i need this quickly please

The maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight is 1.771 ounces.

The maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight can be calculated using the formula:

Margin of error = Z-score x (population standard deviation / square root of sample size)

Here, the Z-score for a 90% confidence level is 1.645 (obtained from a standard normal distribution table). The population standard deviation is given as 5.7 ounces, and the sample size is 28.

Plugging in these values, we get:

Margin of error = 1.645 x (5.7 / sqrt(28))
= 1.645 x (1.076)
= 1.771

Therefore, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight is 1.771 ounces. This means that we can be 90% confident that the true population mean turtle weight lies within the range of (60 - 1.771) to (60 + 1.771) ounces, or 58.229 to 61.771 ounces.

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The distance from tower A to the fire is approximately 13.95 miles.

To find the distance from tower A to the fire, we can use the Law of Sines in a triangle formed by the two towers and the fire's location. Let's label the fire's location as point C, tower A as point A, and tower B as point B.

First, we need to find the angle at point B. Since the bearing from tower B is S65°W, it means the angle between the south line and the line from tower B to the fire is 65°. Since tower A is due south of tower B, the angle at point B is 180° - 65° = 115°.

Now, we know the angle at point A is 58°, and the angle at point B is 115°. We can find the angle at point C by adding these two angles and subtracting the sum from 180°:

Angle C = 180° - (58° + 115°) = 180° - 173° = 7°

Now we have all the angles in the triangle ABC, and we know the distance between the two towers (20 miles). We can use the Law of Sines to find the distance from tower A to the fire:

sin(A) / a = sin(B) / b
sin(58°) / AC = sin(115°) / 20

We need to solve for AC (distance from tower A to the fire):

AC = (sin(58°) * 20) / sin(115°)

AC ≈ 13.95 miles

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When the loaded die is rolled, the probability of getting a 1, 2, 4, 5, or 6 is 1/9 each, while the probability of getting a 3 is 5/9.

If a 3 is five times more likely to appear than each of the other five numbers on the die, we can assign the following probabilities to each outcome:

[tex]P(1) = P(2) = P(4) = P(5) = P(6) = x[/tex] (some common probability)

[tex]P(3) = 5x[/tex]

Since the sum of the probabilities for all possible outcomes must be equal to 1, we have:

[tex]P(1) + P(2) + P(3) + P(4) + P(5) + P(6) = x + x + 5x + x + x + x = 9x = 1[/tex]

Solving for x, we get:

[tex]x = 1/9[/tex]

Therefore, the probabilities for each outcome are:

[tex]P(1) = P(2) = P(4) = P(5) = P(6) = 1/9\\P(3) = 5/9[/tex]

So when the loaded die is rolled, the probability of getting a 1, 2, 4, 5, or 6 is 1/9 each, while the probability of getting a 3 is 5/9.

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Answer:

I am not entirely sure, but I believe the answer is 5 million.

Step-by-step explanation:

If the probability of winning is one out of a 1,000,000, then there is 1 million participants, therefore 5 x 1,000,000 = 5 million.

g(x) is increasing on the interval (0, ∞) and decreasing on the interval (-∞, 0), and it has a local minimum at x = 0.

To determine where g(x) is increasing or decreasing, we need to find its derivative and examine its sign.

g(x) = 36x^2 - 16

g'(x) = 72x

g'(x) is positive when x > 0, and negative when x < 0. Therefore, g(x) is increasing on the intervals (0, ∞) and decreasing on the interval (-∞, 0).

We can also find the critical points of g(x) by setting g'(x) = 0:

72x = 0

x = 0

So, the only critical point is x = 0. We can use the second derivative test to determine whether this is a maximum or minimum:

g''(x) = 72

g''(0) = 72 > 0, so x = 0 is a local minimum.

Therefore, g(x) is increasing on the interval (0, ∞) and decreasing on the interval (-∞, 0), and it has a local minimum at x = 0.

