In Exercises 10-11, find the range of the function.

10. k(x) = x² + 9

11. f(x) = (x + 5)² +3

Answer: look it up :)

Step-by-step explanation: click new tab. then type 'the sum of a number and 9'. the first or second result will come up with your answer, n+9 is the one I got.

Answer: x+9 or n+9

Step-by-step explanation: sum refers to addition you can put x for "a number"  thus you get x+9 as your expression or n+9 for your teacher but both are variables so it doesn't matter if it's j, y, u, or p what's there functionality wise but your teacher might want it a certain variable like n

The diameter or radius of the circle is the dimension of a circle.

The circular line is drawn equidistant from the center point of a circle, which is a two-dimensional geometry object on a plane.

A geometrical rule states that the dimension of an object with n dimensions is n+1. For instance, a square is made up of line segments that are 1d and a cube is built up of squares that are 2d. The circle is therefore 2d or two-dimensional space since it is made up of 1d diameters.

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Answer:

The length of the parallelogram is half of the circumference of the circle, and its height is equal to the radius of the circle.

Step-by-step explanation:

Answer: Mr. Sink bought 7 calves for a total of $3,500, and he later bought another calf for $600, for a total of $4,100.

In total, Mr. Sink bought 7 + 1 = 8 calves.

The mean cost for all of the calves is equal to the total cost of all of the calves divided by the number of calves.

Therefore, the mean cost for all of the calves is 4,100 / 8 = $512.50.

Step-by-step explanation:

Answer:

Perpendicular line ⇒ 2x + 9y + 42 = 0

midpoint: (-1,1)

Step-by-step explanation:

Let's find the coordinates of midpoint of AB

Here, from figure, A = (-3,-2), B = (1,4)

So midpoint:

[tex]P = (\frac{-3+1}{2},\frac{-2+4}{2})[/tex]

∴ P = (-1, 1)

Now, given straight line is x - 2y = -8(x-8)

⇒x - 2y = -8x+64

⇒9x - 2y - 64 = 0

Perpendicular line to 9x - 2y - 64 = 0 is 2x + 9y + k = 0

Perpendicular line passes though (6,-6)

Putting the values, we get

2(6) + 9(-6) + k = 0

⇒12 - 54 + k = 0

⇒k = 42

∴ Perpendicular line ⇒ 2x + 9y + 42 = 0

The value of π can be written with upper and lower limits as -

3.12 ± 0.062.

Significant figures of a number in positional notation are digits in the number that are reliable and necessary to indicate the quantity of something.

Given is that Helen draws a random circle, she then measures the circumference and diameter. She gets a circumference {C} of 405mm correct to 2 significant figures She gets a diameter {D} of 130mm correct to 2 significant figures.

We can write -

Circumference {C} = (405 ± 2) mm

Diameter {D} = (130 ± 2) mm

The value of π can be calculated as -

π = {C}/{D}

π = (405 ± 2)/(130 ± 2)

Now, divide the numbers without errors first -

405/130

3.12

Now, we will calculate the relative errors in each number -

2/405 = 0.004

2/130 = 0.016

Adding the relative errors -

0.004 + 0.016

0.02

Absolute error = 0.02 x 3.12 = 0.062

The value of π can be written with upper and lower limits as -

3.12 ± 0.062

Therefore, the value of π can be written with upper and lower limits as -

3.12 ± 0.062.

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Answer:

The answer will be 1.53 after dividing and rounding to the nearest tenth 3.5 divided by 2.29.

Therefore ,the top limit of the normal class of three parts of mean class 10th is therefore 60, and the median class is 40–60.

Simply average a collection of three or more numbers yields the phrase "mean." The median method, which employs the maximum of a group of products, and the arithmetic average approach, which uses the sum of both the series' values, are two ways to determine the mean for just a given set of numbers.

Given:

Grades received:

X   f   fi   xi

0-20,     10  15   150

20-40,  30  18   540

40-60, 50 21   1050

60-80, 70 29 2030

80-100 90 p   90p

Total: 3770 + 90p + 83p

Mean (3770 plus 90 pi)/(83 plus pi) = 53

=> 3770 + 90p = 83 * 53 + 53p

=> 37p = 629

=> p = 17

17 students received scores in the 80–100 range.

f = 29 and modal class 60-80

minimum of modal class 60

=> 60 + 20 * 8/20

=>68

68 is the modal marks value.

=> ∑fixi = 3770 + 90p = 3770 + 90(17) = 5300

=> 100/2 = 50

60 is the maximum median class for 3 phases of class 10 with a median class of 40–60.

