summarize how the high temperature in this city changed over the 15 days

Answer:

140g

Step-by-step explanation:

One pencil box has a mass of 140g, to find out the weight of 4 pencil boxes we multiply 140 by 4: 140*4 = 560g

Let the mass of the notebook be x: 560+x = 700

560+x = 700

x = 140g

36 students does not watch regularly the programme.

Lets simplify the problem,

Total students = 48

Regular students 1//4*48

=> 12 students

Through Simple Subtraction method,

Irregular students = Total students - regular students

Irregular students = 48-12

=36

Hence 36 students does not watch regularly the programme.

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A kite is a quadrilateral with four sides that may be divided into two adjacent pairs of equal-length sides. The total length of ribbon that is needed to line the two long sides of the hat is 22 inches.

According to the question,

A kite is a quadrilateral with four sides that may be divided into two adjacent pairs of equal-length sides. A parallelogram, on the other hand, has two sets of equal-length sides that are opposite each other rather than adjacent.

Since the two adjacent small and two adjacent long sides of a kite are always equal. Therefore, the length of the smaller sides can be written as,

(2x + 1) inches = 5 inches

2x + 1 = 5

2x = 4

x = 2

Now, the length of the longer side of the kite can be written as,

(3x + 5) inches

= 3(2) + 5

= 11 inches

As both the long sides are needed to be covered with the ribbon, therefore, the length of the ribbon needed is,

Ribbon needed = 11 inches × 2

                         = 22 inches

Hence, a kite is a quadrilateral with four sides that may be divided into two adjacent pairs of equal-length sides. the total length of ribbon that is needed to line the two long sides of the hat is 22 inches.

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Answer:

B.6 is the significant digits of number 1.00250

I HOPE IT HELP YOU

The number of significant figures that are available in 1.00250 are; B: 6

Significant figures are defined as the number of digits in a value, often a measurement, that contribute to the degree of accuracy of the value.

Now, in the question we are given the decimal number 1.00250.

Now, it should be noted that when dealing with significant numbers as regards decimals, any zero digit to the left of the decimal is a non-significant figure while any zero digit to the right of the decimal is a significant figure.

Thus, the significant figures in the question are all the numbers which are 6 in number.

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Answer:

may be 3549 cube inch while rounded up.

Step-by-step explanation:

x³ - x² - 24x - 36

factors of -36 are 1, 2, 3, 4, 6, 9, 12, 18, 36 and negative equivalents.

1 - 1 - 24 - 36 != 0

8 - 4 - 48 - 36 != 0

27 - 9 - 72 - 36 != 0

64 - 16 - 96 - 36 != 0

216 - 36 - 144 - 36 = 0

So one factor is 6

x = 6

(x - 6) = 0

x²(x - 6) = x³ - 6x²

5x(x - 6) = 5x² - 30x

6(x - 6) = 6x - 36

x³ - 6x² + 5x² - 30x + 6x - 36

(x - 6)(x² + 5x + 6)

(x - 6)(x² + 3x + 2x + 6)

(x - 6)(x(x + 3) + 2(x + 3))

(x - 6)(x + 3)(x + 2)

x - 6 = 0

x = 6

x + 3 = 0

x = -3

x + 2 = 0

x = -2

x = -2, -3, 6.

One is the product of the other 2 as -2 x -3 = 6.

Graphic proof is shown above or below in the image

Question 8

1) [tex]\triangle ACE[/tex] with [tex]\overline{AC} \cong \overline{EC}[/tex], [tex]\overline{BC} \cong \overline{DC}[/tex] (given)

2) [tex]\angle C \cong \angle C[/tex] (reflexive property)

3) [tex]\triangle ACD \cong \triangle ECB[/tex] (SAS)

Question 9

1) [tex]\overline{PQ}[/tex] and [tex]\overline{PR}[/tex] are the legs of isosceles [tex]\triangle PQR[/tex], [tex]\overline{PS} \cong \overline{QR}[/tex] (given)

2) [tex]\angle PSQ[/tex] and [tex]\angle PSR[/tex] are right angles (definition of perpendicular lines)

3) [tex]\angle Q \cong \angle R[/tex] (angles opposite the legs of an isosceles triangle are congruent)

4) [tex]\overline{PS} \cong \overline{PS}[/tex] (reflexive property)

5) [tex]\angle PSQ \cong \angle PSR[/tex] (all right angles are congruent)

6) [tex]\triangle PSQ \cong \triangle PSR[/tex] (AAS)

Question 10

1) [tex]\overline{AB} \cong \overline{CD}[/tex], [tex]\overline{AB} \perp \overline{BC}[/tex], [tex]\overline{CD} \perp \overline{AD}[/tex] (given)

2) [tex]\overline{AC} \cong \overline{AC}[/tex] (reflexive property)

3) [tex]\angle ABC[/tex] and [tex]\angle ADC[/tex] are right angles (perpendicular lines form right angles)

4) [tex]\triangle ABC[/tex] and [tex]\triangle ADC[/tex] are right triangles (a triangle with a right angle is a right triangle)

5) [tex]\triangle ABC \cong \triangle CDA[/tex] (HL)

6) [tex]\overline{AD} \cong \overline{CB}[/tex] (CPCTC)

Answer:

3rd option

Step-by-step explanation:

8 - 3x ≥ - 4 ( subtract 8 from both sides )

- 3x ≥ - 12

divide both sides by - 3 , reversing the symbol as a result of dividing by a negative quantity.

x ≤ 4

since ≤ the circle on number line is solid ( not open )

since less than 4 then arrow points left away from 4

the solution is shown on the third graph

Answer:

35 acres.

Step-by-step explanation:

Proportions:

15. 8 ⇒ 1 acre

553 ⇒  P acres

P = 553*1/15.8

P = 35 acres

He needs to do 10 visits to earn a free ticket.

We know that he gets 30 points just for signing up, and he gets 8.5 points for each visit, then the amount of points as a function of v, the number of visits, is:

P(v) = 30 + 8.5*v

He will get a free movie ticket when he gets 115 points, then we need to solve the linear equation:

P(v) = 115 = 30 + 8.5*v

Solving for v:

v = (115 - 30)/8.5 = 10

He needs to do 10 visits to earn a free ticket.

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Answer:

25 minutes

Step-by-step explanation:

If it takes 5 minutes to prepare one game we need to multiply 5 games by 5 minutes: 5*5 = 25 minutes

The missing fraction is 7/9

The given equation is:

[tex]\frac{3}{4}+\frac{1}{2}+\frac{2}{9}+x=\frac{9}{4}[/tex]

This can be simplified as:

[tex]\frac{27+18+8+36x}{36} =\frac{9}{4} \\\\\frac{53+36x}{36} =\frac{9}{4}[/tex]

Cross multiply

[tex]9(36)=4(53+36x)\\\\324=212+144x\\\\144x=324-212\\\\144x=112\\\\x=\frac{112}{144} \\\\x=\frac{7}{9}[/tex]

Therefore, the missing value is [tex]\frac{7}{9}[/tex]

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Answer:

91 in2

Step-by-step explanation:

11+15 over 2 , times by 7 equals 91 ??

Answer: [tex]y=5x+1[/tex]

Step-by-step explanation:

The slope of the given line is

[tex]\frac{1-0}{0-5}=-\frac{1}{5}[/tex]

Since perpendicular lines have slopes that are negative reciprocals, the slope of the line we want to find is 5.

Since the y-intercept is (0,1), the equation is [tex]y=5x+1[/tex].

Answer: the answer is c

(a) |-9| + 6 = 9 + 6 = 15

(b) |-9 + 6| = |-3| = 3

Answer:

y = -1x + 1

Step-by-step explanation:

y = mx + c

y = gradient(x intercept) + y intercept

y = -1x + 1

The difference between the observed value of the dependent variable and the value predicted using the estimated regression equation is known as the Residual model.

Regression is the process used to predict the variation in one variable based on another variable.

The difference between the observed value of the dependent variable and the value predicted using the estimated regression equation is known as the residual model.

This value s predicted by the regression line.

Residual = Observed value - predicted value

Therefore, the difference is known as residual.

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No, you will not be dealt this hand exactly 48 ​times. This can be obtained by understanding the concept of probability.

The probability means that out of 100 times nearly 48 times the player is dealt the particular hand.

No, you will not be dealt this hand exactly 48 ​times since 48 times is an approximate value out of 100 times.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: In a certain card​ game, the probability that a player is dealt a particular hand is 0.48. Explain what this probability means. If you play this card game 100​ times, will you be dealt this hand exactly 48 ​times? Why or why​ not?

Answer:

Infinite solutions.

Step-by-step explanation:

 y = 5 - 2x

 2x + y = 5  ---------(I)

 a₁ = 2  ; b₁ = 1  and c = 5

4x + 2y = 10

a₂ = 4  ; b₂ = 2   and c₂  = 10

[tex]\sf \dfrac{a_1}{a_2}=\dfrac{2}{4}=\dfrac{1}{2}\\\\\dfrac{b_1}{b_2}=\dfrac{1}{2}\\\\\dfrac{c_1}{c_2}=\dfrac{5}{10}=\dfrac{1}{2}[/tex]

⇒  [tex]\sf \dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}=\dfrac{1}{2}[/tex]

So, the line are coincident and has infinite solutions.

The equation which expresses the number of bacteria, P, present at any time, t is P(t) = 4(2)^t

Check all options

When t = 1

P(t) = 8(4)^t

= 8(4)¹

= 8(4)

P(t) = 32

Not true

P(t) = 4(2)^t

= 4(2)¹

= 4(2)

= 8

True

P(t) = (2)^t

= (2)¹

= 2

Not true

P(t) = 8(2)^t

= 8(2)¹

= 8(2)

= 16

Not true

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The simplified form of the expression is [tex]10 x^{18}[/tex].

What are indices in maths?

The given expression is [tex]\sqrt{100x^{36} }[/tex]

Applying the rule, [tex]\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}[/tex]

Now, [tex]\sqrt{100} \sqrt{x^{36} }[/tex]

Simplifying, we get;

[tex]10\sqrt{x^{36} }[/tex]

Applying the exponent rule, [tex]a^{bc} = (a^{b} )^{c}[/tex]

We get

[tex]10 \sqrt{(x^{18} })^{2}[/tex]

[tex]10 x^{18}[/tex]

Therefore, the simplified form of the expression is [tex]10 x^{18}[/tex].

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Answer:

10 x 18

Step-by-step explanation:

The total weight of the package was 20 pounds, given the total shipping cost was $3.45, using the total cost function, C(P) = 1.65 + 0.12(P - 5), where P is the weight of the package in pounds.

In the question, we are given that a package weighs P pounds, P being a whole number. To ship this package by express costs $1.65 for the first five pounds and 12c for each additional pound. The total shipping cost was $3.45.

We are asked for the package weight in pounds.

First, we design a general cost function.

The cost is given to be $1.65 for the first 5 pounds, and 12c for each additional pound.

The weight of the package is given to be P pounds.

We assume the total cost function to be C(P), a function of the weight of the package, P pounds.

Thus, the total cost function can be shown as the sum of $1.65 and 12c or $0.12 multiplied with (P - 5), as it is the cost for additional pounds after 5 pounds.

Thus, the total cost function, C(P) = 1.65 + 0.12(P - 5).

Now, we are given that the total shipping cost was $3.45.

Thus, to find the weight of the package, we equate the total cost function, C(P) to 3.45, to get:

1.65 + 0.12(P - 5) = 3.45,

or, 1.65 + 0.12P - 0.6 = 3.45,

or, 0.12P + 1.05 = 3.45,

or, 0.12P = 3.45 - 1.05,

or, 0.12P = 2.40,

or, P = 2.40/0.12 = 20.

Thus, the total weight of the package was 20 pounds, given the total shipping cost was $3.45, using the total cost function, C(P) = 1.65 + 0.12(P - 5), where P is the weight of the package in pounds.

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The net Change in latitude and longitude of the helicopter are; 28.47° and 7.35° respectively.

The net change in latitude of the helicopter can be evaluated as follows;

x = |-6.20° - 22.27°| = |-28.47°|

x = 28.47°

The net change in longitude of the helicopter can be evaluated similarly as follows;

y = |106.80° - 114.15°| = |-7.35°|

x= 7.35°

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The fraction of the students in Siena's class are girls with brown eyes is 5/12.

