C          40.6       12                   [tex]\frac{40.6}{12}[/tex] = 3.3                        [tex]\frac{3.3}{3.3} = 1[/tex]

H          5.1          1                      [tex]\frac{5.1}{1}[/tex] = 5.1                          [tex]\frac{5.1}{3.1} = 2[/tex]

O         54.2       16                    [tex]\frac{54.2}{16}[/tex] = 3.3                        [tex]\frac{3.3}{3.3} = 1[/tex]

The Empirical formula of compound is C₁H₂O₁ or CH₂O

Molecular formula = Empirical formula × n

[tex]n = \frac{\text{Molecular weight}}{\text{Empirical Formula weight}}[/tex]

   [tex]= \frac{118.084}{30}[/tex]

   = 4

Molecular formula = n × Empirical formula

                              = 4 (C₁H₂O₁)

Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

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The mass of 1 atom of copper metal in the given face-centered cubic structure is determined as  1.054 x 10⁻²² g.

The mass of 1 atom of copper is calculated as follows;

mass of 1 atom of copper = molar mass of copper / Avogadro's number

substitute the value of molar mass of copper and Avogadro's number;

mass of 1 atom of copper = (63.5 g/mol) / (6.023 x 10²³)

mass of 1 atom of copper = 1.054 x 10⁻²² g

Thus, the mass of 1 atom of copper is determined as  1.054 x 10⁻²² g.

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After removing the particles, the solution's chloride content can be assessed using various techniques, such as titration and photometry.

After removing the particles, the solution's chloride content can be assessed using various techniques, such as titration and photometry.

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