Answer:
120 pounds = 54.5 kilogram
Step-by-step explanation:
We know that,
1 kilogram=2.2 pounds
or
1 pound = (1/2.2) kilogram
We need to convert 120 pounds to kilograms.
[tex]120\ \text{pounds}=\dfrac{120}{2.2}\ \text{kilogram}\\\\=54.5 \text{kilogram}[/tex]
So, there are 54.5 kilograms in 120 pounds.
Can we write 0 in the form of p by q?
Answer:
Yes
=======================
Any rational number can be written in the form of p/q as per definition of a rational number.
In case with zero, it can be:
p = 0,q = any number other than zero.So, we'll have:
0/any number = 0seven twelfths plus two twelfths equals one half 1 one and one half 2
Answer:
the answer is 3/4 because 7/12 + 2/12 is 9/12 which simplified is 3/4
Step-by-step explanation:
How to simplify equations
Simplifying equation is done by either reducing the complexity or the components parts of an equation for better understanding.
SimplifyThis means to make simpler, either by reducing in complexity, reducing to component parts, or making easier to understand.
Simplification is an act of simplifying an equation or expression.
For instance,
Simplify 4(3x + 2) - 4(2x)
open parenthesis= 12x + 8 - 8x
= 12x - 8x + 8
= 4x + 8
Simplify 1/2 + 2/3
= (3+4) / 6
= 7/6
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Damian has 74 m of fencing to build a four-sided fence around a
rectangular plot of land. The area of the land is 342 square meters.
Solve for the dimensions (length and width) of the field.
Answer:
Step-by-step explanation:
Let the length be l and the width be y. We have the following:
l + w = 37
lw = 342
From here, we can find the factor pairs of 342, and see which pair has a sum of 37. Our desired pair is 18 & 19, so the dimensions of the field are 18 by 19 feet.
(The two triangles are not the same)
In the quadrilateral ABCD, in which angle A = 60° and angle B = 50°. The measure of angles C and D are,
∠C = 200° and ∠D = 50°
In the quadrilateral ABCD, it is given that,
A = 60° and angle B = 50°
Now, since AC is the angle bisector of angles A and C, we have,
∠DAC = ∠BAC ......... (1)
And ∠ACD = ∠ACB ............ (2)
Also, AC divides the quadrilateral ABCD into two triangles, ΔABC and ΔACD.
In ΔABC, ∠BAC = 30° [from (2)] and ∠ABC = 50°
Using angle sum property of a triangle, we have,
∠BAC + ∠ABC + ∠ACB = 180°
⇒ 30° + 50° + ∠ACB = 180°
80° + ∠ACB = 180°
∠ACB = 180° - 80°
∠ACB = 100°
From (1), ∠ACD = ∠ACB = 100°
∠C = ∠ACD + ∠ACB
⇒ ∠C = 100° + 100°
∠C = 200°
Now, according to the angle sum property of a quadrilateral,
∠A + ∠B + ∠C + ∠D = 360°
Substituting the values of ∠A, ∠B, and ∠C, we get,
60° + 50° + 200° + ∠D = 360°
310° + ∠D = 360°
∠D = 360° - 310°
∠D = 50°
Hence, in quadrilateral ABCD, ∠C = 200° and ∠D = 50°
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In a professional division of a Hockey league, there are 9 total teams. How many different rankings are possible at the end of the year
The cross-sectional areas of a triangular prism and a right cylinder are congruent. The triangular prism has a height of 5 units, and the right cylinder has a height of 3 units. Which conclusion can be made from the given information? (1 point) The volume of the prism is half the volume of the cylinder. The volume of the prism is twice the volume of the cylinder. The volume of the prism is equal to the volume of the cylinder. The volume of the prism is not equal to the volume of the cylinder.
Answer:
Step-by-step explanation:
The volume of the prism is not equal to the volume of the cylinder.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Let x represent the cross sectional areas of a triangular prism and a right cylinder.
Volume of cylinder = cross sectional area * height = 3 * x = 3x
Volume of triangular prism = cross sectional area * height = 5 * x = 5x
The volume of the prism is not equal to the volume of the cylinder.
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What must be added to x² + 6x²-x+ 5 to make it exact divisible by (x + 3)
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
What are the potential solutions of log4X+log4(x+6)=2?
Ox=-2 and x=-8
Ox=-2 and x = 8
O x=2 and x=-8
Ox=2 and x=8
Answer:
x = 2 ; x = -8
Step-by-step explanation:
Log rule: Log a + log b = log a*b[tex]\sf \ log_4 \ x +log_4 \ (x +6) = 2\\\\ log_4 \ (x)*(x +6) = 2\\\\[/tex]
log₄ ( x² + 6x) = 2
4² = x² + 6x
x² + 6x - 16 = 0
x² - 2x + 8x - 16 = 0
x(x - 2) + 8(x - 2) = 0
(x - 2) (x + 8) = 0
x - 2 = 0 or x + 8 = 0
x = 2 or x = - 8
The half-life of a radioactive material is about 2 years. How much of a 5.0 kg sample of this material will remain after 4 years
The remaining amount after 4 years is 1.25 kg
How to determine the remaining amount?The half life of a function is represented as:
[tex]A = A_o * (1/2)^{t/h}[/tex]
Where
Ao represents the initial amount
So, we have:
[tex]A = 5 * (1/2)^{t/2}[/tex]
In 4 years, t = 4.
So, we have:
[tex]A = 5 * (1/2)^{4/2}[/tex]
This gives
[tex]A = 5 * (1/2)^2[/tex]
Evaluate the expression
A = 1.25
Hence, the remaining amount after 4 years is 1.25 kg
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Mateo teaches a continuing education class at the library on tuesday nights. he estimates that 75% of his students are satisfied or very satisfied with the class. last week, he asked a random sample of students to take a survey on their experience in the class. however, the results showed that only 70% indicated that they are satisfied or very satisfied with the class. he decides to randomly survey more of his students. how will mateo know whether his model is valid or not?
The computed value must closely match the real value for a model to be considered valid. If the percentage of pleased or very satisfied students remains close to 75% after Mateo surveys additional students, Mateo's model is still viable. The model is faulty if the opposite is true.
How will mateo know whether his model is valid or not?In general, a valid model is one whose estimated value is close to the real value. This kind of model is considered to be accurate. It must be somewhat near to the real value if it doesn't resemble the real value.
If the findings of the survey are sufficiently similar to one another, then the model may be considered valid.
P1 equals 75%, which is the real assessment of the number of happy pupils
P2 is 70 percent; this represents the second assessment of happy pupils
In conclusion, The estimated value of a model has to be somewhat close to the real value for the model to be considered valid. If the number of students who are either pleased or extremely satisfied remains close to 75 percent following Mateo's survey of more students, then Mateo's model is likely accurate. In any other scenario, the model cannot be trusted.
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Which of these is a characteristic of certificates of deposit (CDs)? O They are always offered at variable rates They last for a set period of time They can be opened with any amount of money O They allow access to the money at any time without penalty
The characteristic of certificates of deposit (CDs) is that it last for a set period of time and is denoted as option B.
What is Certificate of deposit?This is also referred to as time deposit and is characterized by a lump sum being saved at a fixed period of time and is stricter than the normal savings system.
This type of savings has a fixed interest rate and can't be withdrawn before the maturity date unlike savings account which can be accessed at any point in time which makes it unique and is therefore the most appropriate choice.
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Instructions: Find the missing side. Round your answer to the nearest tenth.
Using the sine ratio, the length of the missing side is: 11.8.
How to Find Missing Side Using the Sine Ratio?The sine ratio is, sin ∅ = opposite/hypotenuse.
Given the following:
∅ = 24°
Opposite = x
Hypotenuse = 29
sin 24 = x/29
x = (sin 24)(29)
x = 11.8
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Please explain your steps as I'm a bit confused about the process... thanks!!!
Answer:
x = -1.5056Step-by-step explanation:
To solve this equation log both sides and apply log rules.
