The amount of carbon dioxide in the air is increasing in a large city due to the growing number of vehicles. The mayor wants to plant more trees. I totally agree with the mayor's suggestions.
Growing number of vehicles contributes towards carbon emissions into the atmosphere. Driving a car with gasoline as its fuel produces three carbon emissions. All of the emissions that take place across a company's value chain and are not covered by scope 2.
These emissions aren't caused by the business or the things it makes. Carbon emissions from operating a gasoline-powered vehicle are significant. Scope 3 applies since the product, not the company's machines, is what causes the emissions. There are three types of carbon emissions: 'Scope 1' or 'Direct Emissions' Direct GHG is produced at sources where the fuel is burned there and then. Examples of scope 1 emissions are personal automobiles and gas stoves. Planting more trees will result in minimizing the harmful effect of these gases upon the environment.
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1. Several solids, liquids, and gases can be found in your home. List three examples of each. (9 points) Think about where solids, liquids, and gases might be found in your refrigerator, bathroom, or basement/garage.
2. What states of matter exist within the human body? What state of matter do you think your body is mostly made up of? Why? (4 points) Think about whether the body contains solids, liquids, or gases. Which of the three would you be most likely to find?
3. Your blood contains many dissolved solids. What do you think could be done if you needed to remove the water from a sample of blood in order to study the solids that remained? (4 points) Think about what processes remove water from watery foods, solutions, or objects.
4. Your body contains a considerable amount of dissolved metal ions. Based on what you know about food and nutrition, list at least three metals you think could be found within the human body. (3 points) Refer to the periodic table — do any of the metal element names seem familiar? (Think about the ingredients list printed on food labels.)
1. Examples of solids, liquids, and gases found in a home
Solids: books, furniture, toys
Liquids: water, juice, shampoo
Gases: air, natural gas, propane
2. The human body contains solids, liquids, and gases. Solids include bones, muscles, and organs. Liquids include blood, saliva, and urine. Gases include air in the lungs and dissolved gases in the bloodstream. The body is mostly made up of liquids, as they make up a large percentage of its overall volume.
3. If you needed to remove the water from a sample of blood to study the solids that remained, you could use a process such as evaporation or freeze-drying. Evaporation involves heating the sample to allow the water to evaporate, leaving behind the solids. Freeze-drying involves freezing the sample and then removing the water under vacuum, leaving behind a dry solid.
4. Some metals that could be found within the human body include iron, zinc, and copper. These metals are commonly found in foods such as meat, seafood, nuts, and whole grains. Other metals such as calcium, magnesium, and potassium are also important for the body and are found in a variety of foods.
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50 POINTS
Choose an organism. Using at least 5 sentences, describe why your specific organism could have siblings that share the same parents, but might have different traits. Why might they be different? Give specific examples of traits that might be different.
Answer:
One possible organism that I can choose is a dog. A dog is an animal that belongs to the kingdom Animalia, the phylum Chordata, and the class Mammalia.
A dog could have siblings that share the same parents, but might have different traits because of genetic variation.
Genetic variation is the difference in DNA sequences among individuals of the same species
It can result from mutations, recombination, or random assortment of chromosomes during meiosis
Some examples of traits that might be different among dog siblings are coat color, eye color, size, shape, and temperament
These traits are influenced by both genes and environment
Explanation:
is that good?
Why should we learn to use a fire extinguisher before doing practical work in the laboratory?
It is essential to learn the usage of fire extinguishers before doing practical work in the laboratory as a fire can arise at any time.
Before performing practical work in lab, learning how to use a fire extinguisher is crucial because fires can happen unexpectedly in a lab. This can be due to variety of reasons, including electrical faults, chemical reactions, or human error. Understanding how to use a fire extinguisher can assist keep small fires from escalating and harming people, property, or the lab itself.
Aside from that, different fires call for various fire extinguishers. For example, it is best to avoid using water-based fire extinguishers on electrical or chemical fires since they may worsen the situation. It is crucial to understand how to choose and utilise the appropriate fire extinguisher for the sort of fire that can develop in the laboratory.
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A compound contains 87.4 percent nitrogen and 12.6 percent hydrogen. If the molecular mass of the compound is 32.05 g/mol, what is the molecular formula?
