When referring to a plasmid, it can be said that the plasmid is a circular piece of DNA found in a bacterium.
Plasmids are small extrachromosomal DNA molecules within cells that are physically separated from the chromosomal DNA and capable of independent replication. They are most frequently established as small circular double-stranded DNA molecules in bacteria. However, plasmids can be present in archaea and eukaryotes.
Plasmids occur naturally in bacterial cells and also in some eukaryotes. Genes contained in plasmids often provide bacteria with genetic advantages such as antibiotic resistance. Plasmids are the utmost commonly used bacterial cloning vectors. These cloning vectors contain sites that allow insertion of DNA fragments, such as multiple cloning sites and a polylinker containing several commonly used restriction sites to which DNA fragments can be ligated.
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What do we call the organized steps taken to answer a scientific problem?
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What keeps object A in orbit around object B?
The force of gravity between objects A and B.
The force of gravity between objects A and C.
The force of gravity between objects A and E.
The force of gravity between objects B and X.
9514 1404 393
Answer:
(a) The force of gravity between objects A and B.
Explanation:
The force of gravity between two objects is what keeps them in orbit around their common center of mass. If A is in orbit around B, it is because of ...
The force of gravity between objects A and B.
_____
Please note this question can be asked different ways, so different answers may apply.
Answer:
A. The force of gravity between objects A and B.is x male or female in cell reference
Answer:
An XY chromosome will be a male chromosome pair.
An XX chromosomes will be a female chromosome pair.
Which of the following correctly explains the differences between artificial and natural selection?
Not sure what the options are, but artificial selection would be when farmers/breeders choose only to plant/breed the organism with desired characteristics in order to cause the evolution of the trait while natural selection is when organisms that are better adapted to their environment usually survive and produce offspring, causing the evolution of their traits which help them to survive.
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Question 10
1.25
Perception, thinking, language, problem-solving, and creativity are topics of investigation for those interested in:
O A. Humanistic psychology
ОВ.
Introspection
oc. Cognitive psychology
Structuralism
OD
L A Moving to the next question prevents changes to this answer.
ere to search
It is said that it is the male who determines the sex of the baby rather than it is the female. From your knowledge of the sex chromosome, is it true?
Answer: yes because they have xy chromasomes so they have to give one of them
Explanation:
What are general traits of a specialist species?
Answer:
fvgvurhufv
Explanation:
What type of genotype does a person with a recessive genetic disorder have?
Answer:
one mutated recessive one and one mutated dominant gene
Explanation: These disorders are usually passed on by two carriers. Their health is rarely affected, but they have one mutated gene (recessive gene) and one normal gene (dominant gene) for the condition.
Answer:
Because it is a recessive disorder both the representative letters will be lowercase. It will look like this, using D as an example: dd
What is the correct answer I accidentally clicked echo
Answer:
sound waves. they come in longitudinal waves and vibrations. echo is wrong though youre right on that one
Merle is a marking pattern in canine coats that appears as a marbling of color in a solid coat. The merle gene displays incomplete dominance.
CSCS individuals display a solid coat
CMCS individuals are merle and show patches of fur with a lighter, mottled effect
CMCM individuals are "double merle" and show patches of fur with much more pronounced lightening
Another gene, FGF5, also influences coat phenotype and determines whether dogs display long or short coats, with short coats being dominant to long coats.
A. Determine the proportion of offspring phenotypes that would result when two merle dogs mate, if one dog is true-breeding for the long-coat trait and the other dog is true-breeding for the short-coat trait.
a. 0
b. 1/16
c. 1/8
d. 3/16
e. 1/4
f. 3/8
g. 1/2
h. 3/4
1. double merle with short coat:___.
2. double merle with long coat:___.
3. merle with short coat:___.
4. merle with long coat:___.
5. solid with short coat:___.
6. solid with long coat:____.
B. Determine the proportion of offspring phenotypes that would result when two merle dogs mate, if both dogs are heterozygous(Ll) for the gene that regulates coal length.
a. 0
b. 1/16
c. 1/8
d. 3/16
e. 1/4
f. 3/8
g. 1/2
h. 3/4
1. double merle with short coat:___.
