A constant acceleration of 9.68 [tex]ft/s^{2}[/tex] is required to increase the speed of the car from 21 mi/h to 54 mi/h in 5 seconds.
First, we need to convert the speeds from miles per hour to feet per second, since acceleration is usually given in feet per second squared.
21 mi/h = 30.8 ft/s, 54 mi/h = 79.2 ft/s
Next, we can use the following kinematic equation to find the acceleration: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time interval.
Plugging in the values we have: 79.2 = 30.8 + a(5)
Subtracting 30.8 from both sides gives: 48.4 = 5a
Dividing both sides by 5 gives: a = 9.68 [tex]ft/s^{2}[/tex]
Therefore, a constant acceleration of 9.68 [tex]ft/s^{2}[/tex] is required to increase the speed of the car from 21 mi/h to 54 mi/h in 5 seconds.
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A cat pushes a 0.25-kg toy with a net force of 8n. According to Newton's second law of motion, what is the acceleration of the ball?
Answer:
a = 32 m/s sq
Explanation:
6th grade science pls help
Answer:
D
Explanation:
I hope you get a good grade!
A horse has a momentum of 25 kg*m/s and a velocity of 2.5 m/s. What is the horse mass?
==================================================
Work Shown:
We have these variables
p = momentum = 25 kg*m/sm = mass = unknownv = velocity = 2.5 meters per secondSolving for the mass gets us...
p = m*v
25 = m*2.5
25/2.5 = m
10 = m
m = 10
The mass of the horse is 10 kg.
A 1-kg book is at rest on a desk. Determine the force the desk exerts on the book
[tex]\displaystyle F_n = 9.8 \ N[/tex]
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightPhysics
Forces
SI Unit: Newtons N
Free Body Diagrams
Gravitational Force: [tex]\displaystyle F_g = mg[/tex]
m is mass (in kg)g is Earth's gravity (9.8 m/s²)Normal Force: [tex]\displaystyle F_n[/tex]
Newton's Law of Motions
Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motionNewton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)Newton's 3rd Law of Motion: For every action, there is an equal and opposite reactionExplanation:Step 1: Define
1 kg book at rest
Step 2: FBD
See Attachment
Draw a free body diagram to label the forces acting upon the book. We see that we would have gravitational force from Earth pointing downwards and normal force from the surface of the desk pointing upwards.
Since the book is not moving, we know that ∑F = 0 (sum of forces equal to 0).
Step 4: Find Normal Force
Define Forces [Newton's Law of Motions]: [tex]\displaystyle \sum F = 0[/tex][Newton's Law of Motions] Substitute in forces: [tex]\displaystyle F_g - F_n = 0[/tex][Newton's Law of Motions] [Addition Property of Equality] Isolate [tex]\displaystyle F_n[/tex]: [tex]\displaystyle F_g = F_n[/tex][Newton's Law of Motions] Substitute in [tex]\displaystyle F_g[/tex]: [tex]\displaystyle mg = F_n[/tex][Newton's Law of Motions] Rewrite: [tex]\displaystyle F_n = mg[/tex][Newton's Law of Motions] Substitute in variables: [tex]\displaystyle F_n = (1 \ kg)(9.8 \ \frac{m}{s^2})[/tex][Newton's Law of Motions] Multiply: [tex]\displaystyle F_n = 9.8 \ N[/tex]An island reports that in the year 2000 there were 240 babies born. That same year, 100 individuals died.
What is the growth rate for this island?(Show your work and indicate if it is positive or negative.)
Answer:
+ 140
Explanation:
You can show the natural growth rate by subtracting the death rate from the birth rate during one year and converting this into a percentage.
Here it would be:
240 - 100 = + 140
// if you want to convert it to percentage, you need to know the size of the population
it would be
140 / (population size) * 100 %
If Jay pushes on a box with a force of 20 N to the right and Bradley pushes on a box with a force of 15 N to the left, what is the net force on the box?
Answer:
Net force = 5N
Explanation:
Jay = 20N to the right
Bradley = 15N to the left
To find the net force;
Since the forces are being applied to the box in opposite direction i.e acting in opposite direction, we would subtract them.
Net force = 20 - 15
Net force = 5N
Therefore, the net force on the box is 5 Newton.
how was youll day still in school by the way.
My day is alright! I just finished school for the day.. and I’m excited for the weekend! How was your day?
What is the velocity of a 0.8kg ball that has a momentum of 3 kg*m/s?
If the mass of a 1.8 g paperclip was able to be completely converted to energy, how much energy would you obtain?
Answer:
[tex]E=1.62\times 10^{14}\ J[/tex]
Explanation:
Given that,
The mass of the paperclip, m = 1.8 g = 0.0018 kg
We need to find the energy obtained. The relation between mass and energy is given by :
[tex]E=mc^2[/tex]
Where
c is the speed of light
So,
[tex]E=0.0018\times (3\times 10^8)^2\\\\E=1.62\times 10^{14}\ J[/tex]
So, the energy obtained is [tex]1.62\times 10^{14}\ J[/tex].
A ray diagram shows an object placed between 2F and F of a convex lens.
The image produced is
smaller than the object.
upright.
larger than the object.
virtual
Answer:
larger than object
Explanation:
the image formed will be on the opposite side of lens and magnified
Answer:
C
Explanation:
What is the only part in our body we do not stretch?
Answer:
The quadriceps consists of four muscles: the skinny rectus femoris and the three huge “vasti” — vastus lateralis/intermedius/medialis. The vasti are only elongated by knee flexion, which is limited to about 120˚ when the calf hits the hamstrings. The vasti cannot be stretched strongly.
Answer:Masseter and temporalis
Why it’s unstretchable: The jaw can only open so far.
Why it’s a dang shame: Jaw tension is epidemic, and trigger points in these muscles cause a wide array of strange face and head pains, including toothaches, headaches, and earaches.
Determine the amount of work you would need to do in order to stop a 1100kg car with 1400J of kinetic energy.
Answer:
W = -1400 J
Explanation:
Let's use the relationship between work and kinetic energy
W = ΔK
kinetic energy is
K = ½ m v²
therefore in this case
K₀ = 1400 J
Thus
W = 0 -1400
W = -1400 J
The negative sign indicates that the work is done against the energy, that is, in the opposite direction to the movement
Light described as what two things?
Answer:modeled as an electromagnetic wave. In this model, a changing electric field creates a changing magnetic field.
Explanation:
How many straight edges does a cube have
Answer:
12
Explanation:
An outfielder throws a baseball to home plate with a velocity of 27 m/s at 35o. It is caught by the first baseman. How long was it in the air
Answer:
Explanation:
Initial velocity of the ball = 27 m /s .
Its vertical component = 27 sin 35 = 15.48 m /s
Considering vertical displacement to the top point ,
initial velocity u = 15.48 m /s
acceleration due to gravity g = 9.8 ,
velocity at the top v = 0
v = u - gt
0 = 15.48 - 9.8 t
t = 15.48 / 9.8 = 1.579 s
So time of ascent = 1.579 s
Similarly , time of descent = 1.579
Total time of flight = 2 x 1.579
= 3.16 s
pls help i’ll give brainliest if you give a correct answer!!
Answer:
C. The distance traveled by an object at a certain velocity.
Explanation:
YW!
Answer:
third option is the most accurate
A 100-newton object is lifted 100 meters in 100 seconds. What is the
power generated in this situation?
Two charged spheres 10 cm apart attract each other with a force of 3.0 x 10^-6 N. What electrostatic force will result if both charges are doubled and the distance remains the same?
Answer:
The electrostatic force that will result if both charges are doubled and the distance remains the same is 6.0 * 10⁻⁶ N
Explanation:
Coulomb's law of electricity states that the magnitude of the force of attraction or repulsion between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance of of separation between them.
In formula; F = KQ₁Q₂/d²
Using the formula for electrostatic force of attraction above to determine the force of between the two charged spheres
Let the charges be Q₁ and Q₂; distance of separation be d, K is a constant
Initially, F₁ = KQ₁Q₂/d² ---- (1)
F₁ = 3.0 * 10⁻⁶ N
when the charges are doubled, Q₁ = 2Q₁; Q₂ = 2Q₂; K and d remains constant
F₂ = 2KQ₁Q₂/d² ----(2)
Dividing equation (2) by (1) to find the ratio of their forces
F₂/F₁ = (2KQ₁Q₂/d²) / KQ₁Q₂/d²
F₂/F₁ = 2
Thus, F₂ is twice F₁.
Since F₁ = 3.0 * 10⁻⁶ N; F₂ = 2 * 3.0 * 10⁻⁶ N
F₂ = 6.0 * 10⁻⁶ N
Therefore, the electrostatic force that will result if both charges are doubled and the distance remains the same is 6.0 * 10⁻⁶ N
Electrostatic force is a force imposed by one charge on another as a result of the field.Electrostatic force will be 12.0 x 10⁻⁶ N if both charges are doubled and the distance remains the same.
What is the electrostatic force?It is a force imposed by one charge on another as a result of the field.
The electrostatic force produced by one line charge on another line charge separated by distance d is determined by the charge potency of each charge as well as the separation distance between them.
Hence the electrostatic force is given by
[tex]\rm F=\frac{Kq_1q_2}{d^2}[/tex]
The given data in the question ,
d is the distance between the charge
F₁ is the electric force for case 1= 3.0 x 10⁻⁶ N
F₂ is the electric force for case 2= ?
Conditions for case 2;
(q₁=2q₁),(q₂=2q₂),d₂=d₁
For case 1,
[tex]\rm F_1=\frac{Kq_1q_2}{d_1^2}[/tex]
For case 2,
[tex]\rm F_2=\frac{K(2q_1)(2q_2)}{d_1^2}[/tex]
[tex]\rm F_2=4\times\frac{Kq_1q_2}{d_1^2}\\\\\rm F_2=4F_1[/tex]
[tex]\rm F_2=4\times\frac{Kq_1q_2}{d_1^2}\\\\\rm F_2=4\times3.0\times 10^{-6}\\\\\rm F_2=12.0\times10^{-6}[/tex]
Hence electrostatic force will be 12.0 x 10⁻⁶ N. if both charges are doubled and the distance remains the same.
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In a bar magnet the magnetic force seems to come from each end. The ends of a bar magnet are
called the___
What one word completes the sentence?
How can you use the period of a wave to find the frequency?
Explanation:
Frequency is the number of occurrences of a repeating event per unit of time.
It is also referred to as temporal frequency, which emphasizes the contrast to spatial frequency and angular frequency.
The period is the duration of time of one cycle in a repeating event, so the period is the reciprocal of the frequency.
Relationship between Period and frequency is as under :
The frequency of a wave describes the number of complete cycles which are completed during a given period of time.
As such, frequency is a rate quantity which describes the rate of oscillations or vibrations or cycles or waves on a per second basis.
A common unit of frequency is the Hertz, abbreviated as Hz.
Frequency
=
1
Period
f = c / λ = wave speed c (m/s) / wavelength λ (m).
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1. How much electrical energy is needed to bring two charges Q1= 5.5 x 10-7C and Q2= 1.7 x 10-6 C from infinity to where they are 1 meter apart.
Answer:
The electrical energy needed is 8.415*10⁻³ N
Explanation:
Energy is the ability of a body to make changes or work.
By separating or joining two electric charges a distance (for example, a radius r) within their electric fields, you are taking away or giving the electric charges energetic potentials, relative to each other. By releasing these charges, they will attract or repel each other, releasing that acquired electrical energy.
In other words, electric potential energy is linked to the particular configuration of a conglomerate of point charges in a defined system.
That is, it calculates the capacity of an electrical system to carry out a task based exclusively on its position or configuration. So, it is a kind of energy stored in the system, or the amount of energy that it is capable of delivering.
Thus, a charge will exert a force on any other charge and the potential energy is the result of the set of charges.
The electric potential energy that has a point charge q in the presence of another point charge Q that are separated by a certain distance r is:
[tex]Ep=K*\frac{Q1*Q2}{r^{2} }[/tex]
where:
Ep is the electric potential energy. It is measured in Newton (N). Q1 and Q2 are the values of the two point charges. They are measured in Coulombs (C). r is the value of the distance that separates them. It is measured in meters (m). K is the constant of Coulomb's law. For vacuum its value is approximately 9*10⁹ N*m²/C²In this case:
Q1=5.5*10⁻⁷ CQ2=1.7*10⁻⁶ Cr=1 mReplacing:
[tex]Ep=9*10^{9}\frac{N*m^{2} }{C^{2} } *\frac{5.5*10^{-7}C *1.7*10^{-6}C }{(1m)^{2} }[/tex]
Solving:
Ep= 8.415*10⁻³ N
The electrical energy needed is 8.415*10⁻³ N
The electrical energy is needed to bring two charges Q1 and Q2 from infinity to where they are 1 meter apart is 8.415 x 10⁻³ N.
What is the electric potential?An electric potential can be defined as the amount of work or energy needed to move a charge from one point to another against the electrical field.
