The value of the temperature and volume are:
A. 270 K
B. 360 K
C. 0.347 J
D. 373.347 J
E. 373 J
To solve this problem, we can use the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.
A. To find the initial temperature, we can rearrange the ideal gas law as T = PV/nR and plug in the given values:
T = (2.90 atm)(3.20×10−2 m3)/(3 mol)(8.31 J/mol·K) = 270 K
B. To find the final temperature, we can again use the ideal gas law, but this time with the final volume:
T = (2.90 atm)(4.30×10−2 m3)/(3 mol)(8.31 J/mol·K) = 360 K
C. The amount of work the gas does in expanding is given by the equation W = PΔV, where ΔV is the change in volume:
W = (2.90 atm)(4.30×10−2 m3 - 3.20×10−2 m3) = 0.347 J
D. The amount of heat added to the gas can be found using the first law of thermodynamics, which states that ΔU = Q - W, where ΔU is the change in internal energy and Q is the heat added:
ΔU = (3/2)nRΔT = (3/2)(3 mol)(8.31 J/mol·K)(360 K - 270 K) = 373 J
Q = ΔU + W = 373 J + 0.347 J = 373.347 J
E. The change in internal energy of the gas is given by the equation ΔU = (3/2)nRΔT:
ΔU = (3/2)(3 mol)(8.31 J/mol·K)(360 K - 270 K) = 373 J
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The crystal in a digital watch oscillates at a rate of 215 Hz. If the maximum displacement of one crystal face (measured from one extreme of its motion to the other) is 50 nm, what is the maximum speed of the face?
The maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.
Maximum speed of the face
v = fλ
where;
f is frequency of the waveλ is the wavelengthAngular speed of the waveω = 2πf
v(max) = ωA
v(max) = 2πfA
where;
A is amplitude of the wavev(max) = 2π(215)(50 x 10⁻⁹ m)
v(max) = 6.75 x 10⁻⁵ m/s
Thus, the maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.
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A copper penny has a mass of 3.0 g. A total of 4.0 × 1012 electrons are transferred from one neutral penny to another. If the electrostatic force of attraction between the pennies is equal to the weight of a penny, what is the separation between them?
Answer:
F = K Q1 Q2 / R^2 = m g
Q1 = - Q2 = (4E12 * 1.60E-19) = 6.4E-7 coulombs
Q^2 = 4.10E-13
R^2 = 9.0E9 * 4.1E-13 / (.003 * 9.80) = 36.9E-4 / 2.94E-2
R^2 = .126
R = .35 m
F = K Q1 Q2 / R^2 = m g, Q1 = - Q2 = (4E12 * 1.60E-19) = 6.4E-7 coulombs Q^2 = 4.10E-13, R^2 = 9.0E9 * 4.1E-13 / (.003 * 9.80) = 36.9E-4 / 2.94E-2 R^2 = .126 and R = .35 m.
What is Electrostatic force?Due to their electric charges, particles can be attracted to or repelled by electrostatic forces. This force is also known as the Coulomb force or Coulomb contact, and it was first described in 1785 by French physicist Charles-Augustin de Coulomb.
Over a distance of 10-16 meters, or roughly one-tenth the diameter of an atomic nucleus, the electrostatic force is present. While opposite charges attract one another, like charges repel one another.
For instance, two positively charged protons, two negatively charged electrons, or two anions all repel one another. Cation and anions, as well as protons and electrons, are all attracted to one another.
Therefore, F = K Q1 Q2 / R^2 = m g, Q1 = - Q2 = (4E12 * 1.60E-19) = 6.4E-7 coulombs Q^2 = 4.10E-13, R^2 = 9.0E9 * 4.1E-13 / (.003 * 9.80) = 36.9E-4 / 2.94E-2 R^2 = .126 and R = .35 m.
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If the ocular lens magnifies a specimen 10x, and the objective lens used magnifies the specimen 35x. What is the total magnification being used to observe the specimen?
Answer:
350x^2
Explanation:
I'm assuming you're saying you're using them together, like stacking them on top of each other, so if that's the case then this is a simple multiplication problem, which can be written as 10x(35x). Solve it and you get 350x^2.
