Answers
Answer:
Explanation:
Molarity of NaOAc needed
Using the Henderson-Hasselbalch Equation calculate base molarity needed given [HOAc] = 1.00M and pKa(NaOAc) = 4.75 and [HOAc] = 1.00m.
pH = pKa + log [NaOAc]/[HOAc]
5.00 = 4.75 + log[NaOAc]/[1.00M]
5.00 - 4.75 = log [NaOAc] - log[1.00M]
log [NaOAc] = 0.25 => [NaOAc] = 10⁰·²⁵ M = 1.78
Given 10ml of HOAc, how much (ml) 1.78M NaOAc to obtain a buffer pH of 5.00.
Determine Volume of Base Needed
(M·V)acid = (M·V)base => V(base) = (M·V)acid / (M)base
Vol (NaOAc) needed = (1.00M)(0.010L)/(1.78M) = 0.0056 liter = 5.6 ml.
Checking Results:
5.00 = 4.75 + log [1.78M]/[1.00M] = 4.75 + 0.25 = 5.00 QED.
The volume of 1.00 M sodium acetate solution needed to prepare an acetic/acetate buffer of pH 5.00 using 10.0 mL of 1.00M acetic acid solution is 17.8 mL.
We can find the volume of the acetate solution with the Henderson-Hasselbalch equation:
[tex]pH = pka + log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]})[/tex] (1)
Where:
[CH₃COOH] = 1.00 M
[CH₃COONa] =?
pH = 5.00
pKa = 4.75
From equation (1), we have:
[tex] log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]}) = pH - pKa [/tex]
[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{pH - pKa} [/tex]
[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{5.00 - 4.75} = 1.78 [/tex]
Now, the volume of the acetate solution is:
[tex]\frac{n_{CH_{3}COONa}/Vt}{n_{CH_{3}COOH}/Vt} = 1.78[/tex]
Since the total volume is the same, we have:
[tex]\frac{n_{CH_{3}COONa}}{n_{CH_{3}COOH}} = 1.78[/tex]
[tex] \frac{[CH_{3}COONa]_{i}*V_{b}}{[CH_{3}COOH]_{i}*Va} = 1.78 [/tex]
Solving for Vb
[tex] Vb = \frac{1.78*[CH_{3}COOH]_{i}*Va}{[CH_{3}COONa]_{i}} = \frac{1.78*1.00M*10.0mL}{1.00 M} = 17.8 mL [/tex]
Therefore, we need to add 17.8 mL of sodium acetate solution.
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Related Questions
Which set of coefficients will correctly balance the following skeleton equation?
Fe + Cl2 →FeCl3
Answers
Answer:
2Fe + 3Cl2 → 2FeCl3
Explanation:
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Calculate the mass, in grams, of 0.540 mol of manganese (Mn).
Report your answer with three significant figures.
Answers
Answer:
m = 29.6 grams
Explanation:
Given that,
Number of moles = 0.540
The molar mass of manganese = 54.93 g/mol
We know that,
Number of moles = given mass/molar mass
[tex]m=n\times M\\\\m=0.540 \times 54.93\\\\m=29.6\ g[/tex]
So, the required mass of the Manganese is equal to 29.6 grams.
How many moles are in 2.5L of 1.75 M Na2CO3
Answers
Answer: There are 4.375 moles in 2.5 L of 1.75 M [tex]Na_2CO_3[/tex]
Explanation:
To calculate the number of moles for given molarity, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
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Putting values in equation , we get:
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Which postmortem parameter is fixed by 8 hours?
1)cloudiness of the eyes
2)rigor mortis
3)livor mortis
4)putrefaction
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Plasma can be found naturally in
O water and ice.
O stars and lightning.
O wood and metal.
O comets and asteroids.
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Answer:
stars and lightning. this is the answer ok
Hope it helped
Who among, Amit and Saaketh, is correct? Explain.
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Answer:
What is their question answers exactly? I won't be able to explain who is correct.
Explanation:
Answer:
Not a lot to draw from this question if im going to be honest
Explanation
Astronauts go to live on the International Space Station for a period of ________ month(s). A one B three C six D nine
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Answer:
The answer is C. six months
Explanation:
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Who knows how to do this please help
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Answer: You forgot to zero the balance
Explanation:
Which of the following is a characteristic of both the Earth and the Moon?
