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The reaction has a change in free energy of -6.5 kJ and is spontaneous Option D.

The term spontaneous reaction refers to a reaction that occurs with n external input of energy. We know that a spontaneous reaction is one in which the value of the change in free energy is negative. If the change in the free energy is positive then the reaction is nonspontaneous.

If the value of the change in free energy is zero then it follows that the reaction has attained equilibrium.

Now;

ΔG = ΔH - TΔS

ΔH = 2 kJ/mol

T =  500 K

ΔS =  0.017 kJ/(K-mol)

When we substitute values;

ΔG = 2 kJ/mol - (500 K * 0.017 kJ/(K-mol))

ΔG = -6.5 kJ

It the follows that the reaction has a change in free energy of -6.5 kJ and is spontaneous Option D.

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(2.) A lab assistant Alex test for the presence of X, the balanced chemical equation is CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O. (3.) Another lab assistant perform the test, the balanced chemical equation is CaCO₃ + 2NaOH → Ca(OH)₂ + Na₂CO₃. (4.) The Substance X is Calcium carbonate.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

(2.) To test for the presence of substance X, a lab assistant, Alex, treats a sample of the material with hydrochloric acid. Bubbles of carbon dioxide gas are observed and collected during the test reaction.

The balanced chemical equation is

CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O

(3.) Another lab assistant, Jess, disagrees with Alex, and treats a sample of substance X with sodium hydroxide. One of the products of this reaction is a compound called milk of lime (found to be only slightly soluble in water).

The balanced chemical equation is

CaCO₃ + 2NaOH Ca(OH)₂ + Na₂CO₃

The type of reaction is Double displacement reaction

(4.) The lab assistant Alex perform the valid test for substance X because it gives effervescence of bubbles. The substance X is calcium carbonate. When calcium carbonate react with dilute HCl then carbon dioxide gas bubbles is present in it.

Thus from the above conclusion we can say that  (2.) A lab assistant Alex test for the presence of X, the balanced chemical equation is CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O. (3.) Another lab assistant perform the test, the balanced chemical equation is CaCO₃ + 2NaOH → Ca(OH)₂ + Na₂CO₃. (4.) The Substance X is Calcium carbonate.

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Calcium carbonate ([tex]CaCO_{3}[/tex]), an insoluble precipitate that could be removed from water by filtration, is created when the calcium ion in hard water bonds with the carbonate ion.

Precipitates may be ionic solids that are insoluble and result from reactions between certain cations as well as anions in water. A precipitate's formation could be influenced by a variety of circumstances.

When calcium atoms gain or lose electrons, they change their charge but also reactivity, forming calcium ions.

Therefore, Calcium carbonate ([tex]CaCO_{3}[/tex]), could be used to precipitate the calcium ion form a water sample

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Answer:

Non-polar

Explanation:

Non-polar bonds occur when the electrons in a covalent bond are equally shared between the two atoms.

The indicated bond is most likely non-polar because the two atoms are identical (both carbons). In addition, these two carbons are balanced (their other bonds are identical). This means there is no reason for the electrons in the bond to be pulled in any particular direction.

