Answer:
TRUE IS THE ANSWER
Step-by-step explanation:
The name of the circle pictured is circle C is True statement.
What is Circle?A circle is a collection of points in a plane that are all equally spaced apart from one another. The radius is the distance from the centre, while the centre is the location of the point. The diameter is defined as twice the radius. A complete angle, which is equal to or radians, is the angle that a circle subtends from its centre.
we have a graph for a circle.
We know a circle many parts such as Center, Radius, Diameter, Chord, etc.
A circle usually know from its Center.
Also, the center of circle shows the point of circle.
Thus, the given statement is True.
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I. Read each question carefully, then write the letter of the correct answer.
1. What is the relationship of the volume between a prism and a pyramid of the same dimensions?
A. the volume of the pyramid is 2/3 of the volume of the prism
B. the volume of the pyramid is 3/3 of the volume of the prism
C. the volume of the pyramid is 1/3 of the volume of the prism
D. the volume of the pyramid is 3/2 of the volume of the prism
2. The volume of a cone is the volume of a cylinder if both are of the same dimensions.
A. double B. thrice
C. twice
D. 4 times
3. How many cones can fill the whole sphere with the same dimension?
A. 1
B. 2
C.3
D.4
4. If the volume of a cylinder is 120 m3, what will be the volume of a cone with the same dimension?
A.180m3
B. 60 m3
C. 40 m3
D. 30 m3
5. What is the length of the edge of a cube if it has a volume of 27 cubic inches?
A. 9 in
B. 6 in
C. 3 in
D. 2 in
Answer:
The answer for number 1 is C
For the straight line defined by the points (2,57) and (4,83), determine the slope (m) and y-intercept (b).
Step-by-step explanation:
the answer is in the image above
HELP HELPPP!!!у- 3
|
у+
у- 3
3
What is the common denominator of y+
3
in the complex fraction
5 2
9* Зу
?
Зу(у – 3)
у(у – 3)
Зу
О 3
Answer:
The common denominator of [tex]y + \frac{y-3}{3}[/tex] is 3
Step-by-step explanation:
Given
The complex fraction
Required
The common denominator
To solve this, we need not consider the whole complex fraction.
We only consider
[tex]y + \frac{y-3}{3}[/tex]
Take LCM
[tex]y + \frac{y-3}{3} = \frac{3y - (y-3)}{3}[/tex]
Single out the denominator, i.e. 3
Hence, the common denominator of [tex]y + \frac{y-3}{3}[/tex] is 3
A rocket is launched from the ground and travels in a straight path. The angle of inclination of the rocket's path is 1.2 radians. (That is, the rocket's path and the ground form an angle with a measure of 1.2 radians.)]
Required:
a. What is the slope of the rocket's path?
b. If the rocket has traveled 85 yards horizontally since it was launched, how high is the rocket above the ground? _____yards.
c. At some point in time, the rocket is 313 yards above the ground. How far has the rocket horizontally (since it was launched) at this point in time? _____yards
Answer:
a)[tex]S=2.57[/tex]
b)[tex]H=203.2yard[/tex]
c)[tex]X=121.79yards[/tex]
Step-by-step explanation:
From the question we are told that:
Angle [tex]\theta=1.2=68.755^o[/tex]
a)
Generally the equation for Slope is mathematically given by
[tex]S=tan \theta[/tex]
[tex]S=tan 68.755[/tex]
[tex]S=2.57[/tex]
b)
Given the right Angle triangle with horizontal distance [tex]x=85yard[/tex]
Generally the equation for Height traveled is mathematically given by
[tex]H=tan\theta*x[/tex]
[tex]H=2.57*85[/tex]
[tex]H=218.45[/tex]
[tex]H=203.2yard[/tex]
c)
Generally the equation for Horizontal Distance traveled at 313 height traveled is mathematically given by
[tex]X=\frac{313}{tan65.75}[/tex]
[tex]X=\frac{313}{2.57}[/tex]
[tex]X=121.79yards[/tex]
Using the projectile principle, the slope of the rockets path, height above the ground and the distance traveled at a height of 313 yards would be 2.57, 218.63, 121.69 respectively.
Given the Parameters :
Angle of inclination = 1.2 radianConverting to degree :
θ = 1.2 rads × 180/π = 68.755°A.)
The slope of the rocket's path :
Slope = tanθSlope = tan(68.755) = 2.57
B.)
Horizontal distance, = distance along the x-axis = 85 yards
Vertical distance = height = distance along y-axis, y
y = tanθ × xy = slope × x
y = tan(68.755) × 85
y = 218.63 yards
C.)
Vertical distance, y = 313 yards
From :
[tex] y = x tan\theta [/tex]
[tex] x = \frac{y}{tan\theta} [/tex]
[tex] x = \frac{313}{tan(68.755°)} [/tex]
x = 121.69 yards
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Cómo chica quiere armar sus propios lindos para una galería de arte los cuadros deben ser de forma cuadrada así que todos los lados deben de medir los mismos y una amiga le donó dos trozos de madera de 128 cm y 224 cm respectivamente qué tan grande es podrían ser los lados sin que sobre madera?
ppose we are testing a new shampoo to see if it makes hair grow faster. We knowthat the average rate of hair growth is 0.5 inches per month. The hypothesis are as follows:H0:m0:5vs.H1:m>0:5. Suppose that the null hypothesis is not rejected and that thereal truth is that the shampoo actually does make hair grow faster. What type of error, if any,occurred?
Answer:
Type II error occurred
Step-by-step explanation:
It is given that a new shampoo is being tested to determine whether the hair grows faster by using this shampoo.
It is known that hair grow at 0.5 inches per month at average.
The hypothesis are,
Null hypothesis, [tex]$H_0: \mu=0.5$[/tex]
Alternate hypothesis, [tex]$H_1: \mu>0.5$[/tex]
But it is known that :
Type [tex]$I$[/tex] error occurs when rejecting the null hypothesis when the null hypothesis is true actually.
Type [tex]$II$[/tex] error occurs [tex]\text{when we fail reject the null hypothesis}[/tex] when the null hypothesis is actually false.
Now here since the null hypothesis is not been rejected, type [tex]$II$[/tex] error had occurred.
write the other side of this equation so its true for all values of x: 1/2(6x-10)-x=
9514 1404 393
Answer:
2x -5
Step-by-step explanation:
Any equivalent expression can be used. It is perhaps easiest just to simplify the given expression.
1/2(6x -10) -x = 3x -5 -x = 2x -5
Putting 2x-5 on the right will give an equation true for all x.
1/2(6x -10) = 2x -5
a bag contains 16 red coins , 8 blue coins , and 8 green coins. A player wins by pulling a red coin from the bag. Is this game fair? Justify your answer
Answer:
Step-by-step explanation:
there are a total of 16+8+8=32 coins in bag
16 out of 32 are red
player wins by pulling a red coin
assume it is a single pull, the winning probability = 16/32 = 1/2
so it is 50/50 chance n hence a fair game
Step-by-step explanation:
yes it is a fair game because any one don't know what the coin will get, it is based on luck
I need help I’ll mark u as brainlest
Answer:
105 in³
Step-by-step explanation:
Volume of triangular prism = base area * height
here
base area = (10*7)/2 = 35
height = 3
Volume = 35* 3 = 105
Determine if segment AB is tangent to the circle.
Answer: Segment AB is tangent to the circle
Step-by-step explanation:
3 sides are 16, 20, and 12
If angle a is 90 then ab is tangent
now check using Pythagorean theorem
since 12^2 + 16^2 =20^2, this means angle a is a right angle meaning segment AB is tangent to the circle
In an experiment, equal amounts of heated water and soil were left to cool down. The initial and final temperatures of each were recorded. A partial record of the temperature is shown. Experimental Record Substance Initial Temperature Final Temperature Water 27 °C 24 °C Soil 27 °C ? Which statement about the final temperature of soil is correct? (3 points) It will be less than 24 °C as soil loses heat relatively faster than water. It will be less than 24 °C as water loses heat relatively faster than soil. It will be more than 24 °C as it takes relatively longer to change soil temperature than water temperature. It will be more than 24 °C as it takes relatively longer to change water temperature than soil temperature.
Answer:less than 24 °C as soil loses heat relatively faster than water. It will be less than 24 °C as water loses heat relatively faster than soil. It will be more than 24 °C as it takes relatively longer to change soil temperature than water temperature. It will be more than 24 °C as it takes relatively longer to change water temperature than soil temperature.
