What expression represents the volume of the prism, in cubic units? one-halfx3 x2 one-halfx3 three-halves x2 x3 x2 x3 3x2

Answers

Answer 1

The expression which represents the volume of the prism, in cubic units, is one-half x³+ x².

What is of volume of prism?

Volume of prism is the amount of quantity, which is obtained in it in the 3 dimensional space. The volume of a prism is the product of the area of its base and height.

[tex]V=A_b\times h[/tex]

Here, ([tex]A_b[/tex]) is the area of the base and (h) is the height of the prism.

The side of the base of the triangular prism is x units. Thus the area of the base is,

[tex]A_b=\dfrac{x\times x}{2}\\A_b=\dfrac{x^2}{2}[/tex]

The height of this prism is (x+2) units long. Thus, the volume of the prism is,

[tex]V=\dfrac{x^2}{2}\times (x+2)\\V=\dfrac{1}{2}x^3+x^2[/tex]

Thus, the expression which represents the volume of the prism, in cubic units, is one-half x³+ x².

Learn more about the volume of a prism here;

https://brainly.com/question/4016105

Answer 2

Answer:

1. A- 1/2x^3

2. 168

3. 927

4A. 48

4B. 336

5. A D

6. 1 3 3

7. 12 cm

8. 8 , 4

9. B

10. A C D

Step-by-step explanation:

whole thing right on edge


Related Questions


Directions: Calculate the area of a circle using 3.14x the radius
1) d = 4.4 mm.
Calculate the area of the circle.

2) d = 3.7 cm.
Calculate the area of the circle.

3) r= 8.3 cm.
Calculate the area of the circle.

4) d = 5.8 yd.
Calculate the area of the circle.


5) d = 1 yd.
Calculate the area of the circle

6) r = 8 ft.
Calculate the area of the circle

Answers

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

As we know ~

Area of the circle is :

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

Problem 1

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 4.4\div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 2.2 \: mm[/tex]

Now find the Area ~

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {(2.2)}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {4.84}^{} [/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2} [/tex]

・ .━━━━━━━†━━━━━━━━━.・

problem 2

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 3.7 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 1.85 \: \: cm[/tex]

Bow, calculate the Area ~

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times (1.85) {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 3.4225 {}^{} [/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2} [/tex]

・ .━━━━━━━†━━━━━━━━━.・

Problem 3

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times (8.3) {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 68.89[/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx216.31 \: \: cm {}^{2} [/tex]

・ .━━━━━━━†━━━━━━━━━.・

Problem 4

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 5.8 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 2.9 \: \: yd[/tex]

now, let's calculate area ~

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {(2.9)}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 8.41 [/tex]

[tex] \qquad \sf  \dashrightarrow \:area \approx26.41 \: \: yd {}^{2} [/tex]

・ .━━━━━━━†━━━━━━━━━.・

problem 5

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 1 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 0.5 \: \: yd[/tex]

Now, let's calculate area ~

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times (0.5) {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 0.25[/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx0.785 \: \: yd {}^{2} [/tex]

・ .━━━━━━━†━━━━━━━━━.・

problem 6

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {(8)}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 64[/tex]

[tex]\qquad \sf  \dashrightarrow \:area = 200.96 \: \: yd {}^{2} [/tex]

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Please answer 27-40, In simplified form. Thanks. No links

Answers

Answer:

-13

Step-by-step explanation:

Find the value of x. 136° (8x + 40) (The figure is not to scale.)​

Answers

Answer:

x= 12

Step-by-step explanation:

Hope u understood it

"PLEASE MARK ME THE BRAINLIEST"

Since the value of all angles within a triangle must equal 180 degrees, if you know at least two angles, you can subtract them from 180 to find the missing third angle. If you are working with equilateral triangles, divide 180 by three to find the value of X.

please just answer don’t explain

Answers

Answer:

13 C 14 D 15 A 16 B

Step-by-step explanation:

Sorry thats all i know hope you found this helpful

CHOOSE THE CORRECT ANSWER

Answers

The answer is 5 because if you do 5x4x3 that gives you 60 and since the base adds up to 12, we do 12x5 to give us 60

The (period,amplitude,frequence) of y=1/4cos1/2x is 4pie.
one of these is the answer need help

Answers

Answer:

  period

Step-by-step explanation:

The attached graph shows a period of the function. Its amplitude is 1/4 (vertical distance from centerline to peak). Its period is 4π (horizontal distance from peak to peak). Its frequency is the reciprocal of the period, so would be 1/(4π).

