poisson The average number of accidental drownings per year in the USA is 3.0 per 100,000. What is the probability that in a city with a population of 200,000 there will be exactly 2 accidental drownings per year

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Answer 1

2.23% is the probability of a city with a population of 200,000, and there will be exactly 2 accidental drownings per year.

The Poisson distribution, is useful for modeling the number of events (in this case, accidental drownings) in a fixed interval (here, a year). Given the average rate of 3.0 drownings per 100,000 people per year, we first need to find the expected number of drownings in a city with a population of 200,000.

Expected drownings per year = (3.0 drownings / 100,000 people) * 200,000 people = 6 drownings

Now, we can use the Poisson probability formula to calculate the probability of exactly 2 accidental drownings per year in this city:

P(X = k) = (λ^k * e^(-λ)) / k!

Here, X represents the number of drownings, k is the desired number of drownings (2 in this case), λ (lambda) is the expected number of drownings per year (6), e is the base of the natural logarithm (approximately 2.718), and k! is the factorial of k.

P(X = 2) = (6^2 * e^(-6)) / 2! = (36 * e^(-6)) / 2 = (36 * 0.002478) / 2 = 0.04461 / 2 = 0.022305

Therefore, the probability that in a city with a population of 200,000, there will be exactly 2 accidental drownings per year is approximately 0.0223 or 2.23%.

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Related Questions

The interarrival time of customers is 2 minutes. The processing time is 5 minutes. What is the minimum number of servers needed

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The denominator is negative, we know that the system is unstable and there is no minimum number of servers that can guarantee a stable system.

To determine the minimum number of servers needed, we can use the following formula:

[tex]N = (p^2 + p) / (2(1 - p))[/tex]

where N is the number of servers, ρ is the utilization factor, which is equal to the ratio of the average service time (5 minutes) to the interarrival time (2 minutes), or ρ = 5/2 = 2.5, and the denominator is equal to the average number of customers in the system.

Plugging in the values, we get:

[tex]N = (2.5^2 + 2.5) / (2(1 - 2.5))[/tex]

N = 6.25 / (-3)

Since the denominator is negative, we know that the system is unstable and there is no minimum number of servers that can guarantee a stable system. This means that either the interarrival time or the processing time needs to be adjusted to achieve a stable system.

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A random sample of size 36 is taken from a population with mean 50 and standard deviation 5. What is

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When a sample is taken from a population, it is important to understand the characteristics of both the sample and the population. In this scenario, the sample size is 36, meaning that 36 individuals or data points were randomly selected from the larger population.

The population mean is 50, which tells us the average value of the population data. The standard deviation of the population is 5, which indicates the degree of variability in the data.

Using the information provided, we can calculate the standard error of the mean (SEM), which is the standard deviation of the sample mean. The formula for SEM is:

[tex]SEM = population standard deviation / square root of sample size[/tex]

SEM = 5 / square root of 36

SEM = 5 / 6

SEM = 0.83

Therefore, the standard error of the mean for this sample is 0.83. This means that if we were to take many samples of size 36 from this population, we would expect the mean of each sample to be within 0.83 units of the true population mean of 50.

It is important to note that while this sample may give us some insight into the characteristics of the larger population, it is not necessarily representative of the entire population. To increase the accuracy of our findings, we would need to take multiple random samples and calculate the means and standard errors of each sample.

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The probability of snow for each of the next three days is $\frac{2}{3}$. What is the probability that it will snow at least once during those three days

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The probability that it will snow at least once during the next three days is $\frac{26}{27}$.



To find the probability that it will snow at least once during the next three days, it is easier to first calculate the probability that it will NOT snow at all in those three days and then subtract that value from 1.

The probability of no snow for one day is 1 - $\frac{2}{3}$ = $\frac{1}{3}$.

For three days, the probability of no snow on all three days is the product of the individual probabilities:
($\frac{1}{3}$) * ($\frac{1}{3}$) * ($\frac{1}{3}$) = $\frac{1}{27}$.

