Answer:
total distance dibide by total time
Two particles, with identical positive charges and a separation of 2.65 10-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration 1 whose magnitude is 5.00 103 m/s2, while particle 2 has an acceleration 2 whose magnitude is 7.70 103 m/s2. Particle 1 has a mass of 6.20 10-6 kg. (a) Find the charge on each particle. q1 = C q2 = C (b) Find the mass of particle 2. kg
Answer:
a) [tex]q=4.92*10^{-8} C[/tex]
b) [tex]m=4.026*10^{-6} kg[/tex]
Explanation:
From the question we are told that:
Separation distance [tex]d=2.65*10^{-2} m[/tex]
Acceleration 1 [tex]a_1=5.00*10^3 m/s^2,[/tex]
Acceleration 2 [tex]a_2=7.70*10^3 m/s^2,[/tex]
Mass 1 [tex]m_1=6.20*10^{-6}[/tex]
Generally the equation for Force is mathematically given by
[tex]F=ma[/tex]
For Particle 1
[tex]F=6.2*10^{-6} *5*10^3[/tex]
[tex]F=0.031 N[/tex]
Also
[tex]F=\frac{kq_1*q2}{r^2}[/tex]
Where
[tex]q_1=q_2[/tex]
Therefore
[tex]0.031=\frac{9*10^9*q^2}{(2.65*10^-2)^2}[/tex]
[tex]q=4.92*10^{-8} C[/tex]
b)
Generally the equation for Force is mathematically given by
[tex]F=ma[/tex]
[tex]0.031=7.7*10^3[/tex]
[tex]m=4.026*10^{-6} kg[/tex]
Change the following as indicated in the brackets.
8m (km,cm)
metres to kilometres = 1/1000
8 m ⇒ 0.008 km
metres to centimetres = × 100
8 m ⇒ 800 cm
Answer:
1000m=1km
so, 8m=8/1000 = 0.008km
1m=100cm
so, 8m=8×100=800
Which type of wave causes particles of matter to vibrate in a direction
perpendicular to the direction of its motion?
O A. Sound
B. Transverse
C. Longitudinal
D. Compression
Answer:
C.) Longitudinal
HELPP ILL GIVE BRIANLISG
Answer:
31. Respiratory System
32. Excretory System
33. Nervous System
34. Reproductive system
35. Skeleton System
Explanation:
Hope it helps you.^_^
Answer:
31. Respiratory System
32. Excretory System
33. Circulatory System
34. Reproductive System
35. Muscular and Skeletal System
Explanation:
In 35. you should write both systems since only one of them may give you half the marks.
Also do put your questions on the health section
To change the temperature from kelvin to degree Celsius
TK= ( )⁰C
Answer:
-272.1
Explanation:
1K − 273.15 = -272.1°C
What is measurement ?
Answer:
Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events
Answer:
The comparison of an unknown quantity with a known quantity is called measurement
Number of conducting plates of a multiplate capacitor is 5. The no. Of capacitors is
A.1
B.2
C.3
D.4
(Ans with explanation pls)
Answer:
4 capacitors
Explanation:
Given
[tex]n = 5[/tex] --- conducting plates
Required
The number of capacitor (c)
This is calculated as:
[tex]c = n - 1[/tex]
So, we have:
[tex]c = 5 - 1[/tex]
[tex]c = 4[/tex]
IM SOO CONFUSED PLS HELP!! The mass of the nucleus is approximately EQUAL to the mass number multiplied by ____ Atomic Mass unit.
a. 1
b. 10
c. 100
d. 1000
Answer:
option a.
Explanation:
We can think of an atom as a nucleus (where the protons and neutrons are) and some electrons orbiting it.
We also know that the mass of an electron is a lot smaller than the mass of a proton or the mass of an electron.
So, if all the protons and electrons of an atom are in the nucleus, we know that most of the mass of an atom is in the nucleus of that atom.
Then we define the mass number, which is the total number of protons and neutrons in an atom. Such that the mass of a proton (or a neutron) is almost equal to 1u
Then if we define A as the total number of protons and neutrons, and each one of these weights about 1u
(where u = atomic mass unit)
Then the weight of the nucleus is about A times 1u, or:
A*1u = A atomic mass units.
Then the correct option is:
The mass of the nucleus is approximately EQUAL to the mass number multiplied by __1__ Atomic Mass unit.
option a.
Which power station is the most efficient overall, the normal power station or the combined heat and power station? Give reasons for your answer.
Answer:
Cogeneration is a more efficient use of fuel or heat, because otherwise-wasted heat from electricity generation is put to some productive use. Combined heat and power (CHP) plants recover otherwise wasted thermal energy for heating.
Explanation:
Since energy cannot be created or destroyed, how does it exist?
Answer:
Matter and atoms
Directions. Read and understand each item carefully. Write your answers on the space provided.
1. Create a graphic representation based on the following data tabulated on Table 2 and make an interpretation of
the graph. Make sure to coordinate points correctly and trace line to show motion of the object.
Table 2. The distance travelled by a car in a given time.
(Dudes I need this today, pls answer this correctly)
Answer:
Please find attached the required graph of the data points
The graph can be interpreted as showing that which was at rest starts moving at a constant speed of 2 km/min
Explanation:
The table is presented as follows;
[tex]\begin{array}{lcl}Time \ (min)&& Distance \ (km)\\0&&0\\5&&10\\10&&20\\15&&30\\20&&40\\25&&50\\30&&60\end{array}[/tex]
The graphic representation of the above data can be created by plotting the Time on the x-axis and the Distance on the y-axis on a graph paper
The graph of the data can be created also using a spreadsheet application such as MS Excel by using the Chart function under the Insert menu, after selecting the points input into cells on the spreadsheet as shown in the attached drawing
The distance travelled by the car in a given time is found by obtaining the rate of change of the values of the graph, m, as follows;
[tex]m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
Where (y₁, x₁), and (x₂, y₂) are a pair of chosen points on the given line
When, the chosen points are (y₁, x₁) = (0, 0), and (x₂, y₂) = (30, 60), we get;
[tex]m =\dfrac{60 \, km-0 \, km}{30 \, min-0 \, min} = 2 \, km/min[/tex]
The graph can be interpreted as showing that the rate of change of the distance travelled by the car per unit time which is the speed of the car starting from rest is 2 km/min
Ayyo help a girl out please-
An object is pulled to the right using spring balance. The spring balance reads 20N. The object is moving with constant speed, so the net force acting on it is equal to zero. If we consider that the force of pull and the friction force are the only forces acting on the object, what will be the value of the friction force? Explain.
Answer:
The given details in the question are;
The device with which the object is pulled = A spring balance
The reading on the spring balance as the object is pulled = 20 N = The force with which the object is pulled
The speed with which the object is moving = Constant speed (zero acceleration)
The net force acting on the object = Zero
The forces acting on the object are;
The force of pull and the friction force
Therefore;
The force of pull + The friction force = 0
The force of pull = 20 N
∴ 20 N + The friction force = 0
The friction force = 0 - 20 N = -20N
The magnitude of the friction force = 20 N = The force of pull
(The negative sign in the value of the friction force (-20 N), indicates that the direction of the friction force is opposite to the direction of the force of pull)
Explanation:
who is the father of computer but not Charles Babbage can anyone guess
Answer:
It's Obusively charles Babbage I guess
what is fundamental
Fundamental
forming a necessary base or core; of central importance.
"the protection of fundamental human rights"
In Part l, the independent variable was
Answer:
The independent variable is the variable the experimenter manipulates or changes, and is assumed to have a direct effect on the dependent variable. ... The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.