2. double merle with long coat:___.
3. merle with short coat:___.
4. merle with long coat:___.
5. solid with short coat:___.
6. solid with long coat:____.
Answer:
A)
1. double merle with short coat: 1/4 (e).
2. double merle with long coat: 0 (a).
3. merle with short coat: 1/2 (g).
4. merle with long coat: 0 (a).
5. solid with short coat: 1/4 (e).
6. solid with long coat: 0 (a).
B)
1. double merle with short coat: 3/16 (d).
2. double merle with long coat: 1/16 (b)
3. merle with short coat: 3/8 (f).
4. merle with long coat: 1/8 (c).
5. solid with short coat: 3/16 (d).
6. solid with long coat:1/16 (b)
Explanation:
Available data:
CSCS individuals display a solid coatCMCS individuals are merle and show patches of fur with a lighter, mottled effectCMCM individuals are "double merle" and show patches of fur with much more pronounced lighteningshort coats, L-, being dominant to long coats, ll.Cross: merle long-coated dog x merle short-coated dogParentals) CMCS ll x CMCS LL
Gametes) CMl, CSl, CMl, CSl
CML, CSL, CML, CSL
Punnett square) CMl CMl CSl CSl
CML CMCM Ll CMCM Ll CMCS Ll CMCS Ll
CML CMCM Ll CMCMLl CMCS Ll CMCS Ll
CSL CMCS Ll CMCS Ll CSCS Ll CSCS Ll
CSL CMCS Ll CMCS Ll CSCS Ll CSCS Ll
F1) 4/16 = 1/4 = 25% CMCM Ll, double merle short-coated individuals
4/16 = 1/4 = 25% CSCS Ll, solid short-coated individuals
8/16 = 1/2 = 50% CMCS Ll, merle chort-coated
Cross: merle short-coated dog x merle short-coated dogParentals) CMCS Ll x CMCS Ll
Gametes) CML, CMl, CSL, CSl, CML, CMl, CSL, CSl
Punnett square) CML CMl CSL CSl
CML CMCM LL CMCM Ll CMCS LL CMCS Ll
CMl CMCM Ll CMCM ll CMCS Ll CMCS ll
CSL CMCS LL CMCS Ll CSCS LL CSCS Ll
CSl CMCS Ll CMCS ll CSCS Ll CSCS ll
F1) 1/16 CMCM LL, double merle short-coated individual
2/16 CMCM Ll, double merle short-coated individual
1/16 CMCM ll, double merle long-coated individual
2/16 = 1/8 CMCS LL, merle short-coated individual
4/16 = 2/8 CMCS Ll, merle short-coated individual
2/16 = 1/8 CMCS ll, merle long-coated individual
1/16 CSCS LL, solid short-coated individual
2/16 = 1/8 CSCS Ll, solid short-coated individual
1/16 CSCS ll, solid long-coated individual
Explain what happens to the enzyme activity of Pepsin as the alkalinity increase.
PLS I HAVE 5 MINS ILL GIVE BRAINLIEST
Answer:
c
Explanation:
When we say that a bulb is fused, what is wrong with the bulb? How can we use it again?
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here is ur answer(refer the image)
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How humans use Nitrogen and phosphorus to make more food?
A. Dog foods
B. Fuels
C. Fertilizers
D. Cars
Answer:
C. Fertilizers
Explanation:
what type of pollination happens when pollen grains from anther are transferred to the stigma of a flower what belongs to the same plant?
A.across-pollination
B.auto-pollination
C.cross-pollination
D.self-pollination
Answer:
It is D
Explanation:
Self-pollination occurs when the pollen from the anther is deposited on the stigma of the same flower, or another flower on the same plant. Cross-pollination is the transfer of pollen from the anther of one flower to the stigma of another flower on a different individual of the same species.
A deleterious recessive allele is one that can be harmful when it is found in its homgous condition, resulting in a poorly fit phenotype. An example of this is the allelefor sickle cell, which results in the condition known as sickle cell anemia when both recessive alleles are inherited. owever, in regions of Afriche proportion of the sickle cell allele is igher than expected, with as much as 15% of the alleles in the population being the recessive, deleteriou rsion. In the African population, there is also a high prevalence of malaria, a disease caused by the parasitic infestation of a plasmodium protozoan in the blood of humans. The recessive allele for sickle cell has been maintained over many generations. Evaluate the graph above and select the claim that supports the high frequency of the recessive allele in these African populations.
A)There is a selective advantage to the aa genotype, as the presence of sickle cell provides a greater fitness in an environment where malaria is common.
B)There is a selective pressure against the aa genotype, but the presence of malaria induces new mutations which generates more alleles within the population.
C)There is directional selection towards the Aa genotype, since aa is often a lethal condition. Non-random mating tends to maintain the recessive allele in the population.
D)There is a selective advantage to the heterozygous (Aa) condition as there is selective pressure against both the AA and aa genotypes. This maintains the recessive allele in the population.
Answer:
D) There is a selective advantage to the heterozygous (Aa) condition as there is selective pressure against both the AA and aa genotypes. This maintains the recessive allele in the population.
Explanation:
Since the AA condition is more likely to be affected by malaria and the aa condition is more likely to not survive the sickle cell condition, the heterozygote here has the advantage.
The high frequency should be considered the D) There is a selective advantage to the heterozygous (Aa) condition.
Evaluation of the graph;Since the AA condition should be impacted by the malaria and the aa condition should not able to survive the cell condition i.e. sickle.
At the same time, the heterozygote has the advantage.
Also, there is the selective pressure that oppose to the AA and aa genetypes.
Hence, the option d is correct.
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If a segment of DNA that contains 500 nitrogen bases contains 100 cytosine nucleotides, how many adenine, guanine, and thymine nucleotides would be present
Answer:
The perecentage of guanine is 30%
Select all of the correct purposes for cells undergoing mitosis
what is types of tissue
Answer:
pls give me brainlest There are 4 basic types of tissue: connective tissue, epithelial tissue, muscle tissue, and nervous tissue. Connective tissue supports other tissues and binds them together (bone, blood, and lymph tissues). Epithelial tissue provides a covering (skin, the linings of the various passages inside the body).
Answer:
There are 4 basic types of tissue: connective tissue, epithelial tissue, muscle tissue, and nervous tissue. Connective tissue supports other tissues and binds them together (bone, blood, and lymph tissues). Epithelial tissue provides a covering (skin, the linings of the various passages inside the body).
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Find the edge length of the cube. (The density of copper is 8.96 g/cm3, and the volume of a cube is equal to the edge length cubed.)
Express your answer with the appropriate units.
Answer:
[tex]x = 2.13\ cm[/tex]
Explanation:
See comment for complete question
Given
[tex]Mass = 87.2g[/tex]
[tex]Density = 8.96gcm^{-3[/tex]
Required
Calculate the edge length of the cube
First, we need to calculate the volume of the cube using:
[tex]Density = \frac{Mass}{Volume}[/tex]
Make Volume the subject:
[tex]Volume= \frac{Mass}{Density }[/tex]
Substitute values for Mass and Density
[tex]Volume= \frac{87.2g}{8.96gcm^{-3}}[/tex]
[tex]Volume= \frac{87.2cm^3}{8.96}[/tex]
[tex]Volume= 9.73cm^3[/tex]
Represent the edge length with x.
So:
[tex]Volume = x^3[/tex]
Substitute x^3 for Volume in [tex]Volume= 9.73cm^3[/tex]
[tex]x^3 = 9.73cm^3[/tex]
Take cube root of both sides
[tex]x = \sqrt[3]{9.73cm^3}[/tex]
[tex]x = 2.13\ cm[/tex] --- approximated
Hence, the edge length is 2.13cm
A congenital cataract is a clouding of the lens of the eye that is present from birth. The mode of
inheritance for one type of congenital cataract is from a dominant allele. Suppose a man is
heterozygous for this type of congenital cataract, and a woman does not have cataracts. If these two
individuals have a child, what is the probability that the child will have this type of congenital cataract?
a. 25%
b. 50%
c. 75%
d. 100%
Answer:
The mode of inheritance for one type of congenital cataract is autosomal dominant. If these two individuals have a child, what is the probability that the child will have A male with horns is mated with a heterozygous female without horns.