An astronaut in training is seated at the end of a horizontal arm 8 meters long. How many revolutions per second must the arm make for the astronaut to experience a horizontal acceleration of 4.0g
Answer:
a = v^2 / R where a is the centripetal acceleration and R the radius
v = 2 π R N / t where (N / t) is the revolutions / sec giving distance / time
a = 4 g horizontal acceleration
4 g = (2 π R N / t)^2 / R = 4 π^2 * R * (N / t)^2
(N / t)^2 = g / (π^2 * R)
N / t = 1 / π * (g / R)^1/2 = .318 * (9.80 m / s^2 / 8 m)^1/2 = .352 / sec
A 1.5 kg ballistic cart, moving at 2.8 m/s, ejects a 25 g ball vertically with an initial velocity of 6.5 m/s. What is the magnitude of the initial velocity of the ball relative to the ground?
a. 2.8 m/s
b. 9.3m/s
c. 7.1 m/s
d. 6.5 m/s
The magnitude of the initial velocity of the ball relative to the ground is 9.3 m/s.
What is relative velocity?Relative velocity is the velocity of an object relative to another moving in the same plane. On frame of reference is used when measuring relative velocity.
The velocity of the ball relative to the ground is the sum of the velocity of the ballistic cart and the velocity in which the ball is ejected.
The velocity of the ball relative to the ground = 6.5 m/s + 2.8 m/s = 9.3 m/s
In conclusion, relative velocity measures the velocity of an object from a reference point.
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5. a new type of hoverboard has been designed to levitate over a copper surface. the
developers had a skateboard icon test out the hoverboard on a copper halfpipe.
what type of field is responsible for levitating the hoverboard and rider as it
traverses the half pipe?
a-magnetic field
b-gravitational field
c-electric field
d-tesla field
The magnetic field is responsible for levitating the hoverboard and rider as it traverses the half pipe.
What is a magnetic field?The magnetic field is defined as the field the magnetic materials generate or when an electric charge moves in a field region that generates the magnetic field.The surface is made up of from the copper and copper is conductor of electricity.When an electrical charge moves, it generates a magnetic field. As with electrical current running via a wire, the spinning and orbiting of an atom's nucleus produces a magnetic field.Thus, the magnetic field is responsible for levitating the hoverboard and rider as it traverses the half pipe.What is the characteristics of Magnetic fields?Magnetic field lines never cross one another.They begin (from the north pole) and end (to the south pole) perpendicular to the surface of the magnet. Magnetic field lines also run through the magnet.The magnetic field is denser at the poles and less dense as we move away from them.A single magnetic pole does not exist. Magnetic poles are always found in pairs of opposing poles.Learn more about the magnetic field here:
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Does your experimental density of the unknown liquid agree with the true value? if no, give reasons for the discrepancy. Do not include operator errors
The reasons for the discrepancy in the experimental density of the unknown liquid agree with the true value can be instrument not having same levels , Temperature Effects , Kind of scales used and Shape of objects used for measure .
According to the question
Discrepancy:
The state or quality of being discrepant or in disagreement, as by displaying an unexpected or unacceptable difference; inconsistency.
Density:
Density is mass per unit volume, so when measuring density, you find the mass of the object and divide it by its measured volume.
All measurements include some uncertainty, however, and certain kinds of errors can increase the uncertainty in your calculation.
The reason of discrepancy in the experimental density of the unknown liquid agree with the true value can be:
1. Use of instrument not having same levels
2. Temperature Effects as Density varies with temperature .
3. Kind of scales used for measures
4. Shape of objects used for measure .
Hence, the reasons for the discrepancy is instrument not having same levels , Temperature Effects , Kind of scales used and Shape of objects used for measure .
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2. Find rectangular coordinates for the point (6, 240°).
Answer:
(-3, -3√3)
Explanation:
To convert from polar coordinate to rectangular coordinate, first you have to know these two equations:
[tex]\displaystyle{x=r\cos \theta}\\\displaystyle{y=r\sin \theta}[/tex]
We know that (x,y) is in rectangular coordinate form while (r,θ) is in polar coordinate form.
