Let XY be a random draw from the following box of tickets0 0 1 1 21 2 0 1 0Find E(X+Y)^2

The number of pounds of chocolate costing $8.20 per pound should be mixed with trail mix is; 18 pounds

Let c represent the pounds of chocolate needed.

The weight of the snack mix is c + 23.

Thus, the algebraic expression here is;

8.2c + 3.4(23) = 5.49(c + 23)

8.2c + 78.2 = 5.49c + 126.27

8.2c - 5.49c = 126.27 - 78.2

2.71c = 48.07

c = 48.07/2.71

c ≈ 18 pounds

This value represents the number of pounds of chocolate costing $8.20 per pound should be mixed with trail mix

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Approximately 7.11 fluid ounces of shampoo to fill a one-gallon container.

One gallon is equal to 128 fluid ounces.

The ratio of shampoo to water is 1:18. This means for every 1 fl oz of shampoo, we need 18 fl oz of water.

To find out how much shampoo is needed to fill a one-gallon container, we need to set up a proportion:

1 fl oz shampoo / 18 fl oz water = X fl oz shampoo / 128 fl oz water

To solve for X, we can cross-multiply:

18 fl oz water * X fl oz shampoo = 1 fl oz shampoo * 128 fl oz water

18X = 128

X = 7.11 fl oz shampoo

So, we need approximately 7.11 fluid ounces of shampoo to fill a one-gallon container.

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The statement about the data the points appear to be on a straight line

From the question, we have the following parameters that can be used in our computation:

Equation of a trend line: y = 0.0001x + 12

The above equation is a linear equation

This implies that the data points represented by  the equation would appear to be on a straight line

Note that: The points may or may not be on a perfect straight line depending on the correlation value

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The area of the bookmark is 72.56 cm².

The area of Rectangle is length times of width.

The width of the rectangle is 4 cm, so the diameter of each semicircle is also 4 cm.

Radius of each semicircle is 2 cm.

The area of the rectangle is length x width

= 15 cm x 4 cm

= 60 cm².

The area of each semicircle is (1/2) x π x radius²

= (1/2) x 3.14 x 2² = 6.28 cm².

The total area of the two semicircles is 2 x 6.28 = 12.56 cm².

The total area is 60 cm² + 12.56 cm² = 72.56 cm²

Therefore, the area of the bookmark is 72.56 cm².

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Saif's performance was better.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

We will compare the run rates of Saif and Anus.

The run rate is the average number of runs scored per over.

Now,

The run rate of Saif.

= 60 / 5

= 12 runs per over

And,

The run rate of Anus

= 72 / 8

= 9 runs per over

Therefore,

Saif's performance was better.

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The median of the randomly selected list of prices of trucks will be 26 thousands dollars.

To find the median , first we need to arrange the list in either ascending form or descending form. Let us arrange the list in ascending form  :

List before sorting : 20,46,19,14,42,26,33

List after sorting it in ascending form : 14,19,20,26,33,42,46

Here, the number of observations is 7 which is odd. So, The formula to find the median term from a given number of "Odd" observations in a set is :

⇒ {(n+1) / 2}th term (where n is the number of observations in a set)

⇒({7+1}/2)

⇒8/2

⇒4th term

Therefore, the 4th term in our list of prices of trucks is the median which is 26 thousand dollars

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Answer:

7.95%

An annuity due is an annuity whose payment is due immediately at the beginning of each period. A common example of an annuity due payment is rent, as landlords often require payment upon the start of a new month as opposed to collecting it after the renter has enjoyed the benefits of the apartment for an entire month.

Answer:

$313.57

Step-by-step explanation:

Compound interests and and compound numbers need:

This means the original amount is multiplied in the first example by 106%, and the product of that is multiplied by 106%, until its done 10 times for 10 years.

Bank À is best

The quantity 2a 2c corresponds to the rate of change of the surface area with respect to a. So, Correct option is C.

When considering a rectangular prism with dimensions a, b, and c, there are three different measures that we can associate with the dimensions: the length, width, and height. These measures are important in determining both the volume and the surface area of the prism.

In this problem, we are given a quantity 2a 2c and asked to determine which measure of the rectangular prism it corresponds to. We can do this by considering the formulas for the volume and surface area of the prism, and taking the partial derivatives with respect to each of the three dimensions.

The volume of a rectangular prism is given by:

V = abc

Taking the partial derivative of this expression with respect to a, we get:

[tex]\frac {\partial v} {\partial a}[/tex] = bc

This is not equal to 2a 2c, so we can eliminate the possibility of the quantity corresponding to the rate of change of the volume with respect to a.

Taking the partial derivative of the volume with respect to b and c gives:

[tex]\frac {\partial v} {\partial b}[/tex] = ac

[tex]\frac {\partial v} {\partial c}[/tex] = ab

Again, neither of these expressions is equal to 2a 2c, so we can eliminate the possibilities of the quantity corresponding to the rate of change of the volume with respect to b or c.

Next, we can consider the surface area of the prism, which is given by:

A = 2ab + 2ac + 2bc

Taking the partial derivative of this expression with respect to a, we get:

[tex]\frac {\partial v} {\partial a}[/tex] = 2b + 2c

Substituting 2a 2c for 2b + 2c, we get:

[tex]\frac {\partial A} {\partial a}[/tex] = 2a 2c

This is the same expression as the given quantity, so we can conclude that the quantity 2a 2c corresponds to the rate of change of the surface area with respect to a.

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Answer:

b

Step-by-step explanation:

time debends in how long it going to take the longer the race the longer the time

If we run tests that can reveal non random patterns in the time ordered data , then the four patterns that might be seen are : Points outside limits , Trend , Cycles and Bias .

The four patterns that might be seen in run tests which can reveal non-random patterns in time-ordered data are:

(i) Points outside limits: This pattern indicates that the data points fall outside of the control limits and suggests that the process is not in statistical control.

(ii) Trend: This pattern indicates that the data points are moving consistently in a particular direction, either increasing or decreasing over time.

(iii) Cycles: This pattern indicates that the data points are oscillating around a central value over time, with a repeated pattern of highs and lows.

(iv) Bias: This pattern indicates that the data points are consistently above or below the centerline over time, indicating a systematic error or shift in the process.

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The graph of the function f(x)=(x-3)(x-1)(x+1) is given by the image presented at the end of the answer.

The function for this problem is defined as follows:

f(x)=(x-3)(x-1)(x+1).

The product is written as a product of it's linear factors, hence the x-intercepts are given as follows:

The y-intercept of the function is given as follows:

f(0) = -3(-1)(1) = 3.

The end behavior is given as follows:

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The graph of the linear equation is on the image at the end.

Here we have the following linear equation:

y = (7/3)*x + 5

To graph that line we need to find two points on the line, to get them, we need to evaluate the line in two different values of x.

if x = 0

y = (7/3)*0 + 5 = 5

if x = 3

y = (7/3)*3 + 5 = 12

Then we have the points (0, 5) and (3, 12)

Now just graph these points and connect them with a line.

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The IQ score of the adult is 110.05.

A normal distribution in statistics is defined as the type of continuous probability distribution where the data are arranged in a symmetrical bell shaped graph.

Given that,

Area to the right of a normally distributed graph is 0.2525.

From the standard table, z score for the area given is 0.67.

z = 0.67

We have the formula,

z = (x - μ) / σ

Given Mean, μ = 100 and standard deviation, σ = 15

0.67 = (x - 100) / 15

x - 100 = 10.05

x = 110.05

Hence the indicated IQ score is 110.05.

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The inequality 2x - 3y < 7 represents the given graph, which is the correct option (B).

Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.

As per option (B), we have

2x - 3y < 7

Subtract 2x from both sides of the inequality:

-3y < 7 - 2x

Divide both sides of the inequality by -3.

y > (7 - 2x) / (-3)

y > (2/3)x - (7/3)

This represents a region in the coordinate plane that is above the line y = (2/3)x - (7/3).

Thus, the inequality 2x - 3y < 7 illustrates the given graph as shown.

Therefore, the correct answer is an option (B) 2x - 3y < 7.

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(A) The mean value of x is 1.12.

(B) The probability that x exceeds its mean value is 0.22.

The first answer is:

(a) To calculate the mean value of x, we multiply each possible value of x by its corresponding probability and add up the products. Mathematically, we can write:

x = (0 * 0.55) + (1 * 0.16) + (2 * 0.07) + (3 * 0.06) + (4 * 0.16)

x = 0 + 0.16 + 0.14 + 0.18 + 0.64

x = 1.12

Therefore, the mean value of x is 1.12.

(b). P (x >? x) = P (x > 1.12)

To find this probability, we need to add up the probabilities of all values of x that are greater than 1.12. From the table, we can see that the probabilities for x = 3 and x = 4 are both greater than 1.12. Therefore, we can write:

P (x > 1.12) = P (x = 3) + P (x = 4)

P (x > 1.12) = 0.06 + 0.16

P (x > 1.12) = 0.22

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The interquartile range, IQR=31.

What is interquartile range?

Interquartile range is a measure of statistical dispersion, which is the spread of the data. The interquartile range is calculated by the  difference between the upper and lower quartile. The formula for the interquartile range is given below

                              [tex]IQR=Q_3-Q_1[/tex]

The given data : 45, 21, 3, 15, 32, 97, 68, 27, 29, 52.

Arrange in ascending order,

3, 15, 21, 27 , 29 ,32 , 45 , 52 , 68 , 97

By dividing in to 2 partition as lower half and upper half from let to right.

Lower half = 3, 15, 21, 27 , 29

Upper half = 32 , 45 , 52 , 68 , 97

Lower Quartile[tex]Q_{1}[/tex]  = Median of Lower half of data

⇒[tex]Q_{1}[/tex]= 21 (Median is the middle most term)

Upper Quartile[tex]Q_{3}[/tex] = Median of Lower half of data.

⇒[tex]Q_{3}[/tex]=52 (Median is the middle most term)

Interquartile range = [tex]IQR=Q_3-Q_1[/tex]

                               = 52-21

                               = 31

Hence, the interquartile range IQ=31.

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We reject the null hypothesis at a significance level of =0.01.

At a significance level of α=0.01, we reject the null hypothesis if the p-value is less than 0.01. In this case, the p-value of 0.0291 is greater than 0.01, so we fail to reject the null hypothesis. Therefore, we do not have sufficient evidence to conclude that the proportion of students in Yvonne's school who rarely or never argue with their friends is significantly different from the national average of 0.72 at a significance level of α=0.01.

In other words, we do not have enough evidence to say that Yvonne's school is significantly different from the national trend of 72% of teens who say they seldom or never argue with their friends.

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The probability of getting the same outcome on all five dice is (1/6) x (1/6) x (1/6) x (1/6) x (1/6) = 1/6^5, or approximately 0.00077.

The probability that every one of the five dice show a similar result is equivalent to the probability of obtain a particular result on one pass on, increased by the probability of come by similar result on every one of the leftover four dice.

The probability of obtain a particular result on one pass on is 1/6, since there are six potential results (1, 2, 3, 4, 5, or 6) and they are similarly probable.

In this manner, the probability of obtain similar result on each of the five dice is (1/6) x (1/6) x (1/6) x (1/6) x (1/6) = 1/6^5, or roughly 0.00077.

This is the probability of moving a Yahtzee in a solitary throw of five dice, it are similarly prone to expect all results.

The probability of moving a Yahtzee, which is the point at which each of the 5 dice show a similar number, is determined by duplicating the probability of come by a particular result on one bite the dust (1/6) without help from anyone else multiple times. This gives a probability of 1 in 6^5, or roughly 0.00077.

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The negation for the formula is Jxez[~p(x) v ~q(x)] ^ Vxez[~p(x) ^ ~q(x)] ^ Vxez[p(x) v ~q(x)]

Negation is a concept used in mathematics to express the opposite or contradictory statement of a given formula.

To find the negation of this formula, we need to apply De Morgan's laws, which state that the negation of a logical conjunction (and) is a logical disjunction (or) with the negation of each of the operands, and vice versa.

First, let's apply De Morgan's laws to the first expression in the formula:

~[Vx €Z[p(x) ^ q(x)]]

The negation of "for all x in Z, p(x) and q(x)" is "there exists x in Z such that ~(p(x) and q(x))," which can be expressed as:

Jxez[~p(x) v ~q(x)]

Now, let's apply De Morgan's laws to the second expression in the formula:

=> ~[Jx €Z[p(x) v q(x)]]

The negation of "there exists x in Z such that p(x) or q(x)" is "for all x in Z, ~(p(x) or q(x))," which can be expressed as:

=> Vxez[~p(x) ^ ~q(x)]

Finally, let's apply De Morgan's laws to the third expression in the formula:

~[Jx €Z[~p(x) ^ q(x)]]

The negation of "there exists x in Z such that not p(x) and q(x)" is "for all x in Z, ~(not p(x) and q(x))," which can be expressed as:

Vxez[p(x) v ~q(x)]

Putting these three expressions together, we get the negation of the original formula as:

=> Jxez[~p(x) v ~q(x)] ^ Vxez[~p(x) ^ ~q(x)] ^ Vxez[p(x) v ~q(x)]

In this case, the original formula involved three functions (p(x), q(x), and logical operators) that were negated using De Morgan's laws to obtain the final expression.

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The difference between the starting volumes is 200 milliliters, the first bucket has the larger volume.

We know that the volumes can be modeled by linear equations, and remember that a general linear equation is:

y = a*x + b

Where a is the slope and b is the initial value.

If the line passes through two points (x₁, y₁) and (x₂, y₂), then the slope is:

a = (y₂ - y₁)/(x₂ - x₁)

For the first bucket we have the points (1, 2900), (10, 2000), then the slope is:

a = (2000 - 2900)/(10 - 1) = -900/9 = -100

So we can write:

y = -100*x + b

To find the value of b, we can replace the value of one of the points in the equation. I will use the first point (1, 2900)

2900 = -100*1 + b

2900 + 100 = b

3000 = b

Now for the other bucket, we have the points (1, 2725) and (10, 2050), so the slope is:

a = (2725 - 2050)/(10 - 1) = -75

So this line is:

y = -75*x + b

Again, replacing the values of one of the points we will get:

2725 = -75*1 + b

2725 + 75 = b

2800 = b

Then the difference in the starting volumes is:

3000  - 2800 = 200

The first bucket has 200 milliliters more.

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The male in the 92nd percentile in height would be 73.75 inches tall.

To find the z-score corresponding to the 92nd percentile, we need to find the value on the standard normal curve such that 92% of the area is to the left of that value.

Using the standard normal table, we can find the z-score closest to 0.92 which is 1.75.

Now that we have the z-score, we can use the following formula to find the height:

height = z-score * standard deviation + average height

So, using the given values of average height (70.5") and standard deviation (2.5"):

height = 1.75 * 2.5 + 70.5

height = 73.75"

Therefore, a male in the 92nd percentile in height would be 73.75 inches tall.

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a. 0.7787; b. 0.0228; c. 0.7453; d. 0.9793. The probabilities are found by looking up the Z-value in Table 1 and finding the corresponding probability.

a. To find the probability that Z is greater than 0.74, we look up 0.74 in Table 1 and find the corresponding probability. The probability that Z is greater than 0.74 is 0.7787, which is the area to the right of the Z-value in the table.

b. To find the probability that Z is less than or equal to −1.92, we look up −1.92 in Table 1 and find the corresponding probability. The probability that Z is less than or equal to −1.92 is 0.0228, which is the area to the left of the Z-value in the table.

c. To find the probability that Z is between 0 and 1.62, we look up 0 and 1.62 in Table 1 and find the corresponding probabilities. The probability that Z is between 0 and 1.62 is 0.7453, which is the area between the two Z-values in the table.

d. To find the probability that Z is between −0.90 and 2.94, we look up −0.90 and 2.94 in Table 1 and find the corresponding probabilities. The probability that Z is between −0.90 and 2.

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Answer:

[tex]C. \ \sqrt{58}.[/tex]

Step-by-step explanation:

1) coordinates of the given points are: A[-3;2] and B[4;-1];

2) the required distance can be calculated using  the next formula:

[tex]d=\sqrt{(X_A-X_B)^2+(Y_A-Y_B)^2} ;[/tex]

3) according to the folmula above the required distance is:

[tex]d=\sqrt{(-3-4)^2+(2--1)^2} =\sqrt{49+9} =\sqrt{58} .[/tex]

Answer:

According to the 2010 ADA standard, the number of wheelchair spaces required in a classroom depends on the total number of seats in the classroom. Specifically, 1 wheelchair space is required for the first 25 seats, and an additional wheelchair space is required for each 25 seats thereafter.

For the 5 classrooms on the 1st floor, there are a total of 5 x 20 = 100 seats. Therefore, we need 1 wheelchair space for the first 25 seats, and 1 additional wheelchair space for the next 25 seats. So in total, we need 2 wheelchair spaces for the 1st floor classrooms.

For the 8 classrooms on the 2nd floor, there are a total of 8 x 35 = 280 seats. Therefore, we need 1 wheelchair space for the first 25 seats in each classroom, and an additional wheelchair space for the next 25 seats. This means that each classroom needs 2 wheelchair spaces. So in total, we need 8 x 2 = 16 wheelchair spaces for the 2nd floor classrooms.

Therefore, the total number of wheelchair spaces needed in all 13 classrooms is 2 + 16 = 18.

However, it's important to note that the question asks for the "fewest total number" of wheelchair spaces needed. Since we can't have a fraction of a wheelchair space, we need to round up to the nearest whole number. Therefore, the answer is 18 rounded up to the nearest whole number, which is 19.

So the correct answer is not one of the options given. The closest option is K. 21, but that is too high.

The total hours you study on Friday and Saturday is ; 3 hours

It is easy to calculate the Mean of a data table and we do this by Adding up all the numbers, then divide by how many numbers there are.

From the table, we are given number of hours spent for 5 days as;

Sunday = 0.75 hours

Monday = 1.5 hours

Tuesday = 0 hours

Wednesday = 2.5 hours

Thursday = 1 hour

Thus, if average for the week of 7 days is 1.25 and total for Friday and Saturday is x, then we have;

(0.75 + 1.5 + 0 + 2.5 + 1 + x)/7 = 1.25

x + 5.75 = 8.75

x = 8.75 - 5.75

x = 3 hours

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The maximum possible area of such a triangle is $\frac{1}{2} \cdot \sqrt{4 + 2\sqrt{3}} = \frac{\sqrt{12 + 6\sqrt{3}}}{2} = 3\sqrt{3} + 3$, and $a + b + c = 3 + 3 + 3 = \boxed{9}$.

Let O and O' be the centers of the circles with radii 1 and 3, respectively, and let P and Q be points on the small and large circles, respectively, such that TPQ is a triangle. ]

Since the radius of the small circle is 1, we have TP = 1. Let R be the midpoint of PQ, so that TR is the altitude of triangle TPQ from T. Let x = TP = 1, y = TQ, and z = TR.  [asy]

unit size(0.6 cm);

pair O, OO, P, Q, R, T;

O = (0,0);

OO = (4,0);

T = (0,3);

P = intersection points(Circle(O,1),Circle(T,2))[1];

Q = intersection points(Circle(OO,3),Circle(T,2))[0];

R = (P + Q)/2;

draw(Circle(O,1));

draw(Circle(OO,3));

draw(T--P--Q--cycle);

draw(T--R);

label("$O$", O, SW);

label("$O'$", OO, SE);

label("$P$", P, NW);

label("$Q$", Q, NE);

label("$R$", R, S);

label("$T$", T, N);

label("$x$", (T + P)/2, W);

label("$y$", (T + Q)/2, E);

label("$z$", (T + R)/2, W);

[/asy]

Then we have TR = z, and by the Pythagorean Theorem in right triangle TPQ we have

\begin{align*}

TQ^2 - 1 &= TR^2 = z^2, \

TQ^2 + 9 &= (TQ + TR)^2 = (TQ + z)^2.

\end{align*}Solving for TQ in the first equation and substituting into the second, we obtain

[(1 + z)^2 + 9 = (1 + z)^2 + 4z^2,]which simplifies to $z^2 - 2z - 2 = 0$. The positive root of this quadratic equation is $z = 1 + \sqrt{3}$, so $TQ = \sqrt{4 + 2\sqrt{3}}$. Then the area of triangle TPQ is

[\frac{1}{2} \cdot TP \cdot TQ = \frac{1}{2} \cdot \sqrt{4 + 2\sqrt{3}}.]Thus the maximum possible area of such a triangle is $\frac{1}{2} \cdot \sqrt{4 + 2\sqrt{3}} = \frac{\sqrt{12 + 6\sqrt{3}}}{2} = 3\sqrt{3} + 3$, and $a + b + c = 3 + 3 + 3 = \boxed{9}$.

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Answer:

3(m-7)

Step-by-step explanation:

because 3 times the quantity: m-7

Answer:

6. 3 times the quantity m minus 7

Step-by-step explanation:

You're welcome.

Let's call the amount of money Rosa spent on art supplies "x". Since Rosa spent 1/4 of her money on art supplies, we can write the equation:

x = (1/4) * 300

x = 75

So Rosa spent $75 on art supplies.

Now we can find out how much money she had left after spending the $75 on art supplies.

remaining = 300 - 75

remaining = 225

And we can find out how much she spent on the boots.

boots = (2/5) * remaining

boots = (2/5) * 225

boots = 90

So Rosa spent $90 on the boots.

Let's call the amount of money Rosa spent on art supplies "A". Since Rosa spent 1/4 of her original $300 on art supplies, we can write the equation:

A = 1/4 * $300

A = $75

So, Rosa spent $75 on art supplies.

Next, let's find out how much money she had left after buying the art supplies. We can subtract the amount she spent on art supplies from her original $300:

$300 - $75 = $225

Now, let's find out how much she spent on the boots. We know that she spent 2/5 of the remainder on the boots, so we can write the equation:

B = 2/5 * $225

B = $90

So, Rosa spent $90 on the boots.

Answer:

x=2

Step-by-step explanation:

We will begin by subtracting both sides by 3

3x+2=4x

We will then subtract both sides by 3x since 3x and 4x are like terms

2=x OR x=2

Hope this helps!

The range of x-values is 1 < x < 21.

According to triangle inequality theorem, for any given triangle, the sum of two sides of a triangle is always greater than the third side.

Given:

We have three sides of Triangle as

PQ = 7x + 13, QR = 10x-2, PR = x + 27.

So, PQ + QR  > PR

(7x + 13) + (10x - 2) > x + 27, which simplifies to x > 1

and, PQ + PR > QR

(7x + 13) + (x + 27) > 10x - 2, which simplifies to x < 21

and, QR + PR > PQ

(10x - 2) + (x + 27) > 7x + 13, which simplifies to x > -3

So, the Range of sides is 1 < x < 21.

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