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The answer to this question is true. Trigonometric equations with multiple angles can have an infinite number of solutions.

Multiple angles in trigonometry refer to the angles that are multiples of the standard angles (0, 30, 45, 60, 90 degrees).

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The thickness of the ring would be 20.7 cm if the diameter of the rings were to be shrunk down to the width of a dollar bill (6.6 cm) and the ring wraps around itself once.

If the diameter of the rings were to be shrunk down to the width of a dollar bill (6.6 cm), we can use the formula for the circumference of a circle, which is C = 2πr, where C is the circumference and r is the radius of the circle.

If we assume that the original diameter of the rings is d, then the radius (r) would be d/2. So, if we shrink the diameter down to 6.6 cm, then the radius would be 6.6/2 = 3.3 cm.

Now, we can use the formula for the circumference to find the length of the circle that has a radius of 3.3 cm:

C = 2πr
C = 2π(3.3)
C = 20.7 cm

Therefore, if the diameter of the rings were to be shrunk down to the width of a dollar bill (6.6 cm), the length of the circle would be 20.7 cm.

To find the thickness of the rings, we need to divide the length of the circle by the number of times the ring wraps around itself (the height of the ring). Let's assume the ring wraps around itself once.

So, the thickness of the ring would be:

Thickness = Length of the circle / Number of wraps
Thickness = 20.7 cm / 1 wrap
Thickness = 20.7 cm

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The approximate total time using equations of motion takes for the ball to hit the ground is 3.49 seconds, and it travels approximately 69.8 meters horizontally before hitting the ground.

To begin with, we can use the equations of motion to solve for the time it takes for the ball to hit the ground. Since the ball is thrown horizontally, we can ignore the vertical component of the velocity and focus only on the horizontal motion.

First, let's find the horizontal distance the ball travels before hitting the ground. We know that the ball is thrown at a speed of 20 meters per second, so its horizontal velocity will remain constant throughout its motion. We can use the formula:

distance = velocity x time

Since the ball will hit the ground, we want to find the horizontal distance it travels in the time it takes to fall. We know that the height of the tower is 60 meters, so the vertical distance the ball falls is also 60 meters. We can use the formula for the time it takes to fall from a certain height:

time = [tex]\sqrt{(2 * height / gravity) }[/tex]

where gravity is the acceleration due to gravity, approximately 9.8 meters per second squared. Plugging in the values, we get:

time = [tex]\sqrt{(2 x 60 / 9.8)}[/tex] = 3.49 seconds

This is the total time it takes for the ball to hit the ground. Now, to find the horizontal distance it travels, we can use the formula above:

distance = velocity x time = 20 x 3.49 = 69.8 meters

Therefore, the approximate total time it takes for the ball to hit the ground is 3.49 seconds, and it travels approximately 69.8 meters horizontally before hitting the ground.

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The correct answer would be Structure 2 The reason for this is because Hydrogen bonds are the bonds between A T, and C G. Structure 1 shows the double helix, structure 3 shows 3 prime and 6 prime, And structure 4 shows the bases / nucleotides. That is why Structure 2 Is your CORRECT answer <3

Feel free to 5 star if you liked this answer ^^

Answer:

5%

Step-by-step explanation:

The compound interest formula is A = P (1 + r/n)^nt where A is the future value of the investment, P is the principal investment amount, r is the annual interest rate (decimal), n is the number of times the interest is compounded per year and t is the time in years  1.

In your case, we have P = Rs. 8000, A = Rs. 8820 (Rs. 820 + Rs. 8000), n = 1 (compounded yearly) and t = 2 years  2.

Substituting these values in the above formula we get:

8820 = 8000(1 + r/1)^(1*2)

Solving for r we get:

r = ((8820/8000)^(1/2) - 1)*100

r ≈ 5%

Therefore, the rate of compound interest is approximately 5%

Let's denote the increase in both the radius and the height of the cylinders as 'x' inches.

The volume of a cylinder can be calculated using the formula V = πr²h, where V is the volume, r is the radius, and h is the height.

For the first cylinder (with original radius 8 inches and height 3 inches), the volume is given by V₁ = π(8)²(3) = 192π cubic inches.

For the second cylinder (with increased radius and height), the volume is given by V₂ = π(8 + x)²(3 + x).

Given that the resulting volumes are equal, we can set up the following equation:

V₁ = V₂

192π = π(8 + x)²(3 + x)

Canceling out the π from both sides, we have:

192 = (8 + x)²(3 + x)

Expanding the equation:

192 = (64 + 16x + x²)(3 + x)

192 = 192 + 48x + 16x² + 3x + x²

0 = 16x² + 51x

Simplifying the quadratic equation:

16x² + 51x = 0

x(16x + 51) = 0

Setting each factor equal to zero:

x = 0 (nonzero number of inches)

16x + 51 = 0

16x = -51

x = -51/16

Since we're looking for a nonzero increase, the increase is x = -51/16 inches.

Note: It's important to check the validity of the negative value for 'x' since it represents an increase. In this case, the negative value implies a decrease rather than an increase. Therefore, the increase in both the radius and the height is 0 inches.

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The dimensions of the box that will have the greatest volume are:

Length and width of the base: 2√3 feet

Height: h = (36 - x^2) / 8x = (√3)/2 feet

Let the length and width of the base be x, and let the height be h.

The surface area of the top is x^2, and the surface area of the remaining four sides is [tex]2(xh + xh) = 4xh[/tex].

The cost of the top is [tex]x^2[/tex], and the cost of the remaining four sides is [tex]2(4xh) = 8xh[/tex]. Therefore, the total cost is:

[tex]C(x,h) = x^2 + 8xh[/tex]

We know that the total cost is $36, so we have:

[tex]x^2 + 8xh = 36[/tex]

Solving for h, we get:

[tex]h = (36 - x^2) / 8x[/tex]

The volume of the box is given by:

[tex]V(x,h) = x^2h[/tex]

Substituting h in terms of x, we get:

[tex]V(x) = x^2 ((36 - x^2) / 8x)[/tex]

Simplifying, we get:

[tex]V(x) = (1/8) x (36x - x^3)[/tex]

To find the dimensions of the box that will have the greatest volume, we need to find the value of x that maximizes V(x). We can do this by taking the derivative of V(x) with respect to x, setting it equal to 0, and solving for x:

[tex]V'(x) = (1/8) (36 - 3x^2) = 0[/tex]

Solving for x, we get:

x = 2√3

Therefore, the dimensions of the box that will have the greatest volume are:

Length and width of the base: 2√3 feet

Height: [tex]h = (36 - x^2) / 8x[/tex] = (√3)/2 feet

The volume of the box is:

[tex]V = x^2h[/tex]= (2√3)^2 ((√3)/2) = 9√3 cubic feet

Note: To confirm that this value represents the maximum volume, we can check that V''(x) < 0, which indicates a maximum point. We have:

[tex]V''(x) = (1/8) (-6x) = -3x/4[/tex]

At x = 2√3, V''(x) = -3(2√3)/4 = -3√3/2 < 0, so this is indeed a maximum point.

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The reported sky cover is one continuous overcast layer, its thickness is 5,780 feet.

To calculate the thickness of a cloud layer, you need to subtract the cloud base height from the cloud top height. In this case, the sky cover is reported as one continuous layer, and the cloud top is reported at 6,500 feet.

Aviation Routine Weather Reports (METARs) typically include cloud height information in increments of 100 feet above ground level (AGL). If the sky cover is reported as overcast (OVC) with no height information, it is assumed to be at or below 6,000 feet AGL.

Therefore, the thickness of the cloud layer in this scenario can be calculated as follows:

Cloud base height = 620 feet (field elevation) + 100 feet = 720 feet AGL

Cloud thickness = Cloud top height - Cloud base height

= 6,500 feet - 720 feet

= 5,780 feet

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A pressure of 14 pounds per square inch is needed to produce a volume of 30 cubic feet, assuming that the volume of the gas is inversely proportional to the pressure.

If the volume of a gas is inversely proportional to the pressure, we can use the formula:

P1 x V1 = P2 x V2

P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.

P1 = 21 pounds per square inch and V1 = 20 cubic feet.

To find P2 when V2 = 30 cubic feet.

Plugging in the values we have:

21 x 20 = P2 x 30

Simplifying:

420 = 30P2

Dividing both sides by 30:

P2 = 14 pounds per square inch

We may apply the formula: if the volume of a gas is inversely proportional to the pressure.

P1 x V1 equals P2 x V2

The original pressure and volume are P1 and V1, whereas the new pressure and volume are P2 and V2.

V1 is 20 cubic feet, and P1 is 21 pounds per square inch.

when V2 = 30 cubic feet, to determine P2.

When we enter the values we have:

21 x 20 = P2 x 30

Condensing: 420 = 30P2

30 divided by both sides:

14 pounds per square inch is P2.

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The median of 14 is the most accurate to use, since the data is skewed.

The most appropriate measure of center to represent the data depends on the nature of the data distribution. Looking at the histogram provided, it appears that the data is positively skewed, with a long tail towards the right. This means that there are a few larger values (donations in this case) that are pulling the mean towards the right, while the median is a better representative of the typical or central donation.

Therefore, in this case, the median of 14 is the most accurate measure of center to use to represent the data, since it is less affected by the extreme values and gives a better idea of the central tendency of the data. The mean of 13.2 is also close to the median and can be used as a measure of center, but it is not as representative of the typical donation due to the skewness of the data.

The median of 13.2 and the mean of 14 cannot be used to show whether the charity needs more or plenty of money, as this depends on other factors such as the expenses and goals of the charity.

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Answer:

Step-by-step explanation:

1:2

For The allowable accuracy for a map at a scale of 1:250,000, we need to first understand the relationship between scale and accuracy, we can assume that the allowable accuracy for a map at 1:250,000 would be less than the allowable accuracy for a map at 1:20,000.

As the scale of a map decreases, the level of detail shown on the map decreases, which means that the allowable accuracy also decreases.

When it comes to maps, accuracy is crucial for providing accurate information to the user. The accuracy of maps is often measured in terms of the scale used to create the map. In this case, the question mentions a map with a scale of 1:20,000, which means that one unit on the map represents 20,000 units in the real world.

According to the question, maps with a scale smaller than 1:20,000 can have no more than 10% of the sampled points off by 1/50th of an inch. This means that for every 100 sampled points, no more than 10 points can be off by 1/50th of an inch.

To determine the allowable accuracy for a map at a scale of 1:250,000, we need to first understand the relationship between scale and accuracy. As the scale of a map decreases, the level of detail shown on the map decreases, which means that the allowable accuracy also decreases.

Based on this understanding, we can assume that the allowable accuracy for a map at 1:250,000 would be less than the allowable accuracy for a map at 1:20,000. However, without more information about the specific requirements for this map, we cannot determine the exact allowable accuracy.

In general, it is important to ensure that maps are as accurate as possible to prevent errors and confusion for users. This can be achieved through careful measurement, data collection, and map creation techniques.

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The minimum sample size required to estimate the unemployment rate in Champaign-Urbana to within 2% of its true value with 95% confidence is 753 people in the labor force.

To determine the minimum sample size required to estimate the unemployment rate in Champaign-Urbana to within 2% of its true value with 95% confidence, we can use the formula:
n = (Z^2 * p * (1-p)) / E^2
where:
n = sample size
Z = z-score for desired level of confidence (1.96 for 95%)
p = estimated proportion of unemployed (0.10 based on economist's statement)
E = maximum error (0.02)
Plugging in the values, we get:
n = (1.96^2 * 0.10 * 0.90) / 0.02^2
n = 752.45
Therefore, the minimum sample size required to estimate the unemployment rate in Champaign-Urbana to within 2% of its true value with 95% confidence is 753 people in the labor force.