The value 4π is the period of the function.

Maggie wants 20 cookies equally in boxes. Each box holds 5 cookies how many does she need?

Answers

Answer:

4 boxes

Step-by-step explanation:

If she has 4 boxes that hold 5 cookies each, that will total 20 cookies.

4×5=20

20÷5=4

4 cookies 5 boxes 4 times 5 equals 20

Evaluate the function for the given value of x.

Answers

Answer:

f(-6)= -41 923

Step-by-step explanation:

f(-6)= -( -6)⁶ +5(-6)⁴+8(-6)³+2(-6) -7 you substitute x with -6 the you use a calculator which will then give you - 41923

Find the value of cos⁻¹ (cos7π/6).

Answers

Answer:

5π/6

Step-by-step explanation:

Given :

cos⁻¹ (cos7π/6)

Solving :

We know that : cos⁻¹ cosθ = θBut we can't just do that in this caseBecause the range of cos values is [0, π]Clearly, our value does not lie in this rangeWe have to take a different Quadrant other than the 3rd Quadrant which gives cos a negative valueThe 2nd Quadrant also has cos values negativeTherefore,cos⁻¹ cos (π - π/6)cos⁻¹ cos (5π/6)⇒ 5π/6 ∈ [0, π] ⇒ It lies in the range!

Answer:

5π Over 6

Step-by-step explanation:

You can write  7π6 as (π+π6)Thus we can clearly see the angle falls in the third quadrant. And the cosine value in third quadrant is always negative. Hence, cos(π+π6)=−cos(π6)coming back to the question cos−1[cos(7π6)]=cos−1[−cos(π6)]=π−cos−1[cos(π6)]=π−π6=5π6

The _____ between two points is the length of the line segment joining the points.
A. linear pair
B. angle
C. distance
D. midpoint
E. bisector

Answers

It would be c. Distance

Leila received 5/7 of 49 votes for the class president. How many votes did she receive?

Answers

Answer:

71.428571%

Step-by-step explanation:

You divide 5 by 7

Find the volume of a cone with a height of 3.25 centimeters and
a diameter of 2.2 centimeters.

Answers

Answer:

As per Provided Information

Height of cone h is 3.25 cm

Diameter of cone is 2.2 cm

Radius = Diameter/2

Radius = 2.2/2

Radius = 1.1 cm

We have been asked to determine the volume of the cone .

Using Formulae

[tex] \boxed{\bf \:Volume_{(Cone)} = \cfrac{1}{3} \pi {r}^{2}h}[/tex]

Substituting the given value and let's solve it

[tex]\sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times {1.1}^{2} \times 3.25 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times 1.21 \times 3.25 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times 3.9325 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 12.34805 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{12.34805}{3} \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = 4.11 {cm}^{3} [/tex]

Therefore,

Volume of the cone is 4.11 cm³ .

What is 164 divided by 5.40

Answers

Answer:

30.37

Step-by-step explanation:

164÷5.40164×100/54016400/540give 30.37

Answer:

[tex]164 \div 5.40 ={\ 30.3704{}}[/tex]

The answer is 30.3704

Pls help me on this problem I’m confused

Answers

5 quarts I think 4 cups per quart has 5 quarts and 2 cups I think

Answer:

1 quart = 4 cups

8 × 4 = 32

32 - 6 = 26

26 - 18 = 8

he has 2 quarts left

What is 7 1/3 x 2/5?
Math

Answers

Answer:

Step-by-step explanation:

you would multiply the fractions

then you would add the hole number

Answer:

2 14/15

Step-by-step explanation:

please help !
what is the probability of the complement of event A ?

Answers

Answer:

[tex]P(A < 84)=\frac{4}{7}[/tex]

Step-by-step explanation:

[tex]Total\ numbers:\ 7\\Numbers\ less\ than\ 84:\ 4\\\\P(A < 84)=\frac{4}{7}[/tex]

-
nd
According to the line of best fit, about how many words
will Jean have typed when she completes 60 minutes of
typing?
0 2,500
o 2,750
3,000
O
3,250

Answers

Answer:

C. 3000

Step-by-step explanation:

i took the quiz!

also 60 and 3000 line up

Answer:

C 3,000

Step-by-step explanation: It's right on Edge

Select the correct answer.
Which number is an irrational number?

A.

B.

C.

D.

Answers

Answer:

you do not have any numbers, only letters so I cannot answer your question. sorry...

Step-by-step explanation:

Select the correct answer.

Which number is an irrational number?

A.

B.

C.

D.

A triangle has sides that measure 3 cm, 4 cm, and 5 cm. What type of triangle is it?

help pls

Answers

Answer:

it is A Scalene Triangle

Calculate the area of the equilateral triangle using the formula for area of a regular polygon, and compare it to Bianca’s answer. The apothem, rounded to the nearest tenth, is units. The perimeter of the equilateral triangle is units. Therefore, the area of the equilateral triangle is , or approximately 43. 5 units2. The calculated areas are.

Answers

The calculated areas of both are the same instead of using the different formulas that are 43. 5 squared unit.

What is the area of a regular polygon?

The area of the polygon is the product of half of the apothem of the triangle and perimeter.

The area of the polygon = [tex]\frac{1}{2} \times h \times p[/tex]

The side of the triangle is 10 units.

Apothem of an equilateral triangle

[tex]s = \frac{\sqrt{3} a}{6}[/tex]

s= [tex]\sqrt{3} \times 10/6[/tex]

s = 2.88

Here, a is the side of the triangle.

Thus the apothem of the triangle is 2.9 units.

The perimeter of the equilateral triangle is equal to the three times the sides.

Perimeter of the equilateral triangle ,

P = 3(10)

P = 30

Therefore, the perimeter of the equilateral triangle is 30 units.

The area of the equilateral triangle-

The area of the polygon = [tex]\frac{1}{2} \times h \times p[/tex]

A = [tex]1/2 \times 2.9 \times 30[/tex]

A = 43.5

Thus the area of the equilateral triangle is 43.5 squared units.

Therefore, The calculated areas of both are the same instead of using the different formulas.

Learn more about the apothem;

brainly.com/question/10580427

Answer:

(A) 2.9

(C)30

(A)1/2(2.9)(30)

(D)The same despite using different formulas

Step-by-step explanation:

I did it

Find the value of a. Round your answer to the nearest tenth. B 10 77.5 A C 7.9

Answers

Answer:

[tex]\displaystyle 11,3[/tex]

Step-by-step explanation:

Use the Law of Cosines to find the length of the third edge:

Solving for Angles

[tex]\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos\angle{C} \\ \frac{a^2 - b^2 + c^2}{2ac} = cos\angle{B} \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos\angle{A}[/tex]

Use [tex]\displaystyle cos^{-1}[/tex]towards the end or you will throw your result off!

Solving for Edges

[tex]\displaystyle b^2 + a^2 - 2ba\:cos\angle{C} = c^2 \\ c^2 + a^2 - 2ca\:cos\angle{B} = b^2 \\ c^2 + b^2 - 2cb\:cos\angle{A} = a^2[/tex]

Take the square root of the final result or it will be thrown off!