Fossils and fossil
fuels under the
surface
Rocky surface
covered with
landforms
Flowing water in
Oceans and rivers
Atmosphere
containing oxygen
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Answer:
rocky surface covered with landforms
Explanation:
plz help :(
In a high-pressure system,
a.
air molecules are far apart and pressing on Earth’s surface.
b.
air molecules are far apart and rising away from Earth’s surface.
c.
air molecules are close together and pressing on Earth’s surface.
d.
air molecules are close together and rising away from Earth’s surface.
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Answer:
c.
air molecules are close together and pressing on Earth’s surface.
Explanation:
i hope this helps!
Does the magnetic field lines of repelling magnets always combine. True or False?
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Answer:
True
Explanation:
yes magnetic feild lines is always combined
If 280.4 g of KOH react with an excess of FeCl3, how many grams of Fe(OH)3 will be produced?
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How many grams will be produced?
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Answer:
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Balance the Molecular Equation
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Ions for the Complete Ionic Equation
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Net Ionic EquationExplanation:
Balance Ca + HCI +CaCl2 + H2
Answers
Answer:
Ca + 2 HCl -- CaCl2 + H2
Explanation:
There are two hydrogen on the right side, so we multiply the left side( HCl) by 2 to get 2 hydrogen on the left. This automatically gives you 2 Cl on left side and there are already 2 cl on the right side, so now this equation is balanced.
What is the atomic mass of element XX if 3.6 moles of the substance has a mass of 192 grams?
Answers
Answer:
53.3g/mol
Explanation
Moles=mass/molar mass
Molar mass= mass/moles
Molar mass= 192/3.6
= 53.3
help plz and will give brainly
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Balance the chemical equation
C2H6+O2 = CO2 +H2O
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........................
1) Calculate the percent composition of each element in ammonia (NH).
Answers
Answer:
[tex]\% N=82.2\% \\\\\% H=17.8\%[/tex]
Explanation:
Hello there!
In this case, since ammonia is NH₃, we can see nitrogen weights 14.01 g/mol and hydrogen 3.03 g/mol as there is one only nitrogen atom and three hydrogen atoms; thus, the total mass is 17.04 g/mol. In such a way, the percent composition of each element turns out to be:
[tex]\% N=\frac{14.01}{17.04}*100\%=82.2\% \\\\\% H=\frac{3.03}{17.04}*100\%=17.8\%[/tex]
Best regards!
PLS HELP THIS IS DUE IN 10 MINS!
Compare and contrast floods and droughts. Give two examples of how they are the same and two examples of how they are different.
Answers
Different: Floods are an excess amount of water whereas droughts are a lack of water for a prolonged period of time. Floods are more common in coastal areas whereas droughts are most common in the Midwest and South.
Question 2 (1 point)
(02.01 LC)
Which scientist proposed the model of an atom as a solid sphere? (1 point)
John Dalton
Niels Bohr
Ernest Rutherford
William Crookes
Answers
Answer:
John Dalton
Explanation:
Both John Dalton and Democritus thought that the atom was an indivisible sphere until J.J. Thompson came out with the plum pudding model. Hope I helped!
Liquids B and C are partially miscible at 25 oC. When one starts with 1 mol of C at 25 oC and isothermally adds B a little at a time, a two-phase system first appears when a bit more than 0.125 mol of B has been added; continuing to add B, one finds the two-phase system becomes a one-phase system when a total of 3 mol of B has been added. For a system consisting of 2.5 mol of B and 2 mol of C at 25 oC, find the number of moles of B and of C present in each phase.
Answers
Answer:
[tex]0.8\overline 3[/tex] moles of A and 2.5 moles of B in the one-phase system
[tex]1.1 \overline 6[/tex] moles of A and [tex]0.1458 \overline 3[/tex] moles of B in the two-phase system
[tex]0.3541 \overline 6[/tex] moles of B remains in the system
Explanation:
The given parameters are;
The extent of miscibility of liquid B and C = Partially miscible
The number of moles of liquid B added to 1 mole of liquid A that forms a two-phase system = 0.125 mol of liquid B
The number of moles of liquid B added to 1 mole of liquid A that forms a one -phase system = 3 moles of liquid B
Whereby the system consist of 2.5 mol of B and 2 mol of C at 25°C, we have;
The 1 mole of A mixes with 3 moles of B to form a single phase solution
Therefore;
2.5 moles of B will mix with (1/3)×2.5 moles of A = 5/6 moles of A
The remaining number of moles of A in the system = 2 - 5/6 = 7/6 moles of A
Similarly, we have;
At least, 0.125 mole of B combines with 1 mole of A to form a two-phase system
7/6 moles of A will combine with 7/6 × 0.125 = 7/48 moles of B to form a two-phase system
The number of moles of B left = 0.5 - 7/48 = 17/48 = 0.3541[tex]\overline 6[/tex] moles of A
Therefore, we have;
5/6 moles of A and 2.5 moles of B in the one-phase system
7/6 moles of A and 7/48 moles of B in the two-phase system
17/48 moles of B remaining in the system
The subscript represents the number of ____________ in a chemical equation.
Answers
Good luck!
what is derived from sheep and goats that is used in break fluid
A bones and horns
B Fats and Fattys acids
C Manure
D Wool and Lanolin
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the answer is A I took the test
A severe storm would be most likely to damage a coastal area by causing
A.
volcanoes.
B.
pollution.
C.
erosion.
D.
earthquakes.
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my teacher told me
A severe storm would be most likely to damage a coastal area by causing pollution. Therefore, the correct option is option B.
What is coastal area?The region where land joins the ocean, or even as a line defining the border between the land as well as the shoreline, is known as the coast, sometimes referred as the coastline and seashore. The terrain of the area's surroundings has an impact on shorelines, as do water-induced erosion processes like wave action.
The length of the shoreline on Earth is about 620,000 kilometers. Natural ecosystems' coasts are significant zones and frequently the site of a diverse range of biodiversity. They are home to significant ecosystems on land, such as freshwater and estuarine wetlands, that are crucial for the survival of bird populations or other land animals. A severe storm would be most likely to damage a coastal area by causing pollution.
Therefore, the correct option is option B.
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Elizabeth REALLY didn’t study, and she also wrote the formula for dicarbon tetrafluoride as “C2F5”. Describe why her answer is incorrect.
Answers
Answer:
correct formula: C2F4
Explanation:
tetra means 4. There are 2 C and 4 F in dicarbon tetrafluoride.
How many grams equal 4.3 x 1024 atoms of oxygen (02)?
Answers
Answer: 248.66g
Explanation:
4.3e24 / 6.23e23 = 6.9 mols O2
6.9(18.02*2)=248.66
help please guys i need it
Answers
Answer:
Amplitude
Explanation:
Hope I helped :)
hi, if your looking for extra points (50+) and br ainiest here is ur chance, answer this question correctly plz
Answers
what is the mass of 1.25 L of ammonia gas at STP
Answers
Answer:
mass 1.25 Liters NH₃(gas) = 0.949 grams (3 sig-figs)
Explanation:
At STP (Standard Temperature-Pressure conditions => 0°C(=273K) and 1atm pressure, 1 mole any gas will occupy 22.4 Liters.
So, given 1.25 Liters ammonia gas at STP, convert to moles then multiply by formula wt. (17g/mole gives mass of NH₃.
moles NH₃(gas) = 1.25L NH₃(gas)/22.4L NH₄(gas)· NH₃(gas)mole⁻¹ = 0.0558 mole NH₃(gas).
Converting to grams NH₃(gas) = 0.0558 mole NH₃(gas) x 17 g·mol⁻¹ = 0.949 grams NH₃(gas).
A gas takes
up a volume of 17 L, has a
pressure of 2.3 atm, and a temperature
of 299 K. If I raise the temperature to
350 K and lower the pressure to 1140
mmHg, what is the new volume?
Answers
Answer:
V₂ = 25.065 L
Explanation:
Given data:
Initial volume = 15L
Initial pressure = 1500 mmHg (1500/760 = 1.97 atm)
Initial temperature = 299 K
Final temperature = 350 K
Final volume = ?
Final pressure = 1050 mmHg (1050/760 = 1.38 atm)
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.97 atm × 15 L × 350 K / 299 K × 1.38 atm
V₂ = 10342.5 atm .L. K / 412.62 K.atm
V₂ = 25.065 L