Step-by-step explanation:
less than 24 °C as soil loses heat relatively faster than water. It will be less than 24 °C as water loses heat relatively faster than soil. It will be more than 24 °C as it takes relatively longer to change soil temperature than water temperature. It will be more than 24 °C as it takes relatively longer to change water temperature than soil temperature.
Trong một lớp học có 50 sinh viên. Hỏi có bao nhiêu cách bầu ra một ban cán sự lớp gồm 3 người: 1 lớp trưởng, 1 lớp phó, 1 bí thư và không kiêm nhiệm chức vụ.
Answe
SI Si olla amigo lel just spammin here
Step-by-step explanation:
You deposit $10,000 in an account that pays 4.5% interest compounded quarterly. Find the future value after one year.
Answer:
11800
Step-by-step explanation:
4.5%=0.045
0.045x10,000=450
450x4(quarterly)=1800
10,000+1800= 11800
Answer:
After 1 year, $10,457.65
Step-by-step explanation:
P = $ 10, 000
r = 4.5% = 0.045
T = 1 year
n = 4 ( compounded quarterly )
[tex]A = P( 1 + \frac{r}{n})^{nt}[/tex]
[tex]= 10000( 1 + \frac{0.045}{4})^{4 \times 1}\\\\=10000 \times 1.01125^{4}\\\\= 10000 \times 1.04576508633\\\\= 10457.6508633\\\\= \$ 10, 457.65[/tex]
1.) If I am selling a dozen at $3, how much would each egg cost?
2.) If each egg costs that amount of money, how much would an 18 pack be?
I'm trying to figure this out because this is a real-life problem, and I'm trying to sell eggs to my teacher.
Answer:
1.$3÷12=0.25
each egg would cost 25 cents
2.12×18=216
216×25=5,400
Construct a frequency polygon that represents the following data regarding the selling prices of houses sold in 2006 for a particular neighborhood find the midpoint
Class Frequency
78787 – 98786 9
98787 – 118786 8
18787 – 138786 9
138787 – 158786 4
158787 – 178786 8
Answer:
See attachment for polygon
Step-by-step explanation:
Given
[tex]\begin{array}{cc}{Class} & {Frequency} & 78787 - 98786 & 9 &98787 - 118786 & 8 & 118787 - 138786 & 9 & 138787 - 158786 & 4 & 158787 - 178786 & 8 \ \end{array}[/tex]
Required
The frequency polygon
First, we calculate the midpoint of each class.
This is the average of the class limits
So, we have:
[tex]x_1 = \frac{78787 + 98786}{2} = \frac{177573}{2} = 88786.5[/tex]
[tex]x_2 = \frac{98787 + 118786}{2} = \frac{217573}{2} = 108786.5[/tex]
----
--
-
[tex]x_5 = \frac{158787 + 178786}{2} = \frac{337573}{2} = 168786.5[/tex]
(138787 + 158786)/2
So, the table becomes:
[tex]\begin{array}{ccc}{Class} & {Frequency} & {x} &78787 - 98786 & 9 & 88786.5 & 98787 - 118786 & 8 & 108786.5 & 118787 - 138786 & 9 & 128786.5 & 138787 - 158786 & 4 & 148787.5 & 158787 - 178786 & 8 & 168786.5\ \end{array}[/tex]
See attachment for frequency polygon
The mid point of the line segment joining the points A(4,7) and B(2,5)
Answer:
hope it helps you.......
It May Help You
Thank You:)
A man, 1.5m tall, is on top of a building. He observes a car on the road at an angle of 75°. If the building is 30m, how far is the car from the building?
Answer:
The answer to this question is 8.44 m.
Step-by-step explanation:
This problem is best illustrated in the photo below.
First, we must know that the angle stated in the problem is the angle of depression. Angle of depression is the angle between the horizontal and the line of sight of the observer. On the other hand, if the observer is looking upward, then the angle between the horizontal and his line of sight is called the angle of elevation.
Since we have the given angle of depression, we must use its complementary angle to solve for the distance of the car from the building.
Let x = complementary angle of 75°
y = distance of the car from the building
To solve for x,
To solve for y, we need to use a trigonometric function that will relate the adjacent of 15° and the opposite of 15°. Let us look at the mnemonics
SOH: Sine =
CAH: Cosine =
TOA: Tangent =
Therefore we must use the tangent function to solve for y.
Low concentrations of EDTA near the detection limit gave the following dimensionless instrument readings: 175, 104, 164, 193, 131, 189, 155, 133, 151, and 176. Ten blanks had a mean reading of 50.0. The slope of the calibration curve is 1.75 x 10^-9 M^-1.
a. Estimate the signal detection limit for EDTA.
b. What is the concentration detection limit?
c. What is the lower limit of quantification?
Answer:
Step-by-step explanation:
From the given information:
The mean of the readings is:[tex]=\dfrac{175+104+164+193+131+189+155+133+151+ 176}{10}[/tex]
[tex]= \dfrac{1571}{10}[/tex]
= 157.1
The standard deviation (SD) can be computed by using the expression:
[tex]SD =\sqrt{ \dfrac{\sum_f(x_i - \bar x)^2}{n-1}}[/tex]
[tex]SD =\sqrt{ \dfrac{(175-157.1)^2+(104-157.1)^2+(164-157.1)^2+...+(176-157.1)^2}{10-1}}[/tex]
Standard deviation = 28.195
∴
FOr the EDTA complexes;
The signal detection limit = (3*SD) + [tex]y_{blanks}[/tex]
= (3*28.195) + 50
= 84.585 + 50
= 134.585
We need to point out that the value of the calibration curve given is too vague and it should be (1.75 x 10^9 M^-1) as oppose to (1.75 x 10^-9 M^-1)
The concentration of detection limit is:
[tex]=\dfrac{3 \times SD}{slope }[/tex]
[tex]=\dfrac{3 \times 28.195}{1.75 \times 10^{9} \ M^{-1} }[/tex]
[tex]\mathbf{= 4.833\times 10^{-8} \ M}[/tex]
The lower limit of quantification is:
[tex]=\dfrac{10 \times SD}{slope }[/tex]
[tex]=\dfrac{10 \times 28.195}{1.75 \times 10^{9} \ M^{-1} }[/tex]
[tex]\mathbf{= 1.611 \times 10^{-7} \ M}[/tex]
bine like terms.
7 – 64 – 5x3 – 1 + x3 – 7 – 2y
PLS HURRY
Answer:
-4x³ - 8y - 1
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
7 - 6y - 5x³ - 1 + x³ - 7 - 2y
Step 2: Simplify
[Addition] Combine like terms (x³): -4x³ + 7 - 6y - 1 - 7 - 2y[Subtraction] Combine like terms (y): -4x³ - 8y + 7 - 1 - 7[Subtraction] Combine like terms: -4x³ - 8y - 1I need help with this!
Answer:
1. y=5 x=1
2. y=4 x=4/5
3. y=2 x=2/5
Step-by-step explanation:
Plug the y-values in for y:
1. 5=5x
2. 4=5x
3. 2=5x
Then solve for x:
1. x=1
2. x=4/5
3. x= 2/5
Hope this helps!
Ivy is competing in a 400 m race.
She runs at a constant speed of 5.4 m/s for the first 150 m, then 4.5 m/s for 40 seconds.
The remainder of the race takes her 34 seconds to complete.
What is Ivy's average speed for the entire race to 1 dp?
Answer:
4.5m/s
Step-by-step explanation:
4.5x40=180
180+150=330
400-330=70
70/34=2.05882352941
(2.05882352941x70)+(5.4x150)+(4.5x180)=1791.11764706
1791.11764706/400=4.47779411765
4.47779411765=4.5
4.5m/s
Answer:
Average speed = 3.9 m /s
Step-by-step explanation:
Total distance = 400m
First 150m = 5.4m/s
[tex]speed = \frac{distance}{time} \\\\time = \frac{distance}{speed} = \frac{150}{5.4} = 27.78 \ s[/tex]
Second part :
S = 4.5m/s for 40s
[tex]Distance = speed \times time = 4.5 \times 40 = 180 \ m[/tex]
Third part :
Remaining distance = 400 - 150 -180 = 70m
Time taken to cover it = 34s
[tex]speed = \frac{distance}{time} = \frac{70}{34} = 2.05 \[/tex]
Speed = 2.05m/s
Find average speed
[tex]Average\ speed = \frac{total \ distance }{total \ time \ taken } \\\\Average \ speed = \frac{400}{101.78} = 3.93 \ mps[/tex]
Round to 1 dp => average speed = 3.9m /s
Simplify this algebraic expression.
Z-4/4+8
O A. Z+7
O B. z+ 9
O c. z-3
O D. Z-7
Answer:
Z +7
Step-by-step explanation:
Z-4/4+8
Divide first
Z -1 +8
Add and subtract
Z +7
Which of the following equations is NOT an example of inverse variation?
I. f(x)=kx
II. f(x)=2kx
f
(
x
)
=
2
k
x
III. f(x)=−kxz
Based on the equation,the equation which is not an inverse variation is f(x) = kx
Inverse variationf(x) = kx
= k × x
f(x) = 2k/x
= k(2/x)
f(x) = -kx/z
= k(-x/z)
Inverse variation is given by:
y = k(1/x)
where,
k = constant of proportionalityTherefore, f(x) = kx is not an inverse variation.
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I need help resolving this please
27x^6 = 387420489
You want something similar but cubed.
[tex]\sqrt[3]{387420489}[/tex] = 729
YOUR ANSWER: 729x^3 = 387420489
Step-by-step explanation:
look at attachment below
please help steps thx
Answer:
240 cubic metres
Step-by-step explanation:
I'm not really sure for Q17 but I do know Q18.
Q18. Volume of cuboid = Length×Breadth×Height
=12×4×5
=240 cubic metres
hope it helps!!!
Which function is increasing and has a domain of (1,∞ )
The graph of a square root function has a domain of (0, ∞) and range of [1, ∞).
Answer:
f(x)=log(x-1)+2
Step-by-step explanation:
I did the test on plato and got it right.
What are the 2 \ 3 parts of a right angle in a whole wheel?
Answer:
[tex]\frac{2}{3} \ part \ of \ right \ angle \ is \ \frac{1}{6} \ part \ of \ a \ whole \ wheel.[/tex]
Step-by-step explanation:
[tex]\frac{2}{3} \ of \ a \ right \ angle \ = \frac{2}{3} \times 90^{\circ} = 60^{ \circ}\\\\A \ whole \ wheel \ is \ = 360^ {\circ}\\\\[/tex]
Now to find what part of 360 is 60 :
[tex]Let \ it \ be \ x\\\\x \times 360 = 60 \\\\x = \frac{60}{360} = \frac{1}{6}[/tex]
Therefore ,
[tex]\frac{2}{3} \ part \ of \ right \ angle \ is \ \frac{1}{6} \ part \ of \ a \ whole \ wheel.[/tex]
An item costs $370 before tax and the sales tax is $11.10. Find the sales tax rate::Write your answer as a percentage.
Answer:
3%
Step-by-step explanation:
Cost x sales tax rate =tax
370 x sales tax rate = 11.10
sales tax rate =11.10/370
sales tax rate=.03 or 3%
The sales tax rate is 3% if an item costs $370 before tax and the sales tax is $11.10.
What is the percentage?The percentage is defined as a ratio expressed as a fraction of 100.
To determine the sales tax rate, we need to divide the amount of sales tax paid by the cost of the item before tax and then multiply the result by 100% to express it as a percentage.
As per the question, the amount of sales tax paid is $11.10, and the cost of the item before tax is $370. Therefore, the sales tax rate is:
sales tax rate = tax paid / (cost of the item before tax) x 100%
sales tax rate = $11.10 / $370 x 100%
Apply the division operation,
sales tax rate = $0.03 x 100%
Apply the multiplication operation,
sales tax rate = 3%
Therefore, the sales tax rate is 3%.
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Có 7 cây hãy trồng thành 6 hàng, mỗi hàng 3 cây?
Answer:
Step-by-step explanation:
Bạn vẽ 1 tức giác ABCD lồi sau đó nối AB và CD cắt nhau tại E, AD và BC cắt nhau tại F, AC và BC cắt nhau tại G. Trồng 7 cây vào các điểm ABCDEFG l. Ta có sáu hàng là ABE, DCE, BCF, ADF, ACG, BDG