Mrs. Jeffers bought 3 ¼kg of caramels and 2½ of chocolate. How many kilograms of candy did she buy altogether?​

Answer:

Average height = 64.2 inches

Step-by-step explanation:

[tex]Average = \frac{sum \ of \ the \ values }{number \ of\ value}[/tex]

            [tex]=\frac{62 + 70 + 60 + 63 + 66}{5}\\\\=\frac{321}{5}\\\\=64.2 \ inches[/tex]

The average of the given heights is 64.2 inches

An average of a list of data is the expression of the central value of a set of data. It is defined as the ratio of summation of all the data to the number of units present in the list.

According to the given problem,

Given data = { 62, 70, 60, 63, 66 }

Sum of the given heights = ( 62 + 70 + 60 + 63 + 66 )

                                          = 321

Average = [tex]\frac{321}{5}[/tex]

              = 64.2 inches

Hence, we can conclude, the average of the given data is 64.2 inches.

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Answer:

31.57 cars is the answer rounded to the hundredth, but since its cars you might want to put just 31 since half a car cant pass through. it depends on what your teacher wants really.

Step-by-step explanation:

70=2.1n+3.7

70-3.7=2.1n

66.3=2.1n

66.3/2.1=n

31.57=n

Answer:

A. 120

Step-by-step explanation:

600÷60=10

10×12=120

Hope this helps! :)

Answer:

Question 1: 75 minutes

Question 2: 4:07

Question 3: 30 minutes

Question 4: 8:35

Step-by-step explanation:

An hour is sixty minutes; that's the key to solving these questions.

The time basketball was played is 75 minutes or 1 hour 15 minutes

The time I get home is at 4:07

The cook was cooked for 30 minutes.

The cheerleading was over at 8:35.

It is the conversion of one unit to another unit with its standard conversion.

We have,

Trey and Na Asia played basketball from 10:30 - 11:45.

From 10 to 11 we have 60 minutes.

= 60 minutes - 30 minutes [10:30] + 45 minutes [ 11:45]

= 105 minutes - 30 minutes

= 75 minutes

The time basketball was played.

= 75 minutes

= 1 hour 15 minutes

I left school at 3:15 on the bus. I got home 52 minutes later.

1 hour = 52 minutes

= 3:15 + 52 minutes

= 3  + 15 minutes + 52 minutes

= 3 + 67 minutes

= 3 + 1 hour +  7 minutes

= 4:07

The time I get home is at 4:07

Antavious makes Macaroni and cheese. He begins making it at 6:35 and finished at 7:05.

= 6:35 to 7:05

From 6 to 7 we have 60 minutes.

So,

= 60 minutes - 35 minutes [6:35] + 5 minutes [7:05]

=  65 minutes - 35 minutes

= 30 minutes

The cook was cooked for 30 minutes.

Makhiya and Madison went to cheerleading at 7:15. It was over 1 hour and 20 minutes later.

= 7:15 + 1 hour + 20 minutes

= 7 + 15 minutes + 1 hour + 20 minutes

= 8 + 35 minutes

= 8:35

The cheerleading was over at 8:35.

Thus,

The time basketball was played is 75 minutes or 1 hour 15 minutes

The time I get home is at 4:07

The cook was cooked for 30 minutes.

The cheerleading was over at 8:35.

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Answer:

12m²

Step-by-step explanation:

are the files to be used only for the floor, or also for the walls ? ceiling ?

if it is only for the floor, then the height of the room is irrelevant.

perpendicular clearly stands here for rectangular.

so, the good of the room is a rectangle of 4m length and 3m width.

the area of a rectangle is length×width.

area = 4×3 = 12m²

so, 12m² of tiles will be needed (in reality there would be at least 10% to 20% added for bad tiles, wrong cuts, ...).

if walls need to be included, then you will have to add the areas of 4 more rectangles of length×height.

which would be 2 times 3×2.5 = 7.5m² and 2 times 4×2.5 = 10m².

so, the total area incl. walls would be

12 + 7.5 + 7.5 + 10 + 10 = 47m²

if the ceiling has to be included too, then you need to add the area of another rectangle of the same size as the floor.

so, that total would then be

47 + 12 = 59m².

6.2a = 0.0143

=> a = 0.0143/6.2

=> a = 0.0023......

Answer:

The two column proof is presented as follows;

Statement  [tex]{}[/tex]                            Reason

ΔSCW ≅ ΔTUW [tex]{}[/tex]                    Given

[tex]\overline {SV}[/tex] ≅ [tex]\overline {TU}[/tex] [tex]{}[/tex]                               CPCTC

[tex]\overline {SW}[/tex] ≅ [tex]\overline {TW}[/tex]  [tex]{}[/tex]                            CPCTC

[tex]\overline {WV}[/tex] ≅ [tex]\overline {UW}[/tex] [tex]{}[/tex]                            CPCTC

∠SVW ≅ ∠TUW  [tex]{}[/tex]                   CPCTC

SU = SW + UV [tex]{}[/tex]                       Additive property of Length

TU = TW + VW [tex]{}[/tex]                       Additive property of Length

SU = TW + VW [tex]{}[/tex]                       Substitution

SU = TV [tex]{}[/tex]                        [tex]{}[/tex]          Transitive property

ΔSTV ≅ ΔTSU  [tex]{}[/tex]                       SAS

∠TSV ≅ ∠STU [tex]{}[/tex]                        CPCTC

Step-by-step explanation:

The two column proof is presented as follows;

Statement  [tex]{}[/tex]                            Reason

ΔSCW ≅ ΔTUW [tex]{}[/tex]  Given

[tex]\overline {SV}[/tex] ≅ [tex]\overline {TU}[/tex] [tex]{}[/tex]            Congruent Parts of Congruent Triangles are Congruent

[tex]\overline {SW}[/tex] ≅ [tex]\overline {TW}[/tex]  [tex]{}[/tex]         Congruent Parts of Congruent Triangles are Congruent                  

[tex]\overline {UV}[/tex] ≅ [tex]\overline {VW}[/tex] [tex]{}[/tex]         Congruent Parts of Congruent Triangles are Congruent                  

∠SVW ≅ ∠TUW  [tex]{}[/tex]Congruent Parts of Congruent Triangles are Congruent                  

SU = SW + UV [tex]{}[/tex]    Additive property of Length

TU = TW + VW [tex]{}[/tex]   Additive property of Length

SU = TW + VW [tex]{}[/tex]    Substitution

SU = TV [tex]{}[/tex]              Transitive property

ΔSTV ≅ ΔTSU  [tex]{}[/tex]   Side-Angle-Side rule of congruency

∠TSV ≅ ∠STU [tex]{}[/tex]     Congruent Parts of Congruent Triangles are Congruent                  

Answer:

26/63

Step-by-step explanation:

Try to make the denominators equal so that you can add them:

4(3)/21(3)= 12/63

2(7)/9(7)= 14/63

And now you add, which will give you:

12/63 + 14/63= 26/63

Answer:

47

Step-by-step explanation:

47

4 is 3 less than 7 so fits the requirement for the first part

47 reversed = 74

47 + 74 = 121

Answer:

47

So the number in the unit digit is x since it is unknown.

the number in the tens digit is 3 less than x which can be expressed as x-3.

we have to multiply x-3 by 10 since x-3 is supposed to represent the digit in the tens place. so we have 10(x-3)+x (we are adding x because in any number we always add the tens digit by the ones, for example, 13, 10 + 3)

the reverse number would instead be x in the tens place and (x-3) in the ones place so the equation would be 10x+(x-3)

10(x-3)+x + 10x+(x-3) is equal to 121.

distribute 10(x-3), 10x-30

10x - 30 + x +`10x+x-3

Add like terms, 10x+x and -30-3

11x-33+11x

11x+11x = 22x

so we have 22x-33=121

add 33 to both sides to isolate 22x

121+33= 154

22x=154, divide both sides by 22

154/22 = 7

x=7 but this is only the ones digit.

10(x-3)+x is the equation, so replace x with 7

10(7-3)+7

7-3 = 4 and 4*10 = 40

40 + 7 = 47

original number is 47

Answer:

2103 bags

Step-by-step explanation:

8412/4=2103

Answer:

84 m

Step-by-step explanation:

Perimeter of the park = perimeter of rectangle + perimeter of 2 semicircles

62

Answer:

second option is correct

Answer:

q ≥ 5/7

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

-6q + 7 ≤ 8q - 3

Step 2: Solve for q

Here we see that any number q greater than or equal to 5/7 would work as a solution to the inequality.

Answer:

q ≥ [tex]\frac{5}{7}[/tex]

Step-by-step explanation:

Given

- 6q + 7 ≤ 8q - 3 ( add 6q to both sides )

7 ≤ 14q - 3 ( add 3 to both sides )

10 ≤ 14q ( divide both sides by 2 )

5 ≤ 7q ( divide both sides by 7 )

[tex]\frac{5}{7}[/tex] ≤ q , then

q ≥ [tex]\frac{5}{7}[/tex]

Answer:

Area = 160 cm²

Perimeter = 55.31 cm

Step-by-step explanation:

Applying,

Area of the figure = area of the rectangle- area of the triangle

A = lw+bh/2............... Equation 1

From the question,

Given: l = 16 cm, w = 12 cm, h = 8cm, b = 8 cm

Substitute these values into equation 1

A = (16×12)-(8×8/2)

A = 192-32

A = 160 cm²

Perimeter P = /BC/+/CD/+/DE/+/EF/+/FG/+/GA/

Applying pythagoras theorem to get /FG/

FG² = GE²+EF²

FG² = 8²+8²

FG² = 64+64

FG² = 128

FG = √128

FG = 11.31 cm

Therefore,

P = 16+12+4+8+11.31+4

P = 55.31 cm

Answer:

Step-by-step explanation:

[tex]\frac{a^{m}}{a^{n}}=a^{m-n}\\\\\frac{3n^{5}}{6n^{3}}=\frac{3}{6}*n^{5-3}\\\\=\frac{1}{2}n^{2}[/tex]

Answer:

[tex]\frac{n^{2} }{2}[/tex]

Step-by-step explanation:

Rewrite the division as a fraction.

[tex]\frac{3n^{5} }{6n^{3} }[/tex]

Cancel the common factor of 3 and 6.

[tex]\frac{3(n^{5}) }{6n^{3} }[/tex]

[tex]\frac{n^{5} }{2n^{3} }[/tex]

Cancel the common factor

[tex]\frac{n^{2} }{2}[/tex]

Hope this helps!

If you need more help with questions like these please reach out to me!

Answer:

C = 28

Step-by-step explanation:

6/42 = 32-x/x

Answer:

C = 28

I hope this helped you

Answer:

∠B = 74°

a ≈ 14.5 inches

c ≈ 11.4 inches

Step-by-step explanation:

The given parameters of triangle ΔABC are;

∠A = 62.2°, ∠C = 43.8° and side [tex]\overline{AB}[/tex] = b = 15.8 in

By sine rule, we have;

[tex]\dfrac{a}{sin(\angle A)} = \dfrac{b}{sin(\angle B)} = \dfrac{c}{sin(\angle C)}[/tex]

[tex]a = {sin(\angle A)} \times \dfrac{b}{sin(\angle B)}[/tex]

By angle sum property, we have;

∠B = 180° - (∠A + ∠C)

∴ ∠B = 180° - (62.2° + 43.8°) = 74°

∠B = 74°

[tex]\therefore {a} = {sin(62.2^{\circ})} \times \dfrac{15.8}{sin(74^{\circ})} \approx 14.5[/tex]

a ≈ 14.5 in.

[tex]c = {sin(\angle C)} \times \dfrac{b}{sin(\angle B)}[/tex]

[tex]\therefore {c} = {sin(43.8^{\circ})} \times \dfrac{15.8}{sin(74^{\circ})} \approx 11.4[/tex]

c ≈ 11.4 in.

Answer:

7 Hours

Step-by-step explanation:

According to the Question,

He then continued doing Fishing until 11 am. As a result, he fished for 4 h 45 min. more after resting.

So the Total Time he Spends Fishing is 4 hour 45 min. + 2 hours 15 min.

7 hours  

Answer:

132.8 are left enjoy

Answer:

Domain:  all real numbers

Step-by-step explanation:

The domain is the values that x can take

X can be any real number

Domain:  all real numbers

The mode is the highest frequency data among the given data set is 2.

The value that appears most frequently in a data set is called the mode. One mode, several modes, or none at all may be present in a set of data.

Mode is the highest frequency of any number among data

For example 2,3,5,5,6,5,9,8,5,1

Here mode will be 5 because it has a frequency of 4 remaining all have a lower frequency than 5.

Given the data set is

2, 8, 16, 4, 12, 9, 2

2 has frequency = 2

And remaining all have a frequency as 1

Since 2 has the highest frequency so it will be mode.

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9514 1404 393

Answer:

  3

Step-by-step explanation:

For "a = b" it appears that the intention is b = f(a). It appears that f(a) is the number of letters in the spelling of 'a'.

  "One" has 3 letters

  "Two" has 3 letters

  "Three" has 5 letters

  "Four" has 4 letters

  "Five" has 4 letters

  "Six" has 3 letters

so, 6 = 3.

_____

Additional comment

This appears to be a non-standard use of the equal sign, in which it has no relation to the usual meaning of "equals." Using standard symbols with non-standard meanings should generally be avoided, unless the intended meaning is explained.

Answer:

[tex]A^{I}[/tex]= (7, -1)

Step-by-step explanation:

Rotation is a method of rigid transformation in which a point is moved about a reference point through a stated angle. The rotation could be clockwise or counterclockwise so as to produce the image of the initial object.

In the polar coordinate given, the coordinate of A is given as;

A = (3, 3)

On rotating point A about point C counterclockwise for [tex]270^{o}[/tex], an image [tex]A^{I}[/tex] would be produced.  

But [tex]A^{I}[/tex] would have a coordinate;

[tex]A^{I}[/tex]= (7, -1)

The image of A produced is [tex]A^{I}[/tex] (7, -1).

Given:

Two points are A(6,1) and B(9,4).

To find:

The equation of the line that passes through the given points.

Solution:

If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the equation of the line is:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

It is given that the line passes through the two points A(6,1) and B(9,4). So, the equation of the line is:

[tex]y-1=\dfrac{4-1}{9-6}(x-6)[/tex]

[tex]y-1=\dfrac{3}{3}(x-6)[/tex]

[tex]y-1=1(x-6)[/tex]

[tex]y-1=x-6[/tex]

Adding 1 on both sides, we get

[tex]y-1+1=x-6+1[/tex]

[tex]y=x-5[/tex]

Therefore, the equation of the line is [tex]y=x-5[/tex].

Answer:

b

Step-by-step explanation:

Answer: B <S

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

The line is parallel to y axis, so the equation is x = 5