The molecular formula is twice the empirical formula which is (NH₂)₂ or N₂H₄.
How to determine molecular formula?To determine the molecular formula of the compound, find the empirical formula first. The empirical formula gives the simplest whole number ratio of atoms present in a compound.
Assuming we have 100 g of the compound, then 87.4 g of it is nitrogen and 12.6 g of it is hydrogen:
moles of N = 87.4 g / 14.01 g/mol = 6.24 mol
moles of H = 12.6 g / 1.01 g/mol = 12.5 mol
Find the simplest whole number ratio of moles of nitrogen to moles of hydrogen. To do this, we divide both values by the smaller one (in this case, 6.24 mol):
moles of N / 6.24 = 6.24 mol / 6.24 mol = 1
moles of H / 6.24 = 12.5 mol / 6.24 mol = 2
So the empirical formula is NH₂.
To find the molecular formula, know the molecular mass of the compound
The molecular mass of the compound is given as 32.05 g/mol. The empirical formula mass of NH₂ is:
empirical formula mass = 14.01 g/mol + 2(1.01 g/mol) = 16.03 g/mol
The molecular formula mass is a multiple of the empirical formula mass, divide the molecular mass by the empirical formula mass to find the multiple:
molecular mass / empirical formula mass = 32.05 g/mol / 16.03 g/mol = 2
Therefore, the molecular formula is twice the empirical formula:
(NH₂)₂ or N₂H₄.
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which environment would best support large land animals like giraffes elephants and lions
The savanna grassy plain environment would best support large land animals like giraffes elephants and lions.
A dry climate with a distinct wet and dry season, as well as moderate to high temperatures is observed in savannas. Grass species which can withstand seasonal droughts and frequent fires, predominate in savanna vegetation. Although they are more widely spaced than in other forested environments, trees and shrubs are still present.
Large land animals thrive in the savanna because it offers a variety of food sources, such as grasses, leaves and fruits, as well as plenty of room to move around and find resources. Animals can see each other clearly and communicate effectively in the open grasslands and the scatted trees and shrubs provide shelter from the sun and wind.
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How many grams are produced when 2.3moles of water is synthesized from hydrogen and
oxygen gas? 2H2 + O2 à 2H2O
When 2.3 moles of water are synthesized from hydrogen and oxygen gas, 2.313 grams of hydrogen gas and 18.4 grams of oxygen gas are consumed to produce the water.
The balanced chemical equation for synthesis of water from hydrogen and oxygen gas:
[tex]2H_2 + O_2[/tex] → [tex]2H_2O[/tex]
2 moles of hydrogen gas = 2 moles of water
Therefore:
(2.3 moles/2 moles) = 1.15 moles of hydrogen gas
1 mole of hydrogen gas = 2.02 g/mol of molar mass
= (1.15 moles x 2.02 g/mol) = 2.313 g
0.5 moles of oxygen gas = 2 moles of water
Therefore:
(0.5 moles/2 moles) = 0.575 moles of oxygen gas
1 mole of oxygen gas = 32 g/mol
Therefore: (0.575 moles x 32 g/mol) = 18.4 g
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4. Calculate the number of moles in each of the following quantities:
b. 1.06 x 1023 atoms of tungsten
The number of mole in 1.06×10²³ atoms of tungsten is 0.176 mole
How do i determine the number of mole?The following data were obtained from the question:
Number of atoms = 1.06×10²³ atomsNumber of mole =?The number of mole that contains 1.06×10²³ atoms of tungsten can be obtained as illustrated below:
From Avogadro's hypothesis,
6.022×10²³ atoms = 1 mole of substance
Thus, we can say that
6.022×10²³ atoms = 1 mole of tungsten
Therefore,
1.06×10²³ atoms = (1.06×10²³ atoms × 1 mole) / 6.022×10²³ atoms
1.06×10²³ atoms = 0.176 mole of tungsten
Thus, we can conclude from the above calculation that the number of mole is 0.176 mole
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Why is listing information an important scientific skills?
Answer:
to be able to understand where your data and work came from
Explanation:
Which tides would Earth be experiencing if the sun, Earth and moon are lined up?