Let us get to wourk:

[tex]\displaystyle 10^2 + 7,9^2 - 2[10][7,9]\:cos\:77,5 = a^2 \hookrightarrow 100 + 62,41 - 158\:cos\:77,5 = a^2 \hookrightarrow \sqrt{128,212541} = \sqrt{a^2}; 11,323097677... \\ \\ \boxed{11,3 \approx a}[/tex]

I am joyous to assist you at any time.

n 12. Find the volume of the sphere.​

Answers

Answer:

2929 1/3 [tex]\pi[/tex] in^3

Step-by-step explanation:

The equation for the volume of a sphere is [tex]\frac{4}{3} \pi r^3[/tex].

Insert 13 for r.  Then, simplify.

Find the value of x. Round to the nearest degree. Explain step by step

Answers

You have tu use

a2+b2+c2

the question is too hard

Answers

Answer:

a

Step-by-step explanation:

7(g-9)+12=26

7(g-9)+12-12=26-12

7(g-9)=14

7(g-9)/7=14/7

g-9=2

g-9+9=2+9

g=11

Answer:

(A) G= 11

Step-by-step explanation:

26=7(g-9)+12

(take 12 to 26)

so it will be 7(g-9)= 26-12

=> 7(g-9)= 14

(then take 7 to 14)

=> g-9= 14/2

=> g-9= 2

(then take 9 to 2)

g= 2 + 9

g= 11

hope it is properly explained

STAY SAFE, HAVE A NICE DAY

please help asap have a good day and ily

Answers

Answer:

Pretty sure it's 2:30 P.M.

Step-by-step explanation:

If her track practice started at 12:00 P.M., and and ran relays for one hour, it would already be 1:00 P.M.

Then she practiced the long jump for an hour and thirty minutes. Add another hour to that and it would be 2:00 P.M. Add thirty minutes, and it would be 2:30 P.M.

Hopefully that makes sense to you

Hello people ~
factorise ↷
x^2 + 6x + 8​

Answers

[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer}}[/tex]

Let's solve ~ ☂

⧠ Here, I'm using middle term split method :

[tex] \qquad\rightarrowtail \sf {x}^{2} + 6x + 8[/tex]

[tex] \qquad\rightarrowtail \sf {x}^{2} + 4x + 2x+ 8[/tex]

[tex] \qquad\rightarrowtail \sf {x(x}^{} + 4) + 2(x+ 4)[/tex]

[tex] \qquad\rightarrowtail \sf (x + 2)(x+ 4)[/tex]

[tex]\\ \rm\rightarrowtail x^2+6x+8[/tex]

[tex]\\ \rm\rightarrowtail x^2+4x+2x+8[/tex]

[tex]\\ \rm\rightarrowtail x(x+4)+2(x+4)[/tex]

[tex]\\ \rm\rightarrowtail (x+2)(x+4)[/tex]

Done!

Find a value for Y and give a reason for your answer

Answers

Step-by-step explanation:

inscribed angles subtended by the same arc are equal.

the central angle of a circle is twice any inscribed angle subtended by the same arc.

the first statement tells us that the 53° angle as well as y stay the same size no matter where on their arcs (between the 2 points connected to O) they would be. so, we don't need to bother with any line lengths.

the 2nd statement tells us that x = 2×53 = 106°. the 53° and x angles refer to the short arc on the right of the 2 points connected to O.

and y and x refer to the larger arc on the left of the 2 line connected to O. that means according to the second statement : 360-x (the big angle around O) = 2y

so,

360 - 106 = 2y

254 = 2y

y = 127°

pls can I get some help this is compound interest (10) will give brainliest

Answers

Answer:

2.7

Step-by-step explanation:

PLEASE HELP!
Solve for x. 4/5 = x/7 x =

Answers

Answer:

5.6

Step-by-step explanation:

4/5 = .8

so ? ÷ 7 = .8|
7 x .8 = 5.6
x= 5.6

x = 5.6

hope it helps...!!!!

Lines a and b are parallel.
what is the value of x?

A) 15

B) 16

C) 56

D) 64

Answers

Answer:

56

Step-by-step explanation:

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