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The underlying argument in the film is that "you can't be what you can't see," which means that women need to see more representations of themselves in positions of power and influence in order to feel empowered to pursue those roles.

Women have historically been underrepresented in leadership positions, both in politics and in the workplace. This lack of representation can make it difficult for women to envision themselves in these roles, leading to a lack of ambition and confidence.

By increasing the visibility of women in positions of power, we can help to inspire and motivate the next generation of female leaders.

This argument applies not only to women, but to other marginalized groups as well. By increasing representation across all dimensions of diversity, we can create a more inclusive and equitable society where everyone has the opportunity to achieve their full potential.

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To be 95% confident that the sample's variance is within 40% of the population's variance, the minimum sample size needed is 16.

To calculate the minimum sample size, we can use the formula:

[tex]$n = \frac{(z_{\alpha/2})^2\sigma^2}{E^2}$[/tex]

Where:

[tex]$n$[/tex]= sample size

[tex]$z_{\alpha/2}$[/tex]= the z-score corresponding to the level of confidence (in this case, 95%, so [tex]z_{\alpha/2}$ = 1.96)[/tex]

[tex]$\sigma$[/tex] = population standard deviation (since we're interested in variance, we need to square it: [tex]\sigma^2$)[/tex]

[tex]$E$[/tex] = the maximum allowable error (in this case, 40% of the population variance, so [tex]E = 0.4\sigma^2$)[/tex]

Substituting these values into the formula, we get:

[tex]$n = \frac{(1.96)^2\sigma^2}{(0.4\sigma^2)^2}$[/tex]

Simplifying:

[tex]$n = \frac{5.385\sigma^2}{\sigma^4/25} = \frac{134.63}{\sigma^2}$[/tex]

Therefore, the minimum sample size needed to be 95% confident that the sample's variance is within 40% of the population's variance is [tex]\frac{134.63}{\sigma^2}$.[/tex]

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Since our calculated t-value of 4.39 is greater than the critical value of 1.782, we can reject the null hypothesis at the 0.10 level of significance. This means that we have evidence to suggest that the mean weight of Pineapple Corporation's cans is not equal to 12 ounces, supporting the production group's belief.

To test whether the production group's belief that the mean weight of Pineapple Corporation's cans has changed, we need to conduct a hypothesis test. We can start by setting up our null and alternative hypotheses:

- Null hypothesis (H0): The mean weight of Pineapple Corporation's cans is equal to 12 ounces.
- Alternative hypothesis (Ha): The mean weight of Pineapple Corporation's cans is not equal to 12 ounces.

We can use a two-tailed t-test to test this hypothesis since we do not have information about the direction of the change in mean weight. With a sample size of 13, we need to use a t-distribution with 12 degrees of freedom.

Using the information given, we can calculate the test statistic:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))
t = (12.03 - 12) / (0.07 / sqrt(13))
t = 4.39

Looking at a t-distribution table with 12 degrees of freedom and a significance level of 0.10 (two-tailed), we can see that the critical values are +/- 1.782.

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To model the evolution of the populations of frogs, flies, and crocodiles over time, we can use the following system of differential equations: dP/dt = k1PQ - k2P

dQ/dt = k3Q - k4PQ
dR/dt = -k5R + k6PQ

where P, Q, and R represent the populations of frogs, flies, and crocodiles at time t, and k1 through k6 are positive constants representing various factors affecting the populations.

In the first equation, the term k1PQ represents the growth of the fly population due to the presence of frogs, while the term k2P represents the natural decay of the frog population.

In the second equation, the term k3Q represents the growth of the fly population in the absence of crocodiles, while the term k4PQ represents the impact of the frog population on the fly population.

In the third equation, the term k5R represents the natural decay of the crocodile population, while the term k6PQ represents the impact of the frog and fly populations on the crocodile population.

The plus or minus signs in these equations depend on the direction of the population change. For example, the term k1PQ is positive because an increase in the frog population (P) will lead to an increase in the fly population (Q).

However, the term -k5R is negative because an increase in the crocodile population (R) will lead to a decrease in the crocodile population over time.

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The sampling distribution of the sample mean for samples of size 400 has a mean of 18 and a standard deviation of 0.25.

To find the sampling distribution of the sample mean, we need to calculate the mean and standard deviation of the sample mean for samples of size 400.

The mean of the sample mean is equal to the mean of the population, which is given as 18.

The standard deviation of the sample mean is equal to the standard deviation of the population divided by the square root of the sample size. Therefore, the standard deviation of the sample mean can be calculated as:

standard deviation of the sample mean = standard deviation of the population / sqrt(sample size)

[tex]= 5 / \sqrt{(400)}[/tex]

= 5 / 20

= 0.25

So the sampling distribution of the sample mean for samples of size 400 has a mean of 18 and a standard deviation of 0.25.

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if  floor is 3.4 meters wide and 5.2 meters long then area of bathroom floor is 17.68 square meters

The floor is 3.4 meters wide and 5.2 meters long.

Width is 3.4 meters

Length is 5.2 meters

Area of the bathroom is length times width

Area = Length × Width

=5.2×3.4

=17.68 square meters

Hence, if  floor is 3.4 meters wide and 5.2 meters long then  area of bathroom floor is 17.68 square meters

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If the z-score exceeds the critical value at a chosen level of significance, such as 0.05, the professor can reject the null hypothesis and conclude that the percentage of community college students owning smartphones is indeed higher than the national average of 40%

According to a Pew Research Center study in May 2011, 40% of all American adults had a smartphone, which allows users to read email and surf the internet.

A communications professor at a university believes that the percentage of community college students owning smartphones is higher than this national average. To test her hypothesis, she conducts a study by selecting 465 community college students at random and finds that 207 of them have a smartphone.

To test her hypothesis, the professor needs to perform a hypothesis test. The null hypothesis (H0) is that the percentage of community college students with smartphones is equal to the national average (40%). The alternative hypothesis (H1) is that the percentage is higher than 40%.

By using a sample proportion (p-hat) and a sample size (n) of 465, the professor can calculate the z-score and compare it to the critical value to determine if there's enough evidence to reject the null hypothesis. In this case, p-hat is equal to 207/465, which is approximately 44.52%.

If the z-score is below the critical value, she cannot reject the null hypothesis, and the difference between the national average and the community college students' smartphone ownership could be due to chance.

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The measure of the angle ACB given in the figure representing circle, tangent and secant is equal to option a. 32°

Arc AB = 176°

Measure of ∠ABC = 56°

Since AC is tangent to the circle,

∠CAB = 90°.

Let O be the center of the circle and let ∠ACB = x.

Since AX is a secant,

∠AXB = 1/2 arc AB

          = 88°.

Also, since ∠CBA = 56°,

∠XBC = 180° - ∠CBA

          = 124°.

In triangle ABC,

Sum of angles in a triangle is 180 degrees.

∠ACB + ∠ABC + ∠CAB = 180°

Substituting the values  we get,

⇒ x + ∠ABC + 90° = 180°

⇒ ∠ABC = 90° - x

Angle  BAC is an inscribed angle that intercepts arc AXB and arc AB.

By the inscribed angle theorem, we have,

angle  BAC= (1/2) arc AXB

                 = (1/2) × 184

                  = 92 degrees.

Finally, use the fact that the angles in a triangle sum to 180 degrees to find angle ACB.

angle ACB = 180 - angle BAC - angle CBA

= 180 - 92 - 56

= 32 degrees.

Therefore, the measure of angle ACB in the given figure is equal to option (a) 32°.

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The above question is incomplete, the complete question is:

The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X:

The figure shows a circle with points A and B on it and point C outside it. Side BC of triangle ABC intersects the circle at point X. A tangent to the circle at point A is drawn from point C. Arc AB measures 176 degrees, and angle CBA measures 56 degrees.

What is the measure of angle ACB?

a. 32°

b. 60°

c. 28°

d. 16°

Figure is attached .

So, a sample size of around 155 visitors is most likely to yield a sample median of 1,005 visitors, assuming the distribution of visitors is roughly normal.

The formula for calculating the standard error of the median is:

SE = 1.253 * (IQR / √n)

Where SE is the standard error of the median, IQR is the interquartile range (the difference between the 75th percentile and the 25th percentile), and n is the sample size.

Assuming that the distribution of visitors to the zoo each day is roughly normal, we can use the standard error of the median to estimate the range of values within which the sample median is likely to fall. Specifically, we can say that the sample median is likely to fall within:

sample median +/- (z-score * SE)

Where z-score is the number of standard deviations from the mean that corresponds to a particular level of confidence. For example, if we want to be 95% confident that the sample median falls within our estimated range, we would use a z-score of 1.96.

So, to answer your question, we need to find the sample size for which a sample median of 1,005 visitors is likely to fall within the estimated range of values. We can set up an equation like this:

1,005 +/- (1.96 * SE) = 893

Solving for n, we get:

n = (1.253 * IQR / (1.96 * (1,005 - 893)))^2

Using the interquartile range of the distribution (which we don't have, so let's assume it's 500) and plugging in the numbers, we get:

n = 155.14

So a sample size of around 155 visitors is most likely to yield a sample median of 1,005 visitors, assuming the distribution of visitors is roughly normal.

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The product [tex]$A \times B \times C \times D$[/tex] is: [tex]$3 \times 7 \times 2.5 \times 10 = \boxed{525}$[/tex]

We start by finding the values of [tex]A$, $B$, $C$[/tex]and [tex]$D$[/tex]. From the given conditions, we have:

[tex]$A+2 = B-2 \Rightarrow B = A+4$[/tex]

[tex]$C \times 2 = A+2 \Rightarrow C = \frac{A+2}{2}$[/tex]

[tex]$D \div 2 = A+2 \Rightarrow D = 2A+4$[/tex]

Substituting these values into the equation for the sum of the four integers, we get:

[tex]$A + (A+4) + \frac{A+2}{2} + 2A+4 = 36$[/tex]

Simplifying the expression, we get:

[tex]$7A + 14 = 36$[/tex]

[tex]$7A = 22$[/tex]

[tex]$A = 3$[/tex]

Substituting[tex]$A=3$[/tex] into the expressions we found earlier, we get:

[tex]$B = A+4 = 7$[/tex]

[tex]$C = \frac{A+2}{2} = 2.5$[/tex]

[tex]$D = 2A+4 = 10$[/tex]

Finally, the product [tex]$A \times B \times C \times D$[/tex] is:

[tex]$3 \times 7 \times 2.5 \times 10 = \boxed{525}$[/tex]

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Full Question ;

Four positive integers[tex]$A$, $B$, $C$[/tex]and [tex]$D$[/tex] have a sum of 36. If [tex]A+2 = B-2 = C \times 2 = D \div 2$,[/tex] what is the value of the product[tex]$A \times B \times C \times D$[/tex]?

The number of dots that are above each data value in a line plot of this data include the following;

In Mathematics and Statistics, a line plot can be defined as a type of graph that is used for the graphical representation of data set above a number line, while using crosses, dots, or any other mathematical symbol.

In this scenario and exercise, we would use an online graphing calculator to graphically represent the given data set on a line plot as shown in the image attached below.

In conclusion, we can reasonably infer and logically deduce that the mode of the data set is equal to 12 because it has the highest frequency of 5.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.