Let the fraction of students in Siena's class with brown eyes be a=5/8.

And the fraction of students in Siena's class with brown eyes are girls be b=2/3.

Then, the fraction of students in Siena's class are girls with brown eyes be z=a×b

Therefore, by substituting the fraction values, we get

z=(5/8)×(2/3)

z=5/12.

Hence, 5/8 of the students in Siena's class have brown eyes. 2/3 of the students with brown eyes are girl. Then, the fraction of students in Siena's class are girls with brown eyes is 5/12.

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Answer:

[tex]x=\frac{83}{36}[/tex]

Step-by-step explanation:

1) Convert [tex]2\frac{1}{4}[/tex] to  improper fraction. Use this rule: [tex]a\frac{b}{c} =\frac{ac+b}{c}[/tex].

[tex]x-\frac{2\times4+1}{4} = \frac{1}{18}[/tex]

2) Simplify [tex]2\times4[/tex] to 8.

[tex]x-\frac{8+1}{4} =\frac{1}{18}[/tex]

3) Simplify [tex]8+1[/tex] to 9.

[tex]x-\frac{9}{4} =\frac{1}{18}[/tex]

4) Add [tex]\frac{9}{4}[/tex] to both sides.

[tex]x=\frac{1}{18} +\frac{9}{4}[/tex]

5) Simplify [tex]\frac{1}{18} +\frac{9}{4}[/tex] to [tex]\frac{83}{36}[/tex].

[tex]x=\frac{83}{36}[/tex]

Decimal Form: 2.305556

Answer:

83/36

Step-by-step explanation:

x - 2 1/4 = 1/18

x = 1/18 + 9/4

L.C.M= 36,

x = 1x2/18x2 + 9x9/4x9

x = 2/36 + 81/36

x = 83/36

Decimal form = 2.305556

The elements which must be contain in a body paragraph of a literary analysis are;

A strong body paragraph basically is characterized as a medium of stating facts regarding a viewpoint and these statements must be accompanied by supporting evidence and commentary.

On this note, the three elements which should be contained in a strong body paragraph are;

Remarks:

an introduction to a text

reasons that support a viewpoint

O a thesis statement

supporting evidence and commentary

Da summary of the main points

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If this is the one you are talking about then:

horizontal translation of 3 units is:     y= f(x-3)

vertical stretch by a scale factor of 3 is:     y= 3f(x)

reflection over the x-axis is:     y= -f(x)

vertical translation of 3 units is:     y= f(x)+3

Step-by-step explanation:

Adding a value to f(x) translates the graph of f vertically. So, the equation that shows a vertical translation of 3 units is y = f(x) + 3.

Adding a value to the input, x, of f(x) translates the graph of f horizontally. So, the equation that shows a horizontal translation of 3 units is y = f(x − 3).

Multiplying f(x) by a negative value reflects the graph of f over the x-axis. So, the equation that shows a reflection over the x-axis is y = -f(x).

Multiplying f(x) by a constant, k, vertically stretches the graph of f by a scale factor of k. So, the equation that shows a vertical stretch by a scale factor of 3 is y = 3f(x).

[tex]Answer: \displaystyle\left {{x^2+(y-3)^2=36} \atop {x^2+(y+8)^2=36}} \right. .[/tex]

Step-by-step explanation:

[tex]D=12\ \ \ \ O(0;b)\\\displaystyle\\R=\frac{D}{2}\\R=\frac{12}{2} \\ R=6.\\Circle \ equation\ is:\\(x-a)^2+(y-b)^2=R^2.\\a=0\ \ \ \ \ R=6\\x^2+(y-b)^2=6^2\\x^2+(y-b)^2=36\\Henese:\\\displaystyle\\\left {{x^2+(y-3)^2=36} \atop {x^2+(y+8)^2=36}} \right. .[/tex]

Answer: Option (4)

Step-by-step explanation:

A quadrilateral with two pairs of opposite congruent sides must be a parallelogram.

Answer:

11

Step-by-step explanation: