If the coefficient of kinetic friction between Josh's sled and the snow is 0.08, he slides 6.97 meter from the base of the hill.
To find how far from the base of the hill Josh's sled ends up, we need to first find the speed of the sled at the bottom of the hill using the conservation of energy principle,
mgh = (1/2)mv², plugging in the values given in the problem, we get,
m(9.81 m/s²)(3.5 m) = (1/2)mv²
Simplifying and solving for v, we get,
v = √(2gh)
v = √(2(9.81 m/s²)(3.5 m))
v = 8.29 m/s
Now we can use the kinematic equation,
d = vt - (1/2)at, to find how far the sled slides on the horizontal patch of snow before coming to a stop, where d is the distance traveled, v is the initial velocity (8.29 m/s), a is the acceleration due to friction (-μg), and t is the time it takes to come to a stop (which we can find by setting v = 0 and solving for t),
0 = 8.29 m/s - μg*t
t = 8.29 m/s / μg
Substituting this value of t back into the kinematic equation, we get,
d = (8.29)(8.29/μg) - (1/2)μg(8.29/μg)²
d = 6.97 m
Therefore, Josh's sled ends up 6.97 meters from the base of the hill.
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what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees
Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:
You have the initial velocity (v): 35 m/s
You have the launch angle (θ): 45 degrees
We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.
To calculate vx (horizontal component):
vx = v * cosθ
vx = 35 * cos(45) = 24.7 m/s
To calculate vy (vertical component):
vy = v * sinθ
vy = 35 * sin(45) = 24.7 m/s
We can calculate the horizontal distance (d) traveled using:
d = vx * t (where t is time)
Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:
t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)
t = 24.7 / 9.8 = 2.52 seconds
Now we can calculate the full horizontal distance traveled:
d = vx * t
d = 24.7 * 2.52
= 62.3 meters
So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.
Let me know if you have any other questions!
Answer:
To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.
The horizontal component of the motion remains constant throughout the trajectory and is given by:
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.
The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:
Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)
Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.
The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.
Using these calculations, we can find the horizontal distance traveled by the object.
Let's calculate step by step:
Step 1: Calculate the time of flight
Vertical displacement = 0 (at the highest point)
0 = (35 * sin(45))^2 / (2 * 9.8)
0 = (24.75^2) / 19.6
0 = 616.0125 / 19.6
0 = 31.43
Step 2: Calculate the time of flight
Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2
0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2
0 = 24.75 * time - 4.9 * time^2
4.9 * time^2 - 24.75 * time = 0
time * (4.9 * time - 24.75) = 0
time = 0 (initial point) or 24.75 / 4.9
time = 5.05 seconds
Step 3: Calculate the horizontal distance
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
Horizontal distance = 35 * 5.05 * cos(45)
Horizontal distance = 35 * 5.05 * (sqrt(2)/2)
Horizontal distance = 88.96 meters
Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.Waves portfolios I will give brainliest!
Now, leave the frequency constant, but play with the amplitude. What is the affect of changing the
amplitude on the tone generated?
Now, leave the frequency of wave constant, but play with the amplitude. then the effect of changing the amplitude on the tone generated is its loudness. more the amplitude more it will be loud.
Wave is is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.
Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.
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if one food calorie which equals 1000 "chemistry" calories equals 4184 J, then how far could you go on one cookie containing 50 calories ?
On one cookie containing 50 calories, you could potentially go approximately 298 meters
How to calculate the valueGiven that one food calorie is equivalent to 4184 joules, we can calculate the total energy in joules contained in the 50 calorie cookie:
50 food calories * 4184 J/calorie = 209,200 joules
Assuming an average efficiency of around 25% (meaning 25% of the energy is effectively used for movement), and a body weight of 70 kilograms, we can use a rough estimation that it takes about 1 joule of energy to move 0.4 meters (based on the energy cost of walking).
Distance = (Energy obtained from the cookie * Efficiency) / (Energy cost per meter * Body weight)
Distance = (209,200 J * 0.25) / (1 J/m * 0.4 m/kg * 70 kg)
Distance ≈ 298 meters
Therefore, on one cookie containing 50 calories, you could potentially go approximately 298 meters
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Which of the following explanations represents why taste aversion breaks the rules of conditioning?
A. Taste aversion requires no cognitive processes in order to develop.
B. Taste aversion is a learned response that does not occur without cognition.
C. Taste aversion can develop after only one pairing of a stimulus and response.
D. Taste aversion cannot be explained by using conditioning processes.
Answer:
C. Taste aversion can develop after only one pairing of a stimulus and response.
Explanation:
Taste aversion is a unique type of learned response where an individual develops a strong aversion or avoidance to a specific taste or food after a single pairing of that taste with a negative reaction, such as nausea or illness. This is in contrast to traditional conditioning, where multiple pairings of a stimulus and response are typically required for learning to occur. Taste aversion demonstrates a unique rapidity and specificity in its development, which deviates from the general principles of conditioning.
QUESTION 2
Technician A says when a vehicle pulls to one side; the problem may be caused by a pinion gear binding on the rack gear of a power rack and
pinion steering gear. Technician B says when a power steering rack and pinion steering gear spool valve binds it may cause a vehicle to pull to one
side. Who is correct?
O Technician A only
O Technician B only
O Both Technician A and Technician B
O Neither Technician A nor Technician B
Both Technician A and Technician B are correct.
option C.
What happens when pinion gear and pinion steering becomes binding?When the pinion gear of a power rack and pinion steering gear becomes binding or stuck on the rack gear, it can cause serious problem to the vehicle and one of the prolems is that the vehicle will pull to one side.
So if we consider the statement made by the technicians,
Technician A says when a vehicle pulls to one side; the problem may be caused by a pinion gear binding on the rack gear of a power rack and pinion steering gear.
Technician B says when a power steering rack and pinion steering gear spool valve binds it may cause a vehicle to pull to one side.
So both technicians are correct.
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What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.
Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.
To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.
The energy required to melt 1 kg of ice is 3.33×105 J/kg.
Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.
To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.
Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.
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Rotation axis. Big disk on the bottom M2 and small disk on the top M1 or mass1. Angular frequency of M₁ is zero. M₂ initial angular frequency is Wi = 6π rad/s. Two objets both can spine freely in the axis someone is holding M1 and M2 is fixed on the axis. So M1 can slide down the axis and M₂ is fixed its rotating. Surface of M₂ is rough like sand paper but bottom of M1 surface is soft and it can rub on M₂ rough surface. then M1 disk is dropped on M2. then both disks are rotating and M1 cant slipe because of M2 rough surface. find wf final anular frequency of the system
The final angular frequency of the system is 3π/2 rad/s. Moment of inertia increased, frictional torque decreased angular momentum, conservation of energy equation used.
At the point when M1 is dropped onto M2, the two circles will be coupled together and pivot as a solitary framework. The complete precise force of the framework should be saved. At first, just M2 was turning with a precise recurrence of Wi = 6π rad/s, while M1 was very still, so the underlying rakish force was L = I2 * Wi, where I2 is the snapshot of dormancy of M2.
At the point when M1 is dropped onto M2, the snapshot of latency of the framework expands, so to preserve rakish energy, the precise recurrence of the framework should diminish. The last rakish recurrence can be tracked down utilizing the preservation of precise force condition: L = I1 * wf + I2 * wf, where I1 is the snapshot of dormancy of M1 and wf is the last rakish recurrence of the framework.
Since M1 is sliding on the unpleasant surface of M2, there is frictional power that goes against its movement. This frictional power creates a force on the framework, which makes the precise energy decline. The last precise recurrence can be determined utilizing the preservation of energy condition, which compares the underlying active energy of the framework to the last dynamic energy of the framework:
0.5 * I1 * 0^2 + 0.5 * I2 * (6π)^2 = 0.5 * (I1 + I2) * wf^2
Improving on the situation and tackling for wf, we get:
wf = 3π/2 rad/s
Thusly, the last rakish recurrence of the framework is 3π/2 rad/s.
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An isolated charged conductor sphere of radius 12cm has an electric field 49000 N/C at distance 21cm its center
What is its surface charge denisty
The surface charge density of the isolated charged conductor sphere is approximately 22.15 [tex]C/m^{2}[/tex]
The surface charge density of an isolated charged conductor sphere can be determined using the formula:
σ = E / ([tex]4πr^{2}[/tex])
where σ is the surface charge density, E is the electric field strength, and r is the distance from the center of the sphere.
In this case, the electric field strength E is given as 49000 N/C, and the distance from the center of the sphere r is 21 cm (which can be converted to meters as 0.21 m). Plugging these values into the formula, we have:
σ = (49000 N/C) / [tex](4π * (0.21 m)^{2})[/tex]
Calculating this expression, we find:
σ ≈ 22.15 [tex]C/m^{2}[/tex]
Therefore, the surface charge density is approximately 22.15 [tex]C/m^{2}[/tex]. This indicates the amount of charge per unit area distributed on the surface of the sphere.
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Describe how the composition of gasses changes as you travel up through the Earth’s atmosphere.
Answer:
As you travel up through the Earth's atmosphere, the composition of gases changes. Near the Earth's surface, the atmosphere consists mainly of nitrogen (about 78%) and oxygen (about 21%) with traces of other gases like carbon dioxide and argon. As you go higher, the amount of oxygen decreases, and the concentration of other gases becomes more prominent, such as helium, hydrogen, and ozone.
4 Starting from rest on a level road a girl can reach a speed of 5 m/s in 10s on her bicycle. a Find the acceleration b Find the average speed during the 10s. c Find the distance she travels in 10 s. [2] Eventually, even though she still pedals as fast as she can, she stops accelerating and her speed reaches a maximum value. Explain in terms of the forces acting why this happens.
a. To find the acceleration, we can use the equation:
acceleration = change in velocity / time taken
Here, the initial velocity is 0 m/s (since she starts from rest), the final velocity is 5 m/s, and the time taken is 10 s. Therefore:
acceleration = (5 m/s - 0 m/s) / 10 s = 0.5 m/s^2
So the acceleration of the girl on her bicycle is 0.5 m/s^2.
b. The average speed during the 10 s can be found by dividing the total distance traveled by the time taken. We don't know the distance traveled yet, so we can use another equation:
distance = (initial velocity x time taken) + (0.5 x acceleration x time taken^2)
Here, the initial velocity is 0 m/s, and the time taken is 10 s. We already calculated the acceleration in part (a) as 0.5 m/s^2. Plugging these values in, we get:
distance = (0 m/s x 10 s) + (0.5 x 0.5 m/s^2 x (10 s)^2) = 25 meters
So the girl traveled 25 meters in 10 seconds.
c. As the girl pedals, she applies force to the pedals, which in turn transfers the force to the rear wheel. This force drives the bicycle forward, causing it to gain speed. However, when the bicycle picks up speed, air resistance (also called drag) comes into play, which increases. Eventually, the force of air resistance becomes equal and opposite to the force that propels the bicycle forward. This means that the net force on the bicycle becomes zero, stopping its acceleration and reaching its maximum speed, known as the terminal velocity. Even if the girl pedals faster, she won't be able to increase her speed because the drag force counteracts the propelling force.
The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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Which Of The Following Terms Best Describes Translational Motion Along A Curved Line?
The term that best describes translational motion along a curved line is option B. curvilinear.
The translational motion refers to the movement of an object in a straight line, where all points of the object move parallel to each other. However, when the motion occurs along a curved path, such as a circle, arc, or any other non-linear trajectory, it is referred to as curvilinear motion.
In curvilinear motion, the object follows a curved path, and the velocity and acceleration vectors change direction as the object moves along the curve. This is different from rectilinear motion, which refers to motion in a straight line.
The rotational motion refers to the movement of an object around an axis or a point, such as the spinning of a wheel or the rotation of a planet. Rotational motion involves objects rotating around a fixed axis rather than moving along a curved line.
General is a broad term that does not specifically describe the type of motion along a curved line. It does not provide any specific information about the nature or characteristics of the motion. Therefore, the correct answer is option B.
The Question was Incomplete, Find the full content below :
Which of the following terms best describes translational motion along a curved line?
A. rectilinear
B. curvilinear
C. rotational
D. general
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Mercury has a mass of
3.30 x 1023 kg, and a radius of
2.44 x 106 m. What is the acceleration
of gravity on its surface?
[?] m/s² Please help!!!
Answer:
The acceleration due to gravity on the surface of a planet or celestial body is given by the formula:
g = G M / R^2
where G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet.
Plugging in the values for Mercury, we get:
g = (6.674 x 10^-11 m^3/kg s^2) (3.30 x 10^23 kg) / (2.44 x 10^6 m)^2
Simplifying this expression gives:
g = 3.70 m/s^2
Therefore, the acceleration due to gravity on the surface of Mercury is approximately 3.70 m/s^2.
20N
10N
40N
30N
Balanced or Unbalanced?
Answer:
Unbalanced
Explanation:
Gavin can type 1/2 page of his book report in 5 3/4 minutes what’s the typingrate
Answer:
Jim Crow Laws Effects.
User
What were Jim Crow laws? Your response should also describe at least two effects Jim Crow laws
had on the rights of Black Americans. (4 points)
ChatGPT
Jim Crow laws were a set of state and local laws in the United States, enacted between the 1870s and 1960s, that enforced racial segregation and discrimination against Black Americans. These laws were named after a popular 19th-century minstrel show character who stereotyped African Americans.
Two effects of Jim Crow laws on the rights of Black Americans were:
Limited access to public facilities: Jim Crow laws mandated that public spaces such as schools, parks, hospitals, and restaurants were segregated by race. Black Americans were often denied access to public spaces that were reserved for white people. This segregation limited the ability of Black Americans to participate fully in public life and access resources and opportunities that were available to white Americans.
Restricted voting rights: Jim Crow laws were used to disenfranchise Black Americans by making it difficult or impossible for them to vote. These laws included literacy tests, poll taxes, and other requirements that were designed to exclude Black Americans from voting. As a result, many Black Americans were unable to exercise their constitutional right to vote until the Voting Rights Act of 1965 was passed. This restriction on voting rights undermined the ability of Black Americans to participate fully in democracy and have their voices heard.
User
Gavin can type 1/2 page of his book report in 5 3/4 minutes what’s the typingrate
ChatGPT
To calculate Gavin's typing rate, we need to divide the amount he can type by the time it takes him to type it.
First, we need to convert the mixed number 5 3/4 into an improper fraction:
5 3/4 = (4 x 5 + 3)/4 = 23/4
Next, we can convert the mixed number 1/2 into an improper fraction:
1/2 = 2/4
Now, we can add the two fractions:
23/4 + 2/4 = 25/4
This means that Gavin can type 25/4 pages in 5 3/4 minutes.
To find Gavin's typing rate, we need to divide the amount he can type (25/4 pages) by the time it takes him to type it (5 3/4 minutes):
Typing rate = (25/4) / (5 3/4)
To divide fractions, we can multiply the first fraction by the reciprocal of the second fraction:
Typing rate = (25/4) x (4/23)
Simplifying the fractions, we get:
Typing rate = 25/23
Therefore, Gavin's typing rate is 25/23 pages per minute.
A particle of mass 2unit moves along space curve defined by ~r(t) = (4t 2 − t 3 )ˆi − 5tˆj + (t 4 − 2)ˆk. Find the force acting on it at any time to work out
The force acting on the particle at t = 1 s is 24.4 N.
Mass of the particle, m = 2 units
Distance of the curve, r(t) = (4t²- t³)i - 5tj + (t⁴- 2)k
The velocity of the particle,
v = d[r(t)]/dt = (8t - 3t²)i - 5j + 4t³k
The acceleration of the particle,
a = d²[r(t)]/dt² = (8 - 6t)i + 12t²k
Let the time for which the force is acting be 1 second.
Therefore, acceleration at t = 1 is,
a₁ = 2i + 12k
Hence, the magnitude of acceleration,
|a₁| = √(2²+ 12²)
|a₁| = √148
|a₁| = 12.2 unit/s²
Therefore, the force acting on the particle at t = 1 s is,
F₁ = m x |a₁|
F₁ = 2 x 12.2
F₁ = 24.4 N
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Gravity pulls objects downward. How much work is performed when gravity pulls the man down 0.5 m after each step?
Each time gravity pulls the man down 0.5 m, it does work of -367.5 J. This work is converted into kinetic energy as the man gains velocity while moving downwards.
The work performed by gravity pulling a man down 0.5 m after each step can be determined utilizing the recipe: work = force x distance x cos(theta), where power is the heaviness of the man (mass x speed increase because of gravity), distance is 0.5 m, and theta is the point between the course of power and the heading of movement (which is 180 degrees since the man is moving downwards).
Expecting the man has a mass of 75 kg, the weight can be determined as 75 kg x 9.8 m/s^2 = 735 N. In this way, the work done by gravity after each step is:
work = 735 N x 0.5 m x cos(180 degrees) = - 367.5 J
The negative sign demonstrates that the work done by gravity is the other way to the relocation of the man. In this way, each time gravity pulls the man down 0.5 m, it takes care of business of - 367.5 J. This work is changed over into active energy as the man acquires speed while moving downwards.
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A plane wave in a nonmagnetic medium has E = 50 sin (10^8 + 2*z) ay V/m. Find (a) The direction of wave propagation (b) λ, f, and Er (c) H
(a) The direction of wave propagation is along the negative z-axis.
(b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × [tex]10^{7}[/tex] Hz, and the wave impedance (Er) is approximately 0.1667 sin ([tex]10^{8}[/tex] + 2z) ohms.
(c) The magnetic field (H) is (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ay A/m.
If the direction of wave propagation is specified as along the negative z-axis, we can conclude that the wave is traveling in the opposite direction to the positive z-axis. In the given expression: E = 50 sin(10^8 + 2z) ay V/m
Since the wave is traveling along the negative z-axis, it means that as z increases (in the positive direction), the wave is propagating in the opposite direction.
Hence, the direction of wave propagation for the given wave is along the negative z-axis.
To find the wavelength (λ), frequency (f), and wave impedance (Er), we can relate the electric field (E) and magnetic field (H) components using the wave equation in a nonmagnetic medium:
E = c * H,
where c is the speed of light in the medium, which can be approximated as 3 × [tex]10^{8}[/tex] m/s in free space.
(a) Direction of wave propagation: Along the positive z-axis.
(b) Calculating λ, f, and Er:
Since the electric field (E) is given as E = 50 sin ([tex]10^{8}[/tex] + 2z) ay V/m, we can see that the angular frequency (ω) is [tex]10^{8}[/tex] rad/s and the wave number (k) is 2.
The relationship between wave parameters is given by: c = λ * f, where c is the speed of light.
Using the relation c = ω/k, we can solve for λ and f:
λ = 2π/k = 2π/2 = π m (meters)
f = ω/2π = [tex]10^{8}[/tex]/2π ≈ 1.59 × [tex]10^{7}[/tex] Hz (Hertz)
To find the wave impedance (Er), we can use the equation Er = E/H:
Er = E/c = (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ≈ 0.1667 sin ([tex]10^{8}[/tex] + 2z) ohms.
(c) The magnetic field (H) can be calculated using the relationship H = E/c:
H = (E/c) = (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ay A/m.
The direction of wave propagation is along the negative z-axis. (b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × [tex]10^{7}[/tex] Hz, and the wave impedance (Er) is approximately 0.1667 sin ([tex]10^{8}[/tex] + 2z) ohms. The magnetic field (H) is (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ay A/m.
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A block on the end of a spring is pulled to position x = A and released. In one full cycle of its motion, through what total distance does it travel? A. A / 2 B. A C24 ) 0.4A
The total distance traveled by the block in a one full or complete cycle is 2A.
option C.
What is the total distance travelled by the block?If a block on the end of a spring is pulled to position x = A and released. In one full cycle of its motion, it will travel the following distance as shown below;
x = A cos (ωt)
where;
A is the amplitude of the motionω is the angle speed of the block = 2πft is the period of the motionDuring a half cycle the block will travel a total distance of A.
During another half cycle the block will travel a total distance of A.
The total distance traveled by the block in a one full or complete cycle is calculated as follows;
distance = A + A
distance = 2A
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Work is done on a wooden crate by pushing it across a floor. The work done is equal to the force applied parallel to the floor multiplied by the
A. force of friction
B. distance moved
C. mass of the crate
D. crate's direction
The work done is equal to the force applied parallel to the floor multiplied by the distance moves. Hence, option B is correct.
When a wooden crate is pushed across a floor, the work done on it is given by the product of the force applied parallel to the floor and the distance moved by the crate.
This is because work is defined as the product of force and displacement in the direction of the force, which in this case is the distance moved by the crate. The force of friction and the mass of the crate are not relevant to the calculation of work done in this scenario
It is important to understand the concept of work and the factors that influence it, as it is a fundamental concept in physics and is used in many real-world applications.
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A pizza delivery man has to lift a very large pizza a height of 3.85cm higher than he is already holding it to meet the outstretched arms of the customer. if it takes 116 kj of work on the pizza to lift it this high, what force does he exert on the pizza
The delivery man exerts a force of approximately 3,012,987 N on the pizza to lift it a height of 3.85 cm.
The work done on the pizza to lift it a level of 3.85 cm can be determined utilizing the equation W = Power*d, where W is the work done, F is the power applied, and d is the distance moved. We are given W = 116 kJ and d = 3.85 cm.
To find the power , we want to switch the distance over completely to meters and the work to joules. 3.85 cm is equivalent to 0.0385 m, and 116 kJ is equivalent to 116,000 J.
Presently we can substitute the qualities in the equation and address for F:
W = Power * d
116,000 J = F0.0385 m
F = 116,000 J/0.0385 m
F = 3,012,987.01 N
Hence, the conveyance man applies a power of roughly 3,012,987 N on the pizza to lift it a level of 3.85 cm.
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Activity 1: UNITS OF MEASUREMENT
I. Identify the quantity described by the following units of measurement. Copy and write your answer on one whole sheet of paper.
1. meter per second = _________ 11. joule = ____________
2. meter = _________ 12. Kilogram = ____________
3. second = _________ 13. Cubic meter = _________
4. meter per second squared = ____ 14. Mole = ____________
5. square meter = _________ 15. Kilogram per cubic meter=
6. mass = _________ 16. Watt = ____________
7. newton = _________ 17. Ampere = ____________
8. kelvin = _________ 18. Hertz = ____________
9. volt = _________ 19. Coulomb = ____________
10. candela = __________ 20. Pascal = ____________
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A skier slides horizontally along the snow for a distance of 22 m before coming to rest. The coefficient of kinetic friction between the skier and the snow is 0.15. Initially, how fast was the skier going, in meters per second?
The skier was initially going at 8.046 m/s velocity.
Assume that the skier's initial velocity is v.
The skier travelled 22 metres before coming to a stop.
The kinetic friction coefficient between the skier and the snow is 0.15.
The force of friction acting on the skier is given by:
friction = coefficient of friction multiplied by normal force
The normal force is equal to the weight of the skier, which can be calculated as:
weight = mass x gravity
Assuming the mass of the skier to be m and the acceleration due to gravity to be g, we get:
weight = m x g
The force of friction can then be calculated as:
friction = 0.15 x m x g
The work done by the force of friction is equal to the initial kinetic energy of the skier, which can be expressed as:
work done by friction = 0.5 x m x [tex]v^2[/tex]
Equating the work done by friction to the initial kinetic energy, we get:
0.5 x m x [tex]v^2[/tex] = 0.15 x m x g x 22
Simplifying the equation, we get:
[tex]v^2[/tex] = 2 x 0.15 x 9.8 x 22
When we take the square root of both sides, we get:
v = 8.046 m/s
As a consequence, the skier began moving at 8.046 m/s.
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The lowest pitch that the average human can hear has a frequency of 28.0 Hz sound with this frequency travels through air with a speed of 331M/S what is the wave length?
In a case whereby the lowest pitch that the average human can hear has a frequency of 28.0 Hz sound with this frequency travels through air with a speed of 331M/S the wave length is
What is frequency?Frequency refers to the number of vibrations measured each second. A wave is a collection of vibrations known as energy. The top node is referred to as the trough, and the bottom node as the crest.
λ = wave velocity/frequency
λ = 331 m/s / 28 Hz
λ = 11.82 m
As a result, the lowest pitch that a typical person can hear is at a frequency of 29 Hz. The wavelength of sound at this frequency is 11.82 m as it moves through air at a speed of 331 m/s.
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1. Which of the following does not affect the resistance of a wire?
a) Length
b) Temperature
c) Usage time
d) Cross-sectional area
2. If a 12V battery is passing current through a resistor with a current of 2A, what is the value of the resistor?
a 24resistance
b) 14resistance
c) 10resistance
d) 6resistance
3. Describe the differences between series and parallel circuits.
4. A circuit contains resistors of 8resistance and 4resistance，what is combined resistance if the resistors are combined:
a) In series
b) In parallel
5. A 0.5A current is passing across three resistors of 8resistance, 4resistance and 12resistance that are linked in series.
What is the potential difference of the circuit?
6. Wire A has a resistance of 24resistance. If wire B is double the length and has a diameter four times as large as wire A, what is the resistance of wire B?