Therefore, substitute r = 6 and θ = 240° in both equations:
[tex]\displaystyle{x=6\cos 240^{\circ}}\\\displaystyle{y=6\sin 240^{\circ}}[/tex]
After evaluating, you'll get:
[tex]\displaystyle{x=-3}\\\displaystye{y=-3\sqrt{3}}[/tex]
Therefore, substitute x and y in rectangular coordinate form - hence, the answer is (-3, -3√3)
describe how you would connect a voltmeter to measure the potential difference across a resistor and an ammeter to measure the current through a resistor
A voltmeter needs to be connected in parallel to the two sites in order to measure the potential difference between them.
What is a voltmeter?The electrical potential difference between two locations in an electric circuit is measured using a voltmeter.The potential difference between two ends of a current-carrying conductor is measured using a voltmeter.On a scale that is typically measured in volts, millivolts (0.001 volts), or kilovolts, a voltmeter primarily monitors the voltage of direct or alternating electric current (1,000 volts).Numerous voltmeters are digital and display readings as numbers.How is a voltmeter connected?A galvanometer with high resistance is a voltmeter.Any portion of an electrical circuit can be measured.Due to its high resistance, it is linked in parallel so that it does not impact the circuit's overall net resistance and does not draw any current by itself.A device's voltage is measured by a voltmeter connected in parallel, and its current is measured by an ammeter connected in series.Learn more about voltmeters here
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Which would require the greater energy; slowing down of the orbital speed of the Earth so it crashes into the sun, or speeding up the orbital speed of the Earth so it escapes the sun
Answer: Speeding up the orbital speed of earth so it escapes the sun require the greater energy.
Explanation: To find the answer, we need to know more about the Orbital and escape velocities.
What is Orbital and Escape velocity?Orbital velocity can be defined as the minimum velocity required to put the satellite in its orbit around the earth.The expression for orbital velocity near to the surface of earth will be,[tex]V_o=\sqrt{gR}[/tex]
Escape velocity can be defined as the minimum velocity with which a body must be projected from the surface of earth, so that it escapes from the gravitational field of earth.The expression for orbital velocity will be,[tex]V_e=\sqrt{2gR}[/tex]
If we want to get into the sun, we want to slow down almost completely, so that your speed relative to the sun became almost zero.We need about twice the raw speed to go to the sun than to leave the sun.Thus, we can conclude that, the speeding up the orbital speed of earth so it escapes the sun require the greater energy.
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Describe the usefulness of frictional force when a soccer player runs with soccer boots
Frictional force provided by the teeth of the boots which are in contact with the grass in the soccer pitch enables the soccer player to start running and prevents him from slipping and falling.
What is friction?Friction is the opposition to the relative motion of one object over another at their surface of contact.
Friction is a type of contact force as it requires between the two objects for its effect to be felt.
Friction has both advantages and disadvantages.
On of the advantages of friction is in the ability to walk or run. Friction between the ground and the foot or the boots of a person walking or running enables the person from slipping.
For example, when a soccer player runs with soccer boots, friction enables the runner to start running and prevents him from slipping and falling. The friction is provided by the teeth of the boots which are in contact with the grass in the soccer pitch.
In conclusion, friction enables a soccer player to start running and also prevents him from falling.
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The radial velocity method preferentially detects: Choose one: A. all of the above described planets equally well. B. small planets far from the central star. C. small planets close to the central star. D. large planets close to the central star. E. large planets far from the central star.
The radial velocity method preferentially detects large planets close to the central star
what is the Radial velocity:The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.
This is due to the fact that low mass stars are more affected by the gravitational tug of planets.
When a planet orbits around a star, the star wobbles a little.
From this, we can determine the mass of the planet and its distance from the star.
hence we can say that,
option D is correct.
The radial velocity method preferentially detects large planets close to the central star
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Find the work done by a person weighing 133 lb walking exactly one revolution(s) up a circular, spiral staircase of radius 5 ft if the person rises 13 ft after one revolution.