Now, to find the probability of it snowing at least once during those three days, subtract the probability of no snow on all three days from 1:

1 - $\frac{1}{27}$ = $\frac{26}{27}$.

So, the probability that it will snow at least once during the next three days is $\frac{26}{27}$.

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You can spend no more than $1,400 and would like to save as much per year in energy costs as possible. How many compact fluorescent light bulbs and how many square feet of insulation should you purchase

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To determine how many compact fluorescent light bulbs and how many square feet of insulation to purchase, we need to make some assumptions about the cost and energy savings of each. Let's assume the following:

Each compact fluorescent light bulb costs $5 and lasts for 5 years. It uses 13 watts of power and provides the same amount of light as a 60 watt incandescent bulb.

Each square foot of insulation costs $0.50 and provides a 10% reduction in heating and cooling costs.

Let $x$ be the number of compact fluorescent light bulbs and $y$ be the number of square feet of insulation to purchase. Then we want to maximize the annual energy cost savings, subject to the constraint that the cost of the purchases is no more than $1,400. Mathematically, we can write:

The optimal solution depends on the specific costs, savings, and preferences for energy efficiency.

What is the optimal number of compact fluorescent light bulbs and square feet of insulation to purchase?

To determine the optimal number of compact fluorescent light bulbs and square feet of insulation to purchase, we need additional information such as the cost and energy savings associated with each item.

Without specific data on the costs and savings, it is not possible to provide an exact answer. However, I can give you a general approach to consider:

1. Determine the cost and energy savings for each compact fluorescent light bulb (CFL) and square foot of insulation.

2. Compare the cost savings per year for CFL bulbs and insulation to evaluate which option provides more savings.

3. Start by allocating the budget to the option with the higher cost savings per dollar spent.

4. Calculate the number of CFL bulbs and square feet of insulation that can be purchased within the budget.

5. Consider any practical limitations or minimum requirements for installation (e.g., minimum insulation coverage, minimum number of bulbs needed).

6. Adjust the quantities of CFL bulbs and insulation based on the budget allocation and practical considerations.

Remember that the optimal solution depends on the specific costs, savings, and preferences for energy efficiency.

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If all else remains constant and the values of two variables move in the same direction it indicates a Question 42 options: a) the values of the two variables will move in the same direction then move in opposite directions. b) inverse slope relationship. c) positive slope relationship. d) negative slope relationship.

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If all else remains constant and the values of two variables move in the same direction it indicates a positive slope relationship.

If all else remains constant and the values of two variables move in the same direction, it indicates a positive slope relationship. This means that as one variable increases, the other variable also increases. Conversely, if the values of two variables move in opposite directions, it indicates a negative slope relationship where as one variable increases, the other variable decreases. An inverse slope relationship is when two variables have opposite relationships and do not move in the same direction.

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An experimenter flips a coin 100 times and gets 51 heads. Find the 85% confidence interval for the probability of flipping a head with this coin. a) [0.438, 0.582] b) [0.488, 0.493] c) [0.338, 0.532] d) [0.358, 0.582] e) [0.438, 0.382] f) None of the above

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The 85% confidence interval for the probability of flipping a head with this coin is [0.438, 0.582], which corresponds to option a).

To find the confidence interval for the probability of flipping a head with this coin, we can use the formula:

CI = p ± z*sqrt((p(1-p))/n)

where p is the sample proportion (51/100), z* is the critical value from the standard normal distribution for an 85% confidence level (which is 1.44), and n is the sample size (100).

Plugging in these values, we get:

CI = 0.51 ± 1.44*sqrt((0.51(1-0.51))/100)

Simplifying, we get:

CI = 0.51 ± 0.104

Therefore, the 85% confidence interval for the probability of flipping a head with this coin is:

[0.406, 0.614]

This is not one of the answer choices given, so the correct answer is f) None of the above.
To find the 85% confidence interval for the probability of flipping a head with this coin, follow these steps:

1. Calculate the sample proportion (p-hat) by dividing the number of heads (51) by the total number of flips (100): p-hat = 51/100 = 0.51.

2. Determine the z-score for an 85% confidence interval. You can look this up in a standard normal distribution table, or use a calculator. The z-score is approximately 1.44.

3. Calculate the standard error (SE) using the formula: SE = sqrt((p-hat * (1-p-hat))/n), where n is the total number of flips. In this case, SE = sqrt((0.51 * 0.49)/100) ≈ 0.05.

4. Calculate the margin of error (ME) using the formula: ME = z-score * SE. In this case, ME = 1.44 * 0.05 = 0.072.

5. Determine the confidence interval by adding and subtracting the margin of error from the sample proportion: Lower limit = 0.51 - 0.072 = 0.438; Upper limit = 0.51 + 0.072 ≈ 0.582.

The 85% confidence interval for the probability of flipping a head with this coin is [0.438, 0.582], which corresponds to option a).

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Question 2 of 5 Select the correct answer from the drop-down menu. Twyla's parents want to have the orange part of their restaurant lamp shades painted in a flower pattern. What is the approximate area that will be painted on each lamp shade? 6 in 7 in The area of the lamp shade that will be painted is about Submit square inches. Reset​

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Here Is the Answer:

28

Step-by-step explanation:

To calculate the approximate area that will be painted on each lamp shade, we need to use the formula for finding the area of a circle: A = πr^2, where r is the radius of the circle. The diameter of the lamp shade is given as 6 inches, which means the radius is half of that, or 3 inches. Therefore, the area of the lamp shade that will be painted is approximately 3.14 x 3^2, which equals 28.26 square inches. So, the answer we select from the drop-down menu would be "28 square inches."

I will mark brainiest and 100 points to whoever fully answers these questions for me tyyy pls help

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The inverse of the function are shown below.

To find the inverse of function replace x and y and solve for x we get,

1. h(n)= 2/3n - 2

y= 2/3n-2

2/3n = y+2

n= 3/2(y+2)

n = 3/2y + 3

So, the inverse is y= 3/2n + 3.

2. g(x) = -x + 3

y = -x+ 3

-x= y- 3

x = 3-y

So, the inverse is y= 3 -x

3. g(n) = -4n+ 12

y= -4n+ 12

-4n = y- 12

n = 3 - y/4

So, the inverse is y = 3- n/4

4. g(x) = -3x+ 9/2

y = -3x + 9/2

2y - 9 = -3x

x = 3 - 2y/3

So, the inverse is y = 3 -2x /3

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If a woman and her husband, who are both carriers, have three children, what is the probability that all three children have the normal phenotype

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If both parents are carriers of a recessive trait, the probability that all three children will have the normal phenotype is around 42.19%.

If both parents are carriers of a recessive trait, the probability that their children will have the normal phenotype can be determined using a Punnett square. Since both parents are carriers, their genotypes are heterozygous (Aa).

When we create a Punnett square, we see the following outcomes for their children's genotypes:
- AA (25%)
- Aa (50%)
- aa (25%)

To have a normal phenotype, the child must have either AA or Aa genotype. Therefore, the probability of one child having a normal phenotype is 75% (25% + 50%).

Now, to calculate the probability of all three children having a normal phenotype, we multiply the probabilities of each child:

0.75 × 0.75 × 0.75 = 0.421875, or approximately 42.19%.

So, the probability that all three children will have the normal phenotype is around 42.19%.

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Describe what is meant by a mixed Nash Equilibrium. Give an example of a 2-player

game, and exhibit a mixed-Nash equilibrium.

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A mixed Nash Equilibrium is a concept in game theory where each player in a 2-player game chooses a mixed strategy that maximizes their expected payoff, given the strategies of the other player.

