please help helppppppp

Answer:

2.28% of players are under 86kg

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The weights of the players were distributed normally with a mean of 98kg and a standard deviation of 6kg.

This means that [tex]\mu = 98, \sigma = 6[/tex]

What percentage of players are under 86kg?

The proportion is the pvalue of Z when X = 86. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{86 - 98}{6}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a pvalue of 0.0228

0.0228*100% = 2.28%

2.28% of players are under 86kg

☁️ Answer ☁️

Inequality Form:

b < −2

❤️

Interval Notation:

(− ∞, −2)

Hope it helps.

Explanation: Have a nice day!~ ￣▽￣

Answer:

b < -2

Step-by-step explanation:

-3 (4b + 7) > 3

-12b -21 > 3

-12b > 3 + 21

-12b > 24

b < 24/-12

b < -2

9514 1404 393

Answer:

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

  cos = 1/sec

  csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

Answer:

[tex]1-8x-2x^2[/tex]

Step-by-step explanation:

(-4x^3-14x^2+10x-1)÷(2x-1)

Factor the expressions that are not already factored.

[tex]\frac{(2x-1)(2x^2-8x+1)}{2x-1}[/tex]

Cancel out 2x−1 in both numerator and denominator.

[tex]2x^2-8x+1[/tex]

Swap terms to the left side.

[tex]1-8x-2x^2[/tex]

Graph if needed:

Answer:

A two-sided alternative hypothesis would be more appropriate in this case

Step-by-step explanation:

A one-sided hypothesis is one that asserts that a given parameter is either smaller than the null hypothesis value or larger than the value presented by the null hypothesis.

However in a two sided hypothesis, the claim is made that a given parameter is not equal to the parameter given in the null hypothesis, such that the parameter can be either larger than than or lesser than the value of the null hypothesis and still satisfy the condition of the hypothesis

Therefore, given for that for there to be a conclusion, the test should be weather the number of people that think of an odd number are equal to the number of people that think of an even number, or weather the number of people that think of an odd number are not equal to the number of people that think of an even number

Therefore, a two-sided hypothesis should be used since the claim (that the numbers are not equal) is not equal to the value of the parameter in the null hypothesis (that the numbers are equal)

Answer:

7881.75

Step-by-step explanation:

10,170x0.775

Answer:

7881.75

Step-by-step explanation:

Answer:

It's 15.

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

Plug in m = 3 & n = 2 into the equation.

7(3) - 3(2)

21 - 6

15

Hope this helps & have a great rest of your day!

Answer: 256

Step-by-step explanation:

Answer:

256cm² is the correct answer

Answer:

D

D. license, permits, and stamp requirements

The type of information that determine the hunting regulations publication is option D.

The following information should be considered:

Learn more: brainly.com/question/16911495

Answer:

a) 10

b) 3

c) 16

Step-by-step explanation:

Count the squares and the half ones match them with each other to get a full square... so so sorry if im wrong i did this a while ago! Currently Yr 9 x

Answer:

Step-by-step explanation:

Midpoint formula:

(x1 + x2)/2, (y1 + y2)/2

Substitute needed values.

4 + -8 = -4

-4/2 = -2

Now for the y's

-1 + 3 = 2

2/2 = 1

MIDPOINT: (-2,1)

Answer:

y=-16

Step-by-step explanation:

Answer:

y = -16

Step-by-step explanation:

−10y+4(3y−8)=−64

Step 1: Simplify both sides of the equation.

−10y+4(3y−8)=−64

−10y+(4)(3y)+(4)(−8)=−64(Distribute)

−10y+12y+−32=−64

(−10y+12y)+(−32)=−64(Combine Like Terms)

2y+−32=−64

2y−32=−64

Step 2: Add 32 to both sides.

2y−32+32=−64+32

2y=−32

Step 3: Divide both sides by 2.

2y

2

=

−32

2

y=−16

Answer:

y=−16

Answer:25

Step-by-step explanation:

Answer:

0.5

Step-by-step explanation:

Answer:

comparing both equations

-2x-1=3x+4

or, -1-4 =3x+2x

or, -5=5x

or, X= -1

Y= -2x-1

or, Y= -2(-1)-1

or, Y=1

hence, ( -1,1)

Answer:

hey there

The answer is 7/10

this is true because we have two green marbles and five blue

2+5=7

Step-by-step explanation:

Answer:

20% or 2/10

Step-by-step explanation:

10 marbles in total. We want to find the probability of not picking a green marble. 10marbles-3red-5blue=2marbles left.

So the probability of picking a green marble is 2/10 or 20%

Answer:

Step-by-step explanation:

∠1 = 180° - ∠2 - ∠3 = 38°

∠5 = ∠1 = 38°

Answer:

h = -25

Step-by-step explanation:

h - 5 = - 30

   +5     +5

h = -25

2+7x=747 X83                 83(2)=83             83(7)= 581

Step-by-step explanation:

Answer:

C.

Step-by-step explanation:

Given

[tex]A =(x_1,y_1)[/tex]

[tex]B =(x_2,y_2)[/tex]

[tex]C =(x_3,y_3)[/tex]

[tex]D =(x_4,y_4)[/tex]

Required:

Which condition proves that AB is perpendicular to CD

First, calculate the slopes of both.

For AB

[tex]m_1 = \frac{y_2 -y_1}{x_2 - x_1}[/tex]

For CD

[tex]m_2 = \frac{y_4 -y_3}{x_4 - x_2}[/tex]

The condition of perpendicularity is:

[tex]m_1 * m_2 = -1[/tex]

Substitute values for m1 and m2

[tex]\frac{y_2 -y_1}{x_2 - x_1} * \frac{y_4 -y_3}{x_4 - x_2} = -1[/tex]

Option (c) is correct

Answer:

You are correct

Step-by-step explanation:

Answer: yes, you are correct :)

Step-by-step explanation:

Answer:

Option A, Left by 4 units

Step-by-step explanation:

Step 1:  Convert g(x) to a function square

We currently have g(x) in this order:  [tex]ax^2 + bx + c[/tex]

However, we want g(x) to be in this order:  [tex](ax + c)^{2}[/tex]

The first thing we have to do is to factor it out:

[tex]g(x)=x^{2}+8x+16[/tex]

[tex]g(x) = (x + 4)(x + 4)[/tex]

[tex]g(x) = (x+4)^{2}[/tex]

Step 2:  Now we can see which way we need to move it

The original form is:  [tex]f(x) = (ax - b)^{2}[/tex]

Since the - has changed to a +, that means that we moved -4 spaces down the x-axis.  This means that we move left by 4 units.

Answer:  Option A, Left by 4 units

Look at the graphs below to make sure:

Answer:

A.) Left By 4 Units

Step-by-step explanation:

Functions f(x) and g(x) are shown below: f(x) = x2 g(x) = x2 + 8x + 16

The direction in which and by how many units the f(x) should be shifted to obtain the g(x) is given by as follows.

Given,

f(x) = x²

g(x) = x² + 8x + 16

we have to consider, the dependent term while selecting the direction.

Therefore, except x², only x term is dependent term.

In g(x), the x term is given by 8.

Therefore, we need to shift the f(x) left by 4 units.

Therefore, option A is correct.

Answer:

The minimum velocity of the particle  = [tex]-e^{-2 }[/tex] units

Step-by-step explanation:

Given - A particle moves along a horizontal line so that its position at time t,

t ≥ 0, is given by  s(t) = 40 + te^−t/20.

To find - Find the minimum velocity of the particle for 0 ≤ t ≤ 100.

Proof -

Velocity, v(t)  = [tex]\frac{d}{dt}(40 + te^{-\frac{t}{20} } )[/tex]

Now,

[tex]\frac{d}{dt}(40 + te^{-\frac{t}{20} } )[/tex] =  [tex]\frac{d}{dt}(40 ) + \frac{d}{dt}(te^{-\frac{t}{20} } )[/tex]

                       = 0 + [tex]t\frac{d}{dt}(e^{-\frac{t}{20} } ) + e^{-\frac{t}{20} }\frac{d}{dt}(t )[/tex]

                       = [tex]t(-\frac{1}{20} )e^{-\frac{t}{20} } + e^{-\frac{t}{20} }[/tex]

⇒v(t) = [tex]-\frac{t}{20}e^{-\frac{t}{20} } + e^{-\frac{t}{20} }[/tex]

Now,

For minimum velocity, Put [tex]\frac{d}{dt}(v(t)) = 0[/tex]

Now,

[tex]\frac{d}{dt}[v(t)] = \frac{d}{dt} [ -\frac{t}{20}e^{-\frac{t}{20} } + e^{-\frac{t}{20} } ][/tex]

           = [tex]-\frac{2}{20} e^{-\frac{t}{20} } + \frac{t}{400} e^{-\frac{t}{20} }[/tex]

Now,

Put [tex]\frac{d}{dt}(v(t)) = 0[/tex], we get

[tex]-\frac{2}{20} = - \frac{t}{400}[/tex]

⇒t = 40

Now,

Check that the point is minimum or maximum

Calculate  [tex]\frac{d^{2} }{dt^{2} } [v(t)][/tex]

Now,

[tex]\frac{d^{2} }{dt^{2} } [v(t)][/tex] = [tex]\frac{d}{dt} [ -\frac{2}{20} e^{-\frac{t}{20} } + \frac{t}{400} e^{-\frac{t}{20} }][/tex]

            = [tex]\frac{1}{400}e^{- \frac{t}{20} } [ 3 - \frac{t}{20}][/tex]

⇒[tex]\frac{d^{2} }{dt^{2} } [v(t)][/tex]  = [tex]\frac{1}{400}e^{- \frac{t}{20} } [ 3 - \frac{t}{20}][/tex]  > 0

∴ we get

t = 40 is point of minimum

So,

The minimum velocity be

v(40) = [tex]-\frac{40}{20}e^{-\frac{40}{20} } + e^{-\frac{40}{20} }[/tex]

      = [tex]-2e^{-2 } + e^{-2 }[/tex]

      = [tex]-e^{-2 }[/tex]

⇒v(40) = [tex]-e^{-2 }[/tex] units

∴ we get

The minimum velocity of the particle  = [tex]-e^{-2 }[/tex] units