The work done by a person will be 2341.28 J
Work done is negative of change in potential energy, that is W=−(∆U). It means that Work done against a force (or work done on a system) increases its potential energy. And Work done by a force (or work done by the system) decreases its potential energy
mass = 60.33kg
height = 3.96 m
work done = change in potential energy
= m*g*h
= 60.33* 9.8 * 3.96 = 2341.28 J
The work done by a person will be 2341.28 J
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Why might the measurements of ""true distances"" be different for different groups even though they are measuring the same distance?
While measuring , there are a lot of errors which can happen due to which ""true distances"" be different for different groups even though they are measuring the same distance.
While measuring , there are a lot of errors which can happen , to find the most correct value in order to make the result precise and accurate number of measurements needed to be done in order to reduce the error
As nothing can be measured with full precision and accuracy, different measurements for different groups even though they are measuring the same distance.
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How does the distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n?
The distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n because:
Option C: The energy difference between adjacent orbit radii decreases with increasing values of the principal quantum number.What determines the distance of the electrons from the nucleus?In an atom, an electron is known to be attracted to a given nucleus by the use of "electromagnetic force".
Note that similar to a baseball, the faster the electron is said to go, the farther away from the nucleus it is known to be seen. Therefore, the electrons in an atom are known to be in a state where they are moving a lot and very fast, so they are said to be far away from their nucleus.
Note also that energy difference between what we call consecutive levels tends to often decreases as well as increases.
Therefore, The distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n because:
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See full question below
Consider the hydrogen atom. How does the distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n?
The distance difference between adjacent orbit radii varies with increasing values of the principal quantum number.
The distance difference between adjacent orbit radii increases with increasing values of the principal quantum number.
The distance difference between adjacent orbit radii remains constant with increasing values of the principal quantum number.
The distance difference between adjacent orbit radii decreases with increasing values of the principal quantum number.
A CD has diameter of 110110 millimeters. When playing audio, the angular speed varies to keep the linear speed constant where the disc is being read. When reading along the outer edge of the disc, the angular speed is about 220220 RPM (revolutions per minute). Find the linear speed.
Answer: A CD has diameter of 110 millimeters. When playing audio, the angular speed varies to keep the linear speed constant where the disc is being read. When reading along the outer edge of the disc, the angular speed is about 220 RPM (revolutions per minute). Then, the linear speed of the disc will be 1.26 m/s.
Explanation: To find the answer we need to know about the uniform circular motion.
What is uniform circular motion?When a body moves in a circular path with a constant speed, it is said to be in uniform circular motion.The rate of change of angular displacement is called the angular velocity.Relation between angular velocity, linear velocity and the radius of revolution is given as,[tex]v=rw[/tex]
The relation between angular velocity and the frequency of revolution can be written as,[tex]w=2\pi f[/tex]
How to solve the problem?Given that the diameter of the disc as 110mm.Thus, the radius of the disc will be 55 mmThere are 220 revolutions per minute, thus the angular velocity w will be,[tex]w=2\pi f=2\pi *220 min^{-1}=1381.6 min^{-1}[/tex]
As we know that,[tex]1mm=10^{-3}m\\1min=60s\\thus,\\w=\frac{1381.6}{60} =23.02 s^{-1}.[/tex]
Thus, the linear speed will be,[tex]v=wr=23.02*55*10^{-3}=1.26 m/s[/tex]
Thus, we can conclude that the linear speed of the disc will be 1.26 m/s.
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Disclaimer: The question was given wrong in the given portal. Here is the correct question.
Question: A CD has diameter of 110 millimeters. When playing audio, the angular speed varies to keep the linear speed constant where the disc is being read. When reading along the outer edge of the disc, the angular speed is about 220 RPM (revolutions per minute). Find the linear speed.
As we adjust to low light, our ______ becomes nonfunctional and it may take ______ for rhodopsin to become regenerated sufficiently so that you can see well in low-light conditions.
As we adjust to low light, our cone becomes nonfunctional and it may take 20-30 min for rhodopsin to become regenerated sufficiently so that you can see well in low-light conditions.
