Solve the equation for x:

3x+5=20

Answer: f(-3) = -10

Step-by-step explanation:

[tex]Substitute \ $x=-3$\\\\$$\begin{aligned}&f(3)=2(-3)-4 \\&f(3)=-6-4 \\&f(3)=-10\end{aligned}$$[/tex]

Answer:

3. 3(x+y)(x-y)

4. (y²+4)(y+2)(y-2)

5. 2(3x+1)(x+2)

Step-by-Step:

3. 3(x²-y²) = 3(x+y)(x-y)

4. y⁴-16 = (y²+4)(y²-4)= (y²+4)(y+2)(y-2)

5. 6x²+14x+4 = 2(3x²+7x+2) = 2(3x+1)(x+2)

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(I have verified my answers on an online calculator)

Answer:

ice cream 3

coffee 5

................

Answer:

coffee is $5 each and $3 for ice cream

Step-by-step explanation:

The standard form of the given equation  [tex]x^2+y^2-18x+8y+5=0[/tex] will be given as  [tex](x-9^2)+(y+4)^2=(2\sqrt{23} )^2[/tex]

The general form of the equation of the circle is given  as

[tex](x-h)^2+(y-k)^2=r^2[/tex]

We have the equation

[tex]x^2+y^2-18x+8y+5=0[/tex]

By adding 81 and 16 on both sides

[tex]x^2-18x+81+y^2+8y+16=-5+81+16[/tex]

[tex](x-9)^2+(y+4)^2=92[/tex]

[tex](x-9)^2+(y+4)^2=(2\sqrt{23})^2[/tex]

Thus the standard form of the given equation  [tex]x^2+y^2-18x+8y+5=0[/tex] will be given as  [tex](x-9^2)+(y+4)^2=(2\sqrt{23} )^2[/tex]

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Answer:

x-9, y+4, & 92

Step-by-step explanation:

i did it

The volume of the stucture made from three rectangular prism is 4080 ft³

Volume is the amount of space occupied by a three dimensional shape or object.

The volume of the rectangular prism = length * width * height = 12 * 10 * 5 = 600 ft³

The volume of the other prism = length * width * height = 10 * 8 * 36 = 2880 ft³

Volume of the structure = 600 ft³ + 600 ft³ + 2880 ft³ = 4080 ft³

The volume of the stucture made from three rectangular prism is 4080 ft³

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Answer:

Voir ci-dessous.

Step-by-step explanation:

1.

OA/OD = 36/64 = 9/16

OB/OC = 27/48 = 9/16

m<AOB = m<COD

triangle AOB ~ trianlge DOC

m<BAO = m<CDO

AB || CD

2.

AB/CD = OA/OD

AB/80 = 36/64

AB/80 = 9/16

16AB = 9 × 80

AB = 9 × 5

AB = 45

AB = 45 cm

3.

AB = 45

BC = OC + OB = 48 + 27 = 75

AB² + AC² = BC²

45² + AC² = 75²

AC² = 5625 - 2025

AC = √3600

AC = 60 cm

hauteur = 5 × 2 cm + 4 × 60 cm

hauteur = 10 cm + 240 cm

hauteur = 250 cm

Answer:

AC=18.1cm

Step-by-step explanation:

When we subtract 11-4=7cm  we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.

We will use Pythagorean theorem to find the second cathetus b

b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>

AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm

AC=18.1cm

Answer:

7.744

Step-by-step explanation:

For this problem you have to work backwards

The equation for the volume is V = (area of circle) x height

So here, to solve the area of the circle, you need to divide the 235.5 by 5

So:

235.5 = (area of circle) x 5

Area of circle is 47.1

Then, you need to find the radius of the circle by using this equation for the area of a circle

[tex]A = \pi \cdot r^{2}[/tex]

So:

47.1 = π * [tex]r^{2}[/tex]

r = 3.872

This question is asking for the diameter, which is double the radius,

2 x 3.872 = 7.744

By working with percentages, we will see that there are 1,080 seats in the theater.

We know that the students filled 702 seats, leaving 35% vacant.

Then 702 seats represents the (100% - 35% = 65%) of the total number of seats.

So, if the total number of seats is S, we can write:

(65%/100%)*S as the 65% of S.

Then we solve:

(65%/100%)*S = 702

0.65*S = 702

S = 702/0.65 = 1,080

There are 1,080 seats in the theater.

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Answer:

it could be many answers but my guess is acute

Answer:

(3) We can also name an angle by placing any number or symbol at the vertex in the INTERIOR of the angle. So, angles can also be called angle 1 or angle 2 or angle 4, etc. Sides AB and AC of the given angle are actually rays.

Step-by-step explanation:

Answer:

The last answer.

Step-by-step explanation:

Regular means all the side lenghts are the same and all the interior angle measures are the same. Think a stop sign.

Irregular polygons have different side lengths and different interior angle measures.