Cho hai điện tích q1=q2=8.10^-7 C đặt cách nhau 5cm. Xác định cường độ điện trường tại điểm:
a. Cách q1=2cm, q2=3cm
b. Cách q1=5cm, q2=10cm
c. Cách q1=5cm, q2=5cm
d. Cách q1=4cm, q2=3cm
Answer: b
Explanation:
Which type of radiation can reach the furthest?
A. Beta
B. Gamma
C. Alpha
Answer:
B. Gamma
Explanation:
The gamma radiation can travel much farther through air than alpha or beta.
b) A stone floor feels very cold to bare feet in winter, but a carpet in
the same room feels comfortably warm. Why is this?
Answer:
A stone floor feels very cold to bare feet in winter, but a carpet in the same room feels comfortably warm.This is because both the floor and the carpet have the same temperature as both are exposed to the same atmosphere. But the former conducts away the heat from the feet better than the carpet as the latter is a non-conductor. So the feet losing more heat, the floor appears cooler to the feet
Explanation:
Hope it may help you!!
Both actually have same temperature. Our feet are warm. Floor is conductor of heat while carpet is not. When we walk on floor, then floor takes away or conducts the heat from our feet, so we feel cold. While carpet doesn't do that, so we feel warm.
A car accelerates along a straight road from rest to 90 km/h in 5.0 s. A) Find the magnitude of its average acceleration. B) Find the velocity of the car at t = 1.0 s, t = 2.0 s and t = 5.0
Answer:
a) [tex]A=5m/s^2[/tex]
b) [tex]V=25m/s[/tex]
Explanation:
From the question we are told that:
Velocity [tex]v=90km/h=25m/s[/tex]
Time [tex]t=5.0s[/tex]
a)
Generally From Newton's motion equation for Average acceleration is mathematically given by
[tex]A=\frac{V-U}{t}[/tex]
Since its from Rest Therefore
[tex]U=0[/tex]
[tex]A=\frac{25m/s-0}{5s}[/tex]
[tex]A=5m/s^2[/tex]
b)
Generally the equation for Average Velocity is mathematically given by
[tex]V=u+at[/tex]
[tex]AT t=1.0s\\\\V=0+5(1)[/tex]
[tex]V=5m/s[/tex]
[tex]AT t=2.0s\\\\V=0+5(2)[/tex]
[tex]V=10m/s[/tex]
[tex]AT t=5.0s\\\\V=0+5(5)[/tex]
[tex]V=25m/s[/tex]
A particular solid is an excellent conductor of thermal energy. Is it more likely to be a metal or a non-metal?
identification of elements compounds and mixtures from a given table
Answer:
the elements are made up of only one kind of atom, the compounds consist of two or more elements that are chemically combined, and the mixtures are physical combination of two or more substances
(x – 2)² = 5(y + 1), where x and y are measured in centimeters. You need to place a new light bulb in your flashlight. How far away from the vertex of the parabolic mirror should you place the bulb to ensure a perfect beam of light? The bulb should be placed .
Answer:
The coordinates of the point the bulb should be placed is (2, 0.25)
Explanation:
The given equation of a parabola is presented as follows;
(x - 2)² = 5·(y + 1)
The point the bulb should be placed is the focus of the parabolic mirror to ensure a perfect (straight) beam
The general form of the equation of a parabola is (x - h)² = 4·p·(y - k)
The coordinates of the focus of the parabola for p > 0 f = (h, k + p)
By comparison, h = 2, k = -1, and p = 5/4
∴ The coordinates of the focus of the parabola, f = (2, -1 + 5/4) = (2, 0.25)
The coordinates of the point the bulb should be placed is at the focus, f = (2, 0.25).
How do you find the normal line for an incident light ray on a concave mirror?
Draw a line from the outer edge of the curve to the point of contact for the ray.
Draw two lines diagonally from the outer edges of the curve until they intersect each other.
Draw a line from the center of the curve to the point of contact for the ray.
Draw a line perpendicular from the center of the curve to the point of contact for the ray.
Answer:
Try different angles
when a metal ball is heated through 30°c,it volume becomes 1.0018cm^3 if the linear expansivity of the material of the ball is 2.0×10^-5k^-1, calculate its original volume
Answer:
The original volume of the metal sphere is approximately 1 cm³
Explanation:
The given parameters are;
The temperature change of the metal ball, ΔT = 30°C = 30 K
The new volume of the metal ball, V₂ = 1.0018 cm³
The linear expansivity of the material ball, α = 2.0 × 10⁻⁵ K⁻¹
We have;
d₂ = d₁·(1 + α·ΔT)
Where;
d₁ = The original diameter of the metal ball
d₂ = The new diameter of the ball
From the volume of the ball, V₂, we have;
V₂ = 1.0018 cm³ = (4/3)×π×r₂³
Where;
r₂ = The new radius = d₂/2
∴ V₂ = 1.0018 cm³ = (4/3)×π×(d₂/2)³
∴ d₂ = ∛(2³ × 1.0018 cm³/((4/3) × π)) ≈ 1.241445 cm
d₁ = d₂/(1 + α·ΔT)
∴ d₁ ≈ 1.241445 cm/(1 + 2.0 × 10⁻⁵·K × 30 K) ≈ 1.24070058 cm
The original volume of the metal ball, V₁ = (4/3)×π×(d₁/2)³
∴ V₁ = (4/3)×π×(1.24070058/2)³ ≈ 0.99999902845 cm³ ≈ 1 cm³
The original volume of the metal sphere, V₁ ≈ 1 cm³.
Please help with this Physics problem!
Answer:
Explanation:
The equation for Coulomb's Law is
[tex]F=\frac{kq_1q_2}{r^2}[/tex] where k is Coulomb's constant, q1 is one of the charges, q2 is another one of the charges (1 of these has to be the one in question, so we will let that be q2) and r is the distance between them squared.
First thing we are going to do is convert those microCoulombs to Coulombs (C).
q1: [tex]-53.0\mu C*\frac{.000001C}{1\mu C}=-5.3*10^{-5}C[/tex] and
q2: [tex]105\mu C*\frac{.000001C}{1\mu C}=1.05*10^{-4}C[/tex] and
q3: our main particle that we will put in for q2 in the formula converts as follows:
q3: [tex]-88.0\mu C*\frac{.000001C}{1\mu C} =-8.8*10^{-5}C[/tex]
First we will find the charge between q1 and the main particle:
[tex]F_1=\frac{(9.0*10^9)(5.3*10^{-5})(8.8*10^{-5})}{(1.45)^2}[/tex] Notice that we did not use the negative charges here. We take the negative charge into account depending upon whether or not the charges are repelled or attracted. Both of these charges are negative, so they will repel and the answer will be made negative. Finding the first force:
[tex]F_1=-2.0*10^1N[/tex] (negative because they repel so q1 will move away from the charge in question, which is also negative)
[tex]F_2=\frac{(9.0*10^9)(1.05*10^{-4})(8.8*10^{-5})}{(.95)^2}[/tex] and the charge between these is
[tex]F_2=92N[/tex] and that is to the right, so positive. These charges are opposite, so they attract. The net force is the sum of the forces, so:
[tex]F_1+F_2:[/tex] -2.0 × 10¹ + 92 = 72N (to the right)
The resistance of a coil is 4.2 ohm at 100 degree centigrade and the temperature coefficient of resistance of its material is 0.004 per degree centigrade. Its resistance at 0 degree centigrade
Answer:
3 ohms
Explanation:
Applying,
R₁₀₀ = R₀(1+αΔT).............. Equation 1
Where α = coefficient of resistance, ΔT = change in temperature, R₁₀₀ and R₀ = Resistance at 100°C and 0°C respectively
make R' the subject of the equation
R₀ = R₁₀₀/(1+αΔT).............. Equation 2
From the question,
Given: R₁₀₀ = 4.2 ohm, α = 0.004 per degree, ΔT = 100-0 = 100°C
Substitute these values into equation 2
R₀ = 4.2(1+0.004×100)
R₀ = 4.2/1.4
R₀ = 3 ohms
what is the meaning of physics
Answer:
physics is the study of functions, systems and and the explainable reasons why they do what they do.