Rhodopsin:The most prevalent protein in the retinal rod cells is rhodopsin, a G-protein coupled receptor. It consists of two components: an opsin molecule connected to an 11-cis-retinal chromophore, which serves as the main photoreceptor molecule of vision. When a photon of light excites 11-cis retinal, rhodopsin is linked to it. This isomerizes into an all-trans conformation.
Rhodopsin is crucial to our ability to see in low light because it enables the rods in our eyes to receive photons and detect light. As rhodopsin absorbs a photon, it separates into a retinal and an opsin molecule before slowly and at a constant rate recombining back into rhodopsin. But because this happens gradually, it takes some time for our eyes to get used to the dark. For humans, acclimating to the dark takes roughly 20 to 30 minutes.
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What is accurate about the planet’s climate system?
The accurate about the planet’s climate system is the wind
because heating near the equator blows the wind to drive the convection cells in the atmosphere, and the friction created by the rotation of the spherical planet in the atmosphere causes the wind to appear to bend left or right across the surface of the planet. ..
The climate system is a highly complex global system consisting of five major components: the atmosphere, the ocean, the cryosphere (cryosphere), the land surface, the biosphere, and the interactions between them.
Solar energy drives the climate by heating the surface of the earth unevenly. Ice also reflects incoming sunlight, further cooling the poles. Temperature differences move the ocean and atmosphere as they work together to disperse heat throughout the globe.
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Voltage-gated calcium ion channels that function in neurotransmission are primarily found on the:_________
Voltage-gated calcium ion channels that function in neurotransmission are primarily found on the: excitable cells
A neurotransmitter is the body’s chemical messenger. They are molecules that transmit signals from neurons to muscles, or between different neurons. The transmission of signals between two neurons occurs in the synaptic cleft.
The electrical signals that travel along the axon are briefly converted into chemical signals through neurotransmitters.
Voltage-gated calcium (Ca2+) channels are key transducers of membrane potential changes into intracellular Ca2+ transients that initiate many physiological events. There are ten members of the voltage-gated Ca2+ channel family in mammals, and they serve distinct roles in cellular signal transduction.
They are found in excitable cells, not only in motor neurons but also in other types of excitable cells .
Voltage-gated calcium channels are important mediators of depolarization-evoked release of neurotransmitters. To ensure efficient coupling of calcium influx to rapid vesicle release, calcium channels must be localized within the active zones of presynaptic nerve terminals
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A substance has life of 40 years. In how many years will the substance disintegrate to 1/8 of its initial size
Answer:
5 years
Explanation:
[tex]\frac{1}{8}(40)\\\\= 5[/tex]
Determine the lamp wattage required to obtain an illumination level of 50 f-c over a 100 ft2 area if a fixture is used with a CU of 0.75 and 80% of the available light reaches the work surface, the rest being absorbed by walls and other items in the space. Assume a luminous efficacy of 70 lumens/watt.
Lamp Wattage is utilized with a CU of 0.75 and 80 percent of the available light reaches the work surface, the remaining 20 percent is absorbed by walls and other objects in the space, resulting in an illumination level of 50 f-c over a 100 ft2 area
The term "lumen" refers to the emission of "luminous flux," which is a measurement of the total amount of visible light emitted by a source in a certain amount of time. The illumination level over a 100 ft2 area will be 50 f-c Lamp Wattage with a CU of 0.75 used, with 80 percent of the available light reaching the work surface and the remaining 20 percent being absorbed by walls and other objects in the room.
Total Lamp Wattage = Number of Lamps X Wattage of Each Lamp.
The fixtures' total wattage is 2 x 32, or 64 watts.
Lumen per Fixtures equals Lumen Efficiency (Lumen per Watt) times the Watt of each Fixture
85x 64 = 5440 lumens per fixture.
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What does the word apparent mean in apparent visual magnitude
The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.
What is visual magnitude?
The brightness of a celestial body is determined by eye estimation with or without optical aid or by other instrumentation equivalent to the eye in spectral sensitivity.
Apparent magnitude:
Apparent magnitude is a measure of how bright the star appears when viewed from Earth.It is a measure of the brightness of a star or other astronomical object observed from Earth. An object's apparent magnitude depends on its intrinsic luminosity and its distance from Earth.Hence,
The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.