Answer: extra-high high tides, and very low, low tides
Explanation: When the sun, moon, and Earth are in alignment (at the time of the new or full moon), the solar tide has an additive effect on the lunar tide, creating extra-high high tides, and very low, low tides—both commonly called spring tides.
What is the mass of 1.78 moles of O2
Answer:
56.96 grams
Explanation:
To find the mass of 1.78 moles of O2, we need to use the molar mass of O2, which is the mass of one mole of O2.
The chemical formula for O2 is O-O or simply O2. The molar mass of O2 is the sum of the atomic masses of two oxygen atoms, which can be found on the periodic table.
The atomic mass of oxygen (O) is approximately 16.00 g/mol. So the molar mass of O2 is:
Molar mass of O2 = 2 x atomic mass of O
= 2 x 16.00 g/mol
= 32.00 g/mol
Therefore, the mass of 1.78 moles of O2 is:
Mass = number of moles × molar mass
= 1.78 mol × 32.00 g/mol
= 56.96 g
So the mass of 1.78 moles of O2 is 56.96 grams.
Ms Explorer has deaf and blind learners in her class. How can she
accommodate these learners in the chat group?
Answer:
i going off the top of my head
Explanation
Interpreters: They facilitate communication between a deaf and hearing person in different modalities, such as ASL, tactile interpretation, or Cued Speech.
Speech-to-text services: They translate spoken communication and other auditory information into text in real-time, using services such as CART, C-Print, or Type Well.
Assistive listening systems: They enhance the understanding of speech for deaf people who use their residual hearing or personal devices, such as FM/DM, infrared, or induction loops.
Note takers: They capture important pieces of information in a systematic way for deaf students who split their attention between other accommodations and the instructor.
During the chlorination of silicon, chlorine gas is reacted with solid silicon to form silicon tetrachloride.
Si(s) + 2Cl2(g) + heat ↔ SiCl4(g)
Which WILL NOT cause the equilibrium of the reaction to shift towards the products?
Question 18 options:
adding a catalyst
increasing the pressure
increasing the temperature
Increasing the mass of both reactants and products by 20%
Adding a catalyst will not cause the equilibrium of the reaction to shift towards the products.
A catalyst is a substance that speeds up the rate of a chemical reaction without being consumed in the reaction. It does not affect the position of the equilibrium or the relative amounts of reactants and products at equilibrium.
In the given reaction, Si(s) + 2Cl₂(g) + heat ↔ SiCl₄(g), the forward reaction is exothermic, which means it releases heat. According to Le Chatelier's principle, an increase in temperature will shift the equilibrium towards the reactants side in order to counteract the increase in heat. Therefore, increasing the temperature will shift the equilibrium towards the left, reducing the yield of silicon tetrachloride.
Increasing the pressure of the system will also shift the equilibrium towards the side with fewer gas molecules, which is the products side. In this case, increasing the pressure will shift the equilibrium towards the products, increasing the yield of silicon tetrachloride.
Increasing the mass of both reactants and products by 20% will not affect the position of the equilibrium either, as it does not change the ratio of the concentrations of the reactants and products.
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What are the advantages and disadvantages of the practical work of science?
Practical science work is advantageous because it fosters a better understanding of theoretical science.
Advantages of practical science workThe advantages of practical work in science include a better understanding of theoretical concepts, hands-on experience, development of laboratory skills, and increased interest in the subject.
Additionally, practical work can promote critical thinking and problem-solving skills.
However, practical work can also be time-consuming and costly, with the need for specialized equipment and safety precautions. Furthermore, results may be subject to human error, and not all experiments are repeatable.
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Which is the correct measure of density?
O g
O
cm
3
cm
0.0
O mass* volume
The correct measure of density is g/cm³ (option A)
What is density?Density is a measure of the mass of matter contained by a unit volume. The symbol most often used for density is ρ, although the Latin letter "D" can also be used.
Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume.
The formula for density is d = M/V
where;
d is densityM is massV is volumeDensity is commonly expressed in units of grams per cubic centimetre (g/cm³).