An increase in the rate of evolution in a population will be affected by which scenario?
Answer:
Shorter generation times, and warmer environments.
describe the feature of cell mbrane
Answer:
The cell membrane or plasma membrane is a biological and thin semi-permeable membrane that surrounds the cytoplasm of a cell
Explanation:
Using compaction and cementation explain why sedimentary rocks are not just a loose pile of sand and rocks.
Compaction and Cementation They are compacted, reducing the available pore space and expelling much of the pore-water. Dissolved minerals in the ground water precipitate (crystallize) from water in the pore spaces forming mineral crusts on the sedimentary grains, gradually cementing the sediments, thus forming a rock.
Through compaction and cementation, minerals form a crusts on the sedimentary rocks which are no longer just a loose pile of sand and rocks.
What are sedimentary rocks?Sedimentary rocks are formed from the pre-existing rocks or pieces of or fossils of living organisms. They form from the deposits which accumulate on the surface of Earth. Sedimentary rocks often have distinctive layering or bedding over Earth.
Dissolved minerals present in the ground water precipitates from the water surface present in the pore spaces forming mineral crusts on the sedimentary grains, which gradually undergo cementing the sediments, which thus lead to formation of a rock.
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3. If an engine exerts 250N of force and moves an object 6.0 meters, how much work did it do? 06
(1 Point)
O 0.024 J
C
42 J
O 41.6 J
O 1500 J
Answer:
1500J
Explanation:
work =force *distance
250*6=1500
In humans, normal color perception (N) dominates the expression of color blindness (n), and both of these genes are carried on the X chromosome (XN or Xn). A woman with normal color vision has a color-blind father. Her husband is also color-blind.
a. What is the genotype of the colorblind man? ____
b. What is the genotype of the woman? ______
c. What is the probability of her daughter to be colorblind? __________%
d. What is the probability of her sons to be colorblind? _________%
CAN SOMEONE HELP MEEE eeee
If a DNA strand contains 12% thymine, it also contains ____
a. 12% A, 38% G, 38% C
b. 12% A, 12% G, 38% C
c. 12% A, 12% G, 12% C
d. 38% A, 12% G, 38% C
Answer:
If G = 14, then C = 14 and G + C is 28. Thus A + T. The percent of adenine in a double-stranded DNA is 38. Therefore G + C = 100 - 76 = 24, and C = 24/2 = 12 percent.
Explanation:
The Waldorf family was caught in a fire but escaped. Unfortunately, the father and daughter suffered burns. The father had second-degree burns on his entire chest, abdomen, and both arms, and third-degree burns on his entire left lower extremity. The daughter suffered first-degree burns on her whole head and neck and second-degree burns throughout both lower extremities.
a. What percentage of the father's body was covered by burns?
b. What percentage of the daughter's body received first-degree burns?
c. What part of the daughter's body has both the dermis and epidermis involved?
d. The father experiences a good deal of pain in the area of the chest and abdomen, but little pain in the leg. Why?
Answer and Explanation:
The father had 54% of the body covered by burns, since a little more than half of his body was burned. In addition, to calculate the percentage of body burn, the following values are considered: head, arms and legs - 9% torso front - 18% torso back - 18%. In addition, the father feels little pain in his legs (which had worse burns) because the third degree burn destroys the nerve endings, while the second degree burn only damages these endings promoting intense pain.
The daughter had 9% of her body burned by first degree burns, which corresponds to her lower limbs. These burns involve the skin and the epidermis, for this reason, we can say that the legs are the part of the daughter's body that has compromised hair and epidermis.
How can humans reduce
the impact of a storm surge?
Explanation:
reducing the impact Global climate change may result in increased storm surge flooding in some areas, through intensification of the cyclones driving the storm surges and as a result of sea level rise. Mangroves can reduce storm surge water levels by slowing the flow of water and reducing surface waves.
Which sequence of events best describes the current theory of the origin of life on Earth?
Answer:
yes
Explanation: