pls help.....

.....20 points​

The equation of the line that fits these points is: y = 3 + 2x for being collinear.

To determine if the points (0, 3), (1, 5), and (2, 7) are collinear, we can use the slope formula:
slope = (y2 - y1) / (x2 - x1)

Let's calculate the slope between the first two points (0, 3) and (1, 5):
slope1 = (5 - 3) / (1 - 0) = 2

Now let's calculate the slope between the second and third points (1, 5) and (2, 7):
slope2 = (7 - 5) / (2 - 1) = 2

Since the slopes are equal (slope1 = slope2), the points are collinear.

Now let's find the equation of the line that fits these points in the form y = c0 + c1x. We already know the slope (c1) is 2. To find the y-intercept (c0), we can use one of the points (e.g., (0, 3)):
3 = c0 + 2 * 0

This gives us c0 = 3. Therefore, the equation of the line that fits these points is:
y = 3 + 2x

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A basis for the eigenspace corresponding to lambda = 5 is {}.

To find the basis for the eigenspace corresponding to the eigenvalue lambda = 5, we need to solve the equation (A - 5I)x = 0, where A is the given matrix and I is the identity matrix.

In this case, A = [6 1 2 4; 0 1 -3 -1; -1 -9 -3 -6; 0 0 0 5]. Subtracting 5 times the identity matrix from A gives us [1 1 2 4; 0 -4 -3 -1; -1 -9 -8 -6; 0 0 0 0].

To find the basis, we solve the system of homogeneous linear equations represented by the augmented matrix [1 1 2 4; 0 -4 -3 -1; -1 -9 -8 -6; 0 0 0 0].

Row-reducing this matrix leads to the row-echelon form [1 1 2 4; 0 -4 -3 -1; 0 0 0 0; 0 0 0 0].

The variables corresponding to the columns with leading 1's (in this case, the first three columns) are the basis vectors for the eigenspace. Since the last column is a dependent variable column, we can choose any three linearly independent vectors from the first three columns as the basis.

Therefore, a basis for the eigenspace corresponding to lambda = 5 is {}. This indicates that the eigenspace is the zero vector space, meaning there are no linearly independent vectors corresponding to the eigenvalue lambda = 5.

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a. if the curve is increasing or remains constant between the two maxima, there will not be a relative minimum point. b. A curve to have an inflection point without having any relative extreme points.

(a) If a smooth curve has two relative maximum points, it may or may not have a relative minimum point. This is because the presence of a relative minimum point depends on the behavior of the curve between the two relative maxima. If the curve is decreasing between the two maxima, it will have a relative minimum point. However, if the curve is increasing or remains constant between the two maxima, there will not be a relative minimum point. (b) If a smooth curve has two relative extreme points, it may or may not have an inflection point. The presence of an inflection point depends on the behavior of the curve between the two relative extreme points. If the curve changes concavity between the two extremes, it will have an inflection point. However, if the curve maintains the same concavity or does not change direction, it will not have an inflection point. It is also possible for a curve to have an inflection point without having any relative extreme points.

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The equilibrium quantity of the function is when x = 250

Given data ,

To find the equilibrium quantity, we need to find the quantity at which the demand and supply are equal

Let the functions be represented as d ( x  ) and s ( x )

Now , on simplifying the demand and supply ,

200 - 0.5x = 0.3x

Adding 0.5x on both sides , we get

200 = 0.8x

Divide by 0.8x , we get

x = 250

So , the equilibrium quantity is 250

And , To find the producer's surplus at the equilibrium quantity, we need to calculate the area between the supply curve and the equilibrium price line.

The producer's surplus represents the difference between the price at which producers are willing to supply goods and the actual market price

when x = 250

s ( x ) = 0.3 ( 250 )

s ( x ) = 75

So the equilibrium price is 75.

On simplifying the function ,

To calculate the producer's surplus, we need to find the area between the supply curve and the price line (which is the equilibrium price of 75) up to the quantity of 250. Since the supply function is a straight line, the area of the triangle can be calculated as:

Producer's Surplus = 0.5 * (Equilibrium Quantity) * (Equilibrium Price)

Producer's Surplus = 0.5 * 250 * 75

Producer's Surplus = 9375

Hence , the producer's surplus at the equilibrium quantity is 9375

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The surface area of the composite figure is 120 cm²

A composite figure is a figure that comprises of two or more simpler figures.

The composite figure consists of a cube on which is a square pyramid.

The surface area of the exposed part of the cube = 5 × 4 cm × 4 cm = 80 cm²

The slant height of the square pyramid from the diagram = 5 cm

Surface area of the four triangular faces = 4 × (1/2) × 4 × 5 = 8 × 5 = 40

The surface area of the figure = 40 cm² + 80 cm² = 120 cm²

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Step-by-step explanation:

I'm not sure if you are missing a / in your question.

if the question is supposed to read p(e) = 11/17, then the probability of the event not happening is 1 - (11/17) = 6/17.

Christine owe money or get a refund $694.89. To determine whether Christine owes money or gets a refund, we need to subtract the amount she had withheld from her tax liability.

Given information:

When she filed her taxes, Christine determined that her tax liability for 2021 was $4,982.53.

Over the course of the year, she had $4,287.64 withheld from her paychecks.

To determine whether Christine owes money or gets a refund, we need to subtract the amount she had withheld from her tax liability.

$4,982.53 - $4,287.64 = $694.89

Since the amount that was withheld is less than her tax liability, Christine owes $694.89 in taxes.

Therefore, Christine owes money ($694.89).

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To determine the equation that represents the time in minutes, t, that Rachael takes for each water break, we can analyze the information given in the problem.

Rachael plans to run a 5-kilometer race and wants to complete it in 38.75 minutes. She wants to give herself some extra time to take a water break at the halfway point between each kilometer marker. Since she runs each kilometer in 7.5 minutes, she needs to account for the time spent on water breaks.

Let's analyze the options provided:

A. 0.25t + 7.5 = 38.75

B. 5(7.5 + t) = 38.75

C. 7.5t + 0.25 = 38.75

D. 7.5(t + 0.25) = 38.75

We can eliminate option B because it multiplies the time for one water break by 5, which would result in a total time greater than 38.75 minutes.

Next, let's consider option A:

0.25t + 7.5 = 38.75

By subtracting 7.5 from both sides, we get:

0.25t = 31.25

And by dividing both sides by 0.25, we obtain:

t = 125

However, a water break time of 125 minutes doesn't make sense in the context of the problem.

Now, let's consider option C:

7.5t + 0.25 = 38.75

By subtracting 0.25 from both sides, we have:

7.5t = 38.5

Finally, by dividing both sides by 7.5, we find:

t = 5

Therefore, the correct equation representing the time in minutes, t, that Rachael takes for each water break is:

C. 7.5t + 0.25 = 38.75

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The arrow's motion can be described by parametric equations: x = V₀cosθt and y = -4.9t² + V₀sinθt + h, where V₀ is the initial velocity, θ is the launch angle, t is the time, and h is the initial height. To determine the time the arrow is in the air before touching the ground and the maximum height reached, we need to solve for the corresponding values in the equations.

(a) To find the time the arrow is in the air before touching the ground for the final time, we need to determine the value of t when y equals zero (the ground level). We can set the equation -4.9t² + V₀sinθt + h = 0 and solve for t. This equation represents the vertical motion of the arrow. Once we find the value of t, we can round it to the nearest tenth.

(b) To determine the maximum height reached by the arrow, we need to find the vertex of the parabolic equation -4.9t² + V₀sinθt + h. The maximum height occurs at the vertex of the parabola, which corresponds to the highest point of the arrow's trajectory. We can use the formula t = -b/2a, where a = -4.9 and b = V₀sinθ, to find the time at which the maximum height is reached. Once we find the value of t, we can substitute it into the equation y = -4.9t² + V₀sinθt + h to calculate the maximum height, rounding it to the nearest whole number.

By solving for the time when the arrow touches the ground and finding the maximum height, we can better understand the arrow's motion and trajectory.

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The point estimate of the population mean purchase price for iPhone owners is 630.

The point estimate of the population mean can be calculated using the sample mean formula:

Point estimate of population mean = Sample mean = [tex]\bar X[/tex]= Σx / n

Where:

[tex]\bar X[/tex] = Sample mean

Σx = Sum of all values in the sample

n = Sample size

Substituting the given values, we get:

[tex]\bar X[/tex] = Σx / n = 630

Therefore, the point estimate of the population mean purchase price for iPhone owners is 630.

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The point estimate for the population mean is given as follows:

$630.

When we have a sample in the context of this problem, which is a group from the entire population, the point estimate for the population mean is given as the sample mean.

A survey of 44 randomly selected iphone owners showed that the purchase price has a mean of $630 with a sample standard deviation of $31, hence the point estimate for the population mean is given as follows:

$630.

(as the point estimate of the population mean is the same as the sample mean, which is given in the problem).

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The type of circuit that is represented above is a closed circuit that allows electrons to flow. That is option B

A circuit is defined as the electrical or electronic pathway that allows the flow of an electrical current.

There are two types of circuit that include the following;

The closed circuit is defined as the type of circuit that is complete and allow the flow of current

The open circuit is the type of circuit that is incomplete and that cannot allow complete flow of electrons.

The circuit shown above is a complete circuit that allows the build to turn on.

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The estimated population of Georgia at the end of 2023 is 11,003,674.

To calculate Georgia's population at the end of 2023, we use the given information that Georgia has averaged approximately 1% growth per year for the last decade. This growth rate is applied to the population at the end of 2013, which was 9,975,592.

We calculate the number of years from 2013 to 2023, which is 10 years. Using the formula for compound interest with a growth rate of 1% (or 0.01), we can find the population after 10 years:

Population = Initial Population * (1 + Growth Rate)^Number of Years

Plugging in the values, we get:

Population = 9,975,592 * (1 + 0.01)^10

Simplifying the equation, we find:

Population ≈ 9,975,592 * (1.01)^10

Population ≈ 9,975,592 * 1.1046

Population ≈ 11,003,674

Therefore, based on the given growth rate, Georgia's population is estimated to be approximately 11,003,674 at the end of 2023. This estimation assumes that the 1% growth rate per year continues to hold true in the future.

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We have shown that the equation x³ + 6x - 5 = 0 has a solution between x = 0 and x = 1 based on the change in sign of the function values at these Endpoints.

The equation x³ + 6x - 5 = 0 has a solution between x = 0 and x = 1, we can utilize the Intermediate Value Theorem.

First, let's evaluate the function at both endpoints:

For x = 0:

Substituting x = 0 into the equation, we get 0³ + 6(0) - 5 = -5.

For x = 1:

Substituting x = 1 into the equation, we get 1³ + 6(1) - 5 = 2.

Notice that the function value changes sign between these two points. The function evaluates to a negative value at x = 0 and a positive value at x = 1. This indicates that the function crosses the x-axis between these two points.

Since the function is continuous (a polynomial function), and it changes sign, the Intermediate Value Theorem guarantees the existence of at least one solution between x = 0 and x = 1.

Hence, we have shown that the equation x³ + 6x - 5 = 0 has a solution between x = 0 and x = 1 based on the change in sign of the function values at these endpoints.

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A 50 percent increase in Earth's albedo, which refers to the reflectivity of its surface, would lead to a decrease in average surface temperatures.

Albedo plays a crucial role in determining how much of the sun's energy is absorbed or reflected by the Earth. The given information states that approximately 30 percent of the sun's energy is currently reflected back into space. If Earth's albedo increases by 50 percent, meaning more energy is reflected, it would result in less energy being absorbed by the Earth's surface and atmosphere.

The increased albedo would cause a higher percentage of the incoming solar radiation to be reflected and scattered back into space. With less energy being absorbed, the average surface temperatures would decrease. This is because less solar energy would be available to warm the Earth's surface and drive atmospheric processes that contribute to temperature regulation. Therefore, a 50 percent increase in Earth's albedo would likely lead to a cooling effect and lower average surface temperatures on our planet.

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No, it is not one-to-one.

The function f(t) is the height of a football t seconds after kickoff, and you would like to determine if it is a one-to-one function using a verbal description. A function is one-to-one if each element in the domain corresponds to a unique element in the range, meaning that no two different inputs give the same output.
In this case, the function f(t) represents the height of the football at any given time t after kickoff. During the football's trajectory, it reaches its maximum height and then descends back towards the ground. Therefore, at different times during its flight, the football may have the same height, indicating that there are two different inputs (t values) that can give the same output (height).
So, No, it is not one-to-one.

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Based on the data given, the histogram is attached

A histogram is a graphical representation of data points organized into user-specified ranges.

Similar in appearance to a bar graph, the histogram condenses a data series into an easily interpreted visual by taking many data points and grouping them into logical ranges or bins.

From the information, the range of the dataset will be:

= 68 - 32

= 36

The number of classes will be:

= 36 / 10

= 3.6

= 4 approximately.

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a) Convergent.

To test the series for convergence or divergence, consider the given series: [tex]∑(n=1 to infinity) (−1)^(n-1) * (7/8^n).[/tex]We can apply the Alternating Series Test, which has two conditions:

1) The terms of the sequence (ignoring the (-1)^(n-1) part) must be non-increasing, i.e., [tex]7/8^n[/tex] must decrease as n increases.
2) The limit of the sequence (ignoring the (-1)^(n-1) part) as n approaches infinity must be 0.

For condition 1, as n increases[tex], 8^n[/tex]will grow larger, causing the fraction [tex]7/8^n[/tex] to decrease. Therefore, the sequence is non-increasing.

For condition 2, take the limit as n approaches infinity:
[tex]lim (n->∞) (7/8^n) = 7 * lim (n->∞) (1/8^n) = 7 * 0 = 0.[/tex]
Both conditions are satisfied, so the series is convergent. The answer is a) Convergent.

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Answer:

standard or standards

Step-by-step explanation:

The solution to the model shown is 1.5

From the question, we have the following parameters that can be used in our computation:

The equation of the model is

2x - 1 = 2

Add 1 to both sides of the equation

So, we have

2x = 3

Divide both sides by 2

x = 3/2

Evaluate

x = 1.5

Hence, the solution to the model shown is 1.5

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The length of the other diagonal BD is approximately 94.34 cm.

Let ABCD be a parallelogram with AB = 50 cm, BC = 80 cm, and diagonal AC = 90 cm. We want to find the length of the other diagonal BD. Since ABCD is a parallelogram, we know that opposite sides are equal in length. Therefore, CD = AB = 50 cm and AD = BC = 80 cm.

We can use the Pythagorean theorem to find the length of the diagonal BD. Let x be the length of BD. Then, in right triangle ABD, we have:

[tex]BD^2 = AB^2 + AD^2[/tex]

Substituting the given values, we get:

[tex]x^2 = 50^2 + 80^2[/tex]

[tex]x^2 = 2500 + 6400[/tex]

[tex]x^2 = 8900[/tex]

[tex]x = \sqrt{8900}[/tex]

x = 94.34 cm

Therefore, the length of the other diagonal BD is approximately 94.34 cm.

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Answer: true

Step-by-step explanation:

To determine if the given ordered pair (5, -9) is a solution to the equation y = -2x + 1, we substitute the values of x and y into the equation and check if it holds true.

For x = 5 and y = -9, let's substitute these values into the equation:

-9 = -2(5) + 1

Simplifying the equation:

-9 = -10 + 1

-9 = -9

The equation holds true since both sides of the equation are equal. Therefore, the statement "The given ordered pair (5, -9) is a solution to the equation y = -2x + 1" is True.

The equation of a circle that is centered at (-2, 3) with a radius of 5 is: B. (x + 2)² + (y - 3)² = 25.

The equation should be rewritten in standard form with the center and radius as: D. (x + 4)² + (y - 2)² = 4, center is (-4, 2) and radius is 2.

In Geometry, the general form of the equation of a circle is modeled by this mathematical equation;

(x - h)² + (y - k)² = r²

Where:

By substituting the given radius and center into the equation of a circle, we have;

(x - h)² + (y - k)² = r²

(x - (-2))² + (y - 3)² = (5)²

(x + 2)² + (y - 3)² = 25

Question 2.

From the information provided above, we have the following equation of a circle:

x² + y² + 8x - 4y + 16 = 0      

x² + y² + 8x - 4y = -16

x² + 8x + (8/2)² + y² - 4y + (-4/2)² = -16 + (8/2)² + (-4/2)²

x² + 8x + 16 + y² - 4y + 4² = -16 + 16 + 4

(x + 4)² + (y - 2)² = 4

(x + 4)² + (y - 2)² = 2²

Therefore, the center (h, k) is (-4, 2) and the radius is equal to 2 units.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

(a) The probability that a randomly selected package weighs between 48 and 50 grams is 0.5596.

(b) The probability that a randomly selected package weighs more than 51 grams is 0.1587.

(c) we can solve for k using the formula z = (k - μ) / σ: 1.645 = (k - 49.8) / 1.2

What is probability?

Probability is a measure of the likelihood of an event occurring.

a. To find the probability that a randomly selected package weighs between 48 and 50 grams, we need to calculate the area under the normal curve between these two values.

We can standardize the values using the formula z = (x - μ) / σ, where x is the value we are interested in, μ is the mean, and σ is the standard deviation.

For x = 48, z = (48 - 49.8) / 1.2 = -1.5

For x = 50, z = (50 - 49.8) / 1.2 = 0.1667

Using a standard normal distribution table or a calculator, we can find the area under the curve between z = -1.5 and z = 0.1667 to be approximately 0.5596.

Therefore, the probability that a randomly selected package weighs between 48 and 50 grams is 0.5596.

b. To find the probability that a randomly selected package weighs more than 51 grams, we need to calculate the area under the normal curve to the right of 51.

Again, we can standardize using z = (x - μ) / σ, where x = 51, μ = 49.8, and σ = 1.2.

z = (51 - 49.8) / 1.2 = 1

Using a standard normal distribution table or a calculator, we can find the area under the curve to the right of z = 1 to be approximately 0.1587.

Therefore, the probability that a randomly selected package weighs more than 51 grams is 0.1587.

c. To find the value of k for which the probability that a randomly selected package weighs more than k grams is 0.05, we need to find the z-score that corresponds to the area to the right of k being 0.05.

Using a standard normal distribution table or a calculator, we can find that the z-score for an area of 0.05 to the right of it is approximately 1.645.

Therefore, we can solve for k using the formula z = (k - μ) / σ:

1.645 = (k - 49.8) / 1.2

Solving for k, we get:

k = 1.645(1.2) + 49.8 ≈ 51.02

So the value of k for which the probability that a randomly selected package weighs more than k grams is 0.05 is approximately 51.02 grams.

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X-bar is an unbiased estimator of A. The expected number of weekly minutes is E(M) = 8nλ / 3.

a. The unbiased estimator of A is the sample mean of the X's, that is, X-bar = (X1 + X2 + ... + Xn) / n. To prove this estimator is unbiased, we need to show that E(X-bar) = A.

By linearity of expectation, E(X-bar) = (E(X1) + E(X2) + ... + E(Xn)) / n = (A + A + ... + A) / n = A. Therefore, X-bar is an unbiased estimator of A.

b. Using the given model M = 2X + 3X^2, we can write M as M = 2(X1 + X2 + ... + Xn) + 3(X1^2 + X2^2 + ... + Xn^2).

Taking the expected value of both sides and using the fact that E(X) = λ for a Poisson RV, we get E(M) = 2nλ + 3n(λ + λ^2) = 2nλ + 3nλ + 3nλ^2 = (2n + 3n + 3nλ)λ = 8nλ / 3.

Therefore, the expected number of weekly minutes is E(M) = 8nλ / 3.

c. To find an unbiased estimator of E(M), we can use the formula for M from part b and substitute X-bar for λ, giving M = 8nX-bar / 3.

Since X-bar is an unbiased estimator of A, and A = λ for a Poisson RV, M is an unbiased estimator of E(M), which we found to be 8nλ / 3 in part b.

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Braxton has enough information to conduct a test of the null hypothesis against the alternative.

Given Information: We have been given the mean family income for a random sample of 550 suburban households in Nettlesville which shows that a 92 percent confidence interval is ($45,700, $59,150).

We are also given that Braxton is conducting a test of the null hypothesis H0: µ = 44,000 against the alternative hypothesis Ha: µ ≠ 44,000 at the α = 0.08 level of significance.

To check whether Braxton has enough information to conduct a test of the null hypothesis against the alternative, we need to check whether the given confidence interval includes the value of the null hypothesis.

If it does not include the value of the null hypothesis, Braxton can conduct the test, otherwise, he can't.

Here, the given confidence interval is ($45,700, $59,150).

The null hypothesis is H0: µ = 44,000.

Since 44,000 does not lie in the given confidence interval, we can say that Braxton has enough information to conduct the test of the null hypothesis against the alternative.

So, Braxton has enough information to conduct a test of the null hypothesis against the alternative. Hence, the correct option is (C).

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Equilibrium is the term interchangeable with the term steady-state(d).