The reflection in a clear window of a store
is a(n)
The reflection in a clear window of a store is a(n) image.
Why are images seen as reflection?Images are seen as reflections because of the behavior of light. When light strikes a smooth, reflective surface such as a mirror or still water, it bounces off the surface at the same angle at which it hit it. This process is called reflection. The reflected light rays then travel to our eyes, creating an image.
The angle of incidence (the angle at which the light strikes the surface) is equal to the angle of reflection (the angle at which the light bounces off the surface). This causes the reflected image to be a mirror image of the original object.
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The diagram below shows the velocity vectors for two cars that are moving
relative to each other.
45 m/s west
25 m/s east
Car 1
Car 2
From the frame of reference of car 1, what is the velocity of car 2?
OA. 20 m/s west
OB. 70 m/s east
C. 70 m/s west
D. 20 m/s east
The relative velocity of the car 2 with respect to car 1 is 70 m/s west. So, the correct option is C.
Velocity of the car 1 with respect to the ground, v₁ = 45 m/s west
Velocity of the car 2 with respect to the ground, v₂ = 25 m/s east
Let the direction towards the east be positive and the opposite direction towards the west be negative.
The expression for the relative velocity of the car 2 with respect to car 1 is given by,
v₂₁ = v₂ - v₁
v₂₁ = 25 - (-45)
Therefore, the relative velocity,
v₂₁ = 70 m/s west
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Attaching the image file here.
weight of a person is less inside the deep cave
The weight of a person is less inside the deep cave because, the acceleration due to gravity decreases as we go down towards the depth.
What is meant by gravity ?Gravity is defined as the force that pulls a body towards the centre of the earth or any other mass-containing physical body.
Here,
Since weight is directly proportional to the acceleration due to gravity, it changes as we travel deeper inside the earth.
This is because as we travel deeper, the acceleration due to gravity also decreases. As a result, the weight decreases when the acceleration due to gravity decreases. Mass is constant; it doesn't change at all.
The gravitational field weakens, and your weight falls as you travel closer to the centre because there is progressive decrease in the acceleration due to gravity as, we go down towards the centre.
Hence,
The weight of a person is less inside the deep cave because, the acceleration due to gravity decreases as we go down towards the depth.
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On the upper surface of Jupiter's atmosphere, the attractive force of gravity is 2.5 times that on Earth. What would a bathroom scale show if a 50 kg person were weighed on Jupiter?
Explanation:
The weight of an object is the force of gravity acting on it. Therefore, we can use the formula:
where mass is the mass of the person and gravitational acceleration is the acceleration due to gravity on Jupiter.
On Earth, the acceleration due to gravity is approximately 9.8 m/s^2. On Jupiter, the acceleration due to gravity is 2.5 times that on Earth, so it is:
2.5 x 9.8 m/s^2 = 24.5 m/s^2
Therefore, the weight of a 50 kg person on Jupiter would be:
weight = 50 kg x 24.5 m/s^2 = 1225 N
So a bathroom scale on Jupiter would show a weight of approximately 1225 newtons (N) for a 50 kg person
The weight of a 50 kg person on Jupiter can be calculated using the following formula:
Weight on Jupiter = Mass x Gravity on Jupiter
where the mass of the person is 50 kg and the gravity on Jupiter is 2.5 times that on Earth, which is approximately 24.79 m/s^2.
Weight on Jupiter = 50 kg x 24.79 m/s^2
Weight on Jupiter = 1239.5 N
Therefore, a bathroom scale would show a weight of 1239.5 Newtons for a 50 kg person on the upper surface of Jupiter's atmosphere.
The arrows in the diagram show the direction of the magnetic fields of the atoms that make up a certain material. Which object could the diagram represent ? A. A steel nail B. A refrigerator magnet C. A wooden log D. An iron bar
The diagram shows atoms with aligned magnetic fields, which means they are capable of producing a magnetic field themselves. The correct answer is option B.
This type of alignment is only found in materials that are magnetized, such as a refrigerator magnet. Steel nails and iron bars can also be magnetized, but they are typically only magnetic if they have been previously exposed to a magnetic field. Wood, on the other hand, is not capable of being magnetized as it does not have magnetic properties. Therefore, the diagram most likely represents a refrigerator magnet, which is made of a material that has been magnetized to produce a magnetic field. Option B is correct.
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