Solve y=x³ with function y=fx​

Answer:

Last one.

Step-by-step explanation:

[tex]\sqrt{3}[/tex] is used in 30-60-90 triangles

[tex]\sqrt{2}[/tex] is used in 45-45-90 triangles

Base is x, leg is x[tex]\sqrt{3}[/tex], hypotenuse is 2x

Answer:

x = 20 ; y= 10√3

Step-by-step explanation:

30, 60 , 90 triangle ratio is

Side opposite to 30 is a

a = AC = 10

Side opposite to 60 is a[tex]\sqrt{3}[/tex]

AB = a[tex]\sqrt{3}[/tex] = 10√3

Side opposite to 90 is  2a

BC = 2a = 2* 10 = 20

Answer:

i think its 13

Step-by-step explanation:

you are supposed to measure the lowest point of the liquid.

Answer:

- 2+8x/x

Step-by-step explanation:

See image below:)

FYI you can use the app photo math you just take a pic of the problem and it gives you the answer and explains the steps and it is free

Answer:

(8x-2) / (x-8)

Step-by-step explanation:

8x/x-8 - 2/x-8

Since the denominator is the same, we can add the numerators

(8x-2) / (x-8)

Answer:

15

Step-by-step explanation:

3/5*25

Answer:

15 girls

Step-by-step explanation:

(3/5) x 25 = 15

Answer:

-80

Step-by-step explanation:

2x^2 + 3xy - 4y^2  

x = 2 | y = - 4

2(2)^2 + 3(2)(-4) - 4(-4)^2

2 * 4 + 3(2)(-4) - 4 * 16

8 - 24 - 64

-80

Answer:

A.

D needs to be equal or more to 260

Answer:

The correct option is A

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

The secondary voltage is proportional to the primary voltage. The constant of proportionality is the ratio of secondary turns to primary turns.

The secondary voltage is ...

  (200/500)(220 V) = 88 V

__

A transformer does not change the frequency.* The voltage in the secondary coil is still 50 Hz.

_____

* Most transformers are designed to operate as linear devices. It is possible to design a transformer (with special core material) that operates non-linearly, and/or that is "tuned" to a frequency other than the one exciting the primary. That is, the secondary voltage may be some harmonic of the primary voltage. This would be a relatively unusual application of a transformer, beyond the apparent scope of the question here.

I dont think I can be answered with just the given info... is some of the q missing still?

Closest we can do with above is dress cost = 120+ c

Answer:

80x⁴

Step-by-step explanation:

[tex](\frac{1}{ax} + 2ax^2)^5 = 5C_0(\frac{1}{ax})^5(2ax^2)^0 + 5C_1(\frac{1}{ax})^4(2ax^2)^1 + 5C_2(\frac{1}{ax})^3 (2ax^2)^2[/tex]

                           [tex]+ 5C_3 (\frac{1}{ax})^2(2ax^2)^3 + 5C_4(\frac{1}{ax})^1(2ax^2)^4 + 5C_5(\frac{1}{ax})^0(2ax^2)^5[/tex]

[tex]5C_0(\frac{1}{ax})^5(2ax^2)^0 =1 \times (\frac{1}{ax})^5 \times 1 = \frac{1}{a^5x^5}\\\\5C_1(\frac{1}{ax})^4(2ax^2)^1 = 5 \times (\frac{1}{ax})^4 \times (2ax^2)^1 = 10 ax^2 \times \frac{1}{a^4x^4} = \frac{10}{a^3x^2}\\\\5C_2 (\frac{1}{ax})^3 (2ax^2)^2= 10 \times (\frac{1}{ax})^3 \times (2ax^2)^2 = 10 \times \frac{1}{a^3x^3} \times 4a^2x^4 = \frac{40x}{a}\\\\5C_3 (\frac{1}{ax})^2 (2ax^2)^3 = 10 \times (\frac{1}{ax})^2 \times (2ax^2)^3 = 10 \times \frac{1}{a^2x^2} \times 8a^3 x^6 = 80ax^4\\\\[/tex]

[tex]5C_4(\frac{1}{ax})^1(2ax^2)^4 = 5 \times \frac{1}{ax} \times 16a^4x^8 = 80a^3x^7\\\\5C_5(\frac{1}{ax})^0(2ax^2)^5 = 1 \times 1 \times 32a^5x^{10}[/tex]

The fourth term of the expansion has the constant a,

the coefficient of a is 80x⁴

Answer:

Step-by-step explanation:

P = 4 + 6 + (3y - 2)      Remove the brackets

P = 10 + 3y - 2            Combine

P = 8 + 3y

Note 3y must be less than 8. That's because 2 sides of any triangle must be larger than the 3rd side or else you don't have a triangle.

Answer:

P(66.4 < X < 241.6) = 0.5039 = 50.39%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A distribution of values is normal with a mean of 232.4 and a standard deviation of 92.2.

This means that [tex]\mu = 232.4, \sigma = 92.2[/tex]

Find the probability that a randomly selected value is between 66.4 and 241.6.

This is the p-value of Z when X = 241.6 subtracted by the p-value of Z when X = 66.4.

X = 241.6

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{241.6 - 232.4}{92.2}[/tex]

[tex]Z = 0.1[/tex]

[tex]Z = 0.1[/tex] has a p-value of 0.5398

X = 66.4

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{66.4 - 232.4}{92.2}[/tex]

[tex]Z = -1.8[/tex]

[tex]Z = -1.8[/tex] has a p-value of 0.0359

0.5398 - 0.0359 = 0.5039

P(66.4 < X < 241.6) = 0.5039 = 50.39%.

Answer:

C=$25+$15m

Step-by-step explanation:

C is Cost

m is 15 minutes

The price for a visit would be $25 + $15 times the amount of time they work on repairs.

The equation you could use to find the total cost of a repair visit is C=$25+$15m.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

The telephone company charges $25 for a service call, and $15 for every 15 minutes the service representative works on repairs.

Let C is Cost and m be 15 minutes

From the data given in the question:

C = 25 + 15m

Thus, the equation you could use to find the total cost of a repair visit is C=$25+$15m.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ2

Answer:

x=50

Step-by-step explanation:

The solution to the equation x – 25 = 25 is x = 50. The axiom used to solve the equation is the addition property of equality.

To solve the equation x - 25 = 25, we want to isolate the variable x to find its value.

Adding 25 to both sides of the equation, we get:

x - 25 + 25 = 25 + 25

Simplifying, we have:

x = 50

Therefore, the solution to the equation is x = 50.

In this case, the axiom used to solve the equation is the addition property of equality. According to this axiom, if two expressions are equal, adding the same value to both sides of the equation preserves the equality.

In the given equation, we add 25 to both sides of the equation to maintain equality and obtain the solution x = 50. The addition property of equality allows us to perform this operation and determine the value of x.

To learn more about axioms click on,

https://brainly.com/question/33725824

#SPJ2

Answer: 17 and a half

Step-by-step explanation:

M    D    W

20  24  480

20   21  420

24   17 and a half  420

= 17 and a half

Answer:

500 kilometers

Step-by-step explanation:

The fuel (y) Karl has in his car is a function of the distance (x) Karl travelled. The amount of fuel (y) is dependent on the distance (x) Karl travelled.

On the y-axis, we have amount of fuel.

On the x-axis, we have distance travelled.

At the time Karl travelled when he had 200 liters of fuel (y) remaining in his car, he had travelled a distance (x) of 500 kilometers.

We know this by looking at the graph given. When x (distance) = 500, y (fuel) = 200.

Answer:

= 21i

Step-by-step explanation:

√-9 = 3i

= 7 . 3i

Multiply the numbers: 7 . 3 = 21

= 21i

Hope this helps!

Answer: The answer is A

Step-by-step explanation:

In the picture, model A shows 3 groups and in the 3 groups are 4 lines !

I'm bad explaining but I hope this helps .

Answer:

20 glasses a day

Step-by-step explanation:

2.5litres equals 2500millilitres

2500÷125=20

Step-by-step explanation:

answer in the image above

Answer:

x = 1.9

Step-by-step explanation:

Thanks to a theorem we can use this proportion

10.47 : 4.44 = 4.44 = x

x = (4.44^2)/10.47 = 1,882865 = 1.9

Given:

In a right angle triangle ABC, [tex]m\angle C=90^\circ , a=4[/tex] and [tex]\sin A=\dfrac{1}{2}[/tex].

To find:

The length of the hypotenuse.

Solution:

It is given that [tex]m\angle C[/tex], so opposite side of this angle is the hypotenuse, i.e., c.

In a right angle triangle,

[tex]\sin \theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]

In the given triangle,

[tex]\sin A=\dfrac{a}{c}[/tex]

Substituting the given values, we get

[tex]\dfrac{1}{2}=\dfrac{4}{c}[/tex]

By cross multiplication, we get

[tex]1\times c=4\times 2[/tex]

[tex]c=8[/tex]

Therefore, the length of the hypotenuse is 8 units.

9514 1404 393

Answer:

  14.4

Step-by-step explanation:

The Pythagorean theorem tells you ...

  7² +a² = 16²

  a² = 256 -49

  a = √207

  a ≈ 14.4

Answer:

D 4x-y=1

Step-by-step explanation:

4x-y=1. (x=0 ,y= -1)

4(0)-(-1)= 1

0+1= 1

4x-y=1 (x=1 y=3)

4(1)-3=1

4-3=1

6+T=1

Try T=-5

6+(-5) = 1

Correct, So...

T=-5

Answer:

The additional deposit to be made in one year should be $ 301.81.

Step-by-step explanation:

Given that I need to save $ 1,300 to go overseas in two years, and I deposit $ 800 in a savings account today, that earns 10% interest, and I will make an additional deposit in one year, to determine how much must I deposit in one year in order to have enough to go on the trip, the following calculation must be performed:

800 x 1.1 = 880

(880 + X) x 1.1 = 1300

1300 / 1.1 = 1,181.81

1,181.81 - 880 = X

301.81 = X

Therefore, the additional deposit to be made in one year should be $ 301.81.

Answer:

1) P = 282m, A = 141m^2

2) P = 82.4in, A = 40in^2

3) P = 62.7m, A = 73.1m^2

Step-by-step explanation:

1) top:L=12m, W=3m, mid: l= 12m, w= 12-7 = 5m, bot: l=15m, w=3m

Perimeter= 2(lw)

P = 2(12x3) + 2(12x5) + 2(15x3)

P = 2(36) + 2(60) + 2(45)

P = 72 + 120 + 90

P = 282m  

Area= lw

A = (12x3) + (12x5) + (15x3)

A = 36 + 60 + 45

A = 141m^2

2) Rectangle:l=7in, w=5in, Right Triangle:a=5-3=2in, b=12-7=5in

Perimeter= 2(lw) + (a+b+sqrt(a^2+b^2))

P = 2(7x5) + (2+5+sqrt(2^2+5^2))

P = 70 + 12.39

P = 82.4in

Area= lw + ((ab)/2)

A = (7x5) + ((2x5)/2)

A = 35 + 5

A = 40in^2

3) Semi-Circle: d=8m, r=8/2=4m, Right Triangle: a=8m, b=12m

Perimeter= pid + (a+b+sqrt(a^2+b^2))

P = 9pi + (8+12+sqrt(8^2+12^2))

P = 28.27 + 34.42

P = 62.7m

Area= (1/2)pir^2 + ((ab)/2)

A = (1/2)pir^2 + ((ab)/2)

A = (1/2)pi(4)^2 + ((8x12)/2)

A = 25.13 + 48

A = 73.1m^2