please hurry and help me on this!!!

The lower bound of the 90% confidence interval for the gift basket's average shipping weight is 55.605.

Given mean weight of 57 ounces ,sample size 70 ,confidence level 90% and standard deviation of 7.1 ounces.

We have to find the lower bound of the confidence interval for the gift's basket's avrage shipping weight.

We can easily find the confidence interval and its lower bound through theformula of margin of error.

Margin of error is the difference between real values and calculated values.

Margin of error=z*σ/[tex]\sqrt{n}[/tex]

where z is the critical value of confidence level

σ is standard deviation,

n is the sample size

We have to first find the z value for 90% confidence level which is 1.645.

Margin of error=1.645*7.1/[tex]\sqrt{70}[/tex]

=11.6795/8.3666

=1.395

Lower bound of the confidence interval = Mean - margin of error

=57-1.395

=55.605.

Hence the lower bound of the confidence interval for the gift basket's average shipping weight is 55.605.

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Step-by-step explanation:

1. Not neccesarily true

2. Not necessarily true

3. True because angles in a triangle add to 180°

4. Not necessarily true

5. True because the medians are being constructed, and the three medians of a triangle are always concurrent.

6. Not necessarily true

The statements that are true about the triangle are:

Option C: m∠P + m∠Q + m∠R = 180°

Option E: PT, QU, and RS intersect at the same point.

1. m∠Q = m∠R: This is not true because there is no indication that the angles are equal.

2.The length of QU is half the length of RP: This is not true because there is no length given to show that measurement.

3. m∠P + m∠Q + m∠R = 180°:

This is true because the sum of angles in a triangle add to 180°

4. QU ≅ RS:

This is not true because we are not told that they are congruent

5. PT, QU, and RS intersect at the same point:

This is true because the medians are being constructed, and the three medians of a triangle are always concurrent.

6. The sum of the lengths of QU and RS is equal to the length of PT: This is not true because we are not told that.

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Answer:

I may have misubderstood the question, so review carefully.

width = 380 m

length is 420 m

Step-by-step explanation:

Let w and l stand for the width and length of the stadium.

We are told that w = l - 40 m

We also learn that l = 420 m

w = l - 40 m

w = (420 m) - 40 m

width = 380 m

length is 420 m

The mean of the data set is 81.6.

The median of the data set is 80.

The mean is the average of a data set. Therefore,

Mean = (70 x 2 + 75 x 8 + 80 x 6 + 85 x 3 + 90 x 9) / 28 = 81.6.

Hence,

mean = 81.6

Median is a statistical measure that determines the middle value of a dataset listed in ascending order .

Therefore,

28 / 2 = 14

median = 80 + 80 / 2 = 160 / 2 = 80

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Answer:

AP = 12, and FQ = 8

Step-by-step explanation:

The proportion between AB:FG and AP:FQ is the same.

--> 9:6 = AP:FQ

I'll say that FQ is x and AP is x+4 (since AP is 4 longer than FQ)

--> 9:6 = x+4:x

--> 6(x+4) = 9x

--> 6x + 24 = 9x

--> 24 = 3x

--> x = 8

Since AP= x+4 and FQ= x. AP becomes 12 and FQ becomes 8.

Simplifying the expression gives 36x^2 - 82x - 10 = 0

Given the expression;

4x-5/3+2x=7+2/9x+2

[tex]\frac{4x - 5}{3 + 2x} = \frac{9}{9x + 2}[/tex]

Cross multiply

[tex]4x - 5( 9x + 2) = 9 (3 + 2x)[/tex]

Expand the bracket

[tex]36x^2 + 8x - 45x - 10 = 27x + 18x[/tex]

Collect like terms

36x^2 + 8x - 45x - 27x - 18x = 0

Add the like terms

36x^2- 82x - 10 = 0

Thus, simplifying the expression gives 36x^2- 82x - 10 = 0

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Answer:

A) y = 16/(x^2), B) 4/5

Step-by-step explanation:

For A, we can plug in some of the table values to check it. I will try 2 and 3

2. 4 = 16 / (2^2)

    16/4 = 4

3. 16/9 = 16 / (3^2)

   16/9 = 16/9

B) We can just input y into the formula 25 = 16 / (x^2)

This leaves us with +-4/5

Answer:

see explanation

Step-by-step explanation:

(a)

given y varies inversely as x² then the equation relating them is

y = [tex]\frac{k}{x^2}[/tex] ← k is the constant of variation

to find k substitute any ordered pair from the table into the equation

using (2, 4 ) , then

4 = [tex]\frac{k}{2^2}[/tex] = [tex]\frac{k}{4}[/tex] ( multiply both sides by 4 )

16 = k

y = [tex]\frac{16}{x^2}[/tex] ← equation of variation

(b)

when y = 25 , then

25 = [tex]\frac{16}{x^2}[/tex] ( multiply both sides by x² )

25x² = 16 ( divide both sides by 25 )

x² = [tex]\frac{16}{25}[/tex] ( take the square root of both sides )

x = ± [tex]\sqrt{\frac{16}{25} }[/tex] = ± [tex]\frac{4}{5}[/tex]

the positive value of x is x = [tex]\frac{4}{5}[/tex]

he has 231 pennies..............

The value of 'x' from the expression is 1/3

Given the expression;

[tex]x + \frac{x}{3} = \frac{4}{9}[/tex]

Find the LCM of the left side, we have

[tex]\frac{3x + x}{3} = \frac{4}{9}[/tex]

Cross multiply

[tex]9(4x) = 4 *3[/tex]

[tex]36x = 12[/tex]

Make 'x' the subject

[tex]x = \frac{12}{36}[/tex]

x = [tex]\frac{1}{3}[/tex]

Thus, the value of 'x' from the expression is 1/3

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Hello !

Answer:

[tex]\boxed{\sf x=\dfrac{1}{3} }[/tex]

Step-by-step explanation:

Our aim is to find the value of x that verifies the following equation :

[tex]\sf x+\frac{x}{3} =\frac{4}{9}[/tex]

Let's isolate x :

Multiply both sides by 3 :

[tex]\sf 3(x+\frac{x}{3} )=\frac{4}{9}\times 3\\ \sf 3x+x=\frac{4}{3}[/tex]

Now we can combine like terms :

[tex]\sf 4x=\frac{4}{3}[/tex]

Finally, let's divide both sides by 4 :

[tex]\sf \frac{4x}{4} =\frac{4}{3} \times \frac{1}{4} \\\boxed{\sf x=\dfrac{1}{3} }[/tex]

Have a nice day ;)

Answer:

-31, /~26, -5, 6

Step-by-step explanation:

Let [tex]C[/tex] be the set of all students in the classroom.

Let [tex]P[/tex] and [tex]M[/tex] be the sets of students that pass physics and math, respectively.

We're given

[tex]n(C) = 60[/tex]

[tex]n(P \cap M') = 17[/tex]

[tex]n(P \cap M) = 25[/tex]

[tex]n((P \cup M)') = n(P' \cap M') = 9[/tex]

i. We can split up [tex]P[/tex] into subsets of students that pass both physics and math [tex](P\cap M)[/tex] and those that pass only physics [tex](P\cap M')[/tex]. These sets are disjoint, so

[tex]n(P) = n(P\cap M) + n(P\cap M') = 25 + 17 = \boxed{42}[/tex]

ii. 9 students fails both subjects, so we find

[tex]n(C) = n(P\cup M) + n(P\cup M)' \implies n(P\cup M) = 60 - 9 = 51[/tex]

By the inclusion/exclusion principle,

[tex]n(P\cup M) = n(P) + n(M) - n(P\cap M)[/tex]

Using the result from part (i), we have

[tex]n(M) = 51 - 42 + 25 = 34[/tex]

and so the probability of selecting a student from this set is

[tex]\mathrm{Pr}(M) = \dfrac{34}{60} = \boxed{\dfrac{17}{30}}[/tex]

Answer:

B,C and E

Step-by-step explanation:

The period can be calculated by dividing 2pi by the coefficfient of the x, so in this case 1. And we'll get 2pi/1 = 2pi.

The function clearly has a minimum of -2, you can see that from the table.

Same thing for the maximum = 4.

Answer:

See Photo

Step-by-step explanation:

Plato/Edmentum

The measure of angle G in terms of x is x+x degrees

The measure of angle F and angle D is 90 degrees so that;

<GFD = <GDF = 90 - x

Since the sum of angle in a triangle is 180 degrees, hence;

<G + 90 - x + 90 - x = 180

<G + 180 - 2x = 180

<G = 2x

<G = x + x

Hence the measure of angle G in terms of x is x+x degrees

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Answer:A

Step-by-step explanation: math and me go together like mustard and pees

Answer:

range of the given set is { 7,2,4,2,1}

Step-by-step explanation:

. Hello !

When the above kind of set is given the second values of each elements belongs to the range or the y whereas, the first values of the elements belongs to the domain or x.

The length of string used to decorate the ceiling = 40.5 meters.

According to the statement

we have given that the hotel staff is decorating the lobby by placing one row of string lights along the outer edge of the rectangular ceiling.

And the coordinates of rectangular ceiling is A(5,16), B(17,10), C(14,4), D(2,10).

And we have to find the total length for string is used to decorate the rectangular ceiling.

We know that the Total length of string = Area of the rectangular ceiling.

And area of rectangular ceiling = L*B

So, Length of rectangular ceiling = A+B

Length of rectangular ceiling = (17-5) + (16-10)

Length of rectangular ceiling = (12+6)/2

Length of rectangular ceiling = 9.

So,

Breadth of rectangular ceiling = B+C

Breadth of rectangular ceiling = (17-14)+(10-4)

Breadth of rectangular ceiling = (3+6) /2

Breadth of rectangular ceiling = 4.5

So, the length of string used = 4.5*9

the length of string used = 40.5 meters.

The length of string used to decorate the ceiling = 40.5 meters.

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Disclaimer: This question was incomplete. Please find the full content below.

Question:

The hotel staff is decorating the lobby by placing one row of string lights along the outer edge of the rectangular celling. A member of the s⊥aff maps the celling on a coordinate grid as shown, where each unit represents . What is the approximate length of string lights the staff needs to decorate the ceiling?

A 20.25 meter

B. 35 meter

C. 40.5 meter

D. 14 meter

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Given the average speed and distance covered, the time taken for the driver to complete the road trip is 5.7 hours

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

We substitute into our equation above.

Speed = Distance ÷ time

70 miles per hour = 400 mile ÷ Elapsed time

Elapsed time = 400 miles ÷ 70 miles per hour

Elapsed time = 5.7 hours

Given the average speed and distance covered, the time taken for the driver to complete the road trip is 5.7 hours.

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The total area of the square based prism is 413.7 square units

The given parameters are:

Base length, a = 10

Height, h = 11

The total surface area is calculated as:

[tex]A = a^2 + 2a\sqrt{\frac{a^2}{4} + h^2[/tex]

This gives

[tex]A = 10^2 + 2 *10\sqrt{\frac{10^2}{4}+11^2[/tex]

So, we have:

[tex]A = 100 + 20\sqrt{246[/tex]

Evaluate

A = 413.7

Hence, the total area of the square based prism is 413.7 square units

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Answer:

x - 3 > 15

Step-by-step explanation:

The length of side VW is 7.5 cm

The given parameters are:

DE is 6 cm, EF is 7.5 cm, and DF is 5 cm

Since the two triangles are congruent, then it means that:

So, we have:

VW= EF

The side EF is

EF = 7.5 cm

So, we have:

VW = 7.5 cm

Hence, the length of side VW is 7.5 cm

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The cutoffs from the left and right sides of normal distribution at a 95-percent confidence level are 1.96.

The confidence level, which is used in statistics, describes the likelihood that the estimation of a statistical parameter's location in a sample survey is also true for the population.

Confidence levels must be decided upon in advance when surveying since they affect the survey's essential scope and error margin. Confidence intervals of 90, 95, and 99 percent are widely employed in surveys.

If the confidence level were set at 95%, there is a very good likelihood that the population's arithmetic mean, as a statistical number, will fall within the survey's established margins of error.

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Answer:

12

Step-by-step explanation:

The area of a triangle is calculated with the following formula:

[tex]\frac{1}{2} *b*h[/tex] (b: base, h: height (or legs))

We can use this formula to find the length of the other leg:

30 = [tex]\frac{1}{2} *b*h[/tex] multiply both sides with 2 to get rid of fraction

60 = b*h one of the leg's length is given as 5 so

60 = 5*h divide both sides by 5

12 = h is the length of the missing leg.

Answer:

Step-by-step explanation:

hello:

here an solution

Answer: 1. A

2. A

Step-by-step explanation:

The information to fill one the box regarding the proof include:

It should be noted that when two triangles of each corresponding sides are equal, then it's said that they are similar.

Here AB = CD, and AD = CB as they illustrate the fact that they are parallel.

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When everyone is sitting down, the number of free seats is 26, using arithmetic addition and subtraction.

The two main arithmetic operations that we learn to add and subtract two or more integers or other mathematical values are arithmetic addition and subtraction. The addition symbol is the plus sign (+), and the subtraction symbol is the minus sign (-). (minus sign).

The initial number of passengers on board=29

After 4 people get off at the first stop,

Using arithmetic addition and subtraction, we get,

Number of passengers left=29-4=25

After 11 people get on,

Number of passengers=25+11=36

At the second stop, when 7 people get off,

Number of passengers=36-7=29

When 23 people get on,

Number of passengers=29+23=52

Total number of passenger seats in the bus=78

Number of free seats, when everyone is sitting=78-52

                                                                              =26

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The equations of the corresponding circles can be any equation only have to satisfy the  general equation for circle .

The question seems incomplete and complete question given in the image !!!!

A circle is the set of all points in a plane at a given distance (called the radius) from a given point (called the center.)

We know that the general equation for a circle is

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where ( h, k ) is the center and r is the radius.

According to the question

The equation of circle given is [tex]x^2+y^2=1[/tex]

Center at origin

i.e

(h,k) = (0,0)

and radius = 1 unit

Now ,

By changing changing center (h,k) and radius of equation it will give following equations

h                      k                       r                            equation of circle

0                       1                       3                      [tex](x-0)^2+(y-0)^2=3^2[/tex]  

2                       2                       3                       [tex](x-2)^2+(y-2)^2=3^2[/tex]

1                        1                        1                     [tex](x-1)^2+(y-1)^2=1^2[/tex]  

-2                      -1                       2                      [tex](x+2)^2+(y+1)^2=2^2[/tex]

3                       2                       1                        [tex](x-3)^2+(y-2)^2=1^2[/tex]      

-5                      1                        3                       [tex](x+5)^2+(y-1)^2=3^2[/tex]

Hence, the equations of the corresponding circles can be any equation only have to satisfy the general equation for circle .

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Answer:

A

Step-by-step explanation:

By using greatest common factor you are able to take a 2 out of all the numbers

Prediction of the value of the dependent variable outside the experimental region is called extrapolation.

According to the question,

Prediction of the value of the dependent variable outside the experimental region is called extrapolation.

Extrapolation is the statistical method beamed at understanding the unknown data from the known data.

Hence, prediction of the value of the dependent variable outside the experimental region is called extrapolation.

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Answer:

10^4 =  10 × 10 × 10 × 10
       =  10000

68% of the daily phone calls answered by the company are between 47 and 53.

Empirical rule states that for a normal distribution, 68% of the data are within one standard deviation from the mean, 95% of the data are within two standard deviation from the mean and 99.7% of the data are within three standard deviation from the mean.

Given mean of 50 and a standard deviation of 3

68% are within one standard deviation from mean = mean ± standard deviation = 50 ± 3 = (47, 53)

68% of the daily phone calls answered by the company are between 47 and 53.

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