The term "steady-state" refers to a situation where a system remains constant over time, with inputs and outputs balanced.

The term "steady-state" is interchangeable with the term "equilibrium." Both terms refer to a condition where a system remains unchanged over time.

Similarly, "equilibrium" refers to a state where opposing forces or processes are balanced, resulting in a stable condition. Both terms describe a state of balance or stability in a system. Therefore, they can be used interchangeably. So D option is correct.

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The expression 1 ÷ (4 × -4 × 4 × -4 × 4) is not equivalent to (14 × -14 × 14 × -14 × 14). The simplified value of the given expression is 1/1024, whereas the value of the second expression is 537,824.

To evaluate the given expression, we can simplify the factors in the denominator first:

4 × -4 = -16

-16 × 4 = -64

-64 × -4 = 256

256 × 4 = 1024

Now we can substitute these values into the original expression:

1 ÷ (1024) = 1/1024

We can simplify the expression on the right-hand side by factoring out 14 and -14:

14 × -14 × 14 × -14 × 14 = (14 × -14) × (14 × -14) × 14

= (-196) × (-196) × 14

= 38416 × 14

= 537,824

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The radian measure of Angle E should be labeled π/3 or 60 degrees, and F should be labeled 2(π/3) or 120 degrees.

A full circle in radian measures is 2π and half π

If we divide π into 3 equal parts it should be π/3 radian.

Angle EAP would be π/3 radians because E is one-third of the way from A to P.

In degrees, π/3 radians is equal to (180/π) × π/3 = 60°

Angle FAP would be 2×(π/3) radians givn that F is 2/3 of the way from A to P.

In degrees, 2×(π/3) radians is equal to (180/π) × 2(π/3) = 120°.

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The product of an irreducible and a unit is always irreducible.

To prove that the product of an irreducible and a unit is irreducible in an integral domain, we must show that it cannot be factored into non-unit factors.
Let's start by defining what we mean by "irreducible" and "unit" in an integral domain.
- An element a in an integral domain is said to be irreducible if it cannot be factored into non-unit factors, i.e., if a = bc for some non-units b and c, then either b or c must be a unit.

- A unit in an integral domain is an element that has a multiplicative inverse, i.e., an element u such that uu^-1 = 1, where 1 is the multiplicative identity of the domain.

Now, let's suppose that we have an irreducible element a and a unit u in an integral domain. We want to show that the product au is also irreducible.

Suppose that au = bc for some non-units b and c. We need to show that either b or c is a unit.

Since u is a unit, we can multiply both sides of the equation by u^-1 to obtain a = (bu^-1)c. Now, since a is irreducible, we know that either bu^-1 or c must be a unit.

If bu^-1 is a unit, then we can multiply both sides by u to obtain b = au^-1. But this means that b is a unit, since a and u are both units and units are closed under multiplication.

On the other hand, if c is a unit, then we can multiply both sides by c^-1 to obtain a(c^-1u) = b. But this means that b is a multiple of a, which contradicts the assumption that b is a non-unit.

Therefore, we have shown that in an integral domain, the product of an irreducible and a unit is always irreducible.

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The data set, any value greater than 92.5 a potential outlier according to the "IQR + 1.5" rule.

To calculate the interquartile range (IQR) and apply the "IQR + 1.5" rule to the given data set, follow these steps:

Arrange the data in ascending order:

60, 72, 73, 75, 78, 78, 79, 80, 80, 81, 82, 82, 83, 83

Find the first quartile (Q1) and the third quartile (Q3):

Q1: The median of the lower half of the data set.

Q3: The median of the upper half of the data set.

The data set has an odd number of elements, so the medians can be found directly:

Q1 = 75

Q3 = 82

Calculate the IQR (interquartile range):

IQR = Q3 - Q1

= 82 - 75

= 7

"IQR + 1.5" rule:

Upper Limit = Q3 + (1.5 × IQR)

= 82 + (1.5 × 7)

= 82 + 10.5

= 92.5

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Complete question:

82, 72, 83, 75, 80, 78, 82, 73, 60, 79, 80, 78, 83, 81 What Is The Q1, Median, Q3 And The IQR With Any Outliers

82, 72, 83, 75, 80, 78, 82, 73, 60, 79, 80, 78, 83, 81

what is the Q1, median, Q3 and the IQR with any outliers