linear equation thats a horizontal line on a graph example

The Coase theorem suggests that in situations like this, bargaining between the two parties can lead to an efficient outcome. In this case, the smoker and non-smoker (roommate and you) could negotiate to find a solution that minimizes the total cost to both parties.

For example, the smoker could agree to smoke outside or use an air purifier, while the non-smoker could offer to pay a portion of the cost of these solutions. Ultimately, the Coase theorem suggests that as long as property rights are clearly defined and transaction costs are low, the two parties can negotiate to find a mutually beneficial solution to the problem of smoking in the apartment.

1. Clearly defining property rights: Establish whether the apartment has a non-smoking policy or if you have the right to a smoke-free environment within your living space.

2. Engaging in negotiation: Communicate your concerns to your roommate and discuss the negative effects of their smoking on you.

3. Finding a mutually beneficial solution: Both parties can negotiate and arrive at a compromise. This could include your roommate agreeing to smoke outside, designating a specific area for smoking, or using a smoke-filtering device. In some cases, you may also consider offering compensation or splitting the costs of a smoke-filtering device.

By following these steps, both you and your roommate can reach an efficient solution that reduces the cost imposed on you due to your roommate's smoking.

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After 8 years, the value of the investment account will be $16345.99 to the nearest cent.

The formula for continuously compounded interest is V = P[tex]e^{(rt)[/tex], where V is the final value of the investment, P is the initial principal, e is the mathematical constant approximately equal to 2.71828, r is the annual interest rate as a decimal, and t is the time in years.

In this problem, the principal initially invested is $8440, the annual interest rate is 9.2%, or 0.092 as a decimal, and the time period is 8 years. Plugging these values into the formula, we get:

V = 8440 * [tex]e^{(0.092*8)[/tex] = 8440 * [tex]e^{0.736[/tex] = 16345.99

Continuous compounding is a powerful tool for increasing the value of an investment over time, as interest is earned not only on the initial principal, but also on any accumulated interest. In this case, the investment nearly doubled in value over 8 years due to the effect of continuous compounding.

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The  solution to the differential equation y^2dx + (2xy + cos y)dy = 0 is given by the implicit equation xy^2 + sin y = C, where C is an arbitrary constant.

(a) To check whether the differential equation y^2dx + (2xy + cos y)dy = 0 is exact, we can compute the partial derivatives of its left-hand side with respect to x and y, respectively:

∂/∂y (y^2) = 2y
∂/∂x (2xy + cos y) = 2y

Since these partial derivatives are equal, the differential equation is exact.

(b) To find the solution of the differential equation, we need to find a function F(x,y) such that its partial derivatives with respect to x and y, respectively, are equal to the coefficients of dx and dy in the differential equation. In other words, we need to find F(x,y) such that:

∂F/∂x = y^2
∂F/∂y = 2xy + cos y

Integrating the first equation with respect to x, we obtain:

F(x,y) = xy^2 + g(y)

where g(y) is a constant of integration that depends only on y. To find g(y), we can differentiate F(x,y) with respect to y and compare it to the second equation:

∂F/∂y = 2xy + g'(y)

Comparing this to the second equation, we see that g'(y) = cos y. Therefore, we can integrate both sides of this equation with respect to y to find g(y):

g(y) = sin y + C

where C is another constant of integration.

Substituting this expression for g(y) into the expression for F(x,y), we get:

F(x,y) = xy^2 + sin y + C

Therefore, the solution to the differential equation y^2dx + (2xy + cos y)dy = 0 is given by the implicit equation xy^2 + sin y = C, where C is an arbitrary constant.

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You would need to include at least 9604 students in your sample to estimate the proportion of college students who have used cell phones to cheat on an exam to within 0.01 with 95% confidence.

To estimate the proportion of college students who have used cell phones to cheat on an exam with 95% confidence and a margin of error of 0.01, you would need to use the formula for sample size calculation for proportions. The formula is n = (Z^2 * p * (1-p)) / E^2, where Z is the confidence level, p is the estimated proportion, and E is the margin of error.

Assuming that we do not have any prior information on the proportion of college students who have used cell phones to cheat on an exam, we can use a conservative estimate of 0.5 for p. This is because the proportion of students who have cheated using cell phones could be higher or lower than 0.5. We also know that the confidence level is 95%, which corresponds to a Z value of 1.96. Substituting these values in the formula, we get:

n = (1.96^2 * 0.5 * (1-0.5)) / 0.01^2
n = 9604

Therefore, you would need to include at least 9604 students in your sample to estimate the proportion of college students who have used cell phones to cheat on an exam to within 0.01 with 95% confidence.

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When the radius of the cup is 3 cm, the rate of change of the radius is approximately -0.214 cm/sec. This means that the radius is decreasing at a rate of about 0.214 cm/sec.

We can use related rates to find the rate of change of the radius of the cup when the radius is 3cm. Let's begin by finding an equation that relates the height and the radius of the cone.

We know that the cup is a right circular cone, so the formula for the volume of a cone is:

V = (1/3)π[tex]r^2[/tex]h

where V is the volume, r is the radius, and h is the height.

We are given that the cup is 16 cm deep and has a radius of 4 cm, so we can use these values to find the constant of proportionality in our equation. Plugging these values in, we get:

V = (1/3)π([tex]4^2[/tex])(16)

V = 64π

Now we can take the derivative of both sides of the equation with respect to time:

dV/dt = (1/3)π(2r)(dr/dt)h + (1/3)π[tex]r^2[/tex](dh/dt)

We are given that water is poured into the cup at a constant rate of 2 cm^3/sec. This means that dV/dt = 2. We are also given that the radius is changing at a certain rate when it is 3 cm, so dr/dt = ? and r = 3. We need to find dh/dt, the rate of change of the height.

We can plug in the values we know and solve for dh/dt:

2 = (1/3)π(2(3))(dr/dt)h + (1/3)π([tex]3^2[/tex])(dh/dt)

2 = 2π(3)(dr/dt)h + 3π(dh/dt)

2 = 6π(dr/dt)h + 3π(dh/dt)

2 = 2π(3)(dr/dt)(16/r) + 3π(dh/dt) (substituting h in terms of r using the similar triangles)

2 = 32π(dr/dt)/r + 3π(dh/dt)

2 = 32π(dr/dt)/3 + 3π(dh/dt) (substituting r=3)

Now we can solve for dh/dt:

2 = 32π(dr/dt)/3 + 3π(dh/dt)

2 - 32π(dr/dt)/3 = 3π(dh/dt)

dh/dt = (2 - 32π(dr/dt)/3) / (3π)

Substituting the given values, we get:

dh/dt = (2 - 32π(dr/dt)/3) / (3π)

dh/dt = (2 - 32π(0.2)/3) / (3π) (since the volume of a cone is (1/3)π[tex]r^2[/tex]h, taking the derivative of this equation gives dh/dt = 0.2(dr/dt))

dh/dt ≈ -0.214 cm/sec

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In the novel "To Kill a Mockingbird" by Harper Lee, during the trial of Tom Robinson in chapters 17-19, Mayella Ewell accuses Tom of raping her. One piece of evidence presented during the trial is a chart showing the timeline of events on the day in question. According to the chart, Mayella asked Tom to come inside the fence to help her with a task. She claimed that she needed him to break up an old chiffarobe (a type of cabinet) for firewood. However, during cross-examination, Tom reveals that Mayella actually asked him to come inside the fence to help her with a different task - to get a box from the top of the chiffarobe. When Tom climbed up to get the box, Mayella hugged him from behind and then kissed him. This unexpected advance scared Tom, and he quickly left the scene. Mayella's false testimony highlights the prejudice and racism present in Maycomb and the injustice of the trial.

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Answer:

4.2%

Step-by-step explanation:

If the total interest for 4 years is 480, then for 1 year is: 480/4 = 120.  Now, we calculate the percentage of 120 of 3000 by division: 120/3000 = 0.0416666... or rounded to 0.042, which is equal to 4.2%.  If you need to know, the equation equal to this is: 120 = 0.042 x 3000.

The absolute deviation for 3 is 4.7.

The absolute deviation for 7 is 0.7.

The absolute deviation for 13 is 5.3.

The MAD of the data set is 2.9.

We have,

To find the absolute deviation from the mean for each data value, we first need to calculate the mean of the data set.

Mean = (6 + 13 + 4 + 3 + 8 + 12 + 11 + 7 + 8 + 5) / 10 = 7.7

Now, we can find the absolute deviation from the mean for each data value:

|3 - 7.7| = 4.7

|7 - 7.7| = 0.7

|13 - 7.7| = 5.3

To find the MAD (mean absolute deviation) of the data set, we need to find the absolute deviation from the mean for each data value, add them up, and divide by the total number of data values:

MAD = (|6 - 7.7| + |13 - 7.7| + |4 - 7.7| + |3 - 7.7| + |8 - 7.7| + |12 - 7.7| + |11 - 7.7| + |7 - 7.7| + |8 - 7.7| + |5 - 7.7|) / 10

= (1.7 + 5.3 + 3.7 + 4.7 + 0.3 + 4.3 + 3.3 + 0.7 + 0.3 + 2.7) / 10

= 2.9

Thus,

The absolute deviation for 3 is 4.7.

The absolute deviation for 7 is 0.7.

The absolute deviation for 13 is 5.3.

The MAD of the data set is 2.9.

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Thus, investigating the proportion of new cars that experience mechanical problems within the first 5,000 miles can provide valuable information for the automobile manufacturer to improve the quality of their cars and potentially increase customer satisfaction.

To investigate the proportion of new cars that experienced a mechanical problem within the first 5,000 miles driven, the automobile manufacturer would need to collect data on the number of new cars that experienced mechanical problems within this mileage range. This data could be collected through surveys or by analyzing repair records.

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The number of ways to select a committee of four Republicans, three Democrats, and two Independents from a group of 10 distinct Republicans, 12 distinct Democrats, and four distinct Independents is: 277,200.

This can be calculated using the formula for combinations, which states that the number of ways to choose k objects from a set of n distinct objects is given by

nCk = n! / (k! * (n-k)!),

where ! denotes the factorial function.

In this case, we use this formula to calculate the number of ways to choose four Republicans from a group of 10, three Democrats from a group of 12, and two Independents from a group of 4.

We then multiply these values together to get the total number of possible committees:

(10C4) x (12C3) x (4C2) = 210 x 220 x 6 = 277,200

The final answer is 277,200.

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The volume of the solid generated by revolving the region bounded by the curve y=7sec(x) and the line y=7√2 over the interval -π/4 ≤ x ≤π/4 about the x-axis is 196π cubic units.

To find the volume of the solid generated by revolving the region bounded by the curve y=7sec(x) and the line y=7√2 over the interval -π/4 ≤ x ≤π/4 about the x-axis, we need to use the formula for volume of a solid of revolution:

V = ∫[a,b] π y^2 dx

where a and b are the limits of integration, and y is the distance from the axis of revolution (in this case, the x-axis).

First, let's find the points of intersection between the curve and the line:

7 sec x = 7√2
sec x = √2
x = π/4 or x = -π/4

So, the limits of integration are -π/4 and π/4.

Next, let's find the expression for y in terms of x:

y = 7 sec x

Since we're revolving about the x-axis, y is the distance from the x-axis, so:

y = |7 sec x|

Now we can substitute this expression for y into the formula for volume:

V = ∫[-π/4,π/4] π (|7 sec x|)^2 dx

= 98π ∫[-π/4,π/4] sec^2 x dx

= 98π [tan x] [-π/4,π/4]

= 196π cubic units

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We can form any total amount greater than or equal to the smallest base case (25 dollars) using combinations of the 25-dollar and 40-dollar gift certificates.To determine the possible total amounts that can be formed using gift certificates in denominations of 25 dollars and 40 dollars, we will use strong induction.

Base Case:
1. One 25-dollar certificate: Total amount = 25 dollars
2. One 40-dollar certificate: Total amount = 40 dollars

Inductive Step:
Let's assume that for any positive integer k, we can form all possible total amounts greater than or equal to P (some positive integer) using the 25-dollar and 40-dollar certificates. Our goal is to prove that we can also form the amount P + 1.

If we can form the amount P using a combination of x 25-dollar certificates and y 40-dollar certificates, then we can also form the amount P + 1 by simply adding another 25-dollar certificate, giving us (x + 1) 25-dollar certificates and y 40-dollar certificates.

However, this may result in an extra 25-dollar certificate. To account for this, we can replace one 25-dollar certificate with a 40-dollar certificate, since 40 = 25 + 25 - 10. This will give us (x - 1) 25-dollar certificates and (y + 1) 40-dollar certificates

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Kermit will likely enjoy Peggy's iced tea as it has the same concentration as his favorite iced tea.

Let's compare the ratios of tea bags to water in Kermit's favorite iced tea and Peggy's iced tea to determine what Kermit might think of Peggy's iced tea.

1. Kermit's favorite iced tea ratio:
Kermit uses 15 tea bags in every 2 liters of water. So, the ratio is 15:2.

2. Peggy's iced tea ratio:
Peggy made a 12-liter batch of iced tea with 90 tea bags. So, the ratio is 90:12.

Now, let's simplify both ratios:

1. Kermit's ratio:
15:2 can be simplified to 7.5:1 by dividing both numbers by 2.

2. Peggy's ratio:
90:12 can be simplified to 7.5:1 by dividing both numbers by 12.

Both iced tea recipes have the same ratio of 7.5:1 (tea bags to water), and the tea bags are in the water for the same amount of time. Therefore, Kermit will likely enjoy Peggy's iced tea as it has the same concentration as his favorite iced tea.

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Answer: 4x+6

Step-by-step explanation:

3x-y+8+x+y-2

3x+x +y-y  +8-2

4x+6

The probability of winning a big bear in this carnival game is 0.03, or 3%.

In the bean bag toss game at the carnival, contestants have the chance to win a big bear, a small bear, or a consolation prize. The probability of each outcome can be represented as follows:

1. Probability of winning a consolation prize: 0.58
2. Probability of winning a small bear: 0.39

To determine the probability of winning a big bear, we need to remember that the total probability of all possible outcomes in a game should equal 1. Therefore, we can set up the equation:

Probability of winning a consolation prize + Probability of winning a small bear + Probability of winning a big bear = 1

0.58 + 0.39 + Probability of winning a big bear = 1

Now, we can solve for the probability of winning a big bear by subtracting the probabilities of the other outcomes from 1:

1 - 0.58 - 0.39 = Probability of winning a big bear

0.03 = Probability of winning a big bear

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There are 1,048,576 ways a student can answer the 15 questions.

To determine the total number of ways a student can answer the 15 questions, we need to consider the number of possible ways to answer each type of question and then multiply them together. There are 10 true-false questions, and for each question, there are two possible answers (true or false). Therefore, the number of ways to answer these questions is 2^10, which is equal to 1024.

There are 5 multiple-choice questions, and each question has 4 possible choices. Therefore, the number of ways to answer these questions is [tex]4^5[/tex], which is equal to 1024.

To determine the total number of ways a student can answer all 15 questions, we multiply the number of ways to answer the true-false questions by the number of ways to answer the multiple-choice questions:

Total number of ways = [tex]2^{10} \times 4^5[/tex]

= 1024 x 1024

= 1,048,576

This means that a student has a vast number of possible ways to answer the questions, and they should carefully consider their choices to ensure that they answer them correctly.

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The efficiency of a probability sampling technique may be assessed by comparing it to that of non-probability sampling techniques.

Probability sampling is a method of selecting participants randomly from a population, which ensures that every individual has an equal chance of being included in the sample.

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A 95% credible interval for the number of people who will be alive in the year 3000 CE would be highly speculative and uncertain, and it's important to approach such predictions with caution and recognize the limitations of available data and modeling techniques.

AI language model, I do not have the ability to predict the future or estimate the number of people who will be alive in the year 3000 CE.

Any attempt to provide a 95% credible interval for such a prediction would be purely speculative and highly uncertain.

The estimation of future population size is a complex and multi-disciplinary field that involves various factors such as birth rates, death rates, migration, technological advancements, and social changes.

Even with the best available data and modeling techniques, any prediction of future population size would be highly uncertain and subject to error.

Moreover, predicting the population size in the year 3000 CE would require a very long-term outlook that goes beyond the scope of available data and statistical methods.

It's important to note that population trends can be influenced by a wide range of factors that are difficult to predict accurately, including geopolitical events, natural disasters, technological breakthroughs, and social and cultural changes.

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The expression which is equivalent to the given expression; 3(-5h-9) + 2 as required in the task content is; -15h + 25.

It follows from the task content that the expression which is similar to the given expression; 3(-5h-9) + 2 is to be determined.

Since the given expression is; 3(-5h-9) + 2; we have that;

By solving the parentheses by the distributive property;

-15h - 27 + 2

= -15h - 25.

Ultimately, the equivalent expression is; -15h - 25.

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We can start by using the Maclaurin series for the arctangent function: arctan(x) = x - x^3/3 + x^5/5 - x^7/7 + ....

Then, we can substitute x/7 for x in this series to get the power series representation for f(x):

f(x) = arctan(x/7) = (x/7) - (x/7)^3/3 + (x/7)^5/5 - (x/7)^7/7 + ...

To find the first five non-zero terms, we can plug in x = 0 to each term and observe that all terms with odd powers of x will evaluate to 0. Therefore, the first five non-zero terms are:

f(x) = (x/7) - (x^3/3)/7^3 + (x^5/5)/7^5 - (x^7/7)/7^7 + (x^9/9)/7^9

Simplifying, we get:

f(x) = x/7 - x^3/147 + x^5/1715 - x^7/24010 + x^9/408410

The radius of convergence of the power series representation can be found using the ratio test:

lim |a(n+1)/a(n)| = lim [(x/7)^(2n+3)/(2n+3)(2n+2)]

= |x/7| lim [(x/7)^2/(2n+3)(2n+2)]

= 0, for any finite x

Since the limit is 0 for any finite value of x, the radius of convergence is infinite, which means that the power series representation converges for all values of x.

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False. It is possible to display the number 34.789 in a field of 9 spaces with 2 decimal places of precision in C++. One way to do this is by using the ioman ip library and the set w() and set precision() functions. For example:

c out << set w(9) << set precision(2) << fixed << 34.789;
This will output the number 34.79 in a field of 9 spaces.
To answer your question about whether it's impossible to display the number 34.789 in a field of 9 spaces with 2 decimal places of precision in C++, the answer is:
2) False
You can achieve this by using the iomanip library in C++ which provides manipulators like setw and setprecision. Here's a step-by-step explanation:
1. Include the necessary libraries: iostream and iomanip.
2. Use the setw manipulator to set the field width to 9 spaces.
3. Use the setprecision manipulator to set the precision to 2 decimal places.
4. Use the fixed manipulator to make sure the precision is in fixed format.

Here's a code snippet demonstrating this:
```cpp
#include
#include
int main() {
   double number = 34.789;
   std::c out << std::set w(9) << std::fixed << std::set precision(2) << number << std::end l;
   return 0;
}
This code will display the number 34.789 in a field of 9 spaces with 2 decimal places of precision, like this: "   34.79".

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After the fifth day, Mary will have $32 left.

1. Start with the initial amount of money: $243.
2. For each day, calculate the amount spent and the remaining amount.
3. Repeat steps 1 and 2 for the five days.

Here's the step-by-step explanation:

Day 1:
- Money spent: $243 x [tex]\frac{1}{3}[/tex] = 81$
- Remaining money: $243 - 81 = 162$

Day 2:
- Money spent: $162 x [tex]\frac{1}{3}[/tex] = 54$
- Remaining money: $162 - 54 = 108$

Day 3:
- Money spent: $108 \times \frac{1}{3} = 36$
- Remaining money: $108 - 36 = 72$

Day 4:
- Money spent: $72 x [tex]\frac{1}{3}[/tex]= 24$
- Remaining money: $72 - 24 = 48$

Day 5:
- Money spent: $48  x [tex]\frac{1}{3}[/tex]  = 16$
- Remaining money: $48 - 16 = 32$

After the fifth day, Mary will have $32 left.

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The surface area of a triangular prism is 288 square inches. If the triangle base is 8 inches, each rectangular face will be 8 inches broad and 10 inches long. The height of the triangular prism is 16 inches.

To find the height of the triangular prism, we need to use the formula for the surface area of a triangular prism:

Surface Area = 2(Area of the rectangular face) + (Perimeter of the base) x (Height)

We know that the rectangular face has a width of 8 inches and a length of 10 inches, so its area is:

Area of the rectangular face = 8 x 10 = 80 square inches

We also know that the surface area of the triangular prism is 288 square inches. Substituting these values into the formula, we get:

288 = 2(80) + (Perimeter of the base) x (Height)

Simplifying this equation, we get:

288 = 160 + 8(Height)

128 = 8(Height)

Height = 16 inches

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a) The expected numbers of each type of pods = 299.16. (b)  p-values mean with regards to your null hypothesis 5%.

a) To calculate the expected numbers of each type of pods, we first need to find the proportion of the two types of pods. Full pods have a frequency of 882/1180 or 0.746, and constricted pods have a frequency of 298/1180 or 0.254. To calculate the expected number of full pods, we multiply the total number of pods by the frequency of full pods: 1180 x 0.746 = 880.84. Similarly, to calculate the expected number of constricted pods, we multiply the total number of pods by the frequency of constricted pods: 1180 x 0.254 = 299.16.

b) The p-value represents the probability of obtaining the observed data or more extreme data, assuming that the null hypothesis is true. In this case, the null hypothesis is that the observed results are consistent with Mendelian inheritance. A p-value less than 0.05 indicates that there is less than a 5% chance of obtaining the observed results or more extreme results, assuming that the null hypothesis is true. In other words, a p-value less than 0.05 suggests that the observed results are unlikely to have occurred by chance alone and we can reject the null hypothesis. However, in this case, the expected and observed frequencies are relatively close, suggesting that the results are consistent with Mendelian inheritance.

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The probability of at most 1 person leaving the elevator on each floor when assuming that every person is equally likely to leave the elevator on any floor depends on the number of floors in the building and can be calculated using the binomial distribution formula.

Assuming that every person is equally likely to leave the elevator on any floor, the probability that on each floor at most 1 person leaves the elevator can be calculated using the binomial distribution.

Let's say there are n floors in the building. The probability of at most 1 person leaving the elevator on each floor is the probability that 0 or 1 person leaves the elevator on each floor. This can be calculated as follows:

P(at most 1 person leaves the elevator on each floor) = P(0 people leave on floor 1) x P(0 or 1 people leave on floor 2) x P(0 or 1 people leave on floor 3) x ... x P(0 or 1 people leave on floor n)

Now, since we are assuming that every person is equally likely to leave the elevator on any floor, the probability of 0 people leaving the elevator on any floor is (n-1)/n and the probability of 1 person leaving the elevator on any floor is 1/n. Therefore, we can calculate the probability of at most 1 person leaving the elevator on each floor as:

P(at most 1 person leaves the elevator on each floor) = (n-1)/n * (1/n + (n-1)/n)^(n-1)

Simplifying this expression, we get:

P(at most 1 person leaves the elevator on each floor) = (n-1)/n * (2/n)^(n-1)

For example, if there are 5 floors in the building, the probability of at most 1 person leaving the elevator on each floor is:

P(at most 1 person leaves the elevator on each floor) = 4/5 * (2/5)^4
P(at most 1 person leaves the elevator on each floor) = 0.08192

Therefore, the probability of at most 1 person leaving the elevator on each floor when assuming that every person is equally likely to leave the elevator on any floor depends on the number of floors in the building and can be calculated using the binomial distribution formula.

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If two independent large samples are taken from two populations, the sampling distribution of the difference between the two sample means can be approximated by a normal distribution.

The correct answer is (c) the sampling distribution of the difference between two sample means can be approximated by a normal distribution.

This is due to the Central Limit Theorem, which states that the sampling distribution of a large sample size will approach a normal distribution, regardless of the shape of the population distribution.

The variance of the sampling distribution of the difference between the two sample means can be estimated using standard formulas, and it will depend on the sample sizes and the variances of the two populations.

Therefore, options a, b, and d are incorrect.

The correct answer is (c)

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A graph that does not show the same data as the others include the following: B. II.

In Mathematics and Geometry, a graph simply refers to a type of visual chart that is used for the graphical representation of data points or ordered pairs on both the horizontal and vertical lines of a cartesian coordinate, which are the x-coordinate (x-axis) and y-coordinate (y-axis) respectively.

In Mathematics and Geometry, an ordered pair is a pair of two elements or data points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate (abscissa) and the y-coordinate (ordinate) on the coordinate plane of any graph.

In this scenario and exercise, we can logically deduce that the ordered pairs in graph II is quite different from those of the other graphs.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Y = c1 e^(3t) + c2 t e^(3t) + c3 e^(29t) + 1/6 x + 1/3296 e^(2x) (2043 sin(5x) - 3160 cos(5x)) + 1/48 e^(3x) (x^2 - 15x - 12) To use the superposition approach, we need to first find the general solution to the homogeneous equation:
y- 7y"+ 41y- 87y = 0
This can be done by assuming a solution of the form e^(rt) and solving for the characteristic equation:
r^3 - 7r^2 + 41r - 87 = 0
Using synthetic division or other methods, we can factor this to:
(r - 3)(r - 3)(r - 29) = 0
So the general solution to the homogeneous equation is:
y_h = c1 e^(3t) + c2 t e^(3t) + c3 e^(29t)

Next, we need to find particular solutions to each of the three non-homogeneous terms on the right-hand side of the equation:
1) x: We assume a particular solution of the form Ax + B. Substituting into the equation and solving for A and B, we get:
yp1 = 1/6 x
2) e^2x sin(5x): We assume a particular solution of the form (C sin(5x) + D cos(5x)) e^(2x). Substituting into the equation and solving for C and D, we get:
yp2 = 1/3296 e^(2x) (2043 sin(5x) - 3160 cos(5x))
3) (x^2 - 9) e^3x: We assume a particular solution of the form (Ex^2 + Fx + G) e^(3x). Substituting into the equation and solving for E, F, and G, we get:
yp3 = 1/48 e^(3x) (x^2 - 15x - 12)

Finally, we add up the homogeneous and particular solutions to get the final form of the particular solution:
Y = y_h + yp1 + yp2 + yp3
Y = c1 e^(3t) + c2 t e^(3t) + c3 e^(29t) + 1/6 x + 1/3296 e^(2x) (2043 sin(5x) - 3160 cos(5x)) + 1/48 e^(3x) (x^2 - 15x - 12)

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The probability that the first lefty is either the third or the fifth person chosen is approximately 0.073 or 7.3%.

To solve this problem, we first need to find the probability that the first lefty is the third person chosen. This can be done using the following formula:

P(first lefty on third pick) = (0.25 * 0.75 * 0.25) = 0.046875

In this formula, the first term (0.25) represents the probability of selecting a lefty on the first pick. The second term (0.75) represents the probability of not selecting a lefty on the second pick, since we have already selected one person. The third term (0.25) represents the probability of selecting a lefty on the third pick, since we have not yet selected a lefty in the first two picks.

Next, we need to find the probability that the first lefty is the fifth person chosen. This can be done in a similar way:

P(first lefty on fifth pick) = (0.25 * 0.75 * 0.75 * 0.75 * 0.25) = 0.0263671875

In this formula, the first term (0.25) represents the probability of selecting a lefty on the first pick. The second, third, and fourth terms (0.75) represent the probability of not selecting a lefty on the second, third, and fourth picks, since we have already selected one or more people. The fifth term (0.25) represents the probability of selecting a lefty on the fifth pick, since we have not yet selected a lefty in the first four picks.

Finally, we can add the two probabilities together to get the overall probability that the first lefty is either the third or the fifth person chosen:

P(first lefty is third or fifth) = P(first lefty on third pick) + P(first lefty on fifth pick)

P(first lefty is third or fifth) = 0.046875 + 0.0263671875

P(first lefty is third or fifth) = 0.0732421875

Therefore, the probability that the first lefty is either the third or the fifth person chosen is approximately 0.073 or 7.3%.

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