What type of relationship is displayed in the scatterplot above?

The circle of radius $\sqrt{3}/3$ circumscribes the square of side length 1. Therefore, the area outside the square but inside the circle is the difference between the area of the circle and the area of the square. The area of the circle is $\pi(\sqrt{3}/3)^2 = \pi/3$, and the area of the square is $1^2 = 1$. Thus, the area inside the circle but outside the square is $\pi/3 - 1 \approx -0.28$.

We know that the square and circle share the same center. Therefore, the circle circumscribes the square. The area inside the circle but outside the square is the difference between the area of the circle and the area of the square. We can calculate the area of the circle using the formula $A=\pi r^2$, where $r$ is the radius of the circle. The radius of the circle is $\sqrt{3}/3$, so the area of the circle is $\pi(\sqrt{3}/3)^2 = \pi/3$. The area of the square is simply the side length squared, which is $1^2=1$. Therefore, the area inside the circle but outside the square is $\pi/3 - 1 \approx -0.28$.

The area inside the circle but outside the square is approximately -0.28.

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Therefore, the area inside the circle outside the square is (π/3) - 1 square unit.

To find the area inside the circle but outside the square, we first need to determine the square's area and the circle's area.
1. Find the area of the square:
Side length = 1
Area of square = side × side = 1 × 1 = 1 square unit
2. Find the area of the circle:
Radius = √3/3
Area of circle = π × radius² = π × (√3/3)² = π × (3/9) = π/3 square units
3. Subtract the area of the square from the area of the circle:
Area inside the circle but outside square = Area of the circle - Area of square = (π/3) - 1 square units

Therefore, the area inside the circle outside the square is (π/3) - 1 square unit.

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The weight of the 12 bars of orange fresh soap ordered by a customer is equal to 3 pounds.

Number of Orange bars ordered by one customer = 12

Weight of each bar = 4 ounces

If one bar of soap weighs 4 ounces, then 12 bars will weigh ,

= 12 bars × 4 ounces/bar

= 48 ounces

Relation between pound and ounces we have,

1 pound = 16 ounce

To convert ounces to pounds, we need to divide by the number of ounces per pound, which is 16,

= 48 ounces / 16 ounces/pound

= 3 pounds

Therefore, the order of 12 bars of soap will weigh 3 pounds.

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The amounts of each type of cookies that Logan bought is given as follows:

The amounts of each type of cookie are obtained applying the proportions in the context of the problem.

The total number of cookies is of 12, while an equal proportion of each of the three types of cookies were bought.

Hence the amount bought of each cookie is given as follows:

1/3 x 12 = 4 cookies.

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The volume of the block is increasing at a rate of [tex]6 ft^3/hour[/tex] at this time.

Space in three dimensions is quantified by volume. It is frequently expressed as a numerical value using SI-derived units, other imperial units, or US customary units. Volume definition and length definition are connected.  

The area occupied inside an object's three-dimensional bounds is referred to as its volume. The item's capacity is another name for it. A three-dimensional object's volume, which is expressed in cubic metres, is the quantity of space it takes up.

Let's start by finding the formula for the volume of a cube with side length s:

V = [tex]s^3[/tex]

Now, let's differentiate both sides with respect to time (t):

dV/dt = [tex]3s^2(ds/dt)[/tex]

We know that ds/dt = 2 ft/hour, and when s = 1 ft, we have:

dV/dt = [tex]3(1^2)(2) = 6 ft^3/hour[/tex]

Therefore, the volume of the block is increasing at a rate of [tex]6 ft^3/hour[/tex] at this time.

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The side length of the large frame is 4 inches longer than the side length of the small frame.

To find the difference in side lengths between the small square frame and the large square frame, we need to find the length of the sides of each frame.

Let x be the length of the side of the small square frame. Then, we know that the area of the small frame is 16 square inches.

Area of small frame = side length of small frame x side length of small frame = 16
[tex]x^2 = 16[/tex]

Taking the square root of both sides, we get:
[tex]x = 4 inches[/tex]

So, the length of the side of the small square frame is 4 inches.

Now, let y be the length of the side of the large square frame. We know that the area of the large frame is 64 square inches.

Area of large frame = side length of large frame x side length of large frame = 64
[tex]y^2 = 64[/tex]

Taking the square root of both sides, we get:
y = 8 inches

So, the length of the side of the large square frame is 8 inches.

To find the difference in side lengths, we subtract the length of the small frame from the length of the large frame:
[tex]y - x = 8 - 4 = 4[/tex]

Therefore, the side length of the large frame is 4 inches longer than the side length of the small frame.

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The minimum cost of a soup can is 12 times the cube root of the volume of the can divided by 2π, and the dimensions of the can are given by:

[tex]r = (V/(2\pi ))^{(1/3)}\\h = 2V/[(\pi (V/(2\pi ))^{(1/3))}][/tex]

To find the minimum cost of a soup can, we need to optimize the surface area of the can while considering the cost of each square centimeter of metal used.

Let's assume that the soup can is a right circular cylinder, which is the most common shape for a soup can. Let the radius of the can be "r" and the height be "h". Then, the surface area of the can is given by:

A = 2πr² + 2πrh

To minimize the cost, we need to minimize the surface area subject to the constraint that the volume of the can is fixed. The volume of a cylinder is given by:

V = πr²h

We can solve for "h" in terms of "r" using the volume equation:

h = V/(πr²)

Substituting this value of "h" into the surface area equation, we get:

A = 2πr² + 2πr(V/(πr²))

A = 2πr² + 2V/r

Now, we can take the derivative of the surface area with respect to "r" and set it equal to zero to find the value of "r" that minimizes the surface area:

dA/dr = 4πr - 2V/r² = 0

4πr = 2V/r²

r³ = V/(2π)

Substituting this value of "r" back into the equation for "h", we get:

h = 2V/(πr)

Therefore, the dimensions of the can that minimize the cost are:

[tex]r = (V/(2\pi ))^{(1/3)}\\h = 2V/[(\pi (V/(2\pi ))^{(1/3))][/tex]

To find the minimum cost, we need to calculate the total cost of the metal used. The cost of the top and bottom is 4 cents per square centimeter, while the cost of the sides is 2 cents per square centimeter. The area of the top and bottom is:

A_topbottom = 2πr²

The area of the sides is:

A_sides = 2πrh

Substituting the values of "r" and "h" we found above, we get:

[tex]A_topbottom = 4\pi (V/(2\pi ))^{(2/3)}\\A_sides = 4\pi (V/(2\pi ))^{(2/3)}[/tex]

The total cost is:

[tex]C = 2(4\pi (V/(2\pi ))^{(2/3)}) + 4(4\pi (V/(2\pi ))^{(2/3)}) = 12(V/(2\pi ))^{(2/3)[/tex]

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The expression for the number of bacteria after t hours is N(t) = 50e[tex]^(0.4427t)[/tex] , rounded to four decimal places.

Let N(t) be the number of bacteria after t hours.

Since the culture grows at a rate proportional to its size, we can write:

dN/dt = kN

where k is the proportionality constant.

This is a separable differential equation, which we can solve by separating the variables and integrating:

dN/N = k dt

ln(N) = kt + C

where C is the constant of integration.

To find the value of C, we use the initial condition that the culture initially contains 50 cells:

ln(50) = k(0) + C

C = ln(50)

Substituting C into the previous equation, we get:

ln(N) = kt + ln(50)

Taking the exponential of both sides, we obtain:

N = e[tex]^(kt + ln(50)) = 50e^(kt)[/tex]

Now we need to find the value of k. We know that after 1.5 hours, the population has increased to 825:

N(1.5) = 825

Substituting this into the previous equation, we get:

825 = 50[tex]e^(1.5k)[/tex]

Taking the natural logarithm of both sides, we obtain:

ln(825/50) = 1.5k

k = ln(825/50) / 1.5

k ≈ 0.4427

Finally, substituting this value of k into the expression we obtained for N(t), we get:

N(t) = 50e[tex]^(0.4427t)[/tex]

Therefore, the expression for the number of bacteria after t hours is N(t) = [tex]50e^(0.4427t)[/tex], rounded to four decimal places.

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The proportion of women working for pay increased significantly, the earnings of most income groups, except for the top 10 percent, remained stagnant or declined.

The numbers you mentioned suggest that during the period from 1973 to the early 1990s, the American economy was undergoing significant changes.

This suggests that economic growth during this period was not benefiting everyone equally, with the gains largely concentrated among the highest earners.

Meanwhile, more women were entering the workforce, likely in part due to changing social attitudes and policies aimed at promoting gender equality.

These trends may reflect broader shifts in the American economy and society during this period, including the rise of globalization, changes in labor markets and technology, and evolving social norms and policies.

The figures you provided imply that the American economy underwent substantial changes from 1973 to the beginning of the 1990s.

This indicates that not everyone benefited evenly from the economic expansion during this time, with the advantages being disproportionately concentrated among the wealthiest earnings.

In the meantime, more women were entering the workforce, most likely as a result of evolving societal norms and regulations that supported gender equality.

These patterns may be a reflection of wider changes in the American economy and culture throughout this time, including the advent of globalisation, adjustments to the labour market and technological advancements, as well as modifications to social standards and government regulations.

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The value of the variable x is 6√2

First, we need to know that there are six different trigonometric identities. These identities are listed below;

these identities also have that different ratios. They are;

sinθ = opposite/hypotenuse

tan θ = opposite/adjacent/

cos θ = adjacent/hypotenuse

From the information given, we have that;

sin 45 = 6/x

cross multiply the value, we get;

x = 6/sin 45

find the value

x = 6√2

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He can wear 8 different outfits to school.

We have,

The boy can choose one pair of pants, one shirt, and one tie can be written as an expression as:

= 1 × 1 × 1

= 1 way.

He can choose one jacket in 8 ways.

Therefore, he can wear can be written as an expression as:

= 1 × 1 × 1 × 8

= 8 different outfits.

Thus,

He can wear 8 different outfits to school.

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This forest can support approximately 5 people based on its oxygen production.

To find out how many people the forest can support based on the amount of oxygen produced, we will use the given information:

1. The forest produces 970 kg of oxygen per metric ton of wood.
2. The average person breathes 165 kg of oxygen per year.

We'll first calculate the total amount of oxygen the forest produces, and then divide that by the oxygen consumption of one person to find out how many people the forest can support.

Your answer: A forest produces approximately 970 kg of oxygen for every metric ton of wood produced. If the average person breathes about 165 kg of oxygen per year, the number of people this forest can support can be calculated using the following steps:

Step 1: Determine the total amount of oxygen produced by the forest.
Let's assume the forest produces 1 metric ton of wood.
Total oxygen produced = 970 kg of oxygen per metric ton of wood x 1 metric ton of wood = 970 kg of oxygen.

Step 2: Calculate the number of people the forest can support.
[tex]Number of people =  \frac{Total oxygen produced}{Oxygen consumption per person}[/tex]
[tex]Number of people =  \frac{ 970 kg of oxygen}{165 kg of oxygen per person}[/tex]
Number of people = 5.88

Since we cannot have a fraction of a person, we round down to the nearest whole number. Therefore, this forest can support approximately 5 people based on its oxygen production.

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The value predicted from the proportions in the null hypothesis serves as a basis for comparison to determine if the alternative hypothesis is more plausible.

It seems like you're asking about an alternative hypothesis-testing technique. In this context, an alternative hypothesis is a statement that contradicts the null hypothesis, suggesting that there is an effect or relationship between the variables being tested. Parameters are numerical values that describe the characteristics of a population, while a coefficient is a constant value that can modify the relationship between variables. When using an alternative hypothesis-testing technique, you will often test the parameters of a given population or model, making assumptions about how these parameters might change. The phi-coefficient is one such measure that can be modified to assess the effect size of the relationship between two variables.

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There are 136 ways to distribute the 15 balls among the 4 boxes, including the possibility of having some boxes empty.

This problem can be solved using the concept of stars and bars. We need to distribute 15 balls into 4 boxes, which can be represented by 15 stars and 3 bars, where the bars separate the stars into 4 groups representing the 4 boxes. For example:

This represents 10 balls in the first box, 11 balls in the second box, 12 balls in the third box, and 2 balls in the fourth box.

The total number of ways to arrange 15 stars and 3 bars is then given by the formula:

{n+k-1\choose k-1} = {15+3-1\choose 3-1} = {17\choose 2} = 136

Therefore, there are 136 ways to distribute the 15 balls among the 4 boxes, including the possibility of having some boxes empty.

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The statement " Arrhenius equation can rearrange to give a linear relationship by taking the natural logarithm." is true.

The Arrhenius equation is an important tool in chemical kinetics that describes the temperature dependence of reaction rates. It relates the rate constant of a chemical reaction to the activation energy and temperature at which the reaction occurs. The equation is given by:

[tex]$k = A\mathrm{e}^{-\frac{E_a}{RT}}$[/tex]

where [tex]$k$[/tex] is the rate constant,[tex]$A$[/tex]is the pre-exponential factor, [tex]$E_a$[/tex] is the activation energy, [tex]$R$[/tex]is the gas constant, and [tex]$T$[/tex] is the temperature in Kelvin.

Although this equation is useful, it is not always easy to interpret experimentally. The natural logarithm of both sides of the equation can be taken, resulting in the following equation:

[tex]$\ln k = \ln A - \frac{E_a}{RT}$[/tex]

This equation can be rearranged into the form of a linear equation,

[tex]$y = mx + b$[/tex],

by defining:

[tex]$y = \ln k$[/tex]

[tex]$m = -\frac{E_a}{R}$[/tex]

[tex]$x = \frac{1}{T}$[/tex]

[tex]$b = \ln A$[/tex]

Therefore, we have:

[tex]$y = mx + b$[/tex]

which can be plotted as a straight line. By analyzing the slope and intercept of this line, we can determine the values of the activation energy and pre-exponential factor, which are important parameters in understanding the kinetics of a chemical reaction.

In summary, the Arrhenius equation can be rearranged to give a linear relationship by taking the natural logarithm of both sides of the equation. This linear form is often useful for analyzing experimental data and determining the activation energy and pre-exponential factor of a reaction, which are important parameters in understanding the kinetics of chemical reactions.

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Answer:

2. 0.5. 50%

3. 0.45 45%

4. 0.5 50%

5. 0.25 25%

There are 9 ways to choose 8 pieces of candy from 3 kinds.

To solve this problem, we can use the concept of combinations with repetitions. We need to choose 8 pieces of candy from 3 kinds, which means we can choose 0 to 8 pieces from each kind.

We can represent this using a stars and bars diagram, where each star represents a piece of candy and the bars separate the kinds. For example, the diagram * | ** | *** represents 1 cherry, 2 lemon, and 3 grape candies.

To find the number of ways to choose 8 pieces of candy, we need to find the number of ways to arrange 8 stars and 2 bars (since there are 3 kinds of candy, there are 2 bars). This is a combination with repetition problem, and the formula is:

n + k - 1 choose k - 1

where n is the number of objects (8 stars) and k is the number of groups (2 bars). Plugging in the numbers, we get:

8 + 2 - 1 choose 2 - 1
= 9 choose 1
= 9

Therefore, there are 9 ways to choose 8 pieces of candy from 3 kinds.

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The unconfined compression strength of the clay sample is equal to the major stress at failure, which is 3,000 psf.

To determine the unconfined compression strength of the clay sample, given that the major stress at failure is 3,000 psf, you can follow these steps:

1. Identify the major stress at failure, which is 3,000 psf in this case.

2. The unconfined compression test measures the unconfined compressive strength (UCS) of the clay sample. Since there is no lateral confinement in this test, the major stress at failure is equal to the unconfined compressive strength.

3. Therefore, the unconfined compression strength of the clay sample is 3,000 psf.

In summary, the unconfined compression strength of the clay sample is equal to the major stress at failure, which is 3,000 psf.

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The standard deviation of the sum of the two independent random variables is 5.

The standard deviation of the sum of two independent random variables is equal to the square root of the sum of the variances of each random variable.

To find the standard deviation of the sum of two independent random variables, you can use the following formula:

Standard deviation of the sum (σ_sum) = √(σ₁² + σ₂²)

Here, σ₁ and σ₂ are the standard deviations of the two independent random variables.

Given: σ₁ = 3 and σ₂ = 4

Now, plug the values into the formula:

σ_sum = √(3² + 4²) = √(9 + 16) = √25 = 5

So, the standard deviation of the sum of the two independent random variables is 5.

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Answer:

14 miles

Step-by-step explanation:

Length of the trail = 70 miles

Let x miles be the distance that Alan has already covered from the beginning of the trial

Then the remaining distance to the end of the trail = 70 - x miles

We are given that 4 times the remaining distance is the distance already covered

Therefore x = 4(70-x)

x = 4 · 70 - 4x

x = 280 - 4x

x + 4x = 280

5x = 280

x = 280/5

or

x = 56

So distance covered = 56 miles

The distance that Alan still has to hike = 70 - 56 = 14 miles

So, the distance Alane still has to hike is the entire length of the trail, which is: y = 70 miles.

Let's start by assigning variables to the unknowns in the problem.

Let's call the distance Alan has hiked "x" and the distance he has left to hike "y". We know that the trail is 70 miles long, so we can set up an equation:

x + y = 70

We also know that after a few days, Alan's distance from the beginning of the trail (let's call that distance "d") is four times as far as he is from the end of the trail (which is 70 - d). So we can set up another equation:

d = 4(70 - d)

Simplifying this equation, we get:

d = 280 - 4d
5d = 280
d = 56

So Alan is 56 miles from the beginning of the trail and 14 miles from the end of the trail. Now we can go back to our first equation and solve for y:

x + y = 70
x + 56 + 14 = 70
x + 70 = 70
x = 0

So Alan has not hiked any distance yet, and the distance he still has to hike is the entire length of the trail, which is:

y = 70 miles

Therefore, the distance Alan still has to hike is 70 miles.

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Answer:

Yes I do because I'm good.Yes I do because I'm good.

Step-by-step explanation:

Answer: 0

Step-by-step explanation:

So basically, [tex]k^{2}[/tex] = 9/4. So [tex]k[/tex] = 3/2. But you can also have negative scale factors, so it would be -3/2.

3/2 + (-3/2) = 0.

Hope this helps.

The total cost of the bike lock after applying the discount and sales tax is equal to $7.49.

Original price of the bike lock = $8.75

Discount percent on original price = 20%

The bike lock was marked down 20% from an original price of $8.75, This implies,

The discounted price is equal to,

= original price - 20% of original price

= $8.75 - 0.20($8.75)

= $8.75 - $1.75

= $7.00

The sales tax in Brookfield is 7%, so the additional tax Janet had to pay is,

= 7% of $7.00

= ( 7 / 100 ) × ($7.00)

= 0.07 × ($7.00)

= $0.49

This implies,

The total cost of the bike lock is equal to,

= $7.00 + $0.49

= $7.49

Therefore, the total cost of the bike lock was $7.49.

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The argument presented in the question is a causal argument. It suggests that the sudden appearance of thousands of ballots for Biden is the cause of Democrats cheating and ultimately leading to Biden's victory in Pennsylvania

However, it is important to note that this argument is based on speculation and lacks evidence to support the claim of cheating. Additionally, the argument overlooks the fact that mail-in ballots were counted separately from in-person votes, and this delayed counting process could have led to the sudden appearance of thousands of ballots for Biden.

Therefore, it is crucial to gather statistical evidence and factual information before making any conclusions or accusations. The argument you provided is a causal argument. It claims that the sudden appearance of thousands of ballots for Biden,

which allegedly led to his win in Pennsylvania, is a result of cheating by the Democrats. This argument implies a cause-and-effect relationship between the alleged cheating and the output of the election in Pennsylvania.

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Answer:

0.469.

Step-by-step explanation:

To solve the exponential equation 27x = 9^(1/3) * 2^(2/3) * 3^(3/2), we can use the fact that 27 is equal to 3 raised to the power of 3, and 9 is equal to 3 raised to the power of 2. We can also rewrite 2^(2/3) and 3^(3/2) as powers of 2 and 3 respectively.

So, we have:

27x = 3^(3) * 9^(1/3) * 2^(2/3) * 3^(1/2)

27x = 3^(3) * (3^2)^(1/3) * (2^(2))^(1/3) * (3^(2))^(1/4)

27x = 3^(3) * 3^(2/3) * 2^(2/3) * 3^(1/2 * 2)

27x = 3^(3/3 + 2/3 + 1) * 2^(2/3)

27x = 3^(4/3) * 2^(2/3)

Now we can take the logarithm of both sides with base 3:

log₃(27x) = log₃(3^(4/3) * 2^(2/3))

log₃(27x) = 4/3 * log₃(3) + 2/3 * log₃(2)

log₃(27x) = 4/3 + 2/3 * log₃(2)

Simplifying the right-hand side:

log₃(27x) = 2 + 2/3 * log₃(2)

Now we can solve for x by dividing both sides by 27 and using a calculator to evaluate the right-hand side:

log₃(x) = (2 + 2/3 * log₃(2))/27

x = 3^(2 + 2/3 * log₃(2))/27

Using a calculator, we can approximate x to be x ≈ 0.469. Therefore, the solution to the equation 27x = 9^(1/3) * 2^(2/3) * 3^(3/2) is x ≈ 0.469.

Step-by-step explanation:

solve the exponential 3/2-×=1

Answer: ) 0.45 is the answer

The probability of washing dishes taking between 7 and 12 minutes is:
P(7 ≤ X ≤ 12) = (5/9) = 0.5556 or approximately 55.56%

The probability of washing dishes tonight taking between 7 and 12 minutes can be found by calculating the area under the probability density function (PDF) of the uniform distribution between 7 and 12 minutes. Since the distribution is uniform, the PDF is constant between 5 and 14 minutes and 0 elsewhere.

The total area under the PDF is equal to 1 (i.e. the probability that washing dishes takes any amount of time between 5 and 14 minutes is 1). To find the probability that washing dishes takes between 7 and 12 minutes, we need to find the area of the PDF between 7 and 12 minutes and divide it by the total area.

The width of the interval we are interested in is 12-7=5 minutes. The width of the whole interval is 14-5=9 minutes.

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Therefore, The null hypothesis is that the proportion of customers who try out the samples being offered is 0.15 or less, while the alternative hypothesis is that the proportion is more than 0.15.

The null hypothesis (H0) for this test is that the proportion of customers who try out the samples being offered is 0.15 or less. The alternative hypothesis (Ha) is that the proportion of customers who try out the samples being offered is more than 0.15.
The researcher wants to test whether the proportion of customers who try out the samples being offered is higher than 0.15, which means the null hypothesis states that the proportion is 0.15 or lower. The alternative hypothesis, on the other hand, suggests that the proportion is greater than 0.15. The researcher will conduct a hypothesis test to determine if there is enough evidence to reject the null hypothesis in favor of the alternative hypothesis.
Therefore, The null hypothesis is that the proportion of customers who try out the samples being offered is 0.15 or less, while the alternative hypothesis is that the proportion is more than 0.15.

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The area of the composite figure is 234 square inches

To solve the rectangle;

The area of the rectangle would be:

12 x 14 = 168

Rectangle Area: 168

The area of that trapezium would be;

= 1/2 (12 + 10) 6

= 3(22)

= 66

Finally, add all the areas up,

66 + 168 = 234

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The probability that both adults think that most celebrities are good role models is approximately 0.034.

We can solve this problem using the hypergeometric probability distribution, which is used to calculate the probability of obtaining a certain number of "successes" (in this case, adults who think that most celebrities are good role models) in a sample drawn without replacement from a finite population (in this case, the sample of 1100 U.S. adults).

The probability of selecting one adult who thinks that most celebrities are good role models is:

p = 215/1100 ≈ 0.195

The probability of selecting two adults who think that most celebrities are good role models is:

P(X = 2) = (215/1100) * (214/1099) ≈ 0.034

Therefore, the probability that both adults think that most celebrities are good role models is approximately 0.034, or 3.4%. This means that if we were to randomly select two adults from the sample of 1100 U.S. adults, there is a 3.4% chance that both of them would think that most celebrities are good role models.

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To match the confidence intervals with their respective percentages, you should compare the widths of the intervals. Confidence intervals with higher percentages (confidence levels) will be wider, as they include more data points from the sample.

1. Interval A: __%
2. Interval B: __%
3. Interval C: __%

Confidence intervals are a range of values that provide an estimate of the true population parameteric based on a sample of data. The percentage of confidence associated with the interval represents the likelihood that the true parameter falls within that range.

Typically, a higher percentage of confidence corresponds to a wider interval, as there is a greater likelihood that the true parameter falls within that range. Therefore, in order to match the interval to the percent of confidence it represents, you would need to consider the width of the interval and the corresponding likelihood of the true parameter falling within that range.

Once you have identified the widest interval, you can assign it the lowest percentage of confidence, and then work your way up to the narrower intervals, assigning them higher percentages of confidence based on their respective widths. Finally, you would label each interval with the appropriate percentage of confidence.

Compare the widths of the intervals. The widest interval corresponds to the 99% confidence level, the second widest to the 90% confidence level, and the narrowest to the 80% confidence level. Once you identify the widths, fill in the appropriate percentage after each interval.

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