PLEASE HELP. (Will Mark Brainliest)

Answer:

14cm

Step-by-step explanation:

The shape is a rectangle.

The formula for perimeter of a rectangle= 2(lenght + breadth)

lenght = 4cm

width = 3cm

2(4+3)

2 × 7

= 14cm

Answer

16.25

Step-by-step explanation: To The Nearest Hundredth

(-1, 2), (3, 1)

√17

(3, 1), (7, 2)

√17

(3, 1), (7, 2)

√8

So our answer is =

8 + √17 + √17 = 16.25

hope it works for you!

Answer:

So, the step1 is correct.

Step-by-step explanation:

The expression is

[tex](6 x^3 + 8 x^2 - 7 x)-(2x^2 + 3)(x- 8)\\\\(6 x^3 + 8 x^2 - 7 x) - (2x^3 - 16 x^2 + 3 x - 24)\\\\6 x^3 + 8 x^2 - 7 x - 2 x^3 - 16 x^2 + 3 x - 24\\\\4 x^3 - 8 x^2 - 4 x - 24[/tex]

So, the step 1 is correct.

Answer:

(0,-41)

Step-by-step explanation:

Let see if this table of values are proportional.

This mean that the function is proportional. This also gives us the slope which is 19/9.

This tell us that this function will be a linear function since we are trying to find the y intercept we would use this equation

We know the slope and we know a point so let use point slope form to find the intercept.

[tex]y - y _1= m(x - x _1)[/tex]

Let use points (-18,-79) and let m =19/9.

[tex]y + 79 = \frac{19}{9} (x + 18)[/tex]

[tex]y + 79 = \frac{19}{9} x + 38[/tex]

[tex]y = \frac{19}{9} x - 41[/tex]

This is in slope intercept form so the y intercept is

[tex] - 41[/tex]

The answer is -41.

Answer:

The domain is all real number

Answer:

9

Step-by-step explanation:

a^2 +b

Let a = -2 and b = 5

(-2)^2 +5

Exponents first

4 +5

Then add

9

Answer:

9

Step-by-step explanation:

Here, we have to observe that a^2 = a×a =-2 × -2 = 4

hence, a^2 + b = 4 + 5 = 9.

Answer

supplementary angles sum to 180

1 & 2

1 & 4

1 & 8

1 & 6

2 & 3

2 & 7

2 & 5

3 & 4

3 & 8

3 & 6

4 & 5

4 & 7

5 & 6

5 & 8

6 & 7

8 & 7

Answer:

30 [tex](1 + \frac{.18}{12})^{5*12}[/tex]

Step-by-step explanation:

Answer:

El área del gimnasio sería 2000 metros cuadrados

Step-by-step explanation:

Un lado del gimnasio será igual al lado de la cancha y el otro lado será igual al lado de la piscina.

Dado que tanto la cancha como la piscina tienen forma cuadrada. El lado de la cancha será raíz cuadrada de 2.500 m2 y el de la piscina será raíz cuadrada de 1.600 m2

Por lo tanto, el lado del gimnasio sería 50 y 40.

El área del gimnasio sería 50 * 40 = 2000 metros cuadrados

Answer:

It is not valid since there is more than one variable being changed at one.

Step-by-step explanation:

Jackson changed the brand of soil, but he also changes the amount of water, and the amount of sunlight the plants are receiving, so his conclusion that the soil was more effective is not valid.

Answer:

No, Jackson did not take into account alternate theories.

Jackson's findings could have been influenced by the watering schedule and the amount of sunlight. Without adjusting for these variables, the experiment is inconclusive.

Answer:

$18,720.5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Depreciation Formula: A = P(1 - rt)

Step-by-step explanation:

Step 1: Define

Identify variables

P = 36001

r = 16% = 0.16

t = 3

Step 2: Find Cost

Answer:

I got 45 degrees

Step-by-step explanation:

knowing that where T is is 90 degrees and a triangle always= 180 degrees I just split 90 in half and got 45. I could be wrong but I hope this helps :)

Answer:

x = 15

Step-by-step explanation:

-3x+20+7x=80

Combine like terms

4x+20 = 80

Subtract 20 from each side

4x+20 -20 = 80-20

4x = 60

Divide by 4

4x/4 = 60/4

x = 15

Answer:

A

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

If you just plug in the answers, so lets take (1,6) and plug it into y = 6x

You could just solve it so it'd be like

6 = 6(1) and

12 = 6(2)

Answer:

[tex] \displaystyle - \frac{1}{2} [/tex]

Step-by-step explanation:

we would like to compute the following limit:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{1}{ \ln(x + \sqrt{ {x}^{2} + 1} ) } - \frac{1}{ \ln(x + 1) } \right) [/tex]

if we substitute 0 directly we would end up with:

[tex] \displaystyle\frac{1}{0} - \frac{1}{0} [/tex]

which is an indeterminate form! therefore we need an alternate way to compute the limit to do so simplify the expression and that yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]

now notice that after simplifying we ended up with a rational expression in that case to compute the limit we can consider using L'hopital rule which states that