1a. The empirical formula of the compound is Fe₂O₃

1b. The molecular formula of the compound is Fe₂O₃

2a. The molecular formula of the anhydrous salt is MgSO₄

2b. The formula of the crystalline salt is MgSO₄.7H₂O

3i. The number of mole of carbon atoms in the compound is 6 moles

3ii. The number of mole of hydrogen atoms in the compound is 18 moles

3iii. The number of molecules in 3 moles of ethane is 1.806×10²⁴ molecules

Divide by their molar mass

Fe = 69.9 / 56 = 1.248

O = 30 / 16 = 1.875

Divide by the smallest

Fe = 1.248 / 1.248 = 1

O = 1.875 / 1.248 = 3/2

Multiply by 2 to express in whole number

Fe = 1 × 2 = 2

O = 3/2 × 2 = 3

Thus, the empirical formula of the compound is Fe₂O₃

Molecular formula = empirical × n = molar mass

[Fe₂O₃]n = 159.89

[(56×2) + (16×3)]n = 159.89

160n = 159.89

n = 159.89 / 160

n = 1

Molecular formula = [Fe₂O₃]n

Molecular formula = [Fe₂O₃] × 1

Molecular formula = Fe₂O₃

We'll begin by calculating the empirical formula

Divide by their molar mass

Mg = 20.0 / 24 = 0.83

S = 26.66 / 32 = 0.83

O = 53.33 / 16 = 3.33

Divide by the smallest

Mg = 0.83 / 0.83 = 1

S = 0.83 / 0.83 = 1

O = 3.33 / 0.83 = 4

Thus, the empirical formula of the anhydrous salt is MgSO₄

The molecular formula of the anhydrous salt can be obtained as follow:

Molecular formula = empirical × n = molar mass

[MgSO₄]n = 120

[24 + 32 + (16×4)]n = 159.89

120n = 120

n = 120 / 120

n = 1

Molecular formula = [MgSO₄]n

Molecular formula = [MgSO₄] × 1

Molecular formula = MgSO₄

Divide by their molar mass

MgSO₄ = 48.8 / 120 = 0.4

H₂O = 51.2 / 18 = 2.8

Divide by the smallest

MgSO₄ = 0.4 / 0.4 = 1

H₂O = 2.8 / 0.4 = 7

Thus, the formula of the crystalline salt is MgSO₄.7H₂O

1 mole of C₂H₆ contains 2 moles of carbon atoms.

Therefore,

3 moles of C₂H₆ will contain = 3 × 2 = 6 moles of carbon atoms

1 mole of C₂H₆ contains 6 moles of hydrogen atoms.

Therefore,

3 moles of C₂H₆ will contain = 3 × 6 = 18 moles of hydrogen atoms

From Avogadro's hypothesis,

1 mole of ethane = 6.02×10²³ molecules

Therefore,

3 moles of ethane = 3 × 6.02×10²³ molecules

3 moles of ethane = 1.806×10²⁴ molecules

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Complete question

2. A crystalline salt when heated becomes anhydrous and loses 51.2% of its weight the anhydrous salt analysis gave the percent composition as magnesium is equal to 20.0% and sulphur is equal to 26.66% and oxygen is equal to 53.33%. Ccalculate the molecular formula of the anhydrous and the crystalline salt. The molecular weight of the anhydrous salt is 120

Answer: The purpose is to analyze the speed of planets around a central star.

Explanation: using variables

The correct option is (2) decomposition.

In the balanced equation 2KClO3==> 2KCl + 3O2, as there is a reduction of oxygen therefore it is decomposition reaction.

A chemical reaction that results in the breakdown of one reactant into two or more reactants is known as a decomposition reaction.

The general equation for decomposition is-

AB -> A + B

Where A & B are now the product molecules and AB is the parent (reactant) molecule.

Some key features of the decomposition reaction are-

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The complete question is-

Given the balanced equation:

2KClO3==> 2KCl + 3O2

Which type of reaction is represented by this equation?

(1) synthesis

(2) decomposition

(3) single replacement

(4) double replacement

Benzoic acid is one of the weakest acid for titration. The pH of the salt solution generated is the pH greater than 7( >7 ) at the equivalence point in any titration.

The benzoate anion, combines with water to create OH- and undissociated benzoic acid. This reaction is stronger than OH-. As a result of the hydroxide ions generated by this reaction, the final solution has a pH greater than 7. Hydrolysis is the term for an ion's reaction with water, such as the benzoate ion.

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An oil separates crude oil into its components by distillation. some components are altered by cracking and Reforming.

The  crude oil  contains many petroleum products like petrol , diesel , Mobil oil coaltar and many more with impurities So, now it is very important to separated it into components to use all product individually in pure form.

