The question below give me used to determine h, The high in feet of a model rocket t seconds after it is launched from a roof that is 48 feet in height.
H=-16t^2+128t+48
Which equation reveals the maximum height reached by the model rocket?
Choices/answers^^
Answers
Answer: the answer is B.
Step-by-step explanation:
The correct equation which reveals the maximum height reached by the model rocket is,
h = - 16 (t + 4)² - 304
What is Quadratic equation?
An equation of order 2 in highest variable is called a Quadratic equation.
Given that;
The equation is,
H = -16t² + 128t + 48
Now, The equation which reveals the maximum height reached by the model rocket is find as;
H = -16t² + 128t + 48
h = -16(t² + 8t) + 48
h = -16 (t² + 8t) + 256 - 256 + 48
h = -16 (t² + 8t + 16) + 256 + 48
h = -16 (t + 4)² + 304
Thus, The correct equation which reveals the maximum height reached by the model rocket is,
h = - 16 (t + 4)² - 304
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Step-by-step explanation:
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Hope this helps
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Answer:
Step-by-step explanation:
i )
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1)
The discovery probabilities of 1, 2 or 3 companies must be added. (0.40 x 0.40 x 0.80 + 0.60 x 0.60 x 0.80 + 0.60 x 0.40 x 0.20) + (0.48 x 0.60 x 0.80 + 0.40 x 0.60 x 0.20 + 0.60 x 0.60 x 0.20) + (0.40 x 0.60 x 0.20) + (0.40 x 0.60 x 0.20) (0.128 + 0.288 + 0.048) + (0.2304 + 0.048 + 0.072) + 0.048 = X 0.464 + 0.3504 + 0.048 = X 0.8624 = X
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Sorry, can you tell me in Spanish, I don't understand much English, I really want to help you, can you do what I told you? Thanks