[tex] \rm \displaystyle \lim _{x \to c} \left( \frac{f(x)}{g(x)} \right) = \lim _{x \to c} \left( \frac{f'(x)}{g'(x)} \right) [/tex]

thus apply L'hopital rule which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \dfrac{d}{dx} \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]

use difference and Product derivation rule to differentiate the numerator and the denominator respectively which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{1}{x + 1} - \frac{1}{ \sqrt{x + 1} } }{ \frac{ \ln(x + 1)}{ \sqrt{ {x}^{2} + 1 } } + \frac{ \ln(x + \sqrt{x ^{2} + 1 } }{x + 1} } \right) [/tex]

simplify which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \sqrt{ {x}^{2} + 1 } - x - 1 }{ (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]

unfortunately! it's still an indeterminate form if we substitute 0 for x therefore apply L'hopital rule once again which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \sqrt{ {x}^{2} + 1 } - x - 1 }{ \dfrac{d}{dx} (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]

use difference and sum derivation rule to differentiate the numerator and the denominator respectively and that is yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{x}{ \sqrt{ {x}^{2} + 1 } } - 1}{ \ln(x + 1) + 2 + \frac{x \ln(x + \sqrt{ {x}^{2} + 1 } ) }{ \sqrt{ {x}^{2} + 1 } } } \right) [/tex]

thank god! now it's not an indeterminate form if we substitute 0 for x thus do so which yields:

[tex] \displaystyle \frac{ \frac{0}{ \sqrt{ {0}^{2} + 1 } } - 1}{ \ln(0 + 1) + 2 + \frac{0 \ln(0 + \sqrt{ {0}^{2} + 1 } ) }{ \sqrt{ {0}^{2} + 1 } } } [/tex]

simplify which yields:

[tex] \displaystyle - \frac{1}{2} [/tex]

finally, we are done!

9514 1404 393

Answer:

  -1/2

Step-by-step explanation:

Evaluating the expression directly at x=0 gives ...

  [tex]\dfrac{1}{\ln(\sqrt{1})}-\dfrac{1}{\ln(1)}=\dfrac{1}{0}-\dfrac{1}{0}\qquad\text{an indeterminate form}[/tex]

Using the linear approximations of the log and root functions, we can put this in a form that can be evaluated at x=0.

The approximations of interest are ...

  [tex]\ln(x+1)\approx x\quad\text{for x near 0}\\\\\sqrt{x+1}\approx \dfrac{x}{2}+1\quad\text{for x near 0}[/tex]

__

Then as x nears zero, the limit we seek is reasonably approximated by the limit ...

  [tex]\displaystyle\lim_{x\to0}\left(\dfrac{1}{x+\dfrac{x^2}{2}}-\dfrac{1}{x}\right)=\lim_{x\to0}\left(\dfrac{x-(x+\dfrac{x^2}{2})}{x(x+\dfrac{x^2}{2})}\right)\\\\=\lim_{x\to0}\dfrac{-\dfrac{x^2}{2}}{x^2(1+\dfrac{x}{2})}=\lim_{x\to0}\dfrac{-1}{2+x}=\boxed{-\dfrac{1}{2}}[/tex]

_____

I find a graphing calculator can often give a good clue as to the limit of a function.

Answer:

The second choice is correct

Step-by-step explanation:

Go to a point like 4,3 and 0,1.   the difference in x is 4 since 4-0 = 4.

4,3 and 0,1 now we find the change in y, 3-1 which is 2. the formula for slope is change in y over change in x so 2/4 is the slope or 1/2.

The y intercept of the line is 1 since the line touches the y-axis at the y, 1.

therefore the equation is y = 1/2x + 1.

Answer:

x= -7

Step-by-step explanation:

the labeled angles are alternate-interior angles which are congruent

we can solve for 'x' by creating this equation:

x+139 = 132

x = -7

Answer:

39,800+x0.18= his total pay

Your Welcome

Biffy Out!!!

Answer:

B

Step-by-step explanation:

The triangles do have equal angles and proportional sides, because they are bot right triangles formed on parallel lines.

:)ur welcome

Answer: Choice B

Yes. Right triangles formed on parallel lines have proportional side lengths and congruent angles.

====================================================

Explanation:

Parallel lines always have equal slopes, but different y intercepts.

Recall that slope = rise/run.

The "rise" is the vertical portion of the triangle, while the "run" is the horizontal portion.

So let's say we had a slope of rise/run = 2/3. This means rise = 2 and run = 3.

If we had something like rise/run = 4/6, then that reduces to 2/3, showing that 4/6 = 2/3. They are the same slope.

We can use the SAS similarity theorem to prove the triangles formed in the diagram are congruent based on what is discussed above.

Because the triangles are similar, this means the corresponding angles are congruent. One such pair is the pair of right angles shown.

Answer:

0.36,0.44,7/10

Step-by-step explanation:

Answer:

0.36, 0.44, 7/10

Step-by-step explanation:

7/10=0.7=0.70

Scale factor from figure a to figure b = DIVIDE BY 3

{Check:- 33/3 = 11 & 15/3 = 5}

hope this helps :)

Answer:

1/3

Step-by-step explanation:

These two quadrilaterals are similar because figure A's sides are 3 times figure B's sides. Figure A's bottom is 15, while figure B's bottom is 5. To get from 15 to 5, we multiply by 1/3. This is the scale factor. All the other sides of figure A are also 3 times bigger than figure B's.

Answer:

volumn= l*b*h

4x*2x*1x= 8000 cm3

8x= 8000 cm3

x= 1000cm3

length = 4000

breadth= 2000

height = 1000

Answer:

8a³b

Step-by-step explanation:

Answer:18

Step-by-step explanation:

Answer:

The chances of her pulling the candy out in that exact order for all of them is extremley low

Step-by-step explanation:

I cannot figure out D though sorry

Answer:

Your welcome

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Replace R1 with 1 and R3 with 0 you have -2(1)+0 which equals 0 and that matches matrix II. Repeat the process with the other numbers in R1 and R3 and they all come out equal therefor the answer is D.