The separation process are based on fraction distillation because all petroleum products have different density and boiling points. All products are separated at different temperature.

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Increase in carbon dioxide in your red blood cells, which causes a drop in pH, causes your breathing to speed up.

The presence of  carbon dioxide in red blood cell will lower the pH because  carbon dioxide combines with water to form [tex]H^{+}[/tex] and [tex]HCO_{3} ^{-}[/tex] .

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The percent yield of the calcium hydroxide is 84.5%.

Stoichiometry enables us to obtain the mass of a substance form the equation of the reaction.

The equation of the reaction is;

CaCO3 + 2HCl -----> CaCl2 + CO2 + H2O

Number of moles of X = 40.0 grams/100 g/mol = 0.4 moles

Number of moles of HCl = 850/1000 * 1 M = 0.85 moles

If 1 mole of CaCO3 reacts with 2 moles of HCl

0.4 moles of  CaCO3 reacts with  0.4 moles  * 2 moles/1 mole

= 0.8 moles of HCl

Hence X is the limiting reactant.

The reaction is 1:1 then the amount of CO2  produced is 0.4 moles

Mass of CO2 = 0.4 CO2 * 44 g/mol = 17.6 g

2) The reaction equation is; 2NaOH + CaCO3 --->  Ca(OH)2 + Na2CO3

Number of moles of X = 25.0 grams/100 g/mol =  0.25 moles

Number of moles of NaOH= 40/1000 L * 2 M = 0.08 moles

If 1 mole of X reacts with 2 moles of NaOH

0.25 moles  reacts with   0.25 moles   * 2 moles /1 mole

= 0.5 moles

NaOH is the limiting reactant

2 moles of NaOH produces 1 mole of CO2

0.08 moles of NaOH produces 0.08 moles * 1 mole/2 moles

= 0.04 moles of CO2

Theoretical yield of CO2 =  0.04 moles of CO2 * 74 g/mol = 2.96  g

Percent yield = 2.5 g/ 2.96  g * 100

= 84.5%

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A 100 cc bottle of Amoxicillin 125 oral suspension requires addition of 61 ml of Purified Water to make 100 cc.  The powder volume is 76.25.

To calculate the powder volume use the expression

[tex]\frac{H}{Q} = \frac{D}{X}[/tex]

where,

H = Dose on hand

Q = Quantity on hand

D = Desired dose

X = Quantity desired

Now put the values in above expression we get

[tex]\frac{H}{Q} = \frac{D}{X}[/tex]

[tex]\frac{100}{61} = \frac{125}{X}[/tex]

[tex]X = \frac{125 \times 61}{100}[/tex]

X = 76.25

Thus from the above conclusion we can say that A 100 cc bottle of Amoxicillin 125 oral suspension requires addition of 61 ml of Purified Water to make 100 cc.  The powder volume is 76.25.

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1. O2 is the limiting reagent

2. Excess NH3 = 0.102 moles

3. 0.088 mol of NO is formed

4. 2.376 grams of H2O is formed

From the equation: [tex]4NH_3 + 5O_2 --- > 4NO + 6H_2O[/tex]

Mole ratio of NH3 and O2 = 4:5

Mole of 3.25 g NH3 = 3.25/17 = 0.19 mol

Mole of 3.50 g O2 = 3.5/32 = 0.11 mol

Equivalent mole of O2 from NH3 = 5/4 x 0.19 = 0.24 mol

Equivalent mole of NH3 from O2 = 4/5 x 0.11 = 0.088 mol

Thus, O2 is the limiting reagent.

Excess NH3 = 0.19 - 0.088 = 0.102 moles

Mole ratio of O2 and NO = 5:4

Equivalent mole of NO = 4/5 x 0.11 = 0.088 mol

Mole ratio of O2 and H2O = 5:6

Equivalent mole of H2O = 6/5 x 0.11 = 0.132 mol

Mass of 0.132 mol H2O = 0.132 x 18 = 2.376 grams

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PO43- can form an ionic bond with a cation.

