Interest of 200 million dollars 53% and 22 years will give brainliest to correct answer

14.11 is the price of one share in the company TYK.

Given:

Find:

Solution:

The dividend is the amount paid to the shareholders for their investment in the company.

Dividend at end of 7th year = $1 per share (given)

dividend expected growth rate = 6%  (given)

the dividend will be paid from the end of seven years.

So find the price of the share at the end of the 6th year.

price at the end of the 6th year

= Dividend at the 7th year/discount rate growth rate

= 1/(10%-6%) = 1/4% = 25

price of the share at the end of the 6th year is $25

discount price 10% (given)

current price share = 25/(1+10%)^6

                              = 25/(1.1)^6

                              = 25/1.77

                             = 14.11

The current price of the share is $ 14.11

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Answer: 57.59- 56.3=1.29

Step-by-step explanation:

57.59-x = 1.29

-x= 1.29-57.59

(—) -x= - 56.3

x=56.3

Answer:

84 flowers.

Step-by-step explanation:

We must multiply 90 by 1/15 to get 6 bulbs that will not flower. 90-6 is 84.

let's firstly convert the mixed fraction to improper fraction and then take it from there, keeping in mind that the whole is "x".

[tex]\stackrel{mixed}{5\frac{5}{6}}\implies \cfrac{5\cdot 6+5}{6}\implies \stackrel{improper}{\cfrac{35}{6}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{7}{3}x~~ = ~~5\frac{5}{6}\implies \cfrac{7}{3}x~~ = ~~\cfrac{35}{6}\implies 42x=105\implies x=\cfrac{105}{42} \\\\\\ x=\cfrac{21\cdot 5}{21\cdot 2}\implies x=\cfrac{21}{21}\cdot \cfrac{5}{2}\implies x=1\cdot \cfrac{5}{2}\implies x=2\frac{1}{2}[/tex]

The path of the given Hamiltonian diagram is A, E, B, C, D, F. See explanation below.

A Hamiltonian path, also known as a traceable path, is one that visits each vertex of the graph precisely once.

A traceable graph is one that contains a Hamiltonian path.

Hence, the path is given as;
A, E, B, C, D, F

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Answer:

telephone was $45, utility was $135

Step-by-step explanation:

Let the telephone bill be x, then the utility bill is 3x

3x+x = 180

4x = 180

x = 45

3x = 135

Answer:

c) 212 sq ft

Step-by-step explanation:

I don't know which ways you tried, but I will show you three different ways, and the answer will be the same using all three ways.

1) The length of the upper horizontal side is 8 ft + 12 ft = 20 ft

Think of a rectangle 20 ft by 16 ft with a rectangle 12 ft by 9 ft missing at the lower right corner.

area = 20 ft × 16 ft - 12 ft × 9 ft

area = 320 ft² - 108 ft²

area = 212 ft²

2) Break up the shape into an upper horizontal rectangle 20 ft long by (16 ft - 9 ft) = 7 ft wide and a lower left rectangle 9 ft high and 8 ft wide.

area = 20 ft × 7 ft + 9 ft × 8 ft

area = 140 ft² + 72 ft²

area = 212 ft²

3) Break up the shape into an left vertical rectangle 16 ft high by 8 ft wide and an upper right rectangle 7 ft high and 12 ft wide.

area = 16 ft × 8 ft + 7 ft × 12 ft

area = 128 ft² + 84 ft²

area = 212 ft²

Answer: c) 212 sq ft

Answer:

Step-by-step explanation:

espero ter ajudado

Answer:

1. x=2       2.

y=1

Step-by-step explanation:

Im sorry I TRIED :(

The mean and the median based on the information given will be 166.08 and 195.

It should be noted that the mean is also the average. It's gotten by adding all the numbers and dividing by 13. This will be 166.08.

The median is simply the middle number. This will be 195.

The range will be:

= 301 - 7

= 294

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The walkway should be about 2.57feet.

What is the total surface area?

The total surface area of the building is the  sum of the total faces of an object contains.

The formula is expressed as:

 TSA = 2(lw + wh + lh)

where,

l is the length ,w is the width , h is the height

Calculation

Given the following parameters

TSA = 168 square feet

length = 8 feet and  Height = 6 feet

Required

Width of the walkway, Substitute the given values in the formula

168 = 2(lw + wh + lh)

84 = (8(6) + 6w + 8w)

84 = 48 + 14w

4w = 84 - 48

14w = 36

w = 2.57feet

The walkway should be about 2.57feet.

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It is true teachers can increase spatial awareness as they use position words or implement mapping and shape manipulation.

This refers to the ability to understand the position of one's body in relation to space and other objects as well as understanding how location and movement work.

In children spatial awareness can be increased through:

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The function that represents the given trigonometric graph is; f(x) = cos (x)

From the given trigonometric Graph, we can see the following;

When x = 0, y = 1

When x = π/2, y = 0

When x = π, y = -1

When x = 2π, y = 1

Now, according to trigonometric functions in radians, we know that;

cos 0 = 1

cos  π/2 = 0

cos  π = -1

cos  2π = 1

These values correspond with what we have in the given trigonometric graph and as such we can say that the function that is graphed is;

f(x) = cos (x)

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In around 6.35 years, the population will be 1 million.

The population is modeled by the exponential equation:

[tex]P(t) = 232,012*e^{0.23*t}[/tex]

Then we just need to solve the equation for t:

[tex]P(t) = 232,012*e^{0.23*t} = 1,000,000[/tex]

Let's solve that:

[tex]232,012*e^{0.23*t} = 1,000,000\\\\e^{0.23*t} = 1,000,000/232,012 = 4.31\\[/tex]

If we apply the natural logarithm to both sides:

[tex]ln(e^{0.23*t}) = ln(4.31)\\\\0.23*t = ln(4.31)\\\\t = ln(4.31)/0.23 = 6.35[/tex]

So in around 6.35 years, the population will be 1 million.

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The range of [tex]y =\log_8(x)[/tex] is the set of all real values

The function is given as:

[tex]y =\log_8(x)[/tex]

The above function is a parent logarithmic function.

The parent logarithmic function have a range of the set of all real values

Hence, the range of [tex]y =\log_8(x)[/tex] is the set of all real values

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Answer:

D

Step-by-step explanation:

on edg

The probability of selecting a respondent who does not prefer Cell C is 0.775

The complete question is in the attached image

From the attachment, we have

Prefer cell C = 90

Total = 400

So, the number of respondents that do not prefer cell C is

Do not = 400 - 90

Do not = 310

The probability is then calculated as:

P = 310/400

Evaluate

P = 0.775

Hence, the probability of selecting a respondent who does not prefer Cell C is 0.775

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When [tex]n=0[/tex], we have

[tex]5^{3^0} + 1 = 5^1 + 1 = 6[/tex]

[tex]3^{0 + 1} = 3^1 = 3[/tex]

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for [tex]n=k[/tex], that

[tex]3^{k + 1} \mid 5^{3^k} + 1[/tex]

Now for [tex]n=k+1[/tex], we have

[tex]5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)[/tex]

so we know the left side is at least divisible by [tex]3^{k+1}[/tex] by our assumption.

It remains to show that

[tex]3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1[/tex]

which is easily done with Fermat's little theorem. It says

[tex]a^p \equiv a \pmod p[/tex]

where [tex]p[/tex] is prime and [tex]a[/tex] is any integer. Then for any positive integer [tex]x[/tex],

[tex]5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3[/tex]

Furthermore,

[tex]5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3[/tex]

which goes all the way down to

[tex]5^{3^k} \equiv 5 \pmod 3[/tex]

So, we find that

[tex]\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3[/tex]

QED

In math, Exponentiation refers to the operation of raising one quantity to the power of another. See the program running the exponentiation below.

The code is given below:

number_of_days = 30

amount_after_30days = 0.01 * (2 ** number_of_days)

# print the amount

print(amount_after_30days)

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The graph of function f is shifted right 3 units and up 4 units.

Let f(x) be the parent function

Now use the Rule : f(x)→f(x-b) to find the shifting of graph

The graph shifts right by b units

So, shift the graph by 3 unit

So, f(x)→f(x-3)

So, the graph shifted right by 3 units

2nd rule used is Rule : f(x)→f(x)+b to find the another shifting of graph

The graph shifts up by b units

Now shift the obtained graph up by 4 units

So,  f(x-3)→f(x-3)+4

So, the graph shifts up by 4 units

Thus, The graph of function f is shifted right 3 units and up 4 units.

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Answer:

A∩B = { 1 }

Step-by-step explanation:

Consider the sets :

A = {1, 2, 6}

B = {x  ;where x is an odd whole number less than 8}

Suppose the numbers of B are natural numbers (not integers).

Then

B = {1 , 3 , 5 , 7}

We obtain :

A = {1, 2, 6}  and  B = {1 , 3 , 5 , 7}

The intersection of A and B or the set A∩B :

is the set of the common numbers of A and B.

Then

A∩B = { 1 }

The set A intersection B(or, A∩B) for the given set A and set B exists {1}.

"The set A intersection B(or, A∩B) exists described as the set composed of all elements that belong to both A and B".

The intersection of a set A with a B exists the set of elements that exist in both sets A and B. The intersection exists represented as A∩B.

The intersection of two mathematical objects exists where they overlap. For geometric objects, the intersection exists as a point or group of points where the objects cross.

For numerical or non-numerical sets, the intersection exists every number or object the two sets contain in common.

Given: A = {1, 2, 6}

B = {x | x is an odd whole number less than 8}.

From the above information, we get

⇒ B = {1, 3, 5, 7}

If A = {1, 2, 6} and B = {1, 3, 5, 7}

then A∩B = {1, 2, 6} ∩ {1, 3, 5, 7}

A∩B = {1}

Therefore, the correct answer A∩B exists {1}.

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The rays and lines in the picture are as follows;

rays: BD, AC and AB

lines: AC

A ray is a part of a line that has one endpoint and goes on infinitely in only one direction.

A ray is named using its endpoint first, and then any other point on the ray

A line segment has two endpoints.

Therefore, the rays and lines are as follows:

rays: BD, AC and AB

lines: AC

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The twelfth element of the geometric sequence is equal to 4,096. (Correct choice: D)

Sequences are series of elements generated according to at least one condition, usually equations. geometric sequences are generated according to a exponential formulas, whose form and characteristics are described below:

f(n) = a · bⁿ ⁻ ¹    (1)

Where:

If we know that a = 4, b = 2 and n = 12, then the twelfth element of the geometric sequence from the statement is:

f(12) = 4 · 2¹² ⁻ ¹

f(12) = 4 · 2¹¹

f(12) = 4 · 2,048

f(12) = 4,096

The twelfth element of the geometric sequence is equal to 4,096. (Correct choice: D)

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Based on the student's grades, and the credit hours, their grade point average is 2.60.

First, find the grade points earned:

= (4 x 3) + (1 x 3) + (3 x 3) + (2 x 1)

= 12 + 3 + 9 + 2

= 26

The GPA is:

=Grade points earned / total number of credits

= 26 / (3 + 3 + 3 + 1)

= 26 / 10

= 2.6

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The number makes the expression a perfect square trinomial is 25.

Hence, we have v² - 10v + 25.

Given the expression; v² - 10v

To determine the number that makes the expression a perfect square trinomial, we divide the coefficient of v by 2 and square the result.

( -1 × 10/2 )²

(-1 × 5)²

( -5 )²

25

We add 25 to the expression to get a perfect square trinomial.

v² - 10v + 25.

Therefore, the number makes the expression a perfect square trinomial is 25.

Hence, we have v² - 10v + 25.

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The correct steps to transform x^2 + 6x +8=0 into the form (x-p)² =q are;

x^2 + 6x +8 +1  = 0 + 1

x^2 + 6x +8 +1  = 1

x^2 + 6x + 9 = 1

(x+3)² = 1

The vertex form of a quadratic equation is expressed as:

a(x-h)² + k

Given the quadratic equation

x^2 + 6x +8=0

Subtract 8 from both sides

x^2 + 6x +8 - 8 = 0 - 8

x^2 + 6x  = -8

Complete the square

(x^2+6x+3^2) = -8 + 9

(x+3)² = -8 + 9

(x+3)² = 1

Hence the correct steps to transform x^2 + 6x +8=0 into the form (x-p)² =q are;

x^2 + 6x +8 +1  = 0 + 1

x^2 + 6x +8 +1  = 1

x^2 + 6x + 9 = 1

(x+3)² = 1

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Answer:

20

Step-by-step explanation:

20+20=40

It is false that x is a function of y

The equation is given as:

x = y^2

Set y = 2

x = (2)^2

x = 4

Set y = -2

x = (-2)^2

x = 4

Different values of y give the same x value.

This means that x is not a function of y

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The domain of the composite function is given as follows:

[–3, 6) ∪ (6, ∞)

The composite function of f(x) and g(x) is given as follows:

[tex](f \circ g)(x) = f(g(x))[/tex]

In this problem, the functions are:

The composite function is of the given functions f(x) and g(x) is:

[tex]f(g(x)) = f(\sqrt{x + 3}) = \frac{1}{\sqrt{x + 3} - 3}[/tex]

The square root has to be non-negative, hence the restriction relative to the square root is found as follows:

[tex]x + 3 \geq 0[/tex]

[tex]x \geq -3[/tex]

The denominator cannot be zero, hence the restriction relative to the denominator is found as follows:

[tex]\sqrt{x + 3} - 3 \neq 0[/tex]

[tex]\sqrt{x + 3} \neq 3[/tex]

[tex](\sqrt{x + 3})^2 \neq 3^2[/tex]

[tex]x + 3 \neq 9[/tex]

[tex]x \neq 6[/tex]

Hence, from the restrictions above, of functions f(x), g(x) and the composite function, the domain is:

[–3, 6) ∪ (6, ∞)

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Answer:

all real values of x where x < -1

Step-by-step explanation:

See attached graph.