In other words, it is a situation where neither player can improve their payoff by unilaterally changing their strategy.
An example of a 2-player game is the classic "Prisoner's Dilemma". In this game, two suspects are arrested for a crime and are being held in separate cells. The prosecutor offers each suspect a plea bargain: if one confesses and the other remains silent, the one who confesses will receive a reduced sentence while the other will receive a harsher sentence. If both confess, they will each receive a moderately harsh sentence, and if both remain silent, they will each receive a light sentence.
To exhibit a mixed Nash Equilibrium in this game, let's assume that both suspects choose between two strategies: "confess" or "remain silent". If one player confesses, the other player's best response is also to confess (since the harsher sentence for remaining silent is worse than the moderately harsh sentence for confessing). However, if both players confess, they both receive a moderately harsh sentence which is worse than if both remained silent. Therefore, neither player has a dominant strategy.
To find the mixed Nash Equilibrium, we can assign probabilities to each strategy for each player. Let's assume that each player chooses "confess" with probability p and "remain silent" with probability 1-p. If one player chooses "confess" with probability p, the other player's expected payoff is 2p (if they also confess) or 1-2p (if they remain silent). Therefore, the other player's best response is to choose "confess" with probability q=2p/(2p+1-2p) or "remain silent" with probability 1-q. Similarly, if the other player chooses "confess" with probability q, the first player's best response is to choose "confess" with probability p=2q/(2q+1-2q) or "remain silent" with probability 1-p.

Solving for the mixed Nash Equilibrium, we find that both players should choose "confess" with probability 1/3 and "remain silent" with probability 2/3. This means that in the long run, both suspects will confess approximately one-third of the time and remain silent two-thirds of the time, resulting in a moderately harsh sentence for both players.
A mixed Nash Equilibrium refers to a situation in a 2-player game where both players adopt a randomized strategy, and neither of them can improve their expected payoff by unilaterally changing their strategy. In other words, both players are indifferent among their strategies, and neither has an incentive to deviate from their current mixed strategy.
An example of a 2-player game that exhibits a mixed Nash Equilibrium is the classic game of Rock-Paper-Scissors. In this game, each player has three strategies: rock, paper, or scissors. The rules are that rock beats scissors, scissors beats paper, and paper beats rock.
To find the mixed Nash Equilibrium, both players should choose each strategy with equal probability (1/3 for rock, 1/3 for paper, and 1/3 for scissors). By doing this, each player's expected payoff is the same regardless of their opponent's strategy, as the chances of winning, losing, or tying are equal. Thus, there is no incentive for either player to deviate from this randomized strategy, and the mixed Nash Equilibrium is achieved.

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True or false: Regression calculations are typically done on a computer because the calculations can be quite tedious and lengthy.

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True: Regression calculations are typically done on a computer because the calculations can be quite tedious and lengthy.

A regression is a statistical technique that relates a dependent variable to one or more independent (explanatory) variables. A regression model is able to show whether changes observed in the dependent variable are associated with changes in one or more of the explanatory variables

True. Regression calculations involve complex mathematical computations and analyzing large datasets, which can be time-consuming and prone to errors if done manually. Using a computer with specialized software can automate the process, making it faster, more accurate, and efficient.

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Why do you add the absolute values?

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Absolute values of the integers can be added to find the sum of the integers.

Absolute value of a number is the distance of that number from the point of origin of a number line. Or in other words absolute value of a number is the magnitude of that number without concerning about the sign.

When doing the addition of two integers, we use absolute value.

If the two integers are having the same sign, then add the absolute value of the integers and then given the same sign as that of the given integers.

If the  two integers are having the opposite sign, then subtract the integer with less absolute value from the greater one. Give the sign as that of the greater one.

Hence the absolute values of the integers can be added to find the sum of the integers.

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The divorce rate for women who marry over the age of 20 years is 36%. The divorce rate for women who were married when they were 18 years or younger is ____________.

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The divorce rate for women who were married when they were 18 years or younger is higher than for those who marry over the age of 20 years. According to the latest research and studies conducted by various organizations, the divorce rate for women who marry at the age of 18 or younger is around 48%.

There are several reasons for the higher divorce rate among women who marry at a young age. One major factor is lack of maturity and life experience. Marriage requires a certain level of maturity and emotional stability to navigate the ups and downs that inevitably come with any long-term commitment. Many young women who marry before the age of 20 may not have fully developed these qualities, leading to conflict and dissatisfaction in the relationship.

Another factor is societal pressure and expectations. Women who marry young are often expected to take on traditional roles such as homemaker and mother, which can be overwhelming and stressful. This can lead to feelings of resentment and frustration, which can ultimately lead to divorce.

It's worth noting that there are exceptions to every rule, and there are certainly couples who marry young and have long, happy marriages. However, statistics show that the divorce rate is higher among those who marry at a young age.

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423 x 764 to one significant number

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Answer: 420,000

Step-by-step explanation: Brainliest pls:)

An object is moving at a speed of g kilometers every 6.5 years. Express this speed in inches per day. Round your answer to the nearest whole number. Note: you must use these exact conversion factors to get this question right. Distance/ length 1 foot (ft) = 12 inches (in) 1 yard (yd) =3 feet (ft) 1 mile (mi) = 528o feet (ft) 1 meter (m) = 100 centimeters (cm) 1 kilometer (km) = 1000 meters (m) 1 inch (in) = 2.54 centimeters (cm) 1 foot (ft) = 0.305 meters (m) 1 mile (mi) = 1.60g kilometers (km) Time 1 minute (min) 60 seconds (sec) 1 hour (hr) = 60 minutes (min) 1 day (day) = 24 hours (hr) 1 week (week) =7 days (days) 1 month (month) = 30 days (days) 1 year (year) 365 days (days)​

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The object is moving at 149 inches everyday

If seven minutes elapse between a customer's arrival at the store and his departure from the service window, find the probability that he waited in line less than one minute to reach the window. (Enter your probability as a fraction.) CHEGG

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The probability that a customer waited in line for less than one minute to reach the window is [tex]\frac{1}{7}[/tex].

f(x) = [tex]\frac{1}{7}[/tex], 0 <= x <= 7

We want to find the probability that the waiting time is less than 1 minute, which is equivalent to finding the area under the probability density function from 0 to 1. This can be calculated using the following formula:

P(X < 1) = ∫[0,1] f(x) dx

Substituting the probability density function, we get:

P(X < 1) = ∫[0,1] [tex]\frac{1}{7}[/tex] dx

Integrating with respect to x, we get:

P(X < 1) = [[tex]\frac{x}{7}[/tex]][tex]0^1[/tex] = [tex]\frac{1}{7}[/tex]

Probability is a branch of mathematics that deals with the measurement and quantification of uncertainty. It is the study of the likelihood or chance of an event occurring, based on available information or data. Probability can be used to predict the outcome of a random event, such as rolling a dice or flipping a coin.

The probability of an event is expressed as a number between 0 and 1, with 0 meaning the event is impossible, and 1 meaning the event is certain. For example, the probability of rolling a six on a dice is 1/6, or approximately 0.17. Probability is used in a wide range of fields, including statistics, finance, engineering, and science. It is often used in decision-making to determine the best course of action in situations where there is uncertainty or risk involved.

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Utilizando los números 1,4,5 y 8 solo una vez, escribe:
numero impar mas pequeño

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The smallest odd number that can be formed via the use of the numbers 1, 4, 5, and 8 if used once each will be 15.

What is the odd number?

To find the smallest  odd number via the use of the numbers 1, 4, 5, and 8 fair once, we have to make use of the digit 1 as the units digit, since it is the as it were odd digit accessible.

To make the complete number as little as seen, the another digit need to be the smallest even digit accessible, which is 4. At that point, the remaining two digits need to be put within the final two positions to create the smallest given number. Hence, we make use of 5 and 8 to create the two left over digits.

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See text below

Using the numbers 1,4,5 and 8 just once, write: smallest odd number

Using the regression line for this problem, the approximate rolling distance for a child on a bike that weighs 110 lbs. is:

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To determine the approximate rolling distance for a child on a bike weighing 110 lbs, we would need the regression line equation derived from a statistical analysis.

The regression line represents the relationship between the weight of the bike and the rolling distance. With the regression line equation, we can substitute the weight of 110 lbs into the equation to estimate the corresponding rolling distance. The regression analysis would have been performed using a dataset with various bike weights and their corresponding rolling distances. By analyzing the data, the regression line provides an approximation for predicting the rolling distance based on the weight of the bike.

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Madison calculates the mean and standard deviation of chloride values from wells near the seashore. They has performed a(n) ____.

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Madison calculates the mean and standard deviation of chloride values from wells near the seashore. They have performed a statistical analysis.

In this scenario, Madison is examining chloride levels in wells located close to the seashore. To analyze the data, they use two common statistical measures: mean and standard deviation. The mean, or average, is calculated by summing up all the chloride values and dividing the total by the number of samples. This provides a central tendency for the data set, giving an overall understanding of chloride levels in the wells.

Standard deviation is another important measure that helps assess the dispersion or spread of the chloride values. A low standard deviation indicates that the values are closely clustered around the mean, while a high standard deviation suggests a wider spread or more variability in the data. By calculating both the mean and standard deviation, Madison can gain valuable insights into the chloride concentrations near the seashore and identify any trends, patterns, or potential issues that may require further investigation or action.

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Suppose that X is a normally distributed random variable, with mean 10 and standard deviation 2. What is the probability that X has a value smaller than 7.5? g

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The probability that X has a value smaller than 7.5 is approximately 0.1056.

To find the probability that X is smaller than 7.5, we have to standardize the variable using the z-score formula:

z = (x - μ) /σ

here,

x = value of probability,

μ = mean of the distribution, and

σ= standard deviation.

Now, we get,

z = (7.5 - 10) / 2 = -1.25

Now, we have to find the probability that Z (the standardized variable) is less than -1.25.

From a standard normal distribution table, we get that the probability of Z being less than -1.25 is 0.1056.

Therefore, the probability that X has a value smaller than 7.5 is approximately 0.1056.

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The probability that X has a value smaller than 7.5 is approximately 0.1056. This means that in a large number of trials, we would expect X to be smaller than 7.5 about 10.56% of the time.

To answer this question, we need to use the properties of the normal distribution. We know that X is normally distributed with mean 10 and standard deviation 2. We want to find the probability that X has a value smaller than 7.5.
We can use the standard normal distribution to solve this problem. To do this, we first need to standardize the value of 7.5. We do this by subtracting the mean from 7.5 and dividing by the standard deviation:
Z = (7.5 - 10) / 2 = -1.25
Now we can use a standard normal distribution table or calculator to find the probability that Z is less than -1.25. This probability is approximately 0.1056.

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You want to establish control limits on your chart with a certain confidence level. You are using a z-value of 1.96. What percentage confidence interval is implied by this z-value

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The z-value of 1.96 is often used to establish control limits on a chart with a 95% confidence level.

This means that we can be 95% confident that the data falls within the control limits. The confidence level is calculated using the normal distribution curve and is equivalent to the area under the curve between the mean and the control limits. The z-value represents the number of standard deviations from the mean, and a z-value of 1.96 corresponds to the 97.5th percentile of the normal distribution curve.

In other words, there is a 2.5% chance that the data falls outside of the control limits. It is important to choose an appropriate confidence level based on the specific application and the consequences of making incorrect decisions based on the data.

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consider a die where the probability of rolling 1, 2, 3, 4, 5, and 6 are in the ratio 1:2:3:4:5:6. what is the probability that when this die is rolled twice, the sum

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The probability that when the die is rolled twice, the sum is 7 is 0.233.

The probability of rolling each number on the die can be expressed as follows:

P(1) = 1/6, P(2) = 2/6, P(3) = 3/6, P(4) = 4/6, P(5) = 5/6, P(6) = 6/6

To find the probability of rolling a sum of 7 when the die is rolled twice, we can use the concept of the convolution of probability distributions.

We can calculate the probability of obtaining each possible sum by multiplying the probabilities of the individual outcomes that add up to that sum, and then summing these products over all possible combinations of the outcomes. The possible sums that can be obtained when rolling the die twice are 2, 3, 4, ..., 11, 12.