The chemical species which can easily form an ionic bond with a cation will be.

The definition of an ionic bond is a chemical bond that is formed between two ions that have opposite charges.

An Ionic bond is formed when one atom gives up one or more electrons to another atom.

These bonds can easily form between a pair of atoms or between molecules. This kind of bonding is most widely seen in bonds present in salts.

Compared to other options given,  is the best option as the total number of 32 valence electrons, is the highest among the given choices. Its tendency to form ionic bonds with the other cation is much higher as compared to others.

P has 5 electrons which combine with 4 O atoms which have 6 lone pairs and a -3 charge on it, which means it is accepting 3 electrons so it will be (+3), so total valence electrons will be 5 + 6 (4) + 3 = 32.

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Dalton's law of partial pressures states that the total pressure of a gas mixture is equal to the sum of the partial pressures of its individual gases.

Partial pressure is defined as the pressure exerted by individual gas constituents that makes up a mixture of gases.

According to Dalton's law of partial pressures which states that the total pressure by a mixture of gases is equal to the sum of the partial pressures of each of the constituent gases.

This can be represented mathematically by the following:

P = P1 + P2

Where P = total pressure

P1 = partial pressure of gas 1

P2 = partial pressure of gas 2.

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The elements listed on the bottom of the reactivity list for all of the following except fireworks and is denoted as option C.

This is referred to the extent in which an element is able to take part in a chemical reaction.

The elements founds at the bottom of the reactivity list include gold which can't be used for making fireworks.

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Answer:

when an electron move closer to the nucleus the magnitude of energy of the nucleus increases

The correct answer is   [tex]LiCH_{3}CH(CH_{3} )CH_{3}[/tex] .

Organometallic chemistry is the study of organometallic compounds, which are substances that contain at least one chemical bond between a carbon atom from an organic molecule and a metal. These substances include alkali, alkaline earth, and transition metals, as well as metalloids like boron, silicon, and selenium. In addition to links to organyl fragments or molecules, bonds to 'inorganic' carbon, such as those to carbon monoxide (metal carbonyls), cyanide, or carbide, are also typically regarded as organometallic. Although they are not strictly speaking organometallic compounds, some similar compounds, such as transition metal hydrides and metal phosphine complexes, are frequently included in discussions of such substances. The phrase "metalorganic compound," which is comparable but different, describes molecules that contain metals but do not have direct metal-carbon bonds but do have organic ligands.

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Sodium represents by the (Na).

Answer:

Mg(OH)2(s) + 2HCl(aq) => MgCl2(aq) + 2HCl(l)

Explanation:

The reaction that occurs in the stomach when one takes an antacid {Mg(OH)2} is termed as Neutralization reaction as it reacts with hydrochloric acid to form magnesium hydroxide and water.

The equation of reaction:

Mg(OH)2(s) + 2HCl(aq) => MgCl2(aq) + 2HCl(l)

Answer:

d. oligomer it is the correct answer also if you would just search that up it pops up

Answer:

11.22 gm

Explanation:

32.07 gm / mole * .350 mole = 11.22 gm

The mass of 0.350 moles of Sulphur is equal to 11.22 g.

A mole is a standard unit which is used to calculate the huge number of quantities of atoms, molecules, ions, or other particular particles. The mass of the one mole of any element is called atomic mass and that of any compound is called molar mass.

The number of units present in one mole was found to be equal to 6.023 × 10 ²³ which is known as Avogadro’s constant or Avogadro’s number.

Given, the number of moles of sulphur = 0.350 moles

The mass of one mole of sulphur = 32.07 g

Then, the mass of 0.350 moles of Sulphur = 0.350 × 32.07

The mass of 0.350 moles of Sulphur (S) = 11.22 g

Therefore, 11.22 grams is the mass of 0.350 moles of Sulphur (S).