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Explanation:

The left-most rectangle spans from x = 0 to x = 2. It has base 2 and height 2, which means it has an area of 2*2 = 4 square units. Let A = 4 since we'll use it later.

The middle rectangle goes from x = 2 to x = 4. It has base 2 and height 3 (because it goes from y = 0 to y = -3). The area is B = 2*3 = 6

Draw a vertical line through 6 on the x axis. This forms the final rectangle we need. It has base 2 (because it goes from x = 4 to x = 6) and height 5. The area is C = 2*5 = 10.

The small sliver to the right of x = 6 is ignored completely.

--------------------

Summary so far:

Those represent the areas of the rectangles from left to right. We ignore the portion to the right of x = 6.

Since rectangle B is below the x axis, we treat this as a negative area, or we subtract off this area. The positive areas of rectangles A and C are added.

So,

A-B+C = 4-6+10 = 8 is the final answer

We can write [tex]\displaystyle \int_{0}^{6}f(\text{x})d\text{x} = \boldsymbol{8}[/tex]

Answer:

true

Explanation

1. if a man has a hundred apples and like to share between 20 men. this has to be equal.

5 to 1man.

The slope-intercept form of the two straight lines in the graph of the question are;

The slope-intercept form of the equation of a straight line is; y = m·x + c

Where;

m = The slope of the line

c = The y-intercept of the line

The values of the ordered pair of the points on the line are in the form (x, y)

The graph consists of two straight lines, therefore the equations that represent the graphs are found as follows;

Points on the blue line graph are (0, 4), (2, 4), and (4, 4)

The slope of the blue line graph is therefore;

m = (4 - 4)/(2 - 0) = 0

The y-intercept of the blue line graph is; c = 4

The slope-intercept form of the equation representing the blue line graph is therefore;

y = 0 × x + 4

The slope-intercept form of the equation of the blue line graph is; y = 4

Points on the red line graph are; (0, 3), (2, 3), (4, 3)

The sloped of the red line graph is therefore; m = (3 - 3)/(2 - 0) = 0

The y-intercept of the red line graph is; c = 3

The slope-intercept form of the equation of the red line graph is therefore; y = 0 × x + 3

y = 3

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On solving the provided question, we can say that - the given triangles ECD and triangle PQR

Three sides and three vertices make up a triangle, which is a polygon. It is among the fundamental forms in geometry. Triangle ABC is the name given to a triangle with vertices A, B, and C. When the three points are not collinear, a unique plane and triangle in Euclidean geometry are found. A triangle is a polygon that has three sides and three corners. The spots where the three sides join end to end make up the triangle's corners. Three triangle angles added together equal 180 degrees.

here,

EC = PQ

CD = PR

ED = QR

therefore both triangles are similar by SSS property

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1) The equation of a line of best fit is; y = -1.15x + 102.8

2) The predicted monthly cost for an average temperature of 25°F is $74.05

The equation of a line of best fit is represented by the equation;

y = mx + c

where;

m is the slope

c is the y-intercept

1. To calculate the slope here, we will use the formula;

Slope = (y₂ - y₁)/(x₂ - x₁)

Using two coordinate points on the scatter plot, (72, 20) and (20, 80), we have the slope as;

Slope (m) = (80 - 20)/(20 - 72)

Slope = 60/-52

Slope = -1.15.

Plug in -1.15 for m and (a, b) = (72, 20) into the formula; y = mx + c to get;

20 = -1.15(72) + c

c = 20 + 82.8

c = 102.8

The equation  will now be;

y = -1.15x + 102.8

2. Monthly heating cost, y, for a month with an average temperature of 25°F (x) will be calculated by plugging in 25 for x in the equation of line of best fit gotten earlier to get;

y = -1.15(25) + 102.8

y = 102.8 - 28.75

y = $74.05

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The  answer is distance from P to l. is equal to square root of 2

Line I contains points (0, -3) and (7,4). Point P has coordinates (4,3)

Find the slope of line l we have the points (0, -3) and (7,4)

m=(4+3)/(7-0) m=7/7 m=1

Find the equation of the line perpendicular to the line l that passes through the point P

Remember that

If two lines are perpendicular, then the product of their slopes is equal to -1, the slope of the perpendicular line is

m=-1 .Find the equation in point slope form

y-y1=m(x-x1)

(x1,y1)=P(4,3)

substitute

y-3=-1(x-4)

y-3=-x+4

y=-x+7

m=1 (see the step 1)

and we have the point (0,-3) -----> y-intercept

so the equation of the line l is

y=x-3

Find the intersection point line l and its perpendicular line

y=x-3 ------> equation A

y=-x+7 -----> equation B

solve the system of equations

Adds equation A and equation B

2y=-3+7

2y=4

y=2

substitute in equation A

2=x-3 x=2+3 x=5

the intersection point is (5,2)

Find the distance between point (5,2) and point P(4,3)

Remember that, this distance is the distance from P to l.

the formula to calculate the distance between two points is equal to

we have

(x1,y1)=(5,2)

(x2,y2)=(4,3)

substitute in the formula

therefore

The  answer is distance from P to l. is equal to square root of 2

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Answer:

t is 13

scale factor is 7/4

Answer:

Step-by-step explanation:

Functions whose inverses are also functions.

Inverse function is represented by [tex]f^{-1}[/tex] with regards to the original function  and the domain of the original function becomes the range of inverse function and the range of the given function becomes the domain of the inverse function. The graph of the inverse function is obtained by swapping (x, y) with (y, x) with reference to the line y = x.

If a horizontal line intersects the original function in a single region, the function is a one-to-one function and inverse is also a function.

Every function has an inverse, but not every inverse will be a function. The inverse may fail the vertical line test. If the original function is a one-to-one function, then its inverse will be a function. A one-to-one function not only passes the vertical line test, it also passes a horizontal line test.

Therefore, functions whose inverses are also functions.

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the quadratic equation have been solved and the required graph is attached below.

What is quadratic equation?

it's a second-degree quadratic equation which is an algebraic equation in x. Ax2 + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term, is the quadratic equation in its standard form. A non-zero term (a 0) for the coefficient of x2 is a prerequisite for an equation to be a quadratic equation. The x2 term is written first, then the x term, and finally the constant term is written when constructing a quadratic equation in standard form. In most cases, the numerical values of letters a, b, and c are expressed as integral values rather than fractions or decimals.

The equation:

[tex]\frac{x^{2}-7x+12 }{x^{2} -1}[/tex]

Its a quadratic equation in both numerator and denominator, by dividing the x² will be get a graph as given in the attached file.

Hence, the quadratic equation will be solved and the required graph is attached below.

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The correct option regarding which of the sentences represents a trigonometric identity is given as follows:

b. None of the equations are identities.

A trigonometric identity is a relation that is true for all possible angle measures of [tex]\theta[/tex]

The first relation is given as follows:

[tex]4\cos{\theta}\tan{\theta}\sec{\theta} = 4[/tex]

The tangent and secant equations are given as follows:

Hence:

4cos(x)tan(x)sec(x) = 4cos(x) x sin(x)/cos(x) x 1/cos(x)

4cos(x)tan(x)sec(x) = 4sin(x)/cos(x)

4cos(x)tan(x)sec(x) = 4tan(x).

Meaning that the first statement is not an identity.

The second relation is given as follows:

[tex]\frac{9\sec^{2}{\theta}}{\cos^{2}{\theta}} - \frac{\tan^{2}{\theta}}{\cos^{2}{\theta}} = 2[/tex]

With a single denominator, we have that:

[tex]\frac{9\sec^{2}{\theta} - \tan^{2}{\theta}}{\cos^{2}{\theta}} = 2[/tex]

The secant identity is given as follows:

[tex]\sec^2{\theta} = 1 + \tan^2{\theta}[/tex]

Hence:

[tex]\frac{9\sec^{2}{\theta} - \tan^{2}{\theta}}{\cos^{2}{\theta}} = 2[/tex]

[tex]\frac{9(1 + \tan^2{\theta}) - \tan^{2}{\theta}}{\cos^{2}{\theta}} = 2[/tex]

[tex]\frac{9 + 8\tan^2{\theta}}{\cos^{2}{\theta}} = 2[/tex]

Is also a false statement, hence neither is an identity and option B is correct.

The statements are given by the image presented at the end of the answer.

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Answer:

15+5=v

Step-by-step explanation:

Solve

1. Add the numbers

15+5 = v

20 = v

2. Move the variable to the left

20 = v

v = 20

3. Solution

   v = 20

Answer:

n = -4/9

Step-by-step explanation:

first get rid of n on left side

-2 = 9n + 2

Get rid of 2 on right side

-4 = 9n

Make 9n into n

-4/9 = n

ans: n = -4/9

hope this helps :)

Therefore , the solution of the given problem of equation comes out to be a.60 , b.20 and c.21.