Answer:

0

Step-by-step explanation:

-2-3+5

-5+5

0

Answer:

Step-by-step explanation:

A = true

D = true

Answer:

(1, - 2.5 )

Step-by-step explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

here (x₁, y₁ ) = (M (- 5, 3 ) and (x₂, y₂ ) = N (7, - 8 ) , then

midpoint = ( [tex]\frac{-5+7}{2}[/tex] , [tex]\frac{3-8}{2}[/tex] ) = ( [tex]\frac{2}{2}[/tex] , [tex]\frac{-5}{2}[/tex] ) = ( 1, - 2.5 )

Answer:

A=130cm2

Step-by-step explanation:

13x10=130

Answer:

Step-by-step explanation:

where is the full question????

Answer:

Approximating has always been an important process in the experimental sciences and engineering, in part because it is impossible to make perfectly accurate measurements. Approximation also arises because some numbers can never be expressed completely in decimal notation. In these cases approximations are used.

Answer:

Approximating has always been an important process in the experimental sciences and engineering, in part because it is impossible to make perfectly accurate measurements. Approximation also arises because some numbers can never be expressed completely in decimal notation. In these cases approximations are used.

Step-by-step explanation:

Answer:

487.5 km

Step-by-step explanation:

Let :

Solving

Forming an equation

Answer: [tex]4\frac{4}{5}[/tex]

Step-by-step explanation:

To see how many [tex]\frac{1}{6}[/tex] pound servings are in [tex]\frac{4}{5}[/tex] of a pound of chicken we must divide [tex]\frac{4}{5}[/tex] by [tex]\frac{1}{6}[/tex]

[tex]\frac{4}{5}[/tex]÷[tex]\frac{1}{6}[/tex]

When dividing by a fraction you can take the reciprocal (flip the numerator and denominator) and you can multiply instead of dividing

[tex]\frac{4}{5}[/tex]×[tex]\frac{6}{1}[/tex]=[tex]\frac{24}{5}[/tex]=[tex]4 \frac{4}{5}[/tex]

Answer:

24/5, or 4.8, servings

Step-by-step explanation:

Let s represent the number of servings. We have:

[tex] \frac{1}{6} s = \frac{4}{5} [/tex]

[tex]s = \frac{24}{5} = 4.8[/tex]

Answer:

4/7

Step-by-step explanation:

1/4 divided by 7/16 is the same thing as 1/4 * 16/7. Multiply this and you will get the fraction of 16/28. Once simplified, this comes out to be 4/7.

Answer:

5.5

Step-by-step explanation:

We nned to divide to solve this!!

22/4 = 5.5

She is going 5.5 mph!!

Have an amazing day!!

Please rate and mark brainliest!!!!

Answer:

Rs. 22,080.

Step-by-step explanation:

Let the height be x m then the breadth is 3x and the length 5x m.

x * 3x * 5x = 960

15x^3 = 960

x^3 = 64

x = ∛ 64 = 4m.

Therefore the height is 4m, the breadth = 12 m and the length = 20m.

So the area of all the surfaces

= 2 * short wall + 2 * long wall + floor + ceiling

= 2 *4*12 + 2*4*20 + 12*20 + 12*20

=  96 + 160 + 240 + 240

= 736 m^2.

Cost plastering  = 736 * 30 = Rs. 22,080

Answer:

0.078125.

Step-by-step explanation:

This is a geometric sequence with first term a1 = 20 and common ratio r = 10/20 = 5/10 = 0.5.

nth term = a1 r^(n -1) so here:

9th term = 20(0.5)^(9-1)

= 20(0.5)^8

= 0.078125.

Answer:

20

Step-by-step explanation:

3x=x+40

Because Vertical Angles

2x=40

x=20

Answer: it is likely that both the number of frostbite cases and the number of sledding accidents are negatively correlated with temperature.

Step-by-step explanation: I just took the test.

The correct answer is the frostbite cases and sledding accidents were not randomly selected.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

If the data for the number of frostbite cases and sledding accidents were not randomly selected, then the correlation between them might not be valid.

if the data were only collected during a specific time period when sledding was popular and the weather was cold, then the number of frostbite cases and sledding accidents might be higher than normal.

In this case, the correlation might be due to the common factor of cold weather, rather than frostbite causing sledding accidents.

Therefore, it is important to consider the methodology of the study and the factors that might influence the correlation between frostbite cases and sledding accidents before concluding that frostbite is the main cause of sledding accidents

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Answer:

Step-by-step explanation:

This is a quadrilateral. A quadrilateral is a plane figure that has four sides or edges, and also has four corners or vertices.

The interior angles of a simple quadrilateral ABCD add up to 360 degrees of arc.

Answer:

Angle x = 40°

Step-by-step explanation:

All angles of any quadrilateral sum up to 360°.

So here, already measure of 3 angles are given.

