PLEASE ANSWER ASAP FOR BRANLIEST!!!!!!!!!!!!

Answer:

575 miles

Step-by-step explanation:

Create a proportion where x is the distance traveled on 11.5 gallons of gas:

[tex]\frac{300}{6}[/tex] = [tex]\frac{x}{11.5}[/tex]

Cross multiply and solve for x:

6x = 11.5(300)

6x = 3450

x = 575

So, the car would travel 575 miles

Answer:

575 mi

Step-by-step explanation:

First we are going to find out how much gasoline the hybrid car uses per mile.

to do this we are going to divide 300 by 6.

[tex]\frac{300}{6}[/tex] = 50 mi

∴ For every 50 miles 1 gallon of gas is used. This can be represented as 1:50 or [tex]\frac{1}{50}[/tex].

To find the distance that 11.5 gallon of gas would be used we are going to multiply 50 by 11.5.

50 × 11.5 = 575 mi

Answer:

14.50 cm

Step-by-step explanation:

Based on the midsegment theorem:

The midsegment connecting two sides of triangle is parallel to the third side of the triangle and the length of the midsegment line is half the length of the third side parallel to the midsegment.

From the diagram ;

QR // ZY

XY = 2 * 2.93 = 5.86

RS // XZ

XZ = 2 * 2.04 = 4.08

QS // XY

XY = 2 * 2.28 = 4.56

The perimeter :

(XY + XZ + XY)

5.86 + 4.08 + 4.56

= 14.50 m

Answer:

d

Step-by-step explanation:

Answer:

5.

Step-by-step explanation:

If you were to rotate the triangle, you can apply Pythagoras Theorem.

Therefore,

a^2 = 12^2 - 13^2 (Note: a^2 = a squared)

a^2 = 144 - 169

a^2 = -25.

a     = 5.

Not sure why its negative though im pretty sure its the right answer.

in BCD triangle :

DC^2 = BC^2 + BD^2

13^2 = 12^2 + BD^2

169 = 144 + BD^2

BD^2 = 169 - 144

BD^2 = 25

BD = 5

_______________________

In the other hand we have :

BD^2 = AB × BC

5^2 = AB × 12

AB = 25/12

________________________

Also we have :

AD^2 = AB × AC

AD^2 = 25/12 × ( 25/12 + 12 )

AD^2 = 25/12 × ( 25/12 + 144/12 )

AD^2 = 25/12 × 169/12

AD^2 = 25 × 169 / 12 × 12

AD^2 = 5 × 5 × 13 × 13 / 12 × 12

AD = 5 × 13 / 12

AD = 65 / 12

AD = 5.42

Thus the correct answer is option C

Answer: The graph of g is the graph of f translated 5 units right, and g(x) = f(x - 5).

Step-by-step explanation:

The graph f(x) = 2x = 6 translated (1,4,5 or 6) units (left, right, up, or down) are g(x) = 2(x + 1) + 6, g(x) = 2(x - 4),  2x + 11, g(x) = 2x.

Suppose we have a function f(x).

f(x) ± d = Vertical upshift/downshift by d units (x, y ±d).

f(x ± c) = Horizontal left/right shift by c units (x - + c, y).

(a)f(x) = Vertical stretch for a > 0, vertical shrink a < 0. (x, ay).

f(bx) = Horizonatal compression b > 0, horizontal stretch for b < 0. (bx , y).

f(-x) = Reflection over y axis, (-x, y).

-f(x) = Reflection over x-axis, (x, -y).

Given, a function f(x) = 2x + 6.

g(x) is translated 1 units left.

g(x) = 2(x + 1) + 6.

g(x) is translated 4 units right.

g(x) = 2(x - 4).

g(x) is translated 5 units up.

g(x) = 2x + 6 + 5 = 2x + 11.

g(x) is translated 6 units down.

g(x) = 2x.

learn more about graphs here :

https://brainly.com/question/2288321

#SPJ2

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: 8 \frac{1}{3}\:(or) \:8.333}}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {Step-by-step\:explanation:}}}[/tex]

[tex]3 \frac{3}{4} \times 2 \frac{2}{9} [/tex]

➺[tex] \: \frac{15}{4} \times \frac{20}{9} [/tex]

➺[tex] \: \frac{300}{36} [/tex]

➺[tex] \: \frac{25}{3} [/tex]

➺[tex] \: 8 \frac{1}{3} [/tex]

➺[tex] \: 8.333[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\pink{Mystique35 }}{\orange{❦}}}}}[/tex]

Answer:

1) 8 + 2i

2) -13

3) 15 + 3i

4) 1

5) 24 - 10i

Step-by-step explanation:

Working with imaginary numbers is similar to working with a variable when it comes to addition and subtraction, so for problems 1 and 3, it is a matter of combining like terms.

1) The like terms are 7i and -5i; 5 and 3. We can combine them.

8 + 2i

2) We can start to compute the problem by noticing it is a special product of difference of squares. The expression can also be written as:

(3i)^2 - (2)^2

9i^2 - 4

i is defined as the square root of negative 1, so i^2 is -1. We can substitute that in:

9(-1) - 4

-9 - 4

-13

3) We can combine the like terms, 12i and -9i; 5 and 10:

15 + 3i

4)The powers of i repeat every four numbers. For example:

i^1 = i

i^2 = -1

i^3 = -i

i^4 = 1

i raised to a power divisible by four is always 1, so i^24 is 1.

5) We can start by normally distributing in this problem:

12 - 18i + 8i - 12i^2

As said before, i^2 is -1:

12 - 10i + 12

24 - 10i

Answer:

What do you need help with?

Step-by-step explanation:

You didn't put a question

Answer:

10.20

the answer is in none of the options just choose

10.12

OPTION D is the correct answer

Answer:

1.tenisha

2.1\5+1\3=1\×

3.n-12=1\3(n+2)

4.500×=120

Answer:

I thinks they take 5 hours to meet each other

Answer:

Step-by-step explanation:

foctorized 990 = 9×10×11

so, (X+2)(X+3)(X+4)=9×10×11

we can choose one of the factors, and get the answer with the same x values

x+2 = 9 , => x =7

x+3 = 10, => x = 7

x+4 = 11, => x = 7

Step-by-step explanation:

-3,4 Is the answer Is it right or wrong if it is true plz mark me as brainliest

Answer:

Ano is correct

Step-by-step explanation:

-3,4is theoretically correct answer

Step-by-step explanation:

he made a mistake in step 3 because you not supposed to add that value behind that division

and you divide first

Answer:

mistake is in step 4. he shouldn't have added first

Answer:

30.00×.06=1.8+30.00=31.8

Answer:

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Answer:

iii) a=3b/2

Step-by-step explanation:

7a-2b= 5a+b

7a-5a=2b+b

2a=3b

a=3b/2

I hope this helps!

Answer:

True

Step-by-step explanation:

When conducting Analysis of Variance test (ANOVA) ; our hypothesis are stated as follows ;

The null hypothesis; H0 ; stats that there is no difference in means between any of the population ;

H0 : μ1 = μ2

While the alternative hypothesis which is the opposite of the null hypothesis will be of the claim that ; atleast one of the population means is different from another.

Hence, once there is sufficient evidence to indicate that atleast one of the population means is different from another, then we reject the Null.

Answer:

a. There are 1365 choices of eleven questions.

b. 1764 groups of eleven questions contain five that require proof and six that do not.

Step-by-step explanation:

The order in which the questions are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

a. How many different choices of eleven questions are there?

Eleven questions from a set of 15. So

[tex]C_{15,11} = \frac{15!}{11!4!} = 1365[/tex]

There are 1365 choices of eleven questions.

b. Suppose seven questions require proof and nine do not. How many groups of eleven questions contain five that require proof and six that do not?

5 from a set of 7 and 6 from a set of 9. So

[tex]C_{7,5}C_{9,6} = \frac{7!}{5!2!} \times \frac{9!}{6!3!} = 1764[/tex]

1764 groups of eleven questions contain five that require proof and six that do not.

Answer:

A. 25

Step-by-step explanation:

From the diagram given, we can deduce that <D EG = <F EG

Therefore:

3y + 4 = 5y - 10

Collect like terms and solve for y

3y - 5y = -4 - 10

-2y = -14

Divide both sides by -2

y = -14/-2

y = 7

✔️m<D EG = 3y + 4

Plug in the value of y

m<D EG = 3(7) + 4

m<D EG = 25°

Answer:

[tex](a)\ \bar x_1 - \bar x_2 = 2.0[/tex]

[tex](b)\ CI =(1.0542,2.9458)[/tex]

[tex](c)\ CI = (0.8730,2.1270)[/tex]

Step-by-step explanation:

Given

[tex]n_1 = 60[/tex]     [tex]n_2 = 35[/tex]      

[tex]\bar x_1 = 13.6[/tex]    [tex]\bar x_2 = 11.6[/tex]    

[tex]\sigma_1 = 2.1[/tex]     [tex]\sigma_2 = 3[/tex]

Solving (a): Point estimate of difference of mean

This is calculated as: [tex]\bar x_1 - \bar x_2[/tex]

[tex]\bar x_1 - \bar x_2 = 13.6 - 11.6[/tex]

[tex]\bar x_1 - \bar x_2 = 2.0[/tex]

Solving (b): 90% confidence interval

We have:

[tex]c = 90\%[/tex]

[tex]c = 0.90[/tex]

Confidence level is: [tex]1 - \alpha[/tex]

[tex]1 - \alpha = c[/tex]

[tex]1 - \alpha = 0.90[/tex]

[tex]\alpha = 0.10[/tex]

Calculate [tex]z_{\alpha/2}[/tex]

[tex]z_{\alpha/2} = z_{0.10/2}[/tex]

[tex]z_{\alpha/2} = z_{0.05}[/tex]

The z score is:

[tex]z_{\alpha/2} = z_{0.05} =1.645[/tex]

The endpoints of the confidence level is:

[tex](\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}[/tex]

[tex]2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}[/tex]

[tex]2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}[/tex]

[tex]2.0 \± 1.645 * \sqrt{0.0735+0.2571}[/tex]

[tex]2.0 \± 1.645 * \sqrt{0.3306}[/tex]

[tex]2.0 \± 0.9458[/tex]

Split

[tex](2.0 - 0.9458) \to (2.0 + 0.9458)[/tex]

[tex](1.0542) \to (2.9458)[/tex]

Hence, the 90% confidence interval is:

[tex]CI =(1.0542,2.9458)[/tex]

Solving (c): 95% confidence interval

We have:

[tex]c = 95\%[/tex]

[tex]c = 0.95[/tex]

Confidence level is: [tex]1 - \alpha[/tex]

[tex]1 - \alpha = c[/tex]

[tex]1 - \alpha = 0.95[/tex]

[tex]\alpha = 0.05[/tex]

Calculate [tex]z_{\alpha/2}[/tex]

[tex]z_{\alpha/2} = z_{0.05/2}[/tex]

[tex]z_{\alpha/2} = z_{0.025}[/tex]

The z score is:

[tex]z_{\alpha/2} = z_{0.025} =1.96[/tex]

The endpoints of the confidence level is:

[tex](\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}[/tex]

[tex]2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}[/tex]

[tex]2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}[/tex]

[tex]2.0 \± 1.96 * \sqrt{0.0735+0.2571}[/tex]

[tex]2.0 \± 1.96* \sqrt{0.3306}[/tex]

[tex]2.0 \± 1.1270[/tex]

Split

[tex](2.0 - 1.1270) \to (2.0 + 1.1270)[/tex]

[tex](0.8730) \to (2.1270)[/tex]

Hence, the 95% confidence interval is:

[tex]CI = (0.8730,2.1270)[/tex]

Answer:

(x - 12)²

Step-by-step explanation:

Given

x² - 24x + 144

Required

Factorize

Start by expanding the expression

x² - 12x - 12x + 144.

Factorize.

x (x - 12) - 12(x - 12)

Factor out x - 12

(x 12)(x - 12)

Rewrite as

(x - 12)²

Answer: a) a) 0.700, (0.676, 0.724)

Step-by-step explanation:

Confidence interval for population proportion p :

[tex]\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]

[tex]\hat{p}[/tex] = Sample proportion, n= sample size, z* = Critical value.

Let p denote the proportion of all people who voted.

As per given, n= 1000

[tex]\hat{p}=\dfrac{700}{1000}\\\\=0.7[/tex]

z* for 90% confidence = 1.645

Required confidence interval :

[tex]0.7\pm (1.645)\sqrt{\dfrac{0.7(1-0.7)}{1000}}\\\\=0.7\pm(1.645)\sqrt{0.00021}\\\\=0.7\pm (1.645)(0.0145)\\\\=0.7\pm 0.0238525\\\\=(0.7-0.0238525,0.7+0.0238525)\\\\=(0.6761475,\ 0.7238525)\approx(0.676, 0.724)[/tex]

hence, the correct option is a) a) 0.700, (0.676, 0.724)

Answer:

the fourth option

9, 30, 93, 282, 849

Step-by-step explanation:

a1 = 9

based on the sequence definition

a2 = 3×a1 + 3 = 3×9 + 3 = 27 + 3 = 30

the only answer option with a2=30 is the fourth one. all others must be therefore wrong.

check

a3 = 3×a2 + 3 = 3×30 + 3 = 93

a4 = 3×a3 + 3 = 3×93 + 3 = 282

a5 = 3×a4 + 3 = 3×282 + 3 = 849

confirmed.

Answer:

It is one-half the area of a rectangle with sides 6 units × 2 units.

Step-by-step explanation:

Area of the triangke ABC = 6

Answer:

Step-by-step explanation:

18t - t + 69 - 6

= 17t + 63 (Ans)

Answer:

17t + 63

Step-by-step explanation:

18t - t + 69 - 6

subtract we get

17 t + 63

Answer:

16 Miles

Step-by-step explanation:

For every week you simply multiply the number of miles from the previous week by 2, therefore

Week 1: 1

Week 2: 2

Week 3: 4

Week 4: 8

Week 5: 16