what is
A two-column proof

The length of the wire is the perimeter of the wire

The radius of the circle is 1.59 meters

The length of the wire is given as:

L  = 20m

When cut into two pieces, we have:

The circumference of the circle is calculated using:

C = 2πr

So, we have:

2πr = 10

Make r the subject

r = 10/2π

Evaluate the quotient

r = 1.59

Hence, the radius of the circle is 1.59 meters

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Step-by-step explanation:

it clearly says (and also shows it by specifying 4cm × 4cm side lengths) : a square base.

so, all net diagrams not having a square in the middle (but a rectangle or a triangle) are out.

and in fact, all 3 that have a square in the middle, are valid nets that would fold up to the pyramid : the 2nd, 4th and 6th.

YES IS THE ANSWER BECAUSE X=9

AND 11+3=87

Answer:

86.5

Step-by-step explanation:

Length of the string forms the hypotenuse AC of right angle triangle ABC.

C is the kite. A is the hand of the person (or, one end of the string). CB is the perpendicular

(height of the kite) from C on the ground. BC is the horizontal.

Sin 60° CB/AC = √3/2

height = 1.73/2 AC = 0.865 * 100 m = 86.5 m

Answer:

T. Perimeter

Step-by-step explanation:

Answer:

Graphs pairs of numerical data, with one variable on each axis, to look for a relationship between them

Step-by-step explanation:

The scatter diagram graphs pairs of numerical data, with one variable on each axis, to look for a relationship between them. If the variables are correlated, the points will fall along a line or curve. The better the correlation, the tighter the points will hug the line.

Answer:

mean

Step-by-step explanation:

The mean will decrease, in an option of mean, mode, median and range:)

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Area of Triangle is 48 cm² . It's Height is given as 6 cm . And, we have been asked to calculate the Base of Triangle .

For calculating the Base of Triangle , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed{ \sf{ \: Area \: _{Triangle} \: = \: \frac{1}{2} \: \times \: B \: \times \: H \: }} [/tex]

Where ,

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf { Area \: _{Triangle} \: = \: \dfrac{1}{2} \: \times \: Base \: \times \: Height } [/tex]

[tex] \longmapsto \: \: \: \sf {48 \: = \: \dfrac {1}{2} \: \times \: Base \: \times \: 6 } [/tex]

[tex] \longmapsto \: \: \: \sf {48 \: \times \: 2 \: = \: 1 \: \times \: Base \: \times \: 6} [/tex]

[tex] \longmapsto \: \: \: \sf {96 \: = \: 1 \: \times \: Base \: \times \: 6} [/tex]

[tex] \longmapsto \: \: \: \sf {96 \: = \: 6 \: \times \: Base } [/tex]

[tex] \longmapsto \: \: \: \sf {Base \: = \: \dfrac {96}{6} } [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Base \: = \: 16 \: cm}} [/tex]

Hence :-

[tex] \underline {\rule {180pt} {4pt}} [/tex]

A triangle has an area of 48 square centimetres. The height of the triangle is 6 centimetres. What is the base of the triangle ?

[tex] \blue{\boxed{Area \: of \: triangle = \frac{1}{2} \times b \times h}}[/tex]

Where ,

In this question the concept belongs to the areas of two dimensional shapes i.e. how we can find length , breadth or height with the help of given area .

[tex] \longmapsto \: 48 = \frac{1}{2} \times b \times 6[/tex]

Now , transposing 2 to left hand side :

[tex] \longmapsto \: 48 \times 2 = 1 \times b \times 6[/tex]

Now , multiplying 48 with 2 and multiplying b with 1 and 6 :

[tex] \longmapsto \: 96 = 6b[/tex]

Now , transposing 6 to left hand side :

[tex] \longmapsto \: \cancel\frac{96}{6} = b[/tex]

Now , by cancelling them we get :

[tex] \longmapsto \: \red{ \boxed{ \sf{b = 16 \: cm}}}[/tex]

We know that area of triangle is equal to 48 cm². So :

[tex] \rightarrow \: \frac{1}{ \cancel2} \times \cancel{16} \times 6 = 48[/tex]

Now , by cancelling 16 with 2 we get :

[tex] \rightarrow \: 8 \times 6 = 48[/tex]

So , by multiplying we get :

[tex] \rightarrow \: 48 = 48[/tex]

That means :

[tex] \rightarrow \: L.H.S = R.H.S[/tex]

The cost to buy the flooring for Raul's bedroom is $364.65.