So if we add up all angles + Angle x then it sums up to 360°.

So, the following steps will lead you to the answer:

73° + 157° + 90° + Angle x = 360°

(Now add up the measure of the three given angles)

320° + Angle x = 360°

(Now, through transposition moves 320° to the RHS) (Remember when transposing the signs change)

Angle x = 360° - 320°

Finally,

Angle x = 40°

Hope it helps!!!

The Laplace transform of the non-homogeneous second order differential equation is [tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex].

A Laplace transform is a frequency-based algebraic substitution method used to determine the solutions of differential equations in a quick and efficient manner.

In this question we shall use the following Laplace transforms:

[tex]\mathcal {L} \{f(t) + g(t)\} = \mathcal {L} \{f(t)\} + \mathcal {L}\{g(t)\}[/tex]   (1)

[tex]\mathcal {L} \{\alpha\cdot f(t)\} = \alpha\cdot \mathcal {L} \{f(t)\}[/tex]   (2)

[tex]\mathcal{L} \left\{y^{(n)} \right\} = s^{n}\cdot \matcal {L}\{f(t)\}-s^{n-1}\cdot y(0) -...-y^{(n)}(0)[/tex]   (3)

[tex]\mathcal {L} \{e^{-a\cdot t}\} = \frac{1}{s+a}[/tex]   (4)

Now we proceed to derive an expression fo the Laplace transform of the solution of the differential equation:

[tex]y'' -5\cdot y' = 8\cdot e^{4\cdot t}-4\cdot e^{-t}[/tex]

[tex]s^{2}\cdot \mathcal {L}\{f(t)\}-5\cdot y(0) - y'(0) - 5\cdot s \cdot \mathcal {L} \{f(t)\} +5\cdot y(0) = \frac{8}{s-4}-\frac{4}{s+1}[/tex]

[tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex]

The Laplace transform of the non-homogeneous second order differential equation is [tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex]. [tex]\blacksquare[/tex]

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The Laplace transform Y'' − 5y' = 8e4t − 4e−t when y(0) = 1, y'(0) = −1 for f(t) = 8e4t − 4e−t would be  [tex]\frac{4(s+6)}{s.(s-4)(s+1).(s-5)} + \frac{1}{s} - \frac{1}{s.(s-5)}[/tex].

A Laplace transform is a frequency-based algebraic substitution method used to determine the solutions of differential equations quickly and efficiently.

The Laplace transform

L[ f(t) + g(t) ] = Lf(t) + Lg(t)

Also,

L [[tex]y^{n}[/tex]] = [tex]s^{n} . L[ f(t) ] - s^{n-1} .y(0) .....y^{n}(0)[/tex]

We have

Y'' − 5y' = 8 . e^4t − 4 . e−t

[tex]s^{2} . L[ f(t) ] - 5. y(0)- y'(0) .....y^{n}(0)[/tex]

y(0) = 1, y'(0) = −1  

for f(t) = 8e4t − 4e−t.

= [tex]\frac{8}{s-4} - \frac{4}{s+1}[/tex]

L [f(t)] = [tex]\frac{4(s+6)}{s.(s-4)(s+1).(s-5)} + \frac{1}{s} - \frac{1}{s.(s-5)}[/tex]

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Answer:

2.1 standard drinks

(or 2 if you need to round to the nearest whole number)

Step-by-step explanation:

The ABV (alcohol by volume) percentage is a measure of the amount of pure alcohol (as a percentage) of the total volume of liquid in a drink.

So for 16% wine, this means that 16% of the volume of the wine is pure alcohol.

Therefore, if 16% of 8 fl oz is pure alcohol, this means that 1.28 fl oz of the 8 fl oz is pure alcohol (since 0.16 × 8 = 1.28).

One standard drink ≈ 0.6 fl oz pure alcohol

To calculate the number of standard drinks, divide the total amount of pure alcohol found by the amount in one standard drink:

1.28 ÷ 0.6 = 2.1

Therefore there is approximately 2.1 standard drinks in 8 fl oz of 16% wine.

No photo attached, but no need.

We're given that f(0) = 1 and f(2) = 5, and that

[tex]\displaystyle \int_0^2 f(x) \, dx = 7[/tex]

Integrate x f'(x) by parts, with

[tex]u = x \implies du = dx[/tex]

[tex]dv = f'(x) \, dx \implies v = f(x)[/tex]

Then

[tex]\displaystyle \int_0^2 x f'(x) \, dx = uv\bigg|_{x=0}^{x=2} - \int_0^2 v \, du \\\\ = x f(x) \bigg|_{x=0}^{x=2} - \int_0^2 f(x) \, dx[/tex]

Now just plug in everything you know:

[tex]\displaystyle \int_0^2 x f'(x) \, dx = 2f(2) - 0f(0) - \int_0^2 f(x) \, dx = 10 - 0 - 7 = \boxed{3}[/tex]