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Arrange these objects according to size, largest to smallest. Group of answer choices traditional dwarf elliptical, ultra-compact dwarfs, globular clusters ultra-compact dwarfs, traditional dwarf galaxies, globular clusters globular clusters, traditional dwarf elliptical, ultra-compact dwarfs globular clusters, ultra-compact dwarfs, traditional dwarf elliptical
Among the given objects, the largest one is dwarf elliptical, then ultra-compact dwarf and then globular clusters. Thus, option a is correct.
To find the correct answer, we need to know about the galaxies.
Are galaxies bigger than globular clusters?Globular clusters are spherical groups of stars that are primarily located in the spiral galaxy' stellar halo. There are 150 or so globular clusters in our Milky Way galaxy, some of which house our galaxy's oldest stars.Globular clusters are much smaller than galaxies.a system of gas and dust, as well as millions or billions of stars, kept together by gravitational attraction is called galaxy.Ultracompact dwarfs are more extended and have higher surface brightness than typical dwarf nuclei.Dwarf elliptical galaxies are elliptical galaxies that are smaller than ordinary elliptical galaxies. They are quite common in galaxy groups and clusters and are usually companions to other galaxies.Thus, we can conclude that, option a is correct.
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A 1.75 kg box is pushed with a 8.35 N force across ground where k = 0.267. What is the net force on the box?
The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.
To find the answer, we have to know more about the basic forces acting on a body.
How to find the net force on the box?Let us draw the free body diagram of the given box with the data's given in the question.From the diagram, we get,[tex]N=mg\\F_t=ma\\F_t=F-f[/tex]
where, N is the normal reaction, mg is the weight of the box, [tex]F_t[/tex] is the net force, f is the kinetic friction.
We have the expression for kinetic friction as,[tex]f=kN=kmg=0.267*1.75*9.8= 4.58N[/tex]
Thus, the net force will be,[tex]F_t= 8.35-4.58=3.77N[/tex]
Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.
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The net force acting on the box is 3.77 N.
We need to learn more about the fundamental forces affecting a body in order to locate the solution.
How can I determine the box's net force?Let's use the information provided in the question to draw the free body diagram of the given box.The diagram gives us,[tex]N=mg\\F_n=F-f[/tex]
where N stands for the normal reaction, mg for the box's weight, is the net force, and f for kinetic friction.
The kinetic friction expression is as follows:[tex]f=kN=kmg=4.58N[/tex]
the net force will be as follows:[tex]F_n=3.77N[/tex]
Thus, it is clear that the box with a mass of 1.75 kg will experience a net force of 3.77 N when it is pushed across a surface with a coefficient of friction of 0.264.
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The period of a satellite, the time it takes for a complete revolution, depends on the satellite's: _________
The period of a satellite, the time it takes for a complete revolution, depends on the satellite's mass of planet and the distance of satellite form center of the planet .
According to the question
The period of a satellite, the time it takes for a complete revolution, depends on the satellite's:
1. The mass of the planet being orbited
2. The distance of the satellite from the center of the planet.
Hence, The period of a satellite, the time it takes for a complete revolution, depends on the satellite's mass of planet and the distance of satellite form center of the planet .
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If a 100 ω resistor is placed across a 0. 10 μf charged capacitor which is initially charged to 3 v. How long does it take it to discharge to 2v to 1v?
