Pls help me over here

Pls Help Me Over Here

Answers

Answer 1

Answer:

1 and the element is hydrogen (there is an exception for the octet rule for the element hydrogen) hope this helps

Explanation:


Related Questions

Given the balanced equation representing a
reaction:
02 → 0 + 0
What occurs during this reaction?

Answers

Answer:

A molecule of oxygen breaks into two atoms of oxygen showing that the bond is being broken. When bonds break, energy is absorbed and when bonds are formed energy is released. Hence, the answer to this question is (A).

Explanation:

help someone i need this

Answers

A is the longest wavelength because of how separated each each wave length is

What rock forms from magma oozing onto the surface?
a. Igneous rock
b. Metamorphic rock
C. Sedimentary rock
d. Lava rock

Answers

Answer: A. Igneous rock
Igneous Rock is formed when magma, has a high temperature. Cooling off makes the lava harden. Creating igneous rock

mathdrrggeszdrsz seer r-

Answers

Answer:

130!!

Explanation:

Help me please tell me and I try to make u brainliest!

Answers

The best option would be A I think. I’m sorry if it’s wrong

What causes a ionic bond to occur

Answers

Answer:

when the valence (outermost) electrons of one atom are transferred permanently to another atom

Rocks are classified as sedimentary, metamorphic, or igneous on the basis of
the
a. age of the rocks.
b. way the rocks were formed.
c. types of fossils the rocks contain.
d. number of minerals found in the rocks.

Answers

The answer is the way the rocks were formed.

A cell biologist measures the volume of a bacteria cell. The volume is 6.027x10-10 L. What is the volume in picoliters? Write your answer as a decimal.
pL

Answers

Answer:

Volume of bacteria cell into Pico liters = 60.27 Pico liters

Explanation:

Given:

Volume of bacteria cell = 6.027 x 10⁻¹⁰ L

Find:

Volume of bacteria cell into Pico liters

Computation:

1 L = 10¹² Pico liters

So,

Volume of bacteria cell = 6.027 x 10⁻¹⁰ L

Volume of bacteria cell = 6.027 x 10⁻¹⁰ x 10¹² Pico liters

Volume of bacteria cell into Pico liters = 60.27 Pico liters

Which body system provides protection of the brain and the spinal cord?

Answers

Answer:

The bones of the skull and spinal column

Explanation:

The central nervous system is better protected than any other system or organ in the body. Its main line of defense is the bones of the skull and spinal column, which create a hard physical barrier to injury.

Answer:

The Central Nervous System (CNS)

Respiration occurs at the cellular level
truebor false?​

Answers

the answer is : False

just did it

Which statement best describes how matter and energy is cycled through the ecosystem?
A. Energy is recycled in an ecosystem, but matter is not recycled.
B. Matter and energy are both cycled throughout an ecosystem, and much of the energy at each level is changed to heat energy.
C. Energy is gained in each level on the energy pyramid, and matter is lost in an ecosystem.
D. Matter and energy are the same.

Answers

D. Matter and energy are the same.

Please need this ASAP. Calculate the mass of lime, CaO, that would be produced from 250 tonnes of limestone,
CaCO3.
Relative atomic masses: C 12; O 16; Ca 40.

Answers

Answer:

1.4×10⁸ g of CaO

Explanation:

We'll begin by converting 250 tonnes to grams (g). This can be obtained as follow:

1 tonne = 1×10⁶ g

Therefore,

250 tonne = 250 × 1×10⁶

250 tonne = 2.5×10⁸ g

Next, the balanced equation for the reaction.

CaCO₃ —> CaO + CO₂

Next, we shall determine the mass of CaCO₃ that decomposed and the mass CaO produced from the balanced equation. This can be obtained as follow:

Molar mass of CaCO₃ = 40 + 12 + (16×3)

= 40 + 12 + 48

= 100 g/mol

Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g

Molar mass of CaO = 40 + 16

= 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

SUMMARY:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Finally, we shall determine the mass of CaO produced by the decomposition of 250 tonnes (i.e 2.5×10⁸ g) of CaCO₃. This can be obtained as follow:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Therefore, 2.5×10⁸ g of CaCO₃ will decompose to produce =

(2.5×10⁸ × 56)/100 = 1.4×10⁸ g of CaO.

Thus, 1.4×10⁸ g of CaO will be obtained from 250 tonnes (i.e 2.5×10⁸ g) of CaCO₃.

Scientists have been classifying living organisms for centuries. In the 1970s, organisms were classified in a five-kingdom
classification scheme. However, two decades later, organisms called Archaebacteria were discovered. This led to a three-domain
system of classification that combined some of the previous five-kingdom schemes.
What does this change in classification methods demonstrate?

Answers

Answer:

Classification is important because it allows scientists to identify, group, and properly name organisms via a standardized system (Linnaeus Taxonomy); based on similarities found in the organisms DNA/RNA (genetics), Adaptations (Evolution), and Embryonic development (Embryology) to other known organisms to better.

Hope I helped!!

The five kingdoms of classifications were animalia, plant, fungi, protista and monera. Later Archaebacteria was discovered and this led to the 3 kingdom classification animalia, plantae and protista.

What is biological classification?

There are different classifications for living things based on their nature, body and origin. The kingdom animalia includes  all the animals including human beings.

Kingdom plante includes all the plants and kingdom fungi, protista and monera are of microbes. Later the discovery and study of Archaebacteria proved that they exhibit similar body type and functions as bacterias.

After that, scientists turned into 3 kingdom classification, where all the prokaryotic organisms including protists, monera and fungi classified as one. The evolutional changes originated in them made this classification.

To find more on biological classification, refer here:

https://brainly.com/question/2994982

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3. Explain what would happen to the digestion process if enzymes were not present. SC.6.L.14.5​

Answers

Without enzymes the nutrients in your food would go to waste which leads to a poor digestion and malnutrition. It’s because enzymes break down the nutrients which use it for energy

1) How many molecules are in 0.02 moles of beryllium iodide?

Answers

Answer:

3 grams??

Explanation:

I think this would be the answer you are looking for.

Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming natural gas. In the first step, nitrogen and hydrogen react to form ammonia: (g) (g) (g) In the second step, ammonia and oxygen react to form nitric acid and water: (g) (g) (g) (g) Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these reactions.

Answers

Answer:

Overall enthalpy change for the formation of one mole nitric acid from nitrogen, hydrogen and oxygen, ΔH = -376 KJ

Note: the question is incomplete. The complete question is given below:

Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming natural gas. In the first step, nitrogen and hydrogen react to form ammonia: N₂(g) + 3H₂(g)  → 2NH₃(g) ΔH = -92. kJ In the second step, ammonia and oxygen react to form nitric acid and water: NH3(g) + 2O2(g) → HNO3(g) + H2O(g) ΔH = -330. kJ Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these reactions. Round your answer to the nearest kJ.

Explanation:

From Hess's law of constant heat summation, the total enthalpy change for a reaction is the sum of all changes without regard to the number of multiple stages or steps involved in a reaction.

Enthalpy is a state function as it does not depend on the path taken to attain its value. Therefore, the summation of the enthalpy changes involved in the individual steps in the reaction of the formation of nitric acid will be equal to the enthalpy change of the overall reaction step.

For the first reaction step:

N₂(g) + 3H₂(g)  →  2NH₃(g) ΔH = -92. kJ

For the second reaction step:

NH₃(g) + 2O₂(g) → HNO3(g) + H2O(g) ΔH = -330. kJ

Overall reaction step:

[tex]\frac{1}{2}[/tex]N₂(g) + [tex]\frac{3}{2}[/tex]H₂(g) + 2O₂(g)  →  HNO₃ + H₂O  ΔH = ?

The overall reaction for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen shows that the first reaction step should be divided by 2

[tex]\frac{1}{2}[/tex]N₂(g) + [tex]\frac{3}{2}[/tex]3H₂(g)  →  NH₃(g) ΔH = -46. kJ

Overall enthalpy change, ΔH = ΔH₁ + ΔH₂

Overall enthalpy change,ΔH = (-46 KJ) + (-330 KJ)

Overall enthalpy change,ΔH = -376 KJ

Whay happens regularly in fission reaction

Answers

Answer:

In nuclear fission, an unstable atom splits into two or more smaller pieces that are more stable, and releases energy in the process. The fission process also releases extra neutrons, which can then split additional atoms, resulting in a chain reaction that releases a lot of energy.

Explanation:

PLZ HELP URGENT!!!!!

Answers

Answer:

A fluke because it is an vertebrae

Explanation:

Oxidation-reduction (redox) reactions are reactions:______
a) in which oxidation numbers change.
b) Oxidation numbers are either real charges or formal charges which help chemists keep track of electron transfer.
c) In practice, oxidation numbers are best viewed as a bookkeeping device.
d) Oxidation cannot occur without reduction.
e) In a redox reaction the substance which is oxidized contains atoms which increase in oxidation number.
f) Oxidation is associated with electron loss (helpful mnemonic: LEO

Answers

Answer:

A. in which oxidation numbers change

Explanation:

This is because in oxidation reduction reactions or redox reactions, involves the sharing or transfer of electrons between species and the oxidation numbers changes. There is change in electrons, ions or oxidation number by gaining or lossing electrons. Increase in oxidation number is an indication of oxidation while decrease in oxidation indicate reduction.

The irreversible elementary gas-phase reaction is carried out isothermally at 305 K in a packed-bed reactor with 100 kg of catalyst. The entering pressure was 20 atm and the exit pressure is 2 atm. The feed is equal molar in A and B and the flow is in the turbulent flow regime, with F A0 10 mol/min and C A0 0.4 mol/dm 3 . Currently 80% conversion is achieved. What would be the conversion if the catalyst particle size were doubled and everything else remained the same

Answers

Answer:

0.856

Explanation:

Given data:

Feed molar rate ( Fao ) = 10 mol/min

Feed concentration ( Cao ) = 0.4 mol/dm^3

current conversion rate = 80%  

Temperature = 305 K

catalyst = 100 kg

entering pressure = 20 atm

exit pressure = 2 atm

Determine the conversion if the catalyst particle size were doubled and everything else remained the same

The conversion if the catalyst particle size were doubled and other factors remains the same = 0.856

attached below is a detailed solution

When developing a question for a scientific inquiry, the question will ideally
A.
not just simply ask why.
B.
identify variables.
C.
be measurable.
D.
all of these

Answers

Answer: https://brainly.com/question/2426371

Explanation: Someone already answered this, click the link. YW! :))

This would be ANSWER C

Go to the Phase Changes tab. Select the particular molecule, and set the temperature to the given values by using the stove to increase or decrease the temperature. Increase the pressure of the cylinder by moving the lid of the cylinder down with the help of the finger. The pressure of the cylinder is indicated by the pressure gauge on the top left corner of the simulation. On the right-hand side of the simulation is the phase diagram for the molecule.
As the molecules collide on the walls of the cylinder, the pressure of the cylinder does not remain constant; it fluctuates slightly as indicated by the gauge.
In the phase diagram, observe the red point. When a particular molecule is selected, set the temperature and pressure condition to the required value. Observe the position of the red point on the phase diagram when the pressure reaches approximately near the required value.
Which of the following conditions will result in the formation of a supercritical fluid?
Check all that apply.
1. Oxygen at 100 K and no pressure
2. Argon at 160 K and approximately 6 atm pressure
3. Water at 294 K and approximately 1 atm pressure
4. Neon at 32 K and approximately 1 atm pressure
5. Neon at 50 K and approximately 10 atm pressure
6. Water at 894 K and approximately 20 atm pressure
7. Argon at 100 K and no pressure
8. Oxygen at 194 K and approximately 2 atm pressure

Answers

Answer:

2. Argon at 160K and approximately 6 atm pressure

5. Neon at 50K and approximately 10 atm pressure

6. Water at 894 K and approximately 20 atm pressure

8. Oxygen at 194K and approximately 2 atm pressure

Explanation:

Super critical fluid is formed when temperature rises beyond critical point. The state of molecules can be liquid or gas. The pressure should be above the certain level with an introduction of different gases at minimum of 2 atm pressure.

Mg(NO3)2 soluble or insoluble?

Answers

Answer:

The chemical compound Mg(NO3)2, also known as magnesium nitrate, is very soluble, especially in water.

2Fe + 6HCl -> 2FeCl3 + 3H2 If 7.0 moles of HCl is added to enough iron that the HCl is completely used up, how many
moles of hydrogen gas will be produced?

Answers

Answer: 3.5 moles of hydrogen gas will be produced.

Explanation:

The balanced chemical equation is:

[tex]2Fe+6HCl\rightarrow 2FeCl_3+3H_2[/tex]

As HCl gets completely used up, [tex]HCl[/tex] is the limiting reagent.

According to stoichiometry :

6 moles of [tex]HCl[/tex] produces =  3 moles of [tex]H_2[/tex]

Thus 7.0 moles of  [tex]HCl[/tex] produces=[tex]\frac{3}{6}\times 7.0=3.5moles[/tex]  of [tex]H_2[/tex]

 Thus 3.5 moles of hydrogen gas will be produced.

How many particles are in 9.58 x 1023 of potassium sulfate (K2SO4)? (5.77 x 1047 particles)

Answers

Answer:

[tex]5.77x10^{47}particles.[/tex]

Explanation:

Hello!

In this case, since we are given 9.58x10²³ moles of potassium sulfate, it is possible to compute the particles according to the Avogadro's number:

6.022x10²³

As shown below:

[tex]9.58x10^{23}mol*\frac{6.022x10^{23}}{1mol}\\\\5.77x10^{47}particles.[/tex]

Best regards!

number of molecules in lithium sulfate Li2So4​

Answers

What the question there is nun

What is chemistry
What is the bond type in CaO

Answers

Answer:

Ionic bond

CaO is an ionic bond. Two-element compounds are usually ionic when one element is a metal and the other is a non-metal. It is made up of one metal ion/cation(Ca^2+) and an non-metal ion/anion(O^2-).

Using Graham's Law of Effusion, calculate
the approximate time it would take for
1.0 L of argon gas to effuse, if 1.0 L of
oxygen gas took 12.7 minutes to effuse
through the same opening.

0.070 minutes

0.89 minutes

None of the other answers

14 minutes

12 minutes

Answers

The rate of effusion of Argon here is 8.03 min

Data;

Molar mass of Oxygen = 16g/molTime for effusion of oxygen = 12.7 minMolar mass of Argon = 40g/molTime for effusion of Argon = ?

Graham's Law of Effusion

This law states that the rate of effusion of a gas is inversely proportional to the square root of it's molar mass.

[tex]R \alpha \frac{1}{\sqrt{M} }[/tex]

From this,

[tex]\frac{r_1}{r_2} = \frac{\sqrt{M_2} }{M_1}[/tex]

substituting the values and solving,

[tex]\frac{R_A_r}{12.7}= \frac{\sqrt{16} }{\sqrt{40} } \\ R_A_r = \frac{12.7*\sqrt{16} }{\sqrt{40} } \\R_A_r = 8.032min[/tex]

The rate of effusion of Argon here is 8.03 min

Learn more on Graham's law of effusion here;

https://brainly.com/question/12211278

(22 points) please please help me thanks so much

Answers

Answer:

d

Explanation:

Answer:

hopen it helps soo much thanks for the points

whose model was discarded as a result of Rutherford's model?
A Dalton's model
B Thomson's model
C Bohr's model
D Quantum's model​

Answers

Answer:

A. Dalton's model

Explanation:

Dalton's model was discarded as a result of Rutherford's model.

[tex]\small\sf{Whose\: model \:was \:discarded \:as \:a \:result\:of}[/tex][tex]\small\sf{ Rutherford's \:model\:?}[/tex]

[tex]{ }[/tex]

[tex]\small\sf\:\:\:\:\:\:\:\:{:}\:\Longrightarrow{\bold{\pink{\sf{Thomson's \:model}}}}[/tex]

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