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

Actual length of the bedroom = 4 x 3.25 = 13 feet

Actual length of the bedroom = 4 x 2.75 = 11 feet

Area = 143 square feet

Cost = 143 x 2.55 = $364.65

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Answer:

point A is the answers for the question

Step-by-step explanation:

please mark me as brainlest

Answer:

A) 9 and 15.

Step-by-step explanation:

First, let's see what each number's factor is:

A)

9 : 1, 3 & 9

15 : 1, 3, 5 & 15

B)

6 : 1, 2, 3 & 6

10 : 1, 2, 5 & 10

C)

8 : 1, 2, 4 & 8

12 : 1, 2, 3, 4, 6 & 12

Therefore, The number 3 is a common factor of A) 9 and 15.

___

Answer:

No Solution

Step-by-step explanation:

-y = -2x + 8

y = 2x - 8

2x + 8 = 2x - 8

2x - 2x = -8 - 8

0 = -16

No Solution

You can also graph y = 2x + 8 and y = 2x - 8. The slope are the same and so they are parallel

Answer:

20 and 13

Step-by-step explanation:

If one list is 'a' and the other one is 'b' then

a-b = 7 and a+b = 33

a-b+a+b = 7+33

2a = 40

a = 20

Now, 20 - b = 7

-b = -13

b = 13

The volume of the chocolate is the amount of choclate used in the cherries

The amount of chocolate used is 17.24 cubic centimeters

Start by calculating the volume of the cherries using:

V = 4/3 π(D/2)^3

The diameter of the cherry is 2.8 cm.

So, we have:

V = 4/3π(2.8/2)^3

Evaluate

V = 11.49

Next, calculate the volume of the cherry and the chocolate.

V = 4/3π(0.5+2.8/2)^3

V = 28.73

Calculate the difference (d) between both volumes

d = 28.73 - 11.49

d = 17.24

Hence, the amount of chocolate used is 17.24 cubic centimeters

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The car on a Ferris wheel with a radius of 20 feet. travels a distance of 125.6 feet.

In order to determine the distance that the car has travelled, we will use the formula for calculating the circumference of a circle.

C = 2πr

where

r = radius

Therefore,

r is the radius of the fairy wheel

r = 20 ft

C = 2 × 3.14 × 20

C = 40 × 3.14

C = 125.6 ft

This shows that the car on a Ferris wheel with a radius of 20 feet. travels a distance of 125.6 feet

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Step-by-step explanation:

each pack 15 pencil

n* 15= 15n

Answer:

Step-by-step explanation:

The largest number of groups they can be split into and have the same number of boys and girls on each team is 6 groups

Given:

Number of girls = 12

Number of boys = 16

Find the highest common factor of 12 and 16

12 = 1, 2, 4

18 = 1, 2,4

The highest common factor of 12 and 16 is 4

Number of girls in each group = 12/4

= 3 girls

Number of boy in each group = 18/4

= 4.5 boys=5

Therefore, the group can be split into 4 groups to have 3 girls and 5 boys in each group

Answer:

Question 3

Given expression:

[tex]\sf \left(\dfrac{-8}{9} \times \dfrac{1}{-5}\right)+\left(\dfrac{-8}{9} \times \dfrac{-7}{11}\right)[/tex]

Both parentheses share a common term.