1. The time taken to discharge to 2 V is 2×10⁻⁹ s
2. The time taken to discharge to 1 V is 5×10⁻¹⁰ s
Energy stored in a capacitorThe energy stored in a capacitor is given by
E = ½CV²
But
E = Pt
Thus,
Pt = ½CV²
Where
E is the energy C is the capacitorV is the voltageP is the power t is the timeWith the formula (Pt = ½CV²), we can determine the time in each case. Detail below:
1. How to determine the time required to discharge to 2 VData obtained from the question include:
Power (P) = 100 wCapacitor (C) = 0.10 μF = 1×10⁻⁷ FVoltage (V) = 2 VTime (t) = ?Pt = ½CV²
100 × t = ½ × 1×10⁻⁷ × 2²
Divide both sides by 100
t = (½ × 1×10⁻⁷ × 2²) / 100
t = 2×10⁻⁹ s
Thus, the time required to discharge to 2 V is 2×10⁻⁹ s
2. How to determine the time required to discharge to 1 VData obtained from the question include:
Power (P) = 100 wCapacitor (C) = 0.10 μF = 1×10⁻⁷ FVoltage (V) = 1 VTime (t) = ?Pt = ½CV²
100 × t = ½ × 1×10⁻⁷ × 1²
Divide both sides by 100
t = (½ × 1×10⁻⁷ × 1²) / 100
t = 5×10⁻¹⁰ s
Thus, the time required to discharge to 1 V is 5×10⁻¹⁰ s
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A graph with vertical axis Energy Unit and horizontal axis Amplitude Unit. A line goes in straight segments from 1 16 to 2 9 to 4 1.
Tara prepared a report to show how the amplitude of waves affects the energy of waves. Is her graphical representation correct? Why or why not?
The graphical representation of Tara is correct because of energy of the wave depends on the amplitude of the wave.
Energy of a waveThe energy of a wave due to the motion of a spring is calculated as follows;
E = ¹/₂KA²
where;
k is the force constant of the springA is the amplitude of the waveThus, the graphical representation of Tara is correct because of energy of the wave depends on the amplitude of the wave.
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Answer: No, it is not correct because as the amplitude of a wave increases, the energy it carries also increases. This graph shows that as the amplitude increases, the energy decreases.
Explanation:
A pulley system is used to lift a 4500 n weight using a 900 n force. if the mass moves 1.0m while the pulley is pulled 6.0m, what is the efficiency of the machine?
The efficiency of the machine is determined as 83.3 %.
Mechanical advantage of the pulley
M.A = load/Effort
M.A = 4500/900 = 5
Velocity ratio of the pulleyV.R = distance moved by effort/distance moved by load
V.R = 6/1 = 6
Efficiency of the pulleyE = M.A/V.R x 100%
E = (5/6) x 100%
E = 83.3 %
Thus, the efficiency of the machine is determined as 83.3 %.
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a 1200 kg car rolling on a horizontal surfact has a speed of 25 m/s when it strikes a horizontal coiled spring and is brought ot rest in a distance of 2.5m. what is the spring constant of this spring
The required spring constant:
The spring constant of the spring is [tex]12\times 10^4 \text{ N/m}[/tex].
Calculation:
The mass of the car is m=1200 kg, the speed of the car is v=25 m/s, and after colliding the spring is brought to rest at a distance of x=2.5m. Let the spring constant of the spring is, k.
From the conservation of energy,
Total initial kinetic energy= Total final potential energy of the spring
Therefore,
[tex]\frac{1}{2}mv^2=\frac{1}{2}kx^2[/tex]
Now, substituting the values of the mass of the car, speed of the car, and displacement, we get:
[tex]$$\begin{aligned}1200\times(25)^2&=k\times (2.5)^2\\\Rightarrow k&=\frac{1200\times(25)^2}{(2.5)^2}\\&=12\times 10^4 \text{ N/m}\end{aligned}$$[/tex]
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If the platinum-based engine is run continuously at 300 k for 1 hour with 0.50 atm of h2 and 0.50 atm of o2 injected for each reaction, approximately what mass of water will be produced?
About 4.5 mol of water will be created when the platinum-based engine is run continuously at 300 K for an hour with 0.5 atm of H2 and 0.5 atm of O2 injected for each reaction.
For fuel cell engines' electrodes, platinum is a requirement. It acts as an electrocatalyst to speed up the electrochemical reactions needed to induce H2 to release electrons and form H2 ions when it is placed on porous electrodes.
Platinum is particularly well suited as a fuel cell catalyst because it makes it possible for the hydrogen and oxygen reactions to occur at an ideal rate and because it is stable enough to withstand both the intense electrical current density and the complex chemical environment found inside a fuel cell. This allows platinum to function effectively over an extended period of time.
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