Answer:
physics is the branch of science concerned with the nature and properties of matter and energy. it includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.
Calculate the relative density of the liquid if mass of empty relative density bottle is 24.5g and mass of relative density bottle filled with water is 56.2g and mass of relative density bottle filled with liquid is 51.2g
Answer:
k=0.84
Explanation:
Relative density of liquid is given by:
k=(56.2−24.5)(51.2−24.5)
k=31.726.7
k=0.84
In which of these media will mechanical waves travel the slowest in?
a Plastic
b Butter
C Ice
d Air
e Steel
Answer:
E
Explanation:
it has more mass
The medium in which mechanical waves will travel the slowest in is air which is gaseous medium.
What is mechanical wave?A mechanical wave is a type of wave that requires material medium for its propagation.
An example of mechanical wave is sound wave because sound wave requires material medium for its propagation.
Sound waves travel fastest in solid, followed by liquid, then least in gasous medium.
Thus, the medium in which mechanical waves will travel the slowest in is air which is gaseous medium.
Learn more about mechanical waves here: https://brainly.com/question/9242091
please help me..im begging you
Answer: The equations in column A is matched with gas laws in column B as follows:
21. PV = nRT : (g) Ideal gas law
22. [tex]V_{1}n_{2} = V_{2}n_{1}[/tex] : (f) Avogadro's law
23. [tex]P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex] : (e) Combined Gas Law
24. [tex]P_{1}T_{2} = P_{2}T_{1}[/tex] : (d) Gay-Lusaac's law
25. [tex]V_{1}T_{2} = V_{2}T_{1}[/tex] : (c) Charles' law
26. [tex]P_{1}V_{1} = P_{2}V_{2}[/tex] : (b) Boyle's law
27. [tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex] : (a) Graham's Law of effusion
Explanation:
(A) Ideal gas law: It states that the product of pressure and volume is directly proportional to the product of number of moles and temperature.
So, PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant
T = temperature
Boyle's law: At constant temperature, the pressure of a gas is inversely proportional to volume.So, [tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
Charles' law: At constant pressure, the volume of a gas is directly proportional to temperature. So,[tex]V \propto T\\\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\V_{1}T_{2} = V_{2}T_{1}[/tex]
Gay-Lussac's law: At constant volume, the pressure of a gas is directly proportional to temperature.So, [tex]P_{1}T_{2} = P_{2}T_{1}[/tex]
Avogadro's law: At same temperature and pressure, the volume of gas is directly proportional to moles of gas.So, [tex]V_{1}n_{2} = V_{2}n_{1}[/tex]
Combined gas law: When Boyle's law, Charles' law, and Gay-lussac's law are combined together then it is called combined gas law. So,[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\or, P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex]
Graham's law of effusion: It states that the rate of effusion of a gas is inversely proportional to the square root of mass of its particles.[tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex]
Thus, we can conclude that equation in column A is matched with gas laws in column B as follows:
21. PV = nRT : (g) Ideal gas law
22. [tex]V_{1}n_{2} = V_{2}n_{1}[/tex] : (f) Avogadro's law
23. [tex]P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex] : (e) Combined Gas Law
24. [tex]P_{1}T_{2} = P_{2}T_{1}[/tex] : (d) Gay-Lusaac's law
25. [tex]V_{1}T_{2} = V_{2}T_{1}[/tex] : (c) Charles' law
26. [tex]P_{1}V_{1} = P_{2}V_{2}[/tex] : (b) Boyle's law
27. [tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex] : (a) Graham's Law of effusion