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Hope Sergil
Check the Science and Interpreting Graphs
A group of students buit electromagnets using, wre, nails, and a 6V lentern battery. They decided design an
one set of investigations Use the graph to complete the organizer
nvestigation to test factors that they could chance to make a stronger electromagnet. The follow dete is from
Number of Wire Wraps and Magnetic Strength
Paperclips Magnet Picks Up
Independent Variable
Dependent Variable
12
10
8
6
4
Possible Research Question
What trends do you notice in the
data?
Write a claim based on this data
What evidence from the chart or
graph supports your claim?
25
vat
50
Number of Coils Wrapped Around
000
75
Answer:
Independent Variable: Number of Coils Wrapped Around
Dependent Variable: Number of Paperclips Magnet Picks Up
Possible Research Question: How does the number of wire wraps affect the strength of an electromagnet?
Trends noticed in the data: As the number of wire wraps (coils) around the nail increases, the magnetic strength of the electromagnet also increases. There is a positive correlation between the number of wire wraps and the number of paper clips the magnet picks up.
Claim based on the data: The magnetic strength of an electromagnet increases as the number of wire wraps (coils) around the nail increases.
Evidence from the chart or graph supporting the claim: The graph shows that as the number of wire wraps increases from 4 to 12, the number of paper clips the magnet picks up also increases from 6 to 25. This suggests a positive correlation between the two variables.
2. Write the Ksp of Ca(OH)2 in terms of its
(a) molar solubility s
(b) [OH-]
(c) [Ca²+].
The expression of the Ksp is Ksp = [Ca²+] [2OH-]^2
What is the Ksp?In the balanced chemical equation for the solute's dissolution, Ksp is defined as the product of the ion concentrations in a saturated solution, each concentration being raised to the power of its stoichiometric coefficient.
Ksp is temperature-dependent and varies with different compounds. It is used to predict the maximum amount of a compound that can dissolve in a given solvent under specific conditions.
We know that we can be able to use the expression that has been given in the problem to arrive at the fact that;
Ksp = [Ca²+] [2OH-]^2
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A student added 5.00g of P4O10 to 1.50 g of water. Determine the limiting reactant.
Process which nitrogen is obtained from air on a large scale.
Answer:
The process by which nitrogen is obtained from air on a large scale is called the cryogenic distillation of air. This process involves cooling the air to very low temperatures (-183°C) to liquefy it. The air is then fed into a distillation column, which separates it into its components, including nitrogen and oxygen. Since nitrogen has a slightly lower boiling point than oxygen, it can be separated from oxygen by taking advantage of this difference in boiling points.
In the distillation column, the air is separated into its components by fractionation. The cold liquid air is fed into the column, where it is heated and allowed to boil. The nitrogen and oxygen gases that are formed are then separated and collected at different points along the column. The collected gases are then further purified to remove any remaining impurities before being compressed and stored for use.
This process is highly efficient and cost-effective, making it the most common method for obtaining nitrogen on a large scale. Nitrogen obtained through this process is used in a wide range of industrial applications, including chemical manufacturing, food packaging, and electronics production.
Zinc reacts with Hydrochloric Acid in a single replacement reaction. If you have 8 g of of zinc metal, what mass of each product would you produce?
Answer:
[tex]16.68g ZnCl_2[/tex]
[tex]0.2472g H_2[/tex]
Explanation:
1.)Write equation:
[tex]Zn(aq)+HCl(aq)== > ZnCl_2(aq)+H_2(g)[/tex]
2.)Balance:
[tex]Zn(aq)+2HCl(aq)== > ZnCl_2(aq)+H_2(g)[/tex]
3.)Convert:
[tex]8g Zn/\frac{1mol Zn}{65.380g Zn}/\frac{1mol ZnCl_2}{1mol Zn}/\frac{136.28g ZnCl_2}{1mol ZnCl_2} =16.68g ZnCl_2[/tex]
[tex]8g Zn/\frac{1mol Zn}{65.380g Zn}/\frac{1 molH_2}{1molZn}/\frac{2.02g H_2}{1mol H_2}=0.2472g H_2[/tex]
(This does not include sig figs)
Why should we write the report in very simple language?