[tex]14^{x-7}=12^{6x}[/tex][tex]log14^{x-7}=log12^{6x}[/tex][tex](x - 7)log14=6xlog12[/tex]Substitute the values of logs:
[tex](x - 7)*1.1461 = 6x*1.0791[/tex]Solve it as linear equation:
[tex]1.1461 x - 7*1.1461 = 6.4746x\\[/tex][tex]1.1461x - 6.4746x = 8.0227[/tex][tex]-5.3285x = 8.0227[/tex][tex]x = 8.0227/-5.3285[/tex][tex]x = -1.5056[/tex]Which of the following is
key property of the quadratic parent function?
A. Its vertex is at the origin.
B. It is not a function.
C. It iS not a parabola.
D It is in quadrants III and IV.
Answer:
Step-by-step explanation:
i think it is c
Answer:
A
Step-by-step explanation:
So let's look at each and determine whether they're true or not.
A. It's vertex is at the origin:
This is true! The reason for this is because you can express a quadratic in vertex form as such: [tex]f(x)=a(x-h)+k[/tex] where (h, k) is the vertex. If you remember the parent function is simply: [tex]f(x)=x^2[/tex] which we can express as: [tex]f(x) = (x-0)+0[/tex] meaning the vertex is at (0, 0). This also intuitively makes sense, the x^2 will only output positive values for real numbers, so when x<0, f(x) is still going to be positive because it's squaring the negative, so that means when you go from -5 to -4, even though you increased x by 1, the f(x) decreases by 1, since it's squaring the value to get a positive value. The lowest value this can output is 0 because 0^2 = 0. This means you vertex is at the origin.
B. It is not a function:
So the quadratic parent function only outputs 1 value for each input, although it isn't a one-to-one function, meaning that each output isn't unique, but each input still only outputs 1 output, which makes this a function
C. It is not a parabola:
parabolas are expressed as quadratic equations, so this is false.
D. It is in quadrants ||| and IV:
This is not true since the parent function opens upwards and has a vertex at (0, 0) so it will only be in quadrant I and II. I'll provide a diagram showing this.
Factor the greatest common factor: −6m2 18m − 36. −6(m2 − 3m 6) −1(6m2 − 18m 36) −6m(m2 − 3m 6) −6(m2 3m − 6)
Answer:
Step-by-step explanation:
−6m2 18m − 36
= -6(m2 - 3m + 6)
Use the grouping method to factor this polynomial completely. 3x^3+12x^2x+8
Answer:171x+8
Step-by-step explanation:
3x^3+12x^2x+8
=27x+144x+8
=171x+8
Richard wants to weed 33% of his garden today. The total garden is 144 square yards. How many square yards should Richard weed to reach his goal?
11. Find the slope of the line that passes through the pair of points. (1, 7), (10, 1)
Answer:
m = [tex]-\frac{2}{3}[/tex]
Step-by-step explanation:
m = [tex]\frac{y2-y1}{x2-x1}[/tex]
m = [tex]\frac{1-7}{10-1}[/tex]
m = [tex]\frac{-6}{9}[/tex]
m = [tex]-\frac{2}{3}[/tex]
Answer:
-2/3
Step-by-step explanation:
slope = (y_2 - y_1)/(x_2 - x_1)
slope = (1 - 7)/(10 - 1)
slope = -6/9
slope = -2/3
Use the quadratic formula to solve the equation below.
x (x + 16) = − 64
The average household income for a recent year was $30,000. five years earlier the average household income was $24,500. assume sample sizes of 34 were used and the population standard deviation of both samples were $5928. at 5% level of significance is there enough evidence to believe that the average household income has increased?
Using hypothesis test, we conclude that there is evidence to believe that the average household income has increased.
According to the question,
The average household income for a recent year (x₁⁻) = $30,000
The average household income for a recent year (x₂⁻) = $24,500
sample sizes n₁ = n₂ = 34
standard deviation of both samples were $24,500. Thus, s₁ = s₂ = $5928.
Null hypothesis: There is no evidence to believe that the average household income has increased.
H₀ : μ₁ ≤ μ₂
Alternative hypothesis: There is evidence to believe that the average household income has increased.
H₁: μ₁ > μ₂
To check hypothesis we have the formula
Standard error= [tex]\sqrt{\frac{s_{1} ^{2} }{n_{1} } + \frac{s^{2} _{2} }{n_{2} } }[/tex]
= [tex]\sqrt{2067128.4706}[/tex]
= 1437.7512
Thus, standard error is $1437.7512.
Formula for test statistic = [(x₁⁻ - x₂⁻) - (μ₁ - μ₂)]/standard error
= [(30000 - 24500) - 0]/1437.7512
= 3.8254
The critical value of z at 5% level of significance is 1.6449.
Here, the calculated value is greater than the critical value so we reject H₀.
Hence using hypothesis test, we conclude that there is evidence to believe that the average household income has increased.
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Which explicit formula generates the infinite sequence 2, 9, 28, 65, 126,.?
O a-n²
O a-n²+1
O a-n³
O a-n³+1
Mark this and return
Save and Exit
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Submit
Answer:
n^3 + 1.
Step-by-step explanation:
Each term is 1 more than a perfect cube.
2 = 1^3 + 1
9 = 2^3 + 1
28 = 3^3 + 1
65 = 4^3 + 1
126 = 5^3 + 1
So the explicit formula is n^3 + 1.
The explicit formula that generates the given sequence is indeed aₙ = n³+1.
What is Sequence?Sequence is an enumerated collection of objects in which repetitions are allowed and order matters.
The nth term of the sequence can be obtained by substituting n = 1, 2, 3, ... into the expression n³+1:
a₁ = 1³+1 = 2
a₂ = 2³+1 = 9
a₃ = 3³+1 = 28
a₄ = 4³+1 = 65
a₅ = 5³+1 = 126
Hence, the explicit formula that generates the given sequence is indeed aₙ = n³+1.
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As a fundraiser, the music boosters wrapped gifts at the mall one weekend. out of the 100 gifts they wrapped, 310 3 10 were for weddings, and 37100 37 100 were for baby showers. the rest of the gifts were for birthdays. what fraction of the gifts was for birthdays? enter your answer in the boxes.
For birthday events 33/100 gifts were packed by the music boosters at the mall.
Calculation of the fractionTotal number of gift items = 100
For the wedding purpose,out of 100 gifts, 3/10 number of gifts were boxed = 3/10*100 = 30
For the baby shower, out of 100 gifts, 37/100 gifts were packed = 37
The rest amount of the gift = 100-( wedding + baby shower)
= 100-(30+37) = 33
So, according to the question, these 33 numbers gift was for a birthday.
When it is expressed as a fraction,
The fraction should be = 33/100
Therefore, it is concluded that 33/100 gifts were packed for birthday occasions.
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Find the volume of the prism. Round to the nearest tenth if necessary.
Answer:
14.7 (Because you asked for no units)
Step-by-step explanation:
The volume of this triangular prism is 1/2 BHL
0.5 * 3.5 * 2 * 4.2 = 14.7 ft^3
Find the area of this circle
Answer:
[tex] {75ft}^{2} [/tex]
Step-by-step explanation:
[tex]a = \pi{r}^{2} = 3 {r}^{2} \\ a =3 ({ \frac{10}{2} })^{2} = 3 \times {5}^{2} \\ a = 3 \times 25 = 75[/tex]
First, we replace π with 3, since we were told to.We know 10 is the diameter and the radius is half of the diameter, so we divide 10 by 2.We get 5. 5 squared is the same as (5×5). Finally, we multiply 3 by 25.To start solving this exercise, we obtain as data:
π = 3r = 10 ft²a = ?To find the area of the circle. We apply the following formula: A =π r², where
a = areaπ = pir = radiusWe substitute our data in the formula and solve:
Substituting values into the equation:
[tex]\boldsymbol{\sf{A=3*(10 \ ft)^{2} }}[/tex]Taking the square root:
[tex]\boldsymbol{\sf{A=3*100 \ ft^{2} }}[/tex]Multiplying
[tex]\boxed{\boldsymbol{\sf{A=300 \ ft^{2} }}}[/tex]Therefore, the area of the circle is 300 ft².
THIS IS VERY HARD PLSSS
Answer:
[tex]y=3\sqrt{x-1}-7[/tex]
Step-by-step explanation:
We are given the function [tex]y=\sqrt{x}[/tex]. Let's apply each transformation separately and see what we get. First, let's apply the vertical shift. We are told that the graph shifts downwards by 7 units. In other words, when x is 0, y should be -7 instead of 0. We can accomplish that by changing the y-intercept of the graph and subtracting our function by 7: [tex]y=\sqrt{x} -7[/tex]. Notice that the -7 is outside the square root.
Next, we can apply the horizontal transformation. We are told that the graph shifts to the right 1 unit. This means that, for [tex]y=\sqrt{x}[/tex], if y is 0, x should be 1. We can accomplish this by doing [tex]y=\sqrt{x-1}[/tex] (if x = 1, y will be 0). Now, we can combine the two transformations we have done so far: [tex]y=\sqrt{x-1}-7[/tex].
Lastly, we need to vertically stretch the function by a factor of 3. All we have to do here is multiply sqrt(x) by 3 (this way, if x is equal to 1, y should be 3 instead of 1 (3 times x)). So, we get something like this: [tex]y=3\sqrt{x}[/tex]. Now, we can combine all of the transformations we did to get our final answer:
[tex]y=3\sqrt{x-1}-7[/tex]
If the polynomials p(x) = ax³+4x²+3x-4 and q(x) = x² - 4x + a, leave the same remainder when divided by (x-3), find value of a.
Steps pls
Answer:
a = -22/13.
Step-by-step explanation:
By the Remainder Theorem
p(3) = remainder when p(x) is divided by x-3.
q(3) is equal to the same remainder.
So we have:
p(3) = q(3) , so
a(3)^3 + 4(3)^2 + 3(3) - 4 = 3^2 - 4(3) + a
27a + 36 + 9 - 4 = 9 - 12 + a
27a - a = 9 - 12 - 36 - 9 + 4
26a = -12 - 36 + 4
26a = -44
a = -44/26
a = -22/13.
HELPPP DOES ANYONE KNOW THE ANSWER???
Answer:
B
Step-by-step explanation:
solve equation.
1.) Write a word problem that can be described by the division expression 3 divided by 1/4.
2.) Solve your word problem using a model. Use complete sentences to describe your model, and interpret the quotient in the context of your word problem. If you wish, you may upload a copy of your model.
3.) Use multiplication to check your answer in question #2. Show or explain all of your work.
The word problem can be:
"let's say that you have $3, and there is an item that costs $(1/4), how many of these items can you buy?"
And the solution is N = 12.
How to write the word problem?We want a problem that can be described by 3 divided by 1/4.
So, let's say that you have $3, and there is an item that costs $(1/4), how many of these items can you buy?
The solution to that question is given by:
[tex]N = \frac{3}{1/4}[/tex]
2) To solve this, we can use a really simple model.
In one unit, we have 4 fourts.
Then in 3 units, we have 3*4 = 12 fourts.
Then the answer is 12.
3) How to use multiplication?
Remember that dividing by a fraction is equivalent to multiplying by the inverse of said fraction, then:
[tex]N = \frac{3}{1/4} = 3*(4/1) = 12[/tex]
We got the same thing as above.
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Suppose that f'(4) = 3 , g'(4) = 7 , g(4) = 4 and g(x) not= to 4 for xnot= to 4 . then cmpute lim xgose to 4 f(g(x))/x-4-f(4)/x-4
It looks like the limit you want to compute is
[tex]\displaystyle \lim_{x\to4} \frac{f(g(x)) - f(4)}{x-4}[/tex]
Since [tex]g(4)=4[/tex], this limit corresponds exactly to the derivative of [tex](f\circ g)(x) = f(g(x))[/tex] at [tex]x=4[/tex]. Recall that
[tex]f'(a) = \displaystyle \lim_{x\to a} \frac{f(x) - f(a)}{x - a}[/tex]
By the chain rule,
[tex](f\circ g)'(4) = f'(g(4)) \times g'(4) = f'(4) \times g'(4) = 3\times7 = \boxed{21}[/tex]
Since [tex]g'(4)[/tex] exists, [tex]g[/tex] is differentiable at [tex]x=4[/tex] so it must be continuous.