We know that in order to know electrical energy is needed to bring two charges Q1= 5.5 x 10⁻⁷C and Q2= 1.7 x 10⁻⁶ C from infinity to where they are 1 meter apart, we need to calculate electric potential energy between the two charged particles,
[tex]E_P = k\dfrac{Q_1Q_2}{d^2}[/tex]
Substitute the values,
[tex]E_P = 9 \times 10^9 \dfrac{5.5 \times 10^{-7} \times 1.7 \times 10^{-6}}{1^2}\\\\E_P = 8.415 \times 10^{-3}\rm\ N[/tex]
Hence, the electrical energy is needed to bring two charges Q1 and Q2 from infinity to where they are 1 meter apart is 8.415 x 10⁻³ N.
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An airliner flys 950 miles from S.B. to Denver at 500 mph. How long does it take to fly to
Denver? time = distance / speed
Answer:
114 minutes
Explanation:
hope this helps. I just divided 950 by 500 that is 1.9 and 1.9 in minutes is 114. gl
15. Which of the following is the correct electron configuration for neon (10Ne)?
A. 1s 2s22p
C. 184 2s2 3s2 2p?
B. 1s 2s2 3s2 2p4
D. 152 282 3s2p5
Answer:
1s2,2s2,2p6 or (He) 2s2 2p6
A hockey puck, with an initial velocity of 65 km/h [W], ricochets off the boards. After 0.76 s in contact with the boards, its final velocity is 47 km/h [E]. Determine the acceleration of the puck.
Answer:
a = 40.937 m / s²
Explanation:
For this exercise let's use the relationship between momentum and momentum variation
I = Δp
F t = m v_f - mv₀
F = m (v_f -v₀) / t
let's reduce the magnitudes to the SI system
v_f = 47 km / h (1000m / 1 km) (1h / 3600 s) = 13.056 m / s
v₀ = - 65 km / h = -18.056 m / s
the negative sign is bearing the speed is west
let's calculate
F = m (13.056 + 18.056) / 0.76
F = m 40.937
now we can use Newton's second law
F = m a
m 40.937 = m a
a = 40.937 m / s²
The acceleration of an object is ____________________ related to the net force exerted upon it and _____________________ related to the mass of the object.
Guys please help me I am dead confused
Answer:
A
Explanation
The diagram in A. contain a variable resistor which can be use to vary the pd from the 6v battery
An object with a mass 4.0 kg has a momentum of 64 kgm/s . How fast is the object traveling ?
Answer:
The object will travel at the speed of 16 m/s.
Explanation:
Given
Mass m = 4.0 kg Momentum p = 64 kgm/sTo determine
How fast is the object traveling?
Important Tip:
The product of the mass and velocity of an object — momentum.
Using the formula
[tex]p = mv[/tex]
where
m = massv = velcityp = momentumThus, in order to determine the speed of the object, all we need to do is to substitute p = 64 and m = 4 in the formula
[tex]p = mv[/tex]
[tex]64\:=\:4\times v[/tex]
switch the equation
[tex]\:4\times \:v\:=64[/tex]
divide both sides by 4
[tex]\frac{4v}{4}=\frac{64}{4}[/tex]
simplify
[tex]v=16[/tex] m/s
Therefore, the object will travel at the speed of 16 m/s.
An object moving in the air at a constant speed is considered to be in a balanced state. Explain Why
Answer:
and there is no friction
Explanation:
An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force. An object in motion with a velocity of 2 m/s, East will (in the absence of an unbalanced force) remain in motion with a velocity of 2 m/s, East. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force. Objects resist changes in their velocity.
A concrete dam holds back a large reservoir of water
potential or kinetic energy
Answer:
The water in a reservoir behind a hydropower dam is another example of potential energy. The stored energy in the reservoir is converted into kinetic energy as the water flows down a large pipe called a penstock and spins a turbine.
Explanation:
Hope this helps :))
A concrete dam holds back a large reservoir of water potential energy, the stored potential energy is converted into the kinetic energy which is converted into mechanical energy and then further converted into electrical energy.
What is hydropower?A dam or other construction that alters the natural flow of a river or other body of water is used to generate hydropower, often known as hydroelectric power.
In order to generate energy, hydropower uses the perpetual, never-ending water cycle, which uses water as a fuel and leaves no waste products behind. Although there are many different kinds of hydropower plants, they are always propelled by the kinetic energy of water moving downstream.
Thus, a concrete dam holds back a large reservoir of water potential energy.
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What is a Sport car transformation
Answer:
when a car transforms...
Explanation:
Explanation:
Vivimos en un puente en lo que el diseño de coches se refiere, consecuencia de la gran disrupción de la automación que ocurriría en los próximos años.