For example, the probability of obtaining a sum of 7 is:

P(1 and 6) + P(2 and 5) + P(3 and 4) + P(4 and 3) + P(5 and 2) + P(6 and 1)

= (1/6)×(6/6) + (2/6)×(5/6) + (3/6)×(4/6) + (4/6)×(3/6) + (5/6)×(2/6) + (6/6)×(1/6)

= 0.233. Therefore, the probability of rolling a sum of 7 when the die is rolled twice is 0.233.

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g The sails of the real Lady Washington have an area of 410 SI units. What is the area of the sails of the scale model

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In this example, the area of the sails of the scale model would be 1.025 SI units

To determine the area of the sails of the scale model, you'll first need to know the scale ratio between the real Lady Washington and the model.

A scale ratio is expressed as a fraction, such as 1:20, which means that 1 unit on the model represents 20 units on the real object.

Once you have the scale ratio, you'll need to apply the square of this ratio to the area of the sails of the real Lady Washington. For example, if the scale ratio is 1:20, then the ratio for the area calculation will be (1/20)^2, or 1/400.

Now, simply multiply the area of the real sails (410 SI units) by the square of the scale ratio. Using the 1:20 example, you'd calculate:

410 SI units * (1/400) = 1.025 SI units.

. Remember to replace the scale ratio with the actual ratio provided for your specific question.

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Swimming one lap in a pool is defined as going across a pool and back again. If a swimmer swims 3 laps in 9 minutes, how can his average velocity be zero?

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If a swimmer swims 3 laps in a pool in 9 minutes, their average velocity can be zero because the swimmer returns to the starting point after each lap.

A lap in a pool consists of going across the pool and back again. Since the swimmer starts and ends at the same location for each lap, their displacement (change in position) is zero after completing each lap. Velocity is defined as the rate of change of displacement with respect to time.
To calculate the average velocity, we need to divide the total displacement by the total time. In this case, the total displacement is zero because the swimmer returns to the starting point after each lap, and the total time is 9 minutes. Therefore, the average velocity is:
Average velocity = (Total displacement) / (Total time) = (0) / (9 minutes) = 0
So, the swimmer's average velocity can be zero after swimming 3 laps in a pool in 9 minutes.

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Your client who is a novice exerciser demonstrates that he can perform a 1-RM bench press at 100 pounds. What would be an appropriate starting resistance for the first set of 12 repetitions

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The answer is that an appropriate starting resistance for the first set of 12 repetitions for a novice exerciser who can perform a 1-RM bench press at 100 pounds would be around 50-60% of their 1-RM, which would be around 50-60 pounds.

It is important to understand the concept of "training load" when designing a resistance training program. The training load is the amount of weight or resistance that is lifted during an exercise, and it is typically expressed as a percentage of the 1-RM.

For a novice exerciser who is just starting out with resistance training, it is important to start with a relatively low training load to avoid injury and allow the body to adapt to the stress of the exercise. A good starting point is usually around 50-60% of the 1-RM, which is light enough to allow for proper form and technique while still providing enough resistance to stimulate muscle growth and strength gains.

In the case of a novice exerciser who can perform a 1-RM bench press at 100 pounds, a starting resistance of around 50-60 pounds for the first set of 12 repetitions would be appropriate. As the individual progresses and becomes stronger, the training load can be gradually increased over time to continue to challenge the muscles and stimulate further gains in strength and muscle size.

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Sam is maintaining a camp fire. He has kept the fire steadily burning for 12 hours with 18 logs. How many hours he could have kept the fire going with 36 logs assuming that all logs are the same

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Sam could have kept the fire going for 24 hours with 36 logs, assuming that all the logs are the same.

How to determine how long the fire could be maintained with a different number of logs?

We can assume that each log provides the same amount of heat to the fire, and therefore, the total amount of heat generated by 18 logs in 12 hours is the same as the total amount of heat generated by 36 logs in a certain number of hours.

Let's call the number of hours Sam could have kept the fire going with 36 logs "x".

So, we can set up a proportion:

18 logs / 12 hours = 36 logs / x hours

To solve for x, we can cross-multiply:

[tex]18 logs * x hours = 12 hours * 36 logs[/tex]

18x = 432

x = 24

Therefore, Sam could have kept the fire going for 24 hours with 36 logs, assuming that all the logs are the same.

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what is the period of the function

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Answer:

The period of function.........

Step-by-step explanation:

The distance between the repetition of any function is called the period of the function. For a trigonometric function, the length of one complete cycle is called a period.

List the eigenvalues of A. The transformation x-Ax is the composition of a rotation and a scaling. Give the angle op of the rotation, where -x

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The transformation x-Ax can be decomposed into a rotation and scaling if and only if A is symmetric.

If A is symmetric, then its eigenvalues will be real and its eigenvectors will be orthogonal. The scaling factor is determined by the magnitude of the eigenvalues, and the rotation angle is determined by the angle between the eigenvectors. However, without knowing the matrix A, I cannot determine the values for these.

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give an unambiguous grammar that generates the set of all regular expressions on σ = {a, b}.

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An unambiguous grammar, also called an unambiguous context-free grammar (CFG), is a grammar that generates exactly one syntax tree for each string in the language it defines. The set of all regular expressions on σ = {a, b} can be generated by the following unambiguous grammar:

1. R -> R | RR | RE | R*
2. E -> a | b | ε
3. RR -> R R
4. RE -> R E
5. R* -> R *

Here's an explanation of the grammar:

1. R represents a regular expression. It can be a concatenation of regular expressions (RR), an elementary regular expression (E), or a regular expression followed by a kleene star (R*).
2. E represents an elementary regular expression, which can be either "a", "b", or the empty string "ε".
3. RR is a production rule that defines the concatenation of two regular expressions.
4. RE is a production rule that defines the concatenation of a regular expression with an elementary regular expression.
5. R* is a production rule that defines a regular expression followed by a kleene star.

This unambiguous grammar generates the set of all regular expressions on σ = {a, b} by allowing combinations of these production rules to form valid regular expressions. As the grammar is unambiguous, each string generated has a unique parse tree, ensuring clarity and correctness in the language defined by the grammar.

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The National Fire Incident Reporting Service stated that, among residential fires, 73% are in family homes, 20% are in apartments, and 7% are in other types of dwellings. If four residential fires are independently reported on a single day, what is the probability that two are in family homes, one is in an apartment, and one is in another type of dwelling

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Okay, here are the step-by-step workings to solve this probability problem:

* According to the NFIS statistics:
- 73% of residential fires are in family homes
- 20% are in apartments
- 7% are in other dwellings

* So the probabilities of a residential fire being in each type of dwelling are:
P(family home) = 0.73
P(apartment) = 0.20
P(other) = 0.07

* 4 residential fires will be reported on a single day.
* We want to determine the probability that:
2 are in family homes
1 is in an apartment
1 is in another type of dwelling

* To calculate this probability, we use the binomial probability formula:
P(X) = n! / (k!(n-k)!) * p^k * (1-p)^(n-k)

Where:
n = 4 (total fires)
k = 2 (number of family home fires)

p = 0.73 (probability of family home fire)
q = 1-p = 0.27 (probability of not family home fire)

So the probability of 2 family home fires is:
P(2) = 4! / (2!(4-2)!) * 0.73^2 * 0.27^2
= 6 * 0.54 * 0.07
= 0.1764

* Similarly, the probability of 1 apartment fire is:
P(1) = 4! / (1!(4-1)!) * 0.2 * 0.8
= 4 * 0.2 * 0.8
= 0.64

And the probability of 1 other dwelling fire is:
P(1) = 4! / (1!(4-1)!) * 0.07 * 0.93
= 4 * 0.07 * 0.93
= 0.28

* To get the total probability, we multiply the probabilities of each event:
P(2 family home fires, 1 apartment fire, 1 other dwelling fire)
= 0.1764 * 0.64 * 0.28
= 0.04608

* Therefore, the probability that 2 out of 4 residential fires are in family homes, 1 is in an apartment, and 1 is in another type of dwelling is 0.04608.

Let me know if you have any questions or need more details on the workings. I can also re-explain any part of the solution in another way.

Probabilities can be tricky, so feel free to ask for clarification or additional examples!
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