If the pth term of an A.P. is q and the qth term is p. Prove that its nth term is (p+q-n). ​

Answers

Answer 1
Given:

pth term of an AP = q

qth term = p

Prove:

nth term of A.P. is (p+q-n). ​

Proof:

We know that,

nth term of an AP (an) = a + (n - 1)d

Hence,

⟹ a + (p - 1)d = q

⟹ a + pd - d = q

⟹ a = q - pd + d -- equation (1)

Similarly,

⟹ a + (q - 1)d = p

Substitute the value of a from equation (1).

⟹ q - pd + d + qd - d = p

⟹ qd - pd = p - q

⟹ - d(p - q) = p - q

⟹ - d = 1

⟹ d = - 1

Substitute the value of d in equation (1).

⟹ a = q - p( - 1) + ( - 1)

⟹ a = q + p - 1

Now,

an = q + p - 1 + (n - 1)( - 1)

⟹ an = q + p - 1 - n + 1

⟹ an = p + q - n

Hence, Proved.

I hope it will help you.

Regards.

Answer 2

Step-by-step explanation:

ANSWER

pth term = q

a+(p−1)d=q

qth term = p

a+(q−1)d=p

Solving these equations, we get,

d=−1

a=(p+q−1)

Thus,

nth term = a+(n−1)d=(p+q−1)+(n−1)×(−1)=(p+q−n)


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Answers

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A ratio indicates how many times one number contain in another number. The ratio of two number is written as x : y, which is equivalent to x/y.

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Given that;

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Answers

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Answers

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Step-by-step explanation

For further help (727) 335-8234

The first step of indirect proof of the conditional below

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