What is the kind of asexual reproduction

Explanation:

When we take a breath, we pull air into our lungs that contains mostly nitrogen and oxygen. When we exhale, we breathe out mostly carbon dioxide.

Answer:

The correct answer is - A) Evaluating an experiment allows the investigator to find errors and make improvements.

Explanation:

Evaluation is the process in any experiment that helps in improving the analysis and remove missing components and errors to get better results. It also checks if all the process is included and running properly without error.

One should constantly be evaluating his or her experiment. It includes assessing how the experiment is going as you carry it out, what could have been improved if it was to be carried out again and how can eliminate any erros.

The type of RNA that functions as the location where proteins are made would be the rRNA.

rRNAs are known as ribosomal RNAs. They are usually found associated with the ribosome - the organelles responsible for synthesizing proteins in eukaryotic cells.

mRNA is the messenger RNA. They are formed directly from the transcription of DNA in the nucleus and then transported to the cytoplasm. They carry genetic information in coded forms and the codes are translated protein synthesis.

tRNA is the transfer RNA. It carries amino acids and anticodons.

siRNA are small interfering RNA.

More on the RNAs can be found here: https://brainly.com/question/19815744

Answer:

The correct answer is - d)  Connective tissue, smooth muscle, epithelial cells.

Explanation:

The connective tissues are the tissue layers that protect the outside of arteries and veins. The thick outermost layer of a tunica adventitia and other, made of connective tissues.

The middle layer that has tunica media that s made up of outer connective and smooth muscles in the inner or middle and in the innermost layer is made up of epithelial layer.

As per the image given the statements that describe the tissues from the left to right in a microscopic image are connective tissue, smooth muscles, and epithelial cells.

Hence the option D is correct.

Learn more about the statement accurately identifies.

brainly.com/question/23999747.

Answer:

Through this process of natural selection, favorable traits are transmitted through generations. Natural selection can lead to speciation, where one species gives rise to a new and distinctly different species. It is one of the processes that drives evolution and helps to explain the diversity of life on Earth.

Explanation:

Answer:

Case 1 ⇒ Bb   x   bb ⇒ F1 = 50% Bb, black + 50% bb, white

Case 2 ⇒ Bb   x   Bb ⇒ F1 = 75% Black + 25% white

Case 3 ⇒ Bb   x   Bb ⇒ F1 = 25% BB + 50% Bb + 25% bb

            ⇒ Bb   x   bb ⇒ F1 = 50% Bb + 50% bb

Case 4 ⇒  BB   x   BB ⇒ F1 = 100% BB Black

            ⇒ Bb   x   BB ⇒ F1 = 50% BB + 50% Bb = 100% Black

            ⇒ bb   x   BB ⇒ F1 = 100% Bb black

Case 5 ⇒ bb   x   bb ⇒  F1 = 100% bb white

Case 6 ⇒ Bb   x   bb ⇒ F1 = 50% Bb black + 50% bb white

Case 7 ⇒ Bb  x  Bb ⇒ F1 = 75% black + 25% white

Explanation:

Due to technical problems, you will find the complete explanation in the attached files

Answer:

Molecules produced in the nucleus are transported to the cytoplasm via endoplasmic reticulum.

Explanation:

economic importance of mosquito larva are

Mosquito larvae grow by consuming microorganisms such as algae and microbes that decompose decaying plant material. Larval mosquitoes contribute to aquatic food chains by serving as food sources for many predators, including fish and birds.i hope it will help you

Answer:

adenine (A), cytosine (C), guanine (G), and thymine (T)

Answer: The final population of Proteus vulgaris after 6 hours is [tex]3.71\times 10^{6}cells[/tex]

Explanation:

We are given:

Proteus vulgaris divides and doubles every 28 minutes

Total time given = 6 hours = 360 min      (Conversion factor: 1 hr = 60 min)

Number of times Proteus vulgaris doubles in 6 hours = [tex]\frac{360min}{28min}=12.857times[/tex]

Calculating the number of bacteria after 6 hours under ideal conditions:

We are given:

Initial population = 500 cells

Number of times it doubles = 12.857 times

Final Proteus vulgaris population = [tex]500\times 2^{12.857}=3709476.8=3.71\times 10^{6}cells[/tex]

Hence, the final population of Proteus vulgaris after 6 hours is [tex]3.71\times 10^{6}cells[/tex]

Answer:

All plants cells have chlorophyll so there is no problem

Answer:

i don't have that alien eys

you do have

in one word this photo is not clear for my eyes

[tex]1 \sqrt{ \frac{ \frac{24 \frac{ \frac{21150 \sqrt{ \cot( \alpha ) } }{?} }{?} \times \frac{?}{?} \times \frac{?}{?} }{?} }{?} } [/tex]

Answer:

A. The mutant strategy will not be able to increase in numbers in the population under the influence of natural selection.

Explanation:

An evolutionarily stable strategy (EES) can be defined as a strategy that is competitively superior to others strategies and cannot be replaced or invaded by any other strategy through natural selection, resulting in punishment for those who deviate from it. Thus, an EES may confer a higher reproductive/adaptive fitness than alternative strategies when it is adopted by most members of the population. Individuals having an ESS are 'spiteful' because they act not only to increase their payoffs but also to decrease the payoffs of their competitors. An EES is resistant to low levels of mutation when all individuals in the population have the same strategy. In game-theoretical terms, an ESS is a strategy such that if all the members of a population adopt this strategy, then no mutant strategies could invade the population under natural selection. In consequence, when all individuals of a population adopt an EES, mutant phenotypes cannot invade and displace the ESS.

Explanation:

feg3fegrgt✴☝️☝️☝️☝️⛲

Answer:

protein number of collect is a bao nhiêu nếu protein phân tử tổng hợp chứa 100aa, trong mỗi phân tử đều chứa 20aa khác nhau

Explanation:

->1 phân tử chứa đủ 20 aa vậy ta cần 5 protein để tổng hộp thành 100aa

Answer:

B) a minimal medium + sucrose

Explanation:

Suc+ ⇒ can utilize sucrose, so you have to add sucrose to the medium.

Trp+ ⇒ can synthesize tryptophan, so it is not required to add tryptophan to the medium because the cell can produce it.

According to this, to select for suc+ trp+ you have to only add sucrose to the medium. Thus, it will only grow the cells that can utilize sucrose and can synthesize tryptophan.

Therefore, the correct option is: B) a minimal medium + sucrose

Answer:

What is population?

A group of organisms of different species interacting with each other and the environment is called populatin.

Answer:

For the bones of wolves trapped 28,500 years ago, the approximate ratio of carbon-14 to carbon-12, 14C to 12C, will be one part per 32 trillion.

Explanation:

Radioactive isotopes of elements are useful for many purposes. Carbon has three isotopes, carbon-12, carbon-13, and carbon-14. Of these,  carbon-14 is radioactive.

The half-life of an carbon-14 is used to determine the age of fossils in a process known as carbon-dating.

Carbon-14 has a half-life of approximately 5700 years. The half-life being the time for half the amount of the radioactive nuclei present in a radioactive element to decay.

The number of half-lives in 28500 years  = 28500/57000 = 5 half-lives

This means that the original amount of atoms present in the atoms has undergone radiactive decay five times.

The ratio of the original amount of 14C to the present amount of 14C = (1/2)⁵ = 1/32

Ratio of 14C to 12C that will be found in the bones = 1/32 × 1/ 1 trillion = 1/32 trillion.

Therefore, for the bones of wolves trapped 28,500 years ago, the approximate ratio of carbon-14 to carbon-12, 14C to 12C, will be one part per 32 trillion.

Answer:

Fertilization in flowering plants happens through a process called pollination. Pollination occurs when pollen grains from the anther land on a stigma. ... Fertilization occurs when one of the sperm cells fuses with the egg inside of an ovule. After fertilization occurs, each ovule develops into a seed

Answer:

option a

Explanation:

They are ectotherms.

hope it is helpful to you

Ectotherms because they are all cold blooded

Answer:

The Answer is -They are strong enough to lift an entire leaf

Explanation:

Based on the picture of a leaf-cutter ant. The prediction that can be made about leaf-cutter ants is they are strong enough to lift an entire leaf. The correct option is D.

Leaf-cutter ants develop their fungus crop by using leaves as fertilizer. By providing freshly cut leaves, they develop fungal gardens while guarding against pests and molds and removing dead materials. The fungus serves as a food supply for the ant larvae in exchange.

These eager ants may seem to bite off more than they can chew, but in reality, they are capable of carrying leaf fragments that are nearly 50 times heavier than themselves. That's like a person pushing a car around.

Therefore, the correct option is D. they are strong enough to lift an entire leaf.

To learn more about leaf-cutter ants, refer to the link:

https://brainly.com/question/29309882

#SPJ2

Answer:

I believe it is Cholestral

Explanation:

Answer:

The answer is Y

Explanation:

Trust me I've done this before

Answer: The statement is TRUE

Explanation:

HEXOKINASE is an enzyme that catalyzes the phosphorylation of glucose to glucose‑6‑phosphate in glycolysis. The main function of glucose is to provide energy for the tissues. The basic pathway through which energy is gotten from glucose is through GLYCOLYSIS. The glycolytic pathway is made up of enzyme catalyzed reactions that leads to the conversion of glucose to pyruvate in the presence of oxygen or lactate in the absence of oxygen.

The first step in glycolysis is catalyzed by HEXOKINASE, an enzyme with broad specificity that catalyzes the phosphorylation of six-carbon sugars. Hexokinase phosphorylates glucose using ATP as the source of the phosphate, producing glucose-6-phosphate, a more reactive form of glucose.

Therefore the above statement is TRUE.

Answer:

The left column contains structures of the bones that belong to the right column.

a) styloid process - 3) temporal bone

b) infraorbital foramen - 5) maxilla

c) sella turcica - 2) sphenoid bone

d) foramen magnum - 6) occipital bone

e) coronoid process - 4) mandible

f) Crista galli - 1) ethmoid bone

Explanation:

The inferior part of the petrous temporal bone forms the styloid process that allows the stylohyoid, stylopharyngeus, and styloglossus muscles to attach with styloid ligaments.

The infraorbital foramen is the opening of the maxillary bone of the skull

sella turcica is a saddle-like structure in the body of the sphenoid bone of the skull.

The foramen magnum is the lower part of the cranial  foss that allows the connecting brain and spinal cord and it the opening

The coronoid process is shoulder joint as well and required mandibles in the skull to form.

Crista galli arises from ethmoid bone that is thick and midline triangular but smooth process.