An equation in mathematics is a representation of two equal variables, one on each side of a "equals" sign. To tackle common issues, equations can be used. We commonly seek pre algebra help to overcome obstacles in real life. Math fundamentals are covered in pre-algebra lessons.

Here,

Given : 9(x - y) = 30,

or (x-y) =30/9

To find :  

a) 18(x - y) = ?

=> 2(9(x - y))

=> 2(30)

=> 60

b)6x - 6y = ?

=> 6(x-y) = 6(30/9)

=> 2*30/3

=> 20

c) 9(x-y)-9

=> 30 -9

=>21

Therefore , the solution of the given problem of  equation comes out to be a.60 , b.20 and c.21.

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Answer:

2x^5+y^12*x^2/3

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

x²+5x=0

by factorizing;

x(x+5)=0

x=0 or x+5=0

Therefore, x= 0 or x=-5 ---> {0, -5}

Amount of pounds that Ben get back is £75.

Exchange rate is defined as the value of a currency with respect to another currency in order to convert the currency.

Ben changes £800 to Euros before he goes on holiday.

Before holiday, exchange rate is, £1 = 1.25 Euro

£800 = 800 × 1.25 Euros = 1000 Euros

He spends 895 Euros.

Euros left = 1000 - 895 = 105 Euros

Now, the exchange rate is £1 = 1.40 Euro.

or 1.40 Euro = £1

⇒ 1 Euro = £ 1/1.40

⇒ 105 Euros = £ (1/1.40) × 105 = £75

Hence Ben got £75 of pounds back.

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By solving system of linear equation we get Cost for 1 cheeseburger $5 and 1 cups of lemonade $2

A system of linear equations is a collection of two or more linear equations that have the same variables. A linear equation is an equation in which the highest power of the variable is 1. In other words, the equation is a straight line when graphed.

Here is an example of a system of linear equations:

3x + 2y = 19

2x + 4y = 18

This is a system of equations problem, where we can use the information provided to set up two equations and then solve for the unknown variables. Let x be the cost of one cheeseburger and y be the cost of one cup of lemonade.

From the information provided, we know that:

3x + 2y = 19 (the cost of 3 cheeseburgers and 2 cups of lemonade is $19)

2x + 4y = 18 (the cost of 2 cheeseburgers and 4 cups of lemonade is $18)

To find the cost of one cheeseburger and one cup of lemonade, we can solve this system of equations. One way to do this is by substitution.

3x + 2y = 19

we get

[tex]x=\frac{19-2y}{3}[/tex]

substituting x in equation 2x+4y=18

we get

 [tex]2(\frac{19-2y}{3})+4y=18[/tex]

[tex]38 - 4y + 12y = 54\\8y = 16\\y = 2[/tex]

substituting y in equation 3x+2y=19

[tex]3x+2(2)=19\\3x=19-4\\3x=15\\x=5[/tex]

The cost of one cup of lemonade is $2

The cost of one cheeseburger is $5

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An acute angle, θ, is in a right triangle such that sin of theta is equal to 3 over 8 period  The value of cot θ is (√55)/3.

To determine the value of cot(θ), Since is an angle in a right triangle and sin() = 3/8, we obtain:

cot(θ) = (√55)/3

In light of the fact that is an acute angle in a right triangle, we may calculate:

sin(θ) = 3/8

Keep in mind:

Hypotenuse = ((opposite cathetus)2 + (adjacent cathetus)2), where sin() = (opposite cathetus)/(hypotenuse)

Next, we have:

contrary cathetus = 3

Using the formula hypotenuse = 8 = (3 + neighboring cathetus)2,

In order to solve this for the nearby cathetus, we obtain:

(82 - 32) = 55 adjacent cathetus

And we are aware of:

(Cot) = (nearby cathetus) (opposite cathetus)

Next, we have:

cot(θ) = (√55)/3

The value of cot θ is (√55)/3.

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The binomials which correctly represent the factors of the given trinomial; x² + x - 30 as required in the task content are; ( x - 5 ) and ( x + 6 ).

As evident in the task content; the given trinomial whose binomial factors are to be determined is; x² + x - 30.

By factorisation; the given trinomial expression can be written as;

x² + 6x - 5x - 30

x ( x + 6 ) -5 ( x + 6 )

( x - 5 ) ( x + 6 )

On this note, the required binomials which are factors of the given trinomial expression are; ( x - 5 ) and ( x + 6 ).

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