Answer: Your report should be prepared in a way that is simple to grasp because it contains a lot of details. Use clear English to accomplish this. Avoid from using slang, or specialist words to help readers with some background about the topic to comprehend it simply as well.
all the questions 1. What contribution did de Broglie make to the development of the modern model of the atom? (A)Observed the effect of bombarding thin gold foil (and other metal foils) with alpha radiation from radioactive substances. 60 m B. Discovery of the nucleus C. Discovered that atoms and molecules emit energy only in certain discrete quantities, or quanta. D. Discovered negatively charged particles by cathode ray tube experiment E. Described the wave properties of particles
De Broglie contributed to the development of the modern model of atoms by describing the wave properties of particles. Option E.
De Broglie's contribution to atomic theoryLouis de Broglie was a French physicist who made significant contributions to the development of quantum mechanics.
In his doctoral thesis, he proposed that particles, such as electrons, have both particle-like and wave-like properties. This idea became known as wave-particle duality and laid the foundation for the development of the modern model of the atom.
According to de Broglie's theory, particles can exhibit wave-like behavior and have a wavelength that is inversely proportional to their momentum.
This theory was later experimentally confirmed in a series of experiments that demonstrated the diffraction of electrons and other particles.
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Which of these is not a property of a sound wave?
Sound waves are mechanical waves that travel through a medium such as air, water, or solids. They are characterized by their frequency, wavelength, and amplitude. The correct answer is 4.
Frequency refers to the number of cycles of the wave that occur per unit of time and is measured in hertz (Hz). Wavelength is the distance between two adjacent points of a wave with the same phase. Amplitude is the maximum displacement of the particles in the medium from their rest position as the wave passes through it. Density, on the other hand, is a property of matter and not a characteristic of a sound wave. It refers to the mass per unit volume of a substance. Correct answer: 4.
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--The complete Question is, Which of these is not a property of a sound wave:
1. frequency,
2. wavelength,
3. amplitude,
4. density --
b. How many kJ of heat are needed to completely vaporize 50.0g of water at 100°C? [Ans:113. kJ]
The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.
Heat of vaporization of waterThe heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:
q = m x Hv
where:
q is the heat needed in joules (J)m is the mass of water in grams (g)Hv is the heat of vaporization of water which is approximately 40.65 kJ/mol at standard temperature and pressure.First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:
moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol
Thus:
q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ
In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.
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H₂PO4 + 3 KOH --- ----> K₂PO4 + 3 H₂O
2. If 49.0 g of H3PO4 is reacted with excess KOH, determine the percent yield of K,PO, if
you isolate 49.0 g of K3PO4.
The percentage of yield of K₂PO₄ obtained from the reaction of 49.0 g of H₃PO₄ is 46.2%
How do i determine the percentage yield of K₂PO₄?We'll begin by obtaining the theoretical yield of K₂PO₄. Details below:
H₃PO₄ + 3KOH -> K₃PO₄ + 3H₂O
Molar mass of H₃PO₄ = 98 g/molMass of H₃PO₄ from the balanced equation = 1 × 98 = 98 gMolar mass of K₃PO₄ = 212 g/mol Mass of K₃PO₄ from the balanced equation = 1 × 212 = 212 gFrom the balanced equation above,
98 g of H₃PO₄ reacted to produce 212 g of K₃PO₄
Therefore,
49 g of H₃PO₄ will react to produce = (49 × 212) / 98 = 106 g of K₃PO₄
Thus, the theoretical yield of K₃PO₄ obtained is 106 g
Now, we shall determine the percentage yield of K₃PO₄. Details below:
Actual yield of K₃PO₄ = 49 gTheoretical yield of K₃PO₄ = 106 gPercentage yield of K₃PO₄ =?Percentage yield = (Actual /Theoretical) × 100
Percentage yield of K₃PO₄ = (49 / 106) × 100
Percentage yield of K₃PO₄ = 46.2%
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3. A common infrared laser operates at 1.06 x 103 nm. Calculate the energy of a photon with this wavelength?
The energy of a photon with a wavelength of 1.06 x 10³ nm is 1.877 x 10⁻¹⁹ J.
The energy of a photon can be calculated using the equation:
E = hc/λ
where E is energy of the photon, h is the Planck's constant (6.626 x 10⁻³⁴ J s), c is speed of light (2.998 x 10⁸ m/s), and λ is wavelength of the photon in meters.
We need to convert the given wavelength from nanometers to meters;
1.06 x 10³ nm = 1.06 x 10⁻⁹ m
Now, we can substitute the values in the equation and calculate the energy of the photon;
E = (6.626 x 10⁻³⁴ J s) × (2.998 x 10⁸ m/s) / (1.06 x 10⁻⁹ m)
E = 1.877 x 10⁻¹⁹ J
Therefore, the energy of photon is 1.877 x 10⁻¹⁹ J.
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What compound has 4 hydrogen atoms and one carbon
Carbon atoms may thus form bonds to as many as four other atoms. For example, in methane (CH 4start subscript, 4, end subscript), carbon forms covalent bonds with four hydrogen atoms
__________________________________________________________
6.
Mg(s) + 2 HCl(aq) → MgCl₂(aq) + H₂(g)
The chemical equation shown above represents the reaction between Mg(s) and HCl(aq). When 12.15 g of
Mg(s) is added to 500.0 mL of 4.0 M HCl(aq), 95 kJ of heat is released. The experiment is repeated with
24.30 g of Mg(s) and 500.0 mL of 4.0 M HCl(aq). Which of the following gives the correct value for the
amount of heat released by the reaction?
The experiment with 12.15 g of Mg(s) is added to 500.0 mL of 4.0 M HCl(aq), 95 kJ of heat is released gives the correct value for the amount of heat released by the reaction.
Heat is the energy that moves via one body to the next when temperatures are different. Heat passes from the hotter to the colder body when two bodies with differing temperatures are brought together.
Usually, however not always, this energy transfer results in a rise in the temperature for the colder body with a fall from the temperature for the hotter body. Through the transition converting one physical state (or phase) to a different one. The experiment with 12.15 g of Mg(s) is added to 500.0 mL of 4.0 M HCl(aq), 95 kJ of heat is released gives the correct value for the amount of heat released by the reaction.
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What mass in grams of the dihydrate H2C2O4 • 2 H2O (molar mass = 126.0 g/mol) is needed in order to make 100.0 mL of a 0.356 M solution of H2C2O4 (molar mass = 90.0)?
Therefore, the mass in grams of the dihydrate H2C2O4 • 2 H2O (molar mass = 126.0 g/mol) is needed in order to make 100.0 mL of a 0.356 M solution of H2C2O4 is 4.49g.
Mass calculation.
To calculate the mass in grams of the dihydrate H2C2O4 • 2 H2O we first need to find the moles of H2C2O4.
Moles of solute = molarity * litres in solution.
= 0.356 *0.01L=0.0356moles.
since dihydrate H2C2O4 • 2 H2O has molar mass of 126.0g/mol it means it has a mass of 126g.
By using mole to mass conversion.
mass of H2C2O4 • 2 H2O= moles of H2C2O4 • 2 H2O * molar mass of H2C2O4 • 2 H2O
mass of H2C2O4 • 2 H2O= 0.0356moles * 126glmol
=4.49g.
Therefore, the mass in grams of the dihydrate H2C2O4 • 2 H2O (molar mass = 126.0 g/mol) is needed in order to make 100.0 mL of a 0.356 M solution of H2C2O4 is 4.49g.
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Question 6 of 25
A man filling his car with gas is expecting what kind of energy conversion to
happen?
O A. Chemical potential energy to kinetic energy
B. Heat energy to gravitational potential energy
C. Kinetic energy to chemical potential energy
D. Gravitational potential energy to heat energy
Answer:
A. Chemical potential to Kinetic energy
Explanation:
The car engine burns gas to produce motion. Burning is a form of chemical reaction and the motion produced is the kinetic energy.
45. Assume that 0.504 g of H₂ gas at STP reacts with
excess CuO according to the following equation:
Cuo(s) + H₂(g) → Cu(s) + H₂O(g)
Make sure the equation is balanced before beginning
your calculations.
a. How many liters of H₂ react?
b. How many moles of Cu are produced?
C. How many grams of Cu are produced?