To factor out a common term: ab + ac = a(b + c)

[tex]\textsf{Factor out the common term }\dfrac{-8}{9}[/tex]

[tex]\sf \implies\dfrac{-8}{9} \times \left(\dfrac{1}{-5}+\dfrac{-7}{11}\right)[/tex]

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Question 4

To calculate the amount of money Rajni had to begin with, sum the three amounts she spent:

[tex]\sf \implies total=10\frac14+25\frac34+16\frac12[/tex]

As [tex]\sf a\frac{b}{c}=a+\frac{b}{c}[/tex], then:

[tex]\sf \implies 10+\frac14+25+\frac34+16+\frac12[/tex]

Collect and sum the whole numbers:

[tex]\sf \implies (10+25+16)+\frac14+\frac34+\frac12[/tex]

[tex]\sf \implies 51+\frac14+\frac34+\frac12[/tex]

As  [tex]\sf \frac14+\frac34=\frac44=1[/tex], then

[tex]\sf \implies 51+1+\frac12[/tex]

[tex]\sf \implies 52+\frac12[/tex]

[tex]\sf \implies 52\frac12[/tex]

Answer:

Step-by-step explanation:

Holding the perimeter fixed, the shape with greatest area is square ( all sides of the same) length) For your name example a square with a perimeter of 20 cm has sides of 5 cm and area of 5 times 4=20 cm) ^3 hope this helps

Answer:

The first x=4       y=8

Step-by-step explanation:

2x-5 = y-5

x+1 = y-3

  Multiply the second by -2(to eliminate x)

  2x-5 =y-5

 -2x-2= -2y+6

      ADD BOTH

-7 = -y+1

y=8

            PLUG y

x+1 =y-3

x+1 =8-3

x+1=5

x=4

Answer: 64 inches

Step-by-step explanation:

Answer:

True I'm pretty sure. Just check to be sure.

Step-by-step explanation:

Answer:

the quotient of 18 and 3 is 6

Step-by-step explanation:

do the inverse and get 6x3=18

The Pythagorean theorem is the idea that the sum of the two legs which are both squared is equal to the hypotenuse's length squared.

     *look at the image I attached for a better explanation

By looking at the picture, we are missing the leg's length, and by using the Pythagorean theorem, we get the equation

    [tex]?^2+5^2 = 13^2\\?^2 + 25 = 169\\?^2 = 144\\? = 12[/tex]

Thus the missing side length is 12 cm

Hope that helps!

The weight of the third heaviest among the four dogs is 2 kg.

An equation is an expression that shows the relationship between two or more numbers and variables.

The 4 dogs weight is 60 kg with each dog weight been different. The second heaviest dog weighs 28 kg.

Let the heaviest dog be 29 kg, the third heaviest be 2 kg and the fourth be 1 kg.

29 + 28 + 2 + 1 = 60 kg

The weight of the third heaviest among the four dogs is 2 kg.

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Answer:

⠀

Step-by-step explanation:

⠀

We know,

[tex]{\longrightarrow \qquad \boldsymbol{\pmb{Area_{(semicircle)} = \dfrac{1}{2}( \pi {r}^{2} ) }}}[/tex]

⠀

Where,

⠀

Now, Substituting the values in the formula :

⠀

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it \dfrac{1}{2} \times 3.14 \times ({8})^{2} }}}[/tex]

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it \dfrac{1}{ \cancel2} \times 3.14 \times \cancel{64} }}}[/tex]

⠀

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it {1} \times 3.14 \times 32 }}}[/tex]

⠀

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it {1} \times 100.48 }}}[/tex]

⠀

[tex]{\longrightarrow \qquad \boldsymbol{ \pmb{Area_{(semicircle)} \approx \it 100.48 }}}[/tex]

⠀

Therefore,

Answer:

100.48 cm² ( option 2 )

Step-by-step explanation:

Given:-

To find:-

Solution:-

Area of semi-circle :-

[tex] \frac{1}{2} \pi \: r {}^{2} [/tex]

1/2 × 3.14 × 8²

[tex]100.48 \: cm {}^{2} [/tex]

Using the given linear function, it is found that Avery was 7 kilometers above sea level before she started climbing.

A linear function is modeled by:

[tex]y = mx + b[/tex]

In which:

In this problem, her altitude in kilometers after t hours is modeled by:

A(t) = 7 + 1.3t.

The y-intercept is of b = 7, which means that Avery was 7 kilometers above sea level before she started climbing.

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Answer:

Label ELabel E

Step-by-step explanation:

Label ELabel ELabel k