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The concentration of the solution in mass percent is 60%.

The concentration of a substance can be expressed in mass percent. This refers to the percentage of the solute that is contained in the solution.

Thus we can write;

Mass percent = Mass of solute/ Mass of solution * 100/1

Mass percent = 1.5kg/1.5kg + 1 Kg * 100/1

Mass percent =  60%

Hence, the concentration of the solution in mass percent is 60%.

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From the calculation, the concentration in parts per billion is 6 ppb.

The term ppb refers to the concentration of a substance in parts per billion. We obtain the ppb using the formula;

Mass of solute/ Mass of solution * 10^9

Now, 1L = 1000cm^3 = 1000 g

The concertation in ppb = 6 * 10^-6 g/1000 g * 10^9

= 6 ppb

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The component(s) of msa make(s) this media selective for sodium chloride.

MSA is a medium  which has both differential as well as selective properties. The distinguishing feature is the high salt content (7.5%). On just this high salt concentration, Staphylococcus species, which frequently inhabit human skin, can develop.

Streptococcus species, however, have their growth inhibited by the high salt content of the agar. Mannitol, a sugar, would be the MSA's unique component.

Resulting in high salt concentration, the sodium chloride in MSA ensures that only Staphylococci species survive. All more gram-positive bacteria are thereafter destroyed.

Therefore, the correct answer will be option (d).

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The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abbreviation (w/v) is also common. 262 grams of sucrose are needed to make 655 mL of a 40.0% (w/v) sucrose solution

A solute is a material that dissolves in a solution. The amount of solvent present in fluid solutions is greater than the amount of solute. The two most common examples of solutions in daily life are salt and water. Salt is the solute because it dissolves in water.

       It provides the real yield of the substance or item.

using w/v we can calculate the weight of sucrose:-

40.0% means 40 g sucrose/ 100 g solution

40.0g sucrose x (655/100)=grams of sucrose

262  grams of sucrose are needed to make 655 mL of a 40.0% (w/v) sucrose solution.

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It is hemoglobin.

In the red blood cells (erythrocytes) of vertebrates, hemoglobin, an iron-containing protein, transports oxygen from the lungs to the body's tissues and organs and returns carbon dioxide to the lungs. In a complete blood cell (CBC) test, the amount of hemoglobin in the blood is often measured.

A globin group is surrounded by four heme groups, which together form a tetrahedral shape in each hemoglobin molecule. Heme is an organic complex known as a porphyrin that has an iron atom linked to it. Heme makes up only 4% of the weight of the molecule. As the blood circulates between the lungs and the tissues, the iron atom is what holds oxygen in place. Each hemoglobin molecule contains four iron atoms, and as a result, it has the capacity to bind four oxygen molecules. Two linked pairs of polypeptide chains make up globin.

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The major 1,2- and 1,4-addition products are 4-Bromo-2-hexene and 2-Bromo-2-hexene.

What is Markovnikov Rule ?

Markovnikov rule explains that in addition reaction of alkene react with a hydrogen halide. The hydrogen atom is attached to the carbon atom that is already bonded to the greatest number of hydrogen.

An addition reaction is an organic reaction occur when two or more molecules combine to form a larger molecule without the loss of any atoms present in reactant.

Thus from the above conclusion we can say that The major 1,2- and 1,4-addition products are 4-Bromo-2-hexene and 2-Bromo-2-hexene.

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Answer:

[tex]K2O[/tex]

Explanation:

If you use a melting point periodic table there is a listing of all the elements and their melting point.

Potassium (K) has a melting point of 63.25 degrees Celsius and oxygen (O) has a melting point of -218 degrees Celsius. Therefore, if you add those two values up

[tex](63.25x2)+-218 = -91.5 Degrees Celsius[/tex]

All the other compounds do not reach negatives.

Answer:

k ion is the largest size of the radius it is always smaller compared to the parent ion

Explanation: