What is the x to help me

since the diameter is 66 cm, then its radius is half that or 33 cm.

[tex]\textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=33\\ \underset{complete~turn}{\theta =2\pi ~\hfill } \end{cases}\implies s=(33)(2\pi )\implies s=66\pi \implies s\approx 207.34~cm[/tex]

4) -0.3 = -1/3 < -1/7 since the bigger a negative number is the less positive it is. 1/8 is positive so it is clear that it should be placed last. & thus do all options this way.

5) B

Area of a triangle = ½ bh.

where b = base &

h = height.

Area of outer shape = (½ x 16 x 12) in^2.

= 96 in^2.

Area of unshaded inner shape = (½ x 3 x 4) in^2.

= 6 in^2.

Area of shaded region = (96 – 6) in^2.

= 90 in^2.

Step-by-step explanation:

3 blue

4 red

2 yellow

in total 9 marbles.

when looking at the 3 blue marbles that leaves 9-3 = 6 others (red and yellow).

so, the ratio is

3:6 = 1:2

remember, a ratio is a fraction and follows the same rules of calculation, simplification, ...

Answer:

$10/hour

Step-by-step explanation:

Solving

Take two points and find slope

Slope

Pay rate 10$/h

Answer: Answer:

A. is your answer

When using the Slope Method, your answer is y - 5 = 4(x - 2).

Feel free to give brainliest.

Have a great day everyone!

Use the slope formula and pick any two points  to find the slope.

m= Y2- Y1/x2-x1

I picked the points (1,8) (3,14).

14-8/3-1= 6/2= 3

Hope this helps .

[tex]\dfrac{3a^2-6a+3}{a^2-1}\\\\=\dfrac{3(a^2 -2a+1)}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)^2}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)}{a+1}\\\\=\dfrac{3a-3}{a+1} ~~~\text{for}~ a\neq 1[/tex]

This being a piecewise function, trying to solve f(2), we must find which two equations we can use.

We can use the function '3x + 1' because its domain is 'x is greater than or equal to 2

   --> f(2) = 3(2) + 1 = 7

Hope that helps!

Step-by-step explanation:

Successive magnification:

In this process, we use to represent real numbers and visualize them on the number line such as by the magnifying glass, due to this we refer it as successive magnification.

Answer:

x⁴ - 8x² + 9

Step-by-step explanation:

The Area of the smallest square is A1 = x . x = x²

The Area of the second square is A2 = ( x² - 3 )(x² - 3)

A2 = x⁴ - 3x² - 3x² + 9

A2 = x⁴ - 6x² + 9

The Area of the Shaded shape is A2 - A1

x⁴ - 6x² + 9 - x²

x⁴ - 8x² + 9

The equations that has a leading coefficient of 3, and a constant of -2 are:

0 = 3x² + 2x – 2

0 = –3x + 3x² – 2

0 = –1x – 2 + 3x²

A leading coefficient is the term that has the highest degree in a polynomial expression.

A constant is a term that has only numbers and contains no variable.

We are given the following equations:

The first, third, and last equations each has a leading coefficient of 3 and a constant of -2.

Therefore, the equations that has a leading coefficient of 3, and a constant of -2 are:

0 = 3x² + 2x – 2

0 = –3x + 3x² – 2

0 = –1x – 2 + 3x²

Learn more about leading coefficient on:

https://brainly.com/question/99237

Answer:

2. |-4| < |-8|

3. |-5| > 1

5. |-2| = |2|

Answer:

2,3,5 are correct

Step-by-step explanation:

i took the test

Answer for first question: x-intercept(s): (92,0)(92,0) y-intercept(s): (0,−95) for second question : x-intercept(s): (23,0)(23,0) y-intercept(s): (0,−12)

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

because 5 is greater than 4

The shop makes 25% profit if the cost price per dress is R280.

Answer:

9*9+40*40=41*41

Step-by-step explanation:

The largest length is always the hypotenuse. If we were to multiply any triple by a constant, this new triple would still represent the sides of a right triangle. Therefore, 6, 8, 10 and 15, 20, 25, among countless others, would represent the sides of a right triangle.

Answer:

Yes. They are proportional.

Step-by-step explanation:

[tex]\frac{56}{72} =\frac{7}{9}[/tex]

[tex]0.777=0.777[/tex]

The left side 0.777 is equal to the right side 0.777, which means that the given statement is always true.

True

The volume of this right prism that has a triangular base is equal to 108 cubic meters.

Mathematically, the volume of a right prism is given by this formula:

V = L x W x H

Where:

Given the following data:

Length of base = 6 meters.

Width of base = 4 meters. cm.

Height of prism = 4.5 meters.

Substituting the given parameters into the formula, we have;

V = 6 x 4 x 5

V = 108 cubic meters.

Read more on volume of prism here: brainly.com/question/3867601

Answer: 54 m³

Step-by-step explanation: proof with more answers

Answer:

False.

Step-by-step explanation:

Because 12 and 9 are both multiples of 3.

Answer:

it should be built at the centre

Answer:

x=11

Step-by-step explanation:

It seems that the two angles are supplementary.  Soo they add up to 180

Thus,

15+15x=180

Solve for x...

15x=165

x=11

Hope this helps!!!

Answer:

Rational

Step-by-step explanation:

A rational number includes any whole number, fraction, or decimal that ends or repeats. An irrational number is any number that cannot be turned into a fraction, so any number that does not fit the definition of a rational number.

Answer:

5(x+2)

Step-by-step explanation:

Answer:

x-y=3

Step-by-step explanation:

Answer:

[tex]x - y = 3[/tex]

is

[tex]y - 3 = (x - 6)[/tex]

in standard form

answer:

(-7; -5)

step by step

ur mom

Step-by-step explanation:

Answer:

$168.75

Step-by-step explanation:

In the morning you'll have a time of about 4 hours.

In the afternoon you'll have 8.5 hours.

You take these and add them together 4 + 8.5 = 12.5

Then you take your sum and multiply it by the wage you make per hour 13.50 x 12.5 = $168.75

Answer:

9 and 18

Step-by-step explanation:

let the numbers be x and 2x

so that x+2x=27

3x=27

x=9

so the numbers are 9 and 18.

I hope this will help

Answer:

[tex] \\ [/tex]

Step-by-step explanation:

It is given that, the sum of two numbers is 27 and one of the number is 2 times as large as the other.

[tex] \\ [/tex]

Let us assume the one number as x and as state in the question, one of the number is 2 times as large as the other (x) . So, the other number will be 2x .

[tex] \\ [/tex]

Now,

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x + 2x = 27 \:}}} \\ \\[/tex]

Adding like terms we get :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad 3x = 27 \:}}} \\ \\[/tex]

Dividing both sides by 3 we get :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad \frac{3x}{3} = \frac{27}{3} \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad {x} = {9} \:}}} \\ \\[/tex]

So,

[tex] \\ [/tex]

Now,

[tex] \\ {\longrightarrow \pmb{\frak {\qquad Other \: number = 2x \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad Other \: number = 2(9) \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad Other \: number = 18 \